The Pecos Pueblo developed as a trading center over time. What evidence in the text supports the idea that this took a long time?

Because of its value as trading center, the Pecos Pueblo grew in size."

One of the last places the trail passed through was the Pecos Pueblo.

The site was just right for the trade.

Today, the trail attracts tourist instead of traiders.

An increased temperature generally causes a reaction to occur faster rather than slower. Therefore option C is correct.

The increased temperature leads to a higher average kinetic energy of the molecules, which results in more frequent and energetic collisions between the reactant particles.

This increased collision frequency and energy facilitate the breaking of chemical bonds and the formation of new bonds, leading to an accelerated reaction rate.

When the temperature is raised, the kinetic energy of the molecules increases. This means that the individual molecules move faster and possess a greater amount of energy. As a result, the molecules collide more frequently and with higher energy, enhancing the likelihood of successful collisions that lead to a reaction.

In summary, an increased temperature leads to a faster reaction rate by increasing the average kinetic energy of the particles, causing more frequent and energetic collisions.

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Answer:

Even in the absence of human-induced climate change, it is unlikely that ice sheets would build up in the next several thousand years, and the current interglacial climate (a period of time with low ice volume) would likely continue for another 50,000 years, making this an unusually long interglacial period. "There's no chance of us going into an ice age now because the greenhouse gases we've put into the atmosphere during the industrial era have warmed the earth." Although scientists cannot say we have definitely prevented the next ice age, it's certainly accepted that humans have had a significant part to play. When plate-tectonic movement causes continents to be arranged such that warm water flow from the equator to the poles is blocked or reduced, ice sheets may arise and set another ice age in motion.

Explanation:

Answer:

D e

Explanation:

An atom of 51V has 51 protons, 51 electrons, and approximately 49 neutrons.

The number of protons, electrons, and neutrons in an atom of 51V (vanadium) can be determined based on its atomic number, which is 51.

The atomic number of an element indicates the number of protons in its nucleus. Therefore, an atom of 51V has 51 protons.

Since atoms are electrically neutral, they must have an equal number of electrons as protons. Therefore, an atom of 51V has 51 electrons.

The number of neutrons in an atom can be calculated by subtracting the atomic number from the atomic mass, which is typically given in atomic mass units (amu). For 51V, the atomic mass is approximately 50.94 amu.

Therefore, the number of neutrons can be calculated as:

atomic mass - atomic number = number of neutrons

50.94 amu - 51 = approximately 49 neutrons

So, an atom of 51V has 51 protons, 51 electrons, and approximately 49 neutrons.

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When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy).

The potential energy that a huge item has in relation to a different massive object due to gravity is known as gravitational energy and gravitational potential energy. When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy). Bringing two things farther apart increases the gravitational potential energy.

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pH = pKa + log [conj.base]/[acid]

Let the concentration of the conjugate base = x

=> The concentration of the acid is also x (As the acid concentration is equivalent to that of the conjugate base)

for CH₃COOH=0.50 M and CH₃COO=0,25 M

pH = pKa + log [salt]/[acid]

pKa = -log Ka = -log 1.8x10-5 = 4.74

pH = 4.74 + log (0.50 M/1.0 M) = 4.74 + log 0.5 = 4.74 + (-0.3)

pH = 4.74 - 0.3

pH = 4.44

For0.20 M Na2CO3

pH=−log[H+]

    =−log (1.54×10−12)

   =11.8

for HNO₂

Kb = 2.17X10^-11 = x^2 / 0.148

x = [OH-] = 1.79X10^-6

pOH = 5.747

pH = 14.000 - pOH = 8.253

​

for HPO₄³⁻

= [HPO₄³⁻] [PO₄³⁻] [H +]/×10⁻³

=[PO₄³⁻]5.464×10⁻¹⁸

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The heat evolved per gram of CuS roasted is -5.01 kJ/g.

