The space probe Deep Space 1 was launched on October 24, 1998. Its mass was 474 kg. The goal of the mission was to test a new kind of engine called an ion propulsion drive. This engine generated only a weak thrust, but it could do so over long periods of time with the consumption of only small amounts of fuel. The mission was spectacularly successful. At a thrust of 56 mN how many days were required for the probe to attain a velocity of 790 m/s (1770 mi/h), assuming that the probe started from rest and that the mass remained nearly constant

Answers

Answer 1

Answer:

T = 77.5 days.

Explanation:

Assuming no other forces acting on the probe, according to Newton's 2nd law, we can find the acceleration attained by the probe due to the thrust (assumed constant) as follows:

       \(a = \frac{F}{m} = \frac{56e-3N}{474kg} = 1.18 e-4 N (1)\)

Since the probe started from rest, we can express the final speed applying the definition of acceleration, as follows:

       \(v_{f} = a* t (2)\)

We can solve for t (in seconds) as follows:

       \(t = \frac{v_{f}}{a} = \frac{790m/s}{1.18e-4m/s2} = 6694915 s (3)\)

Since 1 day = 86400 s, we can find the time in days as follows:

       \(t_{days} = \frac{t_{sec} }{1 day} = \frac{6694915s}{86400s} = 77.5 days (4)\)


Related Questions

Find weather X^N plus Y^N is divisible by X - Y (y not equal to 0) or not

Answers

The expression \(X^{N} + Y^{N}\)is not divisible by X - Y (where Y is not equal to 0).

To determine whether the expression \(X^{N} + Y^{N}\) is divisible by X - Y (where Y is not equal to 0), we can use the factor theorem and the property of binomial expansion.

The factor theorem states that if a polynomial P(x) is divisible by (x - a), then P(a) equals zero. In our case, if \(X^{N} + Y^{N}\) is divisible by (X - Y), then when we substitute X = Y into the expression, the result should be zero.

Let's substitute X = Y into the expression:

\(Y^{N} + Y^{N}\)

Since \(Y^{N}\) is equivalent to \(Y^{N}\) , the expression becomes:

2(\(Y^{N}\))

We can see that the expression 2(\(Y^{N}\)) is not equal to zero unless Y is equal to zero. Therefore, if Y is not equal to zero, \(X^{N} + Y^{N}\) is not divisible by X - Y.

In summary, unless Y is equal to zero, the expression \(X^{N} + Y^{N}\) is not divisible by X - Y according to the factor theorem and the given condition.

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A. A cord passing over an easily turned pulley (one that is both massless and frictionless) has 7kg mass hanging from one end and a 9kg mass hanging from the other end as shown below. G 7.0 kg 9.0 ks This arrangement is known as Atwood's machine. Calculate the (i). acceleration of the masses (ii). tension in the cord. [2.5 ​

Answers

Answer:

M g = M a = a (9 - 7) kg      with the two masses going in different directions

(7 + 9) kg * g = a * 2 kg       2 kg effective in prducing acceleration

a = 16 / 2 * g = 9.8 m/s^2 / 8 = 1.23 m/s^2

M1 a = T - M1 * g        T producing upward acceleration of 1.23 m/s^2

T = 7 (a + g) = 7 * 11 = 77 N

Check:

M2 a =  M2 * g - T          M2 producing downward acceleration

T = M2 (g - a) = 9 * (9.8 - 1.23) = 77 N

Larry the Rock was lonely for multiple years. The inertia that Larry possessed intimated those who walked past by it, therefore people never moved Larry.
Larry constantly watched people and cars accelerate past him but sadly he has never had the opportunity to experience acceleration.
But one day, David decides to let Larry experience acceleration and tried to push him. His friend Pancho heard about this and decided to help out. But
because Pancho was not listening in Physics class, he was pushing Larry from the opposite side of David with an equal amount of force and Larry was sad
he still did not get to move.
What type of Equilibrium is Larry going through?
O Static Equilibrium
O Kinetic Equilibrium
O Dynamic Equilibrium
O Geo Equilibrium
O Francesca Equilibrium

Answers

First option is correct.Larry the Rock is going through Static Equilibrium.

