The Sankey diagram shows the energy transfers in an LED light bulb.

(look at the attached photo)

Answer:

In adding up charges, you can ignore the neutrons ... they have no charge

either way.  They're NEUTRal, which is why they're called NEUTRons.

That leaves us with 3 positive protons and 3 negative electrons.

                      +3  -3  =  0 .

The atom as a whole is neutral ... its net charge is zero.

Explanation:if this isn’t right I am sorry

A lunar eclipse occurs when earth's shadow fall on moon.

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40x magnifies the viewing field to reveal 583.33 distinct blood cells. Due to their rounded shape, blood cells may be recognized. They don't have cell walls as plant cells do.

At a total magnification of 40x (a scanning microscope), there may be counted 583.33 unique blood cells. The diameter of a 40x viewing field of view is 4200 m, whereas the normal size of a red blood cell is 6.2-8.2 m (7.2 m). So, 583.33 is the response. Blood cells appears as separate cells without nuclei when seen using a light microscope at a magnification of 40X.

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Answer: the thing that brings you life- h2o- idrk the question but if this helps your welcome ^-^have a good day

Explanation:

If an object has a balanced force on it, there is a possibility that the object may be in a position i.e. there is no change in speed and direction of the body.

If the forces acting on an object is balanced, it means that the net force acting on the body is zero.

According to Newton's law of motion, an object will continue in a state of motion in a straight line unless acted upon by an external force.

This external force might be a balanced or unbalanced force. Hence if an object has a balanced force on it, there is a possibility that the object may be in a position i.e. there is no change in speed and direction of the body.

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(a) The net charge on the conducting sphere is 11.628π mC. (b) The total electric flux leaving the surface of the conducting sphere is 4.157π x 10¹² N·m²/C.

To determine the net charge on the conducting sphere, we need to calculate the total charge based on the given surface charge density.

(a) Net charge on the sphere:

The surface charge density (σ) is given as 8.1 mC/m². We can find the total charge (Q) by multiplying the surface charge density with the surface area (A) of the sphere.

The formula for the surface area of a sphere is:

A = 4πr²

The diameter of the sphere is 1.2 m, the radius (r) can be calculated as:

r = diameter / 2

r = 1.2 m / 2

r = 0.6 m

Substituting the values into the formula for the surface area:

A = 4π(0.6 m)²

A = 4π(0.36) m²

A = 1.44π m²

Now, we can calculate the net charge (Q):

Q = σA

Q = (8.1 mC/m²)(1.44π m²)

Q = 11.628π mC

11.628 π mC is the net charge.

(b) Total electric flux leaving the surface:

The total electric flux leaving the surface of a closed surface surrounding the charged sphere is given by Gauss's Law:

Φ = Q / ε₀

Where

Φ is the total electric flux,

Q is the net charge enclosed by the surface, and

ε₀ is the permittivity of free space (ε₀ = 8.854 x 10⁻¹² C²/N·m²).

Substituting the known values:

Φ = (11.628π mC) / (8.854 x 10⁻¹² C²/N·m²)

Φ ≈ 4.157π x 10¹² N·m²/C

Therefore, 4.157π x 10¹² N·m²/C is the total electric flux.

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When a star orbits in the disk of the Milky Way and has a high metallicity, it is likely a Population I star.

A stellar population is a group of stars that share a similar origin and age and are distributed in a specific region.

Based on the metallicity, the stars are divided into two populations:

Population I and Population II.

Population I stars have a higher metallicity, and they're younger than Population II stars.In the disk of the Milky Way, Population I stars are the most commonly seen stars. The disk of the Milky Way is a region of space where most of the stars and gas in the galaxy are concentrated.

Population I stars are formed in the disk from metal-rich gas and dust. Therefore, a star that orbits in the disk of the Milky Way and has a high metallicity is most likely a Population I star.

Population I stars are also known as young disk stars that form in the galactic disk and have a higher metallicity than Population II stars.

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Answer:

The force is doubled as well.

Explanation:

If you double the spring then the force doubles as well.

If the deflection of the spring is doubled, the force exerted by the spring will also be doubled.

The relationship between the deflection of a spring and the force it exerts is described by Hooke's Law, which states that the force exerted by a spring is directly proportional to its deflection. Mathematically, this can be expressed as:

F = kx

where F is the force exerted by the spring, x is the deflection of the spring, and k is the spring constant, which represents the stiffness of the spring.

If we double the deflection of the spring, then x becomes 2x, and the force exerted by the spring becomes:

F = k(2x) = 2kx

Thus, if the deflection of the spring is doubled, the force exerted by the spring will also be doubled (assuming the spring constant remains constant).

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Answer:

These layers are the troposphere, the stratosphere, the mesosphere and the thermosphere.

