Considering the Charles' law, the initial temperature of a balloon is 25°C or 298 K and final temperature is 596 K or 323 °C.
Definition of Charles' lawCharles' law establishes the relationship between the temperature and the volume of a gas when the pressure is constant and expresses that the volume is directly proportional to the temperature of the gas: If the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles' law states that if the amount of gas and the pressure remain constant, the ratio between the volume and the temperature always has the same value:
V÷T= k
where:
V is the volume.T es the temperature.k is a constant.Being 1 an initial state and 2 a final state, it is fulfilled:
V₁÷T₁= V₂÷T₂
Final temperatureIn this case, you know:
V₁= 2.3 LT₁= 25 °C= 298 K (being 0°C=273 K)V₂= 4.6 LT₂= ?Replacing in the definition of Charles' law:
2.3 L÷ 298 K= 4.6 L÷T₂
Solving:
(2.3 L÷ 298 K)×T₂= 4.6 L
T₂= 4.6 L÷ (2.3 L÷ 298 K)
T₂= 596 K= 323 °C
Finally, the final temperature is 596 K or 323 °C.
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Answer:
Explanation:
In all, an estimated 8,000 to 10,000 Iraqi forces were killed, in comparison with only 300 coalition troops. Though the Gulf War was recognized as a decisive victory for the coalition, Kuwait and Iraq suffered enormous damage, and Saddam Hussein was not forced from power.
hope this helps a lot!
During a class presentation, your classmate explains that plants perform photosynthesis and animals perform cellular respiration. In your own words, describe what these processes are and explain why your classmate’s statement is correct or incorrect.
My classmate's statement in incorrect because plants are also composed of cells.
All living things are composed of cells. A cell is the smallest unit of living organisms. Cells obtain energy via the process of cellular respiration. During cellular respiration, glucose is broken down to yield carbon dioxide and water.
In photosynthesis, carbon dioxide and water are combined to form glucose. The two processes are opposites of each other. Plants produce their own food via photosynthesis. Since plants are composed of cells, plant cells also undergo cellular respiration therefore my classmate's statement in incorrect.
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Hydrogen reacts with oxygen according to the balanced equation
2H₂ (g) + O2(g) → 2H₂O(g). If X is the number of molecules of H₂ which react,
then the number of O2 molecules reacting is
Answer:
x/2
Explanation:
X = 2 molecules of H2
For 2 molecules of H2, there's only 1 molecule of O2. Meaning, there's twice the amount of H2, so O2 = x/2 molecules.
I hope I'm understanding this question right.
A student weighs out a 5.69 g sample of , transfers it to a 250. mL volumetric flask, adds enough water to dissolve it and then adds water to the 250. mL tick mark.What is the molarity of magnesium sulfate in the resulting solution?
We will convert the volume of the solvent from mL to L, then we will calculate the mass concentration:
\(\begin{gathered} volume:250mL\times\frac{1L}{1000mL}=0.25L \\ \\ mass\text{ }conc.=\frac{mass}{volume} \\ \\ mass\text{ }conc.=\frac{5.69g}{0.25L} \\ mass\text{ }conc.=22.76gL^{-1} \end{gathered}\)We will convert the mass concentration to molar concentration:
\(\begin{gathered} molar\text{ }conc.=\frac{mass\text{ }conc.}{molar\text{ }mass(MgSO_4)} \\ \\ molar\text{ }conc.=\frac{22.76\text{ }gL^{-1}}{120.366\text{ }gmol^{-1}} \\ \\ molar\text{ }conc.=0.189\text{ }molL^{-1} \end{gathered}\)Answer: Molarity of MgSO4 is 0.189M.
35. How many atoms are in 39.2 moles? (1 mole = 6.02 x 10 23 atoms)
A. 2.36 x 10 25atoms
B.
6.5 x 10 23 atoms
C.
6.5 x 10-23 atoms
D.
236 x 10 23 atoms
STOP
Carbon dioxide is produced by the burning of fossil fuels which then leads to higher levels of carbon dioxide in the atmosphere. This gas captures heat (greenhouse gas), so the temperature rises on earth (global warming). If there are 3.2 kg of fuel in a gallon of octane (C8H18) and idling for 15 minutes twice a day Monday- Friday burns half a gallon of gas a day, how many grams of fuel do you use in a week. Then convert the grams to carbon dioxide to determine the amount of carbon dioxide produced by all this idling.