In this situation, Larry is at rest and remains stationary despite the forces acting on him. While David and Pancho are exerting equal forces from opposite sides, their forces cancel each other out, resulting in a net force of zero. As a result, Larry does not move or experience any acceleration.

Static equilibrium occurs when an object's forces and torques balance each other, leading to a stable, balanced state. In this case, the forces exerted by David and Pancho are equal in magnitude and opposite in direction, creating a condition where the resultant force is zero. As a result, Larry remains in a state of rest, unable to experience any movement or acceleration.Therefore, the type of equilibrium that Larry the Rock is going through is Static Equilibrium.

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5. How did your calculated final temperature compare with the actual temperature of the
air-metal mixture? Why or how did you make the prediction that you did?

Answers

To calculate the final temperature of an air-metal mixture, we need to use the principle of heat transfer.

The heat transfer equation states that the heat gained by the metal is equal to the heat lost by the air. This equation can be written as:

mcΔT = mairCpΔT

How to make prediction the of the final temperature?

To make a prediction of the final temperature, we need to consider factors such as the thermal conductivity of the metal and air, the specific heat capacities of the materials, and the heat transfer coefficients at the metal-air interface. Additionally, the shape and size of the metal object and the surrounding environment can affect the final temperature.

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if an object with a mass of 30kg is propelled with a force of 10 N what rate will the object accelrate at

Answers

The given scenario involves calculating the acceleration of an object propelled by a force of 10 N with a mass of 30 kg. The object will accelerate at a rate of 0.333 m/s².

The equation for calculating acceleration is:

acceleration = force / mass

where acceleration is measured in meters per second squared (m/s²), force is measured in Newtons (N), and mass is measured in kilograms (kg).

Given:

mass = 30 kg

force = 10 N

To find the acceleration, we can substitute these values into the equation:

acceleration = force / mass

acceleration = 10 N / 30 kg

acceleration = 0.333 m/s²

Therefore, the object will accelerate at a rate of 0.333 meters per second squared. This means that for every second that passes, the object's velocity will increase by 0.333 meters per second.

It's worth noting that the direction of the force is also important in determining the direction of the acceleration. If the force is applied in the same direction as the motion of the object, it will speed up, but if the force is applied in the opposite direction, it will slow down.

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Car A and car B set off from the same point to travel the same journey. Car A sets off three minutes before car B. If car A travels at 60 km/h and car B travels at 70 km/h, how many kilometres from the starting point will the two cars draw level?​

Answers

Answer:

Let's start by calculating how much of a head start Car A has in distance before Car B starts.

In 3 minutes, Car A will have travelled:

d = r * t = (60 km/h) * (3/60) h = 3 km

So when Car B starts, Car A is 3 km ahead.

Now let's consider the time it takes for both cars to meet. Let's call the time it takes for both cars to meet t.

During that time, Car A will travel at a speed of 60 km/h, and Car B will travel at a speed of 70 km/h.

The distance that Car A will travel during that time is:

dA = 60 km/h * t

The distance that Car B will travel during that time is:

dB = 70 km/h * t

The total distance between the two cars when they meet is:

d = dA + dB

We want to find the value of t that makes dA + dB = 3 km (the distance that Car A is ahead of Car B when Car B starts).

Substituting the expressions for dA and dB, we get:

60 km/h * t + 70 km/h * t = 3 km

Simplifying, we get:

130 km/h * t = 3 km

t = 3 km / 130 km/h

t = 0.0231 h

Now we can calculate the distance that both cars will have travelled when they meet:

dA = 60 km/h * 0.0231 h = 1.38 km

dB = 70 km/h * 0.0231 h = 1.61 km

d = dA + dB = 1.38 km + 1.61 km = 2.99 km

Therefore, the two cars will draw level after travelling approximately 2.99 km from the starting point.

