The magnetic field B at all points within the colored circle of the figure (Figure 1) has an initial magnitude of 0.780 T. (The circle could represent approximately the space inside a long, thin solenoid.) The magnetic field is directed into the plane of the diagram and is decreasing at the rate of 0.0300 T/s.
a) What is the magnitude of the induced electric field at any point on the circular conducting ring with radius r = 0.100 m ?
b) What is the direction of this field at any point on the circular conducting ring?
c) What is the current in the ring if its resistance is 4.00 Ω ?
d) What is the emf between points a and b on the ring?
e) If the ring is cut at some point and the ends are separated slightly, what will be the emf between the ends?
Answers
The magnitude of the induced electrical field is 0.0015V/m, the field is pointing towards the clockwise direction while the current in the ring will be 0.0002355A if the resistance is 4 ohms. The emf between point a and b is zero and the EMF across the point if they're slightly separated between the ends is 0.000942V
To solve this question, we would have to go about each one individually
Data:
\(r=10cm=0.1m\\\)
a.
The magnitude of the induced electrical field at any point within the radius is
\(\int\limits^a_b {E} \, du=\frac{dU}{dt}=\pi \frac{dB}{dt}=\pi r^{2}\frac{dB}{dt}\\E*2\pi r=\pi r^{2}\frac{dB}{dt} \\E=\frac{r}{2}\frac{dB}{dt}=\frac{0.1}{2}*0.03=0.0015V/m\)
b.
The field is pointing towards the clockwise direction.
c.
The current in the ring if we are given a resistance of 4ohms
\(I=\frac{emf}{R}=\frac{\pi r^{2}\frac{dB}{dt} }{R} =\frac{\pi (0.1)^2*0.03}{4} =0.0002355A\)
d.
The emf between point a and b is zero
e.
The EMF across two points if they're separated by small distance across the ring is
we would use the formula to solve for the EMF
\(E=\pi r^{2}\frac{dB}{dt}=\pi (0.1)^2*0.03=0.000942V\)
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Related Questions
When you jump, you push down on the earth and it pushes back up against you. The earth pushing up against you is what causes you to go into the air. Why doesn’t your push cause the earth to go down if your push on the earth is equal and opposite of the earth's push on you?
Answers
That's a great question !
The answer is: It does !
A push on an object causes the object to accelerate in the direction of the force.
The less mass the object has, the more the force accelerates it.
Now, when you jump, the forces on you and on the Earth are equal forces.
The up force on you causes you to accelerate up by some amount.
The down force on the Earth causes the Earth to accelerate down by some amount.
The Earth's mass is something like 5,972,000,000,000,000,000,000,000 kg, while your mass is something like 50 kg.
The Earth has something like 119,400,000,000,000,000,000,000 times as much mass as you have.
So your acceleration is something like 119,400,000,000,000,000,000,000 times as great as the Earth's acceleration.
==> The Earth's downward acceleration, caused by your jump, is there. It's just too small to notice.
BUT . . . That's the reason why seismometers (instruments to detect and measure the vibrations from distant earthquakes) have to be located as far as possible from cities and busy roads.
In places that are too close to cities and roads, the Earth's surface is always vibrating, wiggling, jiggling, heaving and weaving, in reaction to the forces of people walking around, cars and trucks driving around, even rain falling down. And kids jumping up and down !
In such places, these people-motions are louder and stronger than the vibrations coming from distant earthquakes. Seismometers wouldn't work there.
Can somebody please help
Answers
Answer:
Explanation:
part A: C
part B: B
Across
2. Cotton is a____ material.
4. The materials which are difficult to compress are known as____
5. Iron,Cooper,aluminum is called___.
6. The materials through which objects can be seen, but not clearly are known as___.
8. shiny appearance is termed as___
Down
1.Opaque material which we got from trees____
3.water is a____liquid.
7.vinegar is___in water
Answers
Across
2. opaque
4. hard
5. metal(s)
6. translucent
8. luster
Down
1. wood
3. transparent
7. soluble?
Happy to help, have a great day! :)
What is the energy equivalent of an object with a mass of 1.05g?
