The rate of effusion of NH3 is 2.40 mole/min. What would be the rate of effusion of He under the same conditions?

The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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A high mountain peak near the equator could have snow on it all year long because of the altitude. That is option C.

Equator is defined as the imaginary line of latitude that divides the earth into Northern and Southern hemispheres.

There are various regions of the earth that are located near the equator which experiences the equatorial climate throughout the year.

As the the high mountain peak near the equator, they could have snow on it all year long because of increased altitude.

This shows that air around this region becomes thinner and lacks the ability to absorb and retain heat leading to the presence of snow on the mountain top all year long.

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Answer:

317.7778 g

Explanation:

Given data:

Flour required for 18 cup cakes = 260 g

Flour required for 22 cup cakes = ?

Solution:

We will calculate the flour required for 1 cup cake.

260 g /18   = 14.4444 g

Fluor required for 22 cupcakes,

22× 14.4444 g = 317.7778 g

In short,

22 cupcake/18 cup cake×260 g = 317.7778 g

A student combusted magnesium ribbon in a crucible to produce magnesium oxide according to the reaction: the mass of the oxygen reacted is 0.39 g.

The balanced chemical equations given as :

2Mg   +  O₂   ----->    2MgO

given that :

mass of the oxygen reacted.

Mass of crucible + lid: 23.321 g

Mass of magnesium + crucible + lid: 23.914 g

Mass of magnesium oxide + crucible + lid: 24.821 g

mass of magnesium=(mass of magnesium +crucible+ lid )- (mass of

                                                                                            crucible + lid )

                                 = 23.914 - 23.321

                                = 0.593 g

mass of magnesium = 0.593 g

molar mass of magnesium is = 24 g/mol

number of moles of magnesium = mass / molar mass

                                                    = 0.593 / 24

                                                    = 0.0247 mol

2 moles of Mg react with one mole of  O₂

0.0247 mole react react with = 0.0247 / 2 = 0.0123 mol

mass of oxygen = moles × molar mass

                          = 0.0123 × 32

                          = 0.39 g

Thus, A student combusted magnesium ribbon in a crucible to produce magnesium oxide according to the reaction: the mass of the oxygen reacted is 0.39 g.

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Answer:

H

Explanation:

Answer:

c

Explanation:

ok than not c than b maybe

Answer:

2,019 km

Explanation:

Step 1: Given data

Distance traveled by the car (D): 1,255 mi

Step 2: Convert the distance traveled by the car to kilometers

To convert one unit into another, we use a conversion factor. In this case, the appropriate conversion factor between miles and kilometers is 1 mile = 1.609 km. The distance traveled by the car, in kilometers, is:

D = 1,255 mi × (1.609 km/1 mi) = 2,019 km

The balanced equation  \(K_{2}Cr_{2}O_{7}\) oxidizes KI in the presence of \(H_{2}SO_{4}\)can be represented as

6 KI + \(K_{2}Cr_{2}O_{7}\) + 7 \(H_{2}SO_{4}\) → 4 \(K_{2}Cr_{2}O_{7}\) + \(Cr_{2}(SO_{4})_{3}\) + 3 \(I_{2}\)\(I_{2}\) + 7 \(H_{2}O\)

The balanced equation for the oxidation of KI (potassium iodide) by \(K_{2}Cr_{2}O_{7}\)(potassium dichromate) in the presence of \(H_{2}SO_{4}\)(sulfuric acid) can be represented as follows:

6 KI + \(K_{2}Cr_{2}O_{7}\) + 7 \(H_{2}SO_{4}\) → 4 \(K_{2}Cr_{2}O_{7}\) + \(Cr_{2}(SO_{4})_{3}\) + 3 \(I_{2}\)\(I_{2}\) + 7 \(H_{2}O\)

In this equation, \(K_{2}Cr_{2}O_{7}\) is the oxidizing agent, and KI is the substance being oxidized. The sulfuric acid (\(H_{2}SO_{4}\)) serves as a catalyst and provides the necessary acidic conditions for the reaction to occur.

The products of the reaction are potassium sulfate (\(K_{2}SO_{4}\)), chromium(III) sulfate (\(Cr_{2}(SO_{4})_{3}\)), iodine (), and water (\(H_{2}O\)).

Note that this equation represents a stoichiometrically balanced equation, ensuring that the number of atoms of each element is the same on both sides of the equation.

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Answer:

Which of the following is a possible set of quantum numbers for a 3p orbital?

Since you are dealing with a 3p-orbital, your principal and angular momentum quantum numbers will be n=3 and l=1 .

Given the mass of KHP that you have weighed out, the indicator's color change persists longer and you are approaching the endpoint of this titration. You should add NaOH in small increments to avoid overshooting the endpoint. The correct answer is D.

You are getting close to the finish of this titration because the indicator's color shift lasts longer given the mass of KHP that you have weighed out. To prevent overshooting the target, add NaOH in modest doses.

KHP, sometimes referred to as potassium hydrogen phthalate, is a salt chemical with an acidic pH. The products are a colorless solution, white powder, colorless crystals, and an ionic solid that is phthalic acid's monopotassium salt. Despite its low acidity, KHP is a reliable and air-stable primary standard for acid-base titrations.

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Answer: sweet home

Explanation:

The fingerprint region is the right term for this area. The IR spectrum of a molecule is a graphical depiction of the vibrational frequencies of the molecule's bonds.

The fingerprint area is the portion of the IR spectra between 1,000 and 400 cm-1 that is frequently used to distinguish between identical molecules with the same functional groups. This is due to the fact that each molecule has a unique bond configuration, which results in a unique set of vibrational frequencies.The fingerprint region is the right term for this area. The IR spectrum of a molecule is a graphical depiction of the vibrational frequencies of the molecule's bonds.  It is possible to identify individual molecules and distinguish between similar ones by studying the peaks in the fingerprint area.The remaining areas indicated, the downfield, functional group, and Ri regions, are not typically used to define the IR spectrum.

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thefunctionalgroupregion These are often connected to functional group stretching vibrationsA functional group's stretching vibrations are restricted to a small range

Functional connection is defined as the geographically dispersed neurophysiological events' temporal coherence (Friston, 1994). In other words, if there is a statistical link between the activity measurements that have been recorded for two areas, then those two regions are said to exhibit functional connectivity. This connection strategy is based on the idea that if two regions' functional activity is regularly associated, then those two areas are assumed to be connected or to be parts of the same network Functional connectivity is a considerably more direct method of analysing functional networks than effective connectivity studies, which rely on a number of assumptions about the underlying neurobiology and the model used to predict it. Particularly it is in agreement with the intuitive

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Answer:

The correct answer is -

takes place in the Sun

plays a role in the production of essentially all elements heavier than helium

releases large amounts of energy

Explanation:

Fusion reaction takes place when two or more small atomic nuclei come in close proximation for a longer time so the nuclear force pulling them together and form into heavier molecules than helium and releases a huge amount of energy by this process.

A great example of this fusion reaction is the sun where nuclear fusion takes place inside the core of the sun and result in a huge amount of release as it is an exothermic reaction.

Answer:

Explanation

EDGE2021

Answer:

1.03 x 10²³ atoms NaCl

Explanation:

To find the amount of table salt (NaCl) in atoms, you need to (1) convert grams to moles (using the molar mass) and then (2) convert moles to atoms (using Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units.

(Step 1)

Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol

Molar Mass (NaCl): 58.44 g/mol

10 grams NaCl                1 mole
------------------------  x  -----------------------  =  0.17 moles NaCl
                                   58.44 grams

(Step 2)

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

0.17 moles NaCl           6.022 x 10²³ atoms
--------------------------  x  --------------------------------  =  1.03 x 10²³ atoms NaCl
                                                 1 mole

Answer:

2.48 × 10⁴ mol

Explanation:

Step 1: Write the balanced equation

2 CrO₄²⁻ + 3 SO₂ + 4 H⁺ ⇒ Cr₂(SO₄)₃ + 2 H₂O

Step 2: Calculate the reacting moles of CrO₄²⁻

3.00 × 10⁸ L of 5.50 × 10⁻² mM CrO₄²⁻ react. The reacting moles are:

3.00 × 10⁸ L × 5.50 × 10⁻² × 10⁻³ mol/L = 1.65 × 10⁴ mol

Step 3: Calculate the reacting moles of SO₂

The molar ratio of CrO₄²⁻ to SO₂ is 2:3. The reacting moles of SO₂ are 3/2 × 1.65 × 10⁴ mol = 2.48 × 10⁴ mol.

