Answer:
a = 5
Step-by-step explanation:
a^2 + b^2 = c^2
Substitute
b = 12
c = 13
a^2 + 12^2 = 13^2
a^2 + 144 = 169
a^2 = 25
a = \(\sqrt{25} \\\)
a = 5
Mark brainliest please!
Answer:
use Pythagoras theorem
Step-by-step explanation:
\(a^{2} + b ^{2} = c ^{2} \\ a ^{2} + 12 ^{2} = 13 ^{2} \\ a = 5\)
A projectile is launched from the ground with an initial speed of 220 ft/sec at an angle of 60° with the horizontal.
What is the height of the projectile after 4 seconds?
How long is the projectile in the air?
What is the horizontal distance traveled by the projectile?
What is the maximum height of the projectile?
The height of the projectile after 4 seconds is 421.28 ft.
The projectile is in the air for 8.015 seconds.
The horizontal distance traveled by the projectile is 881.77 ft.
The maximum height of the projectile is 464.1 ft.
To solve this problem, we can use the kinematic equations of motion for a projectile.
Let's assume that the initial height of the projectile is zero.
What is the height of the projectile after 4 seconds:
We can use the equation:
\(y = yo + vot + 1/2at^2\)
where
y = height of the projectile
yo = initial height (zero in this case)
vo = initial vertical velocity = 220 sin(60°) = 190.53 ft/sec
a = acceleration due to gravity \(= -32.2 ft/sec^2\) ( negative since it acts downwards)
t = time = 4 sec
Plugging in the values, we get:
\(y = 0 + (190.53)(4) + 1/2(-32.2)(4)^2 = 421.28 ft\)
Therefore, the height of the projectile after 4 seconds is 421.28 ft.
Long is the projectile in the air:
The time of flight of a projectile can be calculated using the equation:
t = 2vo sinθ / g
where θ is the launch angle and g is the acceleration due to gravity.
Plugging in the values, we get:
t = 2(220 sin(60°)) / 32.2 = 8.015 sec
Therefore, the projectile is in the air for 8.015 seconds.
Horizontal distance traveled by the projectile:
The horizontal distance traveled by the projectile can be calculated using the equation:
\(x = xo + vot + 1/2at^2\)
where
x = horizontal distance traveled
xo = initial horizontal position (zero in this case)
vo = initial horizontal velocity = 220 cos(60°) = 110 ft/sec
a = acceleration due to gravity (zero in the horizontal direction)
t = time = 8.015 sec
Plugging in the values, we get:
\(x = 0 + (110)(8.015) + 1/2(0)(8.015)^2 = 881.77 ft\)
Therefore, the horizontal distance traveled by the projectile is 881.77 ft.
Maximum height of the projectile:
The maximum height of a projectile can be calculated using the equation:
\(ymax = yo + (vo^2 sin^2 \theta ) / 2g\)
Plugging in the values, we get:\(ymax = 0 + (190.53^2 sin^2(60\degree )) / (2)(32.2) = 464.1 ft\)
Therefore, the maximum height of the projectile is 464.1 ft.
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solve the question below, please..
Answer:
C = 133.33°
Step-by-step explanation:
Apply the Law of Cosines to find angle C:
\( Cos(C) = \frac{a^2 + b^2 - c^2}{2ab} \)
Where,
a = 8.5 cm
b = 4.1 cm
c = 11.7 cm
Plug in the values
\( Cos(C) = \frac{8.5^2 + 4.1^2 - 11.7^2}{2*8.5*4.1} \)
\( Cos(C) = \frac{-47.83}{69.7} \)
\( Cos(C) = -0.6862 \)
\( C = Cos^{-1}(-0.6862) \)
C = 133.33°
find the mean and median of each of the following sets of data. determine the deviation from the mean for each data point within the sets and find the mean deviation for each set. 24.49 24.68 24.77 24.83 24.73
The average distance from the mean is 0.09.
The mean is also known as the average and is calculated by adding up all the values in the set and then dividing the sum by the total number of values.
So, for the given set of data: 24.49, 24.68, 24.77, 24.83, 24.73, the mean would be calculated as follows:
Mean = (24.49 + 24.68 + 24.77 + 24.83 + 24.73) / 5
= 24.70
It tells us what the typical value is within the data set. In this case, the mean value of the data set is 24.70.
