The H?X bond length is 105 pm and the H?Y bond length is 119 pm. What is true about the bonding in H?X and H?Y? Select the correct answer below:
Question 18 options:
There is greater orbital overlap between H and Y than between H and X
There is greater orbital overlap between H and X than between H and Y
H?Y is a stronger bond than H?X
The H?Y bond energy is greater than the H?X bond energy.

Explanation:

Hydrogen bonding, present in alcohols but not hydrocarbons, leads to strong intermolecular forces and increases the boiling point significantly.

For example:

Glycerol has 3 OH groups, which lead to a much more extensive hydrogen-bonding network and a higher boiling point compared to the 1 OH or 2 OH in other chains.

Answer:

The correct answer is - 75 grams.

Explanation:

Half-life is the amount of time that is used by the given amount of substance or element to make it half of the initial amount of a particular radioactive substance.

Equation for alpha decay for radon

\(^222_{86}Rn\Rightarrow^{218}_{84}Po  \)

we need to calculate the left amount of radon after given time

using formula half life

\(N(t)=N_{0}e^{-\lambda t}\)

\(\lambda =\dfrac{0.693}{3.82}\)

\(\lambda=0.1814\)

\(N(3.82)=150\times e^{-0.1814\times3.82}\)

\(N(3.82)=75.0\ g\)

Thus, the left amount of radon is - 75 grams.

Answer:

Hydrocarbon combustion refers to the chemical reaction where a hydrocarbon reacts with oxygen to create carbon dioxide, water, and heat. Hydrocarbons are molecules consisting of both hydrogen and carbon. ... Methane combining with 2 oxygen to form carbon dioxide, water and heat.

The atoms (or groups of atoms) that can have expanded octets are option c. N and option e. O.

An octet is a set of 8 electrons in an atom's outer shell. The octet rule is a chemical rule that explains how atoms combine and behave chemically by requiring them to have complete outer electron shells consisting of eight electrons. When considering covalent bonding in a compound, the octet rule states that atoms will donate, accept, or share electrons to achieve a full valence shell of eight electrons.

Expanded octets occur when an atom in a compound has more than eight electrons in its outer shell. Expanded octets are only observed for elements in period three and above because of the d orbitals in the valence shell, which allows for more electrons to be held.

Expanded octets can exist due to the existence of d-orbitals in elements. The most popular expanded octets are found in phosphorus, sulfur, and chlorine.

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The reaction proceeds from NO2 and O2 to N2O5, with the correct stoichiometry. As [NO2] and [O2] increase, [N2O5] would increase at one-half the rate, which fits the rate laws provided.
The correct answer is (B) 4 NO2 + O2 → 2 N2O5.

To explain why, we need to use the rate laws provided. The first rate law tells us that the rate of the reaction is proportional to the negative change in [N2O5] over time. This means that as [N2O5] decreases, the rate of the reaction will increase. The second rate law tells us that the rate of the reaction is proportional to the positive change in [NO2] over time. This means that as [NO2] increases, the rate of the reaction will increase. Finally, the third rate law tells us that the rate of the reaction is proportional to the positive change in [O2] over time. This means that as [O2] increases, the rate of the reaction will increase.

Now, let's consider each answer choice. Answer A suggests that the reaction proceeds from N2O5 to NO2 and O2. However, this would mean that as [N2O5] decreases, [NO2] and [O2] would increase at the same rate, which does not fit the rate laws provided. Answer C suggests that the reaction proceeds from N2O5 to NO2 and O2, but with a different stoichiometry. Again, this does not fit the rate laws provided.

Answer D suggests that the reaction proceeds from NO2 and O2 to N2O5, but with a different stoichiometry. However, this would mean that as [NO2] and [O2] increase, [N2O5] would increase at one-fourth the rate, which does not fit the rate laws provided.

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Answer: C. that there may be more than one way to interpret data

Enge 2020 C is the correct answer

Answer:

Total

Hxbdvdbdj

125 grams

Answer:

Strong acids contain more A− than weak acids do.

Strong acids contain more H3O+ than weak acids do

Explanation:

When we talk about a strong acid, we are referring to any acid that is completely dissociated or ionized when it is in an aqueous solution.

It is very eager to lose a proton, H+ in solution according Arrhenius definition.

In aqueous solution, a strong acid ionizes as follows:

HA(aq) + H2O → H3O+(aq) + A−(aq)

Since, strong acids ionize completely in solution, strong acids contain a greater H3O+ and A− concentration than solutions of weak acids.

Answer:

A. Strong acids contain more A− than weak acids do.

B. Strong acids contain more H3O+ than weak acids do.

D. Strong acids contain more OH− than weak acids do.

Explanation:

Plato correct

Answer:

Las bebidas gaseosas como las gaseosas están hechas de un soluto de dióxido de carbono gaseoso en un líquido. La solubilidad del dióxido de carbono en el líquido depende de la presión y la temperatura de la lata de refresco, y también de agitar la lata de refresco que introduce burbujas que permanecen ocultas hasta que se abre la lata antes de que burbujee.

