the power needed to accelerate a projectile from rest to its launch speed v in a time t is 61.0 w. how much power is needed to accelerate the same projectile from rest to a launch speed of 2v in a time of 1 2 t?

Answer:

40° 70° 8

Explanation:

Hello!

For an object sliding down an inclined plane, there are two forces working on the object: The normal force and the force due to gravity.

Breaking the force due to gravity into its components, we get a force of:

Mgsinθ, parallel to the incline's slope. This is the NET force acting on the object, causing it to accelerate.

Since ∑F = m · a:

Mgsinθ = m · a

Divide by the mass:

a = gsinθ

Yes it is important that the temperature of the surface important to apply a clear coat for G60 Galvanized tubing.

The end of a steel sheet (either hot- or cold-rolled) is sheared and welded to the preceding coil to form one continuous coil.A high-performance tension leveler is used to straighten the strip, resulting in excellent flatness.

The strip is dipped in an alkali bath and brushed for preliminary degreasing, and then undergoes alkaline electrolytic degreasing. This removes impurities on the material surface that could harm the zinc coating. The strip is then dipped in a acidic bath to activate the surface.

The zinc-coated strip is given various chemical treatments according to intended use, including phosphate treatment for excellent paintability, and chromate free special treatment for good corrosion resistance.

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Efficiency of a system can never be greater than 100% as it is a ratio of the output work to the input work. In a situation where the efficiency is greater than 100%, this suggests that the output work is greater than the input work, which is impossible.

Calculation of the work done on the bucket of water The work done by the hand crank, W = Fd, where F is the force used to lift the bucket, and d is the distance over which the force is applied. The work done on the bucket is given by the equation W = mgΔh, where m is the mass of the bucket and water, g is the acceleration due to gravity, and Δh is the height the bucket is lifted. To determine the efficiency of the system, we must first calculate the work done on the bucket and then calculate the work done by the hand crank. To do so, we use the following equations:

The calculated efficiency is 196.61%, which is greater than 100%. However, this result is incorrect because it violates the first law of thermodynamics, which states that energy cannot be created or destroyed. As a result, the calculated value of efficiency is impossible. The error in the calculation is most likely due to the incorrect measurement of one of the parameters used in the calculation.

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Using 3rd equation of kinematics

\(\\ \rm\longmapsto v^2-u^2=2as\)

\(\\ \rm\longmapsto s=\dfrac{v^2-u^2}{2a}\)

\(\\ \rm\longmapsto s=\dfrac{30^2-15^2}{2(5)}\)

\(\\ \rm\longmapsto s=\dfrac{900-225}{10}\)

\(\\ \rm\longmapsto s=\dfrac{675}{10}\)

\(\\ \rm\longmapsto s=67.5m\)

"There is no transmission, the probability of reflection is 100% or 1.0. The closest option provided is "e. 96%," which corresponds to 100%."

To calculate the probability of tunneling through a barrier, we can use the transmission coefficient (T). The transmission coefficient represents the probability that the electron will pass through the barrier. The reflection coefficient (R) represents the probability of reflection.

The formula for the transmission coefficient is given by:

T = (4E(V-U))/(4E(V-U) + U²)

Where:

E = kinetic energy of the electron

V = height of the barrier

U = potential energy inside the barrier

Let's substitute the given values into the formula:

E = 5.0 eV

V = 10.0 eV

U = 10.0 eV (assuming the potential energy inside the barrier is the same as its height)

T = (45.0(10.0-10.0))/(45.0(10.0-10.0) + 10.0²)

= 0

The transmission coefficient (T) is 0, which means there is no probability of tunneling through the barrier. Therefore, the probability of transmission is 0%.

Since there is no transmission, the probability of reflection is 100% or 1.0. The closest option provided is "e. 96%," which corresponds to 100%.

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The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.

To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.

Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.

Using the formula, we can calculate the distance traveled as follows:

d = rt

d = 130 mph × 2.5 hours

Multiplying the rate (130 mph) by the time (2.5 hours) gives us:

d = 325 miles

Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.

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A lion with a mass of 190 kg is chasing a gazelle with a mass of 15 kg. The distance between the lion and the gazelle is 2 meters. Both will exert an equal and opposite force on each other  of value  4752.4 * \(10^{-11}\) N

Gravitational Force =  G m1 * m2 / \(r^{2}\)

                                = 6.67 * \(10^{-11}\) * 190 * 15 / 4

                                = 4752.4 * \(10^{-11}\) N

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For a series circuit, as lights are added, the current across each bulb decreases.  

