According to Pythagorean theorem:
c² = a² + b², where a and b legs and c- hypotenuseTo find the missing length of the leg we'll convert the equation:
14² = 9² + x²Simplify:
196 = 81 + x²x² = 196 - 81x² = 115x = √115\(\large\bf{\underline{\underline{\mathfrak{Question}:}}}\)
The hypotenuse of a right triangle has a length of 14 units and side that is 9 units long. which equation can be used to find the length of the remaining side?
\(\large\bf{\underline{\underline{\mathfrak{Solution}:}}}\)
To solve the problems of a right angle triangle we commonly used Pythagoras theorem. It is the most widely used theorem which helps in finding the missing length of a right angle triangle.
According to Pythagoras theorem, the sum of square of base and the square of perpendicular give us square of hypotenuse.
\(:{\Longrightarrow{\large{\rm{H^2=P^2+B^2}}}}\)
In a right angle triangle there are two legs and a hypotenuse.
Given that,
\({:\Longrightarrow{\small{\rm{Hypotenuse\:of\:a\:right\:triangle=14\:units.}}}}\)
\(:{\Longrightarrow{\small{\rm{A\:side\:of\:a\:right\:triangle=9\:units.}}}}\)
By putting these values in the Pythagoras theorem we get;
\(:{\Longrightarrow{\small{\rm{14^2=9^2+B^2}}}}\)
Let B = x
\(:{\Longrightarrow{\small{\rm{196=81+x^2}}}}\)
\(:{\Longrightarrow{\small{\rm{196-81=x^2}}}}\)
\(:{\Longrightarrow{\small{\rm{115=x^2}}}}\)
\(:{\Longrightarrow{\small{\rm{\sqrt{115}=x}}}}\)
Find the area of a circle having a circumference of 34pi Round to the nearest tenth. Use 3.14 for pi.
Answer:
907
Step-by-step explanation:
Circumference = 34pi
radius, r = 34pi/2pi = 17
Area, A = pi r^2 = pi (17^2) = 289pi=907 approximately
How can i show that p^(q-1) + q^(p-1) = 1 (mod pq)?
Step-by-step explanation:
you can just put in some values to check.
I actually used p =2 and q=3
the It will be
2^3-1 + 3^2-1 = 1 (mod 2×3)
2^2 +3^1 = 1 (mod 6)
4+3= 1 (mod6)
7= 1 (mod6)
which is true.
therefore p^(q-1) + q^( p-1) = 1 ( mod pq) is true
To show that p^(q-1) + q^(p-1) = 1 (mod pq), we can use Fermat's Little Theorem, which states that if p is a prime number and a is an integer not divisible by p, then a^(p-1) = 1 (mod p). Using this theorem, we can first show that p^(q-1) = 1 (mod q), since q is a prime number and p is not divisible by q. Similarly, we can show that q^(p-1) = 1 (mod p), since p is a prime number and q is not divisible by p.
Therefore, we can write:
p^(q-1) + q^(p-1) = 1 (mod q)
p^(q-1) + q^(p-1) = 1 (mod p)
By the Chinese Remainder Theorem, we can combine these two equations to obtain:
p^(q-1) + q^(p-1) = 1 (mod pq)
Thus, we have shown that p^(q-1) + q^(p-1) = 1 (mod pq).
We'll use Fermat's Little Theorem to show that p^(q-1) + q^(p-1) = 1 (mod pq).
Fermat's Little Theorem states that if p is a prime number and a is an integer not divisible by p, then:
a^(p-1) ≡ 1 (mod p)
Step 1: Apply Fermat's Little Theorem for p and q:
Since p and q are prime numbers, we have:
p^(q-1) ≡ 1 (mod q) and q^(p-1) ≡ 1 (mod p)
Step 2: Add the two congruences:
p^(q-1) + q^(p-1) ≡ 1 + 1 (mod lcm(p, q))
Step 3: Simplify the congruence:
Since p and q are prime, lcm(p, q) = pq, so we get:
p^(q-1) + q^(p-1) ≡ 2 (mod pq)
In your question, you've mentioned that the result should be 1 (mod pq), but based on Fermat's Little Theorem, the correct result is actually:
p^(q-1) + q^(p-1) ≡ 2 (mod pq)
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Jimmy i eating andwiche at a contant rate the number of andwiche y that he can eat in a hour x i repreented by the linear equation y = 8x how many andwiche doe jimmy eat in 1 hour? 2 hour? 3 hour?