Por lo tanto, dado que la presión en la lata de refresco permanece constante, elevar la temperatura, agitar la lata de refresco o congelar el refresco, lo que aumenta la cantidad de dióxido de carbono en la porción líquida, hará que el refresco forme espuma y se derrame.

Explanation:

non metals

elements that always gain electrons from other elements(mainly metals) are called non metallic elements. During a reaction all non metallic elements gain or receive electrons and all metals lose or give electrons. The most non metallic elememt is Flourine, meaning that is gains or receive many electrons during a reaction with another metal.

Answer:

- 20 J

Explanation:

Heat of Reaction = Heat of Products - Heat of Reactants

From the graph;

Heat of Products = 10

Heat of Reactants = 30

Heat of Reaction = 10 - 30 = -20 J

According to the electronic configuration, vanadium can lend three electrons.

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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To calculate the amount of energy transferred to the filament bulb, we can use the power, voltage, and time involved in the circuit. The given information states that the bulb is labeled as '2.5 V, 1.25 W'.

To start, we can use the formula P = IV, where P represents the power, I represents the current, and V represents the voltage. Since the resistance of the bulb is not provided, we cannot directly use the formula P = V² / R. However, we can derive the value of current using I = V / R, where R is the resistance.

By substituting I = V / R into the equation P = IV, we obtain P = V² / R. Now, we have the power value, which is 1.25 W. The bulb is connected to a 2.5 V battery, so we can use P = IV to find the current, I. Substituting P = 1.25 W and V = 2.5 V into the equation, we get I = P / V = 1.25 / 2.5 = 0.5 A.

Now that we know the current flowing through the bulb is 0.5 A, we can calculate the energy transferred using the formula E = Pt, where E represents energy, P represents power, and t represents time. Given that the bulb is connected for 1 minute (60 seconds), we can calculate E = Pt = 1.25 W × 60 s = 75 J (Joules).

Therefore, the amount of energy transferred to the filament bulb when it is connected to a 2.5 V battery for one minute is 75 Joules.

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The given reaction is already balanced, that is to say tha the number of atoms in the reactants matches the number of atoms in the products. In the reaction, we can see the relationship between CaC2 and H2O. For each mole of CaC2 two moles of H2O react.

So, if 4.8 moles of CaC2 are consumed the moles of H2O needed will be:

Mol of H2O = Mol of CaC2 x 2

Mol of H2O = 4.8 x 2 = 9.6 mol of H2O

Now, to calculate the grams of H2O we will use the following equation and the mass molar of H2O.

Mass molar of H2O =18.01 g/mol

So, if 4.8 moles of CaC2 are consumed in this reaction, 172.9 g of H2O are needed

Answer:

A transition from one accepted theory to another or from one employed method to another.

Explanation:

Answer:

stay the same.

Explanation:  Period 3 consists of the full 1s, 2s, and 2p electron orbitals, plus the 3s and 3p valence orbitals, which are filled with a total of 8 more electrons as we move from left (Na) to the far right (Ar):

Na:  1s2 2s2 2p6 3s1

Ar:    s2 2s2 2p6 3s2 3p6

As we move from left to right, and ignoring the already-filled 1s, 2s, and 2p orbitals, the period three starting and ending elements have the following:

Na: 3s1

Ar: 3s2, 3p6

All the new electrons electrons filled the third energy level (3s and 3p).  So the energy level does not change, just the orbitals.

After considering the given data we conclude and evaluating the given set of options we conclude that the from the following option all are acceptable units for density Except: g/ml  which is option A.

This is confirmed by the research materials , which provide a list of acceptable units for density, including:
Kilogram per cubic meter \((kg/m^3)\)
Gram per cubic centimeter \((g/cm^3)\)
Pound per cubic foot \((lb/ft^3)\)
Pound per cubic inch \((lb/in^3)\)
All of these units are acceptable for density, but g/ml is not included in the list. Therefore, from the following option all are acceptable units for density Except: g/ml which is option A.  
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The complete question is
All of the following are acceptable units for density Except:
a)g/ml
b)kg/l
c)g/cc
d)g/cm

Answer:

355.25g

Therefore, the mass of sodium sulfate formed when we start with 200.0 grams of sodium hydroxide and you have excess sulphuric acid is 355.25g.

Explanation:

HOPE ITS HELP;)

In endothermic reactions, greater power is absorbed whilst the bonds within side the reactants are damaged than is launched whilst new bonds are shaped withinside the products. Endothermic reactions are observed through a lower in temperature of the response mixture.

When a material undergoes an endothermic section change, the temperature stays constant. If warmness is added, the temperature behaves on this way due to the fact power is getting used to triumph over intermolecular forces.