The internal resistance of ammeter is zero and voltmeter is infinite and, ammeter is connected in series and the voltmeter is in parallel.

To find the answer, we have to study about the internal resistance.

Thus, we can conclude that, the internal resistance of ammeter is zero and voltmeter is infinite and, ammeter is connected in series and the voltmeter is in parallel.

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Answer:

R = V^2 sin 2 θ / g        range formula

R is a maximum for θ = 45 and R = V^2  g

g = V^2 / R = 3^2 / 15 = .6 m/s^2

Answer: A B C D

Explanation:

The forms of energy that increase as a rocket blasts off are the chemical potential and kinetic energy that are in Option D, as during the launch of a rocket, the chemical potential energy stored in the rocket's fuel is converted into kinetic energy.

When a rocket launches, it uses its engines to burn fuel and produce exhaust gases, and this process releases the chemical potential energy stored in the fuel, which is converted into kinetic energy, as the rocket gains speed and altitude, its kinetic energy increases, but the potential energy of the rocket remains relatively constant during the launch. So during a rocket launch, the chemical potential energy stored in the fuel is converted into kinetic energy as the rocket's engines expel exhaust gases.

Hence, the forms of energy that increase as a rocket blasts off are the chemical potential and kinetic energy that are in Option D.

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Answer:

a

Explanation:

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Answer:

O'B. Good conductor of heat.

Explanation:

Plastic is not a good conductor of heat because it has no delocalized electrons it's surface to transfer heart.

Answer:

I hope this helps

Explanation:

The wavelength of light required for the transition from n=1 to n=2 is approximately 8.23 × 10⁶ meters, and for the transition from n=2 to n=3, it is approximately 1.51 × 10⁶ meters.

To calculate the wavelength, we use the Rydberg formula, which considers the initial (n₁) and final (n₂) energy levels. Plugging in the values into the formula, we can determine the wavelength. For the n=1 to n=2 transition, the wavelength is determined to be approximately 8.23 × 10⁶ meters. Similarly, for the n=2 to n=3 transition, the wavelength is calculated to be around 1.51 × 10⁶ meters.

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To determine the reject rate (RR) for each scenario, we need to consider the capability indices Cp and Cpk along with the specifications for tensile strength. The reject rate represents the proportion of parts that do not meet the specifications.

1. RR = 0.27%

2. RR = 16.03%

3. RR = 0%

4. RR = 0.003%

5. RR = 0.27%

6. RR = 2.28%

7. RR = 29.93%

8. RR = 0%

9. RR = 5.87%

Please note that these calculations assume a normal distribution of tensile strength and that the process is in statistical control. The reject rate is obtained by evaluating the proportion of values falling outside the specified limits based on the process capability indices Cp and Cpk.

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The energy that the shock absorbers must dissipate is 0.5 * m * 0.7225 Joules,

where m is the mass of the bouncing object.

To calculate the energy that the shock absorbers must dissipate, we will use the formula for kinetic energy:
Kinetic energy (KE) = 0.5 * mass (m) * \(velocity^2 (v^2)\)
However, the mass is not given in the problem. Since the question asks for the energy to be dissipated, we can assume that the entire initial kinetic energy needs to be dissipated by the shock absorbers.
Initial velocity (v) = 0.85 m/s.

Now, let's plug in the values into the formula:
\(KE = 0.5 * m * (0.85 m/s)^2\)
Since the mass is constant, we can write the answer in terms of mass:
KE = 0.5 * m * 0.7225 J/kg.

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Answer:

To answer your question:

a) The formula to calculate the number of wavelengths within a laser pulse is:

number of wavelengths = pulse duration / wavelength

Plugging in the values given in the question, we get:

number of wavelengths = 38 ps / 1062 nm

Converting picoseconds to seconds and nanometers to meters, we get:

number of wavelengths = 38 x 10^-12 s / 1062 x 10^-9 m

number of wavelengths = 0.0358

Therefore, there are approximately 0.0358 wavelengths within the laser pulse.

b) To fit only one wavelength, the pulse duration would need to be equal to the wavelength. The formula to calculate the pulse duration is:

pulse duration = wavelength

Plugging in the value given in the question, we get:

pulse duration = 1062 nm

Converting nanometers to picoseconds using the speed of light ©, we get:

pulse duration = wavelength / c

pulse duration = 1062 x 10^-9 m / 3 x 10^8 m/s

pulse duration = 3.54 x 10^-12 s

Therefore, the pulse would need to be approximately 3.54 ps long to fit only one wavelength.

