Answer: C≈28.27cm
Step-by-step explanation:
C=2πr=2·π·4.5≈28.27433cm
Answer:
28.3 cm
Step-by-step explanation:
You want the circumference of a circle with radius 4.5 cm.
CircumferenceThe circumference of a circle is given by ...
C = 2πr
For the given circle, the circumference is ...
C = 2π(4.5 cm) = 9π cm ≈ 28.3 cm
The circumference is about 28.3 cm.
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Pls help me with this question.
Answer:
C or D would be the best answers to choose from
Step-by-step explanation:
Needs to be answered by the 17th, thanks :))
Answer:
w = 5/4
Step-by-step explanation:
divide each side by -4/5
Answer:
w = 5/4
Step-by-step explanation:
-4/5w = -1
Divided both sides by -4/5
w = 5/4
Let's Check
-4/5(5/4) = -1
-1 = -1
So, w = 5/4 is the correct answer.
Using an integrating factor, solve y-y-5 CD- in the method for solving a first-order linear differential equation, the first step is to put the equation in the standard form y alty bit). is the given equation in the standard form? No Yes Identify a(t) and bit)
The value of a(t) is -1 and b(t) is 55 + \(e^t\)
No, the given equation y' - y = 55 + \(e^t\) is not in the standard form of a first-order linear differential equation.
In the method for solving a first-order linear differential equation, an integrating factor is a function used to transform the equation into a form that can be easily solved.
For an equation in the standard form y' + a(t)y = b(t), the integrating factor is defined as:
μ(t) = e^∫a(t)dt
To solve the equation, you multiply both sides of the equation by the integrating factor μ(t) and then simplify. This multiplication helps to make the left side of the equation integrable and simplifies the process of finding the solution.
To put it in standard form, we need to rewrite it as y' + a(t)y = b(t).
Comparing the given equation with the standard form, we can identify:
a(t) = -1
b(t) = 55 + \(e^t\)
Therefore, The value of a(t) is -1 and b(t) is 55 + \(e^t\)
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If y varies directly with x and y=20.4 when x=6, find the value of y when x=-5?
A. Y=17
B. Y=24.48
C. Y=1.47
D. Y=3.4
Answer:
y=-17
Step-by-step explanation:
y=mx
20.4=m×6
20.4÷6=m
3.4=m
y=3.4×-5
y=-17
The value of the variable 'y' at x = 5 will be 17. Then the correct option is A.
What are ratio and proportion?A ratio is a group of sequentially ordered numbers a and b expressed as a/b, where b is never equal to zero. When two objects are equal, a statement is said to be proportional.
If y varies directly with x. Then we have
y ∝ x
y = kx
At x = 6 and y = 20.4, then the value of the constant k is calculated as,
20.4 = k(6)
k = 20.4 / 6
k = 3.4
Then the equation is given as,
y = 3.4 x
The value of the variable 'y' at x = 5 will be calculated as,
y = 3.4 (5)
y = 17
The worth of the variable 'y' at x = 5 will be 17. Then, at that point, the right choice is A.
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Decide whether the following statement makes sense (or is clearly true) or does not make sense (or is clearly false). Explain your reasoning. I estimate that the probability of my getting married in the next 3 years is 0.7. math
The statement "I estimate that the probability of my getting married in the next 3 years is 0.7" does make sense.
As individuals, we can make personal estimates or predictions about events that are relevant to our lives, such as the probability of getting married in a certain timeframe. These estimates are based on our own subjective beliefs, experiences, and expectations. While they may not be based on precise mathematical calculations or rigorous statistical analysis, they can still reflect our personal opinions or perceptions.
In this case, the person is providing an estimate that they believe there is a 0.7 (or 70%) probability of getting married within the next 3 years. This estimate is a subjective assessment of their own chances based on various factors such as their current relationship status, personal goals, or cultural norms.
It is important to note that personal estimates like this are not necessarily based on concrete evidence or universally applicable probabilities. They can vary greatly from person to person and are subjective in nature. However, they can still hold personal meaning and influence one's decision-making or expectations regarding future events.
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4.83×10^5 as an ordinary number
Answer:
483,000
Step-by-step explanation:
10^5=100,000
4.83×100,000=483,000
Explain some of the opinions on women being on bicycles back then.