Answers
Answer:
The equivalent energy of an object given its mass is calculated through the equation,
E = mc²
where c is the speed of light (3 x 10^8 m/s)
Substituting the known values,
E = (1.05 g/ 1000) (3 x 10^8 m/s)²
E = 9.45x10^13 J
Explanation:
Suppose that a series RL circuit is connected to a voltage source whose input voltage (Vin) is shown in the figure above. As shown in the figure above, the input voltage Vin = Vmax only within time interval 0 ≤ t ≤ T. The input voltage Vin = 0 outside this time interval. Assume that initially (at t = 0), no current is flowing in this circuit (I = 0)! A Determine the output voltage Vout as a function of time t! B Assume that the time interval T is very short so that T → 0, and also assume the the maximum voltage Vmax is quite high, so that VmaxT ≈ Φimp. Show that the output voltage Vout can be approximated by the following equation : Vout(t) ≈ Φimp τ e −t/τ where τ = L R
Answers
A. The output voltage, Vout, as a function of time, t, in a series RL circuit can be determined using the equation: Vout(t) = Vmax * (1 - e^(-t/τ)), where τ = L/R.
B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can approximate the output voltage Vout using the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.
A. To determine the output voltage Vout as a function of time t in a series RL circuit, we use the following equation:
Vout(t) = Vmax * (1 - e^(-t/τ))
Here, Vmax is the maximum input voltage, τ = L/R is the time constant of the circuit (where L is the inductance and R is the resistance).
B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can make the following approximation:
Vout(t) ≈ Vmax * e^(-t/τ)
In this case, we substitute VmaxT with Φimp, which is the total magnetic flux in the circuit.
Rearranging the equation, we get:
Vout(t) ≈ Φimp * e^(-t/τ)
This approximation is valid when the time interval T is very small compared to the time constant τ of the circuit and when the maximum voltage is sufficiently high.
The time constant τ is determined by the values of inductance (L) and resistance (R) in the circuit. It represents the characteristic time scale over which the current and voltage in the circuit change in response to a voltage or current input.
Therefore, in the given scenario, when T is very small and Vmax is high, we can approximate the output voltage Vout(t) in the series RL circuit by the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.
Note: The symbol Φimp in the equation represents the total magnetic flux in the circuit.
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The mass of the planet Mars is 6.39 x 10^23 kg. Using Newton's Law of Gravitation, calculate the force of gravity between the planet Mars and the 74 kg Mars Rover drone on the surface if the distance between the center of Mars and surface is 2129.9 km. Show all work.
Need it ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Answers
Answer:
F = 695.25 N
Explanation:
The force between Mars and Rover can be given by Newton's Law of Gravitation can be written as follows:
F = Gm₁m₂/r²
where,
F = Force of Gravity = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of rover = 74 kg
m₂ = mass of mars = 6.39 x 10²³ kg
r = distance between the centers of mars and rover = 2.1299 x 10⁶ m
Therefore,
F = (6.67 x 10⁻¹¹ N.m²/kg²)(74 kg)(6.39 x 10²³ kg)/(2.1299 x 10⁶ m)²
F = 695.25 N
Sound with frequency 1300 Hz leaves a room through a doorway with a width of 1.03 m . At what minimum angle relative to the centerline perpendicular to the doorway will someone outside the room hear no sound
Answers
Answer:
about 14.7°
Explanation:
The formula for the angle of the first minimum is ...
sin(θ) = λ/a
where θ is the angle relative to the door centerline, λ is the wavelength of the sound, and "a" is the width of the door.
The wavelength of the sound is the speed of sound divided by the frequency:
λ = (340 m/s)/(1300 Hz) ≈ 0.261538 m
Then the angle of interest is ...
θ = arcsin(0.261538/1.03) ≈ 14.7°
At an angle of about 14.7°, someone outside the room will hear no sound.
What is the total mechanical energy of a 3 kg object traveling at 7 m/s if its potential energy is 42 J? (1 point)
247.8 J
115.5 J
31.5 J
73.5 J
Answers
A 3 kilogram object traveling at 7 m/s and possessing a 42 J potential energy has a mechanical energy of 115.5 J.
How much mechanical energy does the thing possess?Performing a specific task results in the accumulation of mechanical energy. It is the total of an object's potential energy and kinetic energy. It is stated as;
Potential and kinetic energy are the components of mechanical energy.
