the kinetic energy associated with the random motion of molecules is called ________

Answers

Answer 1

The kinetic energy associated with the random motion of molecules is called thermal energy.

What is thermal energy?

Thermal energy is the energy created by heat. This energy is a direct result of the kinetic energy associated with the random motion of particles in a material.

What is the equation for thermal energy?

Thermal energy can be calculated using the equation:

Thermal energy = mass x specific heat capacity x temperature change.

The unit of thermal energy is joules (J).

What is the importance of thermal energy?

Thermal energy has several applications, such as powering machines, creating electricity, and heating homes. Also, when we perform activities like exercising, the kinetic energy associated with the random motion of molecules is called thermal energy. It is a crucial element that helps us function properly, even though it is invisible and often goes unnoticed.

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Related Questions

Which waves can
travel though space

Answers

Answer: Radio waves

Explanation:

Radio waves can travel through space. So, if you're wearing a space suit that contains a radio unit and one of your buddies sends you a radio message that there's pizza in the space station, you'd be able to hear it. That's because radio waves aren't mechanical -- they're electromagnetic. Electromagnetic waves can transmit energy through a vacuum.

Where did all the golden carals go?

Answers

Answer:

Thanos went *snap*

Explanation:

A cook wants to prepare some food to be cooked by 1.15p.m. He uses an oven with an automatic timer that can be set to switch on and off at certain times. The oven needs to be switched on for 2 hours 10 minutes. At which time does the oven need to switch on?
A 11.05 a.m.
B 11.25 a.m.
C 3.05p.m.
D) 3.25 p.m.

guys some one help ASAP ,i think it's the ans is D but i am not really sure tho​

Answers

Answer:

I think the answer is D because it needs to be on two hours from 1.15pm

A rock climber is about to haul up 100 N (about 22.5 pounds)
A rock climber is about to haul up 100 N (about 22.5 pounds) of equipment that has been hanging beneath her on 40 meters of rope that weighs 0.8 newtons per meter. How much work will it take?

Answers

8000 Joules is the amount of work required to haul up the equipment.

Work to haul equipment?

To calculate the work required to haul up the equipment, we need to consider two components: the work done against gravity and the work done against the weight of the rope.

Work against gravity:

The force due to gravity is given by the weight of the equipment, which is 100 N. The distance over which the force is applied is the height the equipment is being hauled, which is 40 meters. The work done against gravity can be calculated using the formula:

Work = Force × Distance

Work against gravity = 100 N × 40 m = 4000 N·m or 4000 J (Joules)

Work against the weight of the rope:

The weight of the rope can be calculated by multiplying the weight per meter (0.8 N/m) by the length of the rope (40 m):

Weight of the rope = 0.8 N/m × 40 m = 32 N

Since the rope is being hauled up, the work done against the weight of the rope is the same as the work done against gravity. Therefore, the work against the weight of the rope is also 4000 J.

The total work required to haul up the equipment is the sum of the work against gravity and the work against the weight of the rope:

Total work = Work against gravity + Work against rope weight

Total work = 4000 J + 4000 J

Total work = 8000 J

Therefore, it will take 8000 Joules of work to haul up the equipme

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as the balls reach their maximum displacement, their kinetic energy reaches __________. a maximum zero neither a maximum nor zero

Answers

As the balls reach their maximum displacement, their kinetic energy reaches a minimum.  a maximum zero neither a maximum nor zero. This is because, at the maximum displacement point, the balls have come to a momentary stop and are changing direction, therefore their velocity is momentarily zero.

As kinetic energy is inversely related to the mass and velocity of an object, it will be zero if the velocity is zero. The balls' velocity and kinetic energy will rise once more when they start to move in the other direction. As a result, the kinetic energy is not at its greatest or its minimum at the moment of maximum displacement, but rather it is there.

The balls' kinetic energy depletes when they approach their maximum displacement. The balls' velocity is zero when they have reached their maximum displacement because they briefly stop traveling before turning in a new direction. A velocity of 0 yields zero kinetic energy because kinetic energy is computed as (1/2)mv2, where m represents mass and v is velocity.

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Please help! SATS SOON

Please help! SATS SOON

Answers

1.Diagram of the sailor System

2.A Graph predicted temperature over time

3.A diagram of the water cycle

I don’t know if this is 100% right...