What net force would be required to accelerate a 5 Kg object 2 m/s2? [show all work, including the

equation, substitutions with units, and answer with units]

Answers

Answer:

10 Newtons.

Explanation:

F=MA

F=(5kg)(2 m/s^2)

10 N

What is a sample that is treated exactly like the other experimental groups except that the independent variable is not applied to it is called ?

Answers

Answer:

control

Explanation:

you always need a control in experiment

Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.

Answers

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

How do i determine the quantity of heat energy?

First, we shall list out the given parameters from the question. This is shown below:

Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Data:
AB = 20cm
BC = 30cm
CD is vertical
All members are massless except for BC that has uniform linear density = 1kg/m
Question:
Calculate the moment M applied to the disc that holds the system in equilibrium

Data:AB = 20cmBC = 30cmCD is verticalAll members are massless except for BC that has uniform linear density

Answers

The moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

To calculate the moment M applied to the disc that holds the system in equilibrium, we can use the principle of moments. The principle of moments states that the sum of the clockwise moments about a point is equal to the sum of the counterclockwise moments about the same point.

Let's consider point C as the pivot point. The clockwise moments are produced by the weight of BC and the unknown moment M, while the counterclockwise moments are produced by the weight of AB.

The weight of BC can be calculated as W_BC = linear density * length = 1 kg/m * 0.3 m = 0.3 kg.

The clockwise moment is given by M_clockwise = W_BC * BC = 0.3 kg * 0.3 m = 0.09 Nm.

Since the system is in equilibrium, the clockwise moments must balance the counterclockwise moments. Therefore, the counterclockwise moment produced by the weight of AB is also 0.09 Nm.

Hence, the moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

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Compared to falling on a stone floor, a wine glass may not break when it falls on a carpeted floor because the A) carpeted floor provides a smaller impulse. B) stone floor provides a smaller impulse. C) stopping time is shorter on the carpet. D) stopping time is longer on the carpet.

Answers

Answer: The correct option is D ( stopping time is longer on the carpet).

Explanation:

When an object is involved in a collision, for a given amount of TIME, it experiences a FORCE that will result in its MASS undergoing a change in VELOCITY. The relationship between the fours physical quantities in the sentence above are found in impulse and momentum.

Momentum is defined as the product of the mass of the body and it's velocity while impulse is the product of force and time. The impulse experienced by an object is always equal to the change in its momentum. This is known as IMPULSE-MOMENTUM CHANGE THEOREM and it can be represented in the equation below :

Impulse= Force× time(t)

Change in Momentum = Mass(M) × velocity change ( v - u).

Therefore: F×t = M ( v - u).

In the application of impulse-momentum change in real life situations, force exerted on an object is affected by the collision time because force is inversely proportional to time. That is, the greater the time over which a collision occurs, the smaller the force acting upon the object. Thus, to minimize the effect of force on an object involved in a collision, the time must be increased.

From the example given, the wine glass may not break when it falls on a carpeted floor because the carpet minimize the effect of force on the glass by increasing its stopping time.

Regarding memory, conscious is to _____ as unconscious is to _____. Please choose the correct answer from the following choices, and then select the submit answer button. Answer choices explicit memory; implicit memory shallow processing; deep processing echoic memory; iconic memory recognition; recall

Answers

Regarding memory, conscious is to explicit memory as unconscious is to implicit memory.

A series RL circuit is connected to a 130-V ac source. If the voltage across the resistor is 85 V, find the voltage across the inductor. The voltage across the inductor is V.

Answers

The voltage across the inductor will be 98.361 volts.

Inductor is a passive component used in most power electronic circuits to store energy in the form of magnetic energy when electricity is applied to it.

It is described by its characteristic nature of inductance, which is defined as the ratio of voltage to the rate of change of current.The inductance measured by the inductor has the SI unit as Henry (H).

In inductive reactance (RL), the current through the inductor changes when a potential difference is developed across it.

