The knitting club sold 40 scarves and hats at a winter festival and made $700 from the sales. They charged $18 for each scarf and $14 for each hat.



If s represents the number of scarves sold and h represents the number of hats sold, which system of equations represents the constraints of the situation?

Group of answer choices



A. s + h =40

18s +14h = 700

B. 18s +14h =40

s + h =700

C. 40s + h +700

18s + 14h = 700

D. No answer text provided.

Answer:

\(\sqrt{52\)

Step-by-step explanation:

hope it helps! im not completely sure but its the best answer!

Answer:

C

Let's simplify the answers. Use absolute value.

| -5.1 | = 5.1 - > |5.1| = 5.1

4.7 - > |4.7| = 4.7

| -0.9 | = 0.9 - > |0.9| = 0.9

- |6.7| = -6.7 - > |-6.7| = 6.7

Now, order each from least to greatest.

0.9, 4.7, 5.1, 6.7

Which one is the smallest? 0.9

So, C is correct.

I'm sorry if I misunderstood.

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Answer:

1200?

Step-by-step explanation:

Answer:

8(3s+t)

Step-by-step explanation:

Because the greatest common factor of 24s and 8t is 8, then factoring out 8 from the expression gives us 8(3s+t).

Answer:

8(3s + t)

Step-by-step explanation:

=> 24s + 8t

=> 8 × 3s + 8 × 1t

=> 8(3s + 1t)

=> 8(3s + t)

Answer:

1. Cos θ = 6√2 / 11

2. Tan θ = 7 / 6√2

3. Cosec θ = 11 / 7

4. Sec θ = 11 / 6√2

5. Cot θ = 6√2 / 7

Step-by-step explanation:

From the question given above, the following data were obtained:

Sine θ = 7 / 11

Next, we shall determine the adjacent of the right triangle. This can be obtained as follow:

Sine θ = 7 / 11

Sine θ = Opposite / Hypothenus

Opp = 7

Hypo = 11

Adj =?

Hypo² = Opp² + Adj²

11² = 7² + Adj²

121 = 49 + Adj²

Collect like terms

Adj² = 121 – 49

Adj² = 72

Take the square root of both side

Adj = √72

Adjacent = 6√2

1. Determination of Cos θ

Adjacent = 6√2

Hypothenus = 11

Cos θ =?

Cos θ = Adjacent / Hypothenus

Cos θ = 6√2 / 11

2. Determination of Tan θ

Opposite = 7

Adjacent = 6√2

Tan θ =?

Tan θ = Opposite / Adjacent

Tan θ = 7 / 6√2

3. Determination of Cosec θ

Sine θ = 7 / 11

Cosec θ =?

Cosec θ = 1 ÷ Sine θ

Cosec θ = 1 ÷ 7 / 11

Cosec θ = 1 × 11/7

Cosec θ = 11/7

4. Determination of Sec θ

Cos θ = 6√2 / 11

Sec θ =?

Sec θ = 1 ÷ Cos θ

Sec θ = 1 ÷ 6√2 / 11

Sec θ = 1 × 11 / 6√2

Sec θ = 11 / 6√2

5. Determination of Cot θ

Tan θ = 7 / 6√2

Cot θ =?

Cot θ = 1 ÷ Tan θ

Cot θ = 1 ÷ 7 / 6√2

Cot θ = 1 × 6√2 / 7

Cot θ = 6√2 / 7

Answer:

Step-by-step explanation:

I figured this out with calculus since it's easier that way. The position function for the ball is

\(s(t)=-16t^2+64t+2\). The first derivative of position is velocity, so we need to find the first derivative of the position function which is

v(t) = -32t + 64

Now, where the ball is at its highest point is where the velocity is equal to 0, so setting the velocity function equal to 0 allows us to determine how many seconds it takes to get to that max height.

0 = -32t + 64 and

-64 = -32t so

t = 2 seconds. It takes 2 seconds to get to its max height. In order to determine that max height, we sub 2 in for t in the position function:

\(s(2)=-16(2)^2+64(2)+2\) and

s(2) = 66 feet. The max height of the ball is 66 feet.

Answer:

\(\mbox{\large $0.5 + 0.16 \bar {3}$ = \boxed{\dfrac{199}{300}}}\)

Step-by-step explanation:

\(0.16\bar{3} = 0.16333333333\\\)

the 3 repeats until infinity

Let's multiply this by 100 to move the non-repeating part to the left of the decimal point

0.1633333333...... x 100 = 16.333333333333333...

