The mole fraction of ar in a mixture of gases is 0. 829 with a partial pressure of 0. 341 atm. What is the total pressure of the sample?.

Answer:

An atom is a complex arrangement of negatively charged electrons arranged in defined shells about a positively charged nucleus. This nucleus contains most of the atom's mass and is composed of protons and neutrons (except for common hydrogen which has only one proton).

Answer:

Atoms consist of an extremely small, positively charged nucleus in which the protons and neutrons can be found, and is surrounded by a cloud of negatively charged electrons.

Answer:

i think I false bro

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The final result is approximately 12.53%, indicating that KNO3 constitutes about 12.53% of the total mass of the solution.

Given:

Mass of K3PO4 = 43 g

Mass of water = 900 g

To calculate the percent by mass of KNO3 in the solution, we need to determine the mass of KNO3 and then divide it by the total mass of the solution, and finally multiply by 100.

First, let's calculate the mass of KNO3:

Molar mass of KNO3 = (39.10 g/mol for K) + (14.01 g/mol for N) + (16.00 g/mol for O) × 3

= 101.10 g/mol

To find the mass of KNO3, we need to convert the mass of K3PO4 to moles and then use the stoichiometric ratio between K3PO4 and KNO3.

Number of moles of K3PO4 = Mass of K3PO4 / Molar mass of K3PO4

= 43 g / 101.10 g/mol

≈ 0.425 moles

Since the stoichiometric ratio between K3PO4 and KNO3 is 1:3 (3 moles of KNO3 are equivalent to 1 mole of K3PO4), the number of moles of KNO3 is three times the number of moles of K3PO4:

Number of moles of KNO3 = 3 × Number of moles of K3PO4

= 3 × 0.425 moles

≈ 1.275 moles

Now, we can calculate the mass of KNO3:

Mass of KNO3 = Number of moles of KNO3 × Molar mass of KNO3

= 1.275 moles × 101.10 g/mol

≈ 128.78 g

Next, we calculate the percent by mass of KNO3:

Percent by mass of KNO3 = (Mass of KNO3 / Total mass of the solution) × 100

Total mass of the solution = Mass of KNO3 + Mass of water

= 128.78 g + 900 g

= 1028.78 g

Percent by mass of KNO3 = (128.78 g / 1028.78 g) × 100

≈ 12.53%

Therefore, the percent by mass of KNO3 in the solution containing 43 g of K3PO4 dissolved in 900 g of water is approximately 12.53%.

Now, let's provide an explanation:

To calculate the percent by mass of KNO3, we need to determine the mass of KNO3 and then divide it by the total mass of the solution (which is the sum of the mass of KNO3 and the mass of water), and finally multiply by 100 to express it as a percentage.

First, we calculate the molar mass of KNO3 by summing up the atomic masses of its constituent elements: potassium (K), nitrogen (N), and oxygen (O). This gives us a molar mass of 101.10 g/mol.

Next, we convert the mass of K3PO4 to moles by dividing it by the molar mass of K3PO4. This gives us the number of moles of K3PO4 present in the solution.

Since the stoichiometric ratio between K3PO4 and KNO3 is 1:3, we can determine the number of moles of KNO3 by multiplying the number of moles of K3PO4 by 3.

Using the number of moles of KNO3, we calculate the mass of KNO3 by multiplying it by the molar mass of KNO3.

To calculate the percent by mass of KNO3, we divide the mass of KNO3 by the total mass of the solution (which is the sum of the mass of KNO3 and the mass of water) and then multiply by 100 to express it as a percentage.

The final result is approximately 12.53%, indicating that KNO3 constitutes about 12.53% of the total mass of the solution.

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The approximate molar mass of the fluorocarbon is 138 g mol⁻¹.

Fluorocarbons are fluorinated carbon chain polymers that might be utilized in an assortment of family and commercial merchandise as waterproofing agents, lubricants, sealants, and leather conditioners.

Fluorocarbon is more abrasion resistant than widespread nylon monofilament of identical diameters. Plus, at the same time as the solar's harsh ultraviolet rays weaken nylon over the years, fluorocarbon shrugs off UV and not using ill-consequences. waterproof unlike mono and a few superlines, fluoro does not take in water.

