The mass of chemical A is 2 g, and the mass of chemical B is 5 g. If the two chemicals are mixed and a chemical reaction takes place, what is the mass of the end products?\

The potency of acetylcholine after replacing the acetyl group with propionyl or butyrly group decreases.

Its is a organic chemical that function in the brain and body fofmany types of animal ,and humans also as neurotransmitter.

It act as a messenger , that plays a very important role in the central and peripheral nervous system.

The acetylcholine is important for autonomic body functions, muscle control and memory , learning and attention.

Lack of acetycholine cause no contraction in muscles.

Excess of acetylcholine causes cramps , muscular weakness blurry vision, diarrhea etc.

Propionyl or butyryl  is higher homologus group than acetyl , this is the reason the potency will decreases or reduces its activity.

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Answer:

secondary because the don't only eat plant and can be eaten

The balanced half-reactions for the electrodes on the left and right are

Ni(s) → Ni²⁺(aq) 2 e⁻ . (left) anode

Cu²⁺(aq) + 2 e⁻ → Cu(s) ( right) cathode

The overall reaction is given as :Ni(s) + Cu²⁺(aq) → Ni²⁺(aq) + Cu(s)

A voltaic cell is constructed with a Cu/Cu²⁺ half-cell and an Ni/Ni²⁺ half-cell. The nickel electrode is negative (anode) and the copper electrode is positive (cathode). In the anode takes place the oxidation and in the cathode takes place the reduction. The corresponding half-reactions are:

Anode (oxidation): Ni(s) → Ni²⁺(aq) 2 e⁻

Cathode (reduction): Cu²⁺(aq) + 2 e⁻ → Cu(s)

The overall  reaction is:

Ni(s) + Cu²⁺(aq) → Ni²⁺(aq) + Cu(s)

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The complete question is

A voltaic cell is constructed with a Cu/Cu2 half-cell and an Ni/Ni2 half-cell. what are the balanced half-reactions for the electrodes on the left and right? be sure to include states of matter.

Answer:

Addition

Explanation:edg 2020

Answer:

The correct answer is A.

Explanation:

Edge 2022

Answer:

The type of Chemistry that studies the chemical reactions that occur in the human body, is Biochemistry.

Explanation:

That is true ofcourse so yes

Answer:

sodium bicarbonate, potassium bicarbonate and ammonium bicarbonate are the most commonly used bases.

When the mixture of H₂O₂ and Fe(NO₃)₃ is bubbled, the reaction produces oxygen gas due to the oxidation of Fe(NO₃)₃.

Oxidation is a chemical reaction that involves the transfer of electrons from one molecule to another. It is essentially a reaction between an electron-donating molecule, known as the oxidant, and an electron-accepting molecule, known as the reductant. During an oxidation reaction, the oxidant gains electrons from the reductant, while the reductant loses electrons to the oxidant.

This can be seen by the bubbles rising from the tube. When the bubbling ceases, the reaction is complete and the Fe(NO₃)₃ has been completely oxidized. Adding an extra 3 mL of H₂O₂ to the test tube initiates the reaction again, showing that the Fe(NO₃)₃ is acting as a catalyst, speeding up the reaction but not being consumed in the process. This indicates that Fe(NO₃)₃ is playing the role of a catalyst in the reaction.

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Answer:

2-Methyl-5-nitrothiophene  

Explanation:

The 2- and 5-positions of thiophene are the most susceptible to electrophilic aromatic substitution.

Thus, the major product from the reaction of 2-methylthiophene with HNO₃ in acetic acid is 2-methyl-5-nitrothiophene.

Isomers are compounds that have the same molecular formula, meaning they contain the same types and numbers of atoms but differ in their structural arrangement or spatial orientation.

The five possible isomers corresponding to the formula C7H16, along with their names:

1.  Heptane:

    CH3-CH2-CH2-CH2-CH2-CH2-CH3

2. 2-Methylhexane:

    CH3-CH2-CH(CH3)-CH2-CH2-CH3

3. 3-Methylhexane:

    CH3-CH2-CH2-CH(CH3)-CH2-CH3

4. 2,2-Dimethylpentane:

    CH3-C(CH3)2-CH2-CH2-CH3

5. 2,3-Dimethylpentane:

    CH3-CH(CH3)-CH(CH3)-CH2-CH3

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Phenolphthalein indicator turns blue in basic solutions. The given statement is false because it is commonly used to determine the pH of a solution

Phenolphthalein indicator is a chemical compound commonly used to determine the pH of a solution. It is colorless in acidic solutions (pH below 7) and turns pink or magenta in basic or alkaline solutions (pH above 7). It does not turn blue in basic solutions. Phenolphthalein's color change occurs over a narrow pH range, typically between pH 8.2 and 10.0, making it an effective indicator for titrations involving weak acids and strong bases.