I hope this helps

Based on the data furnished, we can determine that the space-dock employees could have elderly much less compared to the ship's captain when the rocket returns to the space dock.

This conclusion is based on the concept of special relativity, which states that point dilation takes place as an object approaches the rate of mild. In this scenario, the rocket ship Adventure is transferring at a velocity of 0.5 c (half of the speed of light) relative to the distance dock.

When an item moves at excessive speeds relative to an observer, time seems to skip more slowly for that item compared to a stationary observer. This approach is that as the Adventure travels at 0.5 c, time onboard the rocket ship will skip extra slowly relative to the time experienced by the gap-dock employees. The size discrepancy inside the length of the rocket deliver similarly helps this.

According to the ship's captain, the Adventure is 50 m lengthy, while the space-dock employee's degree it to be 43. Three m long whilst it's miles moving at 0.5 c. This phenomenon is called duration contraction, where objects in motion appear shorter within the direction of their movement while determined from a desk-bound body of reference.

Since time dilation happens and period contraction is determined for the rocket ship Adventure because it acts at relativistic speeds, the delivery's captain reports time passing more slowly in comparison to the distance-dock employees. As an end result, when the rocket ship returns to the distance dock, the distance-dock personnel might have elderly in comparison to the delivery's captain.

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The linear acceleration of the car wheel is 0.735 m/s².

The linear acceleration of a point on the rim of a wheel is related to the angular acceleration of the wheel by the equation:

a = rα

Where "a" is the linear acceleration, "r" is the radius of the wheel, and "α" is the angular acceleration.

Given the data in the question;

Plug the given values into the above formula and solve for the linear acceleration of wheel.

a = r × α

a = 0.3 m × 2.45

a = 0.735 m/s²

Therefore, the linear acceleration is 0.735 m/s².

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The 100-w lightbulb produces the same intensity of light as a 75-w lightbulb produces 10 m away at a distance of 4.0 m.

What is lightbulb?

A lightbulb, also known as a lamp or lightbulb, is an electrical device that produces light by the process of incandescence or by the emission of light from a glowing filament. It is one of the most common sources of artificial light used in residential, commercial, and industrial settings.

Traditional incandescent lightbulbs consist of a glass envelope or bulb containing a filament made of a tungsten wire. When an electric current passes through the filament, it heats up and becomes so hot that it emits visible light. The glass bulb is designed to protect the filament from oxidation and to contain the inert gas, usually argon or nitrogen, which helps preserve the life of the filament.

The intensity of light from a light bulb follows an inverse square law, which means that the intensity of light decreases with the square of the distance from the source. So, we can use the formula:

I1/I2 = (d2/d1)²

where I1 and I2 are the intensities of the light bulbs, d1 and d2 are the distances from the light bulbs, and we want to find the distance where I1 = I2.

Let's call the distance we want to find x. We can set up two equations:

I1 = 100 W / x²

I2 = 75 W / 10²

Setting I1 = I2 and solving for x:

100/x² = 75/10²

x² = (100*10²)/75

x = 4.0 m

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Answer:

C

Explanation:

Answer:

B

Explanation:

Because it’s asking about sexual

Answer:

striking and fielding

Explanation:

striking and fielding

Answer:

22. is A and 23. is C

Explanation:

Explanation:

chemical changes

>produce new substances w/ different chemical structure/ properties

> thermal energy can be used to BREAK bonds (endothermic)

>thermal energy can be transferred to a chem rxn to help form new products (endothermic)

> heat can be released by an exothermic chemical reaction (excess energy- the total energy used to break bonds is less than energy released in forming new bonds)

physical changes

>does not result in new substances (typically changes in state- solid, liquid, gas)

> thermal energy can be transferred to EVAPORATE water (add thermal E... water (liquid) to steam (gas)) or FREEZE water (remove thermal E... water (liquid) to ice (solid))

A thermometer is taken from a room where the temperature is 72° F to the outside where the temperature is 32° F. 1.26 minutes does the thermometer have to be outside for it to read 36° F.

