the speed of light is the fastest anything in the universe can go if it is traveling through space.________ can break that speed limit.

Answers

Answer 1

The speed of light is the fastest anything in the universe can go if it is traveling through space. Much faster than light can break that speed limit.

How quickly must you go in order to surpass the speed of light?

We can never go faster than light. Or, to be more precise, in a vacuum, we can never travel at the speed of light. In other words, the 299,792,458 m/s upper limit of the universe's speed is the speed at which all other particles must move in order to exist.

What is the light's 3x10 8 speed?

In a vacuum, light travels at a speed of 3 108 m/s. About 8 minutes pass before sunlight reaches Earth.

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Related Questions

A window air conditioner that consumes 2 kW of electricity when running and has a coefficient of performance of 3 is placed in the middle of a room, and is plugged in. The rate of cooling or heating this air conditioner will provide to the air in the room when running is:

Answers

Answer: Q= QH - QL

= W + QL - QL

= W

= 1 kj/8

Explanation:

Since the net rate is positive the room will be heated.

Which of the following relationships is correct?
2 points
1 N = 1 kg
1 N = 1 kg·m
1 N = 1 kg·m/s
1 N = 1 kg·m/s2

Answers

1 N = 1 kg•m is the answer

explain magnetic flux

explain magnetic flux

Answers

Magnetic flux is a measurement of the total magnetic field, which passes through a given area. If it is a useful tool, for helping describe the effects of the magnetic force on some thing occupying a given area.

A ball rolls from x = -5 m to x = 0 m
in 1 second. What was its average
velocity?
(Units = m/s)
Don't forget: velocities and displacements to
the right are + to the left are

Answers

Explanation:

Ball moves from L to R a distance of +5 m

time = 1 sec

+5 m / 1 s = 5 m/s

Cho các máy cắt sử dụng trong công nghiệp có ký hiệu trên nhãn thiết bị: C350; B500. Hãy tính dòng điện bảo vệ ngắn mạch và dòng điện bảo vệ quá tải của từng thiết bị?

Answers

Answer:

ask in the English then I can help you

Explanation:

please mark me as brain list

What is the mass of an object moving at a speed of 5 m/s and has a momentum of 20 kg. m/s?

Answers

Answer:

An object of mass 20 kg is moving with a velocity of 10 m / s. Its momentum will be: A. 2000 kg · m / s, B. 200 kg · m / s, C. 2 kg · m / s, D. 20 kg · m / s An object of mass 20 kg is moving with a velocity of 10 m / s. Its momentum will be: A. 2000 kg · m / s, B. 200 kg · m / s, C. 2 kg · m / s, and D. 20 kg · m / s.

Explanation:

The correct option is (B) 200 kg.m/s

Given,

Mass of the body = 20 kg

Velocity of the body = 10 m/s

We know,

The momentum of a body is given by the product of the mass of the body and velocity.

So,

M

o

m

e

n

t

u

m

P

=

M

a

s

s

m

×

V

e

l

o

c

i

t

y

v

Putting all the values

P

=

20

×

10

=

200

kg.m/s

Hence the momentum of the body is 200 kg.m/s

A square coil, enclosing an area with sides 2.0 cm long, is wrapped with 2 500 turns of wire. A uniform magnetic field perpendicular to its plane is turned on and increases to 0.25 T during an interval of 1.0 s. What average voltage is induced in the coil

Answers

Answer:

The induced voltage in the coil is 0.25 V.

Explanation:

It is given that,

Area of a square coil is 2 cm or 0.02 m

Number of turns in the wire is 2500

A uniform magnetic field perpendicular to its plane is turned on and increases to 0.25 T during an interval of 1.0 s.

We need to find the induced voltage in the coil. According to Faraday's law, the induced emf in the coil is given by the rate of change on magnetic flux. So,

\(\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(NBA)}{dt}\\\\\epsilon=NA\dfrac{-dB}{dt}\\\\\epsilon=-2500\times (0.02)^2\times \dfrac{0.25}{1}\\\\\epsilon=-0.25\ V\)

So, the induced voltage in the coil is 0.25 V.

Many of the rocks of the canyon wall appear as horizontal bands. What do the bands indicate about the way the rocks formed?

Answers

Given what we know, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.

What do these bands tell us about the canyon?

The bands are the result of sediments being deposited as the canyon was being formed. These sediments are deposited by the running water that carves the canyon. This results in horizontal bands that can tell us much about the history of the canyon as well as the river that formed it.

Therefore, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.

