The second quartile for the numbers 231, 423, 521, 139, 347, 400, 345 is 347. The median value is the second quartile
. So, when the numbers are arranged in ascending order, 347 is in the middle.
The following measures of variability is dependent on every value in a Set of data:
Standard deviation is the measure of variability that is dependent on every value in a Set of data.
Standard deviation is a measure that is used to quantify the amount of variation or dispersion of a set of data values.
Among these statistics, the Interquartile range is unaffected by outliers. The IQR is the distance between the first quartile (Q1) and the third quartile (Q3), which represents the middle 50% of the data.
The interquartile range (IQR) is unaffected by outliers because it only uses the values of the data points located at the 25th and 75th percentile of the data set to measure variability.
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If you fit a slope and intercept at the same time, then their errors will be correlated. True or False?
The given statement "if you try to match a slope and an intercept at the same time, their mistakes will be related" is TRUE.
What is the intercept?A y-intercept, also known as a vertical intercept, is the location where the graph of a function or relation intersects the coordinate system's y-axis.
This is done in analytic geometry using the common convention that the horizontal axis represents the variable x and the vertical axis the variable y.
These points satisfy x = 0 because of this.
The errors of a slope and an intercept will be connected if you fit them simultaneously.
By changing Y to 0 in the equation and figuring out X, you can always determine the X-intercept.
Similarly, by putting X to 0 in the equation and solving for Y, you can always determine the Y-intercept.
Therefore, the given statement "if you try to match a slope and an intercept at the same time, their mistakes will be related" is TRUE.
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which pair of dotplots provides the strongest statistical evidence that the training group ran faster (small times), on average, than the no training group?
Similarly, if the spread of the training group's distribution is smaller than the spread of the no training group's distribution.
The training group ran faster on average, than the no training group.
To determine which pair of dot plots provides the strongest statistical evidence that the training group ran faster.
Compare the center and spread of the two groups.
The center of the training group's distribution is consistently to the left (i.e., lower times) of the center of the no training group's distribution.
Overlap between the two distributions, then we can conclude that the training group ran faster on average, than the no training group.
100 by adding data.
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We need to examine the dotplots and summary statistics of the two groups to determine which pair of dotplots provides the strongest statistical evidence that the training group ran faster, on average, than the no training group.
To determine which pair of dotplots provides the strongest statistical evidence that the training group ran faster, we need to compare the centers and spreads of the two groups. If the center of the training group is shifted to the left (smaller times) compared to the center of the no training group, and if the spread of the training group is smaller than the spread of the no training group, then we have stronger evidence that the training group ran faster, on average, than the no training group.
Without seeing the actual dotplots, we cannot make a definitive determination. However, we can describe what to look for in the dotplots. Specifically, we want to see a clear separation between the centers of the two groups, and we want to see less overlap between the dots in the training group than in the no training group.
In addition, we can calculate summary statistics for the two groups, such as the mean and standard deviation, to help us compare the centers and spreads of the two groups. If the mean of the training group is significantly smaller than the mean of the no training group, and if the standard deviation of the training group is significantly smaller than the standard deviation of the no training group, then we have stronger evidence that the training group ran faster, on average, than the no training group.
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A cat is at the bottom of an 18 foot well. Each day it climbs up 3 feet and each night it slides back 2 feet. How long will it take the cat to get out of the well?
Answer:
16 days
Step-by-step explanation:
This is a tricky question.
If you think of it quickly, you may want to say that it goes up 3 ft each day and down 2 ft each day, so it goes up a net 1 ft per day. Since it must climb 18 ft, it will take 18 days. That is incorrect.
Look at the following table.
Begin Amt Pos. after Amt of Pos. at
Day Pos. of climb climb slide end of night
1 0 3 3 2 1
2 1 3 4 2 2
3 2 3 5 2 3
4 3 3 6 2 4
5 4 3 7 2 5
6 5 3 8 2 6
7 6 3 9 2 7
8 7 3 10 2 8
9 8 3 11 2 9
10 9 3 12 2 10
11 10 3 13 2 11
12 11 3 14 2 12
13 12 3 15 2 13
14 13 3 16 2 14
15 14 3 17 2 15
16 15 3 18
Once it reaches 18 ft high on day 16, it is out of the well.