If an item is heated to a greater temperature, T is transferred to a lower temperature environment, cooling rate ​is directly proportional to the temperature differential. By separating the variables, rewrite the equation. In the derived equation, substitute 0 for t and 72 for T.

If an item is heated to a greater temperature,

T is transferred to a lower temperature environment, T then the cooling rate.

By Newton's Law of Cooling

\(T(t) = T_{s} + Ce^{tr}\)

Here, the ambient temperature, \(T_{s} = 32^{\circ} F\)

The temperature to the outdoor, T(0) = 72°F

Use the equation \(T(t) = T_{s} + Ce^{tr}\) to obtain that,

\(T(0) = T_{s} + Ce^{k - 0}\)

72 = 32 + C

C = 40

So, \(T(t) = 32 + 40 e^{kt}\)

After half minute, the temperature reads 48°F,

so, T(1/2) = 48

Then,

\(T(1/2) = 32 + 40e^{k \times \frac{1}{2}}\)

\(48 = 32 + 40e^{\frac{k}{2}}\)

\(40e^{\frac{k}{2}} = 16\)

\(e^{\frac{k}{2}} = \frac{16}{40}\)

\(e^{\frac{k}{2} = \frac{2}{5}\)

\(\frac{k}{2} = \ln \left(\frac{2}{5} \right )\)

k = 2 ln (2/5)

Therefore,

\(T(t) = 32 + 40e^{2 \ln \left(\frac{2}{5} \right) t}\)

\(T (t) = 32 + 40 \left[ e^{\ln (\frac{2}{5} ) \right ]^{2t}\)

\(T (t) = 32 + 40 \left(\frac{2}{5} \right)^{2t}\)

Now find the time t when T(t) = 36

\(32 + 40 (\frac{2}{5})^{2t} = 36\)

\(40 (\frac{2}{5})^{2t} = 4\)

\((\frac{2}{5})^{2t} = \frac{4}{40}\)

\(2t\ \ln (\frac{2}{5}) = \ln (\frac{1}{10})\)

\(t = \frac{\ln (\frac{1}{10})}{2 \ln (\frac{2}{5})}\)

\(t = \frac{-2.30}{2 \times (-0.91)}\)

t = -2.30/-1.82

t = 1.26 min

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Answer:

Diffusion coefficient D = 2.6613 × 10⁻¹¹ m²/s

Explanation:

From the given information:

Carbon concentration \(C_c\) = 0.012

Iron concentration \(C_{Fe}\) = 100 - 0.012 = 99.988

Density of carbon = 2.25 g/cm³

Density of iron = 7.87 g/cm³

We can convert the carbon concentrations from weight percentage to kilograms carbon per meter cubed by using the formula.

\(C^*_c = \dfrac{C_c}{\dfrac{C_c}{\rho_c}+\dfrac{C_{Fe}}{\rho_{Fe}}}\times 10^3\)

\(C^*_c = \dfrac{0.012}{\dfrac{0.012}{2.25 \ g/cm^3}+\dfrac{99.988}{7.87 \ g/cm^3}}\times 10^3\)

\(C^*_c = \dfrac{0.012}{0.00533 \ g/cm^3 + 12.71 \ g/cm^3} \times 10^3\)

\(C^*_c = 0.9437 \ kgC/m^3\)

However; for 0.0069 wt% C

\(C^*_c = \dfrac{C_c}{\dfrac{C_c}{\rho_c}+\dfrac{C_{Fe}}{\rho_{Fe}}}\times 10^3\)

\(C^*_c = \dfrac{0.0069}{\dfrac{0.0069}{2.25 \ g/cm^3}+\dfrac{99.9931}{7.87 \ g/cm^3}}\times 10^3\)

\(C^*_c =0.5429 \ kgC/m^3\)

Thus; the diffusion coefficient can be computed by using the formula:

\(D = - J \begin {bmatrix} \dfrac{x_A-x_B}{C_A-C_B}\end {bmatrix}\)

\(D = - (3.6 \times 10^{-8} \ kg/m^2-s) \begin {bmatrix} \dfrac{-15^{-3} \ m }{0.9437 \ kgC/m^3 - 0.5429 \ kgC/m^3}\end {bmatrix}\)

D = 2.6613 × 10⁻¹¹ m²/s