The molar mass of a chemical compound is defined as the mass of a pattern of that compound divided via the quantity of a substance that's the variety of moles in that sample, measured in moles. The molar mass is a bulk, not molecular, an asset of a substance.

calculation:-

M = d\(\frac{RT}{P}\);   d = m/v

   = (\(\frac{45.60 g}{7.40}\)) (\(\frac{0.082 * 273}{1}\)

    = 138 g mol⁻¹

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The experimental yield of carbon dioxide would be 85% of the amount of calcium carbonate that reacted.

Carbon dioxide (CO2) is a naturally occurring gas composed of one carbon atom and two oxygen atoms. It is the most significant of the greenhouse gases, responsible for about 63% of the total global warming effect. Carbon dioxide is produced by the burning of fossil fuels, through respiration, and is also released during land-use changes such as deforestation. Carbon dioxide is essential to life on earth, as it is a major component of photosynthesis, which helps plants to grow. In the atmosphere, carbon dioxide acts as a blanket that traps infrared radiation, causing the global temperature to rise.

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Explanation:

(1) Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclei. ... (3) Rates of chemical reactions are influenced by temperature and catalysts.

The scientific method is used by biologists and other scientists to pose inquiries about the natural world.

The first step in the scientific method is an observation, which prompts a question from the scientist. They then develop a theory—a verifiable explanation—that responds to the query.

A controlled experiment is a scientific test that is carried out under predetermined circumstances, meaning that only one (or a small number of) variables are altered at a time while all other variables are held constant. The element that differs between the experimental and control groups—in this case, the volume of water—is referred to as the independent variable. The response tested in an experiment to establish if a treatment had an impact is known as the dependent variable.

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The relationship between volume is inversely proportional. This means that when there are an increase in pressure of molecules that are moving, pushes the molecules closer together, reducing the volume. If the pressure is decreased, the gases are free to move about in a larger volume.

You can see in the graph that the behaviour is: the volume is increasing, so this causes that the pressure increase. The answer would be the third one: pressure increases

Answer:

because it showed how the electron could orbit the nucleus without falling into it.

Because NaCl takes more energy to break it's bigger.

For NaCl, the structure or lattice formation enthalpy is -787 kJ mol-1. Therefore, the lattice dissolution enthalpy is always positive and the lattice formation enthalpy is always negative. The reason that NaCl has the highest lattice enthalpy is that for similar anions, cations with smaller radii have higher lattice enthalpies.

If we want to talk about the amount of energy released when a lattice forms from scattered gas ions we should use the lattice formation enthalpy. MgO has a higher lattice energy because each ion carries two unit charges compared to one in NaCl. NaCl is a compound with higher lattice energy. Description Lattice energy is defined as the energy released when the combination of its constituent ions forms one mole of an ionic compound.

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Answer:

Answer:

Mass, m = 19466.7 kg

Explanation:

Given that,

Portland cement concrete (PCC) has a density of 150 lb/ft³

We need to find how many kilograms of PCC are required to cast a cylindrical column 1.15 m in diameter and 7.8 m in height.

Since, 1 kg = 2.205 lb

1 lb/ft³ = 16.018 kg/m³

150 lb/ft³ = 2402.77 kg/m³

Density, \(d=\dfrac{m}{V}\)

m is mass of PCC in kg and V is volume of cylinder

\(m=d\times V\)

\(m=d\times \pi r^2 h\\\\m=2402.77\times \pi \times (1.15/2)^2\times 7.8\\\\m=19466.70\ kg\)

So, the mass of PCC required is 19466.7 kg.

Answer: it is red

Explanation: it is getting hotter

The expression relating the concentration of a gas in \(\mu g/m^-^3 (X)\) with the concentration expressed in ppm (Y) is \(Y = (X/MW) * 10^6 / V\)

To derive an expression relating the concentration of a gas in \(\mu g/m^3 (X)\) with the concentration expressed in ppm (Y), we can use the ideal gas law. The ideal gas law states that \(PV = nRT\), where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Rearranging the equation, we have \(n = PV/RT\)

To convert the concentration from \(\mu g/m^-^3 (X)\) to moles (n), we divide X by the molecular weight (MW) of the gas. Thus, \(n = X/MW\)

Combining the two equations, we have \(X/MW = PV/RT\)

Since the concentration expressed in ppm (Y) is the same as the number of moles per million parts of air, we can write \(Y = n * 10^6 / V\)

Substituting \(n = X/MW\), we get \(Y = (X/MW) * 10^6 / V\)

Therefore, the expression relating the concentration of a gas in \(\mu g/m^3 (X)\) with the concentration expressed in ppm (Y) is:

\(Y = (X/MW) * 10^6 / V\)

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Complete question is:

Using the ideal Gas Law, derive an expression relating the concentration of a gas \(\mu_g^-^3 (X)\) with the concentration expressed in ppm (Y). (10 pts) Hint:- Ideal gas law \(PV= nRt -R = 0.0821 atm mol^-^1\)  −MW=X= molecular weight

The substance is a white solid at room temperature is sodium chlorides

Sodium Chloride is essential to maintain the electrolyte balance of fluids in a person's body. it is also known as salt table.

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At the end of the reaction, 0.5161 mol of aluminum remains in excess.

To determine the excess reactant and the amount remaining at the end of the reaction, we need to calculate the theoretical amount of each reactant required to completely react and compare it to the given amounts.

First, let's calculate the molar mass of each compound:

- Copper (II) chloride (CuCl₂):

 - Copper (Cu) has a molar mass of 63.55 g/mol.

 - Chlorine (Cl) has a molar mass of 35.45 g/mol.

 - Multiply the molar mass of chlorine by 2 since there are two chlorine atoms in the compound:

   - 35.45 g/mol × 2 = 70.90 g/mol.

 - The molar mass of CuCl₂ is:

   - 63.55 g/mol + 70.90 g/mol = 134.45 g/mol.

- Aluminum (Al):

 - Aluminum has a molar mass of 26.98 g/mol.

Next, let's calculate the number of moles for each reactant using the given masses:

- Moles of CuCl₂:

 - Moles = mass / molar mass

 - Moles = 48.42 g / 134.45 g/mol = 0.3600 mol (rounded to four decimal places).

- Moles of Al:

 - Moles = mass / molar mass

 - Moles = 20.40 g / 26.98 g/mol = 0.7561 mol (rounded to four decimal places).

The balanced chemical equation for the reaction is:

2 Al + 3 CuCl₂ → 3 Cu + 2 AlCl₃

According to the stoichiometry, 2 moles of Al react with 3 moles of CuCl₂ to produce 3 moles of Cu. Therefore, the theoretical amount of CuCl₂ required to react with 0.7561 moles of Al is:

0.7561 mol Al × (3 mol CuCl₂ / 2 mol Al) = 1.134 mol CuCl₂

Similarly, the theoretical amount of Al required to react with 0.3600 moles of CuCl₂ is:

0.3600 mol CuCl₂ × (2 mol Al / 3 mol CuCl₂) = 0.2400 mol Al

To find the excess reactant, we compare the actual amounts given with the theoretical amounts calculated above.

Excess reactant:

- CuCl₂:

 - The actual amount of CuCl₂ given is 0.3600 mol, which is equal to the theoretical amount required. Therefore, there is no excess CuCl₂.

- Al:

 - The actual amount of Al given is 0.7561 mol, and the theoretical amount required is 0.2400 mol.

 - Excess moles of Al = actual moles - theoretical moles

 - Excess moles of Al = 0.7561 mol - 0.2400 mol = 0.5161 mol

Therefore, at the end of the reaction, 0.5161 mol of aluminum remains in excess.

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Answer:

Explanation:

The statement "the thermochemical equation represents a physical change" is false.

The given thermochemical equation must represent a chemical change because it involves a change in the chemical composition of the reactants and products. In particular, it describes the condensation of a gas into a liquid, which involves a change in the arrangement of atoms and molecules.

The other statements are true based on the given information:

The pressure for the process is known: This implies that the process is either carried out under constant pressure or the change in volume is negligible.

The internal energy of the surroundings increases: This suggests that the process is endothermic, meaning that energy is absorbed from the surroundings.

The enthalpy change for the gas condensing into a liquid is known: This is implied by the fact that a thermochemical equation is given, which allows us to calculate the enthalpy change for the given reaction.

The enthalpy change is endothermic: This follows from the statement that the internal energy of the surroundings increases, which means that heat is absorbed from the surroundings, making the enthalpy change positive (endothermic).

To find the volume of ethyl alcohol required, we can use the formula:

Volume = Mass / Density

Given that the mass of ethyl alcohol required is 65.3 g and the density of ethyl alcohol is 0.790 g/cm3, we can substitute these values into the formula to find the volume.

Volume = 65.3 g / 0.790 g/cm3

To simplify the units, we can convert the volume from cm3 to mL by using the conversion factor: 1 cm3 = 1 mL.