Answer: Let's start by finding out how much distance the cat climbs each day:
Distance climbed during the day = 3 feet
Distance slid back during the night = 2 feet
So, the net distance climbed each day = 3 - 2 = 1 foot
To climb out of the well, the cat needs to climb a total of 18 feet.
Since the cat climbs 1 foot per day, it will take the cat 18 days to climb out of the well.
Step-by-step explanation:
9x^2+16=0 what are the solutions
What is the volume of the rectangular prism?
Given the following LP model, which is the correct standard form? Max(Z)=2X1+X2 Restrictions / Constrains 11×1+3×2≥33
8×1+5×2≤40
7×1+10×2≤70
7×1+10×2≤70 X1,X2≥0 Use this problem's information to answer questions 19 to 21. a. Max(Z)=3×1+2X2
11×1+3×2−51≤33
8×1+5×2+52≥40
7×1+10×2+53≥70
b. Max(Z)=3×1+2×2 11×1+3×2+51=33 8×1+5×2−52=40 7×1+10×2−53=70
c. Max(Z)=3×1+2×2 11×1+3×2−51=33 8×1+5×2+52=40 7×1+10×2+53=70
d. Max(Z)=3×1+2×2 11X1+3×2+$1=33 8×1+5×2+52=40 7×1+10×2+53=70
The correct standard form for the given LP model is option C: Max(Z) = 3x1 + 2x2, subject to the constraints 11x1 + 3x2 - 5 <= 33, 8x1 + 5x2 + 5 >= 40, and 7x1 + 10x2 + 5 >= 70, with x1, x2 >= 0. This option aligns with the original objective function and constraints of the LP model.
To convert the LP model into standard form, we need to rewrite the constraints with the variables on the left-hand side and constants on the right-hand side, with inequality signs (<= or >=) consistent throughout. Additionally, we introduce slack or surplus variables to transform any non-standard constraints.
In option C, the constraints are correctly transformed as 11x1 + 3x2 - 5 = 33, 8x1 + 5x2 + 5 >= 40, and 7x1 + 10x2 + 5 >= 70. These constraints are consistent with the original model. The objective function remains the same, Max(Z) = 3x1 + 2x2.
Option A has incorrect signs in the transformed constraints, and option B introduces surplus variables (+5) instead of slack variables (-5), resulting in an incorrect standard form. Option D includes a non-standard term with a dollar sign, which is inconsistent with linear programming conventions.
Therefore, option C is the correct standard form, adhering to the original LP model's objective function and constraints.
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the lower class limit represents the smallest data value that can be included in the class.True/False
the lower class limit represents the smallest data value that can be included in the classThe statement is true.
The lower class limit is the smallest value that can be included in a class interval.
Therefore, the statement is correct.
The lower class limit represents the smallest data value that can be included in a particular class. In a frequency distribution table, data values are grouped into classes, and each class has a lower and upper class limit. The lower class limit denotes the lowest value within that class, and any data value equal to or greater than the lower limit but less than the upper limit falls into that class.
The statement is true, as the lower-class limit indeed represents the smallest data value that can be included in the class.
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question a cup has the shape of a right circular cone. the height of the cup is 12 cm, and the radius of the opening is 3 cm. water is poured into the cup at a constant rate of 2cm3/sec what is the rate at which the water level is rising when the depth of the water in the cup is 5 cm? (the volume of a cone of height h and radius r is given by v
When the water in the cup is 5 cm deep, the rate at which the water level is rising is \(\mathrm{\frac{32\pi}{25}\;cm/s}\).
A cone is a shape that is made by utilizing a sequence of line segments or lines to join the points on a circular base to a single point, known as the apex or vertex. This shape's volume formula is \(V=\frac{1}{3}\pi r^2h\) where h is the cone's height and r is the cone's radius.