Endothermic reactions, greater power is absorbed whilst the bonds within side the reactants are damaged than is launched whilst new bonds are shaped withinside the products. If a chemical response absorbs as a lot power because it releases, it's miles known as isothermic—there may be no power changes.

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Answer:

Answer

Explanation:

Evidence from fossils, glaciers, and complementary coastlines helps reveal how the plates once fit together. Fossils tell us when and where plants and animals once existed. ... This distribution of fossils led to theories that the southern continents were once joined in a supercontinent called Gondwana.

Answer: Evidence from fossils, glaciers, and complementary coastlines helps reveal how the plates once fit together. Fossils tell us when and where plants and animals once existed.

Explanation: I hoped that helped plzz mark as brainliest !!

Explanation:

The name for the compound PbO₂ is lead (IV) oxide. The oxidation state of lead is +4 and the oxidation state of oxygen is -2. Actualy the oxidation state of oxygen in oxides is always -2.

Answer: the oxidation state of O in PbO₂ is -2.

The oxidation number of oxygen in the compound PbO₂ is -2. The oxidation number of an atom can be positive, negative, or zero.

Let's assume that the oxidation number of lead (Pb) is x and the oxidation number of oxygen (O) is y. The compound PbO₂ is neutral, which means the sum of the oxidation numbers must be zero.

The oxidation number of Pb is known to be +4 because PbO₂ is lead dioxide, whereas oxygen is typically assigned an oxidation number of -2.

Thus,

(+4) + 2(y) = 0

4 + 2y = 0

2y = -4

y = -2

Therefore, the oxidation number of oxygen (O) in PbO₂ is -2.

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Gas particles are spaced far apart and move around freely is the statement that describes the particles in a gas Option A is correct.

The gas is the state of matter in which the particles of matter are vey far away from each other and are not even visible from the normal human eyes and can move in zig zag motion in the environment.

As the particles are very much spaced from each other so the shape of the gas is also not fixed it can only be felt not can be seen from the eyes and particles are independent and free to move.

Therefore, Option A is correct. Gas particles are spaced far apart and move around freely is the statement that describes the particles in a gas.

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The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

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Conduction is the mechanism through which heat is transferred between materials that are in close proximity to one another. Typically, it happens in solids. While frying veggies in a skillet, as an illustration of conduct.

When neighbouring atoms or molecules meet, heat energy is delivered by conduction. Conduction occurs more readily in solids and liquids than in gases because of the closer spacing of the particles in these two states.

The process by which heat is transmitted from an object's hotter end to its cooler end is known as conduction. The term "thermal conductivity" refers to an object's capacity to transfer heat, and it is represented by the letter k.

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An example of The substance which is composed of aromatic hydrocarbins is :  Pain reliever.

Aromatic hydrocarbons are hydrocarbons in nature are composed of 6 rings of carbn atoms ( fused benzene rings ) certain compounds like petroluem contain aromatic hydrocarbons in nature. Certain medical drugs administered are composed of aromatic hydrocarbins an example of such drugs are pain relievers.

Hence we can conclude that the substance which is composed of aromatic hydrocarbons is pain reiever.

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The new pressure on the Tank is 31.3 atm.

To find the new pressure, we can use the formula derived from the Gay-Lussac's Law, which states that the pressure of a gas is directly proportional to its temperature when the volume remains constant. The formula is:

P1/T1 = P2/T2

where P1 is the initial pressure, T1 is the initial temperature in Kelvin, P2 is the final pressure, and T2 is the final temperature in Kelvin. First, convert the temperatures from Celsius to Kelvin:

T1 = 22.0°C + 273.15 = 295.15 K
T2 = 35.0°C + 273.15 = 308.15 K

Now, plug in the given values and solve for P2:

(30.0 atm) / (295.15 K) = P2 / (308.15 K)

P2 = (30.0 atm) × (308.15 K) / (295.15 K) ≈ 31.3 atm

The new pressure after heating is approximately 31.3 atm.

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Answer:

well we can't awnser this we don't have the full information srry♥️✨

Answer:

A. the accepted value for the density of aluminum

Explanation:

To know if your calculation is accurate or not, you need to know the accepted value. An example is if the accepted value was 15 and your calculation was 14.9, your calculation is accurate because its close to the actual value. If your calculation was 7, you would not be accurate at all because you are far from the actual value. Hope this helps please give brainliest!

Answer:

Now, we have to determine the limiting reagent.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g of

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂O

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.For, amount of oxygen left of unreacted, Only 24 g of oxygen will react.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.For, amount of oxygen left of unreacted, Only 24 g of oxygen will react.But 29 g is the given amount. Amount of oxygen unreacted = 29 - 24 = 5 g

The theoretical yield of the given chemical equation is 64 g and limiting reactant is oxygen.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

As per the equation 4 g hydrogen reacts with 32 g oxygen thus 8 g hydrogen will react with 8×32/4=64 g oxygen.

Thus, the  theoretical yield of the given chemical equation is 64 g .

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Answer:

54L

Explanation: