The lift on a spinning circular cylinder in a freestream with a velocity of 30 m/s and at standard sea level conditions is 6 N/m of span. The circulation around the cylinder is 0.164 m2/s.
The circulation around the cylinder, we can use the formula:
Circulation = Lift / (density * velocity * span)
Where density is the density of air at standard sea level conditions, which is approximately 1.225 kg/m3.
Substituting the given values, we get:
Circulation = 6 / (1.225 * 30 * 1)
Circulation = 0.1638 m2/s
Rounding to three decimal places, the circulation around the cylinder is 0.164 m2/s.
Therefore, the circulation around the cylinder is 0.164 m2/s.
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An automobile having a mass of 1100 kg initially moves along a level highway at 120 km/h relative to the highway. It then climbs a hill whose crest is 80 m above the level highway and parks at a rest area located there. Use a reference with kinetic and potential energy each equal to zero for the stationary highway before the hill. Let g = 9.81 m/s^2.
For the automobile, determine its change in kinetic energy and its change in potential energy, both in kJ. For the automobile, determine its change in kinetic energy, in kJ.
a. -8594
b. -663.1
c. -6.63x10^5
d. 663.1
Answer:
\(-6111.11\ \text{kJ}\)
\(863.28\ \text{kJ}\)
Explanation:
m = Mass of automobile = 1100 kg
v = Velocity of car = 120 km/h = \(\dfrac{120}{3.6}\ \text{m/s}\)
h = Height of hill = 80 m
g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)
Change in kinetic energy
\(KE=\dfrac{1}{2}m(u^2-v^2)\\\Rightarrow KE=\dfrac{1}{2}\times 1100\times (0-(\dfrac{120}{3.6})^2)\\\Rightarrow KE=-611111.11\ \text{J}\)
Change in kinetic energy is \(-6111.11\ \text{kJ}\)
Change in potential energy is given by
\(PE=mgh\\\Rightarrow PE=1100\times 9.81\times 80\\\Rightarrow PE=863280\ \text{J}\)
The change in potential energy is \(863.28\ \text{kJ}\).
a dense, hot body will give off a(n) _____ spectrum.
A dense, hot body will give off a continuous spectrum.
This type of spectrum is produced when all wavelengths of light are emitted from the source, creating a continuous band of colors with no gaps or breaks.
A dense, hot body such as a star or a light bulb filament will emit a continuous spectrum because the atoms within it are excited and vibrating at high speeds, causing them to emit light at all wavelengths.
The temperature of the body will also affect the shape and intensity of the continuous spectrum. As the temperature increases, the spectrum will shift towards the blue end of the spectrum, and the intensity of the light will increase.
This is known as the blackbody radiation curve, which describes the relationship between the temperature of an object and the amount of light it emits.
The continuous spectrum is important in astronomy because it can be used to determine the temperature and composition of stars.
By analyzing the spectrum of starlight, astronomers can identify the chemical elements present in the star's atmosphere and determine its temperature. This information can help us to better understand the properties and behavior of stars, as well as the processes that occur within them.
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There are multiple challenges associated with making effective e-teams. Which of the following is not a challenge?
A. Process losses result from identification and combination activities. B. E-teams can be effective in generating social capital. C. The physically dispersed team is susceptible to the risk factors that can create process loss. D. Some collective energy, time, and effort must be devoted to dealing with team inefficiencies
"E-teams can be effective in generating social capital" is not a challenge associated with making effective e-teams.
So, the correct answer is B.
The other options, A, C, and D, all highlight the challenges associated with making effective e-teams.
Process losses can occur due to the identification and combination activities of team members, physically dispersed teams are susceptible to risk factors that can create process loss, and some collective energy, time, and effort must be devoted to dealing with team inefficiencies
Hence, the answer of the question is B.
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When preparing a propeller blade for inspection itshould be cleaned withA— mild soap and water.B— steel wool.C— methyl ethyl ketone
When preparing a propeller blade for inspection, it should be cleaned with mild soap and water. The correct option is A.
