The instantaneous velocity at 7s is 1.71 m/sec.
Equation :To know the velocity of the position difference,
Use the formula,
speed = distance / time
Given,
distance 1 = -4m
distance 2 = 8m
time = 7s
v = ?
Putting values,
v = Δs/Δt
v = d₂ - d₁ / t
v = 8 - (-4) / 7sec
v = 12m / 7sec
v = 1.71 m/sec
Velocity :The velocity of a body or object determines the direction of motion. Speed is a scalar quantity in its most fundamental form. Velocity is essentially a vector quantity. It is rate of change in distance. The displacement change rate is the issue.
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. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification
The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.
Given:
Object height (h) = 5 cm
Focal length of the convex lens (f) = 10 cm
Object distance (u) = 15 cm (positive since it's on the same side as the incident light)
To determine the nature, position, and size of the image, we can use the lens formula:
1/f = 1/v - 1/u
Substituting the given values:
1/10 = 1/v - 1/15
To simplify the equation, we find the common denominator:
3v - 2v = 2v/3
Simplifying further:
v = 30 cm
The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.
To find the magnification (M), we use the formula:
M = -v/u
Substituting the values:
M = -30 / 15 = -2
The magnification is -2, indicating that the image is inverted and twice the size of the object.
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A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?
The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and 6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.
4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.For more questions on speed
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A 24.4kg dog is running northward at 2.14m/s, while a 5.53kg cat is running eastward at 3.56m/s. Their 78.5kg owner has the same momentum as the two pets taken together. Find the direction of the owner's velocity. Find the magnitude of the owner's velocity.
The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.
To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.
Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).
According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.
The total momentum before the interaction is given by:
Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)
Mass of the dog (m1) = 24.4 kg
Velocity of the dog (v1) = 2.14 m/s
Mass of the cat (m2) = 5.53 kg
Velocity of the cat (v2) = 3.56 m/s
Mass of the owner (m3) = 78.5 kg
Velocity of the owner (v) = unknown
Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)
The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.
Total momentum after = 0
Equating the two expressions:
(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0
Simplifying the equation:
(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0
71.8648 kg·m/s + (78.5 kg * v) = 0
Solving for v:
78.5 kg * v = -71.8648 kg·m/s
v = -71.8648 kg·m/s / 78.5 kg
v ≈ -0.916 m/s
Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.
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What is the potential gravitational energy of a 2 kg ball thrown up in the air to a height of 7 m?
Answer:
PE = 137.2931 J
Explanation:
PE = 137.2931 J
A force of 600N is applied to an object that accelerates at a rate of 15m/s/s. What is the mass of the object?
Answer:
The answer will be it has a mass of 40 kg.
Explanation:
Because Force = mass x acceleration or F = m a, we can say Force divided by mass or F/a = m or mass so 600 divided by 15 equals 40 kg.
Consider a situation where two point charges of charge Q = 16 nC and mass m = 33 g are 27 cm apart. Then, one of these point charges are let go (NOTE: ignore gravity).
After that charge has moved 16 cm, what will be its speed?
Given that,
Charge = 16 nC
Mass = 33 g
Distance = 27 cm
We need to calculate the acceleration
Using formula of electrostatic force
\(F=\dfrac{kqQ}{r^2}\)
\(ma=\dfrac{kq^2}{r^2}\)
Put the value into the formula
\(33\times10^{-3}\times a=\dfrac{9\times10^{9}\times(16\times10^{-9})^2}{(27\times10^{-2})^2}\)
\(a=\dfrac{9\times10^{9}\times(16\times10^{-9})^2}{(27\times10^{-2})^2\times33\times10^{-3}}\)
\(a=0.0009577\ m/s^2\)
\(a=9.577\times10^{-4}\ m/s^2\)
We need to calculate the speed of charge
Using equation of motion
\(v^2=u^2+2as\)
Where, v= speed
u = initial speed
a = acceleration
s = distance
\(v^2=0+2\times9.577\times10^{-4}\times16\times10^{-2}\)
\(v=\sqrt{0+2\times9.577\times10^{-4}\times16\times10^{-2}}\)
\(v=0.0175\ m/s\)
Hence, The speed of the charge is 0.0175 m
Given that the wavelengths of visible light range from 400 nm to 700 nm, what is the highest frequency of visible light? (c = 3.0 x 10^8 m/s) 2.3 10^20 Hz 5.0 x 10^8 Hz 7.5 x 10^14 Hz 4.3 10^14 Hz 3.1 x 10^8 Hz
7.5 × 10¹⁴ Hz is the highest frequency of visible light when wavelengths of visible light range from 400 nm to 700 nm.
Frequency is defined as the quantity of oscillations of a wave per unit of time, expressed in hertz (Hz).
The relationship between pitch and frequency is inverse. Humans can hear sounds with a frequency between 20 and 20000 Hz.