A further region, beginning about 500 km above the Earth's surface, is called the exosphere.

Explanation:

Hope this helps you. Have a nice day. Please mark as brainliest. It helps a lot.^_^

Answer:

it can be built in mine craft

Explanation:

Answer:

put 2 pistons on each side and then put the block you want the door to be and power it with redstone

The air temperature is approximately 8.67°C.

To determine the air temperature given the frequency and wavelength of a sound wave, we can use the following formula:

v = fλ

where v is the speed of sound, f is the frequency (510 Hz in this case), and λ is the wavelength (0.66 m in this case).

v = (510 Hz)(0.66 m) = 336.6 m/s

Next, we need to use the speed of sound formula:

v = 331.4 + 0.6T

where v is the speed of sound (336.6 m/s), and T is the air temperature in Celsius.

Now, we can solve for T:

336.6 = 331.4 + 0.6T

5.2 = 0.6T

T = 8.67°C

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The energy of photon involved in exciton absorption in Germanium (Ge) is approximately 0.76 eV.

The energy of photon involved in exciton absorption in Germanium (Ge) is approximately 0.76 eV. This can be calculated using the formula E_photon = E_gap + E_excitonwhere E_photon = energy of photon,E_gap = energy gap of Ge, andE_exciton = exciton energy.Substituting the given values we have;E_photon = 0.75 eV + 0.01 eVE_photon = 0.76 eVThe effect of exciton absorption on the absorption spectrum of Ge is the appearance of a new peak or band.

The exciton absorption band is usually narrower than the band for the direct interband transition because of the localization of electron and hole pairs. As the temperature is raised, the absorption coefficient for the exciton peak decreases and broadens due to the thermal dissociation of excitons.

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Answer:

It's D: None of the above.

Explanation:

I looked up the components of soil and all of them were, and I also took the test and got it correct.  

If you flew a spaceship straight into Jupiter, aiming toward its center, the spaceship would experience increasing atmospheric pressure, temperature, and density as it descends. Initially, the spacecraft would encounter the outer layers of Jupiter's atmosphere, which is primarily composed of hydrogen and helium. As it progresses further, it would experience more intense pressure, leading to the hydrogen gas transitioning into a liquid state.

Eventually, the spacecraft would reach a layer where metallic hydrogen is present, which is due to the extremely high pressure and temperature conditions deep within Jupiter's interior. The intense conditions in this region would likely cause the spacecraft to be crushed and destroyed by the immense pressure and heat.

Throughout the descent, the spacecraft would also encounter strong winds and powerful storms, such as the Great Red Spot, which could further challenge its integrity and ability to withstand Jupiter's harsh environment. Overall, the spaceship's journey into Jupiter would be a perilous one, and it would ultimately be destroyed by the planet's extreme conditions.

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Answer:

Explanation:

(a)

In event A , one has to walk along diameter of the field from X to Y.

In this event , walk is along a straight line , both displacement and distance covered will be same.

Distance = displacement = 1 km.

option ii is correct .

(b )

radius of circular track r = 0.5 km

length of track = circumference = 2π r

= 2 x 3.14 x .5 = 3.14 km

Length of running in event B is 15.7 km

No of rounds = 15.7 / 3.14 = 5

option iii is correct .

( c )

speed = length of race / time

time = length of race / speed

= 15. 7 km / 3.14 km /h

= 5 hours .

option iv is correct option.

(d)

In event C , length of race is 25.12 km

speed = length of race / time taken

= 25.12 km  / 4 hour

= 6.28 km/h .

Option i is correct.

Answer:

(a) (ii)

(b) (iv)

(c) (i)

(d) (i)

Explanation:

diameter, XY = 1 km

Event A- Fast walking along the diameter of the field.

Event B- A 15.7 km running race along the circular track.

Event C- A 25.12 km cycling race along the circular track.

(a) When athletes walked from X to Y , the distance is equal to the displacement which is equal to the diameter = 1 km.  

Option (ii).

(b) distance = 15.7 km

distance traveled by one round = 3.14 x 1 = 3.14 km

So, the number of round complete in B = 1.57/3.14 = 0.5

option (iv).

(c)If Pihu ran at an average speed of 3.14 km/h during Event B, then she would finish the race in

time, t = 1.57/3.14 = 0.5 hours

option (i)

(d) What should the average speed of cyclist Yousef be, so that he can complete Event C in 4hours?

Distance = 25.12 km

time , t = 4 hours

Speed = 25.12 / 4 = 6.28 km/h

Option (i)

Answer:5.04 seconds per m

Explanation:

Answer:

5.041 mps

Explanation:

121/24

The force is directly proportional to both the charge and the electric field strength. The force on a particle with a net charge of q that is placed in a uniform electric field with a field strength of e can be calculated using the following equation: F = qe

Where F is the force on the particle and q and e are the charge and field strength, respectively. Therefore, the force on the particle is directly proportional to both the charge and the field strength. The force on the particle in this scenario can be determined using a simple equation that relates the charge and field strength. The force on a charged particle placed in a uniform electric field can be determined using the following formula:
Force (F) = Charge (q) * Electric Field Strength (E)

The particle has a net charge of "q" and the electric field has a strength of "e." To find the force on the particle, simply multiply these two values: F = q * e
This equation illustrates the relationship between the particle's net charge, the electric field strength, and the force exerted on the particle.

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According to the question the speed of the skater's hands is 528 m/min.

To calculate the speed of the skater's hands, we can use the formula:

Speed = Circumference * Revolutions per minute

Given that the skater's hands are 140 cm apart and she spins at 120 rpm, we need to calculate the circumference of the circle formed by her hands.

The circumference of a circle is given by the formula:

Circumference = 2 * π * radius.

In this case, the radius is half the distance between the skater's hands, which is 140 cm / 2 = 70 cm.

Converting the radius to meters, we have 70 cm = 0.7 m.

Now we can calculate the circumference:

Circumference = 2 * π * 0.7 m = 4.4 m (rounded to one decimal place).

Finally, we can calculate the speed of the skater's hands:

Speed = Circumference * Revolutions per minute

     = 4.4 m * 120 rpm

     = 528 m/min.

Therefore, the speed of the skater's hands is 528 m/min.

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The patrol car will take about 12.08 s to catch the speeder, and each car will travel about 1134.72 km and 655.38 km, respectively.

The problem involves finding the time taken by a patrol car to catch a speeder traveling at a constant speed of 94 km/h and the distance traveled by each car.

The patrol car accelerates at a constant rate of (9 km/h)/s from rest to reach its maximum speed of 119 km/h.

The solution to this problem involves calculating the distance covered by both cars and equating them.

For the speeder, we use the formula distance = speed × time.

For the patrol car, we use the formula distance = (initial speed × time) + (1/2 × acceleration × time²).

Once we have calculated the time taken by the patrol car to catch the speeder, we can use the time to calculate the distance covered by both cars.

To find the time taken by the patrol car to catch the speeder, we equate the distances covered by both cars.

Equating these distances gives us a quadratic equation, which we can solve using the quadratic formula. Solving this equation gives us the time taken by the patrol car to catch the speeder as about 12.08 s.

To calculate the distance covered by each car, we use the time calculated above.

The distance covered by the speeder is given by

distance = speed × time

= 94 × 12.08 km,

which is about 1134.72 km.

The distance covered by the patrol car is given by

distance = (initial speed × time) + (1/2 × acceleration × time²)

= 0 × 12.08 + (1/2 × 9 × 12.08²)

= 655.38 km.

Therefore, each car will travel about 1134.72 km and 655.38 km, respectively.

In conclusion, the patrol car will take about 12.08 s to catch the speeder, and each car will travel about 1134.72 km and 655.38 km, respectively.

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Answer:

The turning effect of a force is known as the moment. It is the product of the force multiplied by the perpendicular distance from the line of action of the force to the pivot or point where the object will turn. When undoing a nut fastened to a screw by hand one realises that the amount of force required is a lot greater than when undoing the same nut using a spanner.

Explanation:

Answer:

Fnet = 13.86N

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

\( Fnet = Fapp + Fg\)

Where;

Given the following data;

Mass = 1.1kg

Acceleration = 2.8m/s²

To find the applied force;

\( Fapp = ma\)

Substituting into the equation, we have;

\( Fapp = 1.1 * 2.8\)

Fapp = 3.08N

To find the gravitational force;

We know that acceleration due to gravity, g = 9.8m/s²

\( Fg = mg\)

Substituting into the equation;

\( Fg = 1.1 * 9.8\)

Fg = 10.78N

To find the net force;

\( Fnet = Fapp + Fg\)

Substituting into the equation, we have;

\( Fnet = 3.08 + 10.78\)

Fnet = 13.86N

Therefore, the net force required is 13.86N

Free body diagram:

Here, T_1 is the tension in the left cable (T_1=30000 N; given), T_2 is the tension in the right cable, W is the weight of the tram.

The force equation in horizontal direction is given as,

Therefore, the tension in right cable T_2 is given as,

Substituting all known values,

The force equation in the vertical direction is given as,

Substituting all known values,

Therefore, the weight of the tram is 8038.47 N.

The pattern formed by iron filings around magnets shows the magnetic field lines produced by the magnets.