Jimmy ate 8 , 16 , 24 sandwiches in 1 , 2 and 3 hours respectively .
To find : the no . of sandwiches Jimmy eat in 1 hour , 2 hour and 3 hours .
Given : y = the no . of sandwiches Jimmy can eat
x = no . of hours he take in eating
Relation : y = 8 x
( i ) No . of sandwiches eaten by Jimmy in 1 hour
x = 1
y = ( 8 * 1 )
y = 8
( ii ) No . of sandwiches eaten by Jimmy in 2 hours
x = 2
y = ( 8 * 2 )
y = 16
( iii ) No . of sandwiches eaten by Jimmy in 3 hours
x = 3
y = ( 8 * 3 )
y = 24
Hence , Jimmy ate 8 , 16 , 24 sandwiches in 1 , 2 and 3 hours respectively .
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for all positive angles less than 360°, if csc csc (2x+30°)=cos cos (3y-15°), the sum of x and y is?
Answer:
35 degrees
Step-by-step explanation:
for all positive angles less than 360°, if csc (2x+30°)= cos (3y-15°), the sum of x and y is?
Let the given expression be equal to 1, hence;
csc (2x+30°)= cos (3y-15°) = 1
csc (2x+30°) = 1
1/sin(2x+30) = 1
1 = sin(2x+30)
sin(2x+30) = 1
2x+30 = arcsin(1)
2x+30 = 90
2x = 90-30
2x = 60
x = 60/2
x = 30 degrees
Get the value of y;
cos (3y-15°) = 1
3y - 15 = arccos (1)
3y - 15= 0
3y = 0+15
3y = 15
y = 15/3
y = 5
Sum of x and y;
x+y = 30 + 5
x+y = 35degrees
Hence the sum of x and y is 35 degrees
A rental car company offers two rental plans, Plan A and Plan B, for the same economy size car. For both plans, the total rental cost F(m) is a function of the number of miles M that the car is driven.
Plan A: f(m) = 0.12 + 75
Plan B: f(m) = 0.35m
I. In complete sentences, translate each function into a verbal model describing the total cost of the rental in terms of the number of miles that the car is driven.
II. For each function, determine how the rate of change will affect the total cost of a car rental.
III. For a car rental that will include a maximum of 250 miles for the duration of the rental, which plan is the most cost effective?
Answer:
Plan B
Step-by-step explanation:
look at the image below.
Answer:
add all the sides up
Step-by-step explanation:
yw
is this statement true or false?
nine tiles are numbered 1, 2, 3, . . . , 9, respectively. each of three players randomly selects and keeps three of the tiles, and sums those three values. the probability that all three players obtain an odd sum is m/n, where m and n are relatively prime positive integers. find m n.
The value of m and n from the obtained probability is equal to 3 and 14 respectively.
As given in the question,
Nine tiles numbered 1, 2, .....9
Number of odd numbered tiles are 1,3,5,7,9 = 5
Number of even numbered tiles are 2,4,6,8 = 4
Number of players =3
Possibility to choose 3 tiles by first player out of 9 tiles = ⁹C₃
= 84 ways
Possibility to choose 3 tiles by second player out of 6 tiles = ⁶C₃
=20 ways
Possibility to choose 3 tiles by third player out of 3 tiles = ³C₃
= 1 way
Total number of ways = 84× 20 ×1
= 1680
To have a sum of 3 tiles is odd number at least one tile should be odd.