The potential difference and the rate of change of the current are proportional to each other.

Mathematically, V = \(\sqrt{Vr^{2} + Vl^{2} }\)

Vr = 85 v

V = 130 v

Vl can be calculated as

Vl² = V² - Vr²

Vl² = 130² - 85²

Vl² = 16900 - 7225

Vl² = 9675 v

Vl = 98.361 v

The voltage across the inductor is 98.361 v.

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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?

Answers

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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What is an example of intellectual development?

Answers

Answer:

Emotional and Social Development

During the preschool years, your little one is learning to read emotional cues and is getting better at relating to other people, according to the New York University Child Study Center 1⭐

⭐This is a verified and trusted source

New York University Child Study Center: The Preschool Years: (Ages Four and Five) Expectations and Challenges

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. He can empathize with others and make friends with other children his own age. By his fifth birthday, your preschooler often seeks friends of the same gender and shows a preference for playing with other children, rather than adults. Your preschooler also engages in pretend play and can probably tell the difference between reality and fantasy, according to the American Academy of Pediatrics.

Physical Development

There's a big difference between a 2-year-old and a 5-year-old. During the preschool years, your child develops in many physical ways. She goes from toddling around unsteadily to being able to jump, stand on one foot, walk up and down stairs and walk backward, according to the New York University Child Study Center 1⭐

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New York University Child Study Center: The Preschool Years: (Ages Four and Five) Expectations and Challenges

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. By the time she's 5, your little one should also be able to ride a tricycle, build a block tower, paint on paper, skip, throw a ball, dress and undress and begin drawing recognizable objects, adds the University of Illinois Extension.

A cubic box is completely filled with 2800 g of water. What is the length of one side of the box, in meters?
m
Explain your reasoning.
Since the density of water is
cm3 is
g/cm3, then the volume of 2800 g of water is
cm on each side. Converting [ cm to meters, the cube is
Proy
13 of 15
⠀⠀⠀
Next
cm³. A cubic box with a volume of [
m on each side.

A cubic box is completely filled with 2800 g of water. What is the length of one side of the box, in

Answers

The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.

Jupiter's Great Red Spot is
1.slowly shrinking
2.a large storm
3.smaller than Saturn's spot
4.a large area of liquid hydrogen

Answers

Answer:    

2 : A large storm

Explanation: I hope this helps

A car with a mass of 950 kg is tied to a crane by a strong cable and being lowered at a rate of 1.2 m/s2. Draw a free-body diagram showing all the forces acting on the car. Include the values of each force. Show all calculations.

Answers

Answer:

Data that we know:

Mass of the car = 950kg.

Gravitational acceleration = -9.8m/s^2.

Acceleration of the car = -1.2 m/s^2.

(the negative signs are because that accelerations point downwards)

Now, the total acceleration of the car is:

-1.2m/s^2 = -9.8m/s^2 + Ac.

Where Ac is the acceleration caused by the cable, that is opposite to the acceleration of the car:

Ac = 9.8m/s^2 - 1.2m/s^2 = 8.6m/s^2.

Now we have the accelerations, remember that by second's newton law we have:

F = m*a

Then the force of the cable is:

Fc = 8.6m/s^2*950kg = 8,170N.

The gravitational force is:

Fg = -9.8m/s^2*950kg = -9,310N

The net force is:

Ft = 8,170N - 9,310N = -1,140N.

Below is the free body-diagram.

A car with a mass of 950 kg is tied to a crane by a strong cable and being lowered at a rate of 1.2 m/s2.

One of the asteroids, Ida, looks like an elongated potato. Surprisingly it has a tiny (compared to Ida) spherical moon! This moon called Dactyl has a mass of 4.20 × 10^16 kg, and a radius of 1.57 × 10^4 meters, according to Wikipedia. Ida has a radius of 3.14 x 10^4 meters.
Find the acceleration of gravity on the surface of this little moon.