Have a Nice Day<3

Which substances are inorganic? Check all that apply.

C6H12O6
K2CO3
C4H10
C27H46O
Fe3O4

Answers

The major characteristic an organic compound has which an inorganic

compound doesn't  have is the presence of carbon atoms in the molecule.

This helps us to differentiate the compounds into their respective divisions.

Inorganic compounds

K2CO3Fe3O4

Organic compounds

C6H12O6C4H10C27H46O

We can observe that inorganic compounds lack carbon atoms which makes

the answer valid.

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Answer:

B and E because yk thats the asnwer

2. Calculate the acceleration of a school bus when a force of 2000 N is applied. The mass is
1000 kg.

Answers

Answer:

2m/s square

Explanation:

this means force is the product of mass and acceleration.so a=f/mA=2000N/1000kg A=2m/s squarewhere a is acceleration f is force and m is mass

what is electric lines of force ​

Answers

Answer:

Electric field lines are an excellent way of visualizing electric field. Electrical lines of force can be described as a way or path, it can be straight or curved so that the tangent gives the direction of the intensity of the electric field at that point at any point.

A hydraulic lift is used to raise an automobile of mass 1520 kg. The radius of the shaft of the lift is 8.00 cm and that of the piston is 1.00 cm. How much force must be applied to the piston to raise the automobile?

Answers

To raise the automobile with a hydraulic lift, a force of approximately 19,000 N must be applied to the piston.

In a hydraulic lift, the principle of Pascal's law is applied, which states that pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and the walls of its container. By utilizing this principle, a smaller force applied to a smaller piston can generate a larger force on a larger piston.

In this scenario, the force needed to lift the automobile can be calculated using the formula:

\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)

where \(F_{1}\) is the force applied to the piston, \(A_{1}\) is the area of the piston, \(F_{2}\) is the force generated on the larger piston (required to lift the automobile), and \(A_{2}\) is the area of the larger piston.

Given the radius of the shaft (small piston) as 0.08 m and the radius of the piston as 0.01 m, we can calculate the forces applied and generated as follows:

\(A_{1} = \pi (0.08)^2\\A_{2}= \pi (0.01)^2\)

\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)

Simplifying the equation and substituting the values, we can solve for \(F_{2}\):

\(F_{2}=\frac{F_{1}A_{2}}{A_{1}}\)

Plugging in the values, we find:

\(F_{2}=\frac{F_{1} \pi (0.01)^2 }{ \pi (0.08)^2} \\F_{2}= \frac{F_{1}\times 0.0001}{0.0064} \\F_{2}= 0.015625 \times F_{1}\)

Given that the mass of the automobile is 1520 kg and the acceleration due to gravity is \(9.8 \hspace m/s^{2}\), we can equate \(F_{2}\) to the weight of the automobile:

\(F_{2}= mg\\0.015625\times F_{1}= 1520\times 9.8\)

Solving for \(F_{1}\), we find:

\(F_{1}\approx \frac{1520\times 9.8}{0.015624} \\F_{1} \approx 19072 \hspace N\)

Therefore, a force of approximately 19,000 N must be applied to the piston in order to raise the automobile using the hydraulic lift.

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A 22.5-kg mass was set on a spring whose spring constant was 563 newtons per meter. How far was the spring compressed?(a) 0.0400 m(b) 0.196 m(c) 0.392 m(d) 2.55 m

A 22.5-kg mass was set on a spring whose spring constant was 563 newtons per meter. How far was the spring

Answers

\(\begin{gathered} |x|=\frac{mg}{k}\text{ using this formula } \\ \text{where m=22.5kg and the spring constant k=563 N/m} \\ \text{Now substituting the vlaues ,} \\ \frac{22.5\operatorname{kg}\times9.8\text{ m/s}}{563\text{ N/m}}=0.392\text{ m} \end{gathered}\)

A seashell is suspended in the air at rest by two strands of spider silk. Each strand of silk makes an angle of 75 degrees above the horizontal, and experiences a tension of 1.42 N.

What is the mass of the seashell?