A wavelength is the separation between the two sites that are in phase with one another. As a result, two close wave peaks or troughs are separated by a single full wavelength.
Usually, the letter lambda (λ) is used to indicate a wave's wavelength.
The wave speed is the distance a wave travels in one unit of time (v). Considering that a wave moves one wavelength in a unit of time, v=λ/T
T = 1/f enables us to express the equation above as V = f.
The fact that the wave speed is equal to the product of the frequency and wavelength of the wave implies that frequency and wavelength are related.
The frequency is greatest for the shortest wavelength because the relationship between frequency and wavelength is inverse.
Given
Minimum wavelength of visible light = 400 nm = 4 × 10⁻⁷ m
Speed of light = 3 × 10⁸ m/s
Frequency = c/λ = 3 × 10⁸ / 4 × 10⁻⁷
= 7.5 × 10¹⁴ Hz
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What is the amperage of a current flowing through a wire that has a resistance of 30 ohms if the voltage is 90 volts?
12 ohms
2700 amps
3 amps
4 volts
why is science important for our understanding of the natural world?
A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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Who is really really good at Science because i need help with 9th grade Science
i have to get 100% on this assignment
let me see the question first sir
an electric train moving at 5m/s accelerates to a speed of 8m/s in 20 seconds. Fine the distance travelled in meters during the period of acceleration
===================================================
Explanation:
vi = 5 and vf = 8 are the initial and final velocities respectively. The change in time is t = 20 seconds.
So,
x = 0.5*(vi + vf)*t
x = 0.5*(5+8)*20
x = 130 meters
represents the distance traveled. The first equation shown above is one of the four kinematics equations.
A car starts from rest and accelerates at a constant rate in a straight line. In the first second the car moves a distance of 2.0 meters. How much additional distance will the car move during the second second of its motion?
Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.
In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.
The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.
A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.
Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.
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. An electron has a de Broglie wavelength of 2.80 *
10-10 m. Determine (a) the magnitude of its momentum and (b) its
kinetic energy (in joules and in electron volts
The de- Broglie wavelength of 2.80× 10⁻¹⁰ m is associated with a momentum of 2.36 × 10⁻²⁴ Kg m/s. The kinetic energy will be 3.07 × 10⁻¹⁸ J which is equal to 19.015 ev.
What is de-Broglie wavelength?De-Broglie proposed the dual nature of matter which stated that matter can behave as both wave and particle. For a matter wave, the wavelength of the wave will be the ratio of the Planck's' constant h and its momentum p.
thus, λ = h/p
Given the wavelength = 2.80× 10⁻¹⁰ m.
momentum p = h/λ
= 6.62 × 10 ⁻³⁴ / (2.80× 10⁻¹⁰ m)
= 2.36 × 10⁻²⁴ Kg m/s
The kinetic energy ke = 1/2 mv² = p² /2m.
mass of an electron = 9.1 × 10 ⁻³⁴ Kg.
hence, Ke = (2.36 × 10⁻²⁴ Kg m/s )² / 9.1 × 10 ⁻³⁴ Kg
= 3.07 × 10⁻¹⁸ J.
1 J = 6.24 × 10¹⁸ ev.
thus, KE in ev = 3.07 × 10⁻¹⁸ J × 6.24 × 10¹⁸ ev = 19 ev.
Therefore, the kinetic energy of the electron is 19 ev.
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Two equal and opposite charges are placed 40mm apart,if the force between them is found to be 0.5N Calculate the magnitude of the charge
PLEASE HELP WILL MARK BRAINLIEST!!
A 4.0-kg mass is moving to the right at 3.0 m/s. An 8.0 kg mass is moving to the left at 2.0 m/s. If after collision the two
masses join together, what is their velocity after collision?
O-0.33 m/s
O-0.20 m/s
O +1.4 m/s
O +2.3 m/s
Answer:
- 0.33 m/s
Explanation:
An illustration is shown above,
In this case, since the two objects move in opposite directions before collision, then move together, the formula to be used is,
m1u1 - m2u2 = (m1 + m2)v
Where,
m1 = mass of the first object
u1 = initial velocity of the first object
v1 = final velocity of the first object
m2 = mass of the second object
u2 = initial velocity of the second object
v2 = final velocity of the second object
Therefore,
(4.0 • 3.0) - (8.0 • 2.0) = (4.0 + 8.0)v
12 - 16 = 12v
-4 = 12v
Divide both sides by 12,
-4 / 12 = 12v / 12
-1 / 3 = v
v = -0.33 m/s
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Name three ways temperature can vary:
Answer:
Degree, Location and Time?
Explanation:
Answer:
Age. One of the most elementary factors that influence normal body temperature is age
Time of The Day. ...
Exercise or Physical Exertion. ...
Stress. ...
Meals. ...
Drugs and Smoking.
Explanation:
An object is placed at a distance of 20cm from the optical centre of a convex lens of focal length 15cm .find the distance of the image from the lens what will be the height of the image if the object is 4cm tall
Answer:
Use the lens form:
1/f=1/v-1/u
1/30=1/v-(1/-20)
1/30=1/v+1/20
1/30-1/20=1/v
2-3/60=1/v
-1/60=1/v ;;;v = -60 cm
m = h of image/h of object = v/u
H/2 = -60/-20
H = 3*2
H = 6 cm
what conditions made it possible for earth's interior to separate into layer?
Answer:
Separation of the Earth into layers (crust, mantle, inner core, and outer core) was largely caused by gravitational differentiation (separating different constituents at temperature where materials are liquid or plastic, owing to differences in density) early in Earth's history.
Explanation:
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Which three terms are needed to describe the energy a BASE Jumper has as
she falls toward the ground?
A. Potential
B. Kinetic
C. Gravitational
D. Electromagnetic
Answer:
A.Potential
B.Kinetic
C.Gravitational
Explanation:
I took the test
You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
Answer:
C) The book's inertia carried it forward.
When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.
in coming to a stop, an old truck leaves skid marks 45 m long on the highway. assuming a deceleration of 6m/s2 , estimate the speed of the truck just before braking.
The speed of the truck just before braking is 23.24 m/s.
What is the speed of the clock before braking?
The speed of the truck before braking is calculated by applying the third kinematic equation as shown below.
v² = u² - 2as
where;
v is the final velocity of the truck when it stopsa is the acceleration of the trucks is the distance travelled by the truckWhen the truck stops, the final velocity = 0
0 = u² - 2as
u² = 2as
u = √2as
u = √ ( 2 x 6 x 45 )
u = 23.24 m/s
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A/An breaks down a complicated goal into daily action to make it more manageable?
A routine breaks down a complicated goal into daily action to make it more manageable.
What is a routine?A routine can be described as the sequence of actions regularly followed which do help individuals as well as the organization so they can acheive their goals.
It should be noted that a routine is neccessary in an organization because it will help help them to breakdown the task as well as the activities and this will help to achive the goals as well as the neccessary things on time because allcomplicated goals woud have been included as well as how it will be carried out.
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Work
Can be summarized as an equation.
W = Fd
W = work F = force d = distance
Measured in J Measured in N Measured in m
Example #1: You move a 75 kg refrigerator 35 m.
This requires a force of 90 N. How much work, in
joules, was done while moving the refrigerator?
Which chart correctly describes the properties of magnets and electromagnets?
Answer:
The second chart seems to be correct
Explanation:
write down the value of
920 kg in g
Answer:
920000
Explanation:
Each kg contains 1,000 grams
explain why the insulting layer of fleece is good at reducing the rate of energy transfr
The insulating layer of fleece is effective at reducing the rate of energy transfer due to its unique properties and structure. Fleece is made of synthetic fibers or natural fibers such as wool, which have excellent insulating properties.
One key factor is the structure of fleece. Fleece fabric consists of many small air pockets trapped within the fibers. Air is a poor conductor of heat, so these air pockets act as a barrier to prevent the transfer of thermal energy. The trapped air creates a layer of insulation that helps to slow down the transfer of heat between the body and the environment.
Furthermore, fleece has a high loft, meaning it is thick and fluffy. The loft creates additional air space and increases the insulation capacity. The thickness of the fleece allows for more air to be trapped, providing a thicker barrier for heat transfer. The fibers themselves also have natural crimps and curls, which further enhance the insulation by creating more air pockets.
Additionally, fleece is hydrophobic, meaning it repels moisture. Moisture has a higher thermal conductivity than air, so by repelling moisture, fleece maintains its insulating properties even in damp conditions. This is particularly advantageous in outdoor activities or during physical exertion when the body may produce sweat.
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A rocket sled accelerates from 10 m/s to 40 m/s in 2 seconds. What is the average acceleration of the sled?
Answer:
15m/s²
Explanation:
Given parameters:
Initial velocity = 10m/s
Final velocity = 40m/s
Time taken = 2s
Unknown:
Average acceleration = ?
Solution:
Acceleration is the rate of change of velocity with time;
Acceleration = \(\frac{Final velocity - Initial velocity }{time}\)
Acceleration = \(\frac{40 - 10}{2}\) = 15m/s²
Write a scientific explanation to describe where earthquakes and volcanoes most commonly occur and their relation to plate boundaries .
the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm
The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.
What is the image and object distance?The object and image distance formed by the lens is calculated by applying the following lens formula.
v + u = 40 ------- (1)
v/u = 3 ------------ (2)
v = 3u
Substitute v into equation (1);
3u + u = 40
4u = 40
u = 40/4
u = 10 cm
The image distance = 3u
= 3 x 10 cm
= 30 cm
Thus, the object distance is 10 cm and the image distance is 30 cm.
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