.333333 = 1/3

Therefore the recurring number multiplied by 100 is
\(16 + \dfrac{1}{3} = \dfrac{16 \times 3 + 1}{3}=\dfrac{49}{3}\)

Since this fraction was arrived at by multiplying by 100, divide this fraction by 100 to get back the fraction in its original decimal value of 0.163333

\(\dfrac{49}{3} \div 100\)

To divide by a number, multiply by the reciprocal of that number

Reciprocal of 100 is 1/100:

\(\dfrac{49}{3} \div 100 = \dfrac{49}{3} \times \dfrac{1}{100} = \dfrac{49}{300}\)

(You can verify this by dividing 49 by 300 in a calculator and seeing that the result is 0.163333333333333333333 i.e. 0.16333 recurring

We want to add 0.5 to this.

0.5 = \(\dfrac{1}{2}\)

so
0.5 + 0.16333333 = 0.6633333

\(= \dfrac{1}{2} + \dfrac{49}{300}\)

We can write \(\dfrac{1}{2}\) as \(\dfrac{150}{300}\)  by multiplying numerator and denominator by 150

So we get

\(0.5 + 0.1633333 = \dfrac{150}{300} + \dfrac{49}{300} = \dfrac{150+49}{300} = \dfrac{199}{300}\)

If you perform this division on a calculator you will get the answer as 0.663333 = \(0.66\bar{3}\) which is what you get when you add 0.5 and \(0.16\bar{3}\)

Answer:

slope is also known as gradient

here gradient =2/9

Total earnings = $117

Total hours = 17

Earnings on each job:

Baseball coaching per hour = $6

Gym per hour = $9

So, we have to write an equation:

x= number of hours at baseball cocaching

y= number of hours working at the gym

The system of equations:

x+y= 17 (a)

6x+9y=117 (b)

Solve (a) for x:

x=17-y

Replace x on (b) and solve for y:

6(17-y)+9y=117

102-6y+9y=117

-6y+9y =117-102

3y= 15

y=15/3

y=5

Replace y on (a) ans solve for x:

x+5 = 17

x=17-5

x= 12

Hours worked at the gym (y)= 5

Hours worked at basesball (x)= 12

just convert 452 miles to kilometers

\(1 \: mile = 1.6km\)

\(452 \: miles = 452 \times 1.6km\)

\(452 \: miles = 723.2 \: kilometers\)

Answer:

684km

Step-by-step explanation:

if 1 mile if 1.6 kilometers, then you multiply 452 by 1.6 and get 683.97, round up and you get 684

Answer:

66 units

Step-by-step explanation:

Answer:

6x8x16x10

Step-by-step explanation:

Answer:

\(t(n) = -5^{n-1}*6\)

Step-by-step explanation:

\(t(n) = -5^{n-1}*6\)

The greatest common factors (GCF) of the given sets of numbers are  

                                 GCF

(24 + 32 + 12)               4

(88 + 28 + 32)               4

(12 + 10 + 36)                 2

(20 + 8 + 36)                 4

(14 + 28 + 22)                2

(26 + 24 + 20)               2

From the question, we are to identify the greatest common factors of the given sets of numbers

The greatest common factor of 24, 32 and 12 is 4

The greatest common factor of 88, 28 and 32 is 4

The greatest common factor of 12, 10 and 36 is 2

The greatest common factor of 20, 8 and 36 is 4

The greatest common factor of 14, 28 and 22 is 2

The greatest common factor of 26, 24 and 20 is 2

Hence, the greatest common factors (GCF) of the given sets of numbers are  

                                 GCF

(24 + 32 + 12)               4

(88 + 28 + 32)               4

(12 + 10 + 36)                 2

(20 + 8 + 36)                 4

(14 + 28 + 22)                2

(26 + 24 + 20)               2

Here is the complete question:

Identify the GCF of each expression as 2 or 4.

(24 + 32 + 12)

(88 + 28 + 32)

(12 + 10 + 36)

(20 + 8 + 36)

(14 + 28 + 22)

(26 + 24 + 20)

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Answer:

a=3

Step-by-step explanation:

the sum of anterior angle of a triangle is =180

57+81+14a=180

138+14a=180

42=14a

42/14=14a/14

3=a

therefore a=3.

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An acre is a unit of measurement used to quantify land area, and it is commonly used in the United States to measure the size of plots of land, farms, and estates. One acre is equal to 43,560 square feet.

To visualize an acre, imagine a rectangle that is approximately 208 feet by 209 feet, or a square that is approximately 209 feet on each side.

To convert acres to square feet, you can use the following formula:

1 acre = 43,560 square feet

Therefore, to convert acres to feet, you can simply multiply the acre value by 43,560. For example, if you want to convert 5 acres to square feet, you can use the following formula:

5 acres x 43,560 square feet per acre = 217,800 square feet

So 5 acres is equal to 217,800 square feet.

It's worth noting that the acre is a unit of measurement used primarily in the United States, and other countries may use different units of measurement to quantify land area. For example, in the metric system, the hectare is commonly used to measure land area, with 1 hectare equal to 10,000 square meters (about 2.47 acres).

