the local high school recently passed a rule reducing how much teachers can count homework as a part of a student's grade. Consequently, a larger portion of the students stop doing their homework. A teacher there decides to conduct there experiment. All of his classes get an optional ''test guide'' to help them study for their test.
Answers
An experiment occurs when we want to study the relationship between the dependent and the independent variable. We know that the independent variable is the variable that is manipulated in the experiment and the dependent variable variable is the variable that undergoes a change as we change the independent variable.
It must be known that an experiment is the only way that we could be able to establish a cause and effect relationship. In other words, the results of an experiment tell us categorically if the effect owes to a supposed cause as was captured in the hypothesis of the experiment.
In this case we have the following in this experiment;
The independent variable is the use or absence of the test guide
The dependent variable is the overall performance in the academic year
The control group is the group that did not use the test guides
The experimental group is the group that used the test guides
The constants are the method of instruction, the structure of the test and the difficulty of the test.
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Missing parts;
The local high school recently passed a rule reducing how much teachers can count homework as part of a student's grade. Consequently, a larger portion of the students stop doing their homework. A teacher there decides to conduct an experiment. All of his classes get an optional "test guide" to help them study for their tests. He allows two classes to use the "test guides" (that they must fill in and complete) on their exams. He hypothesizes that students will complete the test guides and learning will occur from filling them out. In his other 2 classes, the teacher does not allow students to use test guides on the exam, and consequently very few of them filled them out. After the 2017-2018 year is over, he wants to compare scores between the 4 classes on the final exam to see if allowing students to use test guides during each test throughout the year improved their later overall performance.
Independent Variable: _____________________________ Dependent Variable: ___________________________________
Experimental Group: _______________________________ Control Group: _________________________________________
3 constants: ______________________________________________________
Related Questions
What is the molar concentration (molarity, M) of a 450 mL solution that contains 2.00 mol of FeCl₂?
Answers
Answer:
3.50 Mol/L or M
Explanation:
450 mL / 1000 = 0.45 L
1 mole ------- 126.751 g
? mole ------- 200 g
moles = 200 * 1 / 126.751
moles = 200 / 126.751
= 1.57789 moles FeCl₂
M = n / V
M = 1.57789 / 0.45
= 3.50 Mol/L or M
Which of the following corresponds to an alpha particle?
A. 1/4He
B. 3/2He
C. 2/2H
D. 4/2He
Answers
Answer:
D. 4/2 He corresponds to an alpha particle.
the set of positions occupied by the three oxygen atoms
Answers
The three oxygen atoms can occupy three distinct positions in space. These positions can be identified by their coordinates in three-dimensional space.
What is the space?The space is an area or volume that exists between two or more objects, areas, or surfaces. In scientific terms, it is the distance between two points in three-dimensional space. It can also refer to a gap between two events, feelings, or other entities. In mathematics, space is a measure of the dimensionality of a given set, which can be described as the number of degrees of freedom within a given set. In physics, space is the physical realm of existence that encompasses all matter and energy. It is a fundamental component of reality and the universe.
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What are the uses of Sulphuric acid?
Answers
Answer:
The major use of sulfuric acid is in the production of fertilizers, e.g., superphosphate of lime and ammonium sulfate. It is widely used in the manufacture of chemicals, e.g., in making hydrochloric acid, nitric acid, sulfate salts, synthetic detergents, dyes and pigments, explosives, and drugs.
The major use of sulfuric acid is in the production of fertilizers, e.g., superphosphate of lime and ammonium sulfate. It is widely used in the manufacture of chemicals, e.g., in making hydrochloric acid, nitric acid, sulfate salts, synthetic detergents, dyes and pigments, explosives, and drugs.
Cell Membrane Transport
List 5 observations when you open the blue and green gated channels:
Section 2
After listing your observation, click “reset all” and do the same process again, following the instructions listed above. Answer the following questions below.
1.) Open the green gated channel and observe. What did you observe when you open the green gated channel?
2.) Based on your observations, what type of solution have you observed? Is it ‘hypertonic’, ‘hypotonic’ or ‘isotonic’? Explain
3.) Open the blue gated channel. Observe on what will happen when you open the blue gated channel. What have you observed?
4.) What type of solution have you observed? Is it ‘hypertonic’, ‘hypotonic’ or ‘isotonic’? Explain.
5.) Slow down the animation. What did you observed on the motion of the green circles and blue diamonds?