Answers

The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

The given parameters:

Tension on each strand of silk, T = 1.42 NAngle of inclination of each strand, θ = 75⁰

The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;

\(\Sigma F = 0\\\\T_1 sin(\theta) + T_2 sin(\theta) - W = 0\)

where;

W is the weight of the seashell

The weight of the seashell is calculated as;

\(1.42 \times sin(75) \ + \ 1.42 \times sin(75) \ - W = 0\\\\2.743 - W = 0\\\\W = 2.743 \ N\)

The mass of the seashell is calculated as follows;

\(W = mg\\\\m = \frac{W}{g} \\\\m = \frac{2.743}{9.8} \\\\m = 0.28 \ kg\)

Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

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A car is travelling along a level road. When the velocity of the car is constant, the force of friction on it is

Answers

I believe the force of friction would also remain constant because the speed is staying the same.

A Ball is dropped from a high rise platform at t=0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t= 18s. What is the value of v? ( Take g= 10m/s2)

Answers

Answer: 75m/s

Explanation:

First find the distance the first ball travels.

1/2*10*18^2 = 1620m

We know that both balls meet after 18s so they each have fallen 1620m when they meet. Second ball falls for 6 seconds less so it falls for 12s

plug this it kinematic equation.

1620 = v*12+1/2*10*12^2

1620 = v*12+720

900 = 12v

v = 75m/s

Determine the direction of the magnetic field of the current-carrying wire in the vicinity of the loop.

Answers

To determine the direction of the magnetic field of the current-carrying wire in the vicinity of the loop, you can use the right-hand rule.

How do you use this right-hand rule?

If you're confused of what the direction of the magnetic field around a current-carrying wire is supposed to be, you can use the right-hand rule to conveniently figure out the direction. To use this right-hand rule, first curl your right-hand fingers and then point your right thumb in the direction of the current in the wire. Your right-hand fingers will be curled in the same direction as the direction of the magnetic field around the current-carrying wire.

There is another type of the right-hand rule. This type of right-hand rule is used to identify the direction of axes or parameters that point in three dimensions.

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please help me with these 2 questions :D

please help me with these 2 questions :D

Answers

Answer:

Explanation:

1- incident ray

2- the substance through which the wave travels

Answer: the incident ray(the incident ray is the ray striking the mirror at the point of incidence while the refracted ray is the ray leaving the mirror)

The substance through which the ray or wave travels.

Convert 15*c in Fahrenheit

Convert 15*c in Fahrenheit

Answers

Answer:

it is 59 degrees Fahrenheit

I'm pretty sure it's 59 °F

What happens when a diamagnetic material gets close to a magnet?How do we describe a magnetic field around a permanent magnet

Answers

Answer:

When a diamagnetic substance is placed in a varying magnetic field, it tends to move away from the stronger to the weaker part of the magnetic field.

Explanation:

Diamagnetic atoms are slightly repelled by magnetic fields.

The magnetic fields of permanent magnets are the sums of the nuclear spins, the electron spins and the orbits of the electrons themselves. A magnetic field is stationary and referred to as a magnetostatic field.

where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the workplace?

Answers

Answer:

on the body of the container of the chemical and it also on the shelf where the chemical is kept in the laboratory.

Explanation:

The information on the chemical and physical properties of a specific chemical should  be located on the body of the container of the chemical. when storing chemicals in a laboratory the properties, both chemical and physical properties of the chemical should be written out and pasted on the body of the container that contains the chemicals.and also o the shelf where the chemical is kept in the laboratory or workplace .

What are general shapes of contour lines

Answers

Answer:

Explanation:The less separation between contour lines means a steeper slope and vice versa. When there are evenly spaced contours, the slope is uniform. At a stream junction, contour lines form a “M” or “W” shape. This can be interpreted as two “V-shaped contours intersecting.

Answer:

At a stream junction, contour lines form a “M” or “W” shape. This can be interpreted as two “V-shaped contours intersecting.

Explanation:

None

Bill Nye- Static Electricity Answer Key?

Answers

Search it up :))))))

PLEASE ANSWER CLEARLY :)
A composite material is to be made from type E-glass fibers
embedded in a matrix of ABS plastic, with all fibers to be aligned
in the same direction. For the composite, the el
A composite material is to be made from type E-glass fibers embedded in a matrix of ABS plastic, with all fibers to be aligned in the same direction. For the composite, the elastic modulus parallel to

Answers

The elastic modulus parallel to the fibers of a composite material made of type E-glass fibers embedded in a matrix of ABS plastic, with all fibers to be aligned in the same direction can be calculated as follows:First, we need to calculate the elastic modulus of each component of the composite material.

The elastic modulus of type E-glass fibers is 72 GPa, and the elastic modulus of ABS plastic is 2.5 GPa.Next, we need to calculate the volume fraction of each component. If we assume that the composite material is made up of 60% type E-glass fibers and 40% ABS plastic, then the volume fraction of type E-glass fibers is 0.6, and the volume fraction of ABS plastic is 0.4.

Finally, we can use the rule of mixtures to calculate the elastic modulus parallel to the fibers. The rule of mixtures states that the elastic modulus of a composite material is equal to the weighted average of the elastic moduli of the individual components, where the weights are the volume fractions.

Therefore, the elastic modulus parallel to the fibers is given by:

Elastic modulus parallel to fibers = (Volume fraction of type E-glass fibers x Elastic modulus of type E-glass fibers) + (Volume fraction of ABS plastic x Elastic modulus of ABS plastic)

Elastic modulus parallel to fibers = (0.6 x 72 GPa) + (0.4 x 2.5 GPa)

Elastic modulus parallel to fibers = 43.5 GPaSo, the elastic modulus parallel to the fibers of the composite material is 43.5 GPa.

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A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.50 km/s in the +x-direction experiences a force of 2.06×10−16 N in the +y-direction, and an electron moving at 4.20 km/s in the −z-direction experiences a force of 8.60×10−16 N in the +y-direction.
Part A
What is the magnitude of the magnetic field?
Part B
What is the direction of the magnetic field? (in the xz-plane)
Part C
What is the magnitude of the magnetic force on an electron moving in the −y-direction at 3.50 km/s ?
Part D
What is the direction of this the magnetic force? (in the xz-plane)

Answers

part a: The magnitude of the magnetic field is 1.17 × 10−5 T. part b:  Therefore, the direction of the magnetic field is in the xz-plane.(explanation below). part c: The magnitude of the magnetic force on an electron moving in the −y-direction at 3.50 km/s is 9.02 × 10−14 N. part d: Therefore, the direction of the magnetic force in the xz-plane is in the +z direction. are the answers

Part A:

The magnetic field is given by the formula:

F= qvBsinθ

where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field and θ is the angle between the velocity of the particle and the magnetic field.

The force on proton moving in the +x direction,

Fp = 2.06×10−16 N and the

velocity,  vp = 1.50 km/s = 1.5 × 10^3 m/s

Putting the values in the formula:

Fp= qvpBsinθp

2.06×10−16 = (1.60 × 10−19)(1.50 × 10^3)Bsinθp

where q is the charge of proton which is 1.6 × 10−19 C

The angle θp between the velocity and the magnetic field is 90° since the force is perpendicular to the velocity and the magnetic field.

Sin 90° = 1

Substituting the values, we get

B = 1.17 × 10−5 T

The magnitude of the magnetic field is 1.17 × 10−5 T

Part B:

The direction of the magnetic field can be obtained from the force on the electron moving in the -z direction and the force is given by

Fe = 8.60×10−16 N

and the velocity,

ve = 4.20 km/s = 4.2 × 10^3 m/s

Putting the values in the formula:

Fe= qveBsinθe8.60×10−16 = (1.60 × 10−19)(4.2 × 10^3)Bsinθe

where q is the charge of electron which is 1.6 × 10−19 C

The angle θe between the velocity and the magnetic field is 90° since the force is perpendicular to the velocity and the magnetic field.

Sin 90° = 1

Substituting the values, we get

B = 1.68 × 10−5 T

Since the force is in the +y direction and the velocity is in the -z direction, the magnetic field should be in the +x direction.

Therefore, the direction of the magnetic field is in the xz-plane.

Part C:

The magnitude of the magnetic force on an electron moving in the −y-direction at 3.50 km/s is given by the formula:

F= qvBsinθ

where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field and θ is the angle between the velocity of the particle and the magnetic field.

The velocity of the electron, ve = 3.50 km/s = 3.5 × 10^3 m/s

The angle between the velocity of the particle and the magnetic field is 90° since the force is perpendicular to the velocity and the magnetic field.

θ = 90° = π/2

Substituting the values in the formula:

F= qveBsinθF = (1.60 × 10−19)(3.5 × 10^3)(1.68 × 10−5) × 1F = 9.02 × 10−14 N

The magnitude of the magnetic force on an electron moving in the −y-direction at 3.50 km/s is 9.02 × 10−14 N.

Part D:

The direction of the magnetic force can be obtained from the right-hand rule. The direction of the magnetic force is perpendicular to both the magnetic field and the velocity of the particle.The velocity of the electron is in the -y direction and the magnetic field is in the +x direction. Using the right-hand rule, the direction of the magnetic force is in the +z direction.

Therefore, the direction of the magnetic force in the xz-plane is in the +z direction.

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a student tries to produce notes of higher frequency by blowing a trumpet harder. he will succeed?​

Answers

Answer:

Please mark as Brainliest!!

Explanation:

He will not succeed as it blows the trumpet harder that only increase the amplitude of the sound wave that means the intensity of the sound will increase but the frequency remains the same.

Answer:

he wont

Explanation:

please help me. i have a picture to help you guys help me lol please help

please help me. i have a picture to help you guys help me lol please help

Answers

Answer:

a. $10.3 per compact disc

b. $10.3 dollars

c. Linear model

Explanation:

a. 10.3 dollars/compact disc ==>$10.3 per compact disc

b. 10.3 dollars

c. Linear model. Linear models have a constant slope.

give the 5 concepts of physical activity and give a short example each​

Answers

Answer:

The 5 components of physical fitness are often used in our school systems, health clubs and fitness centers to gauge how good a shape we are truly in. The 5 components that make up total fitness are:

• Cardiovascular Endurance

• Muscular Strength

Muscular endurance

Flexibility

Body Composition

Total fitness can be defined by how well the body performs in each one of the components of physical fitness as a whole. It is not enough to be able to bench press your body weight. You also need to determine how well you can handle running a mile etc.

Explanation:

hope to help

Somatic versus Sex Cells


2. How do the chromosomes in most cells of an organism, such as the leaf cells of a plant, compare to the chromosomes in its reproductive cells, which are sperm and egg cells?

Answers

Most cells in an organism, such as leaf cells in a plant, are somatic cells. Somatic cells contain two sets of chromosomes, one inherited from each parent, and are diploid. In humans, for example, somatic cells contain 46 chromosomes, arranged in 23 pairs.

On the other hand, reproductive cells, such as sperm and egg cells, are sex cells or gametes. Gametes are haploid, which means they contain only one set of chromosomes, half the number found in somatic cells. In humans, gametes contain 23 chromosomes, which are not arranged in pairs.

The purpose of gametes is to combine during fertilization to produce a zygote, which contains a complete set of chromosomes (i.e., diploid). This ensures that the offspring will have genetic diversity and not be identical to either parent.

The process of reducing the number of chromosomes in gametes from diploid to haploid is called meiosis. Meiosis is a type of cell division that occurs only in gamete cells, and results in the production of four haploid daughter cells, each containing a unique combination of chromosomes.

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who is going to watch the mars occupation tonight?

Answers

that's happening ?????

3. A 700 kg horse has 4000 J of kinetic energy as it is running.
What is the velocity of the horse?
K=
m.v2
2
< PREVIOUS
1
2
O

Answers

Answer:

Explanation:


2. A rectangular block of weight 300N measures 0.1 m by 0.4 m by 1.5 m.
a) Draw a diagram to show how the block must rest to exert the maximum pressure on the ground. Calculate this
pressure.
b) Draw another diagram showing the position of minimum pressure. Calculate this pressure.

2. A rectangular block of weight 300N measures 0.1 m by 0.4 m by 1.5 m.a) Draw a diagram to show how

Answers

Answer:

that's all I could do.hope it helps.

2. A rectangular block of weight 300N measures 0.1 m by 0.4 m by 1.5 m.a) Draw a diagram to show how
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