Next, let's find the median of the set of data. The median is the middle value of a data set when it is arranged in numerical order. In this case, the data set is already arranged in numerical order, so we can easily find the median.
The median value of the data set is the middle value, which is 24.77.
Now, we will calculate the deviation from the mean for each data point within the set. The deviation from the mean tells us how far each value is from the mean value. This is calculated by subtracting the mean from each value in the set.
Deviation from the mean for each data point:
-0.21, -0.02, 0.07, 0.13, 0.03
As you can see, some values are above the mean, and some are below the mean. The deviation from the mean can be used to determine how spread out the data is from the mean value.
Finally, we will calculate the mean deviation for the set. The mean deviation is the average of the absolute values of the deviation from the mean.
Mean deviation = (|(-0.21)| + |(-0.02)| + |0.07| + |0.13| + |0.03|) / 5
= 0.09
The mean deviation tells us the average distance from the mean value.
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95 points
Simplify (4^9/4^3)^5 Show your work for full credit
Answer:
\(4^{30}\)Step-by-step explanation:
\((4^9/4^3)^5=\)\((4^{9-3})^5=\)\((4^6)^5=\)\(4^{6*5}=\)\(4^{30}\)Answer:
The answer is 4³⁰
Step-by-step explanation:
(4⁹/4³)⁵
Here, we will use the property
aᵐ/aⁿ = (aᵐ⁻ⁿ)
(4⁹⁻³)⁵ = (4⁶)⁵ = 4⁶*⁵ = 4³⁰
Thus, The answer is 4³⁰
-TheUnknownScientist 72
Write a numerical expression to represent the phrase "the sum of 25 and the cube of 9." Do not evaluate the expression.
Answer:
25 + 9^3
Step-by-step explanation:
A middle school took all of its 6th grade students on a field trip to see a play at a theater that has 1900 seats. The students filled 44% of the seats in the theater. How many 6th graders went on the trip?
Celeste is planting a rectangular flower garden in which the width will be 4 feet less than its length. She has decided to put a birdbath within the garden that will occupy a space 3feet by 4 feet how many feet are now left for planting? Express your answer on factored form
Answer:
(L-6)(L+2)
Step-by-step explanation:
Let L be the length of the flower garden.
Then the width will be L-4.
The area of the flower garden = L*(L-4) =L²-4L
The area of the birdbath is 3*4 = 12 ft²
The area of the remaining space for planting is
= Area of flower garden - area of birdbath
L² - 4L - 12We can factor the expression as follows:
L² - 4L - 12 L²-(6-2)L-12L²-6x+2x-12taking common frome each two terms
L(L-6)+2(L-6)(L-6)(L+2)Therefore, the number of feet left for planting is (L-6)(L+2) in factored form.
A bag of marbles only has red and blue marbles. The bag has a ratio of blue marbles to red marbles of 3:5, and there are 24 blue marbles in the bag. What is the total number of marbles in the bag?
Answer:
64 marbles
Step-by-step explanation:
24 ÷ 3 = 88 × 5 = 40 (40 total red marbles)40 + 24 = 64The solution is, 24 is the total number of marbles in the bag.
What is ratio?The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.
here, we have,
given that,
A bag of marbles only has red and blue marbles.
The bag has a ratio of blue marbles to red marbles of 3:5,
and there are 24 blue marbles in the bag.
we have to find the total number of marbles in the bag.
let, there are x red marbles .
we have,
blue marbles : red marbles = 3:5
so, we get,
blue marbles : red marbles = 24 : x
i.e. 3:5 = 24 : x
so, x = 24 * 5 / 3
or, x = 8*5
or, x = 40
so, there are 24 red marbles .
so, total = 24 + 40 = 64
Hence, The solution is, 24 is the total number of marbles in the bag.
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Help please! Which of the following tables represents a relation that is a function? Explained answer please
A
B
C
D
Answer:
Step-by-step explanation:
THE ANSWER TO YOUR QUESTION IS C.
Solve: |x−6|+7≥−1. Write your solution in interval notation.
Answer:
-2 ≤ x ≤ 14
Step-by-step explanation:
x - 6 + 7 ≥ -1
x + 1 ≥ -1
x ≥ -2
-(x - 6) + 7 ≥ -1
-x + 6 + 7 ≥ -1
-x + 13 ≥ -1
-x ≥ -14
x ≤ 14
Joesph and molly each have coin collections. Joesph starts with 15 coins in his collection and adds 25 coins each month. Molly starts with 25 coins in her collection and adds 25 coins to each month. If Joseph and molly continue to collect this way, how many coins will each person have after 10 months?
Answer:
Joseph- 265 coins
molly- 275 coins
PLSSSS HELPPP I WILL FIVE BRAINLY!!!!
Answer:
The first box : -4 the second one : 6
Step-by-step explanation:
subtract 7 from 3 for the first box, then add 10 to -4 for the second one.
How many 11-card hands are possible with a 20-card deck?
There is only 1 possible 11-card hand that can be formed from a 20-card deck.
To determine the number of 11-card hands possible with a 20-card deck, we can use the concept of combinations.
The number of combinations, denoted as "nCk," represents the number of ways to choose k items from a set of n items without regard to the order. In this case, we want to find the number of 11-card hands from a 20-card deck.
The formula for combinations is:
nCk = n! / (k!(n-k)!)
Where "!" denotes the factorial of a number.
Substituting the values into the formula:
20C11 = 20! / (11!(20-11)!)
Simplifying further:
20C11 = 20! / (11! * 9!)
Now, let's calculate the factorial values:
20! = 20 * 19 * 18 * ... * 2 * 1
11! = 11 * 10 * 9 * ... * 2 * 1
9! = 9 * 8 * 7 * ... * 2 * 1
By canceling out common terms in the numerator and denominator, we get:
20C11 = (20 * 19 * 18 * ... * 12) / (11 * 10 * 9 * ... * 2 * 1)
Performing the multiplication:
20C11 = 39,916,800 / 39,916,800
Finally, the result simplifies to:
20C11 = 1
Consequently, with a 20-card deck, there is only one potential 11-card hand.
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If f(x) = -5, find the value of x in the function f(x) = 6x + 1.
Answer:
X = -1
Step-by-step explanation:
f(-1) = 6(-1) + 1
6 * -1 = -6
-6 + 1 is equal to -5
I hope this helps (:
A certain sum of money at simple interest amount to $1300 in 4 years and to $1525 in 7 years. Find the sum and the rate percent
Answer:
P((1 + r)^4) = 1,300
P((1 + r)^7) = 1,525
-----------------------
(1 + r)^3 = 61/52, so r = .0547 = 5.47%
P(1.0547^4) = 1,300, so P = $1,050.78
A guy wire runs from the ground to a cell tower. The wire is attached to the cell tower 50 meters above the ground. The angle formed between the wire and the ground is 42° (see figure). (Round your answers to one decimal place.)
(a) How long is the guy wire (in meters)?
(b)How far from the base of the tower (in meters) is the guy wire anchored to the ground?
The length of the guy wire is; 74.72 meters and the distance of its anchor point to the base of the tower is; 55.53 meters.
What is the length of the guy wire?a). The length of the guy wire in discuss as described in the task content can be determined by means of trigonometric ratios as follows;
Sin 42° = 50/x
x = 50/sin 42°
x = 74.72 meters.
b). The distance between the base of the tower and the anchor point of the guy wire can be determined as follows;
Tan 42° = 50/y
y = 50/tan 42°
y = 55.53 meters.
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what is 12 = -5x + 2
Answer:
Hi there!
Your answer is;
-2= x
Step-by-step explanation:
12= -5x +2
-2
10= -5x
/-5
-2 = x
Hope this helps
Answer: x = -2 give me brainliest
Step-by-step explanation:
2.3x + 8 = - 1.7x - 8 solve for x
The value of x after solving (2.3x + 8) = (-1.7x-8) is -4.
According to the question,
We have the following expression:
(2.3x + 8) = (-1.7x-8)
Now, moving -1.7x from the right hand side to the left hand side will result in the change of its sign from minus to plus:
2.3x+1.7x +8 = -8
4x+8 = -8
Now, moving 8 from the left hand side to the right hand side will also result in the change of the sign from plus to minus:
4x = -8-8
4x = -16
x = -16/4 (4 was in multiplication on the left hand side. So, it is in division on the right hand side.)
x = -4
Hence, the value of x is -4.
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NEED HELP ASAP
BEST ANSWER WILL BE MARKED AS BRAINLEST
Answer:
The answer to this problem would be D
Step-by-step explanation:
Hope this helped!!
Tell me if im wrong
For each pair of function f and g below, find f(g(x)) and g(f(x)).
a. f(x)=3/x,x=/= 0
b. g(x)=3/x, x=/=0
c. f(x)=x+4
d. g(x)=-x+4
Answer:
(a) and (b)
\(f(g(x)) = g(f(x)) = x\)
(c) and (d)
\(f(g(x)) =-x + 8\)
\(g(f(x)) = x + 8\)
Step-by-step explanation:
Given
(a) to (d)
Required
Find f(g(x)) and g(f(x)) for each pair
For (a) and (b), we have:
\(f(x) = \frac{3}{x}\)
\(g(x) = \frac{3}{x}\)
Calculate f(g(x))
\(f(x) = \frac{3}{x}\)
\(f(g(x)) = \frac{3}{g(x)}\)
Substitute 3/x for g(x)
\(f(g(x)) = \frac{3}{3/x}\)
Rewrite as:
\(f(g(x)) = 3/\frac{3}{x}\)
\(f(g(x)) = 3*\frac{x}{3}\)
\(f(g(x)) = x\)
Since f(x) = g(x), then:
\(f(g(x)) = g(f(x)) = x\)
For (c) and (d)
\(f(x) =x + 4\)
\(g(x) =-x + 4\)
Solving f(g(x)), we have:
\(f(x) =x + 4\)
\(f(g(x)) =g(x) + 4\)
Substitute \(g(x) =-x + 4\)
\(f(g(x)) =-x + 4 + 4\)
\(f(g(x)) =-x + 8\)
Calculating g(f(x))
\(g(x) =-x + 4\)
\(g(f(x)) = -f(x) + 4\)
Substitute: \(f(x) =x + 4\)
\(g(f(x)) = x + 4 + 4\)
\(g(f(x)) = x + 8\)
Simplify with negative radicands in terms of i.
5+ V-49
6
x=
-1/3i
2i
O
5/6 + 7/61
5/6 - 7/61
Answer: C. 5/6+7/6i
Step-by-step explanation: just did it on Edg
The equation in the form of i will be 5/6 + (7/6)i. Then the correct option is C.
What is simplification?Making anything easier to accomplish or comprehend, as well as making it less difficult, is the definition of simplification.
The equation is given below.
\(x = \dfrac{5 + \sqrt{-49}}{6}\)
We know that √(-1) = i, then we have
x = 5/6 + (√49 / 6)i
x = 5/6 + (7/6)i
Then the correct option is C.
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Plz help! I don't understand these problems!
Find the value of x in each case.
-9a-2(9a-5) need help
Answer: -81a^2 + 27a + 10
Step-by-step explanation: We can do this question by using FOIL (first, outer, inner, last)
(-9a-2)(9a-5)
First, multiply the first two terms in the parentheses
-9a times 9a is -81a^2
Second, multiply the outer terms
-9a times -5 is 45a
Third, multiply the inner terms
-2 times 9a is -18a
And lastly, multiply the last terms
-2 times -5 is 10
After doing this we end up with -81a^2 + 45a - 18a + 10 = -81a^2 + 27a + 10
I need to make a equation that fits the spaces and the equation. pls help
Answer:
-3, 2 , 3.3 , 4.6, 5.9
Step-by-step explanation:
I just counted where the dots were for example "-5"
Answer:
-3, 2 , 3.3 , 4.6, 5.9
The standard deviation of a population is 1.9. What is the margin of error? Enter your answer in the box. ±
The margin of error is defined as follows:
M = 1.9z/sqrt(n).
In which:
z is the critical value.n is the sample size.What is a z-distribution confidence interval?The bounds of the confidence interval are given as follows:
\(\overline{x} \pm z\frac{\sigma}{\sqrt{n}}\)
In which:
\(\overline{x}\) is the sample mean.z is the critical value.n is the sample size.\(\sigma\) is the standard deviation for the population.The margin of error is then given as follows:
\(M = z\frac{\sigma}{\sqrt{n}}\)
Missing InformationThe problem is incomplete, hence the general procedure to obtain the sample size was presented.
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help pls
solve the equation
4 to the power of 3x ÷ 2 to the power of 4x =32
Answer:
x = 5/2
Step-by-step explanation:
(4^3x)/(2^4x) = 32
(2^6x)/(2^4x) = 32
2^2x = 32
2^2x = 2^5
2x = 5
x = 5/2
if 9 kg of sugar cost to 238.50 how much sugar can be bought for 371
Answer:
14 kg
Step-by-step explanation:
Set up a proportion:
9/238.5 = x/371
Cross multiply.
9 x 371 = 3339
238.5 times x = 238.5x
238.5x = 3339
Divide by 238.5 on both sides.
3339/238.5 = 14
The value of "y" varies directly with "x" and y = -8 when x = 20. Find "y" if x = -4. Next, solve the equation for k. -8 = k (20) [?] k = - 1² Reduce to simplest form.
The value of y when x = -4 for the given proportion will be 8/5 and the value of the k for the given equation is (-8/20).
What are the ratio and proportion?The ratio is the division of the two numbers.
For example, a/b, where a will be the numerator and b will be the denominator.
Proportion is the relation of a variable with another. It could be direct or inverse.
As per the given,
y = -8 when x = 20
The ratio of y and x = -8/20
With the same ratio value of y if x = -4
y/(-4) = -8/20
y = (-8/20)(-4) = 8/5
As per the given equation,
-8 = k(20)
k = (-8/20)
Hence "The value of y when x = -4 for the given proportion will be 8/5 and the value of the k for the given equation is (-8/20)".
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The altitude to the hypotenuse of a right triangle divides the hypotenuse into segments of length 6 and 9 what is the length of the altitude
The length of the altitude is 3√6.
According to Right Triangle Altitude Theorem
The altitude drawn from the vertex of the right angle of a right triangle to its hypotenuse has a length that is the geometric mean of the lengths of the two segments of the hypotenuse.
So, AD = √CD. DB
Here we have CD=6 and DB=9 so
AD = √6 x 9
AD = √54
AD = 3√6
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solve the PDE using separation of variables method Uxx = 1/2 Ut 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)
The general solution of the partial differential equation is:
U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)
How to solve Partial Differential Equations?The partial differential equation (PDE) is given as:
Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)
Assume that the solution can be written as a product of two functions:
U(x, t) = X(x)T(t)
Substituting this into the PDE, we have:
X''(x)T(t) = (1/2)X(x)T'(t)
Dividing both sides by X(x)T(t), we get:
(X''(x))/X(x) = (1/2)(T'(t))/T(t)
Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:
(X''(x))/X(x) = -λ²
(1/2)(T'(t))/T(t) = -λ²
Simplifying the second equation, we have:
T'(t)/T(t) = -2λ²
Solving the second equation, we find:
T(t) = Ce^(-2λ²t)
Applying the boundary condition U(0, t) = 0, we have:
U(0, t) = X(0)T(t) = 0
Since T(t) ≠ 0, we must have X(0) = 0.
Applying the boundary condition U(3, t) = 0, we have:
U(3, t) = X(3)T(t) = 0
Again, since T(t) ≠ 0, we must have X(3) = 0.
Therefore, we can conclude that X(x) must satisfy the following boundary value problem:
X''(x)/X(x) = -λ²
X(0) = 0
X(3) = 0
The general solution to this ordinary differential equation is given by:
X(x) = Asin(λx) + Bcos(λx)
Applying the initial condition U(x, 0) = 5*sin(4πx), we have:
U(x, 0) = X(x)T(0) = X(x)C
Comparing this with the given initial condition, we can conclude that T(0) = C = 5.
Therefore, the complete solution for U(x, t) is given by:
U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)
where:
Σ represents the summation over all values of n
λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).
To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):
X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0
X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0
From the first equation, we have Bₙ = 0.
From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.
This implies that 3λₙ = nπ, where n is an integer.
Therefore, λₙ = (nπ)/3.
Substituting the eigenvalues into the general solution, we have:
U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)
where Aₙ are the coefficients that can be determined from the initial condition.
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