Answers
A type of fossil fuel,known as Tar stands.
what is fossil fuel?A fossil fuel is a hydrocarbon-containing material formed naturally in to the Earth's crust from to the remains of dead plants and animals and birds that is the extracted and burned as thr a fuel. The main fossil fuels are mainly coal, oil, and natural gas.
Tar sands are a combination of clay, sand, water and bitumen, which is a heavy hydrocarbon. Like the kerogen in oil shale, tar sands' bitumen can be upgraded to synthetic crude oil.
So answer is tar sands.
These include tar sands – deposits of moist sand and it is clay with 1-2 percent bitumen (thick and heavy are petroleum rich in the carbon and poor in the hydrogen). These are the removed by strip mining in the (see section below on coal)
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Once the roller coaster train gets closer to the bottom of the hill, its kinetic energy increases to 1,100 J, and its potential energy decreases to
Answers
Once the roller coaster train gets closer to the bottom of the hill, its kinetic energy increases to 1,100 J, and its potential energy decreases to zero.
What is potential energy?Potential energy is a type of energy that is stored and depends upon the relative height of system. If its height is increased, the potential energy is also increases while on the other hand, if the body comes to the surface of the earth, its potential energy will be zero due to no height of the object. We know that potential energy is equals to product of mass, gravity and height of an object.
So we can conclude that if the roller coaster train gets closer to the bottom of the hill, its kinetic energy increases to 1,100 J, and its potential energy decreases to zero.
Which of the following describes the change in atomic mass and atomic number during this reaction?
Answers
Mylanta a common antacid contains magnesium hydroxide Mg (OH)2.How many miles of magnesium hydroxide are in 75.0g of magnesium hydroxide?
Answers
To answer this question, we need to convert grams to moles and then use the Avogadro's number to convert moles to molecules.
The molar mass of Mg(OH)2 is 58.32 g/mol.
First, we need to find the number of moles of Mg(OH)2 in 75.0 g.
75.0 g / 58.32 g/mol = 1.287 mol
Next, we need to convert moles to molecules.
1.287 mol x 6.022 x 10^23 molecules/mol = 7.75 x 10^23 molecules
Finally, we can use the molecular formula of Mg(OH)2 to calculate the number of miles of Mg(OH)2.
1 molecule of Mg(OH)2 contains 3 atoms of oxygen (O) and 2 atoms of hydrogen (H).
So, the total number of miles of Mg(OH)2 is:
7.75 x 10^23 molecules x 2 miles/molecule = 1.55 x 10^24 miles
Therefore, there are 1.55 x 10^24 miles of magnesium hydroxide in 75.0 g of magnesium hydroxide.
What doesn’t change the resistance of a wire
Answers
The factor that doesn’t change the resistance of a wire is pressure. option A.
What is resistance of a wire?Resistance is a conductor's capacity to thwart the passage of current. It is controlled by the interplay of the applied voltage and the electric current passing through it. The amount of opposition any object applies to the flow of electric current is referred to as resistance.
The ohm, a unit of measurement for resistance, is represented by the Greek letter omega. According to Ohm's law, the voltage across two places is precisely proportional to the current flowing through a conductor between them.
Hence option A is correct.
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missing part;
The pressure
The length of the resistor.
The thickness of the resistor.
The temperature of the conductor.
Explain why the following picture illustrates the relationships between voltage, current and resistance. (hint: start with Ohm's Law)
Answers
Answer:
Explanation:
We can see that this picture can be used to show Ohm's Law graphically so it illustrates Ohm's Law.
According to Ohm's Law electric current is directly proportional to voltage and inversely proportional to resistance.
Mathematically, V ∝ I,
or V=IR,
where, V ⇒ voltage difference between two points,
I ⇒ current flowing through the resistance,
R ⇒ proportionality constant or resistance.
According to the picture voltage ( SI unit Volt ) is supporting the current ( SI unit Ampier ) to move out from the barrier while the resistor ( SI unit Ohm )is acting as a barrier to its way . As it is satisfying the Ohm's Law it illustrates the relationship between voltage, current, and resistance.
Draw all four products when the following compound undergoes dehydrohalogenation and rank them in terms of stability. Which product do you expect to be the major product?
Answers
Answer:
2 Methyl pent 2 ene
student added 2 ml 2 ml of 0.1 m c a c l 2 0.1 m cacl2 to 2 ml 2 ml of 0.1 m n a 2 c o 3 0.1 m na2co3 in a test tube. he observed a white precipitate form. which of the following is the identity of the precipitate?
