the profit p(x) of a clothing company in thousands of dollars, is given by the function p(x) = -5x²+400x-2550 where x is the amount spent on advertising, in thousands of dollars. a) determine the maximum profit of the company can make.
b) determine the amount spent of advertisement that will result in the maximum profit. explain your response.
c) what amount must be spent on advertising to obtain a profit of at least $54 000 000?

Answer:

see the attachment!

i hope this can help you.

Answer:

No, The line x = 3 is not parallel to the line y = 1/3

Step-by-step explanation:

Here's What the graph looks like on Demos graphing calculator.

High Hopes^^

Barry-

Answer:

sorry dont know the answer im new to this website

Step-by-step explanation:

Answer:

1.x=11

2.x=+5=+2.2362

3.x=+3.750=+1.93649

Answer:

I don't get the question well. I think you have to put it clear.

Both np and n(1-p) are greater than or equal to 10, so a normal model is a good fit for the sampling distribution of sample proportions. So, the correct answer is 30.

A normal model is a good fit for the sampling distribution of sample proportions when the sample size is at least 10, and the condition n*p ≥ 10 and n*(1 - p) ≥ 10 are both satisfied.

The question states that college graduates are randomly sampled from public universities, and the proportion in the sample with student loans is determined. It then asks for which of the following sample sizes is a normal model a good fit for the sampling distribution of sample proportions.

The sample sizes are 10, 20, and 30.

Using the formula np and n(1-p) to determine whether a normal model is a good fit for each sample size:

n = 10np = (10)(0.62) = 6.2n(1-p) = (10)(0.38) = 3.8

Neither np nor n(1-p) is greater than or equal to 10, so a normal model is not a good fit for the sampling distribution of sample proportions.

n = 20np = (20)(0.62) = 12.4

n(1-p) = (20)(0.38) = 7.6

np is greater than or equal to 10, but n(1-p) is not, so a normal model is not a good fit for the sampling distribution of sample proportions.

n = 30np = (30)(0.62) = 18.6

n(1-p) = (30)(0.38) = 11.4

Both np and n(1-p) are greater than or equal to 10, so a normal model is a good fit for the sampling distribution of sample proportions.

Therefore, the correct answer is 30.

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Answer:

3 x 5

Step-by-step explanation:

The dimension of a matrix is normally represented in form of:

number of rows x number of columns

In the given matrix, there are 3 rows and 5 columns.

=> The dimension of this matrix is 3 x 5

=> Option D is correct

Hope this helps!

By using Chebyshev's Inequality with K=3, we can determine that at least 88.89% of the days had temperatures between "F and "F, where "F represents the mean temperature of 76.4°F.

Chebyshev's Inequality provides a lower bound on the proportion of data that falls within a certain number of standard deviations from the mean. In this case, K=3 means that we are considering a range of three standard deviations from the mean.

The inequality states that for any dataset, the proportion of data falling within K standard deviations of the mean is at least 1 - (1/K^2). So, for K=3, we have 1 - (1/3^2) = 1 - (1/9) = 8/9 ≈ 0.8889. Therefore, at least 88.89% of the data falls within three standard deviations of the mean.

In the context of the temperature data, we can conclude that at least 88.89% of the days had temperatures between the mean temperature of 76.4°F minus three standard deviations (76.4 - 3 * 7.3) and the mean temperature plus three standard deviations (76.4 + 3 * 7.3). This range represents a relatively high proportion of the dataset, indicating that the temperature observations are fairly concentrated around the mean with limited extreme values.

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Answer:

4

Step-by-step explanation:

Sub both sides by 3 then describe 20 by 5.

Answer:

1/2x is 0.5x. 3x^2 is 9x^2. 9x^2 - 0.5x is 7.5x^2 + 8, which is 15.5x^2.

Step-by-step explanation:

Answer:

I think the answer is 45 but im not sur

Answer:

Tad ran 6 miles while Elaine ran 4 miles.

Step-by-step explanation:

Since Tad runs one-half mile for every one-third mile that Elaine runs, to determine, if together they run a total of 10 miles, how far does Tad run, the following calculation must be performed:

0.5 x 2 = 1

0.333 x 2 = 0.666

10 / 1.666 = X

6 = X

6 x 1 = 6

6 x 0.666 = 4

Therefore, Tad ran 6 miles while Elaine ran 4 miles.

