The nitro substituent was introduced in the meta position of the methyl benzoate. Why does it preferentially occur at meta-, rather than para- or ortho-? Show structures to prove your reasoning. (Be aware that it preferentially goes to meta, which means that the other reactions are not totally excluded.)

Answer:

It just does

Explanation:

Answer:

Tallgrass Praries have more Rainfall

Explanation:

The mass of a lead ball with a radius of .50mm is  5.9714226×\(10^{6}\) g

A substance's density is defined as its mass per unit of volume. Density is most frequently represented by the symbol, however Latin letter D may also be used. The formula for density is mass divided by volume.

ρ = m/v

For, v = 4/3π\(r^{3}\)

v = 4/3×3.14×\(50^{3}\)

v = 523,809 \(cm^{3}\)

As, density = mass / volume

11.4 = mass / 523,809

mass = 5971422.6 g

mass = 5.9714226×\(10^{6}\) g

So,  the mass of a lead ball with a radius of .50mm is  5.9714226×\(10^{6}\) g

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A statement which most likely explains why the early atomic models did not include the subatomic particles is that: D. subatomic particles could not be detected with the technology available.

Generally, an atom comprises three (3) distinct subatomic particles and these include the following

Ernest Rutherford performed a set of experiments on atoms in 1910 which has helped several scientists and researchers to better understand the structure of atoms by using gold foil.

In his experiment on structure of atoms, Rutherford directed a beam of small, positively charged particles referred to as alpha () particles at a very thin sheet of gold foil.

However, the early atomic models did not include the subatomic particles is that they could not be detected with the technology available at the time.

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Complete Question:

Ancient atomic models described the atom as a solid sphere with no charge. In the 1800's and 1900's, scientist discovered subatomic particles with charges inside the atoms.

Which statement most likely explains why the early models did not include the subatomic particles?

answer choices

atoms changed over time to develop the subatomic particles

not all atoms contain subatomic particles

subatomic particles move and cannot be counted

subatomic particles could not be detected with the technology available.

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M.

Given reaction obeys the rate law, rate=k[A]²[B].

Here, the initial concentration of A= 0.10 M,

initial concentration of B = 0.05 M, and

rate constant, k = 2.0 × 10⁻⁴ M⁻¹s⁻¹

We have to find the concentration of A, after 30 seconds.

To find the concentration of A, we need to know the rate at 0.10 M and 0.05 M. Therefore, we have to calculate the rates at these concentrations.

rate1 = k[A]²[B]

= (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.10 M)²(0.05 M)

= 1.0 × 10⁻⁷ M/srate2

= k[A]²[B] = (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.09 M)²(0.04 M)

= 6.48 × 10⁻⁸ M/s

Using the integrated rate law for a second-order reaction: [A] = [A]₀ - kt where [A]₀ = initial concentration of A, k = rate constant, and t = time in seconds.

We know [A]₀ = 0.10 M and k = 2.0 × 10⁻⁴ M⁻¹s⁻¹.

Substituting the values in the above equation, we get: [A] = [A]₀ - kt= 0.10 M - (2.0 × 10⁻⁴ M⁻¹s⁻¹)(30 s)≈ 0.0934 M

Therefore, the concentration of A in the vessel after 30 seconds is 0.0934 M.

This question requires us to calculate the concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We are given the initial concentration of A and B and the rate constant of the reaction. To find the concentration of A after 30 seconds, we need to calculate the rates at the initial concentrations of A and B.

Using the integrated rate law for a second-order reaction, we can find the concentration of A at any given time. We substitute the given values in the formula and solve for [A]. We get the concentration of A as 0.0934 M after 30 seconds. This calculation is based on the assumption that no other reaction is important.

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B]. We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M. This calculation assumes that no other reaction is important.

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Answer:

it has  a huge surface-to-volume ratio, very high porosity and completely different physiochemical properties.

Explanation:

idk if the answer is good  !

sorry

The minimum volume of 0.289 M potassium iodide solution required to completely precipitate all of the lead in 185.0 ml of a 0.110 M lead (II) nitrate solution is approximately 70.4 ml.

