The Ksp of zinc hydroxide, Zn(OH)2, is 3.00 x 10^-17. Calculate the molar solubility of this compound.

Answer: Down

Explanation: There is more force pulling on the object

It is possible to recover 44.01 g of iron from a 115 g sample of Fe2(CO3)3.

We need to first calculate the molar mass of Fe2(CO3)3.

The formula below can be used to determine the molar mass of Fe2(CO3)3:

2 x atomic mass of Fe + 3 x (atomic mass of C + 3 x atomic mass of O)

= 2 x 55.85 g/mol + 3 x (12.01 g/mol + 3 x 16.00 g/mol)

= 2 x 55.85 g/mol + 3 x (12.01 g/mol + 48.00 g/mol)

= 2 x 55.85 g/mol + 3 x 60.01 g/mol

= 2 x 55.85 g/mol + 180.03 g/mol

= 291.73 g/mol

Therefore, the molar mass of Fe2(CO3)3 is 291.73 g/mol.

Next, we need to calculate the amount of Fe2(CO3)3 in moles, which can be calculated as follows:

moles of Fe2(CO3)3 = mass of Fe2(CO3)3 / molar mass of Fe2(CO3)3

= 115 g / 291.73 g/mol

= 0.394 mol

Finally, we may use stoichiometry to determine the weight in grams of iron. We know that there are two moles of Fe for every one mole of Fe2(CO3)3 based on the chemical formula for Fe2(CO3)3. Consequently, the quantity of iron in moles is:

moles of Fe = 2 x moles of Fe2(CO3)3

= 2 x 0.394 mol

= 0.788 mol

The molar mass of iron is 55.85 g/mol. Therefore, the mass of iron in grams is:

mass of Fe = moles of Fe x molar mass of Fe

= 0.788 mol x 55.85 g/mol

= 44.01 g

Therefore, It is possible to recover 44.01 g of iron from a 115 g sample of Fe2(CO3)3.

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Answer:wth does this even mean

Explanation:

Answer:

No  

Explanation:

C is carbon and H is hydrogen

Answer:

There is not sodium (Na) in C2H6.

Sodium on the periodic table is Na and if present in a molecule would be shown in the chemical formula i.e. NaOH or NaCl. C2H6 is an ethane with a two carbon chain.

7 days old hahahshahah

Answer:

chemical energy

Explanation:

just put that

Answer:

chemical energy

Explanation:

it is the light dependent reaction

Answer:

An Autotroph is an animal which can make its own food eg: plants make their own food. But birds hunt and search for their food they do not make it by themselves. Hence birds are not considered Autotrophs, instead they are considered to be Heterotrophs (animals which do not make their own food)

Explanation:

Elements of boron are not found in nature. It is mixed with borates, kernite, ulexite, colemanite, borax, and boric acid. Boric acids are occasionally present in vulcanic spring fluids.

boron into the air, soil, and water during weathering, boron occurs naturally in the environment. In very small quantities, it may also be present in groundwater.

Through the production of glass, the burning of coal, the melting of copper, and the use of agricultural fertilizers, humans add boron to the environment. Human-added boron concentrations are lower than boron concentrations that occur naturally as a result of weathering.

Although it is unlikely that someone may be exposed to borate dust at work, it is possible to be exposed to borate through the air and drinking water. Consumer goods like laundry detergent and cosmetics might expose you to boron.

Thus Elements of boron are not found in nature. It is mixed with borates, kernite, ulexite, colemanite, borax, and boric acid. Boric acids are occasionally present in vulcanic spring fluids.

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5.632 * \(10^{3}\) gram of water would he need to perspire in order to maintain his original temperature if the energy intake of 1550 KJ.

Energy intake =  1550 KJ

Energy required to vaporize one mole of water is 44KJ.

So, the number of moles of water needed is,

                    = energy taken / 44 KJ

                    =   1550 KJ / 44 KJ

                     = 35.22 Moles

Mass of water = moles * molar mass

                        = 35.22 Moles * 16 g/ mole

                        = 563.2 gram

                        = 5.632 * \(10^{3}\) gram

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The percent sulfur in iron(III) sulfate is approximately 24%. The answer is (d).

