The jogger ran 3km east.
4. Look at the bottom figure. Suppose that a car is 20 km due north of New York City. The car
travels north toward Albany until it is 100 km due north of New York City.

The following which is the best example of a thermodynamically open system is a cup of coffee and is therefore denoted as option A.

This is referred to as the type of system in which matter and/or energy may enter and exit. There is also an exchange of both matter and energy with its surroundings.

An example is a cup of coffee because thermal energy is lost to the surrounding which is usually in the form of vapor. Other options such as our universe and  insulated gas cylinder are closed system which is why there is usually no exchange of energy with external environment thereby making it the correct choice.

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The full question is:

which if the following is the best example of a thermodynamiclly open system?

A. a cup of coffee

B. our universe

C. a greenhouse

D. an insulated gas cylinder

When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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Answer:

The nucleus-containing cells are called eukaryotic cells. Eukaryote means having membrane-bound organelles.

Explanation:

I hope this is what you were looking for?!

Hope this helps!

Have a great day!

-Hailey!

The cells which have a nucleus are called Eukaryotic cells. The cells which do not have a nucleus are called prokaryotic cells.

The nucleus is the controlling center of the body. It performs all the major activities in the cell. The cell which possesses a nucleus is called a eukaryote. The cell which does not have a nucleus is called prokaryote.

A prokaryotic cell is a straightforward, one-celled (unicellular) organism that is devoid of a nucleus or any other organelle that is membrane-bound. The nucleoid, a dark area in the center of the cell, is where prokaryotic DNA is located.

Therefore, The cells which have a nucleus are called Eukaryotic cells. The cells which do not have a nucleus are called prokaryotic cells.

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Answer:

1 Proton, 1 Electron, No Neutrons

Group 1, Period 1

Gases

Answer:

10.2 lbs

Explanation:

m=F/g

m=100N/9.8

m=10.2040816 lbs

The weight of the object in pounds will be 220.46 pounds m/s².

We have an object on Earth whose weight is 100 N.

We have to determine its weight in pounds.

Pounds is used to represent the mass of the body.

According tot the question -

Weight on earth = 100 N = 100 Kg . m/s²

1 Kg = 2.2046 Pounds

Therefore, the weight on earth in pounds will be = 100 x 2.2046 pounds m/s² = 220.46 pounds m/s².

Hence, the weight of the object in pounds will be 220.46 pounds m/s².

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Coefficient of Kinetic Friction = 0.2

Mass of the crate = 1000 kg

Force applied = 2000 N

Normal force is the force applied on the object by the surface. It is equal and opposite to the force of gravity

So, we can say that Normal force = | Gravitational Force |

Normal Force = | mg |

Normal Force = 1000 * 9.8

Normal Force = 9800 N

We know that:

coefficient of Kinetic friction = Friction force / Normal force

replacing the known values

0.2 = Friction force / 9800

Friction Force=  0.2 * 9800

Friction Force = 1960 N

We know that a force of 2000 N is being applied on the crate in the Horizontal direction

Frictional force is always opposite to the horizontal force. So, we can say that:

Applied force - Friction Force = Net Force

replacing the variables

2000 - 1960 = Net force

Net Force = 40N

Therefore, a net force of 40N is being applied on the Crate

From newton's second law of motion:

F = ma

replacing the variables

40 = 1000 * a

a = 40/1000

a = 0.04 m/s²

Hence, the crate will have an acceleration of 0.04 m/s²

Iron is magnetic, so any metal with iron in it will be attracted to a magnet. Steel contains iron, so a steel paperclip will be attracted to a magnet too. Most other metals, for example aluminium, copper and gold, are NOT magnetic. Two metals that aren't magnetic are gold and silver.

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{force}{mass} \\ \)

From the question

force = 97.7 N

mass = 34.2 kg

We have

\(a = \frac{97.7}{34.2} = 2.856725 \\ \)

We have the final answer as

Hope this helps you

Answer:

Right

Explanation:

Coil move right yes

Answer:

what's the question? .

Answer:

\(Va-Vb=168KV\)

Explanation:

From the question we are told that

Two points charge of 4\mu C and 2\mu C

Generally we find the  Va and Vb individually to find there difference

Given a rectangle with two equal sides each,Assume lengths for bot sides

Length L=0.3

Breath B=0.4

Diagonal D=\(\sqrt{0.3^2+0.4^2} =0.5\)

at  opposite sides

Mathematically Va can represented as

\(Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )\)

\(Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )\)

\(Va =9*10^9(0.00001333333-0.000004} )\)

\(Va =84000V\)

\(Va =84KV\)

Mathematically Vb is  represented as

\(Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )\)

\(Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )\)

\(Va =9*10^9(-0.00001333333+0.000004} )\)

\(Va =-84000V\)

\(Va =-84KV\)

Therefore

\(Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV\)

Answer:

delivery truck

Explanation:

because i got it right

Answer:

no

Explanation:

can form either real or virtual images. Convex lens converge parallel rays coming from object at infinity and highly diminished point sized, real and inverted image is formed.