Volume = (65.3 g / 0.790 g/cm3) * (1 cm3 / 1 mL)

Calculating the expression within the parentheses gives:

Volume = 82.78 cm3 / 1 mL

Therefore, the volume of ethyl alcohol required is 82.78 mL.

Note: It is important to pay attention to the significant figures in the given values and carry them through the calculations to maintain accuracy in the final result.

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The molecular formula of a compound is C₂H₂O₄.

Take 100 grams of compound:

1) ω(C) = 26.7% ÷ 100% = 0.267

m(C) = ω(C) × m(compound)

m(C) = 0.267 × 100 g.

m(C) = 26.7 g.

n(C) = m(C) ÷ M(C).

n(C) = 26.7 g ÷ 12 g/mol.

n(C) = 2.22 mol; amount of carbon

2) ω(H) = 2.2 % ÷ 100% = 0.022

m(H) = 0.022 × 100 g.

m(H) = 2.2 g.

n(H) = 2.2 g ÷ 1 g/mol.

n(H) = 2.2 mol; amount of hydrogen

3) ω(O) = 71.1 % ÷ 100%.

ω(O) = 0.711

m(O) = 0.711 × 100 g

m(O) = 71.1 g

n(O) = 71.1 g ÷ 16 g/mol

n(O) = 4.4 mol; amount of oxygen

4) n(C) : n(H) : n(O) = 2.2 mol : 2.2 mol : 4.4 mol /2.2 mol.

n(C) : n(H) : n(O) = 1 : 1 : 2

M(CHO₂) = 45 amu; empirical formula

90 amu ÷ 45 amu = 2 CHO₂

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J. None of the above.

The total amount of energy in a closed system is conserved, meaning that it cannot be created or destroyed, only transformed from one form to another.

What is Energy?

Energy is a physical quantity that measures the ability of a system to perform work. It is an abstract concept that comes in many forms, such as mechanical, thermal, electrical, chemical, and nuclear energy. Energy can be transferred between different objects or systems, and it can be converted from one form to another.

Option H is an example of how thermal energy moves in a predictable pattern. When water is left on a table at a low temperature for a long period of time, its temperature drops below the freezing point of water, and the water molecules start to form ice crystals. This is an example of a predictable pattern in which thermal energy is transferred from the water to the surrounding air, causing the water to freeze.

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The cork cells are the dead cells and they are present periphery of roots and stems of matured plants. Here a Cork Cell is multicultural.

The organisms which is made up of a single cell is defined as the unicellular organisms whereas the organisms with numerous cells are called multicellular organisms. The bacteria is a unicellular organism and humans are multicellular.

In unicellular organisms a single cell carry the whole functions whereas in multicellular organisms multiple cells perform many functions. The body organization of unicellular organism are simple whereas the multicellular organisms have complex body organization.

Here cork cells are multicellular. A protective coat of a tree seen in outer region is called cork. It prevents water loss through bark. A cork is composed of multiple thick layers.

Thus cork cell is a multicellular cell.

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The pattern of chlorophyll in leaves depends on the exposure to light, with leaves kept in the light having a higher and more uniform chlorophyll content compared to those kept in the dark.

The pattern of chlorophyll in leaves differs significantly when comparing a leaf kept in the dark versus a leaf kept in the light. Chlorophyll is the pigment responsible for the green color in plants and plays a crucial role in the process of photosynthesis. In the presence of light, chlorophyll absorbs energy, allowing plants to convert carbon dioxide and water into glucose and oxygen.
When a leaf is kept in the light, its chlorophyll content is higher as the plant actively engages in photosynthesis. The distribution of chlorophyll in the leaf is typically more uniform, allowing for efficient light absorption and energy conversion.
In contrast, a leaf kept in the dark experiences a decrease in chlorophyll content due to the absence of light. Without light, the plant cannot undergo photosynthesis, leading to a reduced need for chlorophyll. As a result, the pattern of chlorophyll in the darkened leaf becomes less uniform, and the leaf may lose its vibrant green color, becoming pale or even yellow over time. This process is known as etiolation.
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The amount of NaOH that must be added is 1.276 moles.

To calculate the pH of a buffer solution, we can use the Henderson-Hasselbalch formula:

  pH = pKa + log(A⁻ / HA)

The equation for the reaction between NaOH and HC₂H₃O₂ is as follows:

  NaOH (s) + HC₂H₃O₂ (aq) -> Na⁺ (aq) + C₂H₃O₂⁻ (aq) + H₂O (l)

The initial moles of HC₂H₃O₂ is 2.0 M * 1.0 L = 2.0 moles.