Answers
The identity of the precipitate from the observed white precipitate form is \(CaCO_{3}\) (Calcium carbonate).
What is the identity of the precipitate?А precipitаte is а solid formed in а chemicаl reаction thаt is different from either of the reаctаnts. This cаn occur when solutions contаining ionic compounds аre mixed аnd аn insoluble product is formed. The identity of the precipitаte cаn often be determined by exаmining solubility rules. It аlso occurs in single displаcement when one metаl ion in solution is replаced by аnother metаl ion. Notice the new solid forming on the bottom of the tube.
Here \(CaCl_{2}\) react with \(Na_{2} CO_{3}\) to give a white precipitate of \(CaCO_{3}\) and NaCl.
\(CaCl_{2}\) + \(Na_{2} CO_{3}\) → \(CaCO_{3}\) + 2NaCl.
Calcium carbonate is an inorganic chemical compound with a chemical formula \(CaCO_{3}\). Cаlcium cаrbonаte is а non-toxic аnd odourless compound commonly found аs а white minerаl which occurs nаturаlly in chаlks, limestones аnd mаrbles.
Your question is incomplete, but your full question can see in the attachment.
Thus, the correct option is D.
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which property is least helpful in identifying a sample of matter? A. melting point B. Volume. C. Reactivity. D. Boiling point
Answers
Answer:
which property is least helpful in identifying a sample of matter is (B) VOLUME
Explanation:
volume depend on the amount of substance present and are not useful in the identification of a sample of matter. volume is an extensive property so it is not useful identifying the sample of matter.
What is nitrogen G how will be formed G
Answers
Nitrogen G is a colorless, tasteless gas that is the most plentiful element in Earth's atmosphere and is a constituent of all living matter of nitrogen.
what is nitrogen g explain?Nitrogen is an essential gaseous element with an atomic number of 7 and an atomic weight of 14.0067. Nitrogen gas has two particles of Nitrogen therefore, the molecular formula of this gas is N2. It is a non-metallic element that settled Group 15
nitrogen. [ nī′trə-jən ] N. A nonmetallic element that constructs up about 78 percent of the atmosphere by capacity, Nitrogen is a nonmetal and the lightest member of group 15 of the periodic table
So we can conclude that Nitrogen is the chemical element with the symbol N and atomic number 7.
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label the sun. which layer of the sun is #4?
Answers
Answer:
is D I guess; photosphere
At 25 degrees Celsius, 50g of sugar is soluble in 100ml of water. If I add 55g of sugar to
25-degree water, what will my solution look like and what will the ratio of dissolved to
undissolved solute be? If I heat up the solution, what will my solution look like and what will
the ratio of dissolved to undissolved solute be? If I then slowly cool the mixture to 25 degrees
again, what will my solution look like and what will the ratio be? Finally, if I add one seed
crystal to the mixture, what will my solution look like and what will my ratio be?
Answers
At 25 degrees Celsius, with 50g of sugar, the solution will appear clear and homogeneous, with all the sugar dissolved. The ratio of dissolved sugar to undissolved sugar will be 50:0, as all the sugar has dissolved.
If an additional 55g of sugar is added to the 25-degree water, the solution will become supersaturated. This means that the water cannot dissolve all the sugar, resulting in the excess sugar remaining undissolved as solid particles at the bottom of the container. The solution will appear cloudy, and the ratio of dissolved sugar to undissolved sugar will be 50:5, as only 50g of the added sugar can dissolve.
When the solution is heated, the solubility of sugar increases. As a result, more sugar will dissolve, and the solution will become clear again. The ratio of dissolved sugar to undissolved sugar will approach 105:0 as the temperature increases and more sugar dissolves.
If the heated solution is slowly cooled back to 25 degrees Celsius, the solubility of sugar decreases. This will cause the excess sugar to come out of the solution and form solid crystals, which will be visible as sugar particles. The solution will appear cloudy again, and the ratio of dissolved sugar to undissolved sugar will depend on the amount of sugar that remains dissolved after cooling.
Adding a seed crystal to the mixture provides a surface for sugar crystals to form, resulting in the rapid crystallization of the remaining dissolved sugar. The solution will become saturated with sugar crystals, and the ratio of dissolved sugar to undissolved sugar will be close to 0:55, as most of the sugar will have crystallized. The solution will appear cloudy with a significant amount of sugar crystals present.
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What are 3 ways the turtle has adapted to survive?
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What are all the possible metabolites for the clofibrate structure through metabolism pathways like hydrolysis, alkylation, conjugation, oxidation etc. ?
Answers
Clofibrate is a lipid-lowering pharmaceutical that has been utilized to treat hyperlipidemia. Its metabolism system includes different pathways such as hydrolysis, oxidation, conjugation, and others.
What are a few potential metabolites of clofibrate?Metabolites are little molecules that are produced during the process of metabolism in living living beings.
Clofibrate hydrolysis metabolite:
2-(4-Chlorophenoxy)-2-methylpropanoic acid (phenoxyisobutyric acid)Clofibrate oxidation metabolites:
4-Chlorophenylacetic acid4-Chlorobenzaldehyde4-Chlorophenylacetyl-CoAClofibrate alkylation metabolites:
No specific alkylation metabolites have been widely reported for clofibrate.Clofibrate conjugation metabolites:
Glucuronide conjugatesSulfate conjugatesConclusively, the relative abundance and significance of each metabolite can vary among individuals.
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calculate the formula mass of the unknown acid using the manual titration volume of naoh used to reach an endpoint (procedure step
Answers
To calculate the formula mass of an unknown acid using the volume of NaOH required to reach the endpoint of the titration, you will need to use the following formula: Formula mass = (molarity of NaOH) x (volume of NaOH) x (molar ratio of NaOH to acid) / (moles of acid).
Here are the steps to follow: Write the balanced equation for the reaction between the acid and NaOH.
Record the volume of NaOH which is used in the titration.
Determine the molarity of the NaOH solution. This can be done by dividing the number of moles of NaOH used in the titration by the volume of NaOH used.
Determine the molar ratio of NaOH to acid from the balanced equation.
Calculate the number of moles of acid that reacted with the NaOH by multiplying the volume of NaOH used in the titration by the molarity of NaOH.
Calculate the formula mass of the acid by plugging in the values for the molarity of NaOH, volume of NaOH, molar ratio of NaOH to acid, and moles of acid into the formula given above.
For example, suppose that you titrated an unknown acid with 0.100 M NaOH, and it took 25.0 mL of NaOH to reach the endpoint. The chemical equation for the reaction is:
Acid + NaOH → NaA + H₂O
The molar ratio of NaOH to acid is 1:1. Let's assume that you used 0.025 moles of NaOH in the titration. Then:
Molarity of NaOH = 0.100 M
Volume of NaOH =25.0 mL =0.0250 L
Moles of acid = (0.100 M) x (0.0250 L) x (1 mol acid / 1 mol NaOH) = 0.00250 mol acid
Now, let's assume that the formula mass of the acid is X. Then:
Formula mass = (0.100 M) x (0.0250 L) x (1 mol acid / 1 mol NaOH) / (0.00250 mol acid) = X g/mol
Therefore, the formula mass of the unknown acid is X g/mol.
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--The given question is incomplete, the complete question is
"How to calculate the formula mass of an unknown acid using the manual titration volume of NaOH with which it was titrated, used to reach the endpoint?"--
The first step that you will do in lab is to prepare approximately 20.0 mL each of the following solutions of NaOH, using the NaCl solution to dilute the concentrated (0.300 M) solution of NaOH. After you prepare each solution, transfer it to a clean 50 mL beaker on top of a labeled piece of paper. 0.200 M NaOH 0.150 M NaOH 0.100 M NaOH 0.050 M NaOH 0.025 M NaOH
Answers
Answer:
0.200 M NaOH: 13.3 mL of the concentrated solution and complete to 20.0mL
0.150 M NaOH: 10.0 mL of the concentrated solution and complete to 20.0mL
0.100 M NaOH: 6.67 mL of the concentrated solution and complete to 20.0mL
0.050 M NaOH: 3.33 mL of the concentrated solution and complete to 20.0mL
0.025 M NaOH: 1.67 mL of the concentrated solution and complete to 20.0mL
Explanation:
It is possible to prepare a solution from a more concentrated one. In the problem, the concentrated solution is 0.300M NaOH. Thus, to prepare 20.0mL of each of the solutions you will need:
0.200 M NaOH: 20.0mL × (0.200M / 0.300M) = 13.3 mL of the concentrated solution and complete to 20.0mL
The ratio between the concentrated solution and the solution you want to prepare is called "dilution factor"
0.150 M NaOH: 20.0mL × (0.150M / 0.300M) = 10.0 mL of the concentrated solution and complete to 20.0mL
0.100 M NaOH: 20.0mL × (0.100M / 0.300M) = 6.67 mL of the concentrated solution and complete to 20.0mL
0.050 M NaOH: 20.0mL × (0.050M / 0.300M) = 3.33 mL of the concentrated solution and complete to 20.0mL
0.025 M NaOH: 20.0mL × (0.025M / 0.300M) = 1.67 mL of the concentrated solution and complete to 20.0mL
Put the following energy sublevels in order from least to greatest energy.