All of the lead in 185.0 ml of a 0.110 M lead (II) nitrate (Pb(NO3)2) solution, we need to consider the stoichiometry of the reaction between KI and Pb(NO3)2.

The balanced chemical equation for the reaction is:

2KI + Pb(NO3)2 → PbI2 + 2KNO3

From the balanced equation, we can see that 2 moles of KI react with 1 mole of Pb(NO3)2 to form 1 mole of PbI2.

Given:

Volume of Pb(NO3)2 solution = 185.0 ml

Concentration of Pb(NO3)2 solution = 0.110 M

Concentration of KI solution = 0.289 M

We can use the following relationship based on the stoichiometry of the reaction:

(C1 × V1) / n1 = (C2 × V2) / n2

Where:

C1 = Concentration of Pb(NO3)2 solution

V1 = Volume of Pb(NO3)2 solution

n1 = Stoichiometric coefficient of Pb(NO3)2

C2 = Concentration of KI solution

V2 = Volume of KI solution

n2 = Stoichiometric coefficient of KI

Substituting the values into the equation:

(0.110 M × 185.0 ml) / 1 = (0.289 M × V2) / 2

Simplifying the equation:

V2 = (0.110 M × 185.0 ml × 2) / (0.289 M)

V2 ≈ 70.4 ml

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Answer:

14g

Explanation:

The empirical formula of the compound is CH₂ ;

When we are dealing with compounds the gram formula mass or gram - molecular weight is the molar mass of the compound.

It is determined by adding the atomic masses of the components together and then expressed in grams.

 Atomic mass of C  = 12

 Atomic mass of H  = 1

  Gram formula mass = 12 + 2(1)  = 14g

Answer:

The amount of sodium chloride.

Explanation:

This is because an independent/manipulated control is something that is changed or controlled by the experimenter. Jax has control over the change of sodium, therefore the answer is the amount of sodium chloride.

I took the test and got this answer right btw. Good luck everyone :)

To determine the maximum pressure of water vapor in wet hydrogen at 1 atm pressure in which chromium can be heated without oxidation occurring at 1500 K, we need to consider the water vapor pressure equilibrium with respect to the oxidation reaction of chromium.

The oxidation of chromium by water vapor can be represented by the following equation:

2Cr + 3H2O(g) → Cr2O3 + 3H2(g)

At equilibrium, the ratio of the product of the partial pressures of the products to the product of the partial pressures of the reactants should be equal to the equilibrium constant (Kp) for the reaction.

The equilibrium constant expression for the reaction can be written as:

Kp = (P(Cr2O3) * P(H2)^3) / (P(Cr)^2 * P(H2O)^3)

At the maximum pressure of water vapor, oxidation of chromium does not occur. This means that the partial pressure of water vapor (P(H2O)) will be equal to zero. Thus, the equilibrium constant expression can be simplified as follows:

Kp = (P(Cr2O3) * P(H2)^3) / (P(Cr)^2)

Since the pressure of hydrogen (P(H2)) is 1 atm and the pressure of chromium (P(Cr)) is negligible compared to the other pressures involved, we can further simplify the expression to:

Kp ≈ P(Cr2O3)

We can now calculate the equilibrium constant (Kp) using available thermodynamic data. The standard Gibbs free energy change (ΔG°) for the oxidation reaction of chromium can be obtained from tables or literature. Let's assume ΔG° = -540 kJ/mol.

The equilibrium constant can be calculated using the equation:

ΔG° = -RT ln(Kp)

Where:

ΔG° = standard Gibbs free energy change (-540 kJ/mol)

R = gas constant (8.314 J/(mol·K))

T = temperature (1500 K)

Converting the units, we have:

ΔG° = -540,000 J/mol

R = 8.314 J/(mol·K)

T = 1500 K

Substituting the values into the equation and solving for ln(Kp), we get:

-540,000 = -8.314 * 1500 * ln(Kp)

ln(Kp) = -540,000 / (-8.314 * 1500)

ln(Kp) ≈ 45.874

Taking the exponential of both sides to solve for Kp, we have:

Kp = e^(45.874)

Kp ≈ 1.13 x 10^19

Since Kp ≈ P(Cr2O3), the maximum pressure of Cr2O3 (P(Cr2O3)) at equilibrium is approximately 1.13 x 10^19 atm.

