the wing's lifting force as the aircraft slows down to km per hour is around \(6,210\) pounds.
What is the lifting force?Let's begin by writing down the joint variation formula for lifting force, F, area of the wing, A, and the square of the plane's velocity, v:
\(F = k * A * v^2\)
where k is the constant of variation that we need to determine.
We are given that when A \(= 300\) square feet and \(v = 110\) miles per hour, \(F = 12,000\) pounds. Let's use this information to solve for k:
\(12,000 = k * 300 * 110^2\)
\(k = 12,000 / (300 *\times 110^2)\)
\(k \approx 0.00207\)(rounded to at least 5 decimal places)
Now we can use the joint variation formula to find the lifting force on the wing when the plane slows down to \(100\) miles per hour. We know that A is still \(300\) square feet, but v is now \(100\) miles per hour:
\(F = 0.00207 \times 300 \times 100^2\)
\(F \approx6,210\) pounds (rounded to the nearest pound)
Therefore, the lifting force on the wing when the plane slows down to \(100\) miles per hour is approximately \(6,210\) pounds.
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Si 2X -7 = 3, luego 3X + 1 =
(1) 4
(2)5
(3)7
(4)12
(5)16
Answer:
2x-7=3
2x=3+7
{2x=10}÷2
x=5
꧁꧁꧂꧂
3x+1=
{3x=1}÷3
x=1/3
Show that 0-58200-48826-5 is a valid UPC number.
Answer:
Proved
Step-by-step explanation:
Given
\(UPC = 0-58200-48826-5\)
Required
Show that it is valid
Add up the elements at odd positions
\(Odd = 0 + 8 + 0 + 4+8+6\)
\(Odd = 26\)
Multiply by 3
\(Product = 26 * 3\)
\(Product = 78\)
Add up the elements at even positions
\(Even = 5 + 2 + 0 + 8 + 2 + 5\)
\(Even = 22\)
Add up both results
\(Result = 78 +22\)
\(Result = 100\)
Take modulus of 10
\(Result \% 10 = 100 \% 10\)
\(Result \% 10 = 0\)
Since the result of the modulus is 0, then the number is valid
Pls help me with this question.
Answer:
x=1Step-by-step explanation:
\( \frac{5(x + 6) - 15(2 - x)}{3x - 1} = 10 \\ \)
\( = > 5(x + 6) - 15(2 - x) = 10(3x - 1)\)
\(5x + 30 - 30 + 15x = 30x - 10\)
\( = > 20x = 30x - 10 \\ = > 20x - 30x = - 10 \\ = > - 10x = - 10 \\ = > x = 1\)
hope it helps:)
The pattern follows the "add one dot to the top of each column and one dot to the right of each row" rule. What will the 6th term be? (1 point)
A pattern showing the square term number rule. The first term has one dot. The second term has four dots. The third term has nine dots. The fourth term has sixteen dots.
a
36
b
49
c
64
d
81
The pattern for the 6th term of the sequence is A₆ = 36
Given data ,
The first term has one dot (1² = 1)
The second term has four dots (2² = 4)
The third term has nine dots (3² = 9)
The fourth term has sixteen dots (4² = 16)
So , the fifth term A₅ = 25
And , from the pattern , the 6th term A₆ = 36
Hence , the 6th term is A₆ = 36
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What is Precession? Group of answer choices
Deviations in the circularity of the orbit
Changes in the rate of Earth's Spin
Changes in the magnitude of the angle of tilt
Changes in the orientation of the axis of rotation
Precession is a phenomenon that refers to the gradual and continuous change in the orientation of the Earth's rotational axis over long periods of time.
This shift in the orientation of the axis of rotation results in changes in the position of the celestial pole with respect to the stars, which causes a shift in the apparent position of stars over time. The precession of the Earth's axis is caused by the gravitational forces of the Sun, Moon, and other planets in the solar system.
Precession is characterized by changes in the magnitude of the angle of tilt, which causes changes in the rate of the Earth's spin. As the axis of rotation moves, it causes the length of the day to change over time. Additionally, deviations in the circularity of the orbit also affect the precession of the Earth's axis.
Precession is a significant phenomenon in astronomy and has been observed for thousands of years. It has important implications for studies of astronomy, geology, and climate change. For instance, precession affects the timing of the seasons and has a significant impact on the Earth's climate. It also affects the orientation of the Earth's magnetic field, which has important implications for navigation and communication systems.