To calculate the percent sulfur in iron(III) sulfate, we need to determine the molar mass of the compound and the molar mass of the sulfur in the compound.

The formula for iron(III) sulfate is Fe2(SO4)3, which has a molar mass of:

Fe2(SO4)3 = 2(55.845 g/mol) + 3(32.066 g/mol + 4(15.999 g/mol)) = 399.88 g/mol

The molar mass of sulfur in the compound is:

32.066 g/mol x 3 = 96.198 g/mol

To calculate the percent sulfur, we can use the formula:

Percent sulfur = (mass of sulfur/mass of iron(III) sulfate) x 100%

Substituting the values we found earlier, we get:

Percent sulfur = (96.198 g/mol/399.88 g/mol) x 100% ≈ 24%

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Structure and the reaction is in the attached photo.

Amides, RCONR'2, can be reduced to the amine, RCH2NR'2 by conversion of the C=O to -CH2-. Amides can be reduced by LiAlH4 but not the with the less reactive NaBH4. Some of the reagents are LiAlH4  / ether solvent, followed by water.

This reduction reaction is different from the different to that of other C=O compounds which reduce to alcohols like in esters.

Lithium aluminium hydride (LiAlH4) and sodium borohydride are the two most frequent sources of the hydride nucleophile (NaBH4).

The presence of a polar metal-hydrogen bond in these reagents acts as a source of hydride rather than the hydride anion, which is absent during this reaction. Since the Al-H bond in LiAlH4 is more polar and aluminium is less electronegative than boron, LiAlH4 is a more potent reducer.

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The answer to the above question is D. as mass transfer refers to the net transfer of mass from one place to another.

One of the fundamental concepts in the study of transport phenomena is mass transfer, which denotes the movement of mass from one location to another. In multiphase systems, mass transfer may occur within a single phase or across phase borders. Although it can also be characterised in terms of solid-phase materials, mass transfer often incorporates at least one fluid phase (gas or liquid) in engineering challenges.

The computation of mass flux in a system and the distribution of the mass of various species through time and space are both made possible by the theory of mass transfer.

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Glycolysis does not need oxygen, so is also known as fermentation.  

During glycolysis, the six-carbon sugar glucose goes through a number of chemical changes. In the end, it is transformed into two pyruvate molecules, which are organic molecules with three carbons. ATP is produced and NAD⁺ is changed into NADH in these processes.

Fermentation is a process that allows glycolysis to occur in the absence of oxygen. Oxygen is necessary for the citric acid cycle, oxidative phosphorylation, and the other three stages of cellular respiration (pyruvate oxidation, and others). Only oxidative phosphorylation directly utilizes oxygen, although the other two processes are dependent on oxidative phosphorylation to function.

Glycolysis is the first step in cellular respiration.

A metabolic process called cellular respiration converts glucose to ATP. Glycolysis, pyruvate oxidation, the citric acid or Krebs cycle, and oxidative phosphorylation are the phases of cellular respiration.

A glucose molecule gradually degrades into water and carbon dioxide during cellular respiration. During the process of transforming glucose, some ATP is created immediately. However, oxidative phosphorylation, a subsequent phase, results in the production of far more ATP. The electron transport chain, a collection of proteins enmeshed in the mitochondrion's inner membrane, is what drives oxidative phosphorylation.    

Electron carriers NAD+ and FAD, which become NADH and FADH₂ when they gain electrons, transfer these electrons, which originate from glucose, to the electron transport chain. The molecule is not created from nothing; rather, it is only transformed into its electron-carrying form.

   NAD² + 2e⁻ + 2H⁺  ⇒ NADH + H⁺

   FAD + 2e⁻ + 2H⁺   ⇒ FADH₂

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Answer:

Do you need 3 ways or just one?

1. Temperature.

2. Pressure.

3. Polarity.

Explanation:

Eh hope these help, Idr understand the question but those are 3 ways to increase the solubility of a solid in water.

Answer:

a combination of two or more elements called a compound

Answer:

32%

Explanation:

To determine the percentage of water in the hydrate, we need to know the original amount of water that was present in the hydrate. We can calculate this by subtracting the amount of anhydrous salt remaining (1.7 g) from the original weight of the hydrate (2.5 g).

