The owner of a meat market has an assistant who has determined that the weights of roasts are normally distributed, with a mean of 3.2 pounds and standard deviation of 0.8 pounds. for a sample of 25 roasts, what is the probability of sample mean less than 3.1 pounds
Answers
The probability of sample mean less than 3.1 pounds: 0.266. The correct option is C.
The weights of roasts are normally distributed with a mean of 3.2 pounds and a standard deviation of 0.8 pounds. In a sample of 25 roasts, we want to find the probability that the sample mean is less than 3.1 pounds.
First, we need to calculate the standard error of the mean, which is the standard deviation divided by the square root of the sample size:
Standard error = 0.8 / √25 = 0.8 / 5 = 0.16
Now, we need to calculate the z-score for the sample mean of 3.1 pounds:
Z = (Sample mean - Population mean) / Standard error = (3.1 - 3.2) / 0.16 = -0.1 / 0.16 = -0.625
Using a z-table or calculator, we find the probability associated with a z-score of -0.625:
P(Z < -0.625) ≈ 0.266
Therefore, the probability of the sample mean being less than 3.1 pounds is approximately 0.266, which corresponds to option C.
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Complete question:
The owner of a meat market has an assistant who has determined that the weights of roasts are normally distributed, with a mean of 3.2 pounds and a standard deviation of 0.8 pounds. For a sample of 25 roasts, what is the probability of sample mean less than 3.1 pounds?
a. 0.495
b. 0.450
c. 0.266
d. 0.521
Related Questions
Michelle ordered shirts to sell at the school carnival. She paid $2.80 per shirt, she adds a
150% markup to the total price she paid for the shirts.
What is the selling price of each shirt?
PLEASE HELP!! Any help will be greatly appreciated!
Answers
Answer:
The selling price is $7
Step-by-step explanation:
Step one:
Given information
She paid $2.80 per shirt
She adds a 150% markup to the total price she paid for the shirts
Let us find 150% of $2.80
=150/100*2.8
=1.5*2.8
=$4.2
Hence the selling price is the markup price plus the cost price
=4.2+2.8
=$7
Build a deterministic FA M
3
for the following language L
3
=L(M
3
)={x over {a,b,c}∣x has strictly more than 3c symbols and does not end in c} For example, abcca ∈
/
L
3
and bacccc ∈
/
L
3
, but cccca ∈L
3
and acbcaaabcccb ∈L
3
.
Answers
The deterministic finite automaton (DFA) M3 for the language L3, where strings have more than 3 'c' symbols and do not end in 'c', is designed with states q0, q1, q2, q3, and q4. Transitions and loops are created to determine acceptance.
To build a deterministic finite automaton (DFA) for the language L3 = {x ∈ {a, b, c}* | x has strictly more than 3 'c' symbols and does not end in 'c'}, we can design the following DFA M3:1. Start with an initial state q0.
2. Create a loop on q0 for 'a', 'b', and 'c' inputs, leading back to q0.
3. From q0, transition to a state q1 on input 'c'. This represents the first 'c' encountered.
4. From q1, create a loop for 'a' and 'b' inputs, leading back to q1.
5. Transition from q1 to q2 on input 'c'. This represents the second 'c' encountered.
6. Similarly, create a loop on q2 for 'a' and 'b' inputs, leading back to q2.
7. Transition from q2 to q3 on input 'c'. This represents the third 'c' encountered.
8. From q3, create a loop for 'a', 'b', and 'c' inputs, leading back to q3.
9. Create a final accepting state q4 and transition from q3 to q4 on 'a' or 'b' inputs.
In this DFA, any string that ends with 'c' or has less than three 'c' symbols will not reach the accepting state q4, hence not belonging to L3.
Therefore, The deterministic finite automaton (DFA) M3 for the language L3, where strings have more than 3 'c' symbols and do not end in 'c', is designed with states q0, q1, q2, q3, and q4. Transitions and loops are created to determine acceptance.
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What is three squared minus two thirds?
Answers
three squared minus two thirds
\(3^2-\frac{2}{3}\)three square = 3 x 3 = 9
\(\begin{gathered} 3^2-\frac{2}{3}=9-\frac{2}{3} \\ 3^2-\frac{2}{3}=\frac{9}{1}-\frac{2}{3} \end{gathered}\)Least common factor of 1 and 3 is 3
\(\begin{gathered} 3^2-\frac{2}{3}=\frac{9}{1}-\frac{2}{3} \\ 3^2-\frac{2}{3}=\frac{27-2}{3} \\ 3^2-\frac{2}{3}=\frac{25}{3} \end{gathered}\)Three squared minus two third is twenty five by three.