A. 1s, 2s, 3s, 4s, 2p, 3p, 4p, 3d, 4d, 4f
B. 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, 4f
C. 1s, 2s, 2p, 3s, 3p, 3d, 4s, 4p, 4d, 4f
D. None of these
Answers
The correct order is 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, 4f. The correct option is B.
Order of energy sublevelsThe correct order of energy sublevel is 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p.
Thus, with the exclusion of 5s, 5p, 6s, 5d, 6p, 7s, 5f, 6d, and 7p, what we have left in order of increasing energy is 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, 4f.
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The correct order from least to greatest energy for the energy sublevels is; 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, 4f (Option B).
What is the Aufbau principle?The Aufbau principle offers a method in which the energy levels in an atoms are arranged from the least to the greatest. We know that electrons are filled into orbitals in order of increasing energy.
Thus, the correct order from least to greatest energy for the energy sublevels is; 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, 4f (Option B).
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A scientist encounters an unknown culture of cells in a laboratory. The only tools available to the scientist to determine the type of cell (animal, prokaryotic, fungal, plant, etc.) are enzymes that degrade particular elements of the extracellular matrix of cells of particular types. Which of the following data would indicate that the unknown cells were from an animal source?
a. The cells are disrupted by application of a lipase (an enzyme that degrades lipids).
b. The cells are disrupted by application of collagenase (an enzyme that degrades collagen).
c. The cells are disrupted by application of cellulase (an enzyme that degrades cellulose).
d. The cells are disrupted by application of lysozyme (an enzyme that degrades peptidoglycan).
Answers
The data that would indicate that the unknown cells are from an animal source is the correct option is b. The cells are disrupted by application of collagenase (an enzyme that degrades collagen).
The data that the cells are the disrupted by the application of collagenase that is an enzyme that degrades collagen. The Animal cells are the standard of the eukaryotic cell, that is enclosed through a plasma membrane. It contains the membrane in certain nucleus and organelles.
The animal cell is a type of the eukaryotic cell that is in lacks of a cell wall and has a true, membrane that is bound to nucleus along with the other cellular organelles.
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A gas has a volume of 50.0 mL at a temperature of 10.0 K and a pressure of 760. kPa. What will be the new volume when the temperature is changed to 20.0 K and the pressure is changed to 380. kPa?
Answers
To solve this problem using the gas laws, we need to use the Ideal Gas Law. This law states that the product of the pressure and the volume of a gas is proportional to the absolute temperature.
The equation of the Ideal Gas Law is the following:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\dfrac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} } \end{gathered}$} }\)
Where:
P₁ = initial pressure = 760 kPaV₁ = initial volume = 50.0 mL = 0.050 LT₁ = initial temperature = 10.0 KP₂ = Final pressure = 380 kPaT₂ = final temperature = 20.0 KV₂ = Final volume = ?We clear for V₂:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{P_1V_1T_2}{P_2T_1 } } \end{gathered}$} }\)
Where:
P₁ = initial pressure V₁ = initial volumeT₁ = initial temperatureP₂ = Final pressureT₂ = final temperatureV₂ = Final volumeSubstituting the known values:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760\not{kPa}\times0.050 \ L\times20.0\not{k} }{ 380\not{kPa}\times10.0\not{k} } } \end{gathered}$} }\)
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760 \ L}{3800 } } \end{gathered}$} }\)
\(\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2\approx0.2 \ Liters} \end{gathered}$} }}\)
When the temperature changes to 20.0 K and the pressure changes to 380 kPa, the new volume will be approximately 0.2 L (200.0 mL).Chemistry Help Please! Worth a lot of points!