The amount of carbon dioxide produced by all the idling described in the problem would be 89.6 kg per week.
What is Global Warming?
Global warming refers to the long-term increase in Earth's average surface temperature, primarily caused by human activities such as burning fossil fuels (coal, oil, and natural gas), deforestation, and industrial processes that release large amounts of greenhouse gases into the atmosphere.
Using the atomic masses from the periodic table, we get:
Molar mass of octane = (8 x 12.01 g/mol) + (18 x 1.01 g/mol) = 114.22 g/mol
Since the molecular formula of octane (C8H18) contains 8 carbon atoms, it produces 8 molecules of carbon dioxide (CO2) per molecule of octane during combustion.
So, the amount of carbon dioxide produced by burning 11,200 grams of octane would be:
11,200 g * (8 x 1 mol CO2 / 1 mol octane) = 89,600 g or 89.6 kg of carbon dioxide produced in a week.
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What could have caused the size of the moon jelly population to increase? Claim 1: A change to the zoo plankton population caused births to increase in the moon jelly population. Claim 2: A change to the sea turtle population caused deaths to decrease in the Moon jellies population
Answer:
i think is claim 1
Explanation:
moon jellies eat zooplankton and the zooplankton population increased
Answer:It’s important to know WHY. Great explanations are what makes Brainly awesomeExplain everything. Imagine that the person who was asking, knows nothing at all so you need to start from the very beginningAlways include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their ownShow all the calculation if it is a numerical question.
Explanation:
what is crop rotations
Answer:
Crop rotation
Explanation:
The growing of different crops in succession on a piece of land to avoid exhausting the soil and to control weeds,pets,and diseases
Why calcium oxide and magnesium oxide used as soil treatment
Answer:
Chemically speaking, lime refers only to calcium oxide
(CaO); however, in common usage the term includes the calcination products of calcitic and dolomitic limestones. Calcitic (high-calcium) limes are produced by calcination of
calcareous materials (e.g., calcitic limestone, calcite,
oyster shells, and chalk) containing from 95 to 99 percent
calcium carbonate (CaCO^). Dolomitic limes are produced from
dolomitic limestone or dolomite which contains from 30 to ^+0
percent magnesium carbonate (MgCO^), the rest being calcium
carbonate.
At atmospheric pressure, calcite in limestone decomposes
at approximately 900°C to form CaO and COg. The decomposition of dolomite, CaMg is a two-stage process. At
temperatures between 650°C to 750°C dolomite decomposes to
form MgO, CO^ and CaCO^. It is necessary to raise the temperature to 900°C to decompose the CaCO^ (15, 35)» This
phenomenon is extremely important, as is shown later.
Various investigators have studied the effects of stone
size, temperature, and time of calcination of commercial
Explanation:
A cube has an edge length of 9 cm .
If it is divided up into 1-cm cubes, how many 1-cm cubes would there be?
Answer:
9^3 i think so like 279
Explanation:
blah
need it by 4:20 please
Answer:
well 4.2 times 10 is 42 and 6.1 times 10 is 61
Explanation:
Look at the diagram of a fuel cell below. A fuel cell with 2 vertical objects labeled A and B connected by an electrical wire through a circle with a M in it. There is an area between the two vertical objects labeled A, and substances flowing to, along, and away from the vertical objects and to the left and right. Which statement describes how electrons move if oxidation occurs on the left side of the cell and reduction occurs on the right side? Electrons move from left to right through Electrons move from right to left through A. Electrons move from left to right through M. Electrons move from right to left through M.
The electrons move from left to right through the circle labeled "M" to reach the cathode, where reduction takes place.
If oxidation occurs on the left side of the fuel cell and reduction occurs on the right side, the movement of electrons can be described as follows: Electrons move from left to right through the circle labeled "M."
In a fuel cell, the process of oxidation takes place at the anode (labeled A) where the fuel is oxidized, releasing electrons. These electrons then flow through the external electrical circuit, represented by the wire connecting objects A and B. The electrons reach the cathode (also labeled A) on the right side of the cell, where reduction occurs.The circle labeled "M" represents the membrane or electrolyte in the fuel cell. This membrane allows the transport of ions but blocks the movement of electrons. As a result, electrons cannot flow directly through the electrolyte but must travel through the external circuit.