Given the information in the query;
The object's mass is 3 kg.
The object's speed is 7 m/s.
Object's potential energy is 42 J.
Calculate the object's kinetic energy.
Kinetic energy = 1/2 × mass × ( velocity )²
Insert the specified values.
Kinetic energy is = 1/2 x 3 kg x 7 m/s2.
Kinetic energy = 0.5 x 3 kg x 49 m2/s2.
Kinetic energy = 73.5 kg/m2/s2.
Kinetic energy = 73.5 J.
Now, the object's mechanical energy will be;
Potential energy plus kinetic energy equals mechanical energy.
Put the values in.
Mechanical energy = 42J + 73.5J
Mechanical energy = 115.5 J.
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Transverse waves on a string have wave speed 12m/s, amplitude 0.05m and wavelength 0.4m. The waves travel in the positive x direction, and at t=0 the x = 0 end of the string has zero displacement and is moving upward.
(a) Find the frequency, period and wave number of these waves
(b)Write a wave function describing the wave
(c) Find the transverse displacement of a wave at x=0.25 at time t -0.15sec
(d) How much time must elapse from the instant in part "(c)" until the point at x = 0.25m has zero displacement
Answers
v = fλ
f = v/λ = 12/0.4 = 30 Hz
The period (T) is the inverse of the frequency, so:
T = 1/f = 1/30 = 0.0333 s
The wave number (k) can be calculated as:
k = 2π/λ = 2π/0.4 = 15.708 rad/m
(b) The wave function can be written as:
y(x, t) = A sin(kx - ωt + φ)
where A is the amplitude, ω is the angular frequency, and φ is the phase constant. Since the x = 0 end of the string has zero displacement and is moving upward at t = 0, the phase constant is 0. At t = 0, the wave function can be written as:
y(x, 0) = A sin(kx)
The amplitude is given as 0.05m, so:
0.05 = A sin(k*0)
sin(0) = 0, so A = 0.05. Therefore, the wave function is:
y(x, t) = 0.05 sin(15.708x - 188.5t)
(c) To find the transverse displacement of the wave at x = 0.25m and t = -0.15s, we can substitute these values into the wave function:
y(0.25, -0.15) = 0.05 sin(15.7080.25 - 188.5(-0.15))
y(0.25, -0.15) = 0.05 sin(0.5906)
y(0.25, -0.15) ≈ 0.029 m
Therefore, the transverse displacement of the wave at x = 0.25m and t = -0.15s is approximately 0.029m.
(d) The point at x = 0.25m has zero displacement when the argument of the sine function is an integer multiple of π, or:
15.708(0.25) - 188.5t + φ = nπ
where n is an integer. We want to find the time at which this equation is satisfied. Rearranging, we get:
t = (15.708*0.25 + φ - nπ)/188.5
The phase constant is 0, so we can simplify the equation to:
t = (15.708*0.25 - nπ)/188.5
For n = 0, the time is:
t = (15.708*0.25 - 0)/188.5 ≈ 0.0208 s
Therefore, the time required for the point at x = 0.25m to have zero displacement is approximately 0.0208s.
find the acceleration of the elevator (magnitude and direction).express your answer with the appropriate units. enter positive value if the direction of the acceleration is upward and negative value if the direction of the acceleration is downward.
Answers
The acceleration of the elevator is -2.2 m/s2 downwards.
What is Acceleration?Acceleration is a vector quantity that describes the rate of change of an object's velocity over a period of time. It is measured in metres per second squared (m/s2). Acceleration is not the same as speed, which is the rate at which an object moves in a particular direction. Acceleration can be either positive (speeding up) or negative (slowing down) and is caused by an applied force, such as friction or gravity. The acceleration of an object changes with time and is dependent on the object's mass, drag, and the force that is applied to it.
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he circles, or orbits, for electrons are called energy levels. Each level can hold only a certain number of electrons. Add electrons to each level until you can’t add any more. How many electrons can each level hold?
Answers
The maximum number of electrons that could be found in particular energy level is given by the formula 2n^2
What is the Bohr model?
According to the Bohr model of the atom, the atom is composed of electrons which are arranged in orbits. The orbits are arranged in such a way that they have specific energy levels.
Now, the maximum number of electrons that could be found in particular energy level is given by the formula 2n^2 where n is the principal quantum number of that energy level.
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Which words or phrase should be emphasized in the following step to help convey order?
Be sure to jump forward. Immediately after you pop, drag your front foot up and “jump forwards.” This will be tough at first, and you’ll have to practice to get the timing down.
a.
Be sure to jump forward
c.
drag your front foot up
b.
Immediately after you pop
d.
his will be tough at first
Please select the best answer from the choices provided
A
B
C
D
Answers
The word or phrase that should be emphasized in the given step to convey order is "Immediately after you pop." Hence, option B is correct
The phrase "Immediately after you pop" indicates the precise timing for the next step, which is to drag the front foot up and jump forward. It is important to follow this sequence of actions in order to execute the trick correctly.
By emphasizing "Immediately after you pop," the reader or listener will understand that this is a crucial step that should not be delayed or performed out of order. This will help them focus on the timing and make sure they do not miss this important step.
While the other phrases are also important, emphasizing "Immediately after you pop" will ensure that the reader or listener understands the correct sequence of actions and is able to execute the trick properly.
Correct answer is Option B) Immediately after you pop.
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explain the term tenscopo
Answers
Answer: Here you go, i hope this kinda helps.
Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".
Watson Assistant replies to user's questions based on a confidence score.
Sometimes the customer's question could be interpreted in two or three different ways.
For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:
Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?
Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.
The Problems: 1. Xavier starts at a position of 0 m and moves with an average speed of 0.50 m/s for 3.0 seconds. He normally moves faster than this but he'd just woken up. Determine his final position. 2. A hedgehog starts at a position of 0 m and moves with an average speed of 0.75 m/s for 4.0 s. Determine the final position of the hedgehog. 3. A tortoise starts at a position of 1.0 m and moves with an average speed of 1.25 m/s for 3.0 s, what is the final position of the tortoise? Cintia, in a 100 m race, has an average speed of 1.25 m/s. What was her race time? 5. Angel runs a marathon with an average speed of 5 miles/hour. How long did it take to finish?
Answers
Answer:
(1). His final position is 1.5 m.
(2). The final position of the hedgehog is 3 m.
(3). The final position of the tortoise
(4). Her race time is 80 sec.
(5). It take to finish in 5 hr.
Explanation:
(1). Given that,
Initial position = 0 m
Average speed = 0.50 m/s
Time = 3.0 s
We need to calculate the final position
Using formula of average speed
\(v_{av}=\dfrac{x_{f}+x_{i}}{t}\)
Where, \(x_{f}\) = final position
\(x_{i}\) = Initial position
t = total time
Put the value into the formula
\(0.50=\dfrac{x_{f}+0}{3.0}\)
\(x_{f}=0.50\times3.0\)
\(x_{f}=1.5\ m\)
(2). Given that,
Initial position = 0 m
Average speed = 0.75 m/s
Time = 4.0 s
We need to calculate the final position
Using formula of average speed
\(v_{av}=\dfrac{x_{f}+x_{i}}{t}\)
Put the value into the formula
\(0.75=\dfrac{x_{f}+0}{4.0}\)
\(x_{f}=0.75\times4.0\)
\(x_{f}=3\ m\)
(3). Given that,
Average speed = 1.25 m/s
Time = 3.0 sec
Initial position = 1.0 m
We need to calculate the final position
Using formula of average speed
\(v=\dfrac{x_{f}+x_{i}}{t}\)
Put the value into the formula
\(1.25=\dfrac{x_{f}+1.0}{3.0}\)
\(x_{f}=1.25\times3.0-1.0\)
\(x_{f}=2.75\ m\)
(4). Given that,
Average speed = 1.25 m/s
Distance = 100 m
We need to calculate the time
Using formula of time
\(t=\dfrac{d}{v}\)
Put the value into the formula
\(t=\dfrac{100}{1.25}\)
\(t=80 sec\)
(5). Given that,
Average speed = 5 miles/hr
Suppose, distance = 25 miles
We need to calculate the time
Using formula of time
\(t=\dfrac{d}{v}\)
Put the value into the formula
\(t=\dfrac{25}{5}\)
\(t=5\ hr\)
Hence, (1). His final position is 1.5 m.
(2). The final position of the hedgehog is 3 m.
(3). The final position of the tortoise
(4). Her race time is 80 sec.
(5). It take to finish in 5 hr.
A metal wire of length 1cm and of uniform diameter has a resistance of 0.8 ohms. What is the resistance of a 50cm wire coil made of the same material but having twice its diameter?
Answers
Answer:
20
Explanation:
R= resistance P = resistivity
L = length A = area
0.8 = 1cm/A
R = J l/A => 0.8* 50*A/A
=> 0.8 * 25
=> 20
Answer:
Resistance is directly proportional to length, inversely proportional to cross-sectional area. Pay attention in class, and observe that even easy multiple choice questions can have only wrong answers if the setter makes a mistake.
define summarize the step you might use to carry out
Answers
Answer:
The steps involved in the scientific method are;
•Draw up a research question
•Construct a hypothesis
•Test the hypothesis through experiments
•Analyse experimental results
•Draw conclusions
Science is a study of the universe from an empirical point of view. This means that scientific investigations depend onexperiments.
The first step in the scientific method of investigation is to draw up the research questions to be investigated. After this is done, subjected to experiments. The experiments may confirm or disprove the hypothesis. If the hypothesis is disproved, then it is revised in line with the results of experiments.
a research hypothesis is constructed and
A 5kg objects is sliding across a floor at 10m/s. How much work is done by friction to bring it to a stop?
Answers
If A 5kg objects is sliding across a floor at 10m/s.then the work done by friction to bring the 5 kg object to a stop is -250 Joules.
To calculate the work done by friction to bring the object to a stop, we need to determine the change in kinetic energy.
Given:
Mass of the object, m = 5 kg
Initial velocity, u = 10 m/s
Final velocity, v = 0 m/s (object comes to a stop)
The work done by friction can be calculated using the equation:
Work = Change in Kinetic Energy
The change in kinetic energy (ΔKE) can be calculated as:
ΔKE = (1/2) * m * (v^2 - u^2)
Plugging in the values:
ΔKE = (1/2) * 5 kg * (0 m/s)^2 - (10 m/s)^2
= (1/2) * 5 kg * (0 - 100 m^2/s^2)
= (1/2) * 5 kg * (-100 m^2/s^2)
= -250 J
The negative sign indicates that the work done by friction is in the opposite direction of the displacement of the object.
Therefore, the work done by friction to bring the 5 kg object to a stop is -250 Joules.
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Calculate the weight of an object with a mass of 50 kg on a planet with an acceleration due to gravity of 2.0 m/s2.
a. .04 N
b. 25 N
c. 100 N
Answers
Answer:
C
Explanation:
Basically force is given by the formula.
F= ma
Where m is mass of the body and 'a' is acceleration.
Here the time is not given, hence it is not possible to calculate acceleration, as acceleration is given by the formula
a= v/t
So most probably the question is wrong.
However if we take acceleration= 2m/s^2
Then F= ma= 50*2= 100N
However if the question was to find energy then it is sufficient to find kinetic energy as moving objects possess kinetic energy.kinetic energy is given by the formula:
KE= 1/2*m* v^2
I.e, KE= 1/2 * 50 * 2* 2
If a pair of shoes weighs 0.3 N on Pluto what is the strength of gravity on Pluto
Answers
Answer:
0.6 m/s 2
Explanation:
(8.6) A space station in deep space is spun like a giant wheel to produce centrifugal force so the occupants experience artificial gravity of one g. How does a clock at the rim of the space station compare with one residing at the hub? What does this say about the behavior of a clock sitting on the surface of a planet with a surface gravity of one g?
Answers
The way that the clock at the rim of the space station compare with one residing at the hub is that Rim clock will always runs slower.
The behavior of a clock sitting on the surface of a planet with a surface gravity of one g is the same.
Is there a timepiece on the ISS?For instance, timekeeping on the International Space Station (ISS) is slightly slower than that of reference clocks on Earth. This explains why astronauts on the International Space Station (ISS) mature more slowly, lagging by 0.007 seconds every six months.
Ground-based atomic clocks have served as the industry standard for timekeeping since the 1950s. These clocks use the extremely steady and accurate frequencies of light emitted by particular atoms to keep time.
Therefore, Satellite clocks run slower due to more velocity but faster due to reduced gravity. Clocks move more slowly at the ISS orbital height because velocity dominates. At GPS altitude, clocks move more quickly due to the influence of gravity.
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Which of the following is true at the point where you reach the top of your jump on a trampoline?
The mechanical energy is zero
he potential energy is at maximum
The kinetic energy and potential energy are equal.
The potential energy is zero.
Answers
The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.
What is Potential EnergyPotential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.
This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.
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The train slows down at the railroad crossing. Is that acceleration, velocity, speed, of none of the above?
Answers
Answer:
none of the above
Explanation:
im pretty positive this is the answer tell me if i am wrong please
a piece of uranium drops from 1500 Celsius to 900 Celsius. what state of matter would we expect it to be in?
Answers
At 1500°C, uranium would be in a molten or liquid state. As it cools to 900°C, it will solidify
How does the temperature affect?
The temperature of a substance determines its state of matter. At high temperatures, substances tend to be in a liquid or gaseous state, and as the temperature decreases, they solidify.
In the case of uranium, at 1500°C, it would be in a molten or liquid state because this temperature is higher than its melting point of 1132°C.
However, as it cools to 900°C, it will become solid because 900°C is below its melting point.
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4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V
Answers
The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.
To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.
Given:
R1 = 4 Ω
R2 = 30 Ω
R3 = 10 Ω
R4 = 5 Ω
Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:
RT1-2 = R1 + R2
RT1-2 = 4 Ω + 30 Ω
RT1-2 = 34 Ω
Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:
1/RTotal = 1/RT1-2 + 1/R3
1/RTotal = 1/34 Ω + 1/10 Ω
1/RTotal = (10 + 34) / (34 * 10) Ω
1/RTotal = 44 / 340 Ω
1/RTotal ≈ 0.1294 Ω
RTotal ≈ 1 / 0.1294 Ω
RTotal ≈ 7.74 Ω
Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:
RTotalCircuit = RTotal + R4
RTotalCircuit = 7.74 Ω + 5 Ω
RTotalCircuit ≈ 12.74 Ω
Therefore, the total resistance of the circuit is approximately 12.74 Ω.
To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:
I = V / RTotalCircuit
I = 56 V / 12.74 Ω
I ≈ 4.39 A
Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).
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Gravity Rocks!
Three friends were talking about gravity. One friend
held up a rock and asked his friends whether the gravi-
tational force on the rock depended on where the rock
was located. Each friend had a different idea about a
place where the gravitational force on the rock would
be the greatest. This is what they said:
Lorenzo: "I think if you put the rock on the top of a very tall mountain, the gravita-
tional force on the rock will be greatest."
Eliza: "I think the gravitational force will be greatest when the rock is resting on
the ground near sea level."
Flo: "I think you have to go really high up. If you drop the rock out of a high-
flying plane, the gravitational force will be greatest."
Explain why you agree with
Which friend do you most agree with?
that friend.
Answers
Answer:
Eliza’s suggestion is the most promising
Explanation:
Newton’s law of universal gravitation is \(F = G\frac{m_1m_2}{r^2}\) where G is a constant and both masses are constant in this experiment as well. So it only depends on r, the distance between the center of mass of both objects.
Bringing it high in the sky, as Flo suggests, is definitely not a good idea because it only increases the distance from the center of the Earth mass.
A mountain contains significant mass, so the center of the Earth mass is somewhat shifted to regions with the largest mountains. However, standing on top of a mountain, as Lorenzo suggests, doesn’t help since the shift of the center of mass, if any, is far smaller than the height of the mountain.
Standing near sea level, as Eliza suggests, is a good way to minimize the distance to the center of the Earth mass.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
Answers
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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Two forces 100n and 42.5n are acting on an object what is the resultant force if the first acts upward and the second acts downward
Answers
The resultant force if the first acts upward and the second acts downward will be 57.5 N
Force is defined as an external cause that changes or tends to change the state of the body once applied; if the body is in motion, it comes to rest and if at rest, then it will come to motion.
since , both the forces are in different direction , have to work according sign convention .
let upward forces = + ve
downward forces = - ve
f1 = + 100 N
f2 = - 42.5 N
f1 + f2 = F net
F net = + 100 + (- 42.5 )
= + 57.5 N
hence , net force will be 57.5 N in upward direction
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The heating element in an electric kettle is rated as 2.0 kW. If the water in the kettle is at 100.0 °C, what volume of water will be converted into steam in one minute? The specific latent heat of vaporization of the water is 2,257,000 J/kg and the
3 density of water is 1,000 kg/m .
Answers
Answer:
The volume is \(V =5.32 *10^{-5} \ m^3\)
Explanation:
From the question we are told that
The power of the heating element is \(P = 2.0 kW = 2.0 *10^3 \ W\)
The temperature of the water in the kettle is \(T _w = 100^oC\)
The time to convert water to steam is t = 1 minute = 60 sec
The specific latent heat of vaporization is \(H_v = \ 2,257,000 J/kg\)
The density of water is \(\rho_w = 1000\ kg/m^3\)
The power of the heating element is mathematically represented as
\(P = \frac{E}{t}\)
Where E Energy generated by the heating element in term of heat
\(E = Pt\)
substituting values
\(E = 2.0 *10^{3} * 60\)
\(E = 120000 J\)
Now
The latent heat of vaporization is mathematically represented as
\(H_v = \frac{E}{m}\)
Where m is the mass of water converted to steam
So
\(m = \frac{E}{H_v}\)
substituting values
\(m = \frac{120000}{2257000}\)
\(m = 0.0532\ kg\)
The volume of water converted to steam is mathematically evaluated as
\(V = \frac{m }{\rho_w}\)
substituting values
\(V = \frac{0.0532}{1000}\)
\(V =5.32 *10^{-5} \ m^3\)
Why do you think the pylon in Figure 24 is designed the way it is, and not in the way shown in Figure 25?
Answers
They are specifically made tο be ideal fοr cοnducting live electrical lines because οf their electrical insulatiοn and mechanical tοughness. A structure called an electric pylοn οf hοt-rοlled steel bevels οr gusset plates.
What kinds οf patterns are used tο create electrical pylοns?Other materials, such as cοncrete and wοοd, may alsο be utilised in additiοn tο steel. Transmissiοn tοwers can be divided intο fοur main categοries: suspensiοn, terminal, tensiοn, οr transpοsitiοn.
Whο was the electrical pylοn's designer?This Central Electricity Bοard held a cοmpetitiοn in 1927, and the winning entry was chοsen by the classical designer Sir Reginald Blοοmfield. He settled οn an A-frame structure with latticewοrk that was οffered by the American cοmpany Milliken Brοthers and is still in use tοday.
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Complete question:
A stack of paper contains 500 sheets of paper. The stack has dimensions of 0.297 m x 21.0 cm x 50.0 mm.
A. What is the thickness of one sheet of paper?
B. What is the volume of the stack of paper in cm3?
Answers
Answer:
0.1 mm
Explanation:
Given data : A stack of paper contains 500 sheets of paper.
The stack has dimensions of 0.297 m x 21.0 cm x
50.0 mm.
To Find : What is the thickness of one sheet of paper
So,
1 m = 1000 mm
1 m = 100 cm
1 cm = 10 mm
The stack has dimensions of 0.297 m x 21.0 cm x 50.0 mm.
0.297 m = 297 mm
21 cm = 210 m
297 mm * 210 mm are paper length width
Hence 50 mm is thickness of 500 sheets
- thickness of one sheet of paper = 50/500 = 1/10 mm
= 0.1 mm
Hope It Helps :)
The thickness of one sheet of paper would be 62.37 ×10⁻⁶ meters.
The volume of the stack of paper in cm³ would be 0.031185 mm³.
What is multiplication?Finding the product of two or more numbers in mathematics is done by multiplying the numbers. It is one of the fundamental operations in mathematics that we perform on a daily basis.
As given in the problem a stack of paper contains 500 sheets of paper. The stack has dimensions of 0.297 m x 21.0 cm x 50.0 mm.
The volume of the stack = 0.297 m x 21.0 cm x 50.0 mm
= 0.000297 mm×2.1 mm x 50.0 mm
the thickness of one sheet of paper = 0.000297 mm×2.1 mm x 50.0/500mm
=62.37 ×10⁻⁶ meters
The volume of the stack of paper = 31.185 cm³
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