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Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)

Answers

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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Please help me in questions 4_5_6

Please help me in questions 4_5_6

Answers

Yes, the force of the engine does work on the car as it accelerates the car forward. Work is defined as the transfer of energy that occurs when a force is applied over a distance, and in this case, the force of the engine is causing the car to move, so it is doing work.

How to explain the force

As the car gains speed, its kinetic energy increases, which means it has more energy of motion. Kinetic energy is defined as one-half of the mass of an object times its velocity squared, so as the car's speed increases, so does its kinetic energy.

The gravitational potential energy of the car will remain constant as long as it stays on a horizontal road, assuming there is no change in elevation. Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, and since the car's position relative to the ground is not changing, its gravitational potential energy will remain constant.

The tractive force of the engine may change depending on the speed of the car and the resistance to motion that the car is encountering. As the car speeds up, the air resistance acting on the car will increase, which will require more force from the engine to maintain the same acceleration. Additionally, if the road surface is rough or there are inclines, the tractive force required to maintain the same speed or acceleration will also increase.

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A student is using two circuits to investigate power consumption. She connects two identical light bulbs in series in one circuit and in parallel in the second circuit. What should she measure to calculate which configuration uses more power?
Responses
A The resistance of the bulbs and the potential difference of the battery.The resistance of the bulbs and the potential difference of the battery.
B The current flowing into each bulb and the potential difference across each bulb.The current flowing into each bulb and the potential difference across each bulb.
C The current flowing out of the battery and the resistance of each bulb.The current flowing out of the battery and the resistance of each bulb.
D The potential difference of the battery and the resistance of the battery.

Answers

The potential difference across the each bulb and the current entering each bulb.

What occurs if you connect two light bulbs in series?

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

When are two identical bulbs linked in both series and parallel?

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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The rings on all the gas giants are made of ________ and ________

Answers

Answer:

Ice and Rock

Explanation:

There's also dust and sand mixed up

negative effects of restricting roles in a democratic society​

Answers

Answer:

it could lead to riot

it could lead to uncertainty of life and property

Answer:

Positive: has everybody informed on whats going on and where. Unadulterated media could let the people know the truth about their governments.

Negative: adulterated media could give people wrong ideas and leading to more unnecessary problems. Media who prioritise money over society would always do what gets them more money, thus their information is unreliable. Since most people believe what the media says, media has the power to alter the truth within an instance

An elevator motor provides 45.0 kW of power while lifting an elevator 35.0 m. If the elevator contains seven passengers each with an average mass of 70.0 kg and it takes 20.0 s to accomplish this task, determine the mass of the elevator.

Answers

Find how much work ∆W is done by the motor in lifting the elevator:

P = ∆W / ∆t

where

P = 45.0 kW = power provided by the motor

• ∆W = work done

• ∆t = 20.0 s = duration of time

Solve for ∆W :

W = Pt = (45.0 kW) (20.0 s) = 900 kJ

In other words, it requires 900 kJ of energy to lift the elevator and its passengers. The combined mass of the system is M = (m + 490.0) kg, where m is the mass of the elevator alone. Then

W = M g h

where

g = 9.80 m/s² = acceleration due to gravity

h = 35.0 m = distance covered by the elevator

Solve for M, then for m :

M = ∆W / (g h) = (900 kJ) / ((9.80 m/s²) (35.0 m)) ≈ 2623.91 kg

m = M - 490.0 kg ≈ 2133.91 kg ≈ 2130 kg

What is the answer to this question number 2?

What is the answer to this question number 2?

Answers

Answer:

1⁺ ion

Explanation:

Metals in the first group on the periodic table will prefer to form 1⁺ ion. This is because the 1 valence electron in their orbital.

Most metals are electropositive and would prefer to lose electrons than to gain it.

Like all metals, the group 1 elements called the alkali metals would prefer to lose and electron.

On losing an electron the number of protons is then greater than the number of electrons. This leaves a net positive charge.

Which device or set of devices is contained in a mobile telephone?

Answers

 

Un teléfono móvil o teléfono celular es un dispositivo portátil que puede hacer o recibir llamadas a través de una portadora de radiofrecuencia, mientras el usuario se está moviendo dentro de un área de servicio telefónco.​ El enlace de radiofrecuencia establece una conexión con los sistemas de conmutación de un operador de telefonía móvil, que proporciona acceso a la red telefónica pública conmutada (PSTN). La mayoría de los servicios de telefonía móvil modernos utilizan una arquitectura de red celular, y por lo tanto los teléfonos móviles son, con frecuencia, llamados celulares, especialmente en Hispanoamérica. En España, se utiliza más el término móvil.

Yanni just turned one. He loves to play with his cars and trucks. He can also name the animals he sees in books.