Answers

Answer:

g = 0.0114 m/s²

Explanation:

The value of acceleration due to gravity on the surface of the moon can be given by the following formula:

\(g = \frac{Gm}{r^2}\)

where,

g = acceleration due to gravity on the surface of moon = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m = mass of moon = 4.2 x 10¹⁶ kg

r = radius of moon = 1.57 x 10⁴ m

Therefore,

\(g= \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(4.2\ x\ 10^{16}\ kg)}{(1.57\ x\ 10^4\ m)^2}\)

g = 0.0114 m/s²

A rocket, initially at rest, steadily gains speed for 4.00s while traveling upwards
70.0m.
What was the rocket's final speed?

Answers

Answer:

\(35.0\; \rm m \cdot s^{-1}\).

Explanation:

The question states that the rocket gains speed steadily. In other words, the acceleration of this rocket in that four seconds would be constant.

Let \(a\) denote the acceleration of this rocket.Let \(t\) denote the duration of the acceleration.Let \(v_{0}\) denote the initial velocity of this rocket.Let \(x\) denote the displacement of this rocket.

Using information from the question:

\(t = 4.00\; \rm s\), \(x = 70.0\; \rm m\),\(v_{0} = 0\; \rm m \cdot s^{-1}\) since the rocket was "initially at rest".

Apply the SUVAT equation \(\displaystyle \frac{1}{2}\, a \cdot t^{2} + v_{0}\cdot t = x\) to find \(a\), the acceleration of this rocket.

\(\displaystyle \frac{1}{2}\, a \times (4.00\; {\rm s})^{2} + 0 = 70.0\; \rm m\).

\(\begin{aligned}a &= \frac{70.0\; \rm m}{\displaystyle \frac{1}{2} \times (4.00\; {\rm s})^{2}} = 8.75\; \rm m \cdot s^{-2}\end{aligned}\).

In other words, this rocket accelerated from rest at a constant \(a = 8.75\; \rm m \cdot s^{-2}\) for \(t = 4.00\; \rm s\). The final velocity of this rocket would be:

\(\begin{aligned}& v_{0} + a\cdot t \\ =\; & 0 \; \rm m\cdot s^{-1} + 8.75\; \rm m\cdot s^{-2} \times 4.00\; \rm s \\ =\; & 35.0\; \rm m\cdot s^{-1}\end{aligned}\).

Gansbsvskssvs oh alas no velwsjshe St h oh dog oh set of

Gansbsvskssvs oh alas no velwsjshe St h oh dog oh set of

Answers

The inverse of the mass is referred to as acceleration. The acceleration will be slower the more mass there is.

How does acceleration work?

Acceleration is the rate of change in an object's velocity over time in mechanics. One of the vector quantities is speed. The direction of the net force exerted on an object is what determines its acceleration. The change in velocity rate is referred to as acceleration. Usually, but not always, acceleration implies a change in velocity.

A circular object moving at a constant velocity is still accelerating because its velocity is changing in the opposite direction. In physics, acceleration is the rate of change in an object's velocity over time.  According to Newton's second law, the sum of all forces acting on an object determines its acceleration. Meters per second (ms²) is the SI unit for acceleration.

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Explain how the energy from the sun is transferred to fossil fuel?

Answers

Answer:

Fossil fuels are energy sources that come directly from nature. First, the sun's radiant energy is stored as chemical energy in plants by photosynthesis. When the plants die, they start decaying. After many years, the plants are turned into fossil fuels.

Explanation:

Fossil fuels rely on the Sun's energy because the energy in fossil fuels came from plants and algae as they performed photosynthesis, which requires sunlight.

When sunlight strikes a plant, some of the energy is trapped through photosynthesis and is stored in chemical bonds as the plant grows.

(u should paraphrase it)

The pressure at the bottom of a full barrel of water is Poriginal . Determine what happens to the pressure when the radius or height of the barrel is changed and water is added to make the barrel full again.