Chances of first player all the 3 tiles are 0dd out of 5 = ⁵C₃
Next two players must 2 even tiles and 1 odd tile.= ²C₁
One player can be selected in ³C₁ way
Remaining 4 even tiles distributed equally = (4!)(2!)/ (2!)² ( 2!)
Number of favourable outcomes = ⁵C₃ × ²C₁ ׳C₁ × (4!)(2!)/ (2!)² ( 2!)
= 10 × 2 × 3 × 6
= 360
Probability (m/n) = 360 /1680
= 3/14
m = 3 and n = 14.
Therefore, from the probability that all three players obtain an odd sum is m/n , the value m = 3 and n = 14.
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consider the quadratic function y equals short dash x squared plus 6 x minus 5. what do we know about the graph of this quadratic equation, based on its formula?
Based on the formula of the quadratic function y=-x^2+6x-5, we know that its graph is a downward-facing parabola that opens wide, with a vertex at (3,-14), and an axis of symmetry at x=3.
Based on the formula of the quadratic function y=-x^2+6x-5, we can determine several properties of its graph, including its shape, vertex, and axis of symmetry.
First, the negative coefficient of the x-squared term (-1) tells us that the graph will be a downward-facing parabola. The leading coefficient also tells us whether the parabola is narrow or wide. Since the coefficient is -1, the parabola will be wide.
Next, we can find the vertex using the formula:
Vertex = (-b/2a, f(-b/2a))
where a is the coefficient of the x-squared term, b is the coefficient of the x term, and f(x) is the quadratic function. Plugging in the values for our function, we get:
Vertex = (-b/2a, f(-b/2a))
= (-6/(2*-1), f(6/(2*-1)))
= (3, -14)
So the vertex of the parabola is at the point (3,-14).
Finally, we know that the axis of symmetry is a vertical line passing through the vertex. In this case, it is the line x=3.
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Find the total of the areas under the standard normal curve to the left of z1=−2.575 and to the right of z2=2.575. Round your answer to four decimal places, if necessary.
The total of the areas under the standard normal curve to the left of z₁=−2.575 and to the right of z₂=2.575 is 0.0100 square units.
What is standard normal curve?
The horizontal axis is approached but never touched by the typical normal curve as it stretches infinitely in both directions. The centre of the bell-shaped standard normal curve, which has z=0 as its centre, is. Between z=3 and z=3, almost all of the area under the standard normal curve is located.
As given,
z₁=−2.575 and z₂=2.575
Then, required area,
= P (Z < -2.575) + P (Z > 2.575)
= P (Z < -2.575) + {1 - P (Z < 2.575)}
Using z table substituting values,
= 0.0050 + {1 - 0.9950}
= 0.0050 + 0.0050
= 0.0100
Hence, the total of the areas under the standard normal curve to the left of z₁=−2.575 and to the right of z₂=2.575 is 0.0100 square units.
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This pyramid has the same base as the prism and its height is three times the height of the prism. What is the ratio of the volume of thepyramid to the volume of the prism?1A} volume of Pyramidvolume of priamB} volume of pyramidvolume of priuamC} volume of pyramidvolume of priimD} Volume of pyramidvolume of priem
This pyramid has the same base as the prism and its height is three times the height of the prism. What is the ratio of the volume of the
pyramid to the volume of the prism?
1
A} volume of Pyramid
volume of priam
B} volume of pyramid
volume of priuam
C} volume of pyramid
volume of priim
D} Volume of pyramid
volume of
prime
____________________________________________
volume of the prism
if x is a positive integer, the expression (1/n)^−2/3
is equivalent to:
If n is a positive integer, then the expression is equivalent to option A) \(\sqrt[3]{n^2}\).
What are Rational Exponents?Rational exponents are numbers which are written in the form of \(x^\frac{p}{q}\), where x is the base with positive integer and p/q is the rational exponent and q ≠ 0.
The given expression is (\(\frac{1}{n}\))^\(^\frac{-2}{3}\).
A number in the form, 1/a can be written as a⁻¹.
So 1/n can be written as n⁻¹.