Answer:

pi/4

Step-by-step explanation:

Answer:

its 1/8

Step-by-step explanation:

he said 1/3 it does not match the other 2 numbers hope its right ;-; also helpfull

Answer:

Step-by-step explanation:

To find the area of the shaded region, we must minus the area of that part of the circle minus the triangle.

But to find the area of the triangle, we must find what is x and what is y.

Based on our angle knowledge, we know that \(cos (30) = \frac{x}{4}\\sin(30) = \frac{y}{4}\)

By solving these two functions we get that x=3.4641 and y =2.0000

Thus the area of the triangle is \(\frac{1}{2} *b*h\) = 0.5* (2*3.4641)*2 = 6.9282

The area of the shaded region = area of that part of the circle - area of triangle

\(\frac{120}{360} *\pi (4^{2})\) \(- 6.9282\) = 16.7552-6.9282 = 9.827 = 9.83

Answer:

Five greater than a number,the result is multiplied by 18

The verbal expression for 18(p + 5) is eighteen times the quantity obtained by adding five to a number p.

The verbal expression for the algebraic expression 18(p + 5) can be described as "Eighteen times the quantity obtained by adding five to a value represented by 'p'." This expression represents a mathematical operation where a given value 'p' is increased by five, and then the result is multiplied by eighteen. This type of expression is commonly encountered in various real-world situations where a value needs to be adjusted and then scaled up by a certain factor. In this case, the result reflects the outcome of multiplying the adjusted value by eighteen.

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Answer:

x-7>0

Straight answer: x-7

Step-by-step explanation:

Assuming that the timber is X cm long and 7cm was cut off, there remaining amount is x - 7cm. In order for 7cm to be cut off, the timber must have been > 7cm long => x > 7 => x - 7 > 0

Answer:

I think it is the last option I am not really sure but I think it is the last option

Step-by-step explanation:

Its the last one , cause it got the ÷ sign .

And we know that equivalent sets contain same elements or symbols even if the number are different .

The required condition for using an ANOVA (Analysis of Variance) procedure on data from several populations is that the sampled populations have equal variances.

In ANOVA, we compare the variation between the sample means to the variation within each sample. By assuming equal variances across populations, we can make valid statistical inferences about the differences in means.

While it is desirable for the populations to have equal means, it is not a strict requirement for conducting ANOVA. ANOVA can still be used even if the population means are not equal, as long as the assumption of equal variances holds.

Uniformity of the populations or dependence between samples are not specifically required conditions for using ANOVA. The focus is primarily on the assumption of equal variances, which allows for valid statistical comparisons of the means across multiple populations.

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The set of positive integers less than 1000 that are:

a)Divisible by 7 are 142

b)Divisible by 7 but not by 11 are 130

c)Divisible by both 7 and 11 are 12

d)Divisible by either 7 or 11 are 220

e)Divisible by exactly one of 7 and 11 are 220

f)Divisible by neither 7 nor 11 are 780

g)Having distinct digits are 576

f)Having distinct digits and even are 337

A whole number that is greater than zero is known as positive integer

a)The positive numbers below 1000 that are divisible by 7 are 7, 14, 21, 28,..., 994.

Total terms: 994, divided by 7, plus (n-1)

There are 142 total terms below 1000 that are divisible by 7.

b) The numbers 77, 154, 231, 308, 385, 462, 539, 616, 693, 770, 847, and 924 are all divisible by both 7 and 11.

The total number of integers below 1000 that are divisible by 7 but not 11 therefore equals 142 - (total number of integers divisible by 7 and 11), which means that the total number of integers that fall into this category is 130.

c) The total amount of integers that can be divided by both 7 and 11 equals the total amount of integers that can be divided by 77.

There are 12 total integers below 1000 that can be divided by 77.

d) The total number of integers that can be divided by either 7 or 11 is equal to the sum of the numbers that can be divided by each of those numbers and the number that can be divided by 77.

The total number of integers below 1000 that are divisible by 11 is (11,22,33,...,990). 990 = 11 + (n-1) 11, which equals 90 integers.

