The Ka expression for the following reaction Cu2+ (ag) +H,O()Cu(OH) (a)+ (aą) iS Cu(OH) H 3.00 x 10 4th attempt What is [H+] if [Cu2+] = 0.965 M? 8.69 3rd attempt

The balanced reaction of this chemical reaction is as follows :

• As we can see, this is a double-displament reaction

On a Space shuttle, LiOH Is used to absorb CO2 to produce LiHCO3

LiOH + CO2 === LiHCO3

Now

58g of CO2 produces 79.3g of LiHCO3

This is the Actual Yield.

Recall

% Yield = Actual yield/Theoretical yield x100

NOW

We have to find the theoretical yield

From the equation of reaction

Now 58g of CO2 reacted

Converting to Moles

mole = Mass/Molar Mass

Molar mass of CO2=44g/mol

Mole = 58/44

=1.318moles of CO2

From the equation Of Reaction.

1 mole of CO2 reacts and Produces 1 mole of LiHCO3

Since their Mole ratio is 1:1

An Equal amount of LiHCO3 will be produced.

So 1.318moles of LiHCO3 will be produced.

Convert this mole to Mass

Mole =Mass/Molar Mass

Mass = Mole x Molar Mas

Molar Mass of LiHCO3 =68g/mol

Mass = 1.318 x 68

Mass = 89.62g.

This is the theoretical Yield.

% yield = 79.3/89.62 x 100

= 88.48%.

Anode rods typically have a lifespan of three to five years, however this is mostly dependent on the quality of your water and the volume of water that passes through your water heater.

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The material that has the largest increase in temperature is B) Cadmium.

The amount of energy required to raise the temperature of one gram of  material by one degree Celsius is called as specific heat capacity. The formula for the change in temperature of a material is ΔT = ΔQ / (m × c)

ΔT is change in temperature, ΔQ is amount of energy added, m is mass of the material, and c is specific heat capacity of the material.

The specific heat capacities of the four materials are:

Iron: 0.45 J/(g°C)

Cadmium: 0.23 J/(g°C)

Silver: 0.24 J/(g°C)

Copper: 0.39 J/(g°C)

ΔT_iron = 100 J / (10.0 g × 0.45 J/(g°C)) = 22.2°C

ΔT_cadmium = 100 J / (10.0 g × 0.23 J/(g°C)) = 43.5°C

ΔT_silver = 100 J / (10.0 g × 0.24 J/(g°C)) = 41.7°C

ΔT_copper = 100 J / (10.0 g × 0.39 J/(g°C)) = 25.6°C

Therefore, material with the largest increase in temperature is Cadmium, with a temperature increase of 43.5°C.

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Answer:

Iron Correct on Acellus

Explanation:

it takes approximately 38.04 years for 16.0 ng of tritium to decay to the point where 2.0 ng remains. The half-life of tritium is 12 years, which means that after 12 years, half of the original amount of tritium will decay. To find out how long it takes for 16.0 ng of tritium to decay to 2.0 ng, we can use the concept of half-life.


Calculate the number of half-lives needed to decay from 16.0 ng to 2.0 ng. First, find the difference in the number of ng: 16.0 ng - 2.0 ng = 14.0 ng. Next, divide this difference by the original amount: 14.0 ng / 16.0 ng = 0.875. This means that 0.875 or 87.5% of the original tritium has decayed. Since each half-life represents a decay of 50%, we need to find the number of half-lives it takes to reach 87.5%.

Calculate the number of half-lives We can use the formula N = (log(final amount) - log(initial amount)) / log(0.5), where N is the number of half-lives. Plugging in the values, we have N = (log(0.875) - log(1)) / log(0.5 Using a calculator, we find N ≈ 3.17.

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Answer:

Nuclear fusion is the process by which two or more atomic nuclei join together to form a single heavier nucleus and large amounts of energy.