The maximum pressure of water vapor in wet hydrogen at 1 atm pressure, in which chromium can be heated without oxidation occurring at 1500 K, is approximately 1.13 x 10^19 atm.

Regarding the second part of the question, the calculation does not provide information about the exothermic or endothermic nature of the oxidation reaction of chromium by water vapor. The equilibrium constant (Kp) only indicates the position of the equilibrium, not the direction or energy change of the reaction. To determine the thermodynamics of the reaction (whether it is exothermic or endothermic), we would need additional information such as the enthalpy change (ΔH°) of the reaction.

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Answer:

Amino acid

Explanation:

When you eat food the body's digestive system breaks down the protein into the individual amino acids, which are absorbed and used by cells to build other proteins and a few other macromolecules, such as DNA

Answer:

it disappeared loll jk

it obviously dried

well you may Mark me as brainliest

Answer:

The given element is Radon because its atomic weight is 222 amu.

Explanation:

Given data:

Percentage of A-219 = 13.92%

Percentage of B-222 = 72.16%

Percentage of C-225 = 13.92%

Atomic weight of element = ?

Solution:

Average atomic mass = (abundance of A isotope × its atomic mass) +(abundance of B isotope × its atomic mass) + (abundance of C isotope × its atomic mass)  / 100

Average atomic mass  = (13.92×219)+(72.16×222) + (13.92×225)/100

Average atomic mass =  3048.48 + 16019.52 +3132/ 100

Average atomic mass  = 22200 / 100

Average atomic mass  = 222 amu.

The given element is Radon because its atomic weight is 222 amu.

Answer:

A solid

the internolecular forces are packed and leave no space behind

Answer:

A...NaS2.............

The strong acid and strong base has high rate constant of dissociation. The rate constant for weak acid and base for the dissociation is low, they do not easily dissociate in water. Therefore, no, acid would not remain acid  if the positions of electrons and protons were swapped.

Acid is a solution which releases H⁺ hydrogen ion when dissolved in water. Base releases hydroxide ion OH⁻ ion when dissolved in water.

pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. Strength of acidic nature is directly proportional to the concentration of hydronium ion.

On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. Temperature affect the pH. At room temperature pH scale is between 0 to 14. 7 is the pH of neutral solution. No, acid would not remain acid  if the positions of electrons and protons were swapped.

Therefore, no, acid would not remain acid  if the positions of electrons and protons were swapped.

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The Avogadro's number is the constant number for the number of atoms or molecules represented in 1 mol, this number is equal to 6.022*10^23, to find out how many molecules there are in 6.0 moles we can set up this equation:

6.0 moles of CH4 * 6.022*10^23 molecules / 1 mol of CH4

The answer will be 3.61*10^24 molecules of CH4

Here's your answer, hope this helps!

Expressing the answer in exponential form we get 3⁴.

To simplify the expression (3⁷/(3³), we can apply the properties of exponents. When dividing two exponential expressions with the same base, we subtract the exponents.

In this case, we have 3⁷ divided by 3³, which can be simplified as:

3⁽⁷⁻³⁾

3⁴

Therefore, the simplified expression is 3⁴.

To understand why we subtract the exponents when dividing, we can break down the steps.

The expression 3⁷ represents 3 multiplied by itself seven times:

3 × 3 × 3 × 3 × 3 × 3 × 3.

The expression 3³ represents 3 multiplied by itself three times:

3 × 3 × 3.