1. Joseph Priestly was the first scientist to be able to prepare pure oxygen gas. He did this by heating mercuric oxide as shown in the reaction below. Answer the question related to the reaction.
2HgO(s) = 2Hg(l) + O2(g)
a.What volume of oxygen gas would be produced at STP through the decomposition of 5.36 grams of HgO? It is not collected over water!
b. What volume of oxygen gas would be produced at 23o and 0.975 atm by the decomposition of 5.36 grams of HgO?
c. What volume of oxygen gas would be collected over water at 23oC and 0.975 atm by the decomposition of 5.36 grams of HgO?
2. How many grams of water will form through the reaction of 550 mL of 2.5 M HCl and an excess amount of Ca(OH)2?
Ca(OH)2(aq) + 2HCl(aq) = CaCl2(aq) + 2H2O(l)
a. How many grams of calcium chloride will form if 250 mL of 2.0 M Ca(OH)2 reacts with 350 mL of 2.5 M HCl? Make sure to determine the limiting reagent!
3. Sam conducted an experiment where he reacted 5.0 grams of magnesium with an excess amount of oxygen gas to form magnesium oxide (MgO). When he conducted this in the lab, he obtained 8.06 grams of magnesium oxide.
a. Write and balance the chemical reaction.
b. Use stoichiometry to predict how many grams of magnesium oxide should form.
c. What is the theoretical yield?
d. What is the actual yield?
e. Calculate the percent yield.
4. Na(s) + Br2(L) = NaBr(s) (not balanced)
b.If 3.05 grams of sodium react with 10.0 grams of diatomic bromine, what is the excess reagent AND how many moles of excess reagent are present after the reaction?
c. How many grams of sodium bromide are formed?
Answers
Answer:
A.
1. a. 11.28L O2
b. 24.3L O2
c. 19.83L O2
2. a. 5.6 grams CaCl2
3. a. 2Mg + O2 = 2MgO
b. 8.06 grams MgO
c. 8.06 grams MgO
d. 8.06 grams MgO
e. 100%
4. a. 2Na + Br2 = 2NaBr
b. Excess reagent: Bromine; 0.5 moles
c. 10.6 grams NaBr
Calculate the moles of Iron (III) Sulfide (Fe253) in 218.8 grams. The molar mass of Iron (III) Sulfide is 207.90 g/mol. Do not include units in your response.
Answers
Answer:
1.052
Explanation:
In order to convert from grams of a substance to moles, we need to divide the given mass by the molar mass of the substance:
Moles = Mass / Molar MassAll the required data is given by the problem:
Moles = 218.8 g / 207.90 g/mol = 1.052 molesThere are 1.052 moles in 218.8 grams of iron (III) sulfide.
Make an ionic equation from: V2O5 (s) + 6HCl (aq) => 2VOCl3 + 3H2O (l)
Answers
The net ionic equation of the reaction is; \(6H^+(aq) + 3O^{2-} (aq) ------ > 3H_{2} O(l)\)
What is the net ionic reaction equation?We know that the ionic reaction equation has to do with the equation that shows the species that underwent a change in the reaction. In this case, we have to be able to look at the reaction, break into ions before we can be able to make the molecular reaction equation.
We have;
Molecular equation; \(V_{2}O_{5} (s) + 6HCl (aq) ---- > 2VOCl_{3}(aq) + 3H_{2}O (l)\). We can see the species that have undergone a change from here and the net ionic equation can now be easily written as;
\(6H^+(aq) + 3O^{2-} (aq) ------ > 3H_{2} O(l)\)
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How many moles of aluminum ions al3+ are present in 0.42 mol of al2so43
Answers
There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.
To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.
The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.
Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:
Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)
Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2
Moles of Al3+ = 0.84 mol Al3+
Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.
It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.
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Does a ticking clock involves energy?
Answers
Answer:
yes
Explanation:
is energy from the light source conduction convention or radiation
Answers
What is the total number of atoms contained in 3.63 moles of nickel?
Answers
Answer:
Explanation:
1 mole of nickel contains 6.02 * 10^23 atoms
3.63 mols of nickel contain x atoms.
What you have is a proportion. A proportion consists of 2 ratios or 4 parts.
Of the 4 parts, you know three of them. The problem is to solve for the 4th.
1/3.63 = 6.02*10^23 / x Cross multiply
x = 3.63 * 6.02* 10^23 Combine the right.
Answer: x = 2.19*10^24 atoms