This movement of electrons through the external circuit is what generates an electric current that can be used to power electrical devices or systems.
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Usually potassium hydrogen phthalate is kept very pure. But Stu Dent thinks the bottle of potassium hydrogen phthalate has been accidently mixed with sodium chloride salt. He decides to use a titration to determine the amount of potassium hydrogen phthalate present. He weighs 2.3854 g of the contaminated potassium hydrogen phthalate mixture. The titration uses 17.47 mL of 0.5000 M sodium hydroxide. Use the titration volume and concentration to calculate the moles of potassium hydrogen phthalate actually reacted. Then use the molar mass (204.2 g/mol) to calculate the mass of potassium hydrogen phthalate actually reacted. Enter the mass to 4 significant digits with units of g.
Answer:
1.784 g
Explanation:
The equation of the reaction is;
NaOH(aq) + KHC8H4O4(aq) --------> KNaC8H4O4(aq) + H2O(l)
Number of moles of NaOH reacted = 17.47/1000 * 0.5000 M
Number of moles of NaOH reacted =8.735 * 10^-3 moles
From the reaction equation;
1 mole of NaOH reacted with 1 mole of KHC8H4O4
Hence, 8.735 * 10^-3 moles of NaOH reacts with 8.735 * 10^-3 moles of KHP.
So,
Mass of KHP reacted = 8.735 * 10^-3 moles * 204.2 g/mol = 1.784 g
Which substance is solvent and which substance is solute (number 4)
Answer:
Solvent - water
solute - lemonade powder
Explanation:
You should learn the definitions of al them words. I made them notes in grade 7 dont judge and was bored while studying so i highlited everything and i thought it looked cute back then. We all did that.
Classify the chemical reaction shown here: Mg + H2SO4 → MgSO4 + H2
How is the reaction speed affected if we add magnesium
If we add more magnesium to the reaction, the reaction speed will increase.
The chemical reaction shown is a single-displacement reaction, also known as a single-replacement reaction. In this type of reaction, one element replaces another element in a molecule, producing a new compound and a different element.
In the given reaction, magnesium (Mg) reacts with sulfuric acid (H₂SO₄) to produce magnesium sulphate (MgSO₄) and hydrogen gas (H₂). This can be represented by the following balanced chemical equation:
Mg + H₂SO₄ → MgSO₄ + H₂
This is because the amount of reactant determines the number of reactions that can occur. If the amount of magnesium is increased, more magnesium atoms are available for the reaction with sulfuric acid, leading to a higher rate of reaction.
However, this increase in reaction rate is only valid up to a certain point, after which further addition of magnesium will not lead to an increase in rate of reaction. This is because other factors such as the concentration of sulfuric acid and the temperature of the reaction may become limiting factors that can no longer be compensated by adding more magnesium.
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Best definition of chemistry
Answer:
its a branch of science which deals with chemical and atomaic molecules
Answer:
Chemistry is the study of matter, it properties and the changes that matter undergoes.
Identify an element on the periodic table that is chemically similar to neon(Ne).
ANSWER
Elements that are similar to neon is helium, and argon
Hope its right if not so advance sorry :)
Answer:
He
Explanation:
plato
What is the molarity of a solution containing 17.3 g of KCl in 231 mL of KCl solution?
Answer:
The molarity of the solution is 0.99M.
Explanation:
The molaruty if a solution represents the amount of solute moles contained in 1 liter (1000ml) of a solution.
1st) In this case, we have 17.3g of KCl, so we have to use the KCl molar mass (74.5g/mol) to convert grams into moles:
\(17.3g*\frac{1mole}{74.5g}=0.23moles\)Now we know that there are 0.23 moles of the solute KCl.
2nd) We have 0.23 moles of KCl contained in 231 mL of solution, so to calculate the molarity (moles of solute contained in 1000mL of solution), we can use a mathematical rule of three:
\(\begin{gathered} 231mL-0.23moles \\ 1000mL-x=\frac{1000mL*0.23moles}{231mL} \\ x=0.99moles \end{gathered}\)Finally, the molarity of the solution is 0.99M.
