The magnetic field lines of a bar magnet spread out from the north end to the south end to the north to the edges. This is because a bar magnet has two poles; the north and south poles. Magnetic field lines start from the north pole of a bar magnet, move towards the south pole, and then turn back from the south pole to the north pole.
Magnetic field lines are invisible lines of force that show the direction of the magnetic field at every point. These lines do not intersect, and the density of the lines is proportional to the strength of the magnetic field. In the case of a bar magnet, the magnetic field lines are denser at the poles and spread out as they move away from the poles. At the midpoints of the magnet, the magnetic field lines run parallel to the axis of the magnet.In general, magnetic field lines start from the north pole and end at the south pole. Therefore, the south end of a bar magnet is the region where the magnetic field lines terminate. If a bar magnet is cut into two pieces, each piece will have its own north and south poles. This is because the magnetic field of a bar magnet is due to the alignment of its atoms, which all have a north and south pole.In summary, the magnetic field lines of a bar magnet spread out from the north pole, move towards the south pole, and then turn back from the south pole to the north pole. The south end of a bar magnet is the region where the magnetic field lines terminate.
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Answer:
north end to the south end.
Explanation:
This person above me is wrong and did it edge
There is evidence that a supermassive black hole is at the center of the milky way based upon:________
There is evidence that a supermassive black hole is at the center of the Milky Way based on several observations and studies.
Some of the key pieces of evidence include:
1. Stellar Orbits: Astronomers have observed the orbits of stars near the center of the Milky Way. These stars exhibit high speeds and tight orbital patterns, indicating the presence of a massive object with strong gravitational influence. By analyzing these stellar orbits, scientists have deduced the presence of a supermassive black hole.
2. Radio Source Sagittarius A*: In the constellation Sagittarius, there is a strong radio source known as Sagittarius A*. Detailed observations of this source have revealed it to be an extremely compact and highly energetic region. Based on its characteristics, scientists believe that Sagittarius A* is a supermassive black hole at the center of our galaxy.
3. X-ray and Infrared Emissions: Observations in X-ray and infrared wavelengths have detected intense emissions coming from the center of the Milky Way. These emissions are consistent with the behavior of matter being heated and accelerated as it falls into a supermassive black hole.
4. Gas and Dust Dynamics: Studies of gas and dust clouds near the galactic center have shown significant disturbances and high velocities. These observations suggest the presence of a massive object exerting gravitational forces on the surrounding material, indicating a supermassive black hole. Collectively, these lines of evidence provide strong support for the existence of a supermassive black hole at the center of the Milky Way.
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50 points QUIZLET ( i dont have an account, but there is answer to this question, if u dont want to bother solving it) Assume uranium-236 splits into two nuclei of palladium-117 (Pd). (The atomic mass of uranium is 236.0455561 u; that of palladium is 116.9178 u.) a. Write down the reaction. b. What other particles must be produced? c. What is the energy released?
The conservation laws we can find the complete reaction of Uranium-235 and the correct answer is:
\(^{235}_{92}U + ^1_0n\) → \(^{236}_{92} U*\)
\(^{236}_{92}U*\) → \(2 \ ^{116}_{46} \ Pd + 2 \ ^1_0n + 195 \ MeV\)
Nuclear fission occurs when a heavy nucleus is divided into two smaller nuclei, for the process to occur requires the absorption of some particle or some form of energy that creates an unstable heavy nucleus this nucleus passes to a lower energy configuration when be divided.
In the case of Uranium 235 this occurs when a neutron is absorbed, according to the reaction
\(^{235}_{92} U + ^1_0n\) → \(^{236}_{92} U*\)
Where uranium 235 and 236 of atomic mass, * indicates that the nucleus is unstable and decays after about 10⁻¹² s
Indicate that one of the daughter nuclei is palladium, which is why a partial reaction remains
^{236}_{92} U* → \(^{116}_{46}Pd\) + Y + \(^1_0n\)
Where Y is the other daughter nucleus and n the neutrons released in the reaction
The conservation laws must be fulfilled, let's use: the conservation of atomic number and mass
.