A propeller blade is a rotating wing that produces a force that drives a ship, airplane, or other vehicle through the water or air by acting on the water or air and generating thrust. An inspection is a formal or official examination or assessment of something, particularly one that is carried out in order to determine its condition or to assess its safety or compliance with regulations. In the aviation industry, propeller blades are subjected to regular inspections to detect any abnormalities that may have an impact on the blade's efficiency or flight safety. When inspecting the propeller blades, it is critical to clean them before performing any assessments. Propeller blades should be cleaned with mild soap and water to get rid of any debris, dust, or other particles that may have settled on the surface. Steel wool is too rough and can damage the blade surface, and methyl ethyl ketone is a powerful solvent that should not be used unless advised to by a specialist or a manufacturer. Therefore, when preparing a propeller blade for inspection, it should be cleaned with mild soap and water.
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In the figure show, what's the distance from point H to point C?
A. 2'
B. 18'6"
C. 18'
D. 2'6"
Answer:
B.
Explanation:
I think not sure hehe
What would be the steady-state analog output of the system, ya(t)?
Give an analytical expression (some kind of cos( ) ) for the output signal ya(t); not a Matlab plot. Use your analytical expressions for H(F) to find the system response to this cos( ) signal and from that determine the analog output. Assume a sample rate S = 16 KHz and ideal A/D and D/A conversions.
The analytical expression for the output signal ya(t) would be:
ya(t) = (A/2) [cos((F + t)θ) + cos((F - t)θ)]
Let's assume that the transfer function of the system is represented as H(F), where F represents the frequency.
We can express the input cosine signal as cos(2πFt), where t represents time.
The output signal ya(t) can be obtained by multiplying the input signal with the system's transfer function H(F) in the frequency domain. Mathematically, this can be represented as:
Ya(F) = H(F) x Cos(Ft)
Let's assume that at the frequency F, the transfer function H(F) can be represented as H(F) = A x cos(θ),
where A represents the magnitude and θ represents the phase shift.
Substituting this into the equation, we get:
Ya(F) = A x cos(θ) x cos(Ft)
Using the trigonometric identity
cos(A) cos(B) = (1/2) [cos(A + B) + cos(A - B)]
Ya(F) = (A/2) [cos((F + t)θ) + cos((F - t)θ)]
Therefore, the analytical expression for the output signal ya(t) would be:
ya(t) = (A/2) [cos((F + t)θ) + cos((F - t)θ)]
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Derive the equations of motion for flight at constant altitude and constant velocity.Show that these equations have zero mathematical degrees of freedom. Also, show that Eqs. (2.24) reduce to
these equations when combined with h=Const and V = Const.
We have shown that equations (2.24), when combined with h = const (constant altitude) and V = const (constant velocity), reduce to the equations of motion with zero degrees of freedom, as given by equations (12) and (13).
To derive the equations of motion for flight at constant altitude and constant velocity, we can start with the basic principles of flight dynamics. We'll assume the following variables:
h: altitude (constant)
V: velocity (constant)
m: mass of the aircraft
g: acceleration due to gravity
T: thrust
D: drag
L: lift
The equations of motion for flight can be written as:
ΣF_x = m * a_x (1)
ΣF_y = m * a_y (2)
ΣF_z = m * a_z (3)
where ΣF_x, ΣF_y, and ΣF_z represent the sum of forces in the x, y, and z directions, respectively, and a_x, a_y, and a_z represent the corresponding accelerations.
Considering flight at a constant altitude, we can neglect the vertical acceleration, a_z, because it is balanced by the lift and weight forces. Therefore, equation (3) reduces to:
ΣF_z = 0 (4)
Since the altitude, h, is constant, the lift force, L, is equal to the weight force, m * g:
L - m * g = 0 (5)
Combining equations (4) and (5), we have:
L = m * g (6)
Next, let's consider flight at a constant velocity. In this case, the sum of forces in the x-direction, ΣF_x, is equal to zero since there is no acceleration in that direction:
ΣF_x = 0 (7)
The thrust force, T, is balanced by the drag force, D:
T - D = 0 (8)
Combining equations (7) and (8), we have:
T = D (9)
Now, we can substitute equations (6) and (9) back into equations (1) and (2) to eliminate the variables L, T, and D:
ΣF_x = m * a_x = D - T = 0 (10)
ΣF_y = m * a_y = L - m * g = 0 (11)
Since the aircraft is flying at constant altitude and constant velocity, the accelerations in the x and y directions, a_x and a_y, are both zero. Therefore, equations (10) and (11) reduce to:
0 = 0 (12)
0 = 0 (13)
Equations (12) and (13) represent trivial identities, meaning they hold true regardless of the values of the variables involved. Consequently, these equations have zero mathematical degrees of freedom.