Suppose a research repot has estmated the demand for a frm's prodact as in O
X
d
=7−15 in P
X
+2 in Py=05 in M+ in A where:
P
X
=$15
P
y
=$6
M−$40000, and
A=$350
a Determine the ownt price elasticity of demand, and state whether demard is elassc, inelastic, ar untary elartic: Own price elasticty Demand is b. Determine Bre cross-pice elasticfy of demand between good X and goed Y, and state whetfer these two goods are sibstitutes or campleinents. Cross gnice efasticfly These two goods are: C. Determine the income elasticity of demand, and state whesher good X1 s a normal or inferior good. lncome elassicity? Good X is: 4. Determine the own advertising elasticity of demand.
Answers
a. Own Price Elasticity of Demand = (-30) / (0) = undefined. Since the own price elasticity of demand is undefined, we cannot determine if the demand is elastic, inelastic, or unitary elastic based on this information.
b. Cross-Price Elasticity of Demand = (12/7) / 0 = undefined. Since the cross-price elasticity of demand is undefined, we cannot determine if goods X and Y are substitutes or complements based on this information.
c. Income Elasticity of Demand = (-2860.71) / (0) = undefined. Since the income elasticity of demand is undefined, we cannot determine if good X is a normal or inferior good based on this information.
d. We cannot calculate the own advertising elasticity of demand with the provided data.
a. To determine the own price elasticity of demand, we need to use the formula:
Own Price Elasticity of Demand = (% Change in Quantity Demanded) / (% Change in Price)
Given the demand equation OXd = 7−15PX+2Py+0.5M+A, we can calculate the derivative of demand with respect to price:
d(OXd) / d(PX) = -15
Now, let's plug in the values:
% Change in Quantity Demanded = (d(OXd) / d(PX)) * (PX / OXd) = (-15) * (15 / 7) = -30
% Change in Price = (ΔPX / PX) = (15 - 15) / 15 = 0
b. To determine the cross-price elasticity of demand between goods X and Y, we use the formula:
Cross-Price Elasticity of Demand = (% Change in Quantity Demanded of Good X) / (% Change in Price of Good Y)
Using the same demand equation, we calculate the derivative of demand with respect to the price of good Y:
d(OXd) / d(Py) = 2
Now, let's plug in the values:
% Change in Quantity Demanded of Good X = (d(OXd) / d(Py)) * (Py / OXd) = (2) * (6 / 7) = 12/7
% Change in Price of Good Y = (ΔPy / Py) = (6 - 6) / 6 = 0
c. To determine the income elasticity of demand, we use the formula:
Income Elasticity of Demand = (% Change in Quantity Demanded) / (% Change in Income)
Using the same demand equation, we calculate the derivative of demand with respect to income:
d(OXd) / d(M) = 0.5
Now, let's plug in the values:
% Change in Quantity Demanded = (d(OXd) / d(M)) * (M / OXd) = (0.5) * (-40000 / 7) = -2860.71
% Change in Income = (ΔM / M) = (-40000 - (-40000)) / (-40000) = 0
d. The own advertising elasticity of demand measures the responsiveness of quantity demanded to changes in advertising expenditure. Unfortunately, the given demand equation does not provide any information about advertising expenditure or its impact on quantity demanded.
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Find the area of the figure. A composite figure made of a triangle, a square, and a semicircle. The diameter and base measure of the circle and triangle respectively is 6 feet. The triangle has a height of 3 feet. The square has sides measuring 2 feet. area: ft²
Answers
The total area of the figure in this problem is given as follows:
41.3 ft².
How to obtain the area of the composite figure?The area of the composite figure is given by the sum of the areas of all the parts that compose the figure.
The figure in this problem is composed as follows:
Triangle of base 6 feet and height 3 feet.Semicircle of radius 3 feet.Square of side length 2 feet.Then the area of the triangle is given as follows:
At = 0.5 x 6 x 3 = 9 ft².
The area of the semicircle is given as follows:
Ac = π x 3² = 28.3 ft².