Total integers that may be divided by both 7 and 11 are equal to 142 + 90 - 12 = 220.

e) The total number of integers that may be divided by either 7 or 11 perfectly is equal to 142 + 90 - 12 = 220 numbers.

f) The total number of integers that cannot be divided by either 7 or 11 is 1000 - (The total number of integers that can be divided by either 7 or 11), which is 1000 - 220 = 780 numbers.

Distinct digits from 1 to 100 = 100 - Total number of integers below 1000 with distinct digits = 1000 - (non-distinct digits) ( 11,22,33,44,55,66,77,88,99,100),

=> Unique digits from 1 to 100 equal 90.

=> The distinct numerals 101 to 200 equal 100. (101,110,111,112,113,114,115,116,117,118,119,121,122,131,133,141,144,151,155,161,166,171,177,181,188,191,199,200),

=> Unique digits from 101 to 200 are: 100 to 28, 72.

=> Unique numbers between 201 and 1000 = 72 x 8 = 576.

h)Different digits and even values equal to 337

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Consider the function f(n) = 4n + 1. To prove or disprove that f(n) is one-to-one, we need to show that for any two different inputs, the function will give two different outputs. In other words, if f(n1) = f(n2), then n1 = n2.

Let's assume that f(n1) = f(n2), then:

4n1 + 1 = 4n2 + 1

Subtracting 1 from both sides gives:

4n1 = 4n2

Dividing by 4 gives:

n1 = n2

This shows that if f(n1) = f(n2), then n1 = n2. Therefore, the function f(n) is one-to-one.

To prove or disprove that f(n) is onto, we need to show that for any output, there is an input that will give that output. In other words, if y is any element in the range of f(n), then there exists an n such that f(n) = y.

Let y be any element in the range of f(n), then:

y = 4n + 1

Subtracting 1 from both sides gives:

y - 1 = 4n

Dividing by 4 gives:

n = (y - 1)/4

Since y is any element in the range of f(n), and n is an element in the domain of f(n), this shows that for any output, there is an input that will give that output. Therefore, the function f(n) is onto.

In conclusion, the function f(n) = 4n + 1 is both one-to-one and onto.

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Answer:

Step-by-step explanation:

20km east - 12km south= 8km east

Answer:

its 120.96

Step-by-step explanation:

i dont have any but i know that is the answer

A measure of goodness of fit for the estimated regression equation is the residual standard error (RSE)

It is a measure of goodness of fit for the estimated regression equation. It measures the average amount that the response variable (y) deviates from the estimated regression line, in the units of the response variable.

The RSE is calculated as the square root of the sum of squared residuals divided by the degrees of freedom. A smaller RSE indicates a better fit of the regression line to the data.

It represents the proportion of the variation in the dependent variable that is explained by the independent variable(s) in the model. The value of R-squared ranges from 0 to 1, with higher values indicating a better fit of the model to the data.

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SOLUTION:

Case: Percentage

Given: Frequency table

Required: To find the percentage of the students in grades 9–10 like rap music

Method:

Step 1: First we find the total number of people in grades 9–10.

We see clearly from the tables that 125 students are in grades 9–10.

Step 2: Next we find the number of people in grades 9–10 who like rap music.

There are 40 students in grades 9–10 who like rap music.

Step 3: We express as this as a percentage of the whole

This is 32% of the students in grades 9-10.

Final answer:

32% of students of the students in grades 9–10 like rap music

Answer:

1. Sides of ∠4 are DC and DG

2. Vertex of ∠2 = Point D

3. Another name for ∠3 = ∠EDG

4. ∠5 is an acute angle

5. ∠CDE is a straight angle

6. m ∠CDF = m∠5 + m∠1 = 42 + 117 = 159°

7. m ∠FDE = 17°

Step-by-step explanation:

For # 7 note that since DG is perpendicular to DF, m ∠GDF = 90°

m ∠GDF = m ∠3 + m ∠FDE
Since m ∠3 = 73°, m∠FDE = 90 - 73 = 17°

The interval for mean sale price is $582

According to statement

The given rates are 560, 468, 685, 534, 658, 593

Now,

Sample mean = X / n

Put the values in it and then

(560+ 468+ 685+ 534+ 658+ 593) / 6 = 582.1667

and use this formula S = sqrt [ X2 - n 2 / (n-1) ]

and put the values in these and

S = sqrt [ X2 - n 2 / (n-1) ] = 95.97179

So, The interval for mean sale price is $582

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Answer:

It is the second one , I'm pretty sure

Answer:

Factored form: \(2(x+4)(x-1)\)

vertex form: \(2(x+1.5)^{2} -12.5\)

Step-by-step explanation:

Factored form:

\(2(x+4)(x-1)=2(x^{2} +4x-x-8)=2(x^{2} +3x-4)=2x^{2} +6x-8\)

Vertex form:

\(2(x+1.5)^{2} -12.5=2(x^{2} +3x+2.25)-12.5\)

                            \(=2x^{2} +6x+4.5-12.5=2x^{2} +6x-8\)

Hope this helps

The value of determinant of the matrix det (AB) is 15.

Given matrices A and B are 3 by 3 matrices with

det (A) = 3 and

det (b) = 5.

We need to find the value of det (AB).

Writing the given matrices into the augmented matrix form gives [A | I] and [B | I] respectively.

By multiplying A and B, we get AB. Similarly, by multiplying I and I, we get I. We can then write AB into an augmented matrix form as [AB | I].

Therefore, we can solve the augmented matrix [AB | I] by row reducing [A | I] and [B | I] simultaneously using elementary row operations as shown below.


The determinant of AB can be calculated as det(AB) = det(A) × det(B)

= 3 × 5

= 15.

Conclusion: The value of det (AB) is 15.

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We need to find the value of determinant det(AB), using the formula: det(AB) = det(A)det(B)

=> det(AB) = 3 × 5

=> det(AB) = 15.

Hence, the value of det(AB) is 15.

The given matrices are A and B. Here, we need to determine the value of det(AB). To calculate the determinant of the product of two matrices, we can follow this rule:

det(AB) = det(A)det(B).

Given that: det(A) = 3

det(B) = 5

Now, let C = AB be the matrix product. Then,

det(C) = det(AB).

To evaluate det(C), we have to compute C first. We can use the following method to solve the augmented matrix by elementary row operations.

Given matrices A and B are: Matrix A and B:

[A|B] = [3 0 0|1 0 1] [0 3 0|0 1 1] [0 0 3|1 1 0][A|B]

= [3 0 0|1 0 1] [0 3 0|0 1 1] [0 0 3|1 1 0].

We can see that the coefficient matrix is an identity matrix. So, we can directly evaluate the determinant of A to be 3.

det(A) = 3.

Therefore, det(AB) = det(A)det(B)

= 3 × 5

= 15.

Conclusion: Therefore, the value of det(AB) is 15.

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The correct answer is B. The graph of h is the graph of g vertically shifted up 1 unit.

The correct answer is:

B. The graph of h is the graph of g vertically shifted up 1 unit.

Explanation:

The original function g(x) = x² represents a basic quadratic function, which is a parabola that opens upward and has its vertex at the origin (0, 0).

When we consider the function h(x) = g(x) + 1, we are adding a constant value of 1 to the output (y) values of the function g(x). This results in a vertical shift of the graph of g(x) by 1 unit upward.

In other words, for every x-value, the corresponding y-value of the function h(x) will be 1 unit higher than the corresponding y-value of the function g(x).

Visually, this means that the graph of h(x) will be the same shape as the graph of g(x), but it will be shifted upward by 1 unit. The vertex of the parabola, which was originally at the origin, will now be at (0, 1).

The statement "The graph of h is the graph of g horizontally shifted left 1 unit" (Option A) is incorrect because there is no horizontal shift in this transformation.

The statement "The graph of h is the graph of g vertically shifted down 1 unit" (Option B) is incorrect because the transformation results in a vertical shift upward, not downward.

The statement "The graph of h is the graph of g horizontally shifted right 1 unit" (Option D) is incorrect because there is no horizontal shift in this transformation.

Therefore, the correct answer is B. The graph of h is the graph of g vertically shifted up 1 unit.

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The question is given below as

Now, we will have to replace the blank spaces with letters a and b

Cross multiply both sides, we will have

By comparing coefficients, we will have

By comparing the second coefficient, we will have

Hence,

The complete equation will be

Answer:

32

Step-by-step explanation:

4(4^(2)-8)+(25-5^(2))

4(8)+(25-25)

32+0

=32

PEMDAS.