the point (a,-a) does not lie on the grap of a. y=x b x+y=0 c.x=a d.y=-a​

Answer:

The top choice.

Step-by-step explanation:

If a quadratic function is a perfect square trinomial, its graph will intersect the x-axis exactly once.

\(y=(x+1)^2\\\)

Expanded, this is \(y=(x+1)(x+1)\)

There is only one value of x which makes the "two" factors equal to zero, and that is -1, where the graph touches the x-axis.

See the attached graph. \(y=(x+1)^2\) is the purple graph.

The green graph is an example of a quadratics which is NOT a perfect square. It's the function \(y=x^2-x-2\).

According to the given information, the sample period should be from 2010-2020.

a) Model specification

The model specification based on the scenario above is as follows:

SDF= f(T, TI, NL)

Where: SDF= Sustainable Development Framework

T= Tourism

TI= Technological innovation

NL= National leadership

b) Justification for the selection of the dependent and independent variables model:

Dependent variable: The dependent variable in this model is Sustainable Development Framework (SDF). The model seeks to develop a framework for sustainable development that would facilitate growth, environmental and socio-cultural sustainability.

Independent variables:

The independent variables are tourism sustainability, technological innovation, and quality of leadership. These variables drive economic development. The inclusion of tourism sustainability reflects its importance in the global economy and its potential to drive growth.

The inclusion of technological innovation reflects its potential to enhance productivity and create new industries. The inclusion of national leadership reflects the role of governance in promoting sustainable development and managing negative externalities.

c) Justification for the selection of the sample period:

The sample period should be selected based on the availability of data for the variables of interest. Ideally, the period should be long enough to capture trends and patterns in the data. However, it should not be too long that the data becomes obsolete or no longer relevant.

Additionally, the period should also reflect the context and relevance of the research question. Therefore, the sample period for this study should cover the last decade to capture the trends and patterns in the data and reflect the relevance of the research question.

The sample period should be from 2010-2020.

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Answer:

I think it is B

Step-by-step explanation:

Because the real numbers are bigger

The correct option is Option B.

Venn diagrams are given which shows relationship between set R and W.

We have to find that which correct describes the relationship between set R and W.

What are whole numbers and real numbers ?

Whole numbers are made up of natural numbers like 1, 2, 3, and 4 also including 0. Whereas real numbers are made up of rational and irrational numbers.

As per the definition ,

Set of whole numbers will be , {W} = { 0,1,2,3,4, . . . . . . }

Set of real numbers will be ; {R} = {- ∞ , . . . . . . . . , + ∞ }

If we take intersection of set we get that ; real numbers include all whole numbers.

Thus , correct option is Option B.

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If a categorical variable that can take the values from the set {Red, Blue, Green, Yellow} is included as an independent variable in a linear regression, the number of dummy variables that are created is two

When a categorical variable that has n categories is to be included as an independent variable in a linear regression analysis, it must be converted to n - 1 dummy variables. The reason for this is that including all n categories as dummy variables would cause perfect multicollinearity in the regression analysis, making it impossible to estimate the effect of each variable.In this case, the set of categories {Red, Blue, Green, Yellow} has four categories. As a result, n - 1 = 3 dummy variables are required to represent this variable in a linear regression. This is true since each category is exclusive of the others, and we cannot assume that there is an inherent order to the categories.The dummy variable for the first category is included in the regression model by default, and the remaining n - 1 categories are represented by n - 1 dummy variables. As a result, the number of dummy variables that are required to represent the categorical variable in the regression model is n - 1.

Thus, if a categorical variable that can take the values from the set {Red, Blue, Green, Yellow} is included as an independent variable in a linear regression, the number of dummy variables that are created is two .

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Answer:

(a)  {(3,4),(3,5), (6,8), (6,9),(9,12), (9,13)}

(b) The inverse relation is not a function

Step-by-step explanation:

Inverse Function

If a relation is given as a set of points (x,y), the inverse relation will have the same points with its coordinates switched.