The area of the square is given as follows:
As = 2² = 4 ft².
Then the total area of the figure is given as follows:
9 + 28.3 + 4 = 41.3 ft².
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help please!!!
When using the SAS Similarity Theorem, the angle used must be the ___ angle.
Question 5 options:
complementary
corresponding
congruent
supplementary
opposite
right
included
Answers
What is 7/2 divided by 5/4?
HURRY UP PLZ!!
Answers
Answer:
\( \frac{14}{5} \)
Step-by-step explanation:
1) Use this rule : a ÷ b/c = a × c/b.
\( \frac{7}{2} \times \frac{4}{5} \)
2) Use this rule: a/b × c/d = ac/bd.
\( \frac{7 \times 4}{2 \times 5} \)
3) Simplify 7 × 4 to 28.
\( \frac{28}{2 \times 5} \)
4) Simplify 2 × 5 to 10.
\( \frac{28}{10} \)
5) Simplify.
\( \frac{14}{5} \)
Therefor, the answer is 14/5. And is decimal form it would be, 2.8.
A circle with a random radius R ? Uniform(0, 1) is generated. Let A be its area. Find the mean and variance of A.
Answers
The mean and variance of the area A of a circle with a random radius R, uniformly distributed between 0 and 1, can be calculated using mathematical formulas. The mean of A is π/4, and the variance of A is (π^2 - 4)/16.
The area A of a circle is given by the formula A = π * R^2, where R is the radius. Since the radius R is uniformly distributed between 0 and 1, we can express the probability density function (PDF) of R as f(R) = 1 for 0 ≤ R ≤ 1, and f(R) = 0 elsewhere.
To find the mean of A, we need to calculate the expected value of A, denoted as E[A]. Using the formula for expected value, we have E[A] = ∫(A * f(R)) dR = ∫(π * R^2) dR from 0 to 1. Solving this integral gives E[A] = π/4.
To find the variance of A, we need to calculate E[A^2] first. Using the formula for expected value, we have E[A^2] = ∫(A^2 * f(R)) dR = ∫(π^2 * R^4) dR from 0 to 1. Solving this integral gives E[A^2] = π^2/5.
The variance of A can be calculated as Var[A] = E[A^2] - (E[A])^2 = π^2/5 - (π/4)^2 = (π^2 - 4)/16.
Therefore, the mean of A is π/4, and the variance of A is (π^2 - 4)/16 for a circle with a random radius R uniformly distributed between 0 and 1.
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What is simple linear regression? Give an intuitive definition and illustrate with a graph. Label residuals and explain how they are used in the construction of the regression line.
Answers
Simple linear regression is a statistical technique used to model the relationship between two variables by fitting a straight line to the data. It provides a way to predict or estimate the value of one variable (dependent variable) based on the value of another variable (independent variable).
In simple linear regression, the relationship between the independent variable (x) and the dependent variable (y) is represented by a straight line. The goal is to find the best-fitting line that minimizes the differences between the observed values of the dependent variable and the predicted values from the regression line.
A graph illustrating simple linear regression includes the scatterplot of the data points, the regression line, and the residuals. The scatterplot shows the individual data points with the independent variable on the x-axis and the dependent variable on the y-axis. The regression line is the line that best fits the data, minimizing the sum of the squared residuals.
Residuals are the vertical distances between the observed data points and the regression line. They represent the differences or errors between the actual values and the predicted values. By examining the residuals, we can assess how well the regression line fits the data. If the residuals are randomly scattered around zero, it suggests that the linear regression model is appropriate. If there is a pattern or systematic deviation in the residuals, it indicates that the model may not be capturing the underlying relationship accurately.
The regression line is constructed by minimizing the sum of the squared residuals, which is known as the least squares method. This ensures that the line represents the best linear approximation of the relationship between the variables.
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a pool has a rectangular base of $$10 ft by $$20 ft and a depth of $$6 ft. what is the change in volume if you only fill it up to $$5.5 ft? use differential to estimate the error when computing the volume.
Answers
Using the volume of rectangle, the change in volume if you only fill it up to $$5.5 ft is 100 square ft.
In the given question,
A base of a rectangular pool = 10 ft
A height of a rectangular pool = 20 ft
A depth of a rectangular pool = 6 ft
We filled it up to 5.5 ft.
So the difference in the height is
dh=(6−5.5) ft
dh=0.5 ft
As we know the volume of rectangle is
V=l∙b∙h
where V=volume of rectangle
l=length of rectangle
b=depth of rectangle
h=height of rectangle
We find the change in volume of a rectangular pool by differentiating with respect to h.
dV=l∙b∙dh
We know that l=10 ft, b=20 ft and dh=0.5 ft
Now substituting the value in dV
dV=10∙20∙0.5
dV=100
Hence, the change in volume if you only fill it up to $$5.5 ft is 100 square ft.
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At a fair last weekend, Zach sold homemade jewelry. If he sold the jewelry for R dollars and it cost him C dollars to make the jewelry, the formula P = R - C describes his profit P in dollars. If his profit was $49.32 and he sold the jewelry for $81.18, how much did it cost him to make the jewelry?
Answers
Answer:
We can use the given formula to solve for the cost C:
P = R - C
We know that P = $49.32 and R = $81.18, so we can substitute these values into the formula:
$49.32 = $81.18 - C
Next, we can solve for C by isolating it on one side of the equation:
C = $81.18 - $49.32
C = $31.86
Therefore, it cost Zach $31.86 to make the jewelry he sold at the fair.
YOU CAN BUY 5 BANANAS FOR $2.50. HOW JAST
MUCH WILL IT COST TO BUY / BANANAS? YOU
BUY
Please Help!
Answers
Answer:
It will cost $12.50
You are baking cookies for a bake sale. It takes 30 minutes to mix the cookie dough and 10.5 minutes to bake a sheet of cookies. The total time can be modeled by t(x) = 10.5x+30, where x is the number of sheets of cookies baked. a. Graph the function and identify its domain and range. b. Find and interpret the value of x so that t(x) = 114.
Answers
Kenny ordered guitar strings for Glenn’s Guitar Shop. The premium guitar strings are $4. 50 apiece. The standard guitar strings are $1. 50 apiece. The bill smeared in the rain, but Kenny knows he ordered a total of 80 strings for $225. Let x = the number of premium strings. Let y = the number of standard strings. X y = 80, 4. 50x 1. 50y = 225 How many of each type of string did Kenny order? He ordered premium strings. He ordered standard strings.
Answers
Answer:
x = 35 y = 45
Step-by-step explanation:
Total number of strings: x + y = 80 ⇒ x = 80 - y
Substitute x = 80 - y into 4.5x + 1.5y = 225 to find y:
4.5(80 - y) + 1.5y = 225
360 - 4.5y + 1.5y = 225
3y = 135
y = 45
Substitute the found value of y into x + y = 80 to find x:
x + 45 = 80
x = 80 - 45 = 35
To solve the problem we must know about the system of equations.
System of equationInconsistent SystemA system of equations to have no real solution, the lines of the equations must be parallel to each other.
Consistent System1. Dependent Consistent System
A system of the equation to be Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.
2. Independent Consistent System
A system of the equation to be Independent Consistent System the system must have one unique solution for which the lines of the equation must intersect at a particular.
The number of premium and standard strings Kenny ordered are 35 and 45 respectively.
Given to us
x = the number of premium stringsy = the number of standard strings4.50x + 1.50y = 225x+y = 80Total Number of StringsTotal Number of Strings
= number of premium strings + number of standard strings
80 = x+ y
Solving for y,
y = 80-x
Total Cost of all stringsTotal Cost of all strings
($4.50)x + ($1.50y) = $225
4.50x + 1.50y = 225
Substitute the value of y,
\(4.50x + 1.50(80-x) = 225\\\\4.50x +120 -1.5x = 225\\\\4.50x-1.5x = 225-120\\\\3x = 105\\\\x=\dfrac{105}{3}\\\\x = 35\)
Thus, the number of premium strings Kenny ordered was 35.
Substitute the value of x in the equation of y,
y = 80 - x
y = 80 - 35
y = 45
Thus, the number of standard strings Kenny ordered was 45.
Hence, the number of premium and standard strings Kenny ordered are 35 and 45 respectively.
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Which postulate proves these two
triangles are congruent?