Given that h is 12 cm, r is 3 cm, and the rate is 2 cm³/s.
Using similar triangle rules,
\(\begin{aligned}\frac{h}{r}&=\frac{12}{3}\\\frac{h}{r}&=4\\r&=\frac{1}{4}h\end{aligned}\)
Then, the volume becomes,
\(\begin{aligned}V&=\frac{1}{3}\pi\left(\frac{1}{4}h\right)^2h\\&=\frac{\pi h^3}{48}\end{aligned}\)
The change in volume is written as,
\(\begin{aligned}\frac{dV}{dt}&=\frac{dV}{dh}\times\frac{dh}{dt}\\2&=\frac{dV}{dh}\times\frac{dh}{dt}\\2&=\frac{3\pi h^2}{48}\frac{dh}{dt} \end{aligned}\)
Substituting the height h = 5 cm and rate = 2 cm³/s, we get the rate as,
\(\begin{aligned}2&=\frac{3\pi(5)^2}{48}\frac{dh}{dt}\\2&=\frac{75\pi}{48}\frac{dh}{dt}\\\frac{96\pi}{75}&=\frac{dh}{dt}\\\frac{dh}{dt}&=\mathrm{\frac{32\pi}{25}\;cm/s}\end{aligned}\)
The required answer is \(\mathrm{\frac{32\pi}{25}\;cm/s}\)
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After drinking, the body eliminates 37% of the alcohol present in the body per hour.
a) The amount of alcohol in grams in the body on an hourly basis is described by a discrete time dynamical system (DTDS) of the form xn+1=f(xn), where xn is the number of grams of alcohol in the body after n hours. Give the updating function f (as a function of the variable x).
b) Peter had three alcoholic drinks that brought the alcohol content in his body to 41 grams, and then he stopped drinking. Give the initial condition (in grams) for the DTDS in (a).
c) Find the solution of the DTDS in (a) with the initial condition given in (b). (Your answer will be a function of the variable n, which represents time in hours.)
The solution of the DTDS is xn = (0.63)^n * 41 grams, where n represents time in hours.
a) The updating function f(x) for the discrete time dynamical system (DTDS) can be derived from the given information that the body eliminates 37% of the alcohol present in the body per hour.
Since 37% of the alcohol is eliminated, the amount remaining after one hour can be calculated by subtracting 37% of the current amount from the current amount. This can be expressed as:
f(x) = x - 0.37x
Simplifying the equation:
f(x) = 0.63x
b) The initial condition for the DTDS is given as Peter having 41 grams of alcohol in his body after consuming three alcoholic drinks. Therefore, the initial condition is:
x0 = 41 grams
c) To find the solution of the DTDS with the given initial condition, we can use the updating function f(x) and iterate it over time.
For n hours, the solution is given by:
xn = f^n(x0)
Applying the updating function f(x) repeatedly for n times:
xn = f(f(f(...f(x0))))
In this case, since the function f(x) is f(x) = 0.63x, the solution can be written as:
xn = (0.63)^n * x0
Substituting the initial condition x0 = 41 grams, the solution becomes:
xn = (0.63)^n * 41 grams
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PLEASE HELP MAX POINTS AND BRAINLIEST!!!Find the length of the longest nail that could fit entirely within a cylindrical can of radius 2 inches and height of 6 inches.
Answer:
a 7.2 inch nail
Step-by-step explanation:
using the Pythagorean theorem:
the diagonal distance of a 6" height and a 2" radius (4" diameter) would be:
D² = 6² + 4² = 36 + 16 = 52
D = √52 = 7.21 inches
Find diagonal that's the answer
Use Pythagorean theorem
H²=P²+B²H²=6²+(2+2)²H²=36+16H²=52H=√52describe the difference between intersect and union, including the purposes for which they are used.
The intersection of two sets is the set of elements that are common to both sets, while the union of two sets is the set of elements that are in either of the two sets. Intersection and union are two of the most important operations in set theory and are used for a variety of purposes.