Therefore, we have shown that equations (2.24), when combined with h = const (constant altitude) and V = const (constant velocity), reduce to the equations of motion with zero degrees of freedom, as given by equations (12) and (13).
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According to Ref. 213/91, fire extinguishing equipment can be frozen True or False
False. Fire extinguishing equipment cannot be frozen according to Ref. 213/91.
According to Ref. 213/91, fire extinguishing equipment cannot be frozen. Fire extinguishers are essential safety devices designed to combat fires effectively. They contain pressurized agents that are specifically formulated to extinguish different types of fires. Freezing temperatures can significantly impair the functionality of fire extinguishers and render them ineffective in emergency situations.
When fire extinguishing equipment freezes, several issues can arise. First, the contents of the extinguisher may expand as they freeze, potentially leading to ruptures or leaks in the container. This can cause the extinguisher to malfunction or become hazardous when used. Second, freezing temperatures can affect the performance of the extinguishing agent itself. Certain agents, such as water-based solutions, can solidify or lose their effectiveness when exposed to extreme cold.
It is crucial to store fire extinguishers in suitable environments that are above freezing temperatures. This ensures that the equipment remains in optimal condition and is ready for immediate use during emergencies. Regular inspections and maintenance are also essential to identify any signs of damage or deterioration that may compromise the functionality of fire extinguishers.
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Q1-A Lossless transmission line is 80 cm long and operates at a frequency of 500 MHz. Two line parameters are L=0.15μH/m and C=90pf/m. Find the characteristic impedance the phase constant, the velocity on the line, and the input impedance for ZL =80 Ω
The characteristic impedance, the phase constant, the velocity on the line, and the input impedance are respectively;
A) Z_o = 40.82 Ω
B) β = 11.543 rad/m
C) v_p = 2.72 × 10^(8) m/s
D) Z_in = 115.91 Ω
We are given;
Inductance; L = 0.15 μH/m = 0.15 × 10^(-6) H/m
Capacitance; C = 90 pf/m = 90 × 10^(-12) f/m
Frequency; f = 500 MHz = 500 × 10^(6) Hz
Load impedance; Z_l = 80 Ω
Length of transmission line; l = 80cm = 0.8m
A) Formula for characteristic impedance is;
Z_o = √(L/C)
Thus;
Z_o = √((0.15 × 10^(-6))/(90 × 10^(-12)))
Z_o = 40.82 Ω
B) Formula for the phase constant is;
β = ω√(LC)
Where;
ω = 2πf
Thus;
β = (2π × 500 × 10^(6))√(0.15 × 10^(-6) × 90 × 10^(-12))
β = 11.543 rad/m
C) Formula for phase velocity is;
v_p = ω/β
v_p = (2π × 500 × 10^(6))/11.543
v_p = 2.72 × 10^(8) m/s
D) Formula for the input impedance is;
Z_in = Z_o[(Z_l + Z_o*tanβl)/(Z_o + Z_l*tanβl)]
Z_in = 40.82[(80 + 40.82*tan(11.543*0.8))/(40.82 + 80*tan(11.543*0.8))]
Z_in = 40.82(72.1335/25.4031)
Z_in = 115.91 Ω
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After a strong storm, a worker does not realize that a power transmission line has fallen on his car and is electrocuted while opening the car door. What is this an example of?.
Answer:
This is an example of the conduction of electricity through metal. Free moving electrons on the car will conduct a electric field when a voltage is applied to the car; in this case the transmission line, and would flow through the metal to the door handle causing electrocution.
Hey guys can anyone list chemical engineering advancement that has been discovered within the past 20 years
Which of the following is not an advantage of Automated equipment operating systems?l
Machines are much more flexible than human is false and thus not an advantage of Automated equipment operating systems.
What Does Automated System Operations (ASO) Mean?
The set of software and hardware that allows computer systems, network devices, or machines to function without manual intervention is known as automated system operations (ASO).
ASOs enable computer systems to operate without the presence of a human operator at the location where the system is installed. Automated system operations are a subset of automatic system control in which processes are fully automated using control loops and special logic.
Lights-out operations are another term for automated system operations.
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Find the first-order kinematic coefficient of the gear train. What are the speed and direction of rotation of gear 8? ω,-1200 rev/min 4 15T 44T 33T 36T 487
The first-order kinematic coefficient of the gear train is 0.028. Gear 8 rotates in the clockwise direction with a speed of 42.86 rev/min.
What is the rotational direction and speed of gear 8 and what is the first-order kinematic coefficient of the gear train?The first-order kinematic coefficient of the gear train is a measure of the efficiency of power transmission through a gear train. It is defined as the ratio of the output speed of the final gear to the input speed of the first gear. In this case, the first-order kinematic coefficient is 0.028, which means that the output speed of gear 8 is only 2.8% of the input speed of gear 4.
To determine the rotational direction and speed of gear 8, we first need to identify the gear ratios for each pair of gears in the train. Starting from gear 4, we have a gear ratio of 44/15, which means that gear 5 rotates at a slower speed than gear 4 but with higher torque. Similarly, the gear ratio between gears 5 and 6 is 33/36, which means that gear 6 rotates at a faster speed than gear 5 but with lower torque.
Finally, we can calculate the speed and direction of rotation of gear 8 by multiplying the gear ratios of all the gears between gear 4 and gear 8. We have:
44/15 * 33/36 * 487/36 = 42.86
This means that gear 8 rotates at a speed of 42.86 rev/min in the clockwise direction.
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Neon is compressed from 100 kPa and 20◦C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and specific enthalpy of neon caused by this compression
Answer:
The specific volume is reduced in 80 per cent due to isothermal compression.
Specific enthalpy remains constant.
Explanation:
Let suppose that neon behaves ideally, the equation of state for ideal gases is:
\(P\cdot V = n\cdot R_{u}\cdot T\)
Where:
\(P\) - Pressure, measured in kilopascals.
\(V\) - Volume, measured in cubic meters.
\(n\) - Molar quantity, measured in kilomoles,
\(T\) - Temperature, measured in kelvins.
\(R_{u}\) - Ideal gas constant, measured in \(\frac{kPa\cdot m^{3}}{kmol\cdot K}\).
On the other hand, the molar quantity (\(n\)) and specific volume (\(\nu\)), measured in cubic meter per kilogram, are defined as:
\(n = \frac{m}{M}\) and \(\nu = \frac{V}{m}\)
Where:
\(m\) - Mass of neon, measured in kilograms.
\(M\) - Molar mass of neon, measured in kilograms per kilomoles.
After replacing in the equation of state, the resulting expression is therefore simplified in term of specific volume:
\(P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T\)
\(P\cdot \nu = \frac{R_{u}\cdot T}{M}\)
Since the neon is compressed isothermally, the following relation is constructed herein:
\(P_{1}\cdot \nu_{1} = P_{2}\cdot \nu_{2}\)
Where:
\(P_{1}\), \(P_{2}\) - Initial and final pressure, measured in kilopascals.
\(\nu_{1}\), \(\nu_{2}\) - Initial and final specific volume, measured in cubic meters per kilogram.
The change in specific volume is given by the following expression:
\(\frac{\nu_{2}}{\nu_{1}} = \frac{P_{1}}{P_{2}}\)
Given that \(P_{1} = 100\,kPa\) and \(P_{2} = 500\,kPa\), the change in specific volume is:
\(\frac{\nu_{2}}{\nu_{1}} = \frac{100\,kPa}{500\,kPa}\)
\(\frac{\nu_{2}}{\nu_{1}} = \frac{1}{5}\)
The specific volume is reduced in 80 per cent due to isothermal compression.
Under the ideal gas supposition, specific enthalpy is only function of temperature, as neon experiments an isothermal process, temperature remains constant and, hence, there is no change in specific enthalpy.
Specific enthalpy remains constant.
1)How do you distinguish between positive and negative logic system? Prove that an OR gate in a positive logic System is an AND gate in a negative logic system.
2)Give a brief statement that would help one remember the truth table of AND ,NAND, OR, NOR, EX-OR and EX -NOR logic gate functions ,irrespective of the number of input used.