B. SSA
A. HL
D. None, not congruent
C. ASA
Answers
i believe that it is choice: a.
i hope this helps
A student bought football tickets online. The ticket company charges a
processing fee of $9.50. The total cost of purchasing the tickets including the
processing fee was $85.30. If the tickets are $18.95 each, how many tickets did
he buy? (ONLY TYPE A NUMBER INTO THE ANSWER BOX] *
Answers
Answer:
3
Step by step explanation:
So, I just added 9.5 to 18.95, I got 28.45. 28.45x3=85.30, so he bought 3 tickets.
Will a large-sample confidence interval be valid if the population from which the sample is taken is not normally distributed? explain
Answers
A normal distribution is a type of continuous probability distribution for a real-valued random variable in statistics.
Yes, the large-sample confidence interval will be valid.
What is meant by normal distribution?A normal distribution is a type of continuous probability distribution for a real-valued random variable in statistics.
The normal distribution, also known as the Gaussian distribution, is a symmetric probability distribution about the mean, indicating that data near the mean occur more frequently than data far from the mean.
The confidence interval will be valid regardless of the shape of the population distribution as long as the sample is large enough to satisfy the central limit theorem.
What does a large sample confidence interval for a population mean?A sample is considered large when n ≥ 30.
By 'valid', it means that the confidence interval procedure has a 95% chance of producing an interval that contains the population parameter.
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Please help asap will give brainilest
Answers
Answer:
a
Step-by-step explanation:
hi! i need help on number 4 and 5 please! this is due tmr
Answers
Answer:
In the picture
Step-by-step explanation:
Hey again ! If you have any question feel free to ask !!
Question 4:
Solve for the variable N in \(55+8n=4n+107\)
Answer:
\(n=13\)
Step-by-step explanation:
1. Subtract \(4n+107\) from both sides; \(4x-52\)
2. Separate variable \(n\) by adding \(52\) to both sides; \(4n=52\)
3. Simplify equation by dividing by \(4\) on both sides; \(=13\)
Question 5:
Solve for the variable N in \(6-6x=5x-9x-2\)
Answer:
\(x=4\)
Step-by-step explanation:
1. Subtract \(5x-9x-2\) from both sides; \(8-2x\)
2. Separate variable \(x\) by adding \(2x\) to both sides; \(8=2x\)
3. Simplify equation by dividing by \(2\) on both sides; \(4=x\)
$1000 into savings account earning %1 annual compound interest for 10 years
Answers
After 10 years, the savings account will have approximately $1104.62.
If you deposit $1000 into a savings account earning an annual compound interest rate of 1% for 10 years, your money will grow over time due to the power of compounding. Compound interest means that the interest earned is added to the principal, and subsequent interest is calculated based on the new total.
In this case, with an interest rate of 1%, the amount will grow steadily over the 10-year period. The formula for calculating the future value of compound interest is FV = PV × (1 + r)ⁿ, where FV is the future value, PV is the principal amount, r is the interest rate, and n is the number of periods.
Plugging in the values, we get FV = $1000 × (1 + 0.01)¹⁰. Evaluating this equation, we find that the future value is approximately $1104.62.
This means that after 10 years, your initial $1000 investment will have grown to approximately $1104.62 due to the compounded interest. It demonstrates the benefit of saving money and allowing it to accumulate over time with compound interest.
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Use the Trapezoidal Rule with n = 6 subintervals to estimate the length of the curve. (Round your answer to two decimal places.) x = t - e, y = t + et, -3 ≤ t ≤ 3 x
Answers
Using the Trapezoidal Rule with n = 6 subintervals, the estimated length of the curve is approximately 14.47 units.
To estimate the length of the curve using the Trapezoidal Rule, we need to calculate the sum of the lengths of the straight-line segments connecting the points on the curve. Here's how you can do it:
1. Divide the interval [-3, 3] into n = 6 equal subintervals.
Each subinterval will have a width of Δt = (3 - (-3)) / 6 = 1.2.
2. Evaluate the x and y coordinates for each t in the subinterval.
Using the given parametric equations:
For each subinterval i, let t_i be the left endpoint of the subinterval.
