The number of golf balls ordered by customers of a pro shop has the following probability distribution.

Probability Distribution
x P(x)
3 0.14
6 0.29
9 0.36
12 0.11
15 0.10

Answer

Option B is correct.

E'F' is equal in length to EF.

Explanation

When a figure is rotated through any degree clockwise or counterclockwise, the length of the figure stays the same.

This proves option B right and it proves options C and D wrong.

But to prove option A wrong, we need to find the coordinates of E'F'.

When a rotation of 270° counterclockwise about the origin is done on some coordinate, A (x, y), it transforms this coordinates into A' (y, -x). That is, we switch y and x, then add negative sign to x.

To obtain the coordinates of E' and F', we need to obtain the coordinates of E and F first.

E (1, -4)

F (5, -4)

When they are transformed through rotation of 270° counterclockwise about the origin, the change is that

A (x, y) = A' (y, -x)

E (1, -4) = E' (-4, -1)

F (5, -4) = F' (-4, -5)

E' (-4, -1) and F' (-4, -5) when marked out and drawn on this graph gives a vertical line that lies on x = -4 and covers from y = -1 to y = -5.

This indicates that E'F' is vertical and not horizontal like EF and thus, E'F' is not parallel to EF, rather, E'F' is perpendicular to EF.

Hope this Helps!!!

The side length of the the rectangular garden are 20 feet by 5 feet.

Let

s = side length of the square garden

l = length of the rectangular garden

w = width of the rectangular garden

From the problem statement,

area of the square garden = area of the rectangular garden

Since the area of a square is just the side length squared, we can write:

s² = l * w

We also know that the length of the rectangular garden is 10 feet longer than the side of the square garden, and that the width of the rectangular garden is 5 feet shorter than the side of the square garden. We can express them as:

l = s + 10

w = s - 5

Now we can substitute these expressions for l and w into our first equation:

s² = (s + 10) * (s - 5)

Expanding the right-hand side, we get:

s² = s² + 5s - 50

0 = 5s - 50

5s = 50

Dividing both sides by 5, we get:

s = 10

Since the side length of the square garden is 10 feet.

We can use this to find the dimensions of the rectangular garden:

l = s + 10 = 10 + 10 = 20

w = s - 5 = 10 - 5 = 5

So the dimensions of the rectangular garden are 20 feet by 5 feet.

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Answer:

The answer would 81, LOLOLOLOL

Step-by-step explanation:

Answer:

its A on edge2020

Step-by-step explanation:

Answer:

1:8

Step-by-step explanation:

1 hour for every 8 ounces gives a 1:8 ratio

Answer:

8:3 would be the ratio

Answer:

O a=0

Step-by-step explanation:

Answer: option D

Step-by-step explanation:

Given equation:

P = 6 w + 8 [eq1]

l=2w+4 [where l is length]

using eq1 we have:

6w=P-8

w=(P-8)/6

hence  option D

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The product of 7 times 63 is 441. We can check this by multiplying 7 by 63 directly and verifying that it also equals 441.

To use the distributive property to find the product of 7 times 63, we can break down 63 into smaller factors. One way to do this is to notice that 63 is divisible by 7, so we can write it as 7 times 9.

Now we can use the distributive property to write an expression for the product of 7 times 63:

7 × 63 = 7 × (7 × 9)

Using the distributive property, we can multiply 7 by each factor inside the parentheses:

7 × (7 × 9) = (7 × 7) × 9

Now we can simplify the expression by multiplying 7 by 7 to get:

(7 × 7) × 9 = 49 × 9

Finally, we can multiply 49 by 9 to get the product:

49 × 9 = 441


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Answer:

The dimensions that will maximize the enclosed area of the pen is 250 ft by 250 ft

Step-by-step explanation:

we have the perimeter as 1000

So the sum of the lengths will be

1000/2 = 500

The dimensions that will maximize these pens will be such that they will have equal values

Mathematically, that will be 500/2 = 250 by 250

Answer:

248 teachers

Step-by-step explanation:

The length in feet of the longest part of the garden would be = 6ft

A garden is defined as an area that is prepared and set aside for the purpose of growing various flowers, shrubs and grasses.

The area of the given triangle = 54in²

The perimeter of the given triangle = 36 in.