8) Percent yield = (0.48 g / 36 g) x 100% = 1.33%

9) Percent yield = (248 g / 176 g) x 100% = 141%

10) Percent yield = (45 g / 120 g) x 100% = 37.5%

The same units must be used for both the theoretical and actual yields (moles or grams). A chemical reaction produces 0.5 g of product. The calculated yield is 1.6 g at its highest. What is the reaction's yield in terms of percent? Actual yield minus theoretical yield equals 100% in percentage yield. The reaction's percentage yield is 31.25% as a result.

8) Known: 2 H2(g) + O2(g) → 2 H2O(1)

Unknown: percent yield

Steps:

Calculate the theoretical yield of water by using the balanced equation.

Compare the theoretical yield to the actual yield of water obtained from the experiment.

Use the formula: (Actual yield / Theoretical yield) x 100% = percent yield

Solution:

Theoretical yield of water = (2 moles H2 x 18 g/mol H2O) = 36 g

Actual yield of water = 0.48 g

Percent yield = (0.48 g / 36 g) x 100% = 1.33%

9) Known: 2 C2H6(g) + 7 O2(g) → 6 H2O(l) + 4 CO2(g)

Unknown: percent yield

Steps:

Calculate the theoretical yield of CO2 by using the balanced equation.

Compare the theoretical yield to the actual yield of CO2 obtained from the experiment.

Use the formula: (Actual yield / Theoretical yield) x 100% = percent yield

Solution:

Theoretical yield of CO2 = (2 moles C2H6 x (4 moles CO2 / 2 moles C2H6)) = 4 moles CO2

Theoretical yield of CO2 = 4 moles CO2 x (44 g/mol CO2) = 176 g

Actual yield of CO2 = 248 g

Percent yield = (248 g / 176 g) x 100% = 141%

10) Known: 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(1)

Unknown: percent yield

Steps:

Calculate the theoretical yield of NO by using the balanced equation.

Compare the theoretical yield to the actual yield of NO obtained from the experiment.

Use the formula: (Actual yield / Theoretical yield) x 100% = percent yield

Solution:

Theoretical yield of NO = (4 moles NH3 x (4 moles NO / 4 moles NH3)) = 4 moles NO

Theoretical yield of NO = 4 moles NO x (30 g/mol NO) = 120 g

Actual yield of NO = 45 g

Percent yield = (45 g / 120 g) x 100% = 37.5%

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Answer:

Explanation:

a) 202.4 g

b) 185.24 m

c) 0.13 dm

d) 6.91 L

e)0.0546 mol

f) 2.7 s

g) 42kg

h) 0

i) -0.11 g

j) -0.34 mL

Answer:

To make a 4.0 M LiBr solution with 100.0 g of LiBr, you will need to make a total volume of 25.0 L. This is calculated using the formula: volume = (moles of solute) x (molarity of solution) x (volume of solution). In this case, the moles of solute is 2.5 mol LiBr (calculated using the formula moles = mass/molar mass), the molarity of the solution is 4.0 M, and the volume of the solution is 25.0 L. Therefore, the total volume of the 4.0 M LiBr solution made with 100.0 g of LiBr is 25.0 L.

make me brainiest

Answer:

c

Explanation:

Answer:

C: 4

H: 1

Mg: 2

O : 6

Explanation:

You can quickly find out the number of valence electrons by looking at where the element is on the periodic table and referring to the table that is attached.

Answer:

Cannot be determined

Explanation:

Hi there,

Could you please add an attachment of the table? We cannot tell what the errors are if there is no table.

Answer:

SYMBOLS, FORMULAS AND MOLAR MASSES

OBJECTIVES

1. To correctly write and interpret chemical formulas

2. To calculate molecular weights from chemical formulas

3. To calculate moles from grams using chemical formulas

INTRODUCTION

Part I. Symbols and formulas

An element is a homogeneous pure substance made up of identical atoms. All matter is made

up of elements and, since chemistry is the study of matter, it is convenient to use symbols to represent

the elements rather than using the entire name.

By international agreement, specific symbols are assigned to each element (Note: This means

that while names of the elements vary with language, symbols are constant throughout the world.) Each

element is assigned a one- or two-letter symbol. The first letter is capitalized, the second (if there is

one) is not. While this often seems trivial, it is in fact a very important point. For example, in chemical

language Co represents cobalt, which is a metal and an element, while CO represents carbon monoxide,

a compound which is a colorless, odorless gas! Even when there is not an obvious correspondence,

for instance "MN", it can cause confusion. Do you mean the element manganese? Did you forget a

letter and mean something else? Are you using "M" to represent something else entirely? Chemists

sometimes use "M" to represent any metal. It is well worth the trouble to memorize the symbols for

common elements.

Since compounds consist of elements, the chemical formulas of compounds also consist of

elements with subscripts used to denote the number of atoms per molecule. If there is no subscript, it is

implied that there is one of that kind of atom. Ones never appear in chemical formulas. Not only do

subscripts denote ratios of atoms, they also denote the ratio of moles of element to one mole of

compound. Parentheses can be used to show groups of atoms, with the subscripts showing how many

groups there are. Parentheses are not used if there is only one group.

Examples: For one mole of the following compounds, how many moles of each element are

present?

MgCl2 1 mole Mg, 2 moles Cl

Mg(NO3)2 1 mole Mg, 2 moles N, 6 moles O

NaNO3 1 mole Na, 1 mole N, 3 mole O

AgCl 1 mole Ag, 1 mole ClPart II. Molar Masses

Each atom has a different size and therefore a different mass. The relative masses of each

element can be found on the periodic table. For example, one atom of magnesium weighs 24.31 amu

(atomic mass units). However, one mole of magnesium weighs 24.31 g. (Moles were planned that

way!) Since one mole of MgCl2 consists of one mole of magnesium and two moles of chlorine, the

mass of one mole of MgCl2 must be the sum of the masses of the elements. The mass of one mole of a

substance is called the molar mass or molecular weight.

Examples: What is the molar mass of the following compounds?

MgCl2 24.31 + 2(35.45) = 95.21 g/mol

Mg(NO3)2 24.31 + 2(14.01) + 6(16.00) = 148.33 g/mol

NaNO3 23.00 + 14.01 + 3(16.00) = 85.01 g/mol

AgCl 107.9 + 35.45 = 143.4 g/mol

(Note: Yes! You DO have to count significant figures when calculating molecular weight/molar

mass. However, the number of significant figures may vary depending on which periodic table you use.)

Chemists are generally interested in number of moles. Unfortunately, it is impossible to measure

moles directly. However, masses are easily measured, and if the chemical formula of the compound is

known, the molar mass can be used to determine the number of moles. The molar mass is defined as:

molar mass = grams/moles = g/mol (1)

Moles may be calculated by using molar mass as a conversion factor in dimensional analysis where

molar mass in grams = 1 (exactly) mole of compound (2)

This method is used in multi-step calculations. For example, if 0.873 g of MgCl2 is weighed out, it

is 9.17 x 10-3

moles.

1 mole

0.873g x 95.21 g = 9.17 x 10-3

mol MgCl2 (3)

However, 0.873 g of AgCl is only 6.09 x 10-3

mol.

1 mole

0.873g x 143.4 g = 6.09 x 10-3

mol AgCl (4)Molar mass may also be used to relate moles to grams. For example, 0.158 mol of MgCl2 is 15.2 g.

0.158 mol x 95.21 g = 15.2 g MgCl2 (5)

1 mol

Percent is used to express parts per one hundred. Usually in chemistry, it refers to

g of species of interest x 100 = % (6)

g of whole thing

Example: For the % Mg in MgCl2: In one mole of MgCl2, there are 24.31 g of Mg (molar mass of Mg,

the part we are interested in) and 95.21 g of MgCl2 (the whole thing), so %Mg in MgCl2 is

(24.31/95.21) x 100 = 25.53% Mg (7)

PROCEDURE

Work individually.

The formula for calcium phosphate is Ca3(PO4)2. Weigh about 2 g of calcium phosphate to the

nearest 0.001 g. In other words, you do not have to have exactly 2.000g, but you must know the

weight you have exactly. Acceptable results include but are not limited to: 1.985g , 2.035g, 2.314g

etc.

Be sure to report all results with the correct number of significant figures and appropriate units!

Answer:

B   proofread the message.

Explanation: Hope this helped

Answer:

59

Explanation:

The acid associated with \(NH_3\) is \(NH_4^+\), with I- is HI, with \(SO_4^{2-}\) is \(HSO_4^-\), with Cl- is HCl, with OH- is \(H_2O\), and with F- is HF.

1. NH3: It is a base that accepts a hydrogen ion (H+) from an acid. \(NH_3 + H^+ --> NH_4^+\). The acid associated with \(NH_3\) is \(NH_4^+\).

2. I-:  is a base that accepts a hydrogen ion (H+) from an acid. \(I^- + H^+ --> HI\) . The acid associated with I- is HI.

3. \(SO_4^{2-}\) : is a base that accepts a hydrogen ion (H+) from an acid. \(SO_4^{2-} + H^+ --> HSO_4^-\). The acid associated with \(SO_4^{2-}\) is \(HSO_4^-\).

4. Cl-: is a base that accepts a hydrogen ion (H+) from an acid. Its conjugate acid is the species formed when Cl- accepts a hydrogen ion (H+). \(Cl^- + H^+ --> HCl\). The acid associated with Cl- is HCl.

5. OH-: It is a base that accepts a hydrogen ion (H+) from an acid. Its conjugate acid is the species formed when OH- accepts a hydrogen ion (H+). \(OH^- + H^+ --> H_2O\). The acid associated with OH- is \(H_2O\).

6. F-:  It is a base that accepts a hydrogen ion (H+) from an acid. \(F^- + H^+ --> HF\).  The acid associated with F- is HF.

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The new water level will be = 20 + 5.45 = 25.45 mL.

First step is to calculate the volume of the copper cylinder as follows:

density = mass / volume

volume = mass / density = 48.85 / 8.96 = 5.45 mL

Then we add the volume of the cylinder to the volume of water to get the new water level:

New water level = 20 + 5.45 = 25.45 mL

The elevation of a sea, stream, lake, or reservoir's free surface in relation to a given vertical datum is referred to as the water level, sometimes known as gauge height or stage.

To determine how much is in the tank, ultrasonic sensors use sound waves that bounce off the surface of the liquid. These liquid level sensors feature an accuracy of 0.25% of the detected range and a precision of up to 0.1 in. (2.5 mm) (current reading).

The level spot on two objects that are distant from one another, like posts or stakes in the ground, is frequently determined by the water level.

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The melting point of the sample if it is not dried completely after filtering the recrystallized product will have a broad range and will occur at lower range than the actual value.

What is melting point?

Melting point is the temperature at which the solid form of a given substance changes to the liquid form at atmospheric pressure. It is important because, by using the physical property of a substance the substance can be identified.

The sharp range melting point of the substance indicates the purity of the substance. If the sample is not dried completely after recrystallisation, the melting point will have a broad range.

Therefore, if the sample given is not dried completely, it will be impure and the decreases the melting point of the substance. So the actual melting point of the substance cannot be determined.

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The solution with the highest value of i is therefore A, 0.1 M K2SO4, which should have the most ideal behavior.

The colligative properties of a solution are the properties that are dependent on the concentration of the solute particles rather than their identity. Osmotic pressure, boiling point elevation, freezing point depression, and vapor pressure lowering are examples of colligative properties of a solution.

The solution with the most ideal behavior would have the greatest value of van't Hoff factor i, which represents the number of particles into which a substance dissociates when it is dissolved in a solvent.

A. K2SO4, 0.1 M: Since it is an ionic compound, K2SO4 should dissociate into three ions when dissolved in water: 2K+ and SO42-. This results in an i value of 3.

B. CaCl2, 0.1 M: CaCl2 should dissociate into three ions when dissolved in water: Ca2+ and 2Cl-. This results in an i value of 3.

C. LiF, 3.0 M: LiF is a covalent compound, which does not dissociate in aqueous solution. Therefore, the i value will be 1.