So,
(\(\frac{1}{n}\))^\(^\frac{-2}{3}\) = (n⁻¹)^\(^\frac{-2}{3}\)
We have a rule for exponent that (xᵃ)ᵇ = xᵃᵇ
Using the rule,
(\(\frac{1}{n}\))^\(^\frac{-2}{3}\) = (n⁻¹)^\(^\frac{-2}{3}\)
= \(n^{-1*\frac{-2}{3}\)
= \(n^\frac{2}{3}\)
= \(n^{2*\frac{1}{3}\)
= \((n^{2})^\frac{1}{3}\)
By the definition of radicals, \(\sqrt[n]{x}\) = \((x)^\frac{1}{n}\), where x is positive integer.
So, \((n^{2})^\frac{1}{3}\) = \(\sqrt[3]{n^2}\)
Hence the equivalent expression is \(\sqrt[3]{n^2}\).
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Helppp!!!! please!!!
Answer:
18Step-by-step explanation:
8 faces and 12 vertices means hexagon as its base
That means 6+6 edges of its bases and 6 side edges.
6+6+6=18
An executive in an engineering firm earns a monthly salary plus a Christmas bonus of 7800 dollars.If she earns a total of 89100 dollars per year, what is her monthly salary in dollars?
Given:
Christms bonus = 7800
total earn in year =89100
So only salary is:
\(\begin{gathered} salary=89100-7800 \\ =81300 \end{gathered}\)In a year ( 12 months) salary is 81300 so per month salary is:
\(\begin{gathered} 12\text{ months salary is: 81300} \\ 1\text{ month salary is=}\frac{81300}{12} \\ =6775 \end{gathered}\)So monthly salary is 6775.
evaluate 3x - 2 when x =
a) 0
b) +3
c) -2
Answer:
- 2, 7 , - 8
Step-by-step explanation:
substitute the given values of x into the expression
(a)
x = 0 : 3(0) - 2 = 0 - 2 = - 2
(b)
x = 3 : 3(3) - 2 = 9 - 2 = 7
(c)
x = - 2 : 3(- 2) - 2 = - 6 - 2 = - 8
5. 7 movie tickets for $56
To find out how much each ticket costs, we can use this equation:
Total cost ÷ Number of tickets = Price of each ticket
Inserting the numbers into the equation would look like this:
56 ÷ 7 = 8To check our work, we can multiply the number of tickets by the price of each ticket to see if it matches up to the correct total price.
7 × 8 = 56Therefore, each ticket costs $8.
N/A yhhhhb hhhbbub bb he hb hb hb h. Hb hb h
Answer:
that is no answer you don't need to type stuff if it is not for work/school
Answer:
14
Step-by-step explanation:
bako has spoken
The variable cost for \( A \) is \( \$ 10 \), and for \( B, \$ 14 \). The revenue generated by each unit is \( \$ 18 \). a) What is the crossover point for the two options? The crossover point for the
The crossover point for options A and B is at 0 units sold, where the total costs and revenues for both options are equal to zero.
The crossover point is the point at which two options have equal costs or revenues. In this case, we need to determine the number of units sold for options A and B that result in the same total cost.
Let's denote the number of units sold as 'x'. The cost for option A is given as $10 per unit, so the total cost for option A is 10x. Similarly, the cost for option B is $14 per unit, so the total cost for option B is 14x.
To find the crossover point, we need to set the total costs for both options equal to each other and solve for 'x':
10x = 14x
Now, we can solve this equation:
10x - 14x = 0
-4x = 0
Dividing both sides by -4:
x = 0
The crossover point occurs at 0 units sold. This means that at this point, both options have zero cost. However, since selling zero units does not generate any revenue, we need to consider the revenue generated as well.
The revenue generated by each unit is given as $18. To find the revenue generated by each option, we multiply the number of units sold ('x') by the revenue per unit.
For option A, the revenue generated is 18x. For option B, the revenue generated is also 18x.
Since the crossover point occurs at 0 units sold, both options have zero revenue at this point.