The relation is given as the set:

{(4,3),(5,3), (8,6), (9,6),(12,9), (13,9)}

(a) The inverse relation is:

{(3,4),(3,5), (6,8), (6,9),(9,12), (9,13)}

(b)

A relation is a function if each element of the input set is related to one and only one element of the output set.

The inverse relation is not a function because several points don't meet the above condition. For example, (3,4) and (3,5) relate the element 3 with two elements.

Answer:

Hey!

\(3\frac{7}{8}\) in decimal form is 3.875

Step-by-step explanation:

7/8 is 0.875

We just add this to 3 to make 3.875!

Answer:

see explanation for answers

Step-by-step explanation:

prism = 12*4 + 5*4 + 12*4 + 5*4 + 12*5 + 12*5 = 256 ft²

lateral surface area of pyramid = 4*1/2*5*5 = 50 ft²

area of square base of the pyramid = 5*5 = 25 ft²

total exposed surface area of the figure = 256 + 50 - 25 = 281 ft²

Answer:

There is a 9 out of 14 chance that the marble will be white or there is a 3 out of 5 chance along with a 6 out of 9 chance.

Step-by-step explanation:

Since there's a total of 14 marbles from both bags and there are a possible 9 white marbles, it would be a total of 9 out of 14, or it would be separate and be a 3 out of 5 chance with a 6 out of 9 chance.

Answer: 2 inches

Step-by-step explanation:

14 inches

Step-by-step explanation:

Length of the hole = 16(½) inches

Length of the dirt = 8(¾)inches

The distance between the top of the pile to the bottom of the hole = ?

Since the dirt is beside the hole and not inside the hole, we can find it's length using addition.

Distance from the top to the bottom = length of dirt + length of the hole

Length of dirt = 8×¾ = 6 inches

Length of the hole = 16 × ½ = 8 inches

Distance from the top of the dirt to the bottom of the hole = (6 + 8) inches

Distance from the top of the dirt to the bottom of the hole = 14 inches

Note: the only way we can use subtraction here is if the hole was filled with dirt, what's the distance that's left

Distance left = length of hole - length of dirt

Distance left = 8 - 6 = 2 inches .

Given,

\( \: \)

To Find,

\( \: \)

Solution :

First of all, we'll find the circumference of the circle :

\(\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{ \: \: Circumference_{(circle)} = 2 \pi r}}}}}} \: \: \bigstar \\ \\\)

Now, we'll substitute the required values in the formula :

\(\\ { \longrightarrow \qquad{ \sf{ \: \: Circumference_{(circle)} = 2 \times 3.14 \times 3.5}}} \: \: \\ \\\)

\( { \longrightarrow \qquad{ \sf{ \: \: Circumference_{(circle)} = 3.14 \times 7}}} \: \: \\ \\\)

\( { \longrightarrow \qquad{ \sf{ \pmb{ \: Circumference_{(circle)} = 21.98}}}} \: \: \\ \\\)

Therefore,

\( \: \)

Now, we'll find the area of the circle :

\(\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{ \: \: Area_{(circle)} = \pi r^2}}}}}} \: \: \bigstar \\ \\\)

\({ \longrightarrow \qquad{ {{ { \sf{ \: \: Area_{(circle)} = 3.14 \times { \times (3.5)}^{2} }}}}}} \: \: \\ \\\)

\({ \longrightarrow \qquad{ {{ { \sf{ \: \: Area_{(circle)} = 3.14 \times { \times 3.5 \times 3.5 }}}}}}} \: \: \\ \\\)

\({ \longrightarrow \qquad{ {{ { \sf{ \: \: Area_{(circle)} = 3.14 \times 12 .25 }}}}}} \: \: \\ \\\)

\({ \longrightarrow \qquad{ {{\pmb { \sf{ \: \: Area_{(circle)} = 38.465 }}}}}} \: \: \\ \\\)

Therefore,

Answer:

my question is also this thanks

Answer:

y = -y

Step-by-step explanation

So since we know that the answer of this question turns out to be a positive, and 5 is a negative number, that means y is negative. Heres my reason why:

( write this down on your essay)

Since a negative number and another negative number added becomes a positive, y would be a negative number.