In conclusion, precession is the gradual change in the orientation of the Earth's rotational axis, caused by the gravitational forces of the Sun, Moon, and other planets. It results in changes in the magnitude of the angle of tilt, changes in the rate of Earth's spin, and deviations in the circularity of the orbit. Precession has significant implications for various fields of study, including astronomy, geology, and climate change.
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If two individuals in the same population have identical X scores, they also will have identical z-scores.
TRUE or FALSE
TRUE. If two individuals in the same population have identical X scores, they also will have identical z-scores.
The z-score of an individual in a population is calculated using the formula:
z = (X - μ) / σ
where X is the individual's score, μ is the population mean, and σ is the population standard deviation.
If two individuals in the same population have identical X scores, it means they have the same value for X. Therefore, when calculating the z-score for each individual using the same population mean and standard deviation, the numerator (X - μ) will be the same for both individuals.
Since the numerator is the same, the z-score for both individuals will also be the same. Therefore, if two individuals have identical X scores in a population, they will have identical z-scores. Hence, the statement is TRUE.
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Which of the following subsets of P2(R) are subspaces of P2(R)? Note: P2(R) is the vector space of all real polynomials of degree at most 2.A. {p(t) | p?(t)+1p(t)+6=0}B. {p(t) | p(?t)=?p(t) for all t}C. {p(t) | p(4)=7}D. {p(t) | \int_{-1}^{7}p(t)dt=0E. {p(t) | p?(8)=p(0)}F. {p(t) | p(3)=0}
The followings A, C, D, and F subsets of P₂ are subspace of P₂.
The subsets of P₂ that are subspace of P₂ are A, C, D, and F.
A.{p(t) | p'(t)+1p(t)+6=0} is a subspace of P₂ because it satisfies the criteria of being closed under addition and scalar multiplication.
B.{p(t) | p('t)='p(t) for all t} is not a subspace of P₂ because the derivative of p(0) does not equal p(4).
C. {p(t) | p(4)=7} is a subspace of P₂ because it satisfies the criteria of being closed under addition and scalar multiplication.
\({p(t) | \int_{-1}^{7}p(t)dt=0\) is constant } is a subspace of P₂ because it satisfies the criteria of being closed under addition and scalar multiplication.
E. {p(t) | '(8) = p(0)} is not a subspace of P₂ because the derivative of p(8) does not equal 0.
F. {p(t) | p(3)=0} for all t} is a subspace of P₂ because it satisfies the criteria of being closed under addition and scalar multiplication.
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Help me please :) thank you
Answer:
a=90°
c=45°
b=45°
Step-by-step explanation:
this triangle is a right triangle. (shown by the box in angle a) this means a must equal 90°
and by extension means the other two angles have to equal 45° each because right angles always have two angles of the same degree and the angles of a triangle always Equal 180°
Tatianna withdrew $20 from her bank account 3 times.how much did her account change? write your answer as an integer.
Answer:
$216
Step by step
Explanation:
First we subtract $ 20 from $ 84 giving us a total of $ 64 and when we add that to $ 152 we get $ 216
.
Answer:
-60
Step-by-step explanation:
factorize:-
x³–3x²–9x–5
no links or spam answers please!
Answer:
X³ – 3x² – 9x – 5
= x³ + x² – 4x² – 4x – 5x – 5
= x²( x + 1) – 4x ( x + 1) – 5(x + 1)
= (x + 1)(x² – 4x – 5)
= (x + 1)(x² -5x + x – 5)
= (x + 1)(x – 5) (x + 1)
hence, (x +1), (x -5) and (x +1) are the factors of given polynomial .
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physics
Joseph Jogs from one end A to the other end B of a straight
300m road in 2 minutes 30 second then turns around and jogs 100 m back to point C in another minute. What are Josef's Average speeds and velocities in jogging from
a) A to B
and
b) A to C
pls give answer with explination do not send link
Answer:
a) Josef jogging from A to B;
i. speed = 2 m/s
ii. velocity = 2m/s
a) a) Josef jogging from A to C;
speed = 1.9 m/s
ii. velocity = 2.2 m/s
Step-by-step explanation:
One major difference between speed and velocity is that speed is a scalar quantity, while velocity is a vector quantity.
a) Josef jogging from A to B;
distance = 300 m
time = 2.5 seconds = 150 seconds
i. his average speed = \(\frac{distance}{time}\)
= \(\frac{300}{150}\)
= 2 m/s
ii. his average velocity = \(\frac{displacement}{time}\)
= \(\frac{300}{150}\)
= 2 m/s
b) Josef jogging from A to C,
distance = 300 + 100 = 400 m
time = 2.5 + 1 = 3.5 minutes
= 210 seconds
i. his average speed = \(\frac{distance}{time}\)
= \(\frac{400}{210}\)
= 1.9 m/s
ii. his average velocity = \(\frac{\sqrt{V_{1} ^{2} + V_{2} ^{2} } }{2}\)
\(V_{1} ^{2}\) = 4 m/s
\(V_{2} ^{2}\) = 1.9 m/s
his average velocity = \(\frac{\sqrt{4^{2} + 1.9^{2} } }{2}\)
= 2.2 m/s
Give the value of M and C.
Answer:
y = 5x - 3, so M = 5 and C = -3.
Please help me don’t have that much time please and thank you
\(f(x)=\frac{1}{9}x-2\\ take:\\x=f(x)^{-1}\\\\f(x)=X\\\\X=\frac{1}{9}f(x)^{-1}-2\\\\(X+2)9 =f(x)^{-1} \\\\f(x)^{-1}=9X+18\\\)
Answer:
22
Step-by-step explanation:
ftrrrrgd fff fftttr fddd
what is the GCF of 12x^2 and 18x
Answer: 6x
Step-by-step explanation:
Factor each term and see what they have in common.
12x²: 2 · 2 · 3 · x · x
18x: 2 · 3 · 3 · x
The common factors are: 2 · 3 · x = 6x
Suppose you paid $150 for a ticket to see your university’s football team compete in a bowl game. Someone offered to buy your ticket for $400, but you decided to go to the game.
Required:
1. What did it really cost you to see the game?
2. What type of cost is this?
The actual cost to see the game is $150, as that is the amount you paid for the ticket. The cost in this scenario can be considered an opportunity cost. By choosing to attend the game instead of selling the ticket for $400, you forgo the opportunity to earn that additional $400.
In this scenario, the cost of attending the game refers to the actual amount of money you spent on the ticket, which is $150. This is the out-of-pocket expense that directly affects your financial resources.
On the other hand, the opportunity cost is the potential benefit or value that you give up by choosing one option over another. In this case, if you had sold the ticket for $400, you would have received a higher amount of money, which represents the opportunity cost of attending the game. By deciding to go to the game, you forego the opportunity to earn that additional $400.
Opportunity cost is a concept in economics that emphasizes the value of the next best alternative forgone when making a decision. It helps assess the trade-offs involved in different choices and helps in evaluating the true cost of a decision beyond the immediate financial expenses.
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Benjamin is turning 9 and wants to have his birthday party at Party Zone Palace. Party Zone Palace offers several different birthday packages. The pricing for three packages are displayed below.
a. Does Package C represent a function? Explain your reasoning.
b. Explain how you know that Package A and Package B represent linear functions.
a) Where the above condition exists, it is correct to state that, yes, Package C represents a function, specifically a step function.
b) We know that Package A and Package B represent linear functions because they have a constant rate of change, or slope.
What is a step function?A step function is a function that has a constant value over a series of intervals, and the value changes abruptly from one interval to the next.
A) With regards to the Benjamin's conditions, Package C represents a function, specifically a step function. It relates the cost of a birthday package to the number of people attending the party. The function takes on different constant values for different intervals of the number of people. For example, if x represents the number of people attending the party, then:
C(x) = 15, if 1 ≤ x ≤ 15
C(x) = 12, if 16 ≤ x ≤ 30
C(x) = 9, if x > 30
So, if Benjamin is expecting 25 guests, his birthday package cost would be $12 per person, or a total of $300.
B)
We know that Package A and Package B represent linear functions because they have a constant rate of change, or slope. In Package A, the cost is determined by multiplying the number of people by a fixed rate of $8, and then adding a constant value of $12. This can be written as:
C(p) = 8p + 12
where p is the number of people attending the party.
The slope of this function is 8, indicating that for each additional person, the cost of the package increases by $8.
Similarly, in Package B, the cost is determined by the total number of people attending the party, and the cost varies linearly with the number of people. This can be represented as:
C(x) = mx + b
where x is the number of people, m is the slope (rate of change), and b is the y-intercept (constant term).
Since the cost varies linearly with the number of people, we know that the slope is constant, indicating that the function represents a linear relationship between the number of people and the cost of the package.
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Please do not send me something to download just give the answer plainly. Ill give u points and brainiest. ASAP
Answer: 624 ft^3
work is in the image i attached
How many unique triangles are there in the regular hexagon?
Answer:
Step-by-step explanation: There are 6 equilateral triangles in a regular hexagon by connecting the opposite vertices of a regular hexagon.
which graph represents a line perpendicular to the line with the equation y=-1/5x+6?
Answer:
y = 5x + 6
Step-by-step explanation:
Remember:
Parallel: The slope is the same
Perpendicular: The slope is the opposite reciprocal
If we look at the equation \(y=-\frac{1}{5}x+6\), it is in slope intercept form and its slope is -1/5. Now, we will first need to flip the fraction and get rid of the negative sign.
\(y=5x+6\)
And we are done!
In triathlons, it is common for racers to be placed into age and gender groups. Friends Leo and Mary both completed the Hermosa Beach Triathlon, where Leo competed in the Men, Ages 30 - 34 group while Mary competed in the Women, Ages 25 - 29 group. Leo completed the race in 1:22:28 (4948 seconds), while Mary completed the race in 1:31:53 (5513 seconds). Obviously Leo finished faster, but they are curious about how they did within their respective groups. Can you help them? Here is some information on the performance of their groups:The finishing times of the Men, Ages 30 - 34 group has a mean of 4313 seconds with a standard deviation of 583 seconds.The finishing times of the Women, Ages 25 - 29 group has a mean of 5261 seconds with a standard deviation of 807 seconds.The distributions of finishing times for both groups are approximately Normal.if the distributions of finishing times are not nearly normal, would the values of the standard score in part a change? explain your reasoning.
Yes, I can help them determine how they did within their respective groups. A higher Z-score indicates a faster time compared to the average for their group, while a lower Z-score indicates a slower time.
To do this, we will calculate the standard score or Z-score for each of them, which measures how many standard deviations above or below the mean their finishing time was. Calculation is as follows:
For Leo:
Z = (4948 - 4313) / 583 = 1.01
For Mary:
Z = (5513 - 5261) / 807 = 0.33
So, Leo finished 1.01 standard deviations above the mean for the Men, Ages 30 - 34 group, while Mary finished 0.33 standard deviations below the mean for the Women, Ages 25 - 29 group.
As for your second question, if the distributions of finishing times were not nearly normal, then the values of the standard score would change. This is because the standard score is calculated using the mean and standard deviation, which are important parameters of a normal distribution, these parameters may not accurately represent the data, and therefore the standard score would not be an accurate measure of relative performance.
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Point L is on line segment \overline{KM}
KM
. Given LM=3x+3,LM=3x+3, KM=5x+4,KM=5x+4, and KL=5x+1,KL=5x+1, determine the numerical length of \overline{KM}.
KM
.
9514 1404 393
Answer:
KM = 4
Step-by-step explanation:
The point of the segment addition postulate is that the combined length of segments laid end-to-end is the sum of their individual lengths.*
KL +LM = KM
(5x +1) +(3x +3) = 5x +4
8x +4 = 5x +4 . . . .simplify
3x = 0 . . . . . . . . . . subtract 5x+4
x = 0 . . . . . . . . . . . divide by 3
Then the length of KM is ...
KM = 5x +4 = 5·0 +4 = 0 +4
KM = 4
_____
* Sometimes it seems that geometrical theorems simply state the obvious. Some interesting math arises from systems of geometry in which this is not true. We usually don't study those in high school.
Please help me will greatly appreciate it TYSM
Organisms A and B start out with the same population size.
Organism A's population doubles every day. After 6 days, the
population stops growing and a virus cuts it in half every day for 4
days.
Organism B's population grows at the same rate but is not infected
with the virus. After 10 days, how much larger is organism B's
population than organism A's population?
Answer:
At the end of ten days, the size of population B is 256 times that of population A
Step-by-step explanation:
We work under the premise that population A and B start both with the same number of individuals. Let's call such initial population \(N_0\)
Now, we write the exponential expression that describes population A as a function of days (t) for the first 6 days:
\(N_A=N_0\,(2)^t\)
which represents the starting point with \(N_0\) individuals on day zero, doubling after one day (t= 1), and keeping on doubling the following days for 6 days.
So at the end of 6 days, population A would have the following number of individuals:
\(N_A=N_0\,(2)^6\\N_A=N_0\,(64)\\N_A=64\,N_0\)
That is 64 times the starting number of individuals.
After this, the population stops growing and starts reducing to one-half each day. This behavior can be represented by:
\(N_A=64\,N_0\,(\frac{1}{2} )^t\)
therefore after 4 days in this pattern, this culture has the following number of organisms:
\(N_A=64\,N_0\,(\frac{1}{2} )^4\\N_A=64\,N_0\,(\frac{1}{16} )\\N_A=4\,N_0\)
which is now just four times what the culture started with.
Now, on the other hand, population B grows doubling each day without interruption, so at the end of 10 days its size is given by:
\(N_B=N_0\,(2)^t\\N_B=N_0\,(2)^10\\N_B=N_0\1024\\N_B=1024\,N_0\)
that is it has 1024 times the initial number of organisms.
So if we compare both populations at day 10:
\(\frac{N_B}{N_A} =\frac{1024\/N_0}{4\,N_0} =256\)
Therefore, at the end of ten days, population B is 256 times the size of population A
Answer:
After 10 days, population B has grown to be 256 times the size of population A.
Step-by-step explanation:
5.5.4 (TST) - Systems of Linear Equations
Answer:
I dont see a
Step-by-step explanation:
1/4 of a box of erasers and you need to share them with a total of 3 people inculding yourself what fraction ofthe box should each person get
Answer:
1/12
Step-by-step explanation:
1/4*3
whats the answer ? and can you show your work if you dont mind me asking ?
Answer:
f(-1)=-2
Step-by-step explanation:
f(x)=-3x-5x^2
f(-1)=-3(-1)-5(-1)^2
f(-1)=-3(-1)-5(1)
f(-1)=3-5
f(-1)=-2
Match each situation to its corresponding expression.
150(0.4)^n
2,500 (1.11)^n
150(0.6)^n
2,500(0.11)^n
In a singing competition, there are
150 participants. At the end of each round, 40% of the participants are
eliminated. How many participants
are left after n rounds?
At the start of an experiment, there are 2,500 bacteria in a colony. The colony grows at a rate of 11% every hour. What will be the number of bacteria in the colony after n hours?
Answer:
(c) 150(0.6^n)(b) 2500(1.11^n)Step-by-step explanation:
Exponential growth or decay can be modeled by the exponential function ...
f(n) = a×b^n
where 'a' is the initial value, and 'b' is the growth factor. The growth factor is ...
b = 1 +r
where r is the growth rate. If decay is involved, the sign of r will be negative.
__
competitionIf 40% of the participants are eliminated each round, then the growth rate per round is -40% = -0.40, and the growth factor is ...
b = 1 -0.40 = 0.60
The initial number of participants is 150, so the number remaining after n rounds is ...
f(n) = 150×0.60^n . . . . . . matches the 3rd choice
__
bacteriaThe growth rate of 11% per hour means the growth factor is ...
b = 1 +11% = 1.11
The initial population is 2500, so the population after n hours is ...
f(n) = 2500×1.11^n . . . . . . matches the 2nd choice
Use the following diagram to solve this problem.
Answer:
x = 19EF = 285m∠EDG = 32°Step-by-step explanation:
EF = FG
9x + 114 = 15x
114 = 15x - 9x
x = 114 / 6
x = 19
Solve EF: substitute x into the equation
EF = 9x + 114
= 9(19) + 114
= 285
m∠EDG = 32°
Multiply the radical expression and simplify your answer. (30 points)
Would prefer work shown as it would be helpful. Thank you.
-2\(\sqrt{6x^{8}y^{3}}\) * 4\(\sqrt{10xy^{8}}\)
You can move \(x^{8}\), \(y^{3}\) and \(y^{8}\) out of the square root to get
-2\(x^{4}\)\(y\)\(\sqrt{6y}\) * 4\(y^{4}\)\(\sqrt{10x}\)
Multiply them
-8\(x^{4}y^{5}\sqrt{60xy}\)
You can take 4 out of 60 to get 2
-16\(x^{4}y^{5}\sqrt{15xy}\)
The probabilty of it raining on a given day is 3/8 what is the probabilty of it not raining?
Answer:
5/8
Step-by-step explanation:
If 3/8 IS raining, then the remaining 8ths is NOT raining. 8 - 3 = 5. So, 5/8 is NOT raining.
I hope this helps!
Answer:
5/8
Step-by-step explanation:
To find the probability of it not raining, subtract 3/8 from 1.
1 - 3/8
= 5/8
Since the probability of it raining is 3/8, this must mean that during the rest of the time, it will not rain.
So, the probability of it not raining is 5/8