Magnetic field lines are described as imaginary lines, which depict the strength and direction of the magnetic field.

The iron filings align themselves along the magnetic field lines, which helps to provide a visual representation of the field's direction and shape. The filings tend to concentrate near the poles of the magnets, where the magnetic field is stronger.

This pattern is important as it helps visualize the magnetic field and understand its characteristics, such as the shape, direction, and strength of the magnetic field produced by the magnets.

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 The two differences between electromagnets and permanent

magnets  are as follows:

Electromagnet exhibit the following:

Permanent magnets exhibit the following:

This refers to a  temporary magnet produced by winding a wire around an iron core.eg.Motors, generators, Loudspeakers, headphones, Relays, Transformers, Actuators such as valves etc.

his refers to a magnet that maintains its magnetism after the magnetizing force has been removed. eg cobalt, nickel, iron, and some alloys.

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The braking force needed to bring the car to a complete stop in 5 seconds is 4000 Newtons.

To calculate the braking force needed to bring the car to a complete stop, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m × a).

Mass of the car (m) = 2000 kg

Initial velocity (u) = 10 m/s

Final velocity (v) = 0 m/s

Time taken (t) = 5 seconds

First, we need to calculate the acceleration (a) using the formula:

a = (v - u) / t

Substituting the values:

a = (0 - 10) / 5

a = -2 m/s²

Since the car is decelerating (negative acceleration), we need to consider the magnitude of the acceleration.

Now, we can calculate the braking force (F) using the formula:

F = m × a

Substituting the values:

F = 2000 kg × (-2 m/s²)

F = -4000 Newtons

The negative sign indicates that the force acts in the opposite direction of the car's motion, which corresponds to the braking force required to bring the car to a stop.

However, in practice, the magnitude of the force would be considered without the negative sign, resulting in a positive value of 4000 Newtons.

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Answer:

800mph

Explanation:

The acceleration of the car is 0.8049\(m/s^{2}\).It takes 13.802s to travel the 230 m.

In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies. Acceleration is a vector quantity (in that they have magnitude and direction). The direction of an object's acceleration is determined by the direction of the net force acting on it. Newton's Second Law states that the combined effect of two factors determines how much an item accelerates: 

(i) It follows that  the magnitude of the net balance of all external forces acting on the object is directly proportional to the magnitude of this net resulting force, and

(ii) the mass of the thing, depending on the materials out of which it is constructed, is inversely proportional to the mass of the thing.

Calculations:

40 km/hr ----- 11.11m/s

80 km/hr ----- 22.22m/s

\(v^{2} -u^{2} =2as\\22.22^{2} - 11.11^{2} = 2 x a x 230\\ 370.296=460a\\ a= 0.8049m/s^{2} \\\)

Time taken

v-u=at

22.22-11.11= 0.8049 x t

t=13.802s

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Answer:

15.1 m/s²

Explanation:

Step 1: Calculate the force exerted by the friction

Friction exerts a force against the direction of the movement. On a horizontal plane, we can calculate the value of that force using the following expression.

Ff = μ × m × g

where,

μ: coefficient of kinetic friction

m: mass of the block

g: gravity

Ff = 0.50 × 10 kg × 9.81 m/s² = 49 N

Step 2: Calculate the resulting force

The horizontal force F and the friction force Ff are vectors that act in opposite directions. We can calculate the resulting force (R) by doing the subtraction.

R = F - Ff = R = 200 N - 49 N = 151 N

Step 3: Calculate the acceleration of the block

We will use Newton's second law of motion.

R = m × a

a = R/m

a = 151 N/10 kg = 15.1 m/s²

Answer:

In Newton’s first law, an object at rest remains at rest until an external force isapplied. When I play soccer, the soccer ball will be at rest on the field (the initial condition) andremain in that spot on the field until I kick it (my muscles applying an external force to the ball).According to Newton’s second law, force = mass x acceleration (F=ma). When I kick the resting soccer ball, which has a given mass, it will accelerate in the direction that I kick it. From the equation, acceleration = force divided by mass. Therefore, since the mass of the soccer ball is fixed, the stronger my leg is and the more force I can apply to the ball, the faster it willaccelerate.According to Newton’s first law, an object in motion remains in motion until an external force isapplied. After I kick the soccer ball, it will continue in motion in the direction that I kicked it,but its acceleration will gradually slow down due to the external forces of friction from the airand the surface of the field. According to Newton’s third law, for every action there is an equal and opposite reaction.When I kick the soccer ball forward, if I also kick it in an upward direction, such as a thirty-degree angle from the field, it will come down at an angle when it strikes the field. When theball lands and strikes the field, there will be an equal and opposite reaction whereby instead oftraveling downward it will bounce of the surface of the field and will then be travelling upward.