1) The conservation of the atomic number allows to find the number of protons (atomic number) to atoms Y
#_protons = 92- 46
#_protons = 46 protons
The other atom is also a Palladium atom, the reaction is
^{236}_{92} U* → \(2 \ ^{116}_{46}Pd\) + \(^1_0n\)
2) Conservation of mass we can find the number of neutrons emitted in the reaction
The mass of the palladium atoms is
m_ {children} = 2 116.9178 u
m_ {children} = 233.8256 u
The mass difference between the uranium and the daughter nuclei is
Δm = m_ u - m_ {daughters}
Δm = 236.0455561 - 233.8256
Δm = 2.2199561 u
The mass of a neutron tabulated is m_n = 1.000866492 u
Consequently there is only mass for two neutrons that must be emitted in the process, the mass of the two neutrons is
m_ {total neutron} = 2.001732984 u
The amount of mass remaining is converted into energy
ΔE = m c²
The remaining mass to be convert to energy is
m_{remaining} = 2.2199561 - 2.001732984 = 0.2103626 u
m = 0.2102626 u (1.66054 10⁻²⁷ kg / 1u) = 0.3491495 10⁻²⁷ kg
ΔE = 0.3491495 10⁻²⁷ (2.99 10⁸) ²
ΔE = 3.1214 10⁻¹¹ J
It is more common to give this energy in eV
ΔE = 3.1214 10⁻¹¹ J ( \(\frac{1 eV}{1.6 \ 10^{-19} J}\) ) = 1.9509 10⁸ eV
We summarize the complete reaction is
\(^{235}_{92}U + ^1_0n\) → \(^{236}_{92} U*\)
\(^{236}_{92}U*\) → \(2 \ ^{116}_{46} \ Pd + 2 \ ^1_0n + 195 \ MeV\)
We can see that this reaction is not very efficient since a neutron is needed to start it and only two neutrons are emitted at the end of the process, even when the amount of energy emitted is high 195 MeV
In conclusion Using the conservation laws we can shorten the complete reaction of Uranium giving that the correct answer is:
\(^{235}_{92}U + ^1_0n\) → \(^{236}_{92} U*\)
\(^{236}_{92}U*\) → \(2 \ ^{116}_{46} \ Pd + 2 \ ^1_0n + 195 \ MeV\)
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An ideal gas exists inside of a piston Which of the following processes will keep the internal energy of the gas constant?
Add 20 J to the gas by heating and have the gas do 20 J of work.
Add 20 J to the gas by heating and do 20 J of work on the gas.
Remove 20 J from the gas by cooling and have the gas do 20 J of work.
The following processes will keep the internal energy of the gas constant: Remove 20 J from the gas by cooling and have the gas do 20 J of work.
When the temperature of an ideal gas is held constant, the internal energy remains constant. As a result, if heat is added to an ideal gas at constant temperature, the gas does some work, and the internal energy remains constant. When work is done on an ideal gas and it loses an equal amount of heat, the internal energy remains constant.
An ideal gas is a theoretical gas consisting of a large number of small particles that move at high speeds in random directions while obeying certain rules and assumptions. An ideal gas is one in which all particles have negligible volume and the interactions between them are nearly nonexistent.
Therefore, the option, "Remove 20 J from the gas by cooling and have the gas do 20 J of work." is correct.
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Scientists are studying a pond. Which property can the scientists measure to understand the amount of energy held by the lake water?
A. the depth of the lake
B. the color of the water
C. the volume of the lake
D. the temperature of the water
Calculate the Kinetic energy of a truck that has a mass of 2900 kg and is moving at 55 m/s.
The kinetic energy of the truck is 44,287,500 J as per the given data.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it.
The kinetic energy (K) of an object can be calculated using the formula:
\(K = 0.5 Xm X v^2\)
Where,
m = mass of the object
v = velocity
Plugging in the values given in the question, we have:
\(K = 0.5 X 2900 X (55 m/s)^2\)
\(K = 0.5 X 2900 X 3025 m^2/s^2\)
K = 44,287,500 J (joules)
So, the kinetic energy of the truck is 44,287,500 J.
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In which group of elements does tellurium (Te) belong?
(1 point)
alkali metals
metalloids
lanthanides
transition metals
Answer:
metalloids
Explanation:
Periodic Table
A Periodic table is an arrangement of chemical elements in order of increasing atomic number.
Metalloids: Metalloids have properties that are midway between metals and non metals
Tellurium is a chemical element with symbol Te and atomic number 52. Classified as a metalloid, tellurium is a solid at room temperature.