The reaction is exothermic, with a delta H of -114.6 kJ/mol. This means that the reaction releases 114.6 kJ of heat for every mole of CuS that is converted to CuO. The reaction is carried out in a roaster, which is a large, industrial-scale furnace that is specifically designed for this process.

To solve the above problem, we need to determine the heat evolved per mole of CuS roasted, and then convert that to heat per gram of CuS roasted.

The heat evolved per mole of CuS roasted can be calculated using the given equation and the given value for the enthalpy change:

AH = -805.6 kJ/mol

We can then convert the heat evolved per mole to heat evolved per gram by dividing by the molar mass of CuS:

Heat per gram = (-805.6 kJ/mol) / (160.6 g/mol) = -5.01 kJ/g

Therefore, After roasting, the copper oxide is then leached with a solution of sulfuric acid to extract the copper. The resulting solution is then filtered and the copper is recovered from the solution through a process called electrowinning.

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See full question below

The first step in the industrial recovery of copper from the copper sulfide ore is roasting, that is, the conversion of CuS to CuO by heating: 2CuS(s) + 302(g) → 2CuO(s) + 2802(g) AH = -805.6 kJ/mol Calculate the heat evolved (in kJ) per gram of CuS roasted.

Answer:

Nucleus, Endoplasmic Reticulum, Ribsome

Explanation:

I tried my best

Answer:

Explanation:

One system available in the industry for the detection of foreign substances in cotton is the High Volume Instrument (HVI) system. The HVI system measures several properties of cotton fibers, such as length, strength, micronaire, color, and foreign matter content. The foreign matter content measurement detects and quantifies any extraneous materials present in the cotton fibers, such as dirt, seed coat fragments, and leaf particles. The HVI system is widely used in the cotton industry for quality control and grading purposes.

Answer:

100.052 degrees C

Explanation:

It has been experimentally proven that the addition of solute to water will result in boiling point elevation due to the presence of more molecules. The boiling point elevation refers to the tendency of a solvent's boiling point to increase when an impurity (a solute) is added.

The formula of boiling point elevation is

\(\Delta T_{b} \ = \ K_{b} \times m\), where m is the molality defined as the number of moles of solute per kilograms of solvent and \(K_{b}\) is the molal boiling point elevation constant.

Given that the molal boiling point elevation constant of water is 0.512 \(^{\circ}\mathrm{C}{m}^{-1}\),

\(\Delta T_{b} \ = 0.512 \ ^{\circ}\mathrm{C}m^{-1} \times \displaystyle\frac{14.2 \ \mathrm{g}}{213 \ \mathrm{g \ mol^{-1} \ \times \ 0.655 \ kg \ (H_{2}O)}} \\ \\ \Delta T_{b} \ = \ 0.052 \ ^{\circ}\mathrm{C}\)

To evaluate the boiling point of the aluminium nitrate solution,

\(T_{b} \ (\mathrm{solution}) \ = \ T_{b} (\mathrm{H_{2}O}) \ + \ \Delta T_{b} \\ \\ \-\hspace{2.06cm} = \ 100^{\circ}\mathrm{C} \ + \ 0.052^{\circ}\mathrm{C} \\ \\ \-\hspace{2.06cm} = 100.052^{\circ}\mathrm{C}\)

Answer:

In the case of a New Moon, the Moon is between Earth and the Sun, so the side of the Moon facing the Sun isn't facing us. We can't see any portion of the lit-up Moon during this phase. (When the Sun and Moon exactly line up, as viewed from Earth, we get a special experience known as a solar eclipse

Explanation:

good luck hope this helps

Answer:

The reaction between carbon (C) and water (H2O) forms carbon monoxide (CO) and hydrogen gas (H2). The balanced chemical equation for this reaction is:

C(s) + H2O(g) -> CO(g) + H2(g)

According to this balanced equation, one mole of carbon reacts with one mole of water to produce one mole of carbon monoxide and one mole of hydrogen gas.

First, calculate the number of moles of carbon in 34 grams. The molar mass of carbon is approximately 12.01 grams/mole.

Moles of carbon = 34 grams / 12.01 grams/mole = 2.831 moles

As the stoichiometry of the reaction shows a 1:1 ratio between carbon and hydrogen, the moles of hydrogen produced would also be 2.831 moles.

The molar mass of hydrogen (H2) is approximately 2 grams/mole.

So, the mass of hydrogen produced = 2.831 moles * 2 grams/mole = 5.662 grams

Therefore, if 34 grams of carbon reacts with an unlimited amount of water, approximately 5.66 grams of hydrogen gas would be formed.

Explanation:

Approximations followed for answer.

Atoms of the same chemical element do not always have the same mass because, although the number of protons in the nucleus is the same for all atoms of the same element, the number of neutrons is not. Most elements as they occur naturally on earth are mixtures of several isotopes

hope this will help

Answer:

The [H₃O⁺] in Sauvignon Blanc with a pH of 3.21 is 6.55 x 10⁽⁻⁴⁾ M, while the [H₃O⁺] in Cabernet Sauvignon with a pH of 3.66 is 2.29 x 10⁽⁻⁴⁾ M. Sauvignon Blanc is about 2.86 times more acidic than Cabernet Sauvignon.

To find the [H₃O⁺] in each wine, we can use the pH formula:

pH = -log[H₃O⁺]

Rearranging this equation gives:

[H₃O⁺] = 10⁽⁻ᵖᴴ⁾

For the Sauvignon Blanc with a pH of 3.21:

[H₃O⁺] = 10⁽⁻³.²¹⁾ = 6.55 x 10⁽⁻⁴⁾ M

For the Cabernet Sauvignon with a pH of 3.66:

[H₃O⁺] = 10⁽⁻³.⁶⁶⁾ = 2.29 x 10⁽⁻⁴⁾ M

To determine how many times more acidic the Sauvignon Blanc is compared to the Cabernet Sauvignon, we can calculate the ratio of their hydrogen ion concentrations:

[H₃O⁺] (Sauvignon Blanc) / [H₃O⁺] (Cabernet Sauvignon) = (6.55 x 10⁽⁻⁴⁾) / (2.29 x 10⁽⁻⁴⁾) = 2.86

Therefore, the Sauvignon Blanc is about 2.86 times more acidic than the Cabernet Sauvignon.

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Density Formula:  Density = Mass / Volume

Answer:

10.5%

Explanation:

The equation used to calculate mass percent by volume is:

                                        Mass Solute (g)
Mass/Volume %  =  -----------------------------------  x  100%
                                   Volume Solution (mL)

In this case, the solute is the glucose. You can plug the given values into the equation and solve.

                                      34.1 g C₆H₁₂O₆
Mass/Volume %  =  -------------------------------  x  100%
                                        325 mL soln

Mass/Volume %   =  0.105 x 100%

Mass/Volume %  =  10.5%

Answer:

72.6 mL

Explanation:

A quick way to solve this titration problem when you have a monoprotic acid is to use the Dilution equation, M1V1=M2V2.

.589(x)=.821(52.1)

X=72.6 mL

Answer:

1.904 ppm

Explanation:

Concentration of drug in units of ppm = mass of solute / (mass of solution ) × 1000000

mass of blood = density of blood × volume = 1.05 g / ml × 5000 ml = 5250  g

mass of solution = mass of blood + mass of solute ( statin) = 5250 + 0.01 g  = 5250.01 g

Concentration of drug in units of ppm = (0.01 g / 5250.01 g) × 1000000 = 1.904 ppm

I hope this helps!!

At 25 degrees Celsius, with 50g of sugar, the solution will appear clear and homogeneous, with all the sugar dissolved. The ratio of dissolved sugar to undissolved sugar will be 50:0, as all the sugar has dissolved.

If an additional 55g of sugar is added to the 25-degree water, the solution will become supersaturated. This means that the water cannot dissolve all the sugar, resulting in the excess sugar remaining undissolved as solid particles at the bottom of the container. The solution will appear cloudy, and the ratio of dissolved sugar to undissolved sugar will be 50:5, as only 50g of the added sugar can dissolve.