The purpose of the intersection operation is to find common elements between two sets, such as the common elements in two groups of people. The intersection operation produces a new set, which contains only the elements that are in both sets.
The purpose of the union operation is to join two sets together. The union operation produces a new set, which contains all the elements that are in either of the two sets. This is useful when you want to combine two different sets of data.
In summary, the intersection operation finds the common elements between two sets, while the union operation combines two sets of data into one. Both operations are important in set theory and are used for a variety of purposes.
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Angela's Uber cab fare is $12. A tax of 3% is added to the fare. she gives the drivers 20% of the original fare as a tip. How much did Angela pay for her cab ride home.
Answer:
$14.80
Step-by-step explanation:
Tax:
3% of 12 is .4. So she would pay $0.40 for the tax.
Tip:
20% of 12 is 2.4. So she would pay $2.40 for the tip.
Sum:
Then you would add them all together, 12 + 0.4 + 2.4 = 14.8. So she payed $14.80 in all.
the lifetimes of batteries created by a company are normally distributed with a mean of 105 hours and a standard deviation of 12 hours. what percentage of these batteries will last between 90.6 and 109.8 hours? state your answer as a percent rounded to the nearest hundredth, but do not include a % symbol in your answer.
Around 21.13% of the batteries will final(last) between 90.6 and 109.8 hours.
To unravel this issue, ready to utilize the standard typical conveyance by standardizing the values utilizing the equation:
z = (x - μ) / σ
where
x is the esteem we need to discover the likelihood
μ is cruel(mean), and σ is the standard deviation.
So, for the lower conclusion of the extent, we have:
z1 = (90.6 - 105) / 12 ≈ -1.20
z1 = -1.20
And for the upper conclusion of the extension, we have the:
z2 = (109.8 - 105) / 12 ≈ 0.45
z2 = 0.45
We need to discover the rate of batteries that will final(last) between these two values, which compares to the area under the typical bend between z1 and z2.
Able to utilize a standard ordinary conveyance table or calculator to discover this zone, or we will utilize the properties of the typical conveyance to inexact it.
Since the typical conveyance is symmetric around the cruel, we know that the zone between z1 and z2 is the same as the range between -z2 and -z1 (i.e., the comparing values on the other side of the mean).
So, ready to discover the range between -z2 and -z1, which compares to the rate of batteries that will final between 90.6 and 109.8 hours:
P(-z2 < z < -z1) ≈ P(z < -z1) - P(z < -z2)
Employing a standard typical dissemination table or calculator, we discover:
P(z < -1.20) ≈ 0.1151
P(z < -0.45) ≈ 0.3264
So, the rate of batteries that will final between 90.6 and 109.8 hours is rough:
P(-z2 < z < -z1) ≈ 0.3264 - 0.1151 ≈ 0.2113
Increasing by 100%, we get:
0.2113 * 100% ≈ 21.13D
44 Subsequently, roughly 21.13% of the batteries will final between 90.6 and 109.8 hours.
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(ASAP)!!!
Sam is making a picture frame. He is gluing craft sticks end-to-end to a plece of cardboard. The sticks do not overlap.
Craft Sticks
Craft Sticks
The top of the frame is 18 inches long. Each craft stick is
Is 3.4 inches long
How many craft sticks will Sam glue to the cardboard to make the top of the frame?
O A St /
OD. 15
OB. 6
O E. 2173
Ос. 6
. 6 /
Answer:5 1/2
Step-by-step explanation:I took the test
HELPPP. i need help with this i have trouble with ordered pairs
Evaluate 18 divided by q when q=1/2
Question:
Evaluate 18 divided by q when q = 1/2
__________________________________________________
Answer:
18 divided by q
= 18/q
When q = 1/2,
= (18) / (1/2)
The 2 from the denominator of (1/2) will go up to the numerator of (18) / (1/2). We will be left with,
= (18 * 2) / (1)
= 36/1
= 36
Given that a = (- 8) b = 2 c = 7 and d = 11 , solve for x, y, z, and w.