Answer:
To women, it was a steed upon which they rode into a new world. All this triggered a backlash from many (male) doctors and onlookers, who cited all sorts of reasons to dissuade women from riding bikes. It would lead to not only bicycle face, but also exhaustion, insomnia, heart palpitations, headaches, and depression. During the late 19th and early 20th centuries, women began to escape some of their restrictions by riding bycicles. Despite strong opposition from men, women cycled on, and the bicycle became an instrument of change that subverted the status quo and became a powerful symbol of women's emancipation.
Step-by-step explanation:
Simplify the following sentence in predicate logic so that all the negation symbols are directly in front of a predicate. (For example, ∀x((¬O(x))→(¬E(x))) is simplified, because the negation symbols are directly in front of the predicates O and E. However, ∀x¬(P(x)∨E(x)) is not simplified.) Show your working. ¬(∀x(E(x)→(S(x)∨∃y(G(y,x))))). Write a sentence in predicate logic (using the same predicates as above) which is true when the class of domain is the class of all integers (…,−2,−1,0,1,2,…), but is false when the domain is the class of positive integers (1,2,3,…). (You do not need to explain
The entire sentence is false for the class of positive integers.
The given predicate logic is ¬(∀x(E(x)→(S(x)∨∃y(G(y,x)))) to simplify this sentence, first, we need to negate the outside predicate:¬(¬∀x(E(x)→(S(x)∨∃y(G(y,x)))))
Then, we need to move the negation inside the parentheses: ∃x¬(E(x)→(S(x)∨∃y(G(y,x))))
We can also simplify the implication by using the rule for rewriting implication, which is equivalent to a disjunction with a negation as an antecedent:∃x(E(x)∧¬(S(x)∨∃y(G(y,x))))
Using the above predicates, we can write a sentence that is true for all integers but false for positive integers.
Let A be the set of all integers, we can write this sentence as: ∀x(x∈A→E(x)∧¬(S(x)∨∃y(G(y,x))))
This sentence is true for all integers because all integers satisfy the condition that x∈A.
However, it is false for positive integers because the predicate E(x) is true for all positive integers, but the second predicate, ¬(S(x)∨∃y(G(y,x))), is false for x=1 since S(1) is true and G(y,1) is false for all y.
Therefore, the entire sentence is false for the class of positive integers.
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Marco has two bags of candy. One bag contains three red lollipops and
2 green lollipops. The other bag contains four purple lollipops and five blue
lollipops. One piece of candy is drawn from each bag. What is the probability
of choosing a green lollipop and a purple lollipop?
The value of the probability of choosing a green lollipop and a purple lollipop is, 8 / 45
We have to given that;
One bag contains 3 red lollipops and 2 green lollipops.
And, The other bag contains four purple lollipops and five blue lollipops.
Hence, The probability of choosing a green lollipop is,
P₁ = 2 / 5
And, The probability of choosing a purple lollipop is,
P₂ = 4 / 9
Thus, The value of the probability of choosing a green lollipop and a purple lollipop is,
P = P₁ × P₂
P = 2/5 × 4/9
P = 8/45
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The path of a firework is described by the function:
h(t) = -4.9(t-5)² + 124 where h(t) is the height of the firework, in meters, and t is the time in
seconds, since the launch.
What is the vertex of the function, and what does it mean in context?
A. (5, 4.9); At 5 seconds, the firework is 4.9 meters above the ground.
B. (124, 5); At 124 seconds, the firework is 5 meters above the ground.
C. (4.9, 124); At 4.9 seconds, the firework is 124 meters above the ground.
D. (5, 124); At 5 seconds, the firework is 124 meters above the ground.
Answer:
D
Step-by-step explanation:
Because this binary function opens down, and it has an extreme point, at t=5, and you plug it in and you get 124 as the maximum.