Answer:

no it does not forms a real image

Explanation:

Thanx for the figure;
The force component of F   UP the ramp that  moves the crate must equal the force of the crate DOWN the ramp

75 kg = mg Newtons = 735.8 Newtons

    Downplane force is   735.8 sin 34°  = 411.4 Newtons

   Fn =The horizontal force will be found by   cos 34 = 411.4/ F                                                                       F = 411.4/cos (34) = 496 N

Normal Force =  735.8 cos 34°  = 610 N   This part is due to the mass of the crate....there is additional normal force from the force pushing the crate up the hill  (from below)

   = F sin34   =  496 sin 34 = 277.4 N

            SUM of normal forces = 610 + 277.4 = 887.4 N

Answer:

  a.  |F| ≈ 496 N

  b.  normal force ≈ 887 N

Explanation:

You want the magnitude of the horizontal force F that moves a crate up a 34° ramp at constant speed, and you want the magnitude of the normal force on the crate.

The constant speed of the crate tells you the net force up the ramp is zero. This is the sum of the component of force F in that direction and the force due to gravity in the opposite direction:

  F·cos(34°) - m·g·sin(34°) = 0

  F = mg·tan(34°) = (75 kg)(9.8 m/s²)tan(34°) ≈ 496 N

The magnitude of force F is about 496 N.

The normal force on the crate will be the sum of the component of F in that direction and the force due to gravity in the same direction:

  F·sin(34°) +m·g·cos(34°) ≈ 887 N

The magnitude of the normal force is about 887 N.

Answer:

(a)    f = 0.58Hz

(b)    vmax = 0.364m/s

(c)    amax = 1.32m/s^2

(d)    E = 0.1J

(e)    \(x(t)=0.1m\ cos(2\pi(0.58s^{-1})t)\)

Explanation:

(a) The frequency of the oscillation, in a spring-mass system, is calulated by using the following formula:

\(f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}\)          (1)

k: spring constant = 20.0N/m

m: mass = 1.5kg

you replace the values of m and k for getting f:

\(f=\frac{1}{2\pi}\sqrt{\frac{20.0N/m}{1.5kg}}=0.58s^{-1}=0.58Hz\)

The frequency of the oscillation is 0.58Hz

(b) The maximum speed is given by:

\(v_{max}=\omega A=2\pi f A\)     (2)

A: amplitude of the oscillations = 10.0cm = 0.10m

\(v_{max}=2\pi (0.58s^{-1})(0.10m)=0.364\frac{m}{s}\)

The maximum speed of the mass is 0.364 m/s.

The maximum speed occurs when the mass passes trough the equilibrium point of the oscillation.

(c) The maximum acceleration is given by:

\(a_{max}=\omega^2A=(2\pi f)^2 A\)

\(a_{max}=(2\pi (0.58s^{-1}))(0.10m)=1.32\frac{m}{s^2}\)

The maximum acceleration is 1.32 m/s^2

The maximum acceleration occurs where the elastic force is a maximum, that is, where the mass is at the maximum distance from the equilibrium point, that is, the acceleration.

(d) The total energy of the system is:

\(E=\frac{1}{2}kA^2=\frac{1}{2}(20.0N/m)(0.10m)^2=0.1J\)

The total energy is 0.1J

(e) The displacement as a function of time is:

\(x(t)=Acos(\omega t)=Acos(2\pi ft)\\\\x(t)=0.1m\ cos(2\pi(0.58s^{-1})t)\)

Answer: An jack makes changing a tire easier because it lifts up the car to get the tire off of the ground.

Explanation:

Answer: B

Explanation: the teacher just told us the answer

The gravitational force between the two spheres is \(1.67 \times 10^{-11} \ N\).

The given parameters;

The gravitational force between the two spheres is determined by applying Newton's law of universal gravitation as shown below;

\(F = \frac{Gm_1 m_2 }{r^2} \\\\\)

where;

\(F = \frac{(6.67\times 10^{-11})\times (1\times 1)}{2^2} \\\\F = 1.67 \times 10^{-11} \ N\)

Thus, the gravitational force between the two spheres is \(1.67 \times 10^{-11} \ N\).

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Answer:

96,000joules!!!

Explanation:

Hope this helps u

Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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Answer:

No.

Explanation:

When the ball is kicked it has Gravity, Normal Force and applied force.

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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46)

Since air resistance is ignored, both cannonballs will fall with the same acceleration due to gravity, which is approximately 9.8 m/s^2. The horizontal velocity of cannonball A does not affect its vertical motion, so it will fall at the same rate as cannonball B.

The time it takes for an object to fall to the ground from a certain height is given by the formula t = sqrt(2h/g), where t is the time, h is the initial height, and g is the acceleration due to gravity.

For cannonball B, which is dropped from a height of 20 meters, the time it takes to reach the ground is:

t = sqrt(2h/g) = sqrt(2*20/9.8) = 2.02 seconds

For cannonball A, which is fired horizontally with a velocity of 5 m/s, the time it takes to reach the ground is also 2.02 seconds, since the vertical motion is the same as cannonball B.

Therefore, both cannonballs will hit the ground at the same time.

47)

The recoil speed of the cannon can be calculated using the principle of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.

Before firing, the total momentum of the system is zero, since the cannon and cannonball A are at rest. After firing, the cannonball A has a momentum of 5 kg * 5 m/s = 25 kg m/s to the right, so the cannon must have an equal and opposite momentum to the left in order to conserve momentum.

The mass of the cannon is 500 kg, so its momentum after firing will be:

p = -25 kg m/s

The velocity of the cannon can be found using the equation:

p = mv

where p is the momentum, m is the mass, and v is the velocity. Solving for v, we get:

v = p/m = (-25 kg m/s) / (500 kg) = -0.05 m/s

Since the momentum of the cannon is negative, the recoil velocity is also negative, indicating that the cannon will move to the left after firing. The magnitude of the recoil velocity is 0.05 m/s, or approximately 0.18 km/h.

(1) The effective spring constant of the system is 7.14 N/m.

(2) The maximum x-acceleration of the glider is 0.9 m/s².

(3) The x-coordinate of the glider at time t= 0.650T is 0.28 m.

(4) The kinetic energy of the glider at x=0.00 m is 0.0175 J.

The effective spring constant of the system is calculated as follows;

F = kx

where;

k = F/x

k = 0.5/0.07

k = 7.14 N/m

a = ω²x

where;

ω = √k/m

ω = √(7.14/0.55)

ω = 3.6 rad/s

a =  (3.6)² x 0.07

a = 0.9 m/s²

T = 2πx/v

T = 2πx/(ωx)

T = 2π/ω

T = 2π/(3.6)

T = 1.75 seconds

t = 0.65T

t = 0.65 x 1.75

t = 1.14 seconds

x = vt

x = (ωx)t

x = (3.6 x 0.07) x 1.14

x = 0.28 m

apply the principle of conservation of energy

Kinetic energy = work done by the spring

Kinetic energy = average force x distance

Kinetic energy = ¹/₂(0.5 N) x 0.07 m

Kinetic energy = 0.0175 J

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The complete question is below:

A 0.550 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.500 N to displace the glider to a new equilibrium position, x= 0.070 m.

1. Find the effective spring constant of the system.

2. The glider is now released from rest at x= 0.070 m. Find the maximum x-acceleration of the glider.

3. Find the x-coordinate of the glider at time t= 0.650T, where T is the period of the oscillation.

4. Find the kinetic energy of the glider at x=0.00 m.

The concrete walls' strength, stability, and resistance to water and fire damage can help to reduce the effects of natural phenomena on buildings.

Concrete home construction gives a wall structure that is more durable than steel and wood. Concrete walls do not deteriorate when exposed to moisture from wind-driven rain, diffusion, or airflow. Contrary to steel, concrete does not rust when exposed to moisture. Termites are resistant to concrete barriers.

Powerful building materials like steel and concrete support the home's façade, and ceilings made of western red cedar temper the industrial style inside. These constructions are resistant to natural calamities since they are constructed of sandbags, barbed wire, and soil.

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Answer:

The total energy must be .7 J + .3 J = 1 J     for a particle at the endpoint or midpoint of motion.

Also,    omega = (k / m)^1/2

f = omega / (2 * pi)

omega^2 = 4 pi^2 * f^2 = k / m    

k = 4 * pi^2 * f^2 * m = 40.05

Max KE or PE = 1/2 k A^2

A^2 = 2 * E / k = 2 * 1 / k = .0499

A = .223 meters

Answer:

Frequency of the wave = 2 x 10³ hz

Explanation:

Given:

Velocity of wave = 5 x 10⁴

Wavelength = 2.5 x 10¹

Find:

Frequency of the wave

Computation:

Frequency of the wave = Velocity of wave / Wavelength

Frequency of the wave = [5 x 10⁴] / [2.5 x 10¹]

Frequency of the wave = 2 x 10³ hz

The frequency of a wave traveling at 5.00 x 10⁴ meters per second and a wavelength of 2.50x10¹ meters is 2 × 10³ Hz

HOW TO CALCULATE FREQUENCY:

λ = v/f

Where,

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