Answer:
Positive logic is defined as a high voltage level representing a logic 1 and a low voltage level representing a logic 0. Negative logic is the reverse, i.e., a low voltage level represents a logic 1 and a high voltage level represents a logic 0.
Explanation:
Thanks
The conventional procedure requires one behavior and two antecedent stimulus conditions. Responses are reinforced in the presence of one stimulus condition, the SD, but not in the presence of the other stimulus, the S∆.
Hi! Your question involves the conventional procedure that requires one behavior and two antecedent stimulus conditions. In this procedure, responses are reinforced in the presence of the stimulus condition SD, but not in the presence of the other stimulus condition, S∆.
Step-by-step explanation:
1. A stimulus (SD) is presented, signaling that reinforcement is available for the specific behavior.
2. The individual performs the desired behavior in the presence of SD.
3. The behavior is reinforced (e.g., through reward or praise), strengthening the association between the behavior and SD.
4. Another stimulus (S∆) is introduced, signaling that reinforcement is not available for the behavior.
5. The individual performs the behavior in the presence of S∆.
6. The behavior is not reinforced in the presence of S∆, allowing the individual to learn that this specific behavior is not effective in this condition.
Through this procedure, the individual learns to perform the desired behavior only in the presence of the SD stimulus, while refraining from performing the behavior in the presence of the S∆ stimulus.
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The conventional procedure you are referring to is known as discrimination training. It involves one behavior and two antecedent stimulus conditions, the SD (discriminative stimulus) and the S∆ (delta stimulus).
The procedure you are referring to is called the Discrimination Training Procedure, which is a method used to teach animals and humans to discriminate between two stimuli. The conventional procedure requires presenting one behavior and two antecedent stimulus conditions.
This means that the individual is asked to perform a specific action or behavior when presented with a particular stimulus, but not when presented with another stimulus.
In this procedure, responses are reinforced in the presence of one stimulus condition, the SD, but not in the presence of the other stimulus, the S∆. This means that if the individual performs the desired behavior when presented with the SD, they will receive some form of reward or reinforcement. However, if they perform the behavior when presented with the S∆, they will not receive any reward or reinforcement.
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The move dialog box appears as soon as components are
inserted into the design.
Select Answer
O True
4
O False
The moment a component is added to the design, the move dialog box opens,It is true.
Which of the following keys is a standard shortcut for the Zoom Fit tool?
Scale to fit (shortcut: f, double-click scroll wheel) - Click this command to enlarge the entire Part Studio, Assembly, or Drawing. You may also use the shortcut key to do so.Typewriter and mouseTo zoom in or out, scroll your mouse wheel up while holding down the Ctrl key. You may already use this to zoom in and out on your browser, for instance.typing justTo zoom out or in on a webpage or document, hold down Ctrl while pressing the - (minus) or + (plus) key. You can utilize the - and + keys on the numeric keypad as well as those next to the backspace key restore the zoom setting Press and hold to restore the zoom to the default setting.
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1) Write a method to compute the average of an int array and return the value as a double. The int array and the number of elements in the array are both passed as parameters to the method in that order.
To write a method to compute the average of an int array and return the value as a double, we need to define the method with two parameters - the int array and the number of elements in the array. This method will take the array and the number of elements as input, and then compute the average of the array.
The steps for writing this method are as follows:
First, we define the method with the name "computeAverage" and two parameters - the int array and the number of elements in the array.
public static double computeAverage(int[] array, int numOfElements) {
Next, we declare a variable to store the sum of all the elements in the array.
int sum = 0;
Then, we use a loop to iterate through the array and add up all the elements.
for (int i = 0; i < numOfElements; i++) {
sum += array[i];
}
After that, we calculate the average by dividing the sum by the number of elements in the array.
double average = (double) sum / numOfElements;
Finally, we return the average.
return average;
}
This method takes an int array and the number of elements in the array as parameters, and returns the average as a double. We can call this method from another part of our code by passing in the array and the number of elements as parameters.
In summary, the method "computeAverage" takes an int array and the number of elements in the array as parameters, computes the average of the array, and returns the average as a double. The steps involved in writing this method include declaring a variable to store the sum of all the elements, using a loop to add up all the elements, calculating the average, and returning the average.
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Is the impedance of the capacitor purely reactive, and how does it compare to the nominal value of the ideal capacitor? Why or why not is it purely reactive?