In summary, the crossover point for options A and B is at 0 units sold, where the total costs and revenues for both options are equal to zero.
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A random sample of 40 UCF students has a mean electricity bill of $110. Assume the population standard deviation is $17.90. Construct a 90% confidence interval for the mean electricity bill of all UCF students. Round final answer to two decimal places. No $ needed in your answer.
If a random sample of 40 UCF students has a mean electricity bill of $110, the 90% confidence interval for the mean electricity bill of all UCF students is $105.34 to $114.66.
To construct a 90% confidence interval for the mean electricity bill of all UCF students, we can use the following formula:
Confidence interval = sample mean ± (z-score)(standard error)
where the z-score for a 90% confidence level is 1.645 and the standard error is the population standard deviation divided by the square root of the sample size, or:
standard error = 17.90 / √40 = 2.83
Substituting the given values, we get:
Confidence interval = 110 ± (1.645)(2.83)
Confidence interval = 110 ± 4.66
Therefore, the 90% confidence interval for the mean electricity bill of all UCF students is $105.34 to $114.66.
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State whether the following categorical propositions are of the form A, I, E, or O. Identify the subject class and the predicate class. (1) Some cats like turkey. (2) There are burglars coming in the window. (3) Everyone will be robbed.
Statement 1: Some cats like turkey, the form is I, the subject class is Cats, and the predicate class is Turkey, statement 2: There are burglars coming in the window, the form is E, the subject class is Burglars, and the predicate class is Not coming in the window and statement 3: Everyone will be robbed, the form is A, the subject class is Everyone, and the predicate class is Being robbed.
The given categorical propositions and their forms are as follows:
(1) Some cats like turkey - Form: I:
Subject class: Cats,
Predicate class: Turkey
(2) There are burglars coming in the window - Form: E:
Subject class: Burglars,
Predicate class: Not coming in the window
(3) Everyone will be robbed - Form: A:
Subject class: Everyone,
Predicate class: Being robbed
In the first statement:
Some cats like turkey, the form is I, the subject class is Cats, and the predicate class is Turkey.
In the second statement:
There are burglars coming in the window, the form is E, the subject class is Burglars, and the predicate class is Not coming in the window.
In the third statement:
Everyone will be robbed, the form is A, the subject class is Everyone, and the predicate class is Being robbed.
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help, please !! you will get 10 points !!
Answer:
25.5
Step-by-step explanation:
Using SOH CAH TOA, you can see that x is the hypotenuse, and 24 is adjacent to the angle 20, so you will need to use CAH.
CAH is cos=adjacent/hypotenuse. Substituting our values in means cos(20) will be equal to 24/x. By cross multiplying, you receive cos(20) x =24. To find x, divide 24 by cos(20) to get 25.5 to the nearest tenth.
The inverse of F(x) is a function.
Answer:
This is true.
Step-by-step explanation:
I hope this helped you! :)
Make x the subject of the formula Tx/q = y
Answer:
Step-by-step explanation:
To make 'x' as the subject isolate 'x'.
To isolate 'x',
Step 1: Multiply the entire equation by q
Step 2: Then Divide by T
\(q*\dfrac{Tx}{q}=q*y\\\\\\Tx=qy\\\\\dfrac{Tx}{T}=\dfrac{qy}{T}\\\\\\x=\dfrac{qy}{T}\)
Answer:
x = qy/T
Step-by-step explanation:
We want to isolate the x term. To do that, first multiply by q to end up with Tx = qy.
Then divide by T to get x = qy/T.
x is by itself, and we have our answer.
Using graphing, what are the approximate solutions to this equation? |2x-3|=log(2x-3)+2
The approximate solutions are: x = 1.505 and x = 2.688
Equation solutionsThe solutions to an equation can be solved by graphing calculators and by solving them explicitly.
The equation is given as:
\(|2x-3|=\log(2x-3)+2\)
Start by splitting the given equation, as follows:
\(|2x-3|=0\),\(\log(2x-3)+2 =0\)Rewrite the above equations as follows:
\(y = |2x-3|\).\(y = \log(2x-3)+2\)The graphsPlot the graphs of the above equations (see attachment).