When the solution is heated, the solubility of sugar increases. As a result, more sugar will dissolve, and the solution will become clear again. The ratio of dissolved sugar to undissolved sugar will approach 105:0 as the temperature increases and more sugar dissolves.

If the heated solution is slowly cooled back to 25 degrees Celsius, the solubility of sugar decreases. This will cause the excess sugar to come out of the solution and form solid crystals, which will be visible as sugar particles. The solution will appear cloudy again, and the ratio of dissolved sugar to undissolved sugar will depend on the amount of sugar that remains dissolved after cooling.

Adding a seed crystal to the mixture provides a surface for sugar crystals to form, resulting in the rapid crystallization of the remaining dissolved sugar. The solution will become saturated with sugar crystals, and the ratio of dissolved sugar to undissolved sugar will be close to 0:55, as most of the sugar will have crystallized. The solution will appear cloudy with a significant amount of sugar crystals present.

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Answer:

Example 1

palladium(II) nitrate,

Example 2

Metal catalysts such as Fe, Ni, Mo, and Co are routinely used in the manufacture of CNMs.

Explanation

The three metals used in catalytic converters — rhodium, platinum and palladium — are part of a category known as platinum group metals, or PGMs, which are known for their catalytic properties.

Answer:

3.11

Explanation:

Any buffer system can be described with the reaction:

\(HA~->~H^+~+~A^-\)

Where is the acid and is the base. Additionally, the calculation of the pH of any buffer system can be made with the Henderson-Hasselbach equation:

\(pH~=~pKa~+~Log(\frac{ [A^-]}{[HA]})\)

With all this in mind, we can write the reaction for our buffer system:

-) Nitrous acid: \(HNO_2\)

-) Sodium nitrate: \(NaNO_2\)

\(HNO_2~->~H^+~+~NO_2^-\)

In this case, the acid is \(HNO_2\) with a concentration of 0.150 M and a volume of 45.0 mL (0.045 L). The base is \(NO_2^-\) with a concentration of 0.175 M and a volume of 20.0 mL (0.020 L).

We can calculate the moles of each compound is we take into account the molarity equation (\(M=\frac{mol}{L}\)). So:

-) moles of \(HNO_2\):

\(mol=0.150~M*0.045~L=0.00657\)

-) moles of \(NO_2^-\):

\(mol=0.175~M*0.020~L=0.0035\)

The total volume would be:

0.020 L + 0.045 L = 0.065 L

With this in mind, we can calculate the molarity of each compound:

-) Concentration of \(HNO_2\)

\(M=\frac{0.00657~mol}{0.065~L}=0.101~M\)

-) Concentration of \(NO_2^-\)

\(M=\frac{0.0035~mol}{0.065~L}=0.0538~M\)

The pKa reported is 3.39, therefore we can plug the values into the Henderson-Hasselbach equation:

\(pH~=~3.39~+~Log(\frac{[0.0538~M]}{[0.101~M]})~=~3.11\)

The final pH value would be 3.11

I hope it helps!

The pH of a buffer made by combining 45.0 mL of 0.150M nitrous acid and 20.0mL of 0.175M sodium nitrate is 2.87.

We have a buffer made by combining 45.0mL of 0.150 M nitrous acid and 20.0mL of 0.175M sodium nitrate.

Nitrous acid is a weak acid and nitrate ion is its conjugate base.

It is a solution used to resist abrupt changes in pH when acids or bases are added.

We do so by multiplying the molar concentration by the volume in liters.

HNO₂: 0.150 mol/L × 0.0450 L = 6.75 × 10⁻³ mol

NaNO₂: 0.175 mol/L × 0.0200 L = 3.50 × 10⁻³ mol

The total volume will be the sum of the volumes of each solution.