In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect.
What is the impedance of an ideal capacitor?An perfect capacitor has an infinite resistance. For all frequencies and capacitance levels, the reactance of a perfect capacitor, and consequently its impedance, is negative.A capacitor that has no resistance and therefore doesn't lose any energy while it's operating is the ideal capacitor. It just possesses capacitance. There is no dielectric loss in a perfect capacitor. High temperature stability characterizes the ideal capacitor.As capacitance and frequency increase, capacitive reactance falls. Impedance is the complete opposition that reactance and resistance give.Similar to inductors, the ideal capacitor is a totally reactive device with no resistive (power dissipative) effects whatsoever. Of course, nothing is so flawless in the actual world. Capacitors, however, have the advantage of often being more pure reactive componentsTo learn more about Ideal capacitor refer to:
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What is desktop publishing software
Desktop publishing (DTP) is the use of personal computers to design books and booklets that are intended to be printed by ink jet or laser printers. The software that supports desktop publishing has a WYSIWYG graphical user interface (GUI) to make the set-up for publishing as easy as possible.
1. Plot these two state points on a pressure (ordinate) - volume (abscissa) plane: at state $1, P_1=60 {Bar}, {V}_1=100 {li}$; at state $2, {p}_2=10 {bar}, {V}_2=700 {li}$. Now join them with a single straight line. (a) What will be the pressure and volume of a third state point located on this line and mid-way between the first two state points? (b) From a right triangle using the straight line as the hypotenuse. What will be the pressure and volume of the state point located at the junction of the two legs of the triangle?
(a) The pressure and volume of the third state point located midway between the first two state points will be approximately 35 Bar and 400 li, respectively.
(b) The pressure and volume of the state point located at the junction of the two legs of the right triangle will be approximately 40 Bar and 250 li, respectively.
(a) To find the pressure and volume of the third state point, we can use the concept of linear interpolation. Since the two given state points are joined by a straight line, we can determine the pressure and volume at the midpoint by taking the average of the corresponding values of the two points. Thus, the pressure at the third state point is (60 + 10)/2 = 35 Bar, and the volume is (100 + 700)/2 = 400 li.
(b) In a right triangle, the hypotenuse represents the straight line joining the two state points. By using the Pythagorean theorem, we can calculate the length of the hypotenuse, which corresponds to the pressure and volume at the junction of the two legs. The difference in pressure between the two state points is 60 - 10 = 50 Bar, and the difference in volume is 700 - 100 = 600 li. Treating these differences as the legs of a right triangle, we can calculate the hypotenuse length using the theorem. The pressure at the junction point is given by sqrt((40^2) + (50^2)) = 40 Bar, and the volume is sqrt((250^2) + (600^2)) = 250 li.
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A cylindrical rod of brass originally 10 mm in diameter is to be cold worked by drawing. The circular cross section will be maintained during deformation. A cold-worked tensile strength in excess of 380 MPa and a ductility of at least 15 %EL are desired. Furthermore, the final diameter must be 7.5 mm. Explain how this may be accomplished. Use the graphs given in previous question.
Answer:
Explanation:
From the information given:
original diameter \(d_o\) = 10 mm
final diameter \(d_f =\) 7.5 mm
Cold work tensile strength of brass = 380 MPa
Recall that;
\(\text {The percentage CW }= \dfrac{\pi (\dfrac{d_o}{2})^2 - \pi(\dfrac{d_f}{2})^2 }{\pi(\dfrac{d_o}{2})^2} \times 100\)
\(\implies \dfrac{\pi (\dfrac{10}{2})^2 - \pi(\dfrac{7.5}{2})^2 }{\pi(\dfrac{10}{2})^2} \times 100\)
\(\implies43.87\% \ CW\)
→ At 43.87% CW, Brass has a tensile strength of around 550 MPa, which is greater than 380 MPa.
→ At 43.87% CW, the ductility is less than 5% EL, As a result, the conditions aren't met.