Therefore, It is true that y is a negative number

Answer:

y = 4 - 2x

y = -2 + 2x

y = -2 + 2x

x = 11

pease tell me if I got them wrong

If the price of the appliance is at least $400, then the first digit must be 4. Given that the first digit is 4, there are two possible orders for the remaining digits: 345 and 435.

So, the probability of winning, given that the price is at least $400, is 2 out of the total number of possible arrangements of the digits 3, 4, and 5, which is 3! = 6. Therefore, the probability of winning is 2/6 = 1/3.

When finding probabilities, it's important to consider all the possible outcomes and determine which ones satisfy the given conditions. In this case, the condition was that the price of the appliance must be at least $400.

We started by using this information to determine that the first digit must be 4. With the first digit fixed as 4, there were only two possible orders for the remaining digits: 345 and 435. So, the probability of winning, given that the price is at least $400, is 2 out of the total number of possible arrangements of the digits 3, 4, and 5, which is 3! = 6.

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Answer:

(10+10)÷(5-3)

Step-by-step explanation:

Always do the parentheses first.

20÷2

Then divide

10

(10+10÷5) -3 is wrong because you do 10÷5 first. That 2 and then +10 is 12. 12-3=9.

Hope this helps!!!

The average velocity from t = 5 to t = 5.1 is -245 m/s.

An equation for the average velocity from 5 seconds to

t seconds is Δt = t - 5.

Required instantaneous velocity at t = 5 is (-50) m/s.

The rock is going down at that moment.

We can tell because the coefficient of the t² term in the equation for d(t) is negative.

The mathematical quantity for instantaneous velocity is a derivative.

How to find the average velocity of the rock from t = 5 to t = 5.1?

To find the average velocity of the rock from t = 5 to t = 5.1, we need to calculate the change in distance and change in time over this interval:

Δd = d(5.1) - d(5) = (35(5.1) - 5(5.1)²) - (35(5) - 5(5)²) ≈ -24.5

Δt = 5.1 - 5 = 0.1

Therefore, the average velocity from t = 5 to t = 5.1 is Δd/Δt ≈ -24.5/0.1 = -245 m/s

To find an equation for the average velocity from 5 seconds to t seconds, we need to calculate the change in distance and change in time over this interval:

Δd = d(t) - d(5) = (35t - 5t²) - (35(5) - 5(5)²) = 35(t - 5) - 5(t² - 25)

Δt = t - 5

Therefore, an equation for average velocity from 5 seconds to t seconds is Δt = t - 5

To find the instantaneous velocity of the rock at t = 5, we need to take the limit of the average velocity expression as Δt approaches 0,

instantaneous velocity at t = 5 = lim(Δt→0) [35 - 5(t + 5)] = 35 - 5(5 + 5) = -50 m/s

Since the instantaneous velocity at t = 5 is negative, the rock is going down at that moment. We can tell because the coefficient of the t² term in the equation for d(t) is negative, which means the parabolic shape of the trajectory is concave downward. The mathematical quantity for instantaneous velocity is a derivative, specifically the derivative of the distance function with respect to time.

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The average velocity from t = 5 to t = 5.1 is -245 m/s.

An equation for the average velocity from 5 seconds to

t seconds is Δt = t - 5.

Required instantaneous velocity at t = 5 is (-50) m/s.

The rock is going down at that moment.

We can tell because the coefficient of the t² term in the equation for d(t) is negative.

The mathematical quantity for instantaneous velocity is a derivative.

How to find the average velocity of the rock from t = 5 to t = 5.1?

