The mass of a string is 7.7 × 10-3 kg, and it is stretched so that the tension in it is 190 N. A transverse wave traveling on this string has a frequency of 300 Hz and a wavelength of 0.80 m. What is the length of the string?

Answer:

Well velocity is the varaible with direction

Explanation:

Answer:

North east

Explanation:

r_1 = 100 i

r_2 = 200 (cos60i + sin60j) = 100i + 173.2j

By vector addition

r = r_1 + r_2 = 200i + 173.2j

Distance (Or magnitude) = sqrt(200^2 + 173.2^2) = 264 km

Direction from the starting point is  north of east.

Answer:

- 670 kg.m/s

Explanation:

Newton's third law states that to every action, there is equal and opposite reaction force. Since the force will be same but different in direction and acted in the same time then the impulses ( force multiply by time) of the two car be same in magnitude but different in direction - 670 kg.m/s

Answer:

1.267 nanometers.

Explanation:

From the question,

Speed = distance/time.

S = d/t.................. Equation 1

Make d the subject of the equation,

d = S×t ............................... Equation 2

Given: S = 4.0 cm/year, t = 1 seconds = 3.17×10⁻⁸ years

Substitute into equation 2

d = 4×3.17×10⁻⁸ =

12.68×10⁻⁸ cm = 12.67×10⁻⁸×10⁷

d = 1.267 nanometers.

Hence the Tectonic plates move 1.267 nanometers.

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.

It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.

This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.

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The magnitude of the forces acting at the top are;

\(\mathbf{F_{Top, \ x}}\) = 132.95 N

\(\mathbf{F_{Top, \ y}}\) = 0

The magnitude of the forces acting at the bottom are;

\(\mathbf{F_{Bottom, \ x}}\) = \(\mathbf{ F_f}\) = -132.95 N

\(\mathbf{F_{Bottom, \ y}}\) = 784.8 N

The known parameters in the question are;

The mass of the person, m₁ = 70.0 kg

The length of the ladder, l = 6.00 m

The mass of the ladder, m₂ = 10.0 kg

The distance of the base of the ladder from the house, d = 2.00 m

The point on the roof the ladder rests = A frictionless plastic rain gutter

The location of the center of mass of the ladder, C.M. = 2 m from the bottom of the ladder

The location of the point the person is standing = 3 meters from the bottom

g = The acceleration due to gravity ≈ 9.81 m/s²

The required parameters are;

The magnitudes of the forces on the ladder at the top and bottom

The strategy to be used;

Find the angle of inclination of the ladder, θ

At equilibrium, the sum of the moments about a point is zero

The angle of inclination of the ladder, θ = arccos(2/6) ≈ 70.53 °C

Taking moment about the point of contact of the ladder with the ground, B gives;

\(\sum M_B\) = 0

Therefore;

\(\sum M_{BCW}\) = \(\sum M_{BCCW}\)

Where;

\(\sum M_{BCW}\) = The sum of clockwise moments about B

\(\sum M_{BCCW}\) = The sum of counterclockwise moments about B

Therefore, we have;

\(\sum M_{BCW}\) = 2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81

\(\sum M_{BCCW}\) = \(F_R\) × √(6² - 2²)

Therefore, we get;

2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81  = \(F_R\) × √(6² - 2²)

\(F_R\)  = (2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81)/(√(6² - 2²)) ≈ 132.95

The reaction force on the wall, \(F_R\) ≈ 132.95 N

We note that the magnitude of the reaction force at the roof, \(F_R\) = The magnitude of the frictional force of bottom of the ladder on the floor, \(F_f\) but opposite in direction

Therefore;

\(F_R\) = \(-F_f\)

\(F_f\) = - \(F_R\) ≈ -132.95 N

Similarly, at equilibrium, we have;

∑Fₓ = \(\sum F_y\) = 0

The vertical component of the forces acting on the ladder are, (taking forces acting upward as positive;

\(\sum F_y\) = -70.0 × 9.81 - 10 × 9.81 + \(F_{By}\)

∴ The upward force acting at the bottom, \(F_{By}\) = 784.8 N

Therefore;

The magnitudes of the forces at the ladder top and bottom are;

At the top;

\(\mathbf{F_{Top, \ x}}\) = \(F_R\) ≈ 132.95 N←

\(\mathbf{F_{Top, \ y}}\) = 0 (The surface upon which the ladder rest at the top is frictionless)

At the bottom;

\(\mathbf{F_{Bottom, \ x}}\) = \(F_f\) ≈ -132.95 N →

\(\mathbf{F_{Bottom, \ y}}\) = \(F_{By}\) = 784.8 N ↑

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Answer:

i think b

Explanation:

The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.

Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.

Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.

Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.

We can use the formula for fringe width in Young's double-slit experiment:

w = (λ * D) / d

Where:

w is the fringe width,

λ is the wavelength of light,

D is the distance between the screen and the double slits, and

d is the distance between the two slits.

Let's calculate the value of D/d using the given information:

D/d = w / λ

= 0.006 m / 4500 Å (1 m = 10^10 Å)

= 0.006 * 10^10 / 4500 m^-1

Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:

(D'/d) = (0.006/2) * 10^10 / 4500 m^-1

Now, we can rearrange the equation to solve for the new wavelength (λ'):

(λ' * D') / d = (D/d)

λ' = (D/d) * d / D

= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å

= 0.0045 m * 10^10 / 2 Å

= \(0.00225 * 10^{10\) Å

=\(2.25 * 10^7\)Å

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Answer:

D

Explanation:

because if the solvent is more than the solvent then we can't resolve it.

so our product will be suspended

Because of location, the Hartsfield Jackson international airport has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport.

It should be noted that transportation simply means the movement of people and animals from one location to another. It should be noted that there are different means of transportation such as rail, air, road, etc.

In this case, because of location, the Hartsfield Jackson international airport has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport. This is located in Atlanta Georgia.

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Select the correct answer from each drop-down menu. Because of location, the has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport.

a. Dallas International Airport.

b. Denver International Airport.

c. John Kennedy International Airport

d. Hartsfield Jackson international airport

Nuclear fusion reaction is mainly responsible for the cause of energy radiation from the sun.

Solar energy is created due to this nuclear fusion. The discharge of energy in the sun is 10²⁶ joules per second

There is nuclear fusion of hydrogen into helium molecules.

Takes place in solar nucleus/plasma, because this reaction can occur only in high temperature.

The special type of fusion that take place in sun is proton-proton fusion.

This kind of fusion is responsible for the cause of energy radiance and is a very efficient method of producing energy.

The 2 condition which help H-H atoms come together is large mass of the sun and the force of gravity.

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Sarah’s velocity immediately after the collision is 4.3 m/s west.

option C is the correct answer.

Sarah’s velocity immediately after the collision is calculated by applying the principle of conservation of linear momentum as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

Sarah’s velocity immediately after the collision is calculated as;

179 (1.6) + 163(3.9) = 179v₁ + 163(0.9)

922.1 = 179v₁ + 146.7

179v₁ = 775.4

v₁ = 4.3 m/s

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The primary means by which heat is transferred through fluids is convection currents (option D).

Convection is the transmission of heat in a fluid by the circulation of currents.

Heat can be transferred by different methods depending on the medium. Fluids like gases and liquids transfer heat through the process of convection.

Therefore, the primary means by which heat is transferred through fluids is convection currents.

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Answer:

D) Lifting it to a high shelf

Explanation:

Potential energy is where energy could be released at any moment. For example, if a cat gets on a tree it's creating potential energy, once that cat jumps from the tree the energy releases. D is the answers because if you set the book in a high shelf, you are only creating more potential energy.

hope I explain my self well enough

cheers man and good luck

Answer:

1.25cm

Explanation:

Using

Minimum, as dsinစ = (m+1/2) lambda

Third dark fringe m= 2

dsinစ = (2+1/2)lambda

d(y/L)= (5/2) lambda

Y= 5/2* lambda *L/d

So substituting

=[ (500E-9m)(5m)/0.5E-3] 5/2

=0.0125m

= 1.25cm

Explanation:

Answer:

1 436 000 000 hrs     163 814 .7 years

Explanation:

40208000000000 km  / 28000 km/hr  =

The Space shuttle's speed is 28,000 km/hr, and the time it will take to get you there is 1436000000 hours or 163814.7 years.

Although Proxima Centauri cannot be seen normally with eyes, it is one of the most famous stars in the sky. This is because it is a member of the Alpha Centauri star system, which is the nearest stellar system to our sun and is home to three known stars.

Proxima, with a distance of 4.22 light-years from our sun, is thought to be the star in Alpha Centauri that is nearest to our sun of the three. For Proxima, astronomers have so far found two planets. It also produces large solar flares, and a strange radio signal may come from it.

According to the question :

The given distance is 4.3 light-years or,

Distance = 40,208,000,000,000 km

Given speed is 28,000 km/hr.

So the time it will take to get you up there is:  Distance/speed

Time = 40,208,000,000,000 km/28,000 km/hr

Time = 1436000000 hours or,

Time = 163814.7 years

Hence, the time taken to get you there will be 163814.7 years.

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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Work = (force) x (distance)

Your force was not enough to move the building, so the distance is zero.

Work = (your force) x (zero)

Work = zero

1.47  is the coefficient of static friction between a mass of 0.75kg and a horizontal surface

m=0.75 KG

g=9.8 M/S^2

N=5 N

F=µN

µ=F/N

µ=mg/N

µ=0.75×9.8÷5

µ=1.47

We are physically surrounded with friction. An object moving along a path is resisted by a force known as static friction. Lastly, use an easy example to comprehend it. Think about the activity we perform frequently called walking. We are constantly in contact with the floor while we work. Motion presses against the ground as we move it backward, and we then advance our feet.

One key concept to be aware of in order to minimize friction is the fact that it operates in the opposite direction from relative motion. This phenomena may be useful for reducing the speed of the action until it eventually comes to a stop.

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Answer:

T = 480.2N

Explanation:

In order to find the required force, you take into account that the sum of forces must be equal to zero if the object has a constant speed.

The forces on the boxes are:

\(T-Mg=0\)      (1)

T: tension of the rope

M: mass of the boxes 0= 49kg

g: gravitational acceleration = 9.8m/s^2

The pulley is frictionless, then, you can assume that the tension of the rope T, is equal to the force that the woman makes.

By using the equation (1) you obtain:

\(T=Mg=(49kg)(9.8m/s^2)=480.2N\)

The woman needs to pull the rope at 480.2N

The bug will cross the sticky region once in each cycle of its motion, where a cycle is defined as one complete round trip from the top of the bowl to the bottom and back to the top.

To find the number of cycles the bug goes through, we can use conservation of mechanical energy. At the top of the bowl, the bug has only potential energy, which is converted to kinetic energy as it slides down the bowl. At the bottom of the bowl, all of the potential energy has been converted to kinetic energy, and as the bug slides up the other side of the bowl, the kinetic energy is converted back into potential energy. At the top of the bowl again, the bug has only potential energy, and the cycle repeats.

Because there is no friction (except for the sticky patch), the total mechanical energy of the system is conserved. Therefore, the potential energy at the top of the bowl is equal to the potential energy at the bottom of the bowl, and the kinetic energy at the bottom of the bowl is equal to the kinetic energy at the top of the bowl.

We can set the potential energy at the top of the bowl to zero, and use the conservation of energy to find the potential energy at the bottom of the bowl:

mgh = (1/2)mv^2

where m is the mass of the bug, g is the acceleration due to gravity, h is the depth of the bowl, and v is the speed of the bug at the bottom of the bowl.

Solving for v, we get:

v = sqrt(2gh)

Plugging in the numbers, we get:

v = sqrt(29.810.12) = 0.775 m/s

The time it takes for the bug to slide from the top of the bowl to the bottom and back up to the top is twice the time it takes to slide from the top to the bottom:

t = 2sqrt(2h/g) = 2sqrt(2*0.12/9.81) = 0.774 s

Therefore, the frequency of the bug's motion is:

f = 1/t = 1/0.774 = 1.29 Hz

Since the bug completes one cycle in each oscillation, the bug will cross the sticky region 1.29 times per second, or approximately once every 0.78 seconds.

According to the question the deceleration speed is 0.15 radians/second^2.

Speed is a measure of how quickly an object moves from one place to another. It is usually measured in units of distance per unit of time, such as miles per hour or meters per second. Speed is a scalar quantity—it has magnitude only, and does not have direction. Speed is often confused with velocity, which is a vector quantity that includes both speed and direction. Speed is an important concept in physics, as it is related to energy, momentum, and acceleration.

The deceleration speed is 0.15 radians/second^2. This is calculated by using the equation for angular acceleration, which is: a = (ωf-ωi)/t, where ωf is the final angular speed, ωi is the initial angular speed, and t is the time it takes to decelerate. In this case, ωf=0, ωi=2π/4.5, and t=30s, resulting in a=0.15 radians/second^2.

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The average speed of the whole journey is 54 mph.

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Answer:

Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice

Explanation:

Answer:

61 m/s

Explanation:

        \(v_{f}^{2} - v_{o}^ {2} = 2* g* h (1)\)

Determine the magnitude of B-A is 53.68

1.4

Magnitude is a term used to describe size or distance. We can relate the magnitude of the movement to the size and movement speed of the object. The magnitude of a thing or an amount is its size. A car moves at a faster pace than a motorcycle, just in terms of speed.

Magnitude is the relative size of an object (mathematics). The mathematical term for a vector's length or size is the norm. By using the symbol |v|, the magnitude of a vector formula can be utilized to determine the length of a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point.

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