Properties
Atomic Mass
127.6u
Oxidation States
+6, +4, -2
Year Discovered
1782
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Two litres of water, initially at 20 °C, is heated to 40 °C. Determine thevolume of water at 40 °C if the coefficient of volumetric expansion ofwater within this range is 30 x 10-9 °C.
Given data
*The given initial volume of water is V_1 = 2 L
*The given initial temperature of the water is T_i = 20 °C
*The given final temperature of the water is T_f = 40 °C
*The coefficient of volumetric expansion of water is
\(\alpha=30\times10^{-9}^{}\text{C}\)The formula for the volumetric expansion is given as
\(\frac{\Delta V}{V}=\alpha(T_f-T_i)\)Substitute the known values in the above expression as
\(\begin{gathered} \frac{\Delta V}{V_1}=30\times10^{-9}\times(40^0-20^0) \\ V_2-V_1=6\times10^{-7}V_1 \\ V_2=6\times10^{-7}V_1+V_1^{} \\ =V_1(6\times10^{-7}+1) \\ =2.00\text{ L} \end{gathered}\)draw a figure of a simple pendulum explain its amplitude and effective length ?
Answer:
Explanation:
A simple pendulum consists of a mass (usually represented as a small object or bob) attached to a string or rod of negligible mass. The mass is free to swing back and forth under the influence of gravity.
In the figure, the point of suspension is denoted by "O," and the mass (bob) is represented by the small circle. The string or rod is represented by the vertical line connecting the point of suspension to the bob.
Amplitude:
The amplitude of a pendulum refers to the maximum displacement or swing of the bob from its equilibrium position. In the figure, the amplitude can be represented by the angle formed between the vertical position and the position of the bob when it swings to its maximum distance on one side. It is usually denoted by the symbol "A."
Effective Length:
The effective length of a pendulum refers to the distance from the point of suspension to the center of mass of the bob. It represents the distance over which the mass swings back and forth. In the figure, the effective length can be measured as the length of the string or rod from the point of suspension to the center of the bob. It is usually denoted by the symbol "L."
It is important to note that the amplitude and effective length of a simple pendulum affect its period of oscillation (the time taken for one complete swing). The relationship between these parameters and the period can be described by mathematical formulas.
Overall, the simple pendulum is a fundamental concept in physics and provides a simplified model for understanding oscillatory motion and the principles of periodic motion.
Margaret walks to the store using the following path 0. 630 mi west, 0. 370 mi north, 0. 180 mi east. Assume north to be along the +y-axis and west to be along the -x-axis. What is the magnitude of her total displacement?
The magnitude of Margaret's total displacement is approximately 0.5828 miles.
Since Margaret walked 0.370 miles towards the north direction, the y-component of her displacement is 0.370 miles.
Thus:
y-component = 0.370 miles
We can now find the magnitude of the displacement using the Pythagorean theorem.
The magnitude of displacement is given by:d = √(x² + y²)
Where,x is the x-component of the displacement, and y is the y-component of the displacement.
Substituting the values:
x = -0.450 m and y = 0.370 m
d = √((-0.450)²+ (0.370)²)
d = √(0.2025 + 0.1369)
d = √(0.3394)
d = 0.5828
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Imagine that you’re observing a collision. Which action would allow you to determine whether the collision is inelastic?
A.
Measure the force of impact.
B.
Observe whether the colliding objects change their shape.
C.
Measure the acceleration of the colliding objects.
D.
Measure the mass of the colliding objects.
Answer:
Its B, observe weather the colliding objects change their shape .
Explanation:
I hope this will help you, if not so advance sorry :)
Laboratory 22 speed of sound resonance what is the accuracy of each of your measurements of the speed?
The accuracy of measurements of the speed of sound in a laboratory experiment can depend on various factors. To ensure accuracy, it is important to use precise equipment and techniques. One method commonly used is the resonance method, where a tube with a known length is filled with a gas and a tuning fork is used to produce a sound. The length of the tube is adjusted until resonance occurs, and the speed of sound is calculated using the known length and the frequency of the tuning fork.
To improve accuracy, multiple measurements should be taken and an average should be calculated. This helps to minimize errors and provides a more reliable value. Additionally, the accuracy can be influenced by external factors such as temperature, humidity, and pressure. These should be controlled and monitored to reduce any potential errors.
It is important to note that the accuracy of the measurements can also be affected by the precision and calibration of the instruments used. Regular maintenance and calibration of equipment can help ensure accurate measurements. Overall, by following proper techniques, using precise equipment, and controlling external factors, the accuracy of measurements of the speed of sound can be maximized in a laboratory experiment.
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A softball player throws a pitch. during the throw, the speed of the softball increases from 0 m/s to 40 m/s in 0.08 seconds. the average acceleration of the ball is...
A softball player throws a pitch. during the throw, the speed of the softball increases from 0 m/s to 40 m/s in 0.08 seconds. The average acceleration of the ball is 500m/s^2
As we know that average acceleration is :
a= Δv/Δt
given:
v1=0 m/s
v2=40m/s
t=0.08 s
put the values in the formula
a= 40 - 0/0.08
a=500m/s^2
Thus the average acceleration is 500 m/s^2.
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By using uniform motion, the average acceleration is 500 m/s².
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vt = 40 m/s
vo = 0 m/s
t = 0.08 s
By substituting the given parameters, we can calculate the acceleration
vt = vo + a . t
40 = 0 + a . 0.08
a = 40/0.08
a = 500 m/s²
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What is the current in a circuit that has a voltage of 1.5v and a resistance of 15?
Answer:
0.1 amps or A
Explanation:
I believe to calculate that you would have to use the formula V = IR and change it to:
I = V/R
I = 1.5/15
I = 0.1 amps or A
The resistance of the connecting wires in a series circuit is generally?
The resistance of connecting wires in a series circuit is generally additive. This means that the total resistance of the circuit is equal to the sum of the individual resistances of each wire in the circuit.
A series circuit is an electrical circuit in which components are connected end-to-end along a single pathway. In a series circuit, the current flows through each component in sequence and must flow through all components to complete the circuit. The current is the same through each component and the total resistance of the circuit is equal to the sum of the resistances of the individual components.
One of the key characteristics of a series circuit is that if one component fails, the entire circuit will be disrupted. This means that a single component failure can render the entire circuit inoperable. It is for this reason that series circuits are generally not used in critical applications, as the failure of a single component can result in a complete circuit failure.
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5. The following human activities are caused of physical weathering, EXCEPT. C. Building roads and tunnels D. Acidic water in the river A. Boating and fishing B. Mining ores
Acidic water in the river is not caused by the human activities on physical weathering. So, option D.
People and the environment natural processes like weathering can be accelerated by human activity. The rate of weathering, for instance, is accelerated by some types of air pollution.
Nitrogen oxide and sulphur dioxide are among the substances released into the atmosphere by the burning of coal, natural gas, and petroleum.
Rocks are not removed during weathering; rather, they are broken down during the process. It is defined as the size-related disintegration or dissolution of a rock at or very close to the earth's surface by natural forces.
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A 0.145 kg rock is thrown with a speed of 32.0 m/s at an angle of 400. what is its kinetic energy at the top of its trajectory?
The kinetic energy at the top of the rock trajectory is 43.57 Joules
The kinetic energy formula and the procedure we will use is:
K.E. = 1/2 m (v*cosθ)²
Where:
v = speedm = massθ = angle Joules = Kg m²*s²Information of the problem:
v = 32 m/sm = 0.145 Kgθ = 40°Applying kinetic energy formula we get:
K.E. = 1/2 m (v*cosθ)²
K.E. = 1/2 * 0.145 kg (32 m/s*cos40°)²
K.E. = 1/2 * 0.145 kg *(24.513 m/s)²
K.E. = 1/2 * 0.145 kg *600.91 m²/s²
K.E. = 87.132 kg m²/s² / 2
K.E. = 43.57 Joules
What is kinetic energy?It is the energy possessed by a body due to its relative motion. It is usually expressed in Joules (J).
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If one knew the luminosity of a star and measured its apparent brightness, which expression would one use to calculate the distance to the star
The expression which one would use to calculate the distance to the star is distance = sq. root. of (luminosity/4pi*apparent brightness)
What is Distance?
This is a scalar quantity and refers to how much ground a body has covered.
In a situation where parameters such as luminosity of a star and measured its apparent brightness are known then the distance to the star will be:
Distance= √(luminosity/4pi*apparent brightness)
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Why is it the distance traveled can be more than where the object ends its path?
Answer: Specifically, if an object changes direction in its journey, the total distance traveled will be greater than the magnitude of the displacement between those two points.
Explanation: I Hope that was helpful! (Please mark as brainliest.)
What effect does wind and water have on mountains?
Answer:
Gale force winds, lightning strikes, temperature extremes and a deluge of snow, hail or rain. These combined forces break up the rocks and erode the peaks into their stark, sculpted forms. Falling ice, rocks and gushing water wear away at the mountain slopes.
1. A small light bulb is shining light on a basketball (diameter is 23 cm or 9 inches). The light bulb is 3 m from the closest side of the basketball. Behind the basketball, on the side away from the light bulb, is a wall 4 m from the basketball. Calculate the size (diameter) of the basketball's shadow on the wall
Answer:
The size (diameter) of the basketball's shadow on the wall is approximately 53.38 cm
Explanation:
The given parameters of the basketball are;
The diameter of the basketball = 23 cm (9 inches)
The distance of the light bulb from the closest side of the basketball = 3 m
The distance from the ball to the wall = 4 m
The distance from the light source to the center of the ball, d = 3 m + 0.23/2 m = 3.115 m
The angle the light ray makes with the edge of the ball, θ = arctan(0.115/3.115)
Therefore, the ratio of the shadow width divided by 2 to the distance from the light from the wall = 0.115/3.115
The distance from the light from the wall = 3 m + 4 m + 0.23 m = 7.23 m
Therefore;
((The width of the shadow)/2)/(The distance from the light from the wall) = 0.115/3.115
∴ ((The width of the shadow)/2)/(7.23 m) = 0.115/3.115
((The width of the shadow)/2) = 7.23 m × 0.115/3.115 = 16629/62300 m ≈ 0.2669 m = 26.69 cm
The width (diameter) of the shadow on the wall = 2 × 16629/62300 m ≈ 0.5338 m = 53.38 cm
The size (diameter) of the basketball's shadow on the wall ≈ 53.38 cm
Planets in the solar system revolve around the Sun in an orbital path and can vary from rocky and terrestrial objects to gaseous and liquid object. Which set of characteristics is unique to the outer planets
Answer:
Gaseous; liquid.
Explanation:
A planet can be defined as a large celestial body having sufficient mass to allow for self-gravity and make it assume a nearly circular shape (hydrostatic equilibrium), revolves in an orbit around the Sun in the solar system and has a cleared neighborhood.
Some examples of the planet are Mars, Venus, Earth, Mercury, Neptune, Jupiter, Saturn, Uranus, Pluto, etc.
Basically, the planets are divided into two (2) main categories and these includes;
I. Inner planets: these planets are the closest to the sun and comprises of mercury, venus, earth and mars.
II. Outer planets: these planets are beyond the asteroid belt and comprises of jupiter, saturn, uranus and neptune, from left to right of the solar system.
These outer planets are made mostly of gases (hydrogen and helium) causing them to be less dense than the solid inner planets. These gases are generally known to be less dense in terms of physical properties.
In conclusion, Planets in the solar system can vary from rocky and terrestrial objects to gaseous and liquid object.
However, the set of characteristics which is unique to the outer planets are gaseous and liquid.
Help FAST PLSS!!!
What is the period of a wave with a wavelength of 8 cm and a frequency of 0.5 hertz?(1 point)
0.125 seconds
4 seconds
0.0625 seconds
2 seconds
Two ropes are identical. A wave traveling through the first rope has a frequency of 1.5 hertz and a wavelength of 6 meters. What is the frequency of a wave in the second rope if its wavelength is 2 meters?(1 point)
3 hertz
1.5 hertz
9 hertz
4.5 hertz
If the wavelength of a wave in a particular medium is tripled, what will happen to the frequency of the wave?(1 point)
It will become one third of its original value.
It will become triple its original value.
It will depend on the speed of the wave.
It will remain constant.
If the speed of sound in air is 340 m/s, approximately how long will it take the sound of a clap of thunder to travel 2 kilometers?(1 point)
3.4 seconds
2.9 seconds
1.7 seconds
5.9 seconds
In music, the note G above middle C has a frequency of about 392 hertz. If the speed of sound in the air is 340 m/s, what is the approximate wavelength of this note?(1 point)
8.7 meters
0.87 meters
0.0026 meters
1.2 meters
Answer:1.) 2 seconds
2.) 4.5 hertz
3.) it will become one third is original value
4.)5.9 seconds
5.)0.87 meters
Explanation:
1. The time period of wave is 0.125 second
2. The frequency of a wave in the second rope is 1.5 hertz.
3. The frequency will become one third of its original value.
4. the time taken by sound of a clap of thunder to travel 2 kilometers is 5.9 seconds.
5. The wavelength of note is 0.87 meter
1. Time period \(=\frac{1}{frequency} =\frac{1}{8} =0.125second\)
2. Since both rope are identical. Therefore, both rope have same frequency.
Thus, The frequency of a wave in the second rope is 1.5 hertz.
3. In relation between wavelength and frequency, wavelength is inversely proportional to frequency.
If the wavelength of a wave in a particular medium is tripled , then the frequency of the wave will become one third of its original value.
4. The time taken by sound of a clap of thunder,
\(=\frac{2000}{340}=5.9seconds\)
5. Wavelength is the ratio of speed to the frequency.
\(Wavelength=\frac{340}{392}=0.87meters\)
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In the photo below, astronaut Alan Bean works at the Apollo 12 lander. Describe the horizon and the surface you see. What kind of terrain did they land on for this, the second human Moon landing, and why ?
Answer:
moon
Explanation:
I dont KNow
Given: NM 1 XZ
Prove: AXYZ- ANYM
N
Try 11
X
Z
M
We know that side NM is
to side
XZ. If we consider side NY the transversal for these
parallel lines, we create angle pairs. Using the
we can state
that YXZ is congruent to YNM. We know that angle
XYZ is congruent to angle
by the reflexive
property. Therefore, triangle XYZ is similar to triangle
NYM by the
similarity theorem.
F
The prove of Angle XYZ- Angle NYM is given below:
∠XYZ is congruent to ∠NYM - reflexive property. ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.What is the triangle about?Note that from the image given;
NM // XZNY = transversal line∠YXZ ≡ ∠YNMSince ∠XYZ is said to be congruent to ∠NYM it can be proven by the use of the reflexive property.
The reflexive property is one that informs that any shape is regarded congruent to itself.
Since ∠NYM has a different way to call ∠XYZ that uses a different vertexes, but the sides are made up of the two angles which are said to be the same.
Therefore , ∠XYZ ≡ ∠NYM are proved by the reflexive property.
Since ΔXYZ is the same with Δ NYM, it can be proven by the AA (angle-angle) similarity theorem.
We have 2 angles Δ XYZ and Δ NYM:
Note that ∠YXZ ≡ ∠YNM
∠XYZ ≡ ∠NYM
So, ΔXYZ is said to be the same to ΔNYM and it is proven by the AA similarity theorem.
Therefore, The prove of Angle XYZ- Angle NYM is given below:
∠XYZ is congruent to ∠NYM - reflexive property. ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.Learn more about triangles from
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Answer:
1. parrael
2. corresponding angles theorem
3. NYM
4. AA
Explanation:
just took it
Which of the following examples represent a bony joint, or synostosis?
Multiple Choice
A synostosis develops at the ends of the tibia and fibula to help hold them together.
Cranial sutures form as a synostosis when the baby's fontanels close.
A synostosis occurs in the jaw when a child's permanent teeth come in.
An infant is born with right and left mandibular bones, but they soon fuse into a single bone.
When the two maxillary bones unite to form the anterior two-thirds of the hard palate, a synostosis develops.
A synostosis develops at the ends of the tibia and fibula to help hold them together. synostosis, or the fusion of separate bones, occurs at the ends of the tibia and fibula, during the fusion of the mandibular bones, and when the two maxillary bones unite to form the hard palate.
Among the given options, the examples that represent a bony joint or synostosis are:
A synostosis develops at the ends of the tibia and fibula to help hold them together.
An infant is born with right and left mandibular bones, but they soon fuse into a single bone.
When the two maxillary bones unite to form the anterior two-thirds of the hard palate, a synostosis develops.
A synostosis at the ends of the tibia and fibula refers to the fusion or joining of these two bones, resulting in a bony joint. This fusion provides stability and strength to the leg.
In the case of an infant being born with separate right and left mandibular bones, they eventually fuse together into a single bone. This fusion of the mandible represents a synostosis, forming the lower jaw bone.
The fusion of the two maxillary bones to form the anterior two-thirds of the hard palate is another example of a synostosis. The maxillary bones fuse during development to create a single, solid structure that forms the hard palate in the roof of the mouth.
In summary, synostosis, or the fusion of separate bones, occurs at the ends of the tibia and fibula, during the fusion of the mandibular bones, and when the two maxillary bones unite to form the hard palate.
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Calculate the average speed of a complete round trip in which the outgoing 290 km is covered at 91 km/h , followed by a 1.0- h lunch break, and the return 290 km is covered at 54 km/h .
The average speed of the complete round trip is 61.12 km / h.
We need to know about the average speed to solve this problem. The average speed can be determined as the total distance divided by the total time. It can be written as
v = d / t
where v is average speed, d is distance and t is time.
From the question above, we know that
d1 = 290 km
v1 = 91 km/h
t lunch = 1 hour
d2 = 290 km
v2 = 54 km/h
Find the time during the outgoing
v1 = d1 / t1
t1 = d1 / v1
t1 = 290 / 93
t1 = 3.12 hours
Find the return time
v2 = d2 / t2
t2 = d2 / v2
t2 = 290 / 54
t2 = 5.37 hours
Hence, the total time
t = t1 + t2 + t lunch
t = 3.12 + 5.37 + 1
t = 9.49 hours
Find the average speed
v = d / t
v = (290 + 290) / 9.49
v = 61.12 km / h
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the hanging mass is referred to as m and it sets the centripetal force. group of answer choices true false
The answer is True
When we do not have the numerical value of mass.
The answer is False
By choosing a value of hanging mass it becomes false.
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a body of mass 5kg moving on a horizontal ground has a coefficient of friction 0.36.find the normal reaction acting on the body?
Answer:
50 N.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 5 Kg
Coefficient of friction (μ) = 0.36
Normal reaction (N) =?
Next, we shall determine the weight of the body. This can be obtained as follow:
Mass (m) = 5 Kg
Acceleration due to gravity (g) = 10 m/s²
Weight (W) =?
W = mg
W = 5 × 10
W = 50 N
Finally, we shall determine the normal reaction. This can be obtained as follow:
Weight (W) = 50 N
Normal reaction (N) =?
Normal reaction = weight of the body
N = W = 50 N
Thus, the normal reaction acting on the body is 50 N
hello I need help with this question. I started it but am confused
Given:
The mass on the table is,
\(m=1.0\text{ kg}\)The hanging mass is,
\(M=1.5\text{ kg}\)THe coefficient of friction is,
\(\mu=0.20\)let the acceleration of the whole system is a (for the hanging mass it is downward and for the mass on the table it is rightward). the tension towards The fixed point of the pulley is T.
we can write,
\(Mg-T=Ma\ldots.\ldots..\ldots\ldots.(1)\)\(ma=T-\mu mg\ldots.\ldots.\ldots..\ldots..(2)\)Adding these equations we get,
\(\begin{gathered} (M+\mu m)g=(M+m)a \\ a=\frac{(M+\mu m)g}{M+m} \end{gathered}\)Substituting the values we get,
\(\begin{gathered} a=\frac{(1.5+0.20\times1.0)9.8}{1.5+1.0} \\ =6.67m/s^2 \end{gathered}\)Hence the acceleration is 6.66 m/s^2.
the motion(s) that occur at the radioulnar joint?
The radioulnar joint is a synovial joint located at the elbow that connects the radius and the ulna, enabling rotational motion.
The radioulnar joint allows for pronation and supination. Pronation refers to the motion of rotating the forearm so that the palm faces downwards, while supination refers to the motion of rotating the forearm so that the palm faces upwards. The radioulnar joint allows the radius and ulna to move relative to each other, resulting in rotational motion.
When the forearm is pronated, the radius rotates over the ulna and crosses it, while the ulna remains stationary. When the forearm is supinated, the radius rotates back to its original position, and the two bones are parallel to each other.The radioulnar joint is important in many activities, including writing, typing, playing musical instruments, and sports like tennis and golf. Any damage to this joint can result in a loss of pronation and supination, making daily activities challenging.
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