the united states postal service (usps) delivers nearly 200 million pieces of mail every day. their website and internal operations are powered by many algorithms. an illustration of the usps delivery flow. the start of the flow is a house icon, with an arrow to an envelope icon, another arrow labeled usps to another envelope icon, and an arrow from there to another house icon. which algorithm's runtime is most likely to be improved by the use of a heuristic? choose 1 answer: choose 1 answer: (choice a) calculating the cost of a package based on weight and distance to destination a calculating the cost of a package based on weight and distance to destination (choice b) identifying the top performing delivery carrier in a region, based on carriers performance scores b identifying the top performing delivery carrier in a region, based on carrier's performance scores (choice c) sorting packages according to expected delivery date, from most urgent to least urgent c sorting packages according to expected delivery date, from most urgent to least urgent (choice d) calculating an efficient route for a delivery carrier through a city, considering factors like parking space and mail volume d calculating an efficient route for a delivery carrier through a city, considering factors like parking space and mail volume
The algorithm whose runtime is most likely to be improved by the use of a heuristic is calculating an efficient route for a delivery carrier through a city, considering factors like parking space and mail volume.
A heuristic is a problem-solving strategy that involves using a practical approach rather than an algorithmic one, often resulting in faster but less precise solutions.
The calculation of an efficient delivery route involves a large number of variables, including traffic, parking, and package volume, which can make it difficult to find the most optimal route.
Using a heuristic to approximate the best route can significantly reduce the time required to find a good solution.
In contrast, calculating the cost of a package based on weight and distance to destination, identifying the top performing delivery carrier in a region, and sorting packages according to expected delivery date are all problems that can be solved efficiently using traditional algorithms.
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12. Bob thought of a number, added 5, multiplied
by 3 and took away 5 to give an answer of 10.
What was the starting number?
Answer:
0
Step-by-step explanation:
Say the number was x.
3(x+5)-5=10
3(x+5)=15
x+5=5
x=0
g(7) =
x² - 5, x≤ (-∞, −7)
9x - 17, x= [-7,2]
(x+1)(x − 5), x=(2,∞)
The graph of this function is a curve which first decreases and then increases and then decreases again.
What is function?In mathematics, a function is a relation between sets that assigns to each element of a first set exactly one element of the second set. Functions are commonly written as an equation, where the first set is the domain and the second set is the range. A function can be described geometrically as a transformation, which is a mapping from one set to another. Functions can be represented graphically, numerically, analytically, and verbally. Many different types of functions exist, including linear, polynomial, exponential, trigonometric, and inverse functions.
The given function G(x) is a piecewise function which is defined in three different intervals. In the interval (-∞,-7), the function G(x) is defined as the equation x² - 5. This equation implies that the output of the function decreases as the input increases. In the interval [-7,2], the function is defined as 9x - 17. This implies that the output increases as the input increases. In the last interval (2,∞), the function is defined as (x+1)(x - 5). This implies that the output decreases as the input increases. The graph of this function is a curve which first decreases and then increases and then decreases again.
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The monthly rent on a two bedroom apartment is $1,643. The monthly rent per square foot is $2.12. What is the total square footage of the apartment?
A two-bedroom apartment has a $1,643 rent each month and $2.12 is paid monthly in rent per square foot. The overall area of the apartment is 775 square footage.
Let's assume that the total square footage of the apartment be X
Given that:
The monthly rent of the apartment = $1,643
The monthly rent per square foot of the apartment = $2.12
Therefore, we can say that,
X = $1,643 / $2.12
Calculating the above equation, we get:
X = 775 square footage
Therefore, the apartment's total square footage is 775.
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Calculating brilliance in epidemiology Context. What follows is a data table showing the development of brilliance among a small class of PHE 450 students. NOTE: Student #8 came in as an existing case of brilliance and did not develop brilliance as a result of exposure to PHE 450. Student WK 1 WK 2 WK 3 WK 4 WK 5 WK6 WK 7 WK 8 WK 9 WK 10 CASE CASE CASE CASE DROP 1 2 3 4 5 6 7 8 9 10 11 12 CASE CASE CASE DROP CASE DROP ASSIGNMENT Referring to the data above, please answer the following questions What is the point prevalence of brilliance at the end of Week 1? What is the point prevalence of brilliance at the end of Week 2? • What is the point prevalence of brilliance at the end of Week 3? • Using person-weeks as your denominator, what is the incidence of brilliance over the course of the 10-week course?
