The owens corning company has developed a program that reuses discarded asphalt shingles removed from homes that are being reroofed. the old shingles are taken to a recycling center, where they are ground up and repurposed into asphalt paving mix. shingles from 19 average-sized homes can help pave one-half mile of a two-lane highway. old shingles from how many such homes would be needed to pave a 10-mile long stretch of two-lane highway?

Alex can find the product by shading 5 sections in each row. In this way, each shaded row represents 5/6.

Now, to find the product, Alex has to add the shaded values, that is,

Answer:

Step-by-step explanation:

a.)

\(4880.76=4000(1+.04/4)^{4x}\\\\1.22019=1.01^{4x}\\\frac{\ln{1.22019}}{\ln{1.01}}=4x\\x= 4.999999= 5\)

b.)

\(5395.4=4000(1+x/12)^{12*5}\\1.34885=(1+x/12)^{60}\\\sqrt[60]{1.34885} =1+x/12\\x= 0.0599999772677= .06\)

c.)

\(\i)\\100*(1+.1255)= 112.55\\\\2)\\100*(1+.1218/2)^2= 112.550881= 112.55\)

Answer:

26

Step-by-step explanation:

Answer:

26

Step-by-step explanation:

a. The set of points on E(F7) is:

{(0, 1), (0, 6), (1, 0), (1, 6), (2, 0), (2, 1), (3, 2), (3, 5), (4, 3), (4, 4), (5, 2), (5, 5), (6, 0), (6, 1)}

b. The set of points on E(F11) is:

{(0, 4), (0, 7), (1, 5), (1, 6), (2, 0), (3, 2), (3, 9), (4, 2), (4, 9), (5, 3), (5, 8), (6, 2), (6, 9), (7, 0), (8, 1), (8, 10), (9, 4), (9, 7), (10, 6)}.

a)\(E: Y^2 = X^3 + 3X + 2 over F7:\)

To find the set of points on this elliptic curve over F7, we can substitute each value of x from 0 to 6 into the equation and check whether there exists a corresponding y that satisfies the equation.

The set of points on E(F7) is:

{(0, 1), (0, 6), (1, 0), (1, 6), (2, 0), (2, 1), (3, 2), (3, 5), (4, 3), (4, 4), (5, 2), (5, 5), (6, 0), (6, 1)}

(b)\(E: Y^2 = X^3 + 2X + 7 over F11:\)

To find the set of points on this elliptic curve over F11, we can similarly substitute each value of x from 0 to 10 into the equation and check whether there exists a corresponding y that satisfies the equation.

The set of points on E(F11) is:

{(0, 4), (0, 7), (1, 5), (1, 6), (2, 0), (3, 2), (3, 9), (4, 2), (4, 9), (5, 3), (5, 8), (6, 2), (6, 9), (7, 0), (8, 1), (8, 10), (9, 4), (9, 7), (10, 6)}.

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Answer:

137°

Step-by-step explanation:

90+47= 137°

the sum of two interior angles is equally to the further exterior angle.

The complex number z = 5e^(3ix) can be expressed in Cartesian notation.  the complex number z = 5e^(3ix) can be expressed in Cartesian notation as z = 5*cos(3x) + 5i*sin(3x), where the real part is 5*cos(3x) and the imaginary part is 5*sin(3x).

To express z in Cartesian notation, we can use Euler's formula, which states that e^(ix) = cos(x) + i*sin(x), where i is the imaginary unit. Applying this formula to the given expression, we have:

z = 5e^(3ix)

 = 5(cos(3x) + i*sin(3x))

Now, we can separate the real and imaginary parts to write z in Cartesian form a + bi, where a represents the real part and b represents the imaginary part:

Real part (a): 5*cos(3x)

Imaginary part (b): 5*sin(3x)

Therefore, the Cartesian form of z is:

z = 5*cos(3x) + 5i*sin(3x)

In summary, the complex number z = 5e^(3ix) can be expressed in Cartesian notation as z = 5*cos(3x) + 5i*sin(3x), where the real part is 5*cos(3x) and the imaginary part is 5*sin(3x).

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The letter grades (A, B, C, D, F) for business analysis students are categories that represent different levels of achievement, so the variable's classification is (b) Categorical Data.

The Categorical data are defined as the variables that represent characteristics or attributes, and they are often expressed as labels or categories.

The Quantitative data, on the other hand, are  the numerical values which  represent measurements or quantities.

Since the letter grades are not numerical values and do not represent a measurement or quantity, they cannot be classified as quantitative data.

Therefore , the letter grades represents a Categorical Variables .

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The given question is incomplete , the complete question is

The letter grades (A, B, C, D, F) of business analysis students are recorded by a professor. this variable's classification .

(a) is time series data

(b) is categorical data

(c) is quantitative data

(d) cannot be determined

Answer:

Step-by-step explanation:

Answer:

-21/40, -3/8, 21, 21 3/8, 21 3/40,

Step-by-step explanation:

The interest when the classmate is calculating the amount in a savings account after 10 years is $2600.