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On a number line, an absolute value equation that has the given solution set is |m - 4| = 2.

By critically observing the given question, we can infer and logically deduce that the solution sets for this absolute value equation is given by:

m = {2, 6}

Next, we would calculate the mean of the solution sets as follows:

m₁ = (2 + 6)/2

m₁ = 8/2

m₁ = 4.

Also, we would calculate the difference in the solution sets as follows:

m₂ = (6 - 2)/2

m₂ = 4/2

m₂ = 2.

Mathematically, the absolute value equation is given by:

|m - m₁| - m₂ = 0

|m - 4| - 2 = 0

|m - 4| = 2.

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The total number of eggs Dale collected is 187 eggs.

To find the total number of eggs, you would use operations, specifically, multiplication and addition. First, multiply the number of cartons (15) by the number of eggs per carton (12). This gives you a total of 180 eggs (15 x 12) in the cartons.

In addition to the eggs in the cartons, Dale also has 7 eggs left over. To find the total number of eggs Dale collected, you simply add the number of leftover eggs (7) to the total number of eggs in the cartons (180). This results in a grand total of 187 eggs (180 + 7) that Dale collected from his chickens.

In summary, Dale collected 187 eggs in total: 180 eggs from filling 15 cartons with 12 eggs each and 7 additional leftover eggs.

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Step-by-step explanation:

they paid 23.75 dollars. I hope it helps l!

Step-by-step explanation:

They paid 23.75 dollars. I really really hope this helps l!

Answer:consecutive exterior angles theorem

Step-by-step explanation: guessing because it’s showing exterior angles :)

Out of 52 cards, there is only one Queen of Hearts. Hence, then, the probability = 47/52

5 cards can be chosen from a deck of 52 cards in ⁵²C₅

In order to avoid choosing a queen of hearts, we must choose 5 cards. There is only one queen of hearts in a deck of 52 cards. There are still 51 cards left, and 5 of them can be chosen in ⁵²C₅.

Therefore, the likelihood that a five-card poker hand does not include the queen of hearts is equal to ⁵¹C₅/⁵²C₅

47/52

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The full question

What is the probability that a five-card poker hand does not contain the queen of hearts?

The experiment compared the fracture toughness of high-purity 18 Ni maraging steel with commercial-purity steel of the same type. For 32 high-purity specimens, the sample average toughness was X=65.5, while for 38 commercial-purity specimens, the sample average toughness was y=59.8.

The high-purity steel is more expensive, and its use for a certain application can be justified only if its fracture toughness exceeds that of commercial-purity steel by more than 5. Both toughness distributions are assumed to be normal with σ1 = 1.2 and σ2 =1.1. Using α=.001, the relevant hypotheses are tested. β is then computed for the test when μ1 – μ2 = 6.
In the experiment, the fracture toughness of high-purity 18 Ni maraging steel (X = 65.5, m = 32, σ1 = 1.2) was compared to commercial-purity steel (Y = 59.8, n = 38, σ2 = 1.1). The goal is to justify the use of high-purity steel if its toughness exceeds commercial steel by more than 5. Both toughness distributions are assumed to be normal.

a. To test the relevant hypotheses using α = .001, we perform a two-sample t-test. The null hypothesis (H0) is that the difference in means (μ1 - μ2) is less than or equal to 5, and the alternative hypothesis (H1) is that the difference is greater than 5.

b. To compute β for the test conducted in part (a) when μ1 - μ2 = 6, we need to determine the probability of a Type II error, which is the likelihood of failing to reject the null hypothesis when it is false. Calculating β requires knowledge of the sampling distributions and the specific alternative value (μ1 - μ2 = 6).

In summary, to justify the use of high-purity steel, a two-sample t-test can be conducted using the given parameters. Additionally, calculating β helps understand the likelihood of a Type II error in this hypothesis test.

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Answer:

72 + 12x

Step-by-step explanation:

Use Distributive proeprty: a*(b +c)= (a*b) + (a*c)

Here, a = 12 ; b = 6 & c = x

12( 6 + x) = 12*6 + 12*x

               = 72 + 12x

Answer:

Step-by-step explanation:

a = BC - DC

\(\frac{60}{BC}\) = tan 28°

BC = \(\frac{60}{tan28}\) ≈ 112.8 m

DC = \(\frac{60}{tan54}\) ≈ 43.6 m

a ≈ 112.8 - 43.6 = 69.2 m

The double numberline is a model used to show relationship and solve ratio problems. They are best used when the quantities have different units, for example, a 5x7 photography, it is used to model both the height and the length.

Answer:

5.5 maybe..

Step-by-step explanation:

Answer: At 100 pounds, a man would reach a BAC of 0.12 by drinking three drinks in less than one hour or four drinks over two hours. At 150 pounds...

Step-by-step explanation: