The low average density of Jupiter indicates that this planet is composed mainly of gases, such as hydrogen and helium. These gases are less dense than liquids or solids, which is why Jupiter's overall density is lower than that of water. In fact, Jupiter is often referred to as a gas giant due to its composition.
However, it is important to note that while Jupiter may be primarily composed of gases, it still has a solid core made up of rock and metal. This core is estimated to be around 20,000 kilometers in diameter and is responsible for generating Jupiter's strong magnetic field.
Overall, the low density of Jupiter suggests that this planet formed differently from Earth and other rocky planets in our solar system. Instead of accumulating solid materials early on, Jupiter likely formed from the collapse of a large cloud of gas and dust.
As a result, it has a vastly different composition and structure compared to other planets in our solar system.
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A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
A. 1.7 × 106 joules
B. 3.4 × 106 joules
C. 5.6 × 106 joules
D. 6.8 × 106 joules
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 ×\(10^4\) meters. If the truck's mass is 7,000 kilograms, the work done to reach this distance is 3.3× \(10^6\) joules.
The correct answer is option E.
To calculate the work done by the truck to cover a distance of 5.8 × \(10^4\)meters, we need to use the equation for work:
Work = Force × Distance
In this case, the force can be calculated using Newton's second law:
Force = mass × acceleration
Where:
Acceleration (a) = \(0.0083 meters/second^2\)
Distance (d) = 5.8 ×\(10^4\) meters
Mass (m) = 7,000 kilograms
First, let's calculate the force exerted by the truck:
Force = mass × acceleration = (7,000 kg) ×\((0.0083 meters/second^2)\)= 57.1 Newtons
Next, we can calculate the work done:
Work = Force × Distance = (57.1 N) × (5.8 × 10^4 meters) = 3.3158 × \(10^6\)joules
Rounded to the nearest significant figure, the work done by the truck is approximately 3.3 × \(10^6\) joules.
Therefore, the correct answer is E.
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The question probable may be:
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 ×\(10^4\)meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
A. 1.7 × \(10^6\) joules
B. 3.4 ×\(10^6\) joules
C. 5.6 × \(10^6\)joules
D. 6.8 × \(10^6\)joules
E. 3,3 ×\(10^6\) joules
If Nitrogen gains three electrons, what will its charge be? *
Answer:
It's change will form the nitride ion
An eagle is flying above a mountain of height 2,700 m above sea level. Calculate the pressure on the eagle if the average density of air is 1.3 kg/m3,the atmospheric pressure at sea level is 76 cm Hg, and the density of mercury is 13,600 kg/m3.
Answer:
The correct option is;
(A) 25.8 cmHg
Explanation:
The given parameters are;
The height of the mountain over which the eagle is flying = 2700 m
The average density of air, ρₐ = 1.3 kg/m³
The atmospheric pressure at sea level = 76 cmHg = 0.76 mHg
The density of mercury, \(\rho _m\) = 13,600 kg/m³
The formula for pressure, p, is p = ρ·g·h
The pressure in the atmosphere = 13,600 × 0.76 × g = 10,336·g
The equivalent height of air is found as follows;
1.3 × g × h = 10,336·g
h = 10,336/1.3 = 7,950.769 meters
Therefore;
The pressure of the atmosphere at 2,700 meters, p₂₇₀₀ = (2,700/7,950.769) × 76 cm Hg
Which gives;
p₂₇₀₀ = 25.808 cmHg ≈ 25.8 cmHg.
Planet Force (N) Mass (kg)
A 8.0 0.50
B 30 3.0
C 45 3.0
D 60 6.0
The gravitational force acting on various masses is measured on different planets. Measured values for the forces acting on the corresponding masses are shown in the data table. Analyze the data and develop a method for comparing the gravitational field strengths on the different planets. Use your method to compare the gravitational field strengths, and report your conclusions.
From the analysis, it can be concluded that planet A has the strongest gravitational field, followed by planet C, and planets B and D have the same gravitational field strength.
The gravitational force acting on various masses is measured on different planets. The table shows the measured values for the forces acting on the corresponding masses:Planet Force (N) Mass (kg)A 8.0 0.50B 30 3.0C 45 3.0D 60 6.0
Method for comparing the gravitational field strengths on the different planets:First, we can use the formula for calculating gravitational force: \(`F = G (m_1m_2 / r^2)`\)where G is the universal gravitational constant `\(6.67 * 10^{-11 }Nm^2/kg^2\), m1 and m2 are the masses of the two objects in kg, and r is the distance between the centers of the objects in meters.
We know that the force is proportional to mass (F = ma). So we can calculate the acceleration due to gravity (g) on each planet by dividing the force by the mass. Therefore, we can use the formula: `g = F / m`.
Comparing the gravitational field strengths on the different planets:We will calculate the acceleration due to gravity (g) on each planet.
For planet A: `
g = F / m
= 8.0 N / 0.50 kg
= 16 \(m/s^2\)`
For planet B: `g = F / m
= 30 N / 3.0 kg
= 10 \(m/s^2\)
For planet C: `g = F / m
= 45 N / 3.0 kg
= 15 \(m/s^2\)
For planet D: `g = F / m
= 60 N / 6.0 kg
= 10 \(m/s^2\)
`So we see that planet A has the strongest gravitational field, followed by planet C, then planet B and planet D have the same gravitational field strength.
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in a ________ fault, the hanging wall block moves up with respect to the footwall block.
.A) normal B) strike slip C) reverse D) abnormal
In a Reverse fault, the hanging wall block moves up with respect to the footwall block.
What is Reverse fault?Reverse fault is a type of fault in which two blocks of earth's crust move away from each other, resulting in the upper block of crust being pushed up above the lower block. It is the opposite of a normal fault, in which two blocks of crust move towards each other. The reverse fault typically occurs when the Earth’s tectonic plates come together and a compressional force pushes up and over the lower plate. This type of fault is usually seen in regions of convergence between two plates and is common along convergent plate boundaries. The reverse fault is usually accompanied by large earthquakes as the plates move against each other. The reverse fault can also be caused by the bending of the Earth’s crust in response to forces such as erosion, volcanic activity and sedimentation. These forces can cause the crust to buckle and rise, resulting in a reverse fault.
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If the length of a pendulum is doubled,what will be the change in its time period??
Explanation:
see the attachment.. hope it will help you
who will catch the ball on the merry-go-round spinning counter-clockwise? a. ball caught by the thrower b. ball caught opposite the thrower c. ball caught to the thrower's left d. ball caught to the thrower's right
The ball will be caught by the thrower's right. The correct answer is option d.
When the merry-go-round is spinning counterclockwise, the person throwing the ball and the ball itself will have a tangential velocity in the counterclockwise direction. As the ball leaves the thrower's hand, it will continue to move in a straight line with this tangential velocity.
However, the ball is also subject to the circular motion of the merry-go-round, which means it will also have a centripetal acceleration towards the center of the merry-go-round.
As a result, the ball will follow a curved path towards the right of the thrower and will be caught by the thrower's right hand.
So, the correct answer is d. the ball caught to the thrower's right.
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Module 3 Discussion!
After reading Ch.12 and 13 of the text (The essentials of Finance and Accounting for nonfinancial managers/ Third Edition) on Strategy and Financial Forecasting, watching the SWOT video based on Paley’s Products from the Ratio Analysis in Module 2 and the additional narrative information in Appendix C, Phase
Create a SWOT analysis that will reflect the TOWS analysis as described in Ch. 12 of the text. The purpose of the SWOT analysis is to lay out several issues and possibilities to be considered in Paley’s strategic planning. The strengths and weaknesses are internal issues, whereas the opportunities and threats are external.
The second part of the analysis is to create actions based on the SWOTs. This is sometimes called a TOWS analysis and is done by comparing the boxes, two at a time:
Offensive actions come from strengths that link to opportunities, so a specific strength can be applied to exploit an opportunity.
Adjusting actions come from addressing weaknesses, which then can be used to exploit opportunities that previously had not been possible.
Turnaround actions come from weaknesses that link to threats. These are high-risk issues where a priority needs to be given to addressing the weakness to minimize the vulnerability.
Defensive actions come from threats that link to strengths. These are latent issues because if the threat materializes, an already-existing strength is available to counter it.
Additional actions can be included to address other issues not directly identified in the SWOTs.
3. From the actions identified in part 2, pick 3-5 strategic actions that you feel Paley must achieve or at least start in the upcoming year and state your reasons for including them.
Attach your completed SWOT form and list of strategic actions with supporting logic and facts from the case as your answer for this discussion question. These actions are the foundation for the strategic plan
SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-
They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.
Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.
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2. A student slides a 0.75 kg textbook across a table, and it comes to rest after
traveling 1.2 m. Given that the coefficient of kinetic friction between the
book and the table is 0.34, use the work-kinetic energy theorem to find
the book's initial speed.
The book's initial speed = 2.83 m/s
The mass of the textbook, m = 0.75 kg
The final speed of the textbook, v = 0 m/s (Since it comes to rest)
The distance covered by the book, d = 1.2 m
Coefficient of kinetic friction, \(\mu = 0.34\)
The frictional force between the table and the book is calculated as:
\(f_k=-\mu mg\\\\ f_k=-0.34 \times 0.75 \times 9.8\\\\f_k=-2.499N\)
The workdone by the textbook is calculated as:
\(W = Fd\\\\W=2.499(1.2)\\\\W=2.9988J\)
According to the work-kinetic energy theorem:
Workdone by the book = Change in Kinetic energy
\(W = 0.5m(v^2-u^2)\\\\-2.9988=0.5 \times 0.75 \times (0^2-u^2)\\\\-2.99988=-0.375u^2\\\\u^2=\frac{-2.9988}{-0.375} \\\\u^2=7.9968\\\\u=\sqrt{7.9968}\\\\u=2.83m/s\)
The book's initial speed = 2.83 m/s
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a crate is sliding down an inclined ramp at a constant speed of 0.55 m/s. the vector sum of all the forces acting on this crate must point:
Answer:
The net force on the object is zero
Explanation:
An object is moving with constant non-zero velocity. If velocity is constant, it means that the change in velocity is equal to 0. As a result, acceleration of the object is equal to 0. Net force is the product of mass and acceleration. Hence, the correct option is (d) "The net force on the object is zero".
A tourist wishes to catch a train in 1.2 hours, which is 115 km away. If she spends the first half-hour going 90km/h, how fast will she need to go to get to station on time?
Answer:
100km/hr
Explanation:
From the problem statement we know that distance of the trip is 115km
Expected time for the trip = 1.2hrs
→ If she spends the first half-hour going 90km/hr,
Here time = 0.5hr
speed = 90km/hr
The distance covered;
Distance covered = Speed x time
Distance covered = 90 x 0.5 = 45km
→The remaining distance will be:
Total distance - distance covered
115km - 45km = 70km
→ The remaining time;
1.2hr - 0.5hr = 0.7hr
Speed = \(\frac{distance}{time}\)
Insert the parameters and solve;
Speed = \(\frac{70}{0.7}\) = 100km/hr
For the remaining lap, the tourist must travel at a rate of 100km/hr to catch up.
] for which of the following nuclei is alpha decay permitted? (a) 210bi (b) 203hg (c) 211at. [2]
Among the given nuclei, alpha decay is permitted for nucleus 210Bi and nucleus 211At.
Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle, consisting of two protons and two neutrons (a helium nucleus). For alpha decay to occur, the parent nucleus must have sufficient mass and atomic number.
In the given options, 210Bi and 211At are the nuclei for which alpha decay is permitted. The decay process for 210Bi involves the emission of an alpha particle, resulting in the formation of a daughter nucleus. Similarly, 211At can undergo alpha decay by emitting an alpha particle.
On the other hand, nucleus 203Hg does not exhibit alpha decay, as it does not meet the criteria for this specific decay mode.
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A skier reaches the end of a 0.9 km track in 1.5 hours, at what speed does it travel?
(Please help,I need the answer as soon as possible)
Speed = Distance/Time
S = D/T
D = 0.9Km, T = 1.5hours,
S = 0.9/1.5
S = 0.6 m/s
hope it helps!
Answer: Speed =
distance = 0.9 * 1000 = 900 metres, because speed is measured in m/s so the km has to be converted to m
time = 1.5 * 60 = 90 seconds , because speed is measured in m/s so the time in minutes(m) has to be converted to seconds(s)
Speed =
= 10m/s
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Explanation: I don't know what this is but this is what I found and I hope it's helpful
derive an expression from the energy stored E, in a stretched wire of original length L cross sectional area A, e, tension e,and young modulus Y of the material of the wire
The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A
How to explain the expressionThe work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).
The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:
T = Y * (ΔL / L)
where Y is the Young's modulus of the material of the wire.
Now, let's calculate the work done to stretch the wire:
dW = T * dL
Integrating this expression from L to L + ΔL:
W = ∫ T * dL = ∫ Y * (ΔL / L) * dL
W = Y * ΔL * ∫ (dL / L)
W = Y * ΔL * ln(L) + C
Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.
Finally, the expression for the energy stored in the wire (E) is:
E = W = Y * ΔL * ln(L)
or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:
E = Y * e * ln(L) * A
Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:
E = Y * e * ln(L) * A
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in the demonstration which required you to calculate the electric potential difference, the charged ball traveled along a path with a vertical segment, then a horizontal segment, then a diagonal segment. which of the following was true about the potential difference along the horizontal segment?
In the demonstration described, the charged ball traveled along a path with a vertical segment, a horizontal segment, and a diagonal segment. The potential difference along the horizontal segment can be understood by considering the electric field and potential difference concepts. Here, the electric potential difference experienced by the charged ball along the horizontal segment will be zero.
The electric potential difference, or voltage, is the work done per unit charge as it moves in an electric field. When a charged particle moves along a horizontal segment, it does not experience any change in the vertical direction, meaning that the vertical component of the electric field has no effect on the potential difference along this segment.
In this scenario, the horizontal segment implies that the charged ball is not moving closer to or further away from the source of the electric field. Therefore, the electric potential difference experienced by the charged ball along the horizontal segment will be zero. This is because the work done on the charged ball by the electric field along the horizontal path is zero, as there is no change in the ball's distance from the source of the field in this direction.
In summary, the potential difference along the horizontal segment of the path is zero, as there is no work done on the charged ball by the electric field in the horizontal direction.
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From one point on the ground, the
angle of elevation of the peak of a
mountain is 10.38°, and from a
point 15,860 ft closer to the
mountain, the angle of elevation is
14.67º. Both points are due south of
the mountain. Find the height of the
mountain.
10.38°
一企一
14.67°
15,860 ft
Trigonometry allows to find the result for the question about the height of the mountain is:
The height mountain is: y = 9674.4 ftTrigonometry allows finding relationships between the angles of a right triangle.
\(tan \theta = \frac{y}{x}\)
Where θ is the angle, y the opposite leg (height) and x the adjacent leg (horizontal distance).
In the attachment we can see a diagram of the system. They indicate that for x distance the angle is 14.67º
tan 14.67 = \(\frac{y}{x}\)
At the other point the angle is 10.38º.
tan 10.38 = \(\frac{y}{x+15860}\)
We look for the horizontal distance (x) with these equations.
x tan 14.67 = (x + 15860) tan 10.38
x tan 14.67 / tan 10.38 = x + 15860
x 1,429 = x + 15860
x 0.429 = 15860
x = \(\frac{15680}{0.429}\)
x = 36955.3 ft
We calculate for the height.
y = x tan 14.67
y = 36955.3 tan 14.67
y = 9674.4 ft
In conclusion using trigonometry we can find the result for the height of the mountain is:
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Which of these activities performed by a chemist is primarily based on an understanding of physics?
A.
using an indicator to determine if a solution is an acid, base, or neutral
B.
testing the molar concentration of a solution
C.
checking whether a given element is a metal or nonmetal
D.
predicting the volume of a gas, given its temperature and pressure
Answer:
Hello! your answer is C. I did this. got 100%. Have a nice day!
Explanation:
Answer:
D Predicting the volume of a gas by its Temp and preasure
Explanation:
1: not C, took the Plato test and it was wrong
C DOES seem like the answer, but determining if an element is a metal or non-metal deals with the molecular structure of said element as well as the different components meaning its more of a chemistry based task
2: the answer choice D refers to the measurement of volume and temp, these are tied to physical traits and therefore, is a task based on the understanding of physics
*SIDENOTE* a good way to tell in this case is process of elimination, we know that option A involves a more chemical style task, referring to the measurement of the acidity of said substance, same goes for option C for it deals with the molecular structure of a solution
1. How did the temperature of the mixture change before and after the ice melted? 2. Calculate the average temperature change per minute of the ice-water mixture prior to the ice melting and the average rate after the ice melted, average rate prior to melting______ average rate after melting______
The temperature of the mixture remained constant at the melting point of ice (0 degrees Celsius) before the ice melted.
The average rate of temperature change per minute was 0 degrees Celsius before the ice melted, and increased to the rate at which heat was being applied after the ice melted.
When ice is in contact with water, it melts at its melting point, which is 0 degrees Celsius. During this phase change, the temperature of the mixture remains constant at 0 degrees Celsius until all the ice has melted.
The average rate of temperature change per minute prior to the ice melting is 0 degrees Celsius, as the temperature remains constant.
After the ice melts, the average rate of temperature change per minute will depend on the rate at which heat is being applied to the mixture, which could vary based on the heat source used and the conditions of the experiment.
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the heating coil in a hair dryer is made of nichrome wire with a radius of 0.275 mm. if the coil draws a current of 8.85 a when there is a 120 v potential difference across its ends, find the following. (take the resistivity of nichrome to be 1.50 ✕ 10−6 ω · m.)
The resistance of the coil R IS 12.435Ω and The length of the wire that is calculated from R= ρL/A is L = 1.97 m.
Electrical resistance is a force that opposes the flow of current and is hence resistance to electricity. In this sense, it acts as a gauge for the difficulty of current flow. Ohms () are used to measure resistance.
Electricity will flow from high to low when there is an electron difference between two terminals. In opposition to that flow is resistance. The current decreases with increasing resistance. Conversely, the higher the current, the lower the resistance. In theory, resistance is affected by the kind, temperature, and length of the material through which the electricity is flowing. Metals generally have low electrical resistance, which varies depending on the type of metal, which makes electricity flow through them more easily.
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___________ force is a supportive force that surfaces exert in order to prevent solid objects from passing through one another.
A. Contact
B. Regular
C. Normal
D. Field
“I know what the atomic number of this atom is, but I don’t know what the number of electrons is,” a friend says. How would you respond?
Once the atomic number of an atom is known, the number of electrons can be deduced depending on if the atom is an ion or a neutral one.
Atomic numberThe atomic number of an atom is the number of protons in the nucleus of the atom.
For atoms that are neutral, that is, no net charges, the number of protons is always equal to the number of electrons. In other words, the positive charges always balance the negative charges in neutral atoms.
Thus, if the atomic number of a neutral atom is 6, for example, the proton number will also be 6. Since the proton must balance the electron, the number of electrons will also be 6.
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A man jumps from an airplane and does not
open
his parachute immediately. As he falls,
two forces act on him: the force mg due to
gravity and the force n, of air resistance. Now
he opens his parachute and begins to fall at
constant velocity.
What forces act upon him now?
Answer:
The forces acting on a skydiver jumping from a plane include the gravitational force and air resistance
Explanation: i, dumb so this is proabaly wrong
Why does Mars provide the best opportunity for habitation by humans?
Answer:
Mars is an opportunity for humans to carry forward the light of consciousness, plus it is the closest planet like earth, it has land humans can land on and although its small, theres still water
i dont understand pojectile motion can someone help with this
When thrown from the balloon, the sandbag has a constant horizontal/forward velocity. As the text puts it, "the sandbag continues forward as if it had not been dropped." What this means is that the sandbag has no acceleration in the horizontal plane of motion, so it moves in this direction at a constant speed. So for any time \(t\), the horizontal velocity is given by
\(v_x(t) = 12\dfrac{\rm m}{\rm s}\)
In the vertical plane of motion, the sandbag has no vertical velocity until it's released and allowed to fall. As it's falling, however, the sandbag is being pulled down by gravity and is accelerating with magnitude \(g=9.8\frac{\rm m}{\mathrm s^2}\), so its vertical/downward velocity at time \(t\) is given by
\(v_y(t) = -gt\)
So, after 3 seconds have passed, the sandbag has horizontal velocity \(v_x = 12\frac{\rm m}{\rm s}\) and vertical velocity \(v_y = -g(3\,\mathrm s) = -29.4\frac{\rm m}{\rm s}\). If the question is specifically asking about speed you would just ignore the negative signs.
opuestos write an adjective with the opposite meaning. question 1 with 1 blank 1 of 1 cerrado question 2 with 1 blank 1 of 1 alegre question 3 with 1 blank 1 of 1 ordenado question 4 with 1 blank 1 of 1 sucio 2 emparejar match the sentence parts. three items from the list will not be used. cuando los estudiantes tienen problemas, los profe
Opposites:
abierto (open)
triste (sad)
desordenado (disorganized)
limpio (clean)
Sentence matching:
"When students have problems, teachers"
A. Les dan soluciones (give them solutions)
B. Escuchan y hablan con ellos (listen and talk to them)
C. Los ignoran (ignore them)
Answer: B. Escuchan y hablan con ellos (listen and talk to them)
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It is known that temperature increases as you ascend in the stratosphere. what compound is responsible for the increase in temperature?
It is the presence of ozone in the stratosphere and its ability to absorb UV radiation that is responsible for the increase in temperature as you ascend in the stratosphere.
The stratosphere is the layer of Earth's atmosphere located above the troposphere, and it extends from about 10 to 50 kilometers above the Earth's surface. In this region, the temperature increases with altitude, which is contrary to the temperature decrease observed in the troposphere.
The increase in temperature in the stratosphere is primarily due to the presence of ozone (O3) molecules. Ozone is a compound consisting of three oxygen atoms. It absorbs a significant portion of the Sun's ultraviolet (UV) radiation in the stratosphere. This absorption of UV radiation leads to the formation of an ozone layer, which acts as a protective shield for life on Earth by preventing harmful UV radiation from reaching the surface.
The absorption of UV radiation by ozone molecules causes an increase in the temperature of the stratosphere because the energy from the absorbed radiation is converted into heat. This energy absorption process results in the temperature inversion, where the temperature rises with increasing altitude.
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do p and u fix the state of a superheated vapor?
Yes, the pressure (P) and temperature (T) of a superheated vapor are two state-fixing factors, because they are two properties directly related to the states of matter.
Pressure and internal energy can fix the state of a superheated vapor. This is because the state of a substance is determined by two independent properties. In the case of a superheated vapor, pressure and internal energy are two independent properties that can be used to determine the state of the vapor.
Once these two properties are known, other properties such as temperature, volume, and enthalpy can be determined.
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Can a molecule of DNA contain 60% thymine? Why
or why not?
Answer:
The possibility of Adenine=40% and Thymine=60% is only in single stranded DNA molecule. In the question, the DNA sample referred is a single stranded DNA. If guanine=10% as guanine will always pair with cytosine, i.e.cytosine is also 10% then adenine and thymine accounts 80% as adenine will always pair with thymine.
A molecule of DNA cannot contain 60% thymine because this amount will surpass 100% in consideration of its complementary base.
DNA:DNA or deoxyribonucleic acid is a biological molecule that stores genetic information in living cells.
DNA is a double stranded molecule that consists of nucleotide bases as follows:
AdenineThymine GuanineCytosineAccording to Chargaff in his rule, the amount of adenine & thymine and guanine & cytosine in a DNA molecule is the same, which must equal 100% overall.
Therefore, if thymine is 60% in the DNA, adenine will also be 60%, which in total has already surpassed 100% without adding the other two bases.
Learn more about DNA at: https://brainly.com/question/1822938
5. A space shuttle travels from earth and through space at a speed of 260,000 km/s. How
far into space did the space shuttle travel during the first 40 seconds?
Equation
Data
Plug in
Answer/units
T=260,000 km/should
Answer:
considering that a space shuttle travels 7,850 m/s and it traveled 40 seconds it would be 314,000 I think this is the right answer
Explanation:
What effect would constriction of the blood vessels have on the body?
Answer:
When blood vessels constrict, the flow of blood is restricted or decreased, thus retaining body heat or increasing vascular resistance. this makes the skin turn paler because the blood reaches the surface, reducing the radiation of heat. hope this helps