(2.5 g - 1.7 g) = 0.8 g

This tells us that 0.8 g of water was present in the original 2.5 g hydrate sample. To find the percentage of water, we divide the weight of the water by the weight of the original hydrate and multiply by 100.

(0.8 g / 2.5 g) * 100 = 32 %

So, 32% of the original 2.5 g hydrate sample was water.

A shielded nucleus will have a reduced chemical shift and will absorb upfield from a deshielded nucleus.

The nucleus is the central part of an atom that contains most of its mass and all of its positive charge. It is composed of protons and neutrons, which are held together by a strong nuclear force. The number of protons in the nucleus determines the element that the atom belongs to, while the number of neutrons can vary and give rise to different isotopes of the same element. The properties of the nucleus are essential in determining the behavior of the atom in chemical and physical reactions. Nuclei can also undergo nuclear reactions such as fission and fusion, which release enormous amounts of energy and are the basis for nuclear power and nuclear weapons. The study of nuclei and their properties is known as nuclear physics and is a fundamental area of modern science.

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The vapour pressure in the water flask is 23.686 torr.

The pressure of \(H_2\) in the flask was 713.514  torr.

Pressure is the \(H_2\) exerting in the flask is 688.314 torr

Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.

a.The vapour pressure of water is given by:

\(Log_{10} P =A- \frac{B}{C+T}\), where T is in degree Celcius, P is in torr.

For 0-100 degree celcius, A=8.07131, B=1730.63, C=233.426

\(Log_{10} P = 8.07131 - \frac{1730.63}{233.426+25} =1.3745\)

As T =25 degree celcius

\(P = 10^{1.3745} torr\) =23.686 torr

b.We know that \(P_{total} =P_{H_2} + P_{H_2O}\)

\(P_{total}\) = Atmospheric pressure

\(737.2 torr = P_{H_2} +23.686 torr\)

\(P_{H_2} = 713.514 torr\)

c.After there is a leak in the gas collection tube, the amount at pressure due to water vapour remains unchanged as it is a quantity dependent on temperature.

\(P_{total} =P_{H_2} + P_{H_2O} + P_{leaking \;air}\)

\(737.2 torr = P_{H_2} + 23.686 torr + 25.2 torr\)

\(P_{H_2} =688.314 torr\)

For calculating molar mass of any gas:

M= Density X (RT ÷ P)

M= 0.714 g X (\(8.314 J mol^{-1}K^{-1}\)273 K ÷ 101325 Pa)

M= 15.994 g/mol = 16 g/mol.

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The compound most likely held together by a covalent bond based on electronegativity difference is NO.

To determine which compound is most likely to be held together by a covalent bond based on the electronegativity difference between its two atoms, we can compare the electronegativity differences for each compound.The electronegativity difference between two atoms in a compound gives us an indication of the type of bond present.

Generally, a difference of 1.7 or higher suggests an ionic bond, while a difference below 1.7 suggests a covalent bond.  To calculate the electronegativity differences for the given compounds:

CO: The electronegativity of carbon (C) is 2.55, and the electronegativity of oxygen (O) is 3.44. The electronegativity difference is 3.44 - 2.55 = 0.89.

NaCl: The electronegativity of sodium (Na) is 0.93, and the electronegativity of chlorine (Cl) is 3.16. The electronegativity difference is 3.16 - 0.93 = 2.23.

NO: The electronegativity of nitrogen (N) is 3.04, and the electronegativity of oxygen (O) is 3.44. The electronegativity difference is 3.44 - 3.04 = 0.40.

CaBr: The electronegativity of calcium (Ca) is 1.00, and the electronegativity of bromine (Br) is 2.96. The electronegativity difference is 2.96 - 1.00 = 1.96.

Based on the electronegativity differences calculated above, the compound with the lowest difference is NO (0.04), which suggests a covalent bond between nitrogen and oxygen. Therefore, the compound most likely held together by a covalent bond based on electronegativity difference is NO.

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the value of the equilibrium constant Kc for the given reaction at the temperature of the mixture is 1.78.

The value of the equilibrium constant Kc for the given reaction at the temperature of the mixture is 1.78. Kc is determined based on the concentrations of reactants and products at equilibrium.