1584 Kg of SO2 is required to treat 3.00 x 10^8 L of 5.50 x 10^-2 mM Cr(VI).

The equation of the reaction is;

2CrO4^2-(aq) + 3SO2(g) + 4H^+(aq) -------> Cr2(SO4)3(s) + 2H2O(l)

Number of moles of Cr(VI) = concentration × volume

concentration =  5.50 x 10^-2 mM or 5.5 x 10^-5 M

volume =  3.00 x 10^8 L

Number of moles of Cr(VI) = 5.5 x 10^-5 M × 3.00 x 10^8 L

= 1.65 x 10^4 moles

From the reaction equation;

2 moles of Cr(VI) reacts with 3 moles of SO2

1.65 x 10^4 moles reacts with  1.65 x 10^4 moles ×  3 moles/2 moles

= 24750 moles

Mass of SO2 = 24750 moles × 64 g/mol

Mass of SO2 = 1584 Kg of SO2

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Answer:

013 g/mol is the molar mass of N2O.

Answer:

Wearing goggles or other eye protection will remove the risk or danger for these students

Explanation:

Soft contact lenses are usually worn in the eyes and Ammonia compound may fog the lens thereby retaining the particles of ammonia which could spread to the eye and cause a lot of damage to it.

Using a goggle is usually more effective in dealing with the risks involved as they prevent the Ammonia from having any contact at all with the eyes due to the far proximity to the eyes when compared to contact lenses.

The amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

To find the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C, we can use the equation Q = mcAT.
First, we need to find the value of m, which is the mass of the water in grams. In this case, it is given as 200 grams.
Next, we need to find the value of AT, which is the change in temperature in degrees Celsius.

This can be calculated by subtracting the initial temperature from the final temperature, which gives us 60 C - 20 C = 40 C.
The specific heat capacity of water, C, is given as 4.18 Joules per gram per degree Celsius.
Now we can plug in the values into the equation:
Q = mcAT
Q = (200 g) x (4.18 J/g°C) x (40°C)
Q = 33,440 J
Therefore, the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

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By definition of atomic number, the correct answers are:

You have to know that atoms are made up of a nucleus made up of protons and neutrons, and a shell made up of electrons. Protons are positively charged, while neutrons are electrically neutral (that is, they have zero charge). Therefore the atomic nucleus always has a positive charge. On the other hand, electrons are negatively charged.

The atomic number is the total number of protons that make up the atomic nucleus of a given chemical element and is represented by the letter Z.

An atom is naturally neutral and has the same number of electrons and protons.

The atomic number is used to classify the elements within the periodic table of elements, going from the smallest to the largest number of protons in the nucleus as you progress through the rows and columns of the table. That is, as you travel a period (row) from left to right and as you travel a group (column) from top to bottom, the atomic number increases.

In summary, the correct answers are:

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Answer:

The answer is "The number of protons is given by the atomic number, which increases by one moving from left to right across each row of the periodic table."

Explanation:

If you look at the periodic table, the elements atomic numbers increase from left to right by one. Therefore, the protons also increase by one from left to right because the number of protons in an element is the same as the atomic number.

Answer:

30 ml

Explanation:

Answer: 4 and 1.

Explanation:

Answer:

4.99*10²³ molecules of N₂O₄ are in 76.3 g of N₂O₄

Explanation:

Avogadro's Number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension. Avogadro's number applies to any substance.

You know that the molar mass of N₂O₄ is 92.02 g/mol, and you have 76.3 g. Then you can apply the following rule of three: 92.02 grams are present in 1 mole of the compound, 76.3 grams in how many moles are they?

\(amount of moles= \frac{76.3 grams*1 mole}{92.02 grams}\)

amount of moles= 0.83 moles

Then, you can apply another rule of three: if by definition of Avogadro's number 1 mole of the compound has 6.023*10²³ molecules, 0.83 moles of the compound, how many molecules will it have?

\(amount of molecules= \frac{0.83 moles*6.023*10^{23}molecules }{1 mole}\)

amount of molecules= 4.99*10²³

4.99*10²³ molecules of N₂O₄ are in 76.3 g of N₂O₄

Amobarbital (like all barbiturates) works by being incontestible to the GABAA receptor at either the alpha or the beta subunit.

Amobarbital (like all barbiturates) works by binding to the GABAA receptor at either the alpha or the beta subunit. These are compulsory sites that are distinct from GABA itself and also distinct from the benzodiazepine binding site.

Amobarbital is a barbiturate classified as having a halfway duration of action, meaning that the effects of the drug can last from 4-6 amobarbital increases the effects of benazepril by apparatus: pharmacodynamic synergism.

So we can conclude that Amobarbital, 5-ethyl-5-isoamyl barbituric acid like all barbiturates.

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The mass of hydrogen in the balloon 10m in diameter is 0.419 grams.

To calculate the mass of hydrogen in a balloon with a 10m diameter, filled at a pressure of 1 standard atmosphere and a temperature of 27°C, we can use the ideal gas law.

Convert the diameter of the balloon to its radius:

Radius = Diameter / 2

= 10 m / 2

= 5 m

Calculate the volume of the balloon:

Volume = (4/3) * π * (\(Radius^{3}\))

Volume = (4/3) * 3.14159 * (\(5^{3}\)) = 523.599 m³

Convert the temperature from Celsius to Kelvin:

Kelvin temperature = Celsius temperature + 273.15

Kelvin temperature = 27°C + 273.15 = 300.15 K

Convert the pressure to Pascals (Pa):

1 atm = 101325 Pa

Determine the number of moles of hydrogen using the ideal gas law:

PV = nRT

n = PV / RT

Where:

P = Pressure = 1 atm = 101325 Pa

V = Volume = 523.599 m³

R = gas constant = 8.314 J/(mol·K)

T = Temperature = 300.15 K

n = (101325 Pa) * (523.599 m³) / ((8.314 J/(mol·K)) * (300.15 K))

n ≈ 21927.41 mol

Convert moles to grams using the molar mass of hydrogen:

Molar mass of hydrogen (H₂) = 2 g/mol

Mass of hydrogen = n * (Molar mass of hydrogen)

Mass of hydrogen = 21927.41 mol * 2 g/mol

Mass of hydrogen ≈ 43854.82 g

Therefore, the mass of hydrogen in the balloon 10m in diameter is 0.419 grams.

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Answer:

The answer is the second one

The rainwater sample has a pH of 4.35, indicating that it is acidic. The concentration of \(H_3O^+\) ions in the sample is \(4.47 * 10^{-5} M\), which is higher than in neutral or basic solutions.

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Answer:

molar mass CO = 28.01 g/mol

3.45 x 10^2 x 28.01 =9.66 x 10^3 g

mass Zn = 2.45 x 10^-2 x 65.39 g/mol=1.60 g => 1.60 x 10^0

Explanation:

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One mole of cobalt weighs 58.9 grams. Hence the mass in grams of 345 moles of cobalt is 20320.5 g.

Cobalt is 27th element in periodic table. It is place in d- block of periodic table and is termed as transition metal. Transition metals sows variable oxidation states.

The atomic number of cobalt is 27. Thus, it contains 27 protons and 27 electrons. The mass number is 57. The mass of a given number of moles of an element can be calculated by multiplying its atomic mass by number of moles.

The atomic mass of cobalt = 58.9 g/mol

The mass of one mole of cobalt is 58.9 g/mol.

Thus, the mass of 345 moles of cobalt is calculated as follows:

mass of 345 moles of Co = 345 mol × 58.9 g/mol = 20320 g.

Therefore, the mass of cobalt in 345 moles is 20320 grams.

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Answer:

Star A would have the greater absolute brightness. This is because absolute brightness finds out the actual brightness of a star at a standard distance from Earth. If Star A is twice as far from Earth as Star B but they still both appear to have the same amount of brightness.