Calculate:
\(- x_i = t_i - e \\ - y_i = t_i + et_i\)
3. Calculate the lengths of the straight-line segments between consecutive points.
For each subinterval i, calculate the length using the distance formula:
\(\[L_i = \sqrt{{(x_{i+1} - x_i)^2 + (y_{i+1} - y_i)^2}}\]\)
4. Sum up the lengths of all the subintervals.
\(- L_{total }= L_1 + L_2 + L_3 + L_4 + L_5 + L_6\)
Let's perform the calculations:
Subinterval 1:
\(t_1 = -3\\x_1 = -3 - e\\y_1 = -3 + e(-3)\)
Subinterval 2:
\(t_2 = -3 + 1.2 = -1.8\\x_2 = -1.8 - e\\y_2 = -1.8 + e(-1.8)\)
Subinterval 3:
\(t_3 = -1.8 + 1.2 = -0.6\\x_3 = -0.6 - e\\y_3 = -0.6 + e(-0.6)\)
Subinterval 4:
\(t_4 = -0.6 + 1.2 = 0.6\\x_4 = 0.6 - e\\y_4 = 0.6 + e(0.6)\)
Subinterval 5:
\(t_5 = 0.6 + 1.2 = 1.8\\x_5 = 1.8 - e\\y_5 = 1.8 + e(1.8)\)
Subinterval 6:
\(t_6 = 1.8 + 1.2 = 3\\x_6 = 3 - e\\y_6 = 3 + e(3)\)
Now we can calculate the lengths of the straight-line segments:
\(\[L_1 = \sqrt{{(x_2 - x_1)^2 + (y_2 - y_1)^2}}\]\[L_2 = \sqrt{{(x_3 - x_2)^2 + (y_3 - y_2)^2}}\]\[L_3 = \sqrt{{(x_4 - x_3)^2 + (y_4 - y_3)^2}}\]\[L_4 = \sqrt{{(x_5 - x_4)^2 + (y_5 - y_4)^2}}\]\[L_5 = \sqrt{{(x_6 - x_5)^2 + (y_6 - y_5)^2}}\]\)
Finally, we can sum up the lengths of the subintervals:
\(L_total = L_1 + L_2 + L_3 + L_4 + L_5 + L_6\)≈ 14.47
Remember to round the final answer to two decimal places.
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Four students each flip a coin multiple times and record the number of times the coin lands heads up. The results are shown in the table. Student Number of Flips Ana 50 Brady 10 Collin 80 Deshawn 20 Which student is most likely to find that the actual number of times his or her coin lands heads up most closely matches the picted number of heads-up landings?
Answers
The student that has the highest probability to find that the actual number of times his or her coin lands heads up most closely matches the predicted numberof heads-up landings is Collin.
How is this so?Let's calculate the expected number of heads-up landings for each student -
Ana = 0.5 * 50 = 25
Brady = 0.5 * 10 = 5
Collin = 0.5 * 80 = 40
Deshawn = 0.5 * 20 = 10
From the above we can see that Collin (80 flips) is most likely to find that the actual number of times his coin lands heads up most closely matchesthe predicted number of heads-up landings (40).
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Full Question:
Although part of your question is missing, you might be referring to this full question:
Four students are determining the probability of flipping a coin and it landing head's up. Each flips a coin the number of times shown in the table below.
Student
Number of Flips
Ana
50
Brady
10
Collin
80
Deshawn
20
Which student is most likely to find that the actual number of times his or her coin lands heads up most closely matches the predicted number of heads-up landings?
the polygons in each pair are similar. find the scale factor of the smaller figure to larger figure.
Answers
Answer:
Scale factor = \(\frac{1}{2}\)
Step-by-step explanation:
From the picture given in the question,
If the larger figure is dilated to form the smaller figure,
Scale factor by which a figure is dilated with is determined by the expression,
Scale factor = \(\frac{\text{Measure of one side of the smaller figure}}{\text{Measure of the corresponding side of the larger figure}}\)
= \(\frac{3}{6}\)
= \(\frac{1}{2}\)
The graph below shows the percent of times a family ate at different restaurants in a year. The family ate at MacGregor’s 27 times.
How many times did the family eat at restaurants in a year?
20% amys place
10% pizza hut
10% taco bell
27 times adams house
Answers
Answer:
b pizza hut
Step-by-step explanation:
sorry im wrong
what is 0.076499 and 10100 to 2 significant figures?
Answers
Answer: \(0.076\) and \(1\overline{0}000\)
Step-by-step explanation:
The question asks you to go to two significant figures.
\(0.076499\) to two significant figures is \(0.076\) because leading zeros are insignificant. Any number from 1 to 9 is always significant. If the digit next to the 6 was 5 or greater, then it would be \(0.077\), but because it is 4 or less, it is not the case.
\(10100\) to two significant figures is \(1\overline{0}000\) because the zeros represent placeholders unless a decimal is present after the final zero. However, what we have is a 0 sandwiched in between a 1 and a 1. Zeros in between numbers that are between 1 and 9 are always significant. Because the second zero is considered significant, we draw a line over it to signify it as such. The remaining zeros are insignificant and are simply placeholders.
For her final project, stacy plans on surveying a random sample of students on whether they plan to go to florida for spring break. From past years, she guesses that about % of the class goes. Is it reasonable for her to use a normal model for the sampling distribution of the sample proportion? why or why not?.
Answers
Yes, it is reasonable for her to use a normal model for the sampling distribution of the sample proportion. In this case, less than ten efforts have been successful. Since 5 is a lot less than 10, this is the case.
Because the data don't fit the success and failure criteria, it is not appropriate to adopt a normal model for a sampling of the sample distribution.
50 students make up the sample. The probability that she assumes 10% of the group will attend is 10%.
It will be demonstrated by:
1 - p = 1 - 10% = 1 - 0.10 = 0.90
np = 50 × 0.1 = 5. This suggests the number of victories.
Less than 10 attempts have succeeded in this instance. 5 is much less than 10, hence this case. As a result, the data does not satisfy the requirement.
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The question is -
For her final project, Stacy plans on surveying a random sample of 50 students on whether they plan to go to Florida for spring break. from past years, she guesses that about 10% of the class goes. is it reasonable for her to use a normal model for the sampling distribution of the sample proportion? why or why not?
Toxoplasma gondii is a flagellated ____________ that is an obligate intracellular parasite. Its natural host is the ____________ but it has little host specificity so it can infect over 200 species of birds and ____________ .
Answers
Toxoplasma gondii is a protozoan parasite that belongs to the phylum Apicomplexa. It is known for its ability to infect warm-blooded animals, including birds and mammals. Although the parasite's natural host is the cat, it can also infect over 200 species of birds and mammals.
This broad host range is due to its ability to exploit various cellular and immune mechanisms across different species. Toxoplasma gondii enters its host through ingestion of contaminated food or water, or by coming into contact with infected animal feces. Once inside the host, the parasite infects and replicates within host cells, forming specialized structures called toxoplasma gondii cysts. These cysts can persist in the host's tissues, particularly in neural and muscular tissues.
While Toxoplasma gondii infections are typically asymptomatic in healthy individuals, they can cause severe complications in individuals or in cases of congenital transmission from infected mothers to their unborn children. Understanding the biology and host range of Toxoplasma gondii is important for studying and managing the risks associated with this widespread parasite.
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30 POINTS!!
LOOK AT PHOTOS!! (THERES 2!!)
Which graph displays points that correspond to the x and y values in the table?
Answers
Have a good day,
Answer:
A
Step-by-step explanation:
A is the only one with (4,0) (1,-1) (0,0) and (-2,5)
An amusement park sold 91 discount tickets and 84 full-priced tickets. What percentage of the tickets sold were discount tickets?
Answers
Percentage = 91/175 x 100 = 52%
RESPUESTA: 175
Explico:
5 trucks can transport 500 quintals of rice to a remote region of Nepal in 3 days. In how many days would 4 trucks transport 800 quintals of rice to the same place?
Answers
We can set up a proportion to solve for the number of days required:
(Trucks) × (Days) = (Rice quintals)
Using the first scenario:
5 trucks × 3 days = 500 quintals
Now we can solve for the second scenario using the same ratio:
4 trucks × (unknown number of days) = 800 quintals
To find the number of days, we can rearrange the equation and solve for it:
(4 trucks) × (unknown number of days) = 800 quintals
Dividing both sides of the equation by 4 trucks, we get:
(Unknown number of days) = 800 quintals / 4 trucks
(Unknown number of days) = 200 quintals per truck
Therefore, it would take 200 quintals per truck to transport the rice. Since the first scenario took 3 days to transport 500 quintals, we can calculate the number of days required for 800 quintals:
(Number of days) = (800 quintals) / (200 quintals per truck)
(Number of days) = 4 days
Therefore, it would take 4 days for 4 trucks to transport 800 quintals of rice to the same remote region in Nepal.