Using the formula for area of a triangle ;

Area = ½ base(b) ×height(h)

where base = 9 in

54 = 1/2 × 9 × h

Make h the subject of formula;

h = 54×2/9

h = 108/9

h = 12

But the perimeter = sum of the whole sides of the triangle

perimeter = 36

side a = 9

side b = 12

side c = X

that is , 36 = 9+12+X

make X the subject of formula;

X = 36-21

X = 15in

Therefore, 15 in when converted to feet;

2 ft = 5 in

X ft = 15 in

xft = 2 × 15/5

X ft = 30/5

X ft = 6ft

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Answer:

\( x = 11 \)

Step-by-step explanation:

Given that ∆CDE ~ ∆FGH

CD = 25

DE = 35

FG = 65

GH = 8x + 3

Therefore,

\( \frac{CD}{FG} = \frac{DE}{GH} \)

(Similarity Theorem)

\( \frac{25}{65} = \frac{35}{8x + 3} \)

Cross multiply

\( 25(8x + 3) = 35*65 \)

\( 200x + 75 = 2275 \)

\( 200x + 75 - 75 = 2275 - 75 \)

\( 200x = 2200 \)

\( \frac{200x}{200} = \frac{2200}{200} \)

\( x = 11 \)

Answer:

C. 11

Step-by-step explanation:

x = 11

Answer:

the answer would be a

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

just got it correct

Answer:

Step-by-step explanation:

1.) Students are going to conduct an experiment to study the effect of a net force applied to an object on the object’s motion. In each trial of the experiment, the students will apply a net force on the object. They also need to take two other measurements. What are the other quantities they should measure in each trial of the experiment?

ANSWER: mass and acceleration

2.) Use the data table to answer the question. It shows the acceleration of a body when a net force is applied to it.

Net force (N) Mass (kg) Acceleration (m/s2)

5.0 5.0 1.0

10.0 5.0 2.0

20.0 5.0  

Which value would complete the last cell?

ANSWER: 4.0

3.) Which statement makes an accurate comparison of the motions for objects C and D?

ANSWER: Object C has an acceleration that is greater than the acceleration for D.

4.) Use the equation for motion to answer the question.

x=x0+v0t+12at2

An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?

ANSWER: 17 m

5.) The graph of an object's position over time is a horizontal line and y is not equal to 0. What must be true about the object's motion?

ANSWER: The velocity is zero.

hope this helps <33

Answer:

Area= 40,000

Step-by-step explanation:

I really hope that is correct I used an online calculator, hopefully its right!

Answer:

-5/6

Step-by-step explanation:

By the application of Analytical geometry the rate of change of y with respect to x is -5/6.

what is Analytical geometry?

Analytical geometry is a branch of mathematics that studies geometric shapes and figures using analytical methods. It is a branch of mathematics that uses algebraic techniques to describe geometric shapes and figures. It involves the use of analytical equations and formulas to study geometric concepts. Analytical geometry is used to study the properties of points, lines, angles, circles, and other geometric shapes. It can also be used to solve problems involving angles, distances, and areas of figures. In addition, analytical geometry can be used to find the intersection of two lines, calculate the area of a circle, and calculate the volume of a cylinder. Analytical geometry is a powerful tool used in many scientific and engineering fields.

The rate of change of y with respect to x for this line is -5/6
Therefore -5/6 is rate of change in this graph.

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Answer:

Step-by-step explanation:

50in-3ft(12in/ft)

50in-36in

14in

Answer:

(C) 12

Step-by-step explanation:

To solve this problem, we can use the following steps:

Find half of 80: 80/2 = 40

Add 20 to half of 80: 40 + 20 = 60

Find one fifth of the result: 60/5 = 12

Therefore, one fifth of twenty more than half of 80 is equal to 12. The correct answer is (C) 12.

Answer:

(C) 12

Step-by-step explanation:

What is one fifth of twenty more than half of 80

0.5 × 80 = 40

What is one fifth of twenty more than half of 80

40 + 20 = 60

What is one fifth of twenty more than half of 80

1/5 × 60 = 60/5 = 12

Answer:

A

Step-by-step explanation:

Cosine X= adjacent /hypotenuse

where adjacent=5 and hyp=13

Cos X=5/13

Step-by-step explanation:

-x-2-2x=-2x-2

-x-2=-2

x=0

Step-by-step explanation:

\(47.1 = 2\pi \times r \\ r = \frac{47.1}{2\pi} = 7.4962996 \\ diameter = 2 \times r \\ = 14.99 = 15 \: feet\)

On solving the provided question, we can say that the quadratic function \(f(x)=x^{2}+10x+24.\) , so f(-2) = 8

Quantities and their variations, equations and related structures, shapes and their placements, and locations where they can be found are all included in the study of mathematics.

The relationship between a group of inputs, each of which has a related output, is referred to as a "function." A function is a relationship between inputs and outputs where each input produces a single, unique result. Every function has a domain and a codomain, often known as a scope. F is typically used to denote functions (x). An x is the input. Based on the following criteria, there are four primary categories of functions that are available: on functions, one-to-one functions, many-to-one functions, within functions, and on functions.

the quadratic function \(f(x)=x^{2}+10x+24.\)

By substituting different values of x

For x = 0

if f(0) = 24

For x = 1

if f(1) = 35

For x = 2

if (2) = 48

For x = -2

so f(-2) = 8

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In accordance with the above formula, the pythagorean ratio of (x - y) to cos(180 - x + y) is equal to -cos (y - x).

The branch of mathematics concerned with the calculation of specific functions of particular angles. There are six widely used angles-related trigonometric functions. Their relative names and acronyms include sum (sin), covariance (cos), curvilinear (tan), median (cot), subplots (sec), and cotangent (csc).

Inferring the cosine of a difference between two angles using trigonometry, we get:

cos(180 - x + y) = cos(180) cos(x - y) + sin(180) sin(x - y)

Since cos(180) = -1 and sin(180) = 0, The equation above may be made simpler to:

cos(180 - x + y) = -cos(x - y)

As a result, we have:

cos(180 - x + y) = -cos(x - y) = -cos(y - x)

The mathematical ratio of (x - y) to cos(180 - x + y) is hence -cos (y - x).

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Answer:

The numerator

Step-by-step explanation:

Answer:

numerator

Step-by-step explanation:

You can think of it as this. Denominator (the number below the line in fraction), starts with D, and down also starts with D.  Denominator starts with D so it's down. Numerator is the opposite. Hope this helped :)

Answer:

Domain = (-∞, ∞) Range = (-∞, ∞)

End Behavior: As X -> -∞, Y -> -∞ | As X -> ∞, Y -> ∞

Inflection Point: (2,0)

Step-by-step explanation:

Answer:

0.7 and 0.07

Step-by-step explanation:

Step-by-step explanation:

s1 = 5

s2 = s1 × -2 = 5×-2 = -10

s3 = s2 × -2 = -10 × -2 = 20

...

now, we could do all that manually.

but there is also a formula for geometric sequence.

in fact, there are 2 - one for finite and one for infinite sequences.

and I was not completely honest, each of these 2 had some sub-forms depending on the size of the multiplier or ratio.

since we need the sum of the first 5 terms, which of the 2 do you think we need ?

of course, finite, because 5 is a normal number we can "touch". it is not infinity.

so, the formulas for finite sums of geometric sequences are :

if |r| < 1, Sn = a(1 - r^n)/(1 - r)

if |r| > 1, Sn = a(r^n - 1)/(r - 1)

if r = 1, Sn = na

if r = -1, then Sn = a or 0 depending on if n is odd or even.

the sequence is in general

s1 = a

sn = sn-1 × r

in our case a = 5, r = -2.

so, what form of the formula do we need ?

|-2| = 2, and 2 > 1, so ...

S5 = 5(-2^5 ‐ 1)/(-2 - 1) = 5(-32 - 1)/-3 = 5×-33/-3 =

= 5 × 11 = 55

quick check, as the 5 terms are

5

-10

20

-40

80

and their sum is : 55

correct !

1.1. Accumulated depreciation:

The accumulated depreciation for the machine bought on 1 July 2013 would be R150,000 as of 31 March 2016.

1.2. Machine realization:

The machine bought in 2013 was sold for R120,000 on 30 June 2015, resulting in a profit/loss on the sale of R10,000.

1.1. Accumulated Depreciation:

To calculate the accumulated depreciation, we need to determine the annual depreciation expense for each machine and then accumulate it over the years.

Machine bought on 1 July 2013:

Cost: R250,000

Depreciation rate: 20% per annum on cost

Depreciation expense for the year ended 31 March 2014: 20% of R250,000 = R50,000

Depreciation expense for the year ended 31 March 2015: 20% of R250,000 = R50,000

Depreciation expense for the year ended 31 March 2016: 20% of R250,000 = R50,000

Accumulated depreciation for the machine bought on 1 July 2013:

As of 31 March 2014: R50,000

As of 31 March 2015: R100,000

As of 31 March 2016: R150,000

1.2. Machine Realisation:

To record the sale of the machine bought in 2013, we need to adjust the machine's value and the accumulated depreciation.

Machine's original cost: R250,000

Accumulated depreciation as of 30 June 2015: R100,000

Net book value as of 30 June 2015:  

R250,000 - R100,000 = R150,000.

On 30 June 2015, the machine was sold for R120,000.

Realisation amount: R120,000

To record the sale:

Debit Cash: R120,000

Debit Accumulated Depreciation: R100,000

Credit Machine: R250,000

Credit Machine Realisation: R120,000

Credit Profit/Loss on Sale of Machine: R10,000 (difference between net book value and realisation amount).

These entries will reflect the appropriate balances in the ledger accounts and properly close off the accounts for the years ended 31 March 2016.

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