When dividing these two expressions, we can cancel out common factors by subtracting the exponents:

(3 × 3 × 3 × 3 × 3 × 3 × 3) / (3 × 3 × 3)

This simplifies to:

3 × 3 × 3 × 3

Which is equivalent to 3⁴.

Thus, the answer in exponential form is 3⁴

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Hazardous materials are grouped into classes identifying their similarities in composition and structure.

The hazardous materials are grouped into classes in order to tell us about the severity of hazard and it is done on the basis of similarity in composition.

So we can conclude that hazardous materials are grouped into classes identifying their similarities in composition and structure.

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Answer:

sjsjsnsjsksiiw the first the best way I can be used for

Answer:

The valid quantum numbers are l=0, l=-2 and l= 2.

Explanation:

Given that,

n = 3 electron shell

Suppose, the valid quantum numbers are

l = 3

m = 3

l = 0

m = –2

l = –1

m = 2

We know that,

The value of n = 3

Principle quantum number :

Then the principal quantum number is 3. Which is shows the M shell.

So, n = 3

Azimuthal quantum number :

The azimuthal quantum number is l.

\(l=0,1,2\)

Magnetic quantum number :

The magnetic quantum number is

\(m=-2,-1,0,1,2\)

Hence, The valid quantum numbers are l=0, l=-2 and l= 2.

Answer: I = 0  m = -2 m = 2

Explanation: Edge.

the correct answers to the second part of this are:

n = 1, I = 0, m = 0

n = 3, I = 0, m = 0

n = 5, I = 4, m = -3

Answer:

insoluble

Explanation:

The energy can be identified by their features, characteristics and impacts on the surrounding environment.

If the energy release heat then we can say that it is a thermal energy because it warms the environment whereas if the energy produce light then it is called radiant energy.

If the energy is released from splitting atoms or fusion of atoms so we can say that it is a nuclear energy. If the energy is released from breaking of bonds of atoms and molecules, so it is Chemical energy.

So we can conclude that the energy can be identified by their features, characteristics and impacts on the surrounding environment.

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They are known as the s p 3 hybrid orbitals because they are made up of ones atomic orbital and three p atomic orbitals. Aspartic acid's structural formula is C4H7NO4, as shown in the image below:

The concept of hypothetical orbitals mixing to produce new orbitals with the same energy is referred to as hybridization. The orbitals are shown with hybrid orbitals. Only sigma bonding makes use of hybrid orbitals. Hybridization is the process of combining atomic orbitals to create new hybridized orbitals. These recently hybridized orbitals are known as hybrid orbitals. The total number of atomic orbitals fused will always equal the total number of hybrid orbitals. For example, one s atomic orbital and three p atomic orbitals may combine.

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Answer:

Materials that do not let current flow easily are called insulators.

Most nonmetal materials such as plastic, wood and rubber are insulators

Answer:

CH³–C=CH——CH³–CH=CH²

Explanation:

THIS IS PROPYNE TO PROPENE

Answer:

1,2,3,4,8,9,10,12,14,15 and 16

Explanation:

Coz they have different kinds (colours) of atoms

The rest are pure substances,

I'm not so sure though, double check after this

Wascana Chemicals should use emissions reduction technologies to reduce the amount of sulphur dioxide emitted during paint production.

To comply with the Ministry of Environment's directive, Wascana Chemicals, a paint manufacturer, needs to reduce the amount of sulphur dioxide released during paint production. This can be accomplished through the use of emissions reduction technology, such as scrubbers, catalytic converters, or gasification systems.Scrubbers are devices that use a wet process to remove pollutants from gas streams. The gas stream is forced through a scrubbing solution that traps pollutants, including sulphur dioxide.Catalytic converters, on the other hand, use a chemical process to transform pollutants into less harmful substances. Gasification systems convert solid or liquid materials into a gas, which can be combusted to generate energy.

In conclusion, to comply with the Ministry of Environment's emissions reduction regulations, Wascana Chemicals should consider implementing one or more emissions reduction technologies such as scrubbers, catalytic converters, or gasification systems to reduce the amount of sulphur dioxide emitted during paint production.

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