the solubility of calcium arsenate (ca3(aso4)2, molar mass = 398.078 g) in water is measured to be 0.032 g/l. what is ksp for this salt?

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Based on the observations provided:

a. Between 2-3 minutes, the temperature changed from -1°C to 0°C. This change is due to the process of melting, where the ice changes from a solid to a liquid state.

b. The temperature remains constant between 30-35 minutes because all the water has been converted into steam and the heat supplied is being used as latent heat of vaporization. Latent heat of vaporization is the heat energy required to change a substance from a liquid to a gaseous state at its boiling point without any change in temperature.

To make the 150 ml of the 0.50 M solution of sucrose, we need grams of sucrose is 25.6 g.

Given that :

The volume of the sucrose = 150 mL

The molarity of the solution = 0.50 M

The molarity expression is given as :

The molarity = moles / volume in L

Moles = molarity × volume

          = 0.50 × 0.150

          = 0.075 mol

The molar mass of sucrose = 342.2 g/mol

The mass of sucrose = moles × molar mass

The mass of sucrose = 0.075 × 342.2

                                    = 25.6 g

Thus, the mass of sucrose is 25.6 g.

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All three substances mentioned - platinum, gold, and graphite - can be used as inert electrodes.  Option(  "any of the above." )

Inert electrodes are typically used in electrolytic cells or certain electrochemical reactions where the electrode material should not participate in the reaction itself. They act as conductors to facilitate the flow of electrons without undergoing any significant chemical changes.

Platinum and gold are commonly used as inert electrodes due to their high electrical conductivity and resistance to corrosion. Graphite, which is a form of carbon, is another commonly used inert electrode material due to its conductivity and inertness.

The choice of inert electrode depends on factors such as the specific reaction, cost, and desired properties.

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Answer:

.

Explanation:

In this situation, using a nonpolar solvent Q for recrystallization will allow for the separation of the polar solute X from the nonpolar impurity Y. Here's a step-by-step explanation of the process:

Dissolution: Dissolve the mixture of solute X and impurity Y in the nonpolar solvent Q at an elevated temperature. Since the nonpolar solvent Q matches the polarity of impurity Y, both the impurity and solvent will have similar intermolecular interactions, leading to their solubility in the solvent.

Filtration: While the solution is still hot, perform hot filtration to remove any insoluble impurities or solid particles. This step ensures that any large solid impurities are physically separated from the solution.

Cooling: Allow the solution to cool down slowly. As the temperature decreases, the solubility of solute X in the nonpolar solvent Q will decrease due to the differences in polarity. This will cause the solute X to crystallize out of the solution, while the impurity Y remains dissolved in the solvent.

Isolation: Once the crystals have formed, collect them by filtration or centrifugation. The crystals will contain the purified solute X, while the impurity Y will remain in the mother liquor (the remaining liquid after crystal formation).

Washing: Wash the collected crystals with a small amount of a nonpolar solvent, such as Q, to remove any residual impurity Y adsorbed on the crystal surface. This step ensures further purification of the solute X.

Drying: Finally, dry the purified solute X to remove any residual solvent and obtain the desired crystalline product.

By using a nonpolar solvent Q that matches the polarity of impurity Y, the recrystallization process selectively separates the polar solute X from the nonpolar impurity Y. This separation is based on the differences in polarity between the solute and impurity, allowing the solute to crystallize out of the solution while the impurity remains dissolved. The process ensures the purification of solute X, resulting in a high-quality crystalline product.

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The final temperature of the gas is approximately 40.96 Kelvin.

To determine the final temperature of the gas, we can use the ideal gas law, which states:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature in Kelvin.

First, let's convert the given temperatures to Kelvin. We have:

Initial temperature: -125 degrees Celsius = 148 K (approximate)

Final temperature: Unknown

The initial conditions of the gas are as follows:

Initial pressure (P1) = 1.25 atm

Initial volume (V1) = 1250 mL = 1.25 L (since 1 L = 1000 mL)

Initial temperature (T1) = 148 K

The final conditions of the gas are as follows:

Final pressure (P2) = 50.0 atm

Final volume (V2) = 325 mL = 0.325 L

Final temperature (T2) = Unknown

Using the ideal gas law, we can set up the following equation:

(P1 * V1) / T1 = (P2 * V2) / T2

Substituting the known values:

(1.25 atm * 1.25 L) / 148 K = (50.0 atm * 0.325 L) / T2

Simplifying the equation:

T2 = (50.0 atm * 0.325 L * 148 K) / (1.25 atm * 1.25 L)

T2 = 40.96 K

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Answer:

3.2 x 10-3 3.2 x 10-12 3.2 x 10-2 11.5

Explanation:

The number of the shared pairs in the molecule is two.