The point prevalence of brilliance at the end of Week 1 is 0.08 or 8%.
The point prevalence of brilliance at the end of Week 2 is 0.17 or 17%.
The point prevalence of brilliance at the end of Week 3 is 0.33 or 33%.
Using person-weeks as denominator, the incidence of brilliance over the course of the 10-week course is 0.017 or 1.7%
In epidemiology context, brilliance can be calculated through calculating point prevalence, cumulative incidence, and incidence rate. The provided data table can be used to determine the point prevalence, incidence, and incidence rate of brilliance among PHE 450 students. So, the calculations of point prevalence, cumulative incidence, and incidence rate based on the provided data are as follows:
The point prevalence of brilliance at the end of Week 1 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time
Student #8 was the only existing case of brilliance at the beginning of Week 1, so the point prevalence of brilliance at the end of Week 1 is; Point prevalence = 1 ÷ 12 = 0.08 or 8%.
The point prevalence of brilliance at the end of Week 2 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time
Student #3 and Student #8 were existing cases of brilliance at the beginning of Week 2, so the point prevalence of brilliance at the end of Week 2 is; Point prevalence = 2 ÷ 12 = 0.17 or 17%.
The point prevalence of brilliance at the end of Week 3 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time
Student #3, #4, #6, and #8 were existing cases of brilliance at the beginning of Week 3, so the point prevalence of brilliance at the end of Week 3 is; Point prevalence = 4 ÷ 12 = 0.33 or 33%.
The incidence of brilliance can be calculated by the following formula; Incidence = Total number of new cases ÷ Total person-weeks of observation
Student #5 and Student #7 developed brilliance during the 10-week course, so the incidence of brilliance over the course of the 10-week course is; Incidence = 2 ÷ 120 = 0.017 or 1.7%.
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Measurements are made on the length and width (in cm) of a rectangular component. Because of measurement error, the measurements are random variables. Let X denote the length measurement and let Y denote the width measurement. Assume that the probability density function of X is
The probability density function of X ( length) and Y (width) are \( f(x)= \begin{cases} 10\quad &\ 9.95<x<10.05\\ 0 \quad & \, otherwise \ \end{cases}\) and \( g(y)= \begin{cases} 5\quad &\ 4.9<x<5.1 \\ 0 \quad & \, otherwise \ \end{cases}\) respectively.
a) The probability value for P(X<9.98) is equals to 0.3.
b) The probability value for P(Y> 5.01) is equals to 0.55.
c) The excepted value or mean of f(x), μₓ is equals to 1.
We have measurements of length and width (in cm) of a rectangular component. Let's consider X and Y represents length and width respectively.. The probability density function of X is written as \( f(x)= \begin{cases} 10\quad &\ 9.95<x<10.05\\ 0 \quad & \, otherwise \ \end{cases}\) and Pdf of y is \( g(y)= \begin{cases} 5\quad &\ 4.9<x<5.1 \\ 0 \quad & \, otherwise \ \end{cases}\)
Now, we have to calculate the probability values :
a) The probability value for P(X<9.98)
\(= \int_{-\infty}^{9.95} f(x) dx + \int_{9.95}^{9.98}f(x) dx + \int_{9.98}^{10.05}f(x) dx + \int_{10.05}^{\infty} f(x) dx \\ \)
\(= \int_{-\infty}^{9.95} 0dx + \int_{9.95}^{9.98}10dx + \int_{9.98}^{10.05}0dx + \int_{10.05}^{\infty} 0dx \\ \)
\(= \int_{9.95}^{9.98} 10 \ dx \)
\(= [ 10x]_{9.95}^{9.98} \)
= 10 × 9.98 - 10× 9.95
= 99.8 - 99.5 = 0.3
b) The probability value for P(Y> 5.01)
\(= \int_{-\infty}^{4.9} g(y)dy + \int_{4.9}^{5.01}g(y) dy + \int_{5.01}^{5.1}g(y)dy + \int_{5.1}^{\infty} g(y) dy \\ \)
\(= \int_{-\infty}^{4.9} 0 \:dy + \int_{4.9}^{5.01} 5\ dy + \int_{5.01}^{5.1} 0\ dy + \int_{5.1}^{\infty} 0\ dy \\\)
\(= [ 5y ]_{4.9}^{5.01} \)
= 5 × 5.01 - 5× 4.9
= 5( 0.11) = 0.55
c) The excepted value or mean of f(x) is sum of the product of each possibility x with P(x). So, \(μₓ = \int_{9.95}^{10.05} f(x) dx \)
\(= \int_{9.95}^{10.05} 10 \: dx \)
\(= [ 10 x]_{9.95}^{10.05}\)
= 10 × 10.05 - 10 × 9.95
μₓ = 100.5 - 99.5 = 1
Hence, required value is 1.