What do all the different types of motor nerves
have in common? Select all that apply.
A. They use sensory receptors to receive
information from the environment.
B. They transmit information to and from muscles
C. They connect to muscle fibers through the motor endplate
D. They control voluntary motor function
Answer:
B and C
Explanation:
The different types of motor nerves transmit information to and from muscles, and they connect to muscle fibers through the motor endplate.
Which statement is true about the effect of human activity on atmospheric carbon dioxide?
Responses
Human activity has converted carbon dioxide in the atmosphere to other compounds.
Human activity has added carbon dioxide to the atmosphere.
Human activity consumes carbon dioxide in the atmosphere.
Human activity has disrupted the carbon cycle by preventing it from reaching the atmosphere.
The statement that is true about the effect of human activity on atmospheric carbon dioxide is Human activity has added carbon dioxide to the atmosphere.
Human activities, such as burning fossil fuels (coal, oil, and natural gas) for energy, deforestation, and industrial processes, have significantly increased the concentration of carbon dioxide in the Earth's atmosphere.
These activities release carbon dioxide that was previously stored in long-term reservoirs, such as fossil fuels and forests, into the atmosphere. This additional carbon dioxide contributes to the greenhouse effect and is a major driver of anthropogenic climate change.
The other statements mentioned are not accurate:
Human activity does not convert carbon dioxide in the atmosphere to other compounds on a large scale. There may be certain localized processes or technologies that aim to capture and convert carbon dioxide, but they are not widespread enough to significantly impact the overall levels of atmospheric carbon dioxide.
Human activity does not consume carbon dioxide in the atmosphere. In fact, human activities release carbon dioxide into the atmosphere through various processes, as mentioned above.
Human activity does not disrupt the carbon cycle by preventing it from reaching the atmosphere. The carbon cycle involves the movement of carbon between the atmosphere, oceans, land, and living organisms.
While human activities can impact the carbon cycle through land-use changes and deforestation, the overall effect is an increase in atmospheric carbon dioxide levels rather than preventing carbon dioxide from reaching the atmosphere.
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Differentiate between a pure substance and a mixture and provide examples
Explanation:
pure substances are those substances which are made up of one elements
mixture that those substances which are made by more than two or three elements
Answer:
Brainliest is appreciated
Explanation:
Substances which have a specific composition and cannot be separated into any constituents are called pure substances. Pure substances are further divided into elements and compounds. The combination of two or more pure substances is called a mixture. Mixtures can be classified into two types viz. heterogeneous and homogeneous mixtures.
EXAMPLES
pure substance
gold, pure water, hydrogen gas
mixture substance
oil and water, sand and sugar
Calculate the solubility (in g / L) of a generic salt with a formula of A2B, a Ksp of 4.30 × 10−11 and a molar mass of 274 g / mol.
With a Ksp of 4.30*10−11 and a molar mass of 274 g / mol the solubility (in g / L) of the generic salt is mathematically given as
S=0.0604g/l
What is the solubility (in g / L) of the generic salt?Generally, the Ksp is mathematically given as
Ksp=4s^3
Therefore
s=(\frac{4.30 × 10−11}{4})^{1/3}
s=2.207×10^{−4]
In conclusion, solubility is
S=2.207×10^{−4]*274
S=0.0604g/l
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How many molecules are in 24 grams of ozone (03)
Answer:48
Explanation:
Answer: 3. 0.125 X 10”23 molecules
Explanation:
Will give Brainliest!
A student titrates 25.0 mL of an unknown base with 0.10 M HCl. During the titration the pH is monitored and the collected data is recorded. These data are shown in the table below.