From the graph, the equations intersect at the following points
x = 1.505x = 2.688Hence, the approximate solutions are: x = 1.505 and x = 2.688
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which number best represents the slope of the graphed line
Answer: 1/2 it cant be an integer bc the graph is positive it can't be 2 bc 2/1 wouldn't match the line.
The required answer is 1/2
Step-by-step explanation:
Answer:
\(\frac{1}{2}\)
Step-by-step explanation:
\(\frac{rise}{run}\) = slope
Pick point on the line where it crosses the y axis.
Notice it crosses at a corner of a square on the grid.
Find how many squares you must rise, and must run until it crosses another corner of a square on the grid.
You rise up 1 square, and run 2 squares to the right.
Find the factors then solve the quadratic of x^2+9x+20
Step 1: Multiply a and c
a = 1
c = 20
a * c = 20
Step 2: Find factors of +20 that add up to +9
Factors of 20 = 1, 2, 4, 5, 10, 20
The two factors that add up to 9 are 4 and 5.
Step 3: Factor
(x + 4)(x + 5) = 0
Answer: (x + 4)(x + 5) = 0
Hope this helps!
what is the factored form of the function f(x)=x³+2x²-15x-36
Answer:
(x+3)(x+3)(x-4)
Step-by-step explanation:
I find a graphing calculator immensely helpful for factoring problems. Of course the constant in the binomial factor is the opposite of the x-intercept value. The x-intercept at -3 just touches the axis, so has even multiplicity. It will give rise to a repeated factor.
The x-intercepts of -3, -3 and +4 mean the factorization is ...
f(x) = (x +3)(x +3)(x -4)
pumpkins were weighed at the pumpkin patch the weights of the pumpkin are shown choose two weights that the most number of pumpkin weigh
Answer: 11 and 9 1/2!
Step-by-step explanation:
Because look at the chart the most are? You guessed it! 11 and 9 1/2 hope it helps!
Write a two-column proof.
Given: MS ≅ RQ, MS || RQ
Prove: Δ M S P ≅Δ R Q P
We can conclude that ΔMSP ≅ ΔRQP under SAS conditions.
What do we mean by a triangle's congruency?If all three corresponding sides and angles of two triangles are the same size, they are said to be congruent.These triangles can be moved, rotated, flipped, and turned to appear identical.If they are moved, they will coincide.When two triangles satisfy the five congruence conditions, congruence exists.They are the side-side-side (SSS), side-angle-side (SAS), angle-side-angle (ASA), angle-angle-side (AAS), and right angle-hypotenuse-side (RHS).So,
Given: MS ≅ RQ, MS || RQ
To Prove: ΔMSP ≅ ΔRQP
MS = RQ = (Given)SP = PQ = (Q is the midpoint)So, ∠MSP = ∠RQP (SAS)ΔMSP ≅ ΔRQP is proved.
Therefore, ΔMSP ≅ ΔRQP under SAS condition.
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A store is offering a 30% discount on shirts. A shirt at the store has an original cost of $25. What is the cost of the shirt, in dollars, after the discount?
The cost of the shirt, in dollars, after the 30% discount is $17.50.
What is discount?
A discount is a reduction in the price of a product or service that is offered by a seller to a buyer. Discounts can be offered for a variety of reasons, such as to attract customers, increase sales, or clear out inventory. Discounts can be expressed as a percentage or a fixed amount, and they can be applied at the time of purchase or deducted from an invoice or bill. Discounts are often used in sales promotions, marketing campaigns, and loyalty programs to incentivize customers to buy or use a product or service.
If a store is offering a 30% discount on shirts that cost $25 originally, then the discount amount is:
30% of $25 = 0.30 x $25 = $7.50
The discount amount is $7.50, so the new price of the shirt after the discount is:
$25 - $7.50 = $17.50
Therefore, the cost of the shirt, in dollars, after the 30% discount is $17.50.
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