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Complete question:
Measurements are made on the length and width (in cm) of a rectangular component. Because of measurement error, the measurements are random variables. Let X denote the length measurement and let Y denote the width measurement. Assume that the probability density function of X is \( f(x)= \begin{cases} 10\quad &\ 9.95<x<10.05\\ 0 \quad & \, otherwise \ \end{cases}\) and that the probability density function of Y is
\( g(y)= \begin{cases} 5\quad &\ 4.9<x<5.1 \\ 0 \quad & \, otherwise \ \end{cases}\).
Assume that the measurements X and Y are independent.
a. Find P(X<9.98).
b. Find
c find μₓ
I am feeling generous again so who ever say's "hey" with any emoiji i will give you brainliest, oh and 17 points
Answer:
Hey :)
Step-by-step explanation:
I dont know how to do emoji on laptop
Determine whether the graphs of the given equations are parallel, perpendicular, or neither.
3x + y = 4
y=-1/3x-2
Answer:
neither
Step-by-step explanation:
look at the image
given 2 vectors a=3i+4j-4k and b=-2i-6j+2k, the value of |a+b| (magnitude of their sum) is Sqrt (7) Sqrt (10) Sqrt (8) Sqrt (9) Sqrt (11)
Thus, the magnitude of value of |a+b| is Sqrt (9), which simplifies to just 3.
To find the magnitude of the sum of two vectors, we need to add the two vectors together and then take the square root of the sum of their squares.
So, let's first add the two vectors together:
a+b = (3i+4j-4k) + (-2i-6j+2k)
= i - 2j - 2k
Now, we can find the magnitude of this vector by squaring each of its components, summing them, and then taking the square root:
|a+b| = sqrt((1^2) + (-2^2) + (-2^2))
= sqrt(1 + 4 + 4)
= sqrt(9)
= 3
Therefore, the value of |a+b| is Sqrt (9), which simplifies to just 3.
In summary, the magnitude of the sum of two vectors can be found by adding the vectors together, squaring each of their components, summing them, and then taking the square root.
For the given vectors a=3i+4j-4k and b=-2i-6j+2k, their sum is i - 2j - 2k, and the magnitude of this vector is 3.
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Perform the indicated operation. (-3 + 5i) - (7 + 9i) -10 + 4i 4 - 4i -10 - 4i
Answer:
-26-8i does this help?
Step-by-step explanation:
I took what was in the parenthesis and put them together coming out with -10 and -4i. Then I took what was next and started putting the variables together and the numbers together.
The bag has 2 yellow cubes, 5 green cubes,and 3 red cubes? what is the probability of selecting a yellow cube at random
The bag has 2 yellow cubes, 5 green cubes,and 3 red cubes. The probability of selecting a yellow cube at random is 0.2 or 20%.
The probability of an event is determined by dividing the number of favorable outcomes by the total number of possible outcomes. There are a total of 2 + 5 + 3 = 10 cubes in the bag. The probability of selecting a yellow cube at random can be calculated as:
number of yellow cubes / total number of cubes
So the probability of selecting a yellow cube at random is:
2 / 10 = 1/5 or 0.2
Therefore, the probability of selecting a yellow cube is 0.2 or 20%.
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What is the Product of 2.18 and 3.4??
Show your work
and no links
Find the measure of the missing angles.
Answer:
153* for both
Step-by-step explanation:
This makes a circle, which is 360*. One angle is given, and it is 27*. If the angle on the opposite side is the same, the total degrees so far would be 54.
Say b and c were equal. Then, the remaining 306* would be split even among them. 306/2 is 153.
Therefore, 153* is the correct answer.
Hope I helped!!!
How is field data aggregated? Number of failed parts Number of failures Hours of operation Maintenance time Mark for follow up Question 3 of \( 7 . \) Data collection extends over a large number of it
Field data aggregation is the process of summarizing, combining, and analyzing data that has been collected from various sources. The following are some of the common ways that field data is aggregated: Count of Failures: A count of how many times a failure has occurred within a given period of time,
such as a day or a week. Number of Failed Parts: The number of parts that have failed over a given period of time, such as a day or a week. Hours of Operation: The amount of time that a machine or system was operational during a given period of time, such as a day or a week. Maintenance Time: The amount of time that was spent maintaining a machine or system during a given period of time, such as a day or a week.
Mark for Follow-Up: An indication of which issues need to be addressed or followed up on to prevent future failures or improve performance. Field data aggregation is the process of summarizing, combining, and analyzing data that has been collected from various sources. The following are some of the common ways that field data is aggregated: Count of Failures: A count of how many times a failure has occurred within a given period of time,
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Write the equation of the line (in slope-intercept form) that has an x-intercept at -6 and a y-intercept at 2. Provide a rough sketch of the line indicating the given points. [1 mark]. Exercise 2. For the polynomial f(x) = −3x² + 6x, determine the following: (A) State the degree and leading coefficient and use it to determine the graph's end behavior. [2 marks]. (B) State the zeros. [2 marks]. (C) State the x- and y-intercepts as points [3 marks]. (C) Determine algebraically whether the polynomial is even, odd, or neither.
To determine if the polynomial is even, odd, or neither, we substitute -x for x in the polynomial and simplify. -3(-x)² + 6(-x) = -3x² - 6x. Since the polynomial is not equal to its negation, it is neither even nor odd.
To write the equation of the line with an x-intercept at -6 and a y-intercept at 2, we can use the slope-intercept form of a line, y = mx + b, where m is the slope and b is the y-intercept.
In this case, the y-intercept is given as 2, so the equation becomes y = mx + 2. To find the slope, we can use the formula (y2 - y1) / (x2 - x1) with the given points (-6, 0) and (0, 2). We find that the slope is 1/3. Thus, the equation of the line is y = (1/3)x + 2.
For the polynomial f(x) = -3x² + 6x, the degree is 2 and the leading coefficient is -3. The end behavior of the graph is determined by the degree and leading coefficient. Since the leading coefficient is negative, the graph will be "downward" or "concave down" as x approaches positive or negative infinity.
To find the zeros, we set the polynomial equal to zero and solve for x. -3x² + 6x = 0. Factoring out x, we get x(-3x + 6) = 0. This gives us two solutions: x = 0 and x = 2.
The x-intercept is the point where the graph intersects the x-axis, and since it occurs when y = 0, we substitute y = 0 into the polynomial and solve for x. -3x² + 6x = 0. Factoring out x, we get x(-3x + 6) = 0. This gives us two x-intercepts: (0, 0) and (2, 0).
To determine if the polynomial is even, odd, or neither, we substitute -x for x in the polynomial and simplify. -3(-x)² + 6(-x) = -3x² - 6x. Since the polynomial is not equal to its negation, it is neither even nor odd.
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pleaseeeeee helpppppppp
Which of the following does not have a difference of 4?
9 - 5
-5 - (-9)
-4 - (-8)
-8 - (-4)
Answer:
-8 - (-4)
Step-by-step explanation:
9 - 5 = 4
-5 - (-9) = 4
-4 - (-8) = 4
-8 - (-4) = -4
In the triangle below y=? Round to the nearest tenth
Answer:
y = 51.3°Step-by-step explanation:
To find y we use tan
tan∅ = opposite/ adjacent
From the question
8 is the adjacent
10 is the opposite
Substitute the values into the above formula
That's
\( \tan(y) = \frac{10}{8} \)
\(y = \tan^{ - 1} ( \frac{10}{8} ) \)
y = 51.34019
We have the final answer as
y = 51.3 to the nearest tenthHope this helps you
4-day-old infants are approximately normally distributed with a population standard deviation of 3.5 mg/dl. Find the 96% confidence interval of the true population mean following the steps: a. State the Critical Values: b. State the Margin of Error: c. Confidence Interval: d. Conclusion:
We can conclude that we are 96% confident that the true population mean falls within the calculated confidence interval.
To find the 96% confidence interval for the true population mean of 4-day-old infants, we can follow these steps:
Step a: State the Critical Values:
Since the sample size is large and the population standard deviation is known, we can use the Z-distribution. For a 96% confidence level, we need to find the critical Z-values. The critical Z-value for a two-tailed test with a 96% confidence level is found by subtracting (1 - 0.96)/2 from 1 and looking up the corresponding value in the standard normal distribution table. The critical Z-value for a 96% confidence level is approximately 1.96.
Step b: State the Margin of Error:
The margin of error is calculated by multiplying the critical Z-value by the standard deviation divided by the square root of the sample size.
Margin of Error = Z * (Standard Deviation / √(Sample Size))
Step c: Confidence Interval:
The confidence interval is calculated by subtracting and adding the margin of error to the sample mean.
Confidence Interval = (Sample Mean - Margin of Error, Sample Mean + Margin of Error)
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Much of Ann’s investments are in Cilla Shipping. Ten years ago, Ann bought seven bonds issued by Cilla Shipping, each with a par value of $500. The bonds had a market rate of 95. 626. Ann also bought 125 shares of Cilla Shipping stock, which at the time sold for $28. 00 per share. Today, Cilla Shipping bonds have a market rate of 106. 384, and Cilla Shipping stock sells for $30. 65 per share. Which of Ann’s investments has increased in value more, and by how much? a. The value of Ann’s bonds has increased by $45. 28 more than the value of her stocks. B. The value of Ann’s bonds has increased by $22. 64 more than the value of her stocks. C. The value of Ann’s stocks has increased by $107. 81 more than the value of her bonds. D. The value of Ann’s stocks has increased by $8. 51 more than the value of her bonds.
The value of Ann’s bonds has increased by $45.28 more than the value of her stocks.
To determine which of Ann's investments has increased in value more, we need to calculate the change in value for both her bonds and stocks and compare the results.
Let's start by calculating the change in value for Ann's bonds:
Original market rate: 95.626
Current market rate: 106.384
Change in value per bond = (Current market rate - Original market rate) * Par value
Change in value per bond = (106.384 - 95.626) * $500
Change in value per bond = $10.758 * $500
Change in value per bond = $5,379
Since Ann bought seven bonds, the total change in value for her bonds is 7 * $5,379 = $37,653.
Next, let's calculate the change in value for Ann's stocks:
Original stock price: $28.00 per share
Current stock price: $30.65 per share
Change in value per share = Current stock price - Original stock price
Change in value per share = $30.65 - $28.00
Change in value per share = $2.65
Since Ann bought 125 shares, the total change in value for her stocks is 125 * $2.65 = $331.25.
Now, we can compare the changes in value for Ann's bonds and stocks:
Change in value for bonds: $37,653
Change in value for stocks: $331.25
To determine which investment has increased in value more, we subtract the change in value of the stocks from the change in value of the bonds:
$37,653 - $331.25 = $37,321.75
Therefore, the value of Ann's bonds has increased by $37,321.75 more than the value of her stocks.
Based on the given answer choices, the closest option is:
A. The value of Ann’s bonds has increased by $45.28 more than the value of her stocks.
However, the actual difference is $37,321.75, not $45.28.
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A triangle has sides measuring 8 inches, 5 inches and 4 inches. How would you classify it?
Answer:
Acute triangle because the angles are smaller than a right triangle
Step-by-step explanation:
As 5² + 4² < 8² it falls into the category of a² + b² < c², therefore it is an acute angle triangle.
What is the way of classifying a triangle?If a² + b² < c² then it is an acute angle triangle.
If a² + b² = c² then it is a right-angle triangle.
If a² + b² ≥ c² then it is an obtuse angle triangle.
Given, A triangle has sides measuring 8 inches, 5 inches and 4 inches.
So, 5² + 4² ? 8².
25 + 16 ? 64.
41 ? 64.
So, 41 < 64 therefore it is a² + b² < c² then it is an acute angle triangle.
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