To find the average velocity of the rock from t = 5 to t = 5.1, we need to calculate the change in distance and change in time over this interval:

Δd = d(5.1) - d(5) = (35(5.1) - 5(5.1)²) - (35(5) - 5(5)²) ≈ -24.5

Δt = 5.1 - 5 = 0.1

Therefore, the average velocity from t = 5 to t = 5.1 is Δd/Δt ≈ -24.5/0.1 = -245 m/s

To find an equation for the average velocity from 5 seconds to t seconds, we need to calculate the change in distance and change in time over this interval:

Δd = d(t) - d(5) = (35t - 5t²) - (35(5) - 5(5)²) = 35(t - 5) - 5(t² - 25)

Δt = t - 5

Therefore, an equation for average velocity from 5 seconds to t seconds is Δt = t - 5

To find the instantaneous velocity of the rock at t = 5, we need to take the limit of the average velocity expression as Δt approaches 0,

instantaneous velocity at t = 5 = lim(Δt→0) [35 - 5(t + 5)] = 35 - 5(5 + 5) = -50 m/s

Since the instantaneous velocity at t = 5 is negative, the rock is going down at that moment. We can tell because the coefficient of the t² term in the equation for d(t) is negative, which means the parabolic shape of the trajectory is concave downward. The mathematical quantity for instantaneous velocity is a derivative, specifically the derivative of the distance function with respect to time.

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Comparing with a cubic function with the same leading coefficient, we have it that the graphs of both functions are similar as they have excatly the same end behavior summarised below;

Here, we want to make a comparism

Before we go on to make the comparism, we want to describe the graph

As can be seen from the given equation of the graph, we have a positive leading coefficenit (the coefficeint of the highest power; x^5 in this case) and an odd degree (degree refers to the highest power of the polynomial)

Using this, we can get the property of the the graph

The property is simply that;

Now, for a cubic function with the same leading coefficient (+1 which is positive) and the degree which is 3; both functions have the same end properties

Answer:

one direction

Step-by-step explanation:

of course one direction

Answer:

20, 7, 5

Step-by-step explanation:

Range-20, range=most

Mode-7, mode=22-15

Most-5

Answer:

400,000

Step-by-step explanation:

Tel Aviv Population (2013) - 413,000

413,000 rounded to nearest hundred-thousand = 400,000

Final sum= 400,000. Hope this helps!

Answer: 400,000

The population of Tel Aviv in 013 was 413,000.

We have to round this number to the nearest 100,000.

We get 400,000, so it is the answer.

Answer:

1/4= 3/12-1/12 which is 2/12 or 1/6 cuz 3/12 is bigger than -1/12

Step-by-step explanation:

Answer: two twelvths

Step-by-step explanation: 1/4=3/12 and then 1/12=1/12. The dimonimator always stay's the same if they are all or both the same number. so dimonimator is 12 and then 3-1=2 so the numiraitor

Sorry if I did the wrong spelling or the answer!

thanks,vivid1388

Answer:

The amount of goo remaining after 32 minutes is approximately 54.7 grams.

Step-by-step explanation:

The half-life of a substance is the amount of time it takes for half of the substance to decay. To find the half-life of the goo in the experiment, we need to solve the equation G ( t ) = G ( 0 ) / 2 for t , where G ( 0 ) is the initial amount of goo and G ( t ) is the amount of goo remaining after time t .In this case, G ( 0 ) = 176 grams and G ( 135 minutes ) = 11 grams, so we can write the equation as follows:11 grams = 176 grams / 2Solving for t , we get:t = 135 minutes * ( 1 / 2 ) = 67.5 minutesThis is the half-life of the goo in the experiment.To find the amount of goo remaining after time t , we can use the equation G ( t ) = G ( 0 ) * ( 1 / 2 ) ^ ( t / t1/2 ) , where G ( 0 ) is the initial amount of goo, t is the time at which we want to find the amount of goo remaining, and t1/2 is the half-life of the goo.In this case, G ( 0 ) = 176 grams, t = 32 minutes, and t1/2 = 67.5 minutes, so we can plug these values into the equation to find the amount of goo remaining after 32 minutes:G ( 32 minutes ) = 176 grams * ( 1 / 2 ) ^ ( 32 minutes / 67.5 minutes )This equation tells us that the amount of goo remaining after 32 minutes is approximately 54.7 grams.

Answer:

0.40 is the correct answer

Answer:

0.35

Step-by-step explanation:

Labeling systems exist to roughly categorize r values where correlation coefficients (in absolute value) which are ≤ 0.35 are generally considered to represent low or weak correlations, 0.36 to 0.67 modest or moderate correlations, and 0.68 to 1.0 strong or high correlations with r coefficients > 0.90 very high.

Answer:

0.45

Step-by-step explanation:

You divided 2.25 by 5

Answer:

30.4

Step-by-step explanation:

17+28+32+35+59+20+19+33+30+31=304

304/10=30.4

Answer:

32.0 or 32/1 or 64/2

To calculate the volume of the complete ring with the given cross-section, we need to determine the area of the cross-section and multiply it by the width or thickness of the ring.

To find the volume V of the complete ring, we first need to calculate the area of the cross-section. The cross-section is likely to have a shape such as a circle, rectangle, or some combination of geometric figures. Once the cross-sectional area is determined, we can multiply it by the width or thickness of the ring to obtain the volume.

The specific calculation method will depend on the shape of the cross-section. For example, if the cross-section is a circle, the area can be found using the formula A = πr^2, where r is the radius of the circle. If the cross-section is a rectangle, the area can be found using the formula A = length × width.

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The probability of selecting a white-tailed deer that carries the Lyme disease bacteria is 1 in 10,000, or 0.0001. This means that out of every 10,000 white-tailed deer on the east coast, only one is expected to carry the Lyme disease bacteria.

If we assume that each deer in the population has an equal chance of carrying the bacteria, then the probability of selecting a deer that carries the bacteria can be calculated using the formula for probability:

Probability = Number of desired outcomes / Total number of possible outcomes

In this case, the number of desired outcomes is one (since we want to select a deer that carries the bacteria), and the total number of possible outcomes is the total number of white-tailed deer in the population. Since we don't know the exact number of deer in the population, we can assume that it is very large, so we can use an approximation:

Probability ≈ 1 / (Very large number)

Therefore, the probability of selecting a white-tailed deer from the east coast population that carries the Lyme disease bacteria is very close to 0.0001 or 1 in 10,000.

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       For C1(Q) = 3 - 2Q.

        For C2(Q) =  4.

     2. The AVC function

           For C1(Q) = 5/Q + 3 + 20/Q - Q.

           For C2(Q) = 3/Q + 4 + 2/Q.

     3. The AFC function

              For C1(Q)= 5/Q - 20/(5 + 3Q + 20/Q - Q)

              For C2(Q) = 0.

     4.  To find the AC function

        For C1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

         For C2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

    5.To find the ATC function

    For C1(Q)= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²)

     For C2(Q)= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

1. To find the MC function, we take the derivative of the cost functions with respect to Q.

For C1(Q) = 5 + 3Q + 202 - Q^2, MC1(Q) = 3 - 2Q.

For C2(Q) = 3 + 4Q + 2, MC2(Q) = 4.

2. To find the AVC function, we divide the cost functions by Q.

For C1(Q), AVC1(Q) = (5 + 3Q + 202 - Q^2)/Q = 5/Q + 3 + 20/Q - Q.

For C2(Q), AVC2(Q) = (3 + 4Q + 2)/Q = 3/Q + 4 + 2/Q.

3. To find the AFC function, we subtract the AVC function from the ATC function.

For C1(Q), AFC1(Q) = (5 + 3Q + 202 - Q^2)/Q - (5 + 3Q + 202 - Q^2)/(5 + 3Q + 20/Q - Q)

= 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AFC2(Q) = (3 + 4Q + 2)/Q - (3 + 4Q + 2)/(3/Q + 4 + 2/Q) = 0.

4. To find the AC function, we add the AVC function to the AFC function.

For

C1(Q), AC1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AC2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

5. To find the ATC function, we divide the AC function by Q.

For

C1(Q), ATC1(Q) = [(5 + 3Q + 202 - Q²)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q)]/Q

= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²).

For

C2(Q), ATC2(Q) = [(3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q]/Q

= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

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Polygons are shapes that have the following:

-sides are all straight

-no overlapping

-shape is always closed

Hope this helps :)