To achieve 15% EL, 28% CW is allowed at most
i.e
The lower bound cold work = 15%
The upper cold work = 28%
The average = \(\dfrac{15+28}{2}\) = 21.5 CW
Now, after the first drawing, let the final diameter be \(d_o^'\); Then:
\(4.5\% \ CW = \dfrac{\pi (\dfrac{d_o^'}{2})^2 - (\dfrac{7.5}{2})^2}{\pi (\dfrac{d_o^'}{2})^2}\times 100\)
By solving:
\(d_o^'} = 8.46 mm\)
To meet all of the criteria raised by the question, we must first draw a wire with a diameter of 8.46 mm and then 21.5 percent CW on it.
Why does the us import oil? because it does not produce any oil at all because it needs higher quality oil than it produces because it has exported too much oil to nearby countries because it is cheaper to import oil than to produce it
US import oil because it is cheaper to import oil than to produce it
What is importation?Importation is a way of bringing in goods and services from neighbouring country into your country.
Countries import because it helps them to supply high cost and scarce resources to its market with products from other countries at a very cheap rate.
Hence we can conclude that US import oil because it is cheaper to import oil than to produce it.
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Answer:
because it is cheaper to import oil than to produce it
Explanation:
d on edge2023
Briefly explain thermal expansion using the potential energy–versus–interatomic spacing curve.
As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.
What are the uses of Thermal Expansion?Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.
It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.
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What does the T wave on an ECG tracing represent?
The T wave on an ECG tracing represents the repolarization of the ventricles of the heart.
During the cardiac cycle, the heart undergoes a series of electrical and mechanical events that are reflected in the ECG tracing. The T wave is the last wave in the ECG cycle and is generated by the repolarization of the ventricles. Repolarization refers to the period when the cells in the ventricles reset their electrical charges to their resting state after the depolarization phase that generates the QRS complex. The T wave is typically a small, rounded wave that follows the QRS complex and is normally in the same direction as the QRS complex. The shape and duration of the T wave can provide important information about the health of the heart, as abnormalities in the T wave can be indicative of certain cardiac conditions such as myocardial ischemia or electrolyte imbalances.
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A plate of width 84mm and thickness 10mm is to be welded to another plate by means of double parallel fillets. The plates are subjected to a static load of 86kN and the maximum permissible shear stress is 3.5MPa.. 1. Find the length of the weld in millimeters(mm).
Answer:
d
Explanation:
i did the test
4 Select the correct answer. A brand selling home appliances conducts a customer survey. The following table indicates the results of the survey. What percent of people are satisfied with the company and are likely to be loyal to the brand? OA 9% B. 12% О с. 14% OD. 45% О Е. 60%
How often might ergonomic training be offered in the workplace
Answer:
'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?
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Explanation:
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Meron akong pangako,hindi mapapako
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Simple man o mahirap,piliting magampanan
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Upang 'di mag hiwalay,magkaibigang tunay.
Show how various Superpave tests used to characterize the asphalt binder are
related to pavement performance.
The tests is used to characterize asphalt binder abecause they help determine the binder's resistance to deformation, cracking and aging which are critical factors in pavement durability.
How are the Superpave tests used?The tests include rotational viscosity test, dynamic shear rheometer test, bending beam rheometer test and the aging oven test in which rotational viscosity test measures the binder's resistance to flow, dynamic shear rheometer test measures the binder's resistance to deformation and cracking.
The bending beam rheometer test determines the binder's stiffness at low temperatures and aging oven test simulates the effect of aging on the binder which is necessary in predicting the pavement's long-term durability.
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A cylindrical vessel is pressurized to 1.7 MPa. The structure on which the vessel rests becomes damaged, resulting in uneven support that causes a twisting moment T0 of 8 106 N-m on the vessel. The vessel has an outer diameter of 2.5 m and a wall thickness of 50 mm. The steel wall has a uniaxial yield strength of 600 MPa. Determine the factor of safety with respect to yielding (a) assuming a maximum shear stress yield criterion and (b) assuming a von Mises yield criterion.
Answer:
a) 15.075 , b ) 12.9
Explanation:
pressure on cylindrical vessel = 1.7 MPa
Twisting moment due to pressure = To of 8( 10^6 ) N-m
outer diameter of vessel = 2.5 m
wall thickness of vessel = 50 mm
Steel wall uniaxial yield strength = 600 MPa
Calculate the factor of safety
a) assuming a max shear stress yield criterion
safety factor = 15.075
b) assuming a von Mises yield criterion
safety factor = 12.9
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