There are other indicators, such as bromothymol blue or litmus paper, that change color at different pH levels, and they can be blue under specific pH conditions. However, phenolphthalein remains one of the most widely used indicators for acid-base titrations due to its distinct color change and suitability for various applications. In summary, phenolphthalein indicator turns blue in basic solutions. The given statement is false because it is commonly used to determine the pH of a solution

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The correct statement is "the lower the activation energy, the faster the reaction rate".

Activation energy is the minimum amount of energy required for a chemical reaction to occur. A lower activation energy means that fewer reactant molecules need to overcome the energy barrier to form products, leading to a faster reaction rate.

This is because a lower activation energy allows a larger fraction of molecules to possess the required energy, increasing the likelihood of successful collisions and product formation.

In contrast, a higher activation energy necessitates a greater amount of energy for the reaction to proceed, reducing the number of molecules capable of crossing the energy barrier and thus slowing down the reaction rate. Therefore, the correct statement is "the lower the activation energy, the faster the reaction rate".

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The sample density is 690 kg/m³.

We need to know about the density to solve this problem. Density is a unit that measures how dense an object is. Density can be measured by dividing mass by volume. It can be written as

ρ = m / V

where ρ is density, m is mass and V is volume

From the question above, we know that

m = 1.20 gram

V = 1.73 cm³

By substituting the following parameters, we get

ρ = m / V

ρ = 1.2 / 1.73

ρ = 0.69 g/cm³

Convert to SI unit (kg/m³)

ρ = 0.69 g/cm³

ρ = 0.69 x 10¯³ kg/ 10¯⁶ m³

ρ = 690 kg/m³

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Answer:

IONIC BOND

Explanation:

the force between oppositely charged IONS is and IONIC BOND

The mass of fe2(so4)3 that is required to produce 1.15 mol fe3 is 230 gm.

The molar mass of a chemical compound is described as the mass of a sample of that compound divided by using the amount of substance that is the wide variety of moles in that pattern, measured in moles. The molar mass is a bulk, no longer molecular, an asset of a substance.

The molar mass of a substance is the mass in grams of one mole of the substance. As shown in this video, we are able to attain a substance's molar mass by summing the molar hundreds of its thing atoms. we will then use the calculated molar mass to convert among mass and variety of moles of the substance.

Calculation:-

Fe₂(SO₄)₃ -------> 2Fe₂⁺³ + 3SO₄⁻²

2 mole Fe⁺³ produced by  1 mole fe2(so4)3

1.15 mol Fe⁺³ produced by = 1/2 × 1.15

                                             = 0.575 mol

molar mass of fe2(so4)3 = 400 g

mass of 0.75 moles of  fe2(so4)3 is = 400 ×  0.575

                                                            = 230 gm

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Answer:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles N2, or 28.0134 grams.

Explanation:

:)

Answer:

1.92

Explanation:

Potassium-41 has 22 neutrons, which is the same number of neutrons as argon-40. Thus, the statement is true.

Both potassium-39 and argon-40 have 20 neutrons. Isotopes are elements that have the same number of protons but different numbers of neutrons. Since the isotope of potassium in the question has the same number of neutrons as argon-40, it means that they have the same atomic mass number. This phenomenon is due to the fact that argon-40 is formed from the radioactive decay of potassium-40, which has 21 neutrons. Therefore, the correct answer to the question is true.
The statement "An isotope of potassium has the same number of neutrons as argon-40" is True (a).

Potassium and argon are two different elements, but isotopes of these elements can have the same number of neutrons. To determine this, we need to look at the isotope of potassium that has the same number of neutrons as argon-40.

Argon-40 is an isotope of argon, which has an atomic number of 18. The atomic mass number of argon-40 is 40, so it has 22 neutrons (40 - 18 = 22).

Potassium has an atomic number of 19, meaning it has 19 protons. To find an isotope of potassium with the same number of neutrons as argon-40, we need to find a potassium isotope with an atomic mass number that results in 22 neutrons.

Potassium-41 is an isotope of potassium with an atomic mass number of 41. To find the number of neutrons in potassium-41, subtract the atomic number (protons) from the atomic mass number:

41 - 19 = 22

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A) The pH of a 0.75 M acetic acid solution, CH3COOH, Ka = 1.8 x 10⁻⁵: The pH is 2.92.

B) The calculated pH of a 0.75 M diethylamine solution, (CH3CH2)2NH, Kb = 7.1 x 10⁻⁴: The pH is 13.71

C) The hydronium ion concentrations can be represented as [H3O+]. the ratio of the hydronium ion concentrations in each solution is 1.59 x 10⁻¹¹.

A) The pH of a 0.75 M acetic acid solution, CH3COOH, Ka = 1.8 x 10⁻⁵: Firstly, we have the formula for Ka:

Ka = ([H3O+][CH3COO-]) / [CH3COOH]

We need to calculate [H3O+] and [CH3COO-].