In which stage of development is Yanni?

childhood
infancy
adolescence
adulthood

Answers

infancy
i think hope this helps

How does work affect energy between objects so it can cause a change in the form of energy?
O Work transfers energy.
O Work changes energy.
O Work increases energy.
O Work decreases energy.

Answers

Answer:

Work transfers energy

Explanation:

Work can affect energy by transfering energy between objects to result to a change in the amount and form of energy

In the figure, point P2 is at perpendicular distance R= 20.6 cm from one end of straight wire of length L = 12.2 cm carrying current i = 0.780 A. (Note that the wire is not long.) What is the magnitude of the magnetic field at P₂?

In the figure, point P2 is at perpendicular distance R= 20.6 cm from one end of straight wire of length

Answers

The magnitude of the magnetic field at P₂ is 6.06 x 10⁻⁵ T.

Using the Biot-Savart Law, we can determine the magnetic field at point P2 due to the current-carrying wire. The magnitude of the magnetic field B at P2 is given by:

B = μ₀i/4π (sinθ₁ - sinθ₂)

where μ₀ is the magnetic constant, i is the current, θ₁ is the angle between the wire and the line joining the wire and point P₂, and θ₂ is the angle between the wire and the line perpendicular to the wire and passing through point P₂.

From the given diagram, we can see that sinθ₁ = L/2R and sinθ₂ = (R - L/2)/R. Substituting these values and the given values of i, L, and R into the equation, we get:

B = (4π x 10⁻⁷ Tm/A) x 0.780 A / 4π (L/2R - (R - L/2)/R)

= 6.06 x 10⁻⁵ T

As a result, the magnetic field magnitude at P₂ is 6.06 x 10⁻⁵ T.

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You drive in straight line at 20 m/s for 10 miles, then at 30m/s for an other 10 miles what is your average speed

Answers

Answer:

25 m/s

Explanation:

Data provided in the question

20 m/s for 10 minutes

And, the 30 m/s for another 10 minutes

Based on the above information, the average speed is

As we know that

\(Average\ speed = \frac{Total\ distance}{Total\ time}\)

\(= \frac{20\times10\times60 + 30\times10\times60 }{20\times60}\)

= 25 m/s

1 hour = 60 minutes

1 minute = 60 seconds

Hence, the average speed is 25 m/s

In the question,  there are miles is given but instead of this we use the minutes as we have to find out the average speed and time should not be in miles it should be in minutes, hour or seconds

Therefore we considered the same

what exercises most beneficial for your overall health​

Answers

Answer:

Endurance, or aerobic

Strength, or resistance training

Balance

Flexibility

Explanation:

Answer:

Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).

Which situation shows where the levels of potential energy and kinetic energy are balanced and equal?

Answers

Answer: Potential energy or stored energy, and kinetic energy, the energy due to motion can be balanced in the process of converting kinetic energy to potential energy during an uphill motion

A roller coaster car going uphill

Explanation:

Answer: A car moving at a steady speed

Proof of validity is shown below.

Which situation shows where the levels of potential energy and kinetic energy are balanced and equal?

Which item is a piece of golf equipment that supports the ball so the player can strike it?
O fairway
O divot
O par
O tee

Answers

its a golf tee. so D

At t = 0, one toy car is set rolling on a straight track with initial position 13.0 cm, initial velocity -3.6 cm/s, and constant acceleration 2.20 cm/s2. At the same moment, another toy car is set rolling on an adjacent track with initial position 11.5 cm, initial velocity 5.40 cm/s, and constant zero acceleration. (a) At what time, if any, do the two cars have equal speeds? (Enter NA if the cars never have equal speeds.) s (b) What are their speeds at that time? (Enter NA if the cars never have equal speeds.) cm/s (c) At what time(s), if any, do the cars pass each other? (If there is only one time, enter NA in the second blank. If there are two times, enter the smaller time first. If they never pass, enter NA in both blanks.) s s (d) What are their locations at that time? (If there is only one position, enter NA in the second blank. If there are two positions, enter the smaller position first. If they never pass, enter NA in both blanks.) cm cm (e) Explain the difference between question (a) and question (c) as clearly as possible.

Answers

Answer:

that's too much to read

I need help with the question 8B

I need help with the question 8B

Answers

The answer of this is C

What is the weight of 5kgs of apples on Earth?

Answers

Answer:5kgs

Explanation:

The following problem applies to questions 8 and 9: a glass window acquires a net negative charge on its surface after being cleaned. Particles of dust, which are usually charged positively, start accelerating toward the window. If a particle travels a distance of 1 meter before reaching the window, in a time duration of 10 sec, and if the mass of the particle is 1 micro-gram and the charge on the particle is 10-12 Coulomb, then the magnitude of the electric field intensity is Group of answer choices

Answers

Answer:

the magnitude of the electric field intensity is 20 N/C

Explanation:

 Given the data in the question;

mass m = 1 micro gram = 1 × 10⁻⁹ kg

time duration t = 10 sec

distance s = 1 m

the charge on the particle q = 10⁻¹² Coulomb

force applied on a charged particle due to electric field E is;

F = Eq  ------ equ 1

where q is the charge on the particle.

Also, force on a particle with mass m  will be;

F = ma  ------ equ

where a is acceleration

so F = ma = Eq

ma = Eq -------- equ 3

using kinetic equation

Distance = 1/2×at²

where a is acceleration and t is the time period

now lets consider that initial velocity is zero (0)

Here;

1 m = 1/2 × a × ( 10 s )²

1 m = a × 50 s²

a = 1 m / 50 s²

a = 0.02 m/s²

so, from equation 3

ma = Eq

E = ma / q

we substitute

E = (1 × 10⁻⁹ kg × 0.02) / 10⁻¹² Coulomb

E = 2 × 10⁻¹¹ / 10⁻¹²

E = 20 N/C

Therefore, the magnitude of the electric field intensity is 20 N/C

In the human femur, bone tissue is strongest in resisting compressive force,
approximately half as strong in resisting tensile force, and only about one-
fifth
as strong in resisting shear force. If a tensile force of 8000 N is sufficient to
produce a fracture, how much compressive force will produce a fracture?
How much shear force will produce a fracture

Answers

The compressive force that would be enough to produce a fracture is 4000 N.

What is the force?

We know that the femur is one of the most important bones that we have in the human body. In this case, we have been told that In the human femur, bone tissue is strongest in resisting compressive force, approximately half as strong in resisting tensile force, and only about one- fifth as strong in resisting shear force.

Then we know that;

Tensile force = 8000

The compressive force would be half of this magnitude as such;

Compressive force = 4000 N

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Please solve this, I’ll give brainliest if it’s correct but
AI answers will be reported!

Q6. Saul (30 kg) is tobogganing down a hill on a toboggan that has a mass of 10 kg. Part way down, when he is still 20 m (measured vertically) above the bottom of the hill, he passes his sister Nadia at a velocity of 15 m/s. [9 marks]

(a) What is the total energy of Saul and the toboggan?

(b) What is the height of the hill?

(c) What will Saul’s velocity at the bottom of the hill be?

(d) What will Saul’s height be when he is moving at a velocity of 9.5 m/s?

Answers

part a.

the total energy of Saul and the toboggan  is 70530 J

part b.

The height of the hill is  235.1 m.

part c.

Saul's velocity at the bottom of the hill will be  22.3 m/s.

part d.

Saul's height when he is moving at a velocity of 9.5 m/s is 10.5 m

How do we calculate?

The total energy of Saul and the toboggan is the addition all of potential energy and kinetic energy.

we know that the initial total energy = potential energy at top of hill

Therefore total energy is gien as

initia total energy  = mass of Saul + mass of toboggan x gravity x height

initia total energy  = (30 kg + 10 kg) x (9.81) x (20 m)

initia total energy  = 5886 J

Total energy  = potential energy + kinetic energy

Total energy = (30 kg + 10 kg) (9.81 ^2) x (20) + (30 kg + 10 kg) x (15)^2/2

= 70530 J

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A student pushes a 6.0-kg box to the right with a
constant force FSB. The box moves at a constant velocity. The box experiences a
friction force f from the floor.
a. What type of friction does the box experience? Explain your reasoning.
b. Identify the four forces acting on the box.

Answers

a. The box experiences static friction because the box is moving at a constant velocity. Static friction is the force that opposes the initiation of motion between two surfaces that are in contact and at rest relative to each other.

b. The four forces acting on the box are:

1. Force of gravity (weight), which acts downwards towards the center of the earth, and has a magnitude of mg, where m is the mass of the box and g is the acceleration due to gravity.

2. Normal force, which is the force exerted by the floor on the box, perpendicular to the surface of contact, and has a magnitude of mg when the box is at rest or moving at a constant velocity.

3. Force applied by the student, denoted as FSB, which is directed to the right and has a magnitude that is equal to or greater than the force of friction.

4. Force of friction, denoted as f, which opposes the motion of the box and is directed to the left, opposite to the direction of the applied force. The magnitude of the frictional force is equal to the magnitude of the force applied by the student, as long as the box is moving at a constant velocity.
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