[[x + y, z], [z - x, w - y]] =
[[a, b], [c, d]]
What is the value of w?
(Only type a number, nothing else)
Answer:
24
Step-by-step explanation:
Okay, let's solve this step-by-step:
1) We are given: a = -8, b = 2, c = 7, d = 11
2) We are asked to solve the matrix equation: [[x + y, z], [z - x, w - y]] = [[a, b], [c, d]]
3) Matching up the elements in the matrices:
x + y = a = -8 (1)
z = b = 2 (2)
z - x = c = 7 (3)
w - y = d = 11 (4)
4) Solving the equations:
From (1): x + y = -8 => x = -8 - y
Substitute in (3): z - (-8 - y) = 7 => z - (-8) = 7 + y => z = 15 + y
Substitute (2) into the above: 2 = 15 + y => y = 13
Substitute y = 13 into (1): -8 - 13 = -21 = x
Substitute x = -21 and y = 13 into (4): w - 13 = 11 => w = 11 + 13 = 24
Therefore, the values are:
x = -21
y = 13
z = 15
w = 24
So the final value of w is:
w = 24
help please asap correct answers only don't answer if u are not answering
hope your day I going well:)
Answer:
113 g
Step-by-step explanation:
Express each weight in grams
34000 mg = 34000 ÷ 1000 = 34 g
0.059 Kg = 0.059 × 1000 = 59 g
Total weight
= 20 + 34 + 59 = 113 g
Step-by-step explanation:
the answer is 113
Wyatt mows lawns to earn money. He charges by the area
of the yard. A new customer has a yard in the shape of a
triangle with a base of 200 feet and a height of 70 feet.
What is the area of the yard?
4,667 ft?
540 ft?
7,000 ft
270 ft?
The area of the triangular yard is 7000 ft².
What is the area of a triangle?The entire area enclosed by three sides of a triangle is the area of it.
Given,
The base of the triangle is 200 feet and the height of the triangle is 70 feet.
Therefore, the area of the triangle
= (1/2) × base of the triangle × height of the triangle = (1/2) × 200 × 70 ft² = 7000 ft².
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Please Help me - You will get 60 points for the rapid reply- Use isosceles trapezoid ABCD to determine the following measurements-
Answer:
1) AD = 9 in
2) DE = 9.25 in
3) ∠EDC = 36°
4) ∠AEB = 108°
5) 11.5 in
Step-by-step explanation:
1) AD = BC = 9in
2) AC = BD (diagonals are equal)
⇒ BD = 14.25
⇒ BE + DE = 14.25
⇒ 5 + DE = 14.25
DE = 9.25
3) Since AB ║CD,
∠ABE = ∠EDC = 36°
4) ∠ABE = ∠BAE = 36°
Also ∠ABE + ∠BAE + ∠AEB = 180 (traingle ABE)
⇒ 36 + 36 + ∠AEB = 180
∠AEB = 108
5) midsegment = (AB + CD)/2
= (8 + 15)/2
11.5
Eliminate arbitrary constants. Y=c1x+c2x^2+sinx
Step-by-step explanation:
chicken
Estimate a 15% tip on a dinner bill of $53.43 by first rounding the bill amount to the nearest ten dollars.
Answer:
$7.50
Step-by-step explanation:
round 53.43 down to 50
tip = total cost * rate of tip
I hope this helped
12 - x
If x = 7, what is the value of the expression above?
Answer:
5
Step-by-step explanation:
12-7=5
Answer:
5
Step-by-step explanation:
We know that x is equal to 7. That means we can replace x with this value. This makes our new expression:
12 - 7
12-7 is equal to 5, so this expression will equal 5 when x = 7.
The function f(x)=5000(0. 98)0. 3x represents the number of white blood cells, per cubic millimeter, in a patient x days after beginning treatment for a virus. What is the average rate of change in white blood cells between days 1 and 5?.
The average rate of change in white blood cells between days 1 and 5 is -29.75 mm³/day.
Given that
The function f(x)=5000(0. 98)0. 3x represents the number of white blood cells.
We need to evaluate this, for this
f ( x ) = 5000 * ( 0.98 ) ^(0.3 x)
f ( 1 ) = 5000 * 0.98^(0.3) = 5000 * 0.99396 = 4,969.788
f ( 5 ) = 5000 * 0.98 ^(5*0.3) = 5000 * 0.98^(1.5) = 5000 * 0.97 = 4,850.753
Average rate of change:
( 4,850.753 - 4,969.788 ) / ( 5 - 1 ) = - 29.75
Hence the answer is The average rate of change in white blood cells between days 1 and 5 is -29.75 mm³/day.
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what is the probability of observing the expected value for the distribution of binomial(100, 0.20)?
The probability of observing the expected value for the distribution of a binomial (100, 0.20) is 0.20 (or 20%).
The probability of observing the expected value for a binomial distribution can be calculated using the following formula:
Probability = (n C r) p^r (1-p)^(n-r)
where n = number of trials,
r = expected value,
p = probability of success
For the given distribution, binomial (100, 0.20), we know that n = 100 and p = 0.20.
The expected value is given by:E(X) = np = 100 * 0.20 = 20
So, to find the probability of observing the expected value of 20, we need to plug in the values of n, r, and p into the formula:
Probability = (n C r) p^r (1-p)^(n-r)=
(100 C 20) (0.20)^20 (0.80)^80≈
0.1875 ≈ 0.20 (rounded to two decimal places)
Therefore, the probability of observing the expected value for the distribution of binomial (100, 0.20) is approximately 0.20 (or 20%).
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Question 8 - Select the answer that best represents the
following argument in Standard Form.
"Hard water can damage home appliances. A water softening system
can prevent hard water. Therefore, a water
Premise 1: Hard water can damage home appliances. Premise 2: A water softening system can prevent hard water. Conclusion: Therefore, a water softening system can prevent damage to home appliances.
The argument consists of two premises and a conclusion. Premise 1 states that hard water can cause damage to home appliances. Premise 2 states that a water softening system can prevent hard water. The conclusion drawn from these premises is that a water-softening system can prevent damage to home appliances.
In standard form, the argument is presented by listing the premises first, followed by the conclusion. This format helps to clearly identify the statements being made and their logical relationship. By representing the argument in this way, it becomes easier to analyze the structure and validity of the reasoning presented.
Therefore, the standard form representation of the argument is:
Premise 1: Hard water can damage home appliances.
Premise 2: A water softening system can prevent hard water.
Conclusion: Therefore, a water softening system can prevent damage to home appliances.
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40 PTS!!!! A single-serving juice boxes measure 10cm by 7cm and 5cm. A manufacturer wants to shrink wrap four boxes together for sale. Which of the two arrangements of the boxes with use the least amount of plastic wrap? Show your work
Both arrangements use the same amount of plastic wrap, with a total surface area of 1240 cm².
To determine which arrangement of the four juice boxes uses the least amount of plastic wrap, we need to consider the total surface area that needs to be covered in each arrangement.
Arrangement 1:
In this arrangement, we can place the four juice boxes in a 2x2 square configuration, with two boxes stacked horizontally and two boxes stacked vertically. Let's calculate the total surface area to be covered:
Surface area of a single box = 2(lw) + 2(lh) + 2(wh)
= 2(107) + 2(105) + 2(7*5)
= 140 + 100 + 70
= 310 cm²
Since we have four boxes in this arrangement, the total surface area to be covered is:
Total surface area = 4 * 310 cm²
= 1240 cm²
Arrangement 2:
In this arrangement, we can stack the four juice boxes in a single column, one on top of the other. Let's calculate the total surface area for this arrangement:
Surface area of a single box is the same as in the previous arrangement:
Surface area of a single box = 310 cm²
Since we have four boxes stacked vertically, the total surface area to be covered is:
Total surface area = 4 * 310 cm²
= 1240 cm²
Therefore, both arrangements use the same amount of plastic wrap, with a total surface area of 1240 cm².