V = 45.0 mL + 20.0 mL = 65.0 mL = 0.0650 L

HNO₂: 6.75 × 10⁻³ mol/0.0650 L = 0.104 M

NaNO₂: 3.50 × 10⁻³ mol/0.0650 L = 0.0538 M

We can calculate the pH of a buffer system using Henderson-Hasselbach's equation.

pH = pKa + log [NaNO₂]/[HNO₂]

pH = 3.16 + log 0.0538/0.104 = 2.87

The pH of a buffer made by combining 45.0 mL of 0.150M nitrous acid and 20.0mL of 0.175M sodium nitrate is 2.87.

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Answer:

Elements in the same period have the same number of electron shells.

Explanation:

elements gain electrons and protons and become less metallic

Answer:

God will help you and has a plan for you. Please don't cheat or look up answers. I used to be like you but I stopped. God always has a plan for you! Just remember this. He loves you. Share the message

Explanation:

Answer:well your in collage so figure it and suck to be you

Explanation:

XD

Answer:

An atom contains three basic particles namely protons, neutrons and electrons. The nucleus of the atom contains protons and neutrons where protons are positively charged and neutrons are neutral. The electrons are located at the outermost regions called the electron shell.

False. Sarah has not achieved homeostasis.

It is the maintenance of a relatively unchanged internal process in the body of organisms.

Since the resting heart rate for Sarah is 70 bpm, a 100 bpm is a far cry from the normal resting heart rate.

Thus, it cannot be said that Sarah has achieved homeostasis.

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The lone pairs on the oxygen in the following compound are best described as: one localized and one delocalized

A lone pair electron is valence shell electron pair associated with one atom, and not part of a covalent bond.

Within the context of this question, the oxygen atom of water for instance has two lone pair of which one of them is localized and other one is delocalized

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Taking into account the reaction stoichiometry, 128.4 grams of C are required to produce 10.7 moles of methane.

In first place, the balanced reaction is:

C + 2 H₂ → CH₄

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: If by reaction stoichiometry 1 mole of CH₄ is produced by 12 grams of C, 10.7 moles of CH₄ are produced by how much mass of C?

mass of C= (10.7 moles of CH₄×12 grams of C)÷1 mole of CH₄

mass of C= 128.4 grams

Finally, 128.4 grams of C are required.

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Answer:

[PCl₅] = 0.5646M

[PCl₃] = 0.1174M

[Cl₂] = 0.1174M

Explanation:

In the reaction:

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

K equilibrium is defined as:

K = 2.44x10⁻² = [PCl₃] [Cl₂] / [PCl₅]

The initial moles of each compound when volume is 15.3L are:

PCl₅ = 0.300mol/L×15.3L = 4.59mol

Cl₂ = 8.55x10⁻²mol/L×15.3L = 1.308mol

PCl₃ = 8.55x10⁻²mol/L×15.3L = 1.308mol

At 8.64L, the new concentrations are:

[PCl₅] = 4.59mol / 8.64L = 0.531M

[PCl₃] = 1.308mol / 8.64L = 0.151M

[Cl₂] = 1.308mol / 8.64L = 0.151M

At these conditions, reaction quotient, Q, is:

Q = [0.151M] [0.151M] / [0.531M]

Q = 4.29x10⁻²

As Q > K, the reaction will shift to the left producing more reactant, that means equilibrium concentrations are:

[PCl₅] = 0.531M + X

[PCl₃] = 0.151M - X

[Cl₂] = 0.151M - X

Where X is reaction coordinate.

Replacing in K expression:

2.44x10⁻² = [0.151M - X] [0.151M - X] / [0.531M + X]

1.296x10⁻² + 2.44x10⁻²X = 0.0228 - 0.302X + X²

0 = 9.84x10⁻³ - 0.3264X + X²

Solving for X:

X = 0.293 → False solution. Produce negative concentrations

X = 0.0336M → Right solution.

Replacing:

[PCl₅] = 0.531M + 0.0336

[PCl₃] = 0.151M - 0.0336

[Cl₂] = 0.151M - 0.0336