The term molecular geometry has to do with the actual arrangement of the electrons that are in the molecule. We know that the arrangement of the molecules that surround the atom is dependent on the nature of the electron pairs that surround the central atom.

Now we are told that  a central atom has 5 lone pairs and the molecular geometry is linear. The fact that the molecular geometry is linear shows that the number of the shared pairs is two.

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Substances with weak intermolecular forces will have higher vapor pressure

Vapor pressure is the measure of the tendency of a material to change into the gaseous or vapor state, and it increases with temperature. So, the temperature at which the vapor pressure at the surface of a liquid becomes equal to the pressure exerted by the surroundings is called the boiling point of the liquid. Or we can simply say that the when a liquid is boiling its vapor pressure is equal to the external pressure.

In the above given case we are comparing the intermolecular forces and understanding the concept of vapor pressure. So, vapor pressure of liquid is said to be  inversely proportional to the intermolecular forces between the atoms of the liquid. This relation means that if the liquid has stronger intermolecular forces than the rate of evaporation of liquid will be very low and hence it causes lower vapor pressure.

But whereas if the  intermolecular forces are weaker then the rate of evaporation of the liquid will be high and therefore it vaporizes fast which results in higher vapor pressure.

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Answer:

A

Explanation:

Evaporation It would become a crystal

Answer:

yes

Explanation:

n the winter, Earth tilts away from the Sun. In North America, around June 21, Earth tilts on its axis toward the Sun. This is called the summer solstice, and it is when the Northern Hemisphere has the most daylight of any time of the year.

Answer:

C

Explanation:

The molar mass of M₂(SO₄)₃ (approximately 114.0 g/mol), and the identity of M is likely calcium (Ca).

To determine the identity of the metal, we need to calculate the molar mass of the metal sulfate and compare it to the molar mass of potential metals.

Given;

Mass of M₂(SO₄)₃ = 0.738 g

Mass of BaSO₄ = 1.511 g

To find the molar mass of M₂(SO₄)₃, we need to convert the given masses to moles using their respective molar masses:

Molar mass of BaSO₄ = 137.33 g/mol + 32.07 g/mol + (4 * 16.00 g/mol) = 233.39 g/mol

Moles of BaSO₄ = Mass of BaSO₄ / Molar mass of BaSO₄

= 1.511 g / 233.39 g/mol

≈ 0.00647 mol

Since M₂(SO₄)₃ and BaSO₄ have a 1:1 stoichiometric ratio, the moles of M₂(SO₄)₃ will also be approximately 0.00647 mol.

Now, we can find the molar mass of M₂(SO₄)₃;

Molar mass of M₂(SO₄)₃ = Mass of M₂(SO₄)₃ / Moles of M₂(SO₄)₃

= 0.738 g / 0.00647 mol

≈ 114.0 g/mol

By comparing the molar mass of M₂(SO₄)₃ (approximately 114.0 g/mol) to the molar masses of various metals, we find that the closest match is for the metal calcium (Ca), whose molar mass is 40.08 g/mol. Therefore, the identity of M is likely calcium (Ca).

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--The given question is incomplete, the complete question is

"The metal, m, forms the sulfate  M₂(SO₄)₃, an 0.738 g sample of this sulfate is converted to 1.511 g BaSO₄. what is the identity of M?

Answer:

Objects with a higher density than the substance it is submerged in will sink. Objects with a lesser density than the substance it is submerged in will float. Sugar substitute is less dense than water and sugar or high fructose corn syrup is denser than water.

Explanation:

Answer: Stimulus

Explanation: The definition of Stimulus is "a thing or event that evokes a specific functional reaction in an organ or tissue," according to the Oxford Dictionary. So the book dropping and causing a noise is an example of a stimulus.

Answer:

A

Explanation:

molarity=moles of solute/liter of solution

molarity=0.26/0.3

molarity=0.87molar

The concentration of the HCl(aq) solution can be determined by using the titration data and the equation: Moles of acid = Moles of base.

To explain further, the titration data involves adding a solution of known concentration (the titrant) to a solution of unknown concentration (the analyte) until the reaction is complete. In this case, a known concentration of sodium hydroxide (NaOH) is added to the unknown concentration of hydrochloric acid (HCl).

The point at which the reaction is complete is called the endpoint and is indicated by a color change in the solution. By measuring the volume of NaOH used and knowing the concentration of NaOH, we can calculate the number of moles of NaOH that reacted with the HCl.

Using the balanced chemical equation for the reaction between HCl and NaOH, we can determine the number of moles of HCl in the solution. From this, we can calculate the concentration of the HCl solution using the formula:

Concentration of HCl = Moles of HCl / Volume of HCl in liters

By repeating the titration and calculating the average concentration from multiple trials, we can increase the accuracy of our measurement.

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Answer:

0.2 moles

Explanation:

The number of moles of aluminum for 1.204 x 0²³ atoms of aluminum is 0.2 moles. Hence, The correct answer is Option (A)

Mole is defined as the amount of the substance containing the same number of discrete entities (atoms, molecules, ions, etc) as there are atoms in a sample of pure 12C weighing exactly 12g.

The number of particles present in one mole of any substance = Avogadro Number = 6.023 x 10²³.

Formula to calculate Mole when number of particles is given ;

n = given number /  6.023 x 10²³

n = 1.204 x 10²³ / 6.023 x 10²³

n = 0.2 moles

Therefore, The number of moles of aluminum for 1.204 x 0²³ atoms of aluminum is 0.2 moles. Hence, The correct answer is Option (A)

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Nonpolar covalent compounds do not mix uniformly with water due to the differences in their polarities.

Some substances that form a separate layer when mixed with water are typically hydrophobic or nonpolar in nature. Examples include oils, greases, waxes, and certain organic solvents such as benzene, toluene, and hexane.

These substances have weak or no interactions with water molecules and tend to separate and form distinct layers when mixed with water.

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A molecular formula is a chemical formula for a molecular compound that shows the types and numbers of atoms in the compound's molecule. Ammonia is a nitrogen-hydrogen compound.

The total number of shared electrons in a molecule is 22.

Ionic and covalent compounds are the two types of compounds. Molecules are the most basic unit of a covalent compound, and they can be represented in a variety of ways.

Atoms are the smallest units of matter that retain an element's fundamental chemical properties. However, much of the study of chemistry is concerned with what happens when atoms combine to form compounds. A compound is a unique collection of atoms held together by chemical bonds.

The electrostatic attraction between the positively charged nucleus and the negatively charged electrons surrounding it holds the structure of the atom together, and the stability within chemical bonds is also due to electrostatic attractions. Consider the two most common types of chemical bonds: covalent bonds and ionic bonds. Two atoms share pairs of electrons in covalent bonds, whereas electrons are fully transferred between two atoms in ionic bonds.

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Answer:

Cl² is dichlorine

Explanation:

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A given substance that has a melting point of -7C and a boiling point of 59C exists as a liquid at room temperature conditions.

The states of matter refer to the separation of the molecules of a given material in certain temperature conditions.

The states of the matter are three and include the gaseous state, liquid state and solid-state.

In conclusion, a given substance that has a melting point of -7C and a boiling point of 59C exists as a liquid at room temperature conditions.

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Answer:

Large Cargo Ship

Explanation:

Hope it helped!

There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the compound formed using element X and Z is X \(_O\)Z●.

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound. Ionic compound are very hard. They have high melting and boiling point because of strong ion bond. The compound formed using element X and Z  with their respective atoms is  X \(_O\)Z●. Atoms are written on the foot of the element.

Therefore, the compound formed using element X and Z is X \(_O\)Z●.

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It is important to mark the solvent level on the chromatography paper as soon as you remove it from the petri dish in a chromatography of food dyes lab because if the solvent level is not marked as soon as possible, the solvent front can evaporate causing the results to be inaccurate.

Chromatography is a laboratory technique for separating a mixture into its individual components. The mixture is dissolved in a solvent and then placed in contact with a stationary phase. The components of the mixture are then separated based on their individual interactions with the stationary phase and the solvent. Chromatography of food dyes is a lab that is used to separate different food dyes that are present in a sample.

The sample is placed on chromatography paper which is then placed in a petri dish containing a solvent. As the solvent moves up the chromatography paper, the different dyes in the sample are separated based on their individual interactions with the paper and the solvent.

In a chromatography of food dyes lab, it is important to mark the solvent level on the chromatography paper as soon as it is removed from the petri dish because the solvent front can evaporate causing the results to be inaccurate. If the solvent front evaporates, the distance traveled by the different dyes will be shorter, making it appear as though they are less separated than they actually are.

By marking the solvent level as soon as possible, the distance traveled by the different dyes can be accurately measured, and the results will be more accurate.

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The reason why it is important to mark the solvent level on the chromatography paper as soon as you remove it from the petri dish is that the solvent level must be measured to calculate the Rf value. The Rf value is a way to quantify how far a particular compound travels in chromatography.

It is calculated as the distance traveled by the compound divided by the distance traveled by the solvent.The chromatography of food dyes lab is a experiment that aims to identify the dyes used in food products by using paper chromatography. The procedure includes: Cut a strip of chromatography paper and mark the solvent level using a pencil as soon as you remove it from the petri dish; prepare the chromatography solvent by mixing rubbing alcohol with water; then, spot the dyes on the chromatography paper using toothpicks or capillary tubes.

Afterwards, place the paper in the petri dish containing the solvent, making sure that the dyes do not touch the solvent, and cover it. Allow the solvent to travel up the paper until it reaches the solvent level mark. Once the solvent level has reached the mark, remove the paper from the petri dish and allow it to dry before analyzing the results.

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Answer:

3.02

Explanation:

In conclusion, d. Arginine is the amino acid with the highest isoelectric point, at 10.76.

The amino acid that has its isoelectric point at the highest pH is d. Arginine. An amino acid is an organic compound that contains both an amino (-NH2) and a carboxyl (-COOH) functional group. It also has a side chain (R group) that is unique to each of the 20 different amino acids.

The isoelectric point (pI) is the pH at which the amino acid has a net zero charge. This is the pH at which it does not migrate in an electric field. An amino acid is positively charged when the pH is less than the pI and negatively charged when the pH is greater than the pI.

Arginine is an amino acid that has a positively charged guanidine group in its side chain. It is an essential amino acid, which means that the body cannot synthesize it and must obtain it from food. The isoelectric point of arginine is 10.76, which is higher than that of the other amino acids listed:

Lysine has a pI of 9.74

Histidine has a pI of 7.59

Threonine has a pI of 5.6

Alanine has a pI of 6.11

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Answer:

For rusting, it is difficult to write an equation due to the complexity of the reaction. Thus, we can express the reaction like the following. According to the law of conservation of mass, the increased mass of nail and rust is the amount of oxygen.

Explanation:

I hope this helps:)

A small amount of heat Q flows from a system A at high temperature (350K) to a system B at low temperature (250K). If Q = 0. 5 J, mA = 1. 2 kg, and mB = 0. 6 kg, the total entropy change of the system be 0.00057J/K.

Firstly we will be taking Q as a positive number,

Then, the entropy lost by A is Q/TA

= (-0.5 J)/(350 K)

= -1/700 J/K

= -0.00143 J/K.

Now, the entropy gain by B is Q/TB

= (0.5 J)/(250 K)

= 1/500 J/K

= +0.00200 J/K.

Therefore, the total entropy change of the system will be the the sum of entropy lost by A and entropy gain by B.

Hence the total entropy would be =0.00057 J/K.

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There is no chemical component to texture. The qualities of a material's surface, such as its smoothness, roughness, softness, or hardness, are described by this physical attribute.

Three physical characteristics are size, color, and texture. They are many. An object's physical characteristics can be used to characterize it. When you touch anything, you can feel its texture.

A qualitative physical characteristic of matter is texture. Another physical characteristic that characterizes an object's resistance to scratching is its hardness. By rubbing one substance against another, you may compare the hardness of the two.

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