Let us represent [H3O+] as x and [CH3COO-] as y.

Let [CH3COOH] be

0.75-x: [H3O+][CH3COO-] / [CH3COOH] = 1.8 x 10⁻⁵x

y / (0.75-x) = 1.8 x 10⁻⁵

x = [H3O+]

pH = - log[H3O+]

pH = - log (1.21 x 10⁻³)

The pH is 2.92.

B) The calculated pH of a 0.75 M diethylamine solution, (CH3CH2)2NH, Kb = 7.1 x 10⁻⁴:Given that Kb = 7.1 x 10⁻⁴.We know that

pKb + pKa = pKw (at 25°C)

Now, we have pKa, which is equal to -log Ka. Let us calculate pKa:

pKa = - log(1.8 x 10⁻⁵)

pKa = 4.74

pKw = 14

pKb = pKw - pKa = 14 - 4.74 = 9.26

Let us now use the formula for Kb:

Kb = [BH⁺][OH⁻] / [B]

Kb = [CH3CH2NH3⁺][OH⁻] / [CH3CH2NH2]

Let us represent [CH3CH2NH3⁺] as x and [OH⁻] as y.

Let [CH3CH2NH2] be 0.75-x.

Therefore, we have:

[CH3CH2NH3⁺][OH⁻] / [CH3CH2NH2] = 7.1 x 10⁻⁴x

y / (0.75-x) = 7.1 x 10⁻⁴

y = [OH⁻]

pOH = -log [OH⁻]

pOH = -log (3.53 x 10⁻³)

The pOH is 2.45.Using the formula

pH + pOH = pKw:

2.92 + 2.45 = 14 - pH + pOH2.

92 + 2.45 = 14 - pH + 11.559.37 - 11.55 = pH

pH = - log(1.93 x 10⁻¹⁴)

The pH is 13.71

C) The hydronium ion concentrations can be represented as [H3O+]. In a 0.75 M acetic acid solution:

[H3O+] = 1.21 x 10⁻³

In a 0.75 M diethylamine solution:

[H3O+] = 1.93 x 10⁻¹⁴

The ratio of the hydronium ion concentrations in each solution is:

1.93 x 10⁻¹⁴ / 1.21 x 10⁻³ = 1.59 x 10⁻¹¹.

Therefore, the ratio of the hydronium ion concentrations in each solution is 1.59 x 10⁻¹¹.

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For a reaction to be spontaneous, the change in enthalpy (ΔH) should be negative (exothermic), and the change in entropy (ΔS) should be positive (increase in disorder). The Gibbs free energy (ΔG) can be used to determine the spontaneity, where a negative value of ΔG indicates a spontaneous reaction.

The change in enthalpy (ΔH) and change in entropy (ΔS) values provide important information about the spontaneity of a reaction. For a reaction to be spontaneous, it should have a negative ΔH (exothermic) and a positive ΔS (increase in disorder).

1. If ΔH is negative, it means that the reaction releases energy in the form of heat. This is favorable for a spontaneous reaction because it indicates that the products are more stable than the reactants.

2. If ΔS is positive, it implies an increase in the randomness or disorder of the system. This increase in entropy favors the spontaneity of a reaction since nature tends to move towards higher entropy states.

3. To determine whether a reaction is spontaneous, we can use Gibbs free energy (ΔG). The relationship between ΔH, ΔS, and ΔG is given by the equation: ΔG = ΔH - TΔS, where T represents temperature. If ΔG is negative, the reaction is spontaneous.

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Answer:

answer three

Explanation:

Cu0 is a compound

The mass of sulfurous acid produced when 245g of sulfur dioxide is reacted with water is 313.8 g

From the question, we are to determine the mass of sulfurous acid produced

First, we will write the balaced chemical equation for the reaction

H₂O + SO₂ → H₂SO₃

This means 1 mole of H₂O reacts with 1 mole of sulfur dioxide (SO₂) to produce 1 mole of sulfurous acid (H₂SO₃)

Now, we will determine the number of moles of sulfur dioxide present

Mass of sulfur dioxide present = 245 g

Molar mass of sulfur dioxide = 64.066 g/mol

Using the formula,

\(Number \ of \ moles = \frac{Mass}{Molar\ mass}\)

Then,

Number of moles of SO₂ present = \(\frac{245}{64.066}\)

Number of moles of SO₂ present = 3.824 moles

This is the number of moles of SO₂ present

From balanced chemical equation

1 mole of H₂O reacts with 1 mole of sulfur dioxide (SO₂) to produce 1 mole of sulfurous acid (H₂SO₃)

Then,

Water (H₂O) will react with the 3.824 moles of sulfur dioxide (SO₂) to produce 3.824 moles of sulfurous acid (H₂SO₃)

∴ The number of moles of sulfurous acid produced is 3.824 moles

Now, for the mass of sulfurous acid produced

Molar mass of sulfurous acid = 82.07 g/mole

Using the formula,

Mass = Number of moles × Molar mass

Mass of sulfurous acid produced = 3.824 × 82.07

Mass of sulfurous acid produced = 313.8 g

Hence, the mass of sulfurous acid produced is 313.8 g

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Answer:

Closed-toe shoes, long pants, a lab coat, safety glasses with side shields or splash goggles, and gloves.