D. MgSO4, 0.1 M: MgSO4 should dissociate into three ions when dissolved in water: Mg2+ and SO42-. This results in an i value of 3.

E. NaCl, 0.1 M: NaCl should dissociate into two ions when dissolved in water: Na+ and Cl-. This results in an i value of 2.

The solution with the highest value of i is therefore A, 0.1 M K2SO4, which should have the most ideal behavior.

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Answer:

Fingerprints are determined by your genetic makeup.  

Explanation:

Despite how much you attempt to remove them, they will grow back because of your DNA.

There are 7.253 x 10^24 H atoms in 17.5 g (NH4)2C2O4.

Avogadro's number is the number of atoms, molecules, or particles in one mole of a substance, which is approximately 6.022 x 10^23.

To determine the number of H atoms in 17.5 g (NH4)2C2O4, we need to first calculate the number of moles of (NH4)2C2O4 using its molar mass and then use the mole ratio between H atoms and (NH4)2C2O4.

The molar mass of (NH4)2C2O4 can be calculated as follows:

Molar mass of NH4 = 14.01 g/mol

Molar mass of C2O4 = 2 * 12.01 g/mol + 4 * 16.00 g/mol = 88.04 g/mol

Molar mass of (NH4)2C2O4 = 2 * molar mass of NH4 + molar mass of C2O4

= 2 * 14.01 g/mol + 88.04 g/mol

= 116.06 g/mol

Number of moles of (NH4)2C2O4 = mass / molar mass

= 17.5 g / 116.06 g/mol

= 0.1507 mol

The mole ratio between H atoms and (NH4)2C2O4 is 8:2, which means that there are 8 H atoms for every 2 (NH4)2C2O4 units. Therefore, we can calculate the number of H atoms as follows:

Number of H atoms = 8 * Avogadro's number * number of moles of (NH4)2C2O4

= 8 * 6.022 x 10^23 * 0.1507

= 7.253 x 10^24 H atoms

Therefore, there are approximately 7.253 x 10^24 H atoms in 17.5 g (NH4)2C2O4.

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Answer:b

Explanation:

The general period and group trends among the main-group elements with respect to each of the following properties are as follows:

Periodic trends are the trends followed by the properties of the elements going down a group or across a period in the periodic table.

The properties of elements that show periodic trends include:

a. atomic radii - the size of an atom of an element

b. first ionization energy - the energy required to remove a valence electron

c. electron affinity - the energy required to add an electron to a neutral atom

d. ionic radii - the size of the ion of an element

e. electronegativity - the ability to attract electrons

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This might help you with your question.

This is a person who scientific researches to make more knowledge in a certain area of interest

Answer:

b

Explanation:

Answer: d:the color change that takes place after heat melts and begins to decompose the sugar

Explanation:i did the study island

Answer:

It has a lower density in its solild stae than it does in its liquid state.

Explanation:

Ice floats, allowing life underneath to leave despite the top freezing.

The statement that describes a unique property of water that helps sustain marine life is that has a lower density in its solid state than it does in its liquid state.

Water is a unique molecule that possesses unique properties as follows:

These unique characteristics of water helps aquatic organisms sustain life in a marine environment.

Therefore, statement that describes a unique property of water that helps sustain marine life is that has a lower density in its solid state than it does in its liquid state.

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The pKw of water at this temprature would be 4, by using the formula for pKw

Although this dissociation is mild, water can split into its ions. The Kw is the dissociation constant, and the ionic product tends to remain constant.

Kw is the equilibrium constant that is connected to the molarity of water in an aqueous solution, so to speak. The concentration of a solute in a solution is indicated by its molarity or molar concentration, which is a volume that varies on temperature.

As a result, whereas the molarity in aqueous solutions is essentially constant, the pKw varies with temperature. When the temperature rises, the pKw decreases; when the temperature falls, the pKw rises.

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Answer:

Earth

Explanation:

The Earth and the sun are the part of the solar system and the earth and other planets revolve around the Sun. The solar system is placed in the universe.