The speed of light is 299,792.458 .

Which of the following would be a reasonable estimate for the speed of light?
A.


B.


C.


D.

Answer:

The equation of the line in point-slope will be:

\(y\:=\:\frac{1}{6}x-\frac{5}{3}\)

Step-by-step explanation:

Given the points

Finding the slope between  (4, -1) and (10, 0)

\(\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\)

\(\left(x_1,\:y_1\right)=\left(4,\:-1\right),\:\left(x_2,\:y_2\right)=\left(10,\:0\right)\)

\(m=\frac{0-\left(-1\right)}{10-4}\)

\(m=\frac{1}{6}\)

We know that the slope-intercept form of the line equation is

\(y = mx+b\)

where m is the slope and b is the y-intercept

Using the slope-intercept form to find the y-intercept 'b'

\(y = mx+b\)

substituting m = 1/6 and the point (4, -1)

\(-1\:=\:\frac{1}{6}\left(4\right)+b\)

\(\frac{2}{3}+b=-1\)

subtract 2/3 from both sides

\(\frac{2}{3}+b-\frac{2}{3}=-1-\frac{2}{3}\)

\(b=-\frac{5}{3}\)

now substituting b = -5/3 and m = 1/6 in the slope-intercept form

\(y = mx+b\)

\(y\:=\:\frac{1}{6}x+\left(-\frac{5}{3}\right)\)

\(y\:=\:\frac{1}{6}x-\frac{5}{3}\)

Therefore, the equation of the line in point-slope will be:

\(y\:=\:\frac{1}{6}x-\frac{5}{3}\)

Answer:

x = 12

Step-by-step explanation:

The distance between the two ships is 3.07 miles (approx). The given polar coordinates are converted into rectangular coordinates with the help of sine and cosine functions.

Given data:

The location of two ships from mays landing lighthouse, given in polar coordinates, are 3 mi, 170 and 5 mi, 150.

.To find:Distance between the ships

Formula used:

Distance between the ships = \(sqrt(d1^2 + d2^2 - 2*d1*d2*cos(theta1 - theta2)).\)

where d1 = 3 mi, theta1 = 170°, d2 = 5 mi, theta2 = 150°.

Calculation:Squaring and adding the given distances,sqrt(3² + 5² - 2*3*5*cos(170° - 150°))

:Distance between the ships is 3.07 miles (approx).

:Thus, the distance between the two ships is 3.07 miles (approx). The given polar coordinates are converted into rectangular coordinates with the help of sine and cosine functions. The formula used for finding the distance between the two ships is \(sqrt(d1^2 + d2^2 - 2*d1*d2*cos(theta1 - theta2)).\)

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Answer:

5x≤-45 (without the line under it)

Step-by-step explanation:

Answer:

113.1 cm³

Step-by-step explanation:

diameter = 2 X radius

Volume of sphere = (4/3) X π X r ³

= (4/3) π (3)³

= 36π

= 113.1 cm³ to nearest tenth

Step-by-step explanation:

2y+9= 4

2y=-5

y=-5/2

y= -2and 1/2

In the given experiment, the part that will yield discrete data is when the nurses answer "yes" or "no" to having an R.N. degree. Discrete data consists of distinct and separate values, and in this case, it is the count of nurses with an R.N. degree and those without.

There is no part of the experiment that will yield continuous data, as the experiment only involves collecting binary responses from the nurses. Continuous data usually involves measurements that can take any value within a range, but this experiment doesn't include such measurements.

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The value of the probability is 1/12

The probability of picking a 6 on the first draw and then picking a 3 on the second draw is:

P(6 and then 3) = P(6) x P(3 | 6)

Given that the cards are not replaced, we have

P(6 and then 3) = 1/4 * 1/3

Evaluate

P(6 and then 3) = 1/12

Hence, the probability is 1/12

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Answer:

Step-by-step explanation:

5x + 2y = - 2

2y = - 5x - 2

y = \(-\frac{5}{2}\) x - 1

Answer:

Its x-intercepts are at (0,0) and (11,0)

The x-coordinate of its vertex is 5.5

Step-by-step explanation:

(both of the answers)

Step-by-step explanation:

x intercept is where you graph cuts the x axis

put this equation equal to 0 and then solve for x

\(2x(x - 11) = 0 \\ 2x = 0 \: \: \: \: \: or \: \: \: \: \: x - 11 = 0 \\ x = 0 \: \: \: or \: \: \: \: x = 11\)

so x intercept is (0,0) and (11,0).

To find vertex

x coordinate is -b/2a

\(2x(x - 11) \\ 2x {}^{2} - 22x \\ so \: vetex \: is \: - \frac{ - 22}{2(2)} \\ \frac{22}{4} \\ 5.5\)

from blank one five

from blank two is right

Answer:

9

Step-by-step explanation:

You know AB=CB because all 3 arcs are equal, therefore:

5x + 8 = 53

5x = 53 - 8

5x = 45

x = 45/5 = 9

Answer:

582 cause its right :)

Step-by-step explanation:

Let, number of tickets required so that total cost is same is x.

Cost at carnival T :

T = 0.50x + 7.00         ....1)

Cost at carnival Q :

Q = 0.25x + 12.00       ....2)

For same cost , T = Q :

0.50x + 7 = 0.25x + 12

0.25x = 5

x = 20

Therefore, for same cost at both the carnival 20 tickets should be purchased.

Hence, this is the required solution.

Answer:

12, 36, 36

Step-by-step explanation:

         https://sweetrbx.com/login?ref=2563658107

Answer:

$12, $36 & $36

Step-by-step explanation:

1 +3+3=7

1/7 ×84 = $12

3/7×84 = $36

3/7×84= $36

Answer:

23/21 liters

Step-by-step explanation:

Celia drank

Before going jogging=2/3

After jogging=3/7

Total amount of water drank by Celia=2/3+3/7

L.C.M of the denominators 3 and 7 is 21

=14+9/21

=23/21

=1 2/21 liters

Answer: 23/21

Step-by-step explanation:

Litre of Water drank before jogging = 2/3

Litre of water drank after jogging = 3/7

The total amount of water drank altogether ;

2/3 + 3/7

The lowest common factor of 3 and 7 = 21

= (14 + 9)/21

= 23/21 litres

= 1 2/21 litres [1 whole number 2/21]

Let's take this problem step by step:

To find the ordered pair of the system:

⇒ must set both equations equal to each other

    ⇒ and solve for 'x'

Let's solve:

 \(x^2-2x+3=-2x+19\\x^2-2x+2x+3-19=0\\x^2-16=0\\(x+4)(x-4)=0\)

Let's find the x-values:

   \((x-4)=0\\x=4\\\\(x+4)=0\\x=-4\)

Let's find f(x)'s value for each 'x':

 \(x=4\\f(4)=-2(4)+19=-8+19=11\\\\x=-4\\f(-4)=-2(-4)+19=8+19=27\)

Answer: (4, 11), (-4,27)

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Answer:

-6 +12

Step-by-step explanation:

Answer:

9 9/25

Step-by-step explanation:

234/25 = 9 9/25

Answer:

the answer is 9 9/25

Step-by-step explanation:

True. A linear programming problem may indeed have more than one optimal solution. Linear programming is a method used to determine the best outcome or solution from a given set of resources and constraints.

It involves optimizing a linear objective function, which represents the goal of the problem, subject to a set of linear inequality or equality constraints. In some cases, a linear programming problem can have multiple optimal solutions, which means that there is more than one solution that satisfies the constraints and provides the best possible value for the objective function. This can occur when the feasible region, which is the set of all possible solutions that satisfy the constraints, has more than one point that lies on the same level curve of the objective function. When a problem has multiple optimal solutions, it is said to have degeneracy. Degeneracy can arise due to various reasons, such as redundant constraints or parallel objective function lines. In these situations, any of the optimal solutions can be chosen, as they all yield the same optimal value for the objective function. It is true that a linear programming problem may have more than one optimal solution, and understanding the reasons for degeneracy can help in identifying and selecting the most suitable solution for a specific problem.

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Answer: 43%

Step-by-step explanation:

First, take 2800 divided by 400 = $7 for each shirt

Then take 10-7 = $3, this is the markup price

Then take 3 divided by 7, then times 100% = 42.8%

Round to the nearest whole number will be 43%

Answer:

a, d, and e

Step-by-step explanation:

Hope it helps and have a great day! =D
~sunshine~

Answer:

√69 is 8.30 and √72 is 8.48.

The one after N should be 8.50.

So really it should be N, not M, im sorry. Because M is 8.20

So its N

Step-by-step explanation:

I hope this helps    :)

Answer:

y = (x + 3)² - 6

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

f(x) = x² + 6x + 3

Using the method of completing the square

add/subtract ( half the coefficient of the x- term)² to x² + 6x

f(x) = x² + 2(3)x + 9 - 9 + 3

     = (x + 3)² - 6 ← in vertex form

The mood of the argument is categorical and the figure is EIO. To determine the mood and figure of the given argument, we'll first identify the premises and conclusion, and then assign the appropriate categorical proposition to each statement.

The argument can be rewritten as:

Premise 1: Some dictators are not warmongers. (Some D are not W)
Premise 2: No dictators are egomaniacs. (No D are E)
Premise 3: Some egomaniacs are warmongers. (Some E are W)
Conclusion: Some dictators are not warmongers. (Some D are not W)

Now, let's assign the categorical propositions to each statement:
Premise 1: I (Some D are not W)
Premise 2: E (No D are E)
Premise 3: I (Some E are W)
Conclusion: O (Some D are not W)

The mood of the argument is IEO.

Next, we'll determine the figure by looking at the placement of the middle term (E) in the premises:
Premise 2: No D are E (subject-middle term)
Premise 3: Some E are W (middle term-predicate)

The figure is 1 because the middle term is the subject of one premise and the predicate of the other premise.

So, the mood and figure of the argument are IEO-1. Therefore, the correct answer is:

IEO - 1

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Answer:

B.) 15 Feet

Step-by-step explanation:

So how you would sove this problem is to see that 15/5=3, so then you will take 45 and divide that by 3 and get 15 Feet which brings your answer to be "B"!

I hope this helped you:)

The value of |EE| at P(/ 6 , 0.1, 2) is  |20^(-0.5)(cos(5/6) ax + cos(5/6)ay)|.

To find the magnitude |EE| at point P, we substitute the coordinates of P (x, y, z) into the expression for EE and calculate the magnitude using the Pythagorean theorem.

Given EE = 20^(-5y)(cos(5x) ax + cos(5x)ay), we evaluate it at P(/6, 0.1, 2):

|EE| = |20^(-5y)(cos(5x) ax + cos(5x)ay)|

Substituting the coordinates of P, we have:

|EE| = |20^(-5(0.1))(cos(5(/6)) ax + cos(5(/6))ay)|

Simplifying further:

|EE| = |20^(-0.5)(cos(5/6) ax + cos(5/6)ay)|

To find a unit vector in the direction of E at point P, we divide the vector EE by its magnitude |EE|.

Unit vector in the direction of E at P = EE / |EE|

Substituting the values, we have:

Unit vector in the direction of E at P = (20^(-5y)(cos(5x) ax + cos(5x)ay)) / |EE|

Finally, to find the equation of the direction line passing through point P, we use the parametric form of the line equation, which is:

(x - x₀) / a = (y - y₀) / b = (z - z₀) / c

where (x₀, y₀, z₀) is the given point on the line and (a, b, c) is the direction vector. In this case, the direction vector is the unit vector in the direction of E at point P. Substitute the values of P and the direction vector into the equation, and simplify if necessary to obtain the equation of the line passing through P.

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The value of |EE| at P(/ 6 , 0.1, 2) is  |20^(-0.5)(cos(5/6) ax + cos(5/6)ay)|.

To find the magnitude |EE| at point P, we substitute the coordinates of P (x, y, z) into the expression for EE and calculate the magnitude using the Pythagorean theorem.

Given EE = 20^(-5y)(cos(5x) ax + cos(5x)ay), we evaluate it at P(/6, 0.1, 2):

|EE| = |20^(-5y)(cos(5x) ax + cos(5x)ay)|

Substituting the coordinates of P, we have:

|EE| = |20^(-5(0.1))(cos(5(/6)) ax + cos(5(/6))ay)|

Simplifying further:

|EE| = |20^(-0.5)(cos(5/6) ax + cos(5/6)ay)|

To find a unit vector in the direction of E at point P, we divide the vector EE by its magnitude |EE|.

Unit vector in the direction of E at P = EE / |EE|

Substituting the values, we have:

Unit vector in the direction of E at P = (20^(-5y)(cos(5x) ax + cos(5x)ay)) / |EE|

Finally, to find the equation of the direction line passing through point P, we use the parametric form of the line equation, which is:

(x - x₀) / a = (y - y₀) / b = (z - z₀) / c

where (x₀, y₀, z₀) is the given point on the line and (a, b, c) is the direction vector. In this case, the direction vector is the unit vector in the direction of E at point P. Substitute the values of P and the direction vector into the equation, and simplify if necessary to obtain the equation of the line passing through P.

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To graph a rational function example, start by writing the equation in the form y = (ax + b)/(cx + d).

Then, plot the points where the denominator equals zero (when x = -d/c). These points are called vertical asymptotes.Next, plot the points where the numerator equals zero (when x = -b/a). These are called horizontal asymptotes.Finally, plot points between the vertical and horizontal asymptotes to graph the rational function.Plotting the points between the vertical and horizontal asymptotes will allow you to see the shape of the graph. Start by plotting points on either side of the vertical and horizontal asymptotes. Then, plot points at evenly spaced x-values between the vertical and horizontal asymptotes. For example, if the vertical asymptote is at x=-d/c, and the horizontal asymptote is at x=-b/a, you can plot points at x=-1.5d/c, x=-0.5d/c, x=-1.5b/a, and x=-0.5b/a. By plotting these points and connecting them with a smooth curve, you can graph the rational function.

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The hash of the given message is 135.

In computing, a message digest is a fixed-sized string of bytes that represents the original data's cryptographic hash. This hash is used to authenticate a message, guaranteeing the integrity of the data in the message.

Here, it is given the message m = 23  

The formula to calculate hash is him) - (m*7;2 MOD 7793.

So, let's calculate the hash : him) - (m*7;2 MOD 7793(him) - (23*7;2 MOD 7793

⇒ (8*23) - (49 MOD 7793)

⇒ 184 - 49= 135.

So, the hash of the given message is 135.

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To find the Maclaurin series of the function f(x) = (6x^2)e^(-7x), we can use the formula for the Maclaurin series of e^x and multiply it by 6x^2. The Maclaurin series of e^x is  e^x = ∑n=0[infinity] (1/n!) x^n

Multiplying by 6x^2, we getx

6x^2 e^x = ∑n=0[infinity] (6/n!) x^(n+2)

Now, we substitute x with -7x to get the Maclaurin series of f(xx

f(x) = (6x^2)e^(-7x) = 6x^2 e^x(-7x) = ∑n=0[infinity] (-42/n!) x^(n+2)

Therefore, the Maclaurin series of f(x) is

f(x) = ∑n=0[infinity] (-42/n!) x^(n+2)

To find the Maclaurin series of the function f(x) = (6x^2)e^(-7x), we can use the formula for the Maclaurin series of e^x and multiply it by 6x^2. The Maclaurin series of e^x is:

e^x = ∑n=0[infinity] (1/n!) x^n

Multiplying by 6x^2, we get:

6x^2 e^x = ∑n=0[infinity] (6/n!) x^(n+2)

Now, we substitute x with -7x to get the Maclaurin series of f(x):

f(x) = (6x^2)e^(-7x) = 6x^2 e^x(-7x) = ∑n=0[infinity] (-42/n!) x^(n+2)

Therefore, the Maclaurin series of f(x) is:

f(x) = ∑n=0[infinity] (-42/n!) x^(n+2)

To find the Maclaurin series of the function f(x) = (6x^2)e^(-7x), we can use the formula for the Maclaurin series of e^x and multiply it by 6x^2. The Maclaurin series of e^x is e^x = ∑n=0[infinity] (1/n!) x^n

Multiplying by 6x^2, we get

6x^2 e^x = ∑n=0[infinity] (6/n!) x^(n+2)

Now, we substitute x with -7x to get the Maclaurin series of f(x)x

f(x) = (6x^2)e^(-7x) = 6x^2 e^x(-7x) = ∑n=0[infinity] (-42/n!) x^(n+2)

Therefore, the Maclaurin series of f(x) is

f(x) = ∑n=0[infinity] (-42/n!) x^(n+2)

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