From the information, the classmate is calculating the amount in a savings account after 10 years and the deposit is $13,000 and the annual simple interest rate is 2%.

It should be noted that interest is calculated as:

= (Principal × Rate × Time) / 100

= ($13000 × 2 × 10) / 100

= $2600

The simple interest is $2600.

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Answer:

Option G is the correct answer.

Step-by-step explanation:

If three parallel lines intersect two transversals, then the segments intercepted on the transversals are proportional.

\( \frac{x}{12} = \frac{2}{8} \\ \\ \frac{x}{12} = \frac{1}{4} \\ \\ x = \frac{12}{4} \\ \\ x = 3 \\ \\ \)

Option G is the correct answer:

Answer:

D. 0.054

Step-by-step explanation:

61.904 - 61.85

= 0.054

Therefore, answer choice D is the correct answer.

The largest binary code is on 4 bits, the maximum possible number is binary 1111 or 15. And the maximum decimal number that can be represented with 1 byte is 255 or 11111111.

Binary code:

In math, binary code refers a coding system using the binary digits 0 and 1 to represent a letter, digit, or other character in a computer or other electronic device.

Given,

Here we need to find the largest binary code.

Here we know that, for each digit d in a binary number, starting from the rightmost digit, the value in decimal corresponding to this digit is written as,

=> d2ⁿ + d*2ⁿ⁻¹ .... 0, where n is its position.

For, example would be converting 11001:

Here we start from the right

=> 1*2⁰ + 0*2¹ + 0*2² + 1*2³ + 1*2⁴ = 25.

Therefore, if we have 8 bits, the largest number would be 11111111, That has the value of 255, which is the same result as the conversion above (1+2+4+8+16+32+64+128).

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The quotient 49/109 ÷ 28/37 represents a quotient expression. This is because 49/109 is the dividend and the number 28/37 is the divisor. The quotient of 49/109 ÷ 28/37 is 259/436

The quotient expression is given as

49/109 ÷ 28/37

The above expression is a quotient expression such that

To calculate the quotient, we start by rewriting the expression as a product

So, we have:

49/109 ÷ 28/37 = 49/109 * 37/28

Divide 49 and 28 by 7

So, we have

49/109 ÷ 28/37 = 7/109 * 37/4

Multiply the numerator and the denominator

So, we have

49/109 ÷ 28/37 = 259/436

Hence, the complete statement is

The quotient 49/109 ÷ 28/37 represents a quotient expression. This is because 49/109 is the dividend and the number 28/37 is the divisor. The quotient of 49/109 ÷ 28/37 is 259/436

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Answer:

It is the third option

Step-by-step explanation:

I hope this helps you

Answer:

5 loaves

Step-by-step explanation:

13 1/3 divided by 2 2/3 is 5 so the answer is 5 loaves.

Rewrite the fractions as improper fractions then divide the total amount used by the amount per loaf:

13 1/3 = 40/3

2 2/3 = 8/3

40/3 / 8/3

When dividing by a fraction flip the fraction over and multiply

40/3 x 3/8 = (40 x3) /( 3 x 8) = 120/24 = 5

She made 5 loaves of bread.

Answer:

the proportion would be 5/8 = r/32

r = 20

Step-by-step explanation:

the number of red stripes would be 20

To calculate the reliability of the bank loan processing system with backup components, we can use the concept of series-parallel system reliability.

In the original system, the three components are connected in series. To calculate the overall reliability of the system, we multiply the reliabilities of the individual components:

R_system = R_1 * R_2 * R_3 = 0.82 * 0.991 * 0.98 ≈ 0.801

So, the reliability of the bank loan processing system without backup components is approximately 0.801.

Now, if each of the three components has a backup with a reliability of 0.80, we have a parallel configuration between the original components and their backups. In a parallel system, the overall reliability is calculated as 1 minus the product of the complement of individual reliabilities.

Let's calculate the reliability of each component with the backup:

R_1_with_backup = 1 - (1 - R_1) * (1 - 0.80) = 1 - (1 - 0.82) * (1 - 0.80) ≈ 0.984

R_2_with_backup = 1 - (1 - R_2) * (1 - 0.80) = 1 - (1 - 0.991) * (1 - 0.80) ≈ 0.9988

R_3_with_backup = 1 - (1 - R_3) * (1 - 0.80) = 1 - (1 - 0.98) * (1 - 0.80) ≈ 0.9992

Now, we calculate the overall reliability of the system with the backups:

R_system_with_backup = R_1_with_backup * R_2_with_backup * R_3_with_backup ≈ 0.984 * 0.9988 * 0.9992 ≈ 0.981

Therefore, the reliability of the bank loan processing system with backup components is approximately 0.981.

Comparing the two scenarios, we can see that introducing backup components with a reliability of 0.80 has improved the overall reliability of the system. The total reliability increased from 0.801 (without backups) to 0.981 (with backups). Having backup components in a parallel configuration provides redundancy and increases the system's ability to withstand failures, resulting in higher reliability.

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Answer:

Step-by-step explanation: To find out what grade Sally needs to earn on her fifth and last math test to achieve a 90 average, we  use the following steps:

Step 1: Add the total points Sally has received: 80 + 82 + 92 + 98 = 352.

Sally has taken 4 tests so far.

Step 2: Find the total marks required for a 90 average on 5 tests: 90 x 5 = 450.

Step 3: Find the score Sally needs to achieve on her fifth test by subtracting the points earned  from the total required points: 450 - 352 = 98.

Therefore, Sally needs to earn a grade of 98 on her 5th and last test to achieve a 90 average on all five tests this semester.

tThe population in this scenario refers to the entire group of policyholders of the large automobile insurance company.

Set up the hypotheses ; Null hypothesis (H0): The mean age in the population of policyholders is 50.  Alternative hypothesis (Ha): The mean age in the population of policyholders is different from 50. Determine the significance level: The significance level is given as 5%.  Calculate the test statistic: The test statistic for a two-sample t-test is given by:
    t = (sample mean - hypothesized mean) / (standard error)

 In this case, the sample mean is 47.2, and the hypothesized mean is 50. The standard error can be calculated using the formula: standard error = sqrt(variance / sample size).  In this case, the variance is 121 and the sample size is 361. Calculate the degrees of freedom:  For a two-sample t-test, the degrees of freedom is calculated as the sum of the sample sizes minus 2.  In this case, the sample size is 361.  Determine the critical value:  Since the alternative hypothesis is two-tailed (different from 50), we divide the significance level by 2 (5% / 2) to get the critical value for each tail.

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We can predict with 99% confidence that a new employee with 9 hours of training will produce between -4.16 and 3.49 defects per countertop.

To find the 99% prediction interval for the number of defects per countertop for an employee with 9 hours of training, we can use the estimated regression equation and the standard error provided.

The 99% prediction interval is given by:

Predicted value ± t(0.995, n-2) x SE

where t(0.995, n-2) is the t-score for the 99% confidence level with n-2 degrees of freedom (where n is the sample size), and SE is the standard error.

First, we need to calculate the predicted value:

Defects per Countertop = 6.717822 - 1.004950(Hours of Training)

Defects per Countertop = 6.717822 - 1.004950(9)

Defects per Countertop = -0.334578

Next, we need to find the t-score for the 99% confidence level with 8 degrees of freedom (n-2 = 10-2 = 8). Using a t-distribution table or calculator, we find that t(0.995, 8) = 3.355387.

Finally, we can calculate the 99% prediction interval:

-0.334578 ± 3.355387 x 1.2297787

This simplifies to:

-4.157722 < Defects per Countertop < 3.488566

Therefore, we can predict with 99% confidence that a new employee with 9 hours of training will produce between -4.16 and 3.49 defects per countertop. However, since the lower limit is negative, it does not have practical meaning in this context. Therefore, we can conclude that we can predict with 99% confidence that a new employee with 9 hours of training will produce between 0 and 3.49 defects per countertop.

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Answer:

Not a whole lot of information there but if i would guess what its trying to ask me is she worked out for 30 minutes the question is the answer.

Try giving for information next time :(

Answer:

What are the Answers?

Step-by-step explanation:

Rectangle is the shape of the cross section formed by the intersection of the plane and the solid​.

If a plane intersects a cylinder in a perpendicular manner, such that the plane is parallel to one of the bases of the cylinder, the resulting cross-section will be a rectangle.

The rectangle's dimensions will depend on the dimensions of the cylinder and the specific position of the plane within the cylinder.

The length of the rectangle will be equal to the circumference of the cylinder, and the width will be equal to the height or the diameter of the cylinder.

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Answer:

down:

18 560

19 890

20 u

Step-by-step explanation:

thinking's answer support 100000/1000 your right answer you

Answer:

12.5 ft

Step-by-step explanation:

Ratio of shadow to person  =

4:5

Ratio of shadow to tree =

10:x

Form an equation

4/5 = 10/x

4x = 50

x = 12.5

Answer = 12.5 ft

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

The area of the small sector is 10.28 cm² and the area of the large sector is 17.98 cm².

The area of a sector of a circle is given by the formula A = (θ/360)πr², where θ is the central angle in degrees, and r is the radius of the circle.

For the small sector with an arc angle of 131 degrees, we have:

A = (131/360)π(3 cm)²

A ≈ 10.28 cm²

For the large sector, we have a central angle of 229 degrees (360 - 131), so:

A = (229/360)π(3 cm)²

A ≈ 17.98 cm²

Therefore, the area of the small sector is approximately 10.28 cm² and the area of the large sector is approximately 17.98 cm².

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Answer:

:))))))))))))))))))))))

Answer:

(4,11)

Step-by-step explanation:

y=2x+3

y=5x-9

the first equation is equal to the second equation so

2x+3=5x-9

put like terms together

2x-5x= -9-3

-3x= -12

divide both sides by -3

.•.x=4

now, use the value of x to find the value of y like this:

y=2x+3 (x=4)

y=2(4)+3

y=8+3

y=11

therefore, the two lines intersect at the point (4,11)