Volume
Added(mL) pH
0.0 11.13
5.0 9.86
10.0 9.44
12.5 9.26
15.0 9.08
20.0 8.66
22.0 8.39
24.0 7.88
25.0 5.28
26.0 2.70
28.0 2.22
30.0 2.00
35.0 1.70
37.5 1.61
40.0 1.52
45.0 1.40
50.0 1.30
a. Use the information provided to draw a titration curve showing the pH as a function of the volume of added HCl. Be certain to label your axes.
b. Identify the equivalence point on your graph and justify your selection of this particular point.
b. Use the data to determine the Kb value for the weak base. Be certain to show the mathematical steps you take to arrive at the answer. Report your final answer to the correct number of significant digits.
c. The student has three indicators that she could use for this experiment. The indicators (with their endpoints) are: Bromophenol Blue (3.0 – 4.6), Methyl Red (4.2 – 6.3), and phenolphthalein (8.3 – 10.0). Which indicator would be appropriate for this titration? Justify your selection.
e. Determine the (i) molarity and the (ii) % ionization of the original weak base solution (before titrating). Report your answers to the correct number of significant digits.
a. Titration Curve:
On the x-axis, label it as "Volume of HCl added (mL)"
On the y-axis, label it as "pH"
b. Equivalence Point:
The equivalence point is the point in the titration where the moles of acid (HCl) added are stoichiometrically equivalent to the moles of base (unknown base) present initially. In the given data, the equivalence point can be estimated to be around 25.0 mL of HCl added. This is where the pH drops dramatically from 7.88 to 5.28, indicating the neutralization of the base.
c. Calculation of Kb Value:
To determine the Kb value, we need to find the pOH at half-neutralization, where half the volume of the equivalent point has been reached. In this case, the half-neutralization volume is 12.5 mL (half of 25 mL).
From the data, we can observe that at 12.5 mL of HCl added, the pH is 9.26.
pOH = 14 - pH = 14 - 9.26 = 4.74
pOH = -log[OH-]
[OH-] = 10^(-pOH)
[OH-] = 10^(-4.74)
To find [OH-] in moles per liter (M), we need to convert mL to L.
[OH-] = 10^(-4.74) mol/L
Now, since we know that at the equivalence point, the concentration of the acid (HCl) is 0.10 M, we can use the stoichiometry of the reaction to determine the concentration of the base (unknown base).
From the balanced equation:
HCl + OH- → H2O + Cl-
1 mole of HCl reacts with 1 mole of OH-
0.10 M (HCl) = [OH-] M (unknown base)
Therefore, Kb = [OH-][unknown base] / [base]
Kb = (10^(-4.74) mol/L)(0.10 M) / (0.10 M - 10^(-4.74) M)
Simplify and calculate Kb.
c. Selection of Indicator:
Based on the given pKa ranges of the indicators, the indicator phenolphthalein (pKa range: 8.3 - 10.0) would be appropriate for this titration. The reason is that the pH at the equivalence point is expected to be around 7, which is well within the range of phenolphthalein's color change. Bromophenol Blue and Methyl Red have lower pKa values and would not be suitable for indicating the equivalence point in this particular titration.
d. Calculation of Molarity and % Ionization of the Weak Base Solution:
To calculate the molarity of the weak base solution, we can use the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
At the half-neutralization point, [A-] = [HA], and the pH is 9.26.
9.26 = pKa + log([A-]/[HA])
The pKa can be determined using the pOH at half-neutralization:
pKa = 14 - pOH = 14 - 4.74 = 9.26
9.26 = 9.26 + log([A-]/[HA])
log([A-]/[HA]) = 0
[A-]/[HA] = 10^0 = 1
Since [A-] = [HA], the concentration of the weak base (before titration) is equal to the concentration of its conjugate acid.
Therefore, the molarity of the weak base solution is 0.10 M.
To calculate the % ionization of the weak base, we can use the formula:
% Ionization = ([A-]/[HA]) × 100
% Ionization = (1/0.10) × 100
% Ionization = 1000%
Note: The % ionization may exceed 100% in cases where the concentration of the conjugate acid is very small compared to the concentration of the weak base.
Consider this reaction involving an unknown element X. F2+2XBr⟶Br2+2XF When 1.300 g of XBr reacts, 0.7241 g of Br2 is produced. Calculate the molar mass of X, and then identify its element symbol.
The molar mass of X would be 63.55 g/mol and the chemical symbol of X would be Cu (copper).
From the equation of the reaction: F2+2XBr⟶Br2+2XF
The mole ratio of XBr to Br2 is 2:1
Mole of Br2 = mass/molar mass
= 0.7241/159.808
= 0.004531 mole
Mole of XBr = 2 x mole of Br2
= 2 x 0.004531
= 0.009062 mole
Molar mass of XBr = mass/mole
= 1.300/0.009062
= 143.456 g/mol
Since the molar mass of Br is 79.904, the molar of X would be:
143.456 - 79.904
= 63.55 g/mol
Hence, X would be Cu.
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CHEM FINAL TOMORROW, NEED IMMEDIATE HELP!!! There are a few topics I don't understand, if someone could give a short explanation of how to do these kinds of problems, it would help so much. I'll be posting a few more of these on my page, so feel free to check those out if you would like. Thanks!
The mass of \(O_2\) needed to produce 8.65 x \(10^{23\) atoms of silver is 22.96 grams.
Stoichiometric calculationIn the given balanced equation, it is stated that 2 moles of \(Ag_2O\) produce 4 moles of Ag and 1 mole of \(O_2\).
First, let's calculate the number of moles of Ag:
8.65 x \(10^{23\) atoms of Ag / (6.022 x \(10^{23\) atoms/mol) = 1.435 moles of Ag
Since 2 moles of \(Ag_2O\) produce 1 mole of \(O_2\), the number of moles of \(O_2\) needed is half of the moles of \(Ag_2O\).
Number of moles of \(O_2\)= 1.435 moles of \(Ag_2O\) / 2 = 0.7175 moles
Now, we'll use the molar mass of \(O_2\) to find the mass:
Molar mass = 32.00 g/mol
Mass of \(O_2\) = number of moles × molar mass
= 0.7175 moles × 32.00 g/mol = 22.96 g
Therefore, the mass of \(O_2\) needed to produce 8.65 x \(10^{23\) atoms of silver is 22.96 grams.
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Experiment by hanging your first object (object 1) on the hook. Hold on to the cardboard, and position the cardboard and string so the object dangles just off the edge of the table. Then let go of the cardboard. If it moves, stop it when it reaches the edge of the table. Repeat the steps by replacing object 1 with object 2 on the hook. Finally, hang object 1 and object 2 together on the hook and repeat the steps. What do you observe when you hang different objects from the hook? What happens when two or more objects are on the hook together?
Answer:
makes now sense
Explanation:
What describes how a liquid flows and diffuses?
A: Fluidity
B: Viscosity
C: Surface tension
D: Condensation
The answer is option is a fluidity
Answer:
A. According to the kinetic-molecular theory of liquids, the particles are not bound together in fixed positions; instead they move about constantly giving them their fluidity
Select all the true statements.
a. Ionic bonding is more prevalent for the higher oxidation states and covalent bonding is more prevalent for the lower states.
b. The highest oxidation state of elements in Groups 3A through 7B is +3.
c. In the transition series, atomic size across a period decreases at first but then remains relatively constant.
d. The transition elements in a period show a steady increase in electronegativity.
Answer:
In the transition series, atomic size across a period decreases at first but then remains relatively constant.
The transition elements in a period show a steady increase in electronegativity.
Explanation:
In considering the transition series, we observe that atomic sizes of the elements decreases first and subsequently remain constant. The reason for the initial decrease in atomic size is the increase in nuclear charge across the period. After the first few elements in the period, the atomic size remains relatively constant due to shielding effect of the inner d electrons which opposes the increase in effective nuclear charge.
It is also observed that electro negativity increases smoothly across the period for the transition series. Consequently, the transition series become less electro positive across the period.
Which polynomial expresses the difference of the two polynomials below? (8u7+5u5−5)−(4u7−8u5+4)
We are going to have the polynomial as;
\(4u^7 + 13 u^2 - 9\)
What is the difference between the polynomials?We know that when we talk about the Polynomial we are referring to the values in which one of the algebraic terms have been raised to a given power as we can see in the problem that we have in the statement that has been made here.
We have the polynomials as;
\((8u^7 + 5u^5 - 5) - (4u^7 - 8u^5 + 4)\)
When we open up the bracket;
\(8u^7 + 5u^5 - 5 -4u^7 + 8u^5 - 4\)
We then have;
\(8u^7 - 4u^7 + 5u^5 + 8u^5 - 5 - 4\\4u^7 + 13 u^2 - 9\)
Thus we have seen how the difference between the polynomials can be gotten for the problem that we have in this case here as shown by the problem that have been solved in the statements above us here.
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