Explanation:

Answer:

A

Explanation:

the type of soil the tulips receive_ with or without fertilizers

Answer:

-2820 kJ

Explanation:

Just got it right on Ap3x :)

Check your question and verify that it says "multiply" and not "reverse", this is the only page that has the answer for that one.

If you have "reverse" there is another guy who asked the question, is easy to find.

Considering the definition of extensive properties and heat of reaction, the enthalpy of reaction for the intermediate reaction is -2820 kJ (option C.).

Extensive properties of matter are defined as those that depend on the amount of material in a body.

The greater the mass or the larger the body or system, the greater the proportion of that property. This means that extensive properties are not fixed, they vary according to the amount of matter.

Also, extensive properties are additive, meaning they can be added together.

The heat of reaction is the energy that is released or absorbed when chemicals are changed in a chemical reaction.

Enthalpy is an extensive property: its magnitude depends on the amount of matter present.

Since enthalpy is an extensive property, if you need to multiply the following reaction by 2 to be an intermediate reaction in a Hess's law problem, the variation of enthalpy also is pultiplied by 2.

Then, ΔH= 2×( -1410 kJ)

ΔH= -2820 kJ

Finally, the enthalpy of reaction for the intermediate reaction is -2820 kJ (option C.).

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According to the solving the density of the marble is:

D = 2.5 g/cm^3

The amount of mass that a substance has per unit volume is known as its density. If two materials occupy the same volume, the one with a higher density would weigh more than the one with a lower density.

Utilizing the density formula is another approach to determining an object's weight-to-volume ratio. Since you only need to perform one operation to find it, the computation is not too difficult.

The density formula is as follows:

D = m / v,

where:

D - density;

m - mass; and

v - volume.

m - 5grams

v - 2cm

D -

Putting the value in the formula we get:

D = 5/ 2,

D = 2.5 g/cm^3

According to the solving the density of the marble is:

D = 2.5 g/cm^3

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Octopus and squids breathe like fishes they breathe from gills

so even octopus and squids breathe through gills too.

maybe this answer would help u

The diffusion coefficient is 4.39x10-12 m2/s.

Given information;

Initial nitrogen concentration, c₀ = 0.08 wt %

Nitrogen concentration to be achieved, cₙ = 0.52 wt %

Diffusion coefficient, D = 9.10E-05 m²/s

Temperature, T = 1100 K

Activation energy, Qd = 168 kJ/mol

Gas constant, R = 8.31 J/mol K

To find;

Diffusion coefficient at 1100 K using Arrhenius equation;

The Arrhenius equation for diffusion coefficient is given as;

D = D₀ exp(-Qd / R T)

where; D₀ is the diffusion coefficient at an infinite temperature.

Substituting the given values of D, Qd, R, and T into the equation above;

D = 9.10E-05 m²/s

Qd = 168 kJ/mol

R = 8.31 J/mol

KT = 1100 K

At 1100 K, the value of kT is;

kT = R T

     = 8.31 J/mol K x 1100 K

     = 9141 J/mol

Multiplying by Avogadro's number to get the value in J;

9141 J/mol x (6.022 x 10²³) / (1 mol) = 5.50 x 10²⁹ J-1

                                                          = 5.50 x 10²⁹ m²/kg

Multiplying by the Boltzmann constant to get the value in m²/s;

K = 1.38 x 10⁻²³ J/KD₀ can now be obtained by rearranging the Arrhenius equation as;

D₀ = D / exp(-Qd / R T)

Substituting the values into the equation;

D₀ = 9.10E-05 m²/s / exp(-168 x 10³ J/mol / 8.31 J/mol K x 1100 K)D₀

     = 9.10E-05 m²/s / exp(-21.36)D₀

     = 9.10E-05 m²/s / 1.29E-09D₀

     = 7.05E-04 m²/s

Therefore, the diffusion coefficient at 1,100 K if k = 8.31 is;

D = D₀ exp(-Qd / R T)D

   = 7.05E-04 m²/s exp(-Qd / R T)D

   = 7.05E-04 m²/s exp(-168 x 10³ J/mol / 8.31 J/mol K x 1100 K)

D = 7.05E-04 m²/s exp(-21.36)D

   = 4.39 x 10⁻¹² m²/s

Therefore, the correct option is 4.39x10-12 m2/s.

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