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ANSWER ASAP A basketball team played six games. In those games, the team won by 8 points, lost by 8, won by 7, won by 10, lost by 2, and won by 9. What was the mean difference in game scores over the six games?
The average difference or mean in game scores across six games is 5.67
MeanThe mean is the average of a data set. The mode is the most common number in a data set. The median is the middle of the set of numbers. The mean is the average or the most common value in a collection of numbers. the mean is one of the measures of b, apart from the mode and median. Mean is nothing but the average of the given set of a data.
To solve this problem, we have to write the wins and loss separate and then find the mean.
Wins = 8 points, 7 points, 20 points, 9 points
Loss = 8 points, 2 points
The sum of win points = 8 + 7 + 20 + 9 = 44 points
The sum of lost points = 8 + 2 = 10 points
The mean difference = (win - loss)/ total number of games
The mean difference = ( 44 - 10) / 6
The mean difference = 34 / 6 =5.67
The mean difference in the game scores over six games is 5.67 points
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Prove that A∗ search always finds the optimal goal. Recall that A∗ uses an admissible heuristic. Show all the steps of the proof and justify every step.
To prove that A* search always finds the optimal goal, we need to show that it satisfies two properties 1. Completeness: A* search is guaranteed to find a solution if one exists. 2. Optimality: If a solution is found by A* search, it is guaranteed to be the optimal solution.
1. Completeness:
To prove completeness, we need to show that A* search is guaranteed to find a solution if one exists.
A* search explores the search space by expanding nodes based on the estimated cost of reaching the goal, which is determined by the heuristic function. The heuristic function used in A* search is admissible, meaning it never overestimates the actual cost to reach the goal.
A* search maintains a priority queue of nodes to be expanded, and it always selects the node with the lowest estimated cost (f-value) to expand next. Since the heuristic is admissible, the f-value of the goal node will never decrease as we explore the search space.
If a solution exists, A* search will eventually reach the goal node because it explores nodes in order of increasing estimated cost. Once the goal node is reached, A* search will terminate and return the solution. Therefore, A* search is complete.
2. Optimality:
To prove optimality, we need to show that if a solution is found by A* search, it is guaranteed to be the optimal solution.
Suppose there exists an optimal solution that is different from the one found by A* search. Let's assume this alternative solution has a lower cost than the one found by A* search.
Since the heuristic function used in A* search is admissible, it never overestimates the actual cost to reach the goal. This implies that the estimated cost (h-value) of any node in the search space is less than or equal to the actual cost (g-value) of reaching the goal from that node.
Now, consider the node in the alternative solution where it deviates from the path found by A* search. This node must have a lower estimated cost (h-value) than the corresponding node in the A* search path because the alternative solution has a lower overall cost.
However, since A* search always selects the node with the lowest estimated cost (f-value) to expand next, it would have chosen the node in the alternative solution before the corresponding node in the A* search path. This contradicts our assumption that the alternative solution has a lower cost.
Therefore, we can conclude that if a solution is found by A* search, it is guaranteed to be the optimal solution.
By establishing both the completeness and optimality properties of A* search, we have shown that A* search always finds the optimal goal.
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Solve for a.
ab +c=d
a=b+c/d
O a = b/(C-d)
O a = (d - c)/b
Answer:
Value : c = ad - b
Step-by-step explanation:
Given the equation: Solve for c;
Multiply both sides by d in we get;
subtract b from both sides we have;
Simplify:
ad - b = c
Therefore, the value of c is, ad -b
Answer:
Step-by-step explanation:
ab +c=d
SUBTRACT c FROM BOTH SIDES.
ab + c (-c) = d - c
ab + 0 = d - c
ab = d-c
Divide both sides by b.
ab/b = (d-c)/b
a = (d-c)/b (FIRST EQUATION)
a=b+c/d
THIS IS ALREADY SOLVED FOR a. (SECOND EQUATION)
O a = b/(C-d)
O a = (d - c)/b