Analysis of an equilibrium mixture of N2O4 (g) gave the following results:

\([NO2(g)] = 4.622x M[N2O4(g)] = 3.222x M\)

The concentration of NO2 and N2O4 in the equilibrium mixture was calculated, which are known as equilibrium concentrations.

Substitute the equilibrium concentrations into the equation below to calculate Kc:

\([N2O4]/[NO2]= 3.222 * / (4.622)= 1.78\)

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Answer:

Both objects are in physical contact with each other

Explanation:

Conduction refers to the flow of heat from one object to another when the both objects are in contact with each other.

Hence, before heat can flow from one object to another, the two objects must be in contact with each other. This is a key requirement before conduction can take place.

Answer:

( c ) sunlight.

Explanation:

the leaves are closer to the sunlight they require.

Answer:

1M

Explanation:

The molarity of a substance is defined as the number of moles of the substance divided by how many liters the solution is. NaOH has a molar mass of about 40 grams, meaning that 10 grams of it would be 0.25 moles. 0.25/0.25= a molarity of 1.

Hope this helps!

Answer:

1.5 moles of KMnO4 will be produced from 1.5 moles of MnO2

Explanation:

The balanced equation of this chemical reaction is

2 MnO2 + 4 KOH + O2 → 2 KMnO4 + 2 KOH + H2

2 moles of MnO2 produces 2 moles of   KMnO4

That means 1 moles of KMnO4 will be produced from 1 moles of MnO2

Hence, 1.5 moles of KMnO4 will be produced from 1.5 moles of MnO2

The moles of manganese oxide were used in the reaction is 1.5 moles.

Stoichiometry of any reaction tells about the relative amount of species present before and after the chemical reaction.

Given chemical reaction is:

2MnO₂ + 4KOH + O₂ → 2KMnO₄ + 2KOH + H₂

From the stoichiometry of the reaction, it is clear that same moles of manganese oxide and potassium permanganate is involved in the reaction.

2 moles of KMnO₄ = produce by 2 moles of MnO₂

1.5 moles of KMnO₄ = produce by 2/2×1.5=1.5 moles of MnO₂

Hence, required moles are 1.5 moles.

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The mass of iodine that must be added to prepare a 0.480 M solution if 62.9 mL of carbon tetrachloride is used is 7.614 g

The molarity of a solution is calculated, using the formula:

molarity = number of moles / volume of solution

The solution to the question is divided into steps:

Step 1: Determine the moles of iodine present in the solution:

Step 2: Calculate the mass of iodine

Therefore, the mass of iodine that must be added to prepare a 0.480 M solution if 62.9 mL of carbon tetrachloride is used is 7.614 g

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Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\(\%C_E = \frac{E}{T} * 100\%\)

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In \((Ca(OH)_2)\)

The amount of all elements is: (i.e formula mass of \((Ca(OH)_2)\))

\(T = 1 * Ca + 2 * H + 2 * O\)

\(T = 1 * 40 + 2 * 1 + 2 * 16\)

\(T = 74\)

The amount of calcium is: (i.e formula mass of calcium)

\(E = 1 * Ca\)

\(E = 1 * 40\)

\(E = 40\)

So, the percentage component of calcium is:

\(\%C_E = \frac{E}{T} * 100\%\)

\(\%C_E = \frac{40}{74} * 100\%\)

\(\%C_E = \frac{4000}{74}\%\)

\(\%C_E = 54.05\%\)

The amount of hydrogen is:

\(E = 2 * H\)

\(E = 2 * 1\)

\(E = 2\)

So, the percentage component of hydrogen is:

\(\%C_E = \frac{E}{T} * 100\%\)

\(\%C_E = \frac{2}{74} * 100\%\)

\(\%C_E = \frac{200}{74}\%\)

\(\%C_E = 2.70\%\)

Similarly, for oxygen:

The amount of oxygen is:

\(E = 2 * O\)

\(E = 2 * 16\)

\(E = 32\)

So, the percentage component of oxygen is:

\(\%C_E = \frac{E}{T} * 100\%\)

\(\%C_E = \frac{32}{74} * 100\%\)

\(\%C_E = \frac{3200}{74}\%\)

\(\%C_E = 43.24\%\)