Plug the known values into the Henderson-Hasselbalch formula:

  5 = -log (1.76 * 10⁻⁵) + log (NaOH moles / 2.0 - NaOH moles)

  5 = 4.754 + log (NaOH moles / 2.0 - NaOH moles)

0.246 =  log (NaOH moles / 2.0 - NaOH moles)

\(10^{0.246}\) =  log (NaOH moles / 2.0 - NaOH moles)

1.762 =  log (NaOH moles / 2.0 - NaOH moles)

NaOH moles = 1.276.

Your question seems incomplete. The completed version is mostly as follows:

What quantity (moles) of NaOH must be added to 1.0 L of 2.0 M HC2H3O2 to produce a solution buffered at pH = 5?

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Answer: Gamma Rays

Explanation:

The waves with the highest frequency are Gamma Rays. These electromagnetic waves travel at a very high speed. Best of Luck to you!

Answer:

C: The solution has become saturated.

Explanation:

The sugar is not dissolving in the tea because the solution has become saturated. Saturation occurs when the concentration of solute (sugar) in a solvent (tea) has reached its maximum limit, beyond which no more solute can dissolve. At this point, the undissolved solute will settle at the bottom of the container. In this case, the tea is unable to dissolve any more sugar, so it stays at the bottom of the glass.

Answer:

C

Explanation:

1-bromopentane is a primary alkyl halide. In its structure, the bromine atom is attached to a carbon atom that is directly bonded to only one other carbon atom. The correct answer is A. 1-bromopentane.

Alkyl halides, also known as haloalkanes or alkyl halogen compounds, are organic compounds that contain halogen atoms (such as chlorine, bromine, or iodine) bonded to an alkyl group. An alkyl group is a portion of a molecule that consists of carbon and hydrogen atoms, derived from an alkane by removing one hydrogen atom. In alkyl halides, one or more hydrogen atoms in the alkane have been replaced by halogen atoms. Alkyl halides are classified as primary, secondary, or tertiary based on the carbon atom to which the halogen is attached.

Primary alkyl halides are organic compounds in which the halogen atom (such as chlorine, bromine, or iodine) is directly bonded to a primary carbon atom. A primary carbon atom is one that is bonded to only one other carbon atom.

Therefore, the correct answer is A. 1-bromopentane. This carbon atom is considered primary because it is connected to one alkyl group.

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A snip of the complete question is attached with this answer.

Molecular kinetic energy refers to the energy associated with the movement of individual molecules. The phase of a substance depends on the relative magnitudes of the molecular kinetic energy and the energy of intermolecular attractions.

The phase of a substance, whether it is a solid, liquid, or gas, is determined by the balance between two key factors: the molecular kinetic energy and the energy of intermolecular attractions.

In a substance, the higher the molecular kinetic energy, the more likely the molecules are to overcome intermolecular attractions and move freely. This results in a gaseous phase where the molecules are widely spaced and have high mobility.

The phase of a substance is determined by the interplay between molecular kinetic energy, which favors a more dispersed phase, and the energy of intermolecular attractions, which promotes a closer arrangement of molecules. The relative magnitudes of these two factors dictate whether a substance exists as a solid, liquid, or gas.

Therefore, the phase of a substance depends on the relative magnitudes of the molecular kinetic energy and the energy of intermolecular attractions.

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Answer:

There are seven (7).

Explanation:

Since 5 digits are not zero and they're before the zero, they're automatically sig figs.

Since there's a sig fig (#4) after the zero, zero and the # 4  are also sig figs.

Added together, they're are seven

To prepare two test solutions, you will have to add approximately 5 ml of deionized water to each of the test tubes. Then, add around 10 drops of the indicator solution to each test tube, each with a slightly different color depending on the type of indicator used. To save one of the test solutions as a reference, simply set aside one of the test tubes without adding anything else to it.

1. Obtain two clean test tubes.
2. Measure approximately 5 ml of deionized water and pour it into each test tube.
3. Add around 10 drops of indicator solution to each test tube containing deionized water.
4. Gently mix the contents of each test tube.
5. Save one test tube as a reference, meaning you will not perform any further tests or changes to this tube. This reference will help you compare the color changes in your experiments.
6. Observe and note the color of the solution in each test tube, which should be the same at this point.

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