Answers

Answer:

a)   P' = P_original, b)  P ’= P_original + ρ  g Δh

Explanation:

The expression for nanometric pressure is

          P = ρ g h

where ρ  is the density of the liquid and h is the height

a) we change the radius of the barrel, but keeping the same height

as the pressure does not depend on the radius it remains the same

        P' = P_original

b) We change the barrel height

         h ’≠ h

we substitute in the equation

      P ’= ρ  g h’

      h ’= h + Δh

      P ’= ρ  g (h + Δh)

      P ’= (ρ  g h) + ρ  g Δh

      P ’= P_original + ΔP

In this case, the pressure changes due to the new height,

*if it is higher than the initial one, the pressure increases

*if the height is less than the initial one, the pressure is less

An owl has a mass of 4 kg. It dives to catch a mouse, losing 800 J of its GPE. What was the starting height of the owl, in meters?

Answers

The owl started out at a height of about 3.2 metres.

What is gravity?

Gravity is the force that draws objects toward the center of a planet or other object.

How do you determine this?

Gravitational potential energy (GPE) is calculated as follows:

GPE = mass x gravity x height. Since we are aware of the owl's mass (4 kg) and the change in GPE (-800 J) in this case, we can rewrite the formula to account for the height: tallness = GPE / (mass x gravity).

On Earth, the acceleration caused by gravity is roughly 9.8 m/s2.

By entering the known numbers, we obtain the height change as follows: -800 J / (4 kg x 9.8 m/s2) = -0.408 metres.

By combining the ultimate height (which is believed to be 0 metres) with the height change, we may get the initial height as follows: 0 m + (-0.408 m) = -0.408 m = 0.408 m = 3.2m.

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Please solve this.. I can't find R_th and V_oc at 6kohm....

Please solve this.. I can't find R_th and V_oc at 6kohm....

Answers

The current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

Thévenin's theorem states that any linear network of voltage and current sources and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor. The equivalent circuit provides the same output voltage and current as the original circuit for any external load connected to it.

To find the current I in the circuit using Thévenin's theorem, we need to follow these steps:

Step 1: Find the Thévenin equivalent voltage (Vth) across the 4 kΩ resistor.

To find Vth, we need to first find the open circuit voltage (Voc) across the 4 kΩ resistor. We can do this by removing the 4 kΩ resistor and finding the voltage between its two terminals using a voltage divider:

Voc = 6 kΩ/(2 kΩ + 6 kΩ) x 2 mA = 1.2 V

Next, we need to find the Thévenin equivalent resistance (Rth) across the 4 kΩ resistor. To do this, we need to short-circuit all the independent voltage sources (in this case, there is only one) and find the equivalent resistance seen from the terminals of the 4 kΩ resistor. With the 2 mA current source shorted out, the 2 kΩ and 4 kΩ resistors are in parallel:

Rth = 2 kΩ || 4 kΩ = 1.33 kΩ

Step 2: Replace the original circuit with the Thévenin equivalent circuit.

We can now replace the original circuit with the Thévenin equivalent circuit, which consists of a voltage source Vth = 1.2 V in series with a resistor Rth = 1.33 kΩ.

Step 3: Find the current I through the 4 kΩ resistor in the Thévenin equivalent circuit.

To find the current I, we can use Ohm's law:

I = Vth/(Rth + 4 kΩ) = 1.2 V/(1.33 kΩ + 4 kΩ) = 0.199 mA

Therefore, the current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

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A bug crawls 3.0 mm east, 4.0mm north, and then 5.0 mm at 45 north of east. Draw a diagram showing its displacements and determine its resultant displacement vector by use of the diagram.​

Answers

Answer:

Explanation is given

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A bug crawls 3.0 mm east, 4.0mm north, and then 5.0 mm at 45 north of east. Draw a diagram showing its

. In a classic clip on America’s Funniest Home Videos, a sleeping cat rolls gently off the top of a warm TV set. Ignoring
air resistance, calculate (a) the position and (b) the velocity of the cat after 0.100 s, 0.200 s, and 0.300 s.

Answers

After 0.100 s, the cat would be 0.049 m below its initial position, with a velocity of 0.98 m/s. After 0.200 s, the cat would be 0.196 m below its initial position, with a velocity of 1.96 m/s. Finally, after 0.300 s, the cat would be  0.441 m below its initial position, with a velocity of approximately 2.94 m/s.

To calculate the position and velocity of the sleeping cat after certain time intervals, we need to make some assumptions and use basic principles of physics.

Assuming the cat falls vertically downward due to gravity and ignoring air resistance, we can apply kinematic equations to solve the problem.

(a) Position:

Using the equation for the position of an object in free fall, h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is time, we can determine the position of the cat.

After 0.100 s: h = (1/2)(9.8 m/s^2)(0.100 s)^2 = 0.049 m (approximately)

After 0.200 s: h = (1/2)(9.8 m/s^2)(0.200 s)^2 = 0.196 m (approximately)

After 0.300 s: h = (1/2)(9.8 m/s^2)(0.300 s)^2 = 0.441 m (approximately)

(b) Velocity:

The velocity of the cat can be calculated using the equation v = gt, where v is the velocity and t is time.

After 0.100 s: v = (9.8 m/s^2)(0.100 s) = 0.98 m/s (approximately)

After 0.200 s: v = (9.8 m/s^2)(0.200 s) = 1.96 m/s (approximately)

After 0.300 s: v = (9.8 m/s^2)(0.300 s) = 2.94 m/s (approximately)

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A cement mixer of radius 2.5 m turns with a period of 50 sec/rev. What is the centripetal force of a
small piece of dried cement of mass 50 g stuck to the inside wall of the mixer?

Answers

The centripetal force acting on the small piece of dried cement is 0.01 N   when mass 50 g stuck to the inside wall of mixer.

Centripetal force :

Any force that alters velocity in the direction toward the center of a circular motion is referred to as a centripetal force. The centripetal force is produced by the portion of the force that is perpendicular to the velocity.

Evaluating :

The period of the cement mixer can be calculated as:

                                T = 50 sec/rev

                                     = 2πr/v,

where r is the radius of the mixer and

v is the velocity of the piece of dried cement.

Solving for v, we get v = 2πr/T.

Substituting the given values, we get

                               v = 2π(2.5 m)/(50 sec/rev)

                                         = 0.314 m/s.

The centripetal force acting on the piece of dried cement can be calculated using the formula :

                                     F = m v² / r,

where m is the mass of the cement,

v is the velocity, and

r is the radius of the mixer.

Substituting the given values, we get

                                 F = (0.05 kg)(0.314 m/s)²/(2.5 m)

                                                      = 0.01 N.

Therefore, the centripetal force acting on the small piece of dried cement is 0.01 N.

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A ray moving in water at 55.5 deg
enters plastic, where it bends to
48.7 deg. What is the index of
refraction for the plastic?
( water n = 1.33, Air n = 1.00 )

Answers

Answer:

Refractive index of the plastic = 1.46

Explanation:

By Snell's law,

\(\frac{\text{sin}\theta _{2} }{\text{sin}\theta _{1}}=\frac{n_1}{n_2}\)

Here, \(\theta _1\) = Angle of incidence in medium 1 (Plastic)

\(\theta_2\) = Angle of refraction in medium 2 (Water)

\(n_1\) = Refractive index of medium 1 (Plastic)

\(n_2\) = Refractive index of medium 2 (Water)

By substituting values in the formula,

\(\frac{\text{sin}(48.7)}{\text{sin}(55.5)}=\frac{1.33}{n_2}\)

\(n_2=\frac{1.33\times \text{sin}(55.5)}{\text{sin}(48.7)}\)

    = 1.46

Therefore, refractive index of the plastic = 1.46

A ray moving in water at 55.5 degenters plastic, where it bends to48.7 deg. What is the index ofrefraction

When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?

Answers

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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