Answer:
365 m/s
Explanation:
Mrs Finley
please help me out with this
The current flowing through the 1Ω resistor in the circuit is 0.66 A.
The emf of the cells, V = 1.1 V
Internal resistance of the cells, r = Ω
Resistance across the circuit, R = 1 Ω
According to Kirchhoff's current law, the total current flowing into and out of a junction in an electrical circuit is equal.
According to Kirchoff's current law,
(1.1 - V'/2) + (1.1 - V'/2) + (1.1 - V'/2) = V'/1
3/2(1.1 - V') = V'
3.3 - 3V' = 2V'
5V' = 3.3
Therefore, the terminal velocity of the battery is,
V' = 3.3/5
V' = 0.66 V
Therefore, according to Ohm's law, the current flowing through the 1Ω resistor is given by,
I = V'/R
I = 0.66/1
I = 0.66 A
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a toy is tossed from the edge of a table. its path is shown; air resisitance is ignored. use the picture below to answer the following questions
As there is only one force acting on the ball i.e. gravitational force, the acceleration will be constant and downward. Also because ball moves in the direction of the acceleration, the velocity increases.
Acceleration - constant; velocity - increasing.
What is Acceleration?
Acceleration is the rate of change of velocity of an object over time. It can be positive, negative, or zero. Positive acceleration is when an object speeds up, negative acceleration is when an object slows down, and zero acceleration is when an object's velocity remains constant.
What is velocity?
Velocity is a measure of the speed and direction of an object's motion. It is typically measured in meters per second (m/s) or kilometers per hour (km/h). Velocity can also be expressed in other units, such as miles per hour (mph) or feet per second (ft/s). Velocity is related to a object's acceleration, as an object's acceleration is the rate of change in its velocity over time.
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If a person walks 1 km north, 5 km west, 3 km south and 7 km east, find the resultant displacement vecto
If a person walks 1km north, 5 km West, 3km south, and 7km east, then the resultant displacement vector would be 2.82 km toward the south east direction
What is displacement?
When an object moves in connection to a reference frame, such as when a passenger travels to the back of an airliner or a professor walks to the right in relation to a whiteboard, its position changes. This movement in position is described as displacement.
as stated in the issue If a person goes one kilometre north, five kilometres west, three kilometres south, and seven kilometres east,
The resulting displacement vector, as we know, is the shortest feasible distance between the beginning and ending points
In the horizontal direction, the outcome is
7-5 pointing east
2 kilometres to the eas
In the vertical direction, the outcome is
3–1 km to the south
2 kilometres to the south
\($\begin{aligned} \text { Resultant displacement } &=\sqrt{ }\left(2^{2}+2^{2}\right) \\ &=2 \cdot \sqrt{2} \\ &=2.82 \end{aligned}$\)
As a result, the resulting displacement vector is 2.82 kilometres to the southeast.
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___________________ uses the heat energy from the Earth. This type of alternative energy can be installed basically anywhere in North Carolina.
A) wave energy
B) solar energy
C) nuclear energy
D) geothermal energy
Answer:
Geothermal!!
Explanation:
Geo means earth! Just like Hydro means water, and Pyro means fire :)
Answer:
The Answer is D). Geothermal energy
Explanation:
Hope this helps!!!!!
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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For a given substance, the molecules
move fastest when the substance is
Answer:GAS
Explanation:
A world-class sprinter can reach a top speed (of about 11.5 m/s) in the first 20.0 m of a race
What is the average acceleration of this sprinter?
Express your answer with the appropriate units.
How long does it take her to reach that speed?
Express your answer with the appropriate units.
(a) The average acceleration of this sprinter is 3.31 m/s².
(b) The time taken for the sprinter to reach the speed is 3.5 s.
What is the average acceleration of this sprinter?The average acceleration of this sprinter is calculated as follows;
v² = u² + 2as
where;
v is the final velocity of the sprinter = 11.5 m/su is the initial velocity of the sprinter = 0a is the average acceleration of the sprinter = ?s is the distance travelled by the sprinterv² = 0 + 2as
a = v² / 2s
a = ( 11.5² ) / ( 2 x 20 )
a = 3.31 m/s²
The time of motion of the sprinter is calculated as follows;
v = u + at
v = 0 + at
t = v / a
t = ( 11.5 ) / ( 3.31 )
t = 3.5 s
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When you hammer a nail into wood, the nail heats up. 30 Joules of energy was absorbed by a 5-g nail as it was hammered into place. How much does the nail's temperature increase (in °C) during this process? (The specific heat capacity of the nail is 450 J/kg-°C, and round to 3 significant digits.
Answer:
13.33 K
Explanation:
Given that,
Heat absorbed, Q = 30 J
Mass of nail, m = 5 g = 0.005 kg
The specific heat capacity of the nail is 450 J/kg-°C.
We need to find the increase in the temperature during the process. The heat absorbed in a process is as follows:
\(Q=mc\Delta T\\\\\Delta T=\dfrac{Q}{mc}\\\\\Delta T=\dfrac{30}{0.005\times 450}\\\\=13.33\ K\)
So, the increase in temperature is 13.33 K.
Convert the following statement to the language used by physicists, "I am cold, please turn on the heat."
Answer:
Explanation:fog
Calculate the speed of a spider that walked 36 cm in 4 seconds.
Mention value of acceleration due to gravity at the pole of the earth
Suppose 10.0 g of ice at -10.0C is placed into 300.0 g of water in a 200.0-g copper calorimeter. The final temperature of the water and copper calorimeter is 18.0C.
1) What was the initial common temperature of the water and copper? (Express your answer to three significant figures.)
The initial common temperature of the water and copper is approximately 2.68°C.
To find the hidden typical temperature of the water and copper, we need to use the norm of protection of energy, which communicates that energy can't be made or obliterated, recently moved or changed beginning with one design then onto the following.
The force lost by the ice as it breaks up is identical to the power obtained by the water and the calorimeter. We can impart this using the recipe:
Q_ice = Q_water + Q_calorimeter
where Q_ice is the force lost by the ice, Q_water is the power procured by the water, and Q_calorimeter is the force gained by the calorimeter.
We can determine the power lost by the ice using the recipe:
Q_ice = m_ice * L_f
where m_ice is the mass of the ice and L_f is the force of blend of water, which is 333 J/g.
Q_ice = (10.0 g) * (333 J/g) = 3330 J
We can sort out the force obtained by the water using the condition:
Q_water = m_water * c * (T_f - T_i)
where m_water is the mass of the water, c is the specific power breaking point of water, which is 4.184 J/g°C, T_f is the last temperature of the water and calorimeter, and T_i is the hidden ordinary temperature of the water and calorimeter.
Q_water = (300.0 g) * (4.184 J/g°C) * (18.0°C - T_i)
We can figure the force obtained by the calorimeter using the recipe:
Q_calorimeter = m_calorimeter * c_calorimeter * (T_f - T_i)
where m_calorimeter is the mass of the calorimeter, which is 200.0 g, c_calorimeter is the specific force breaking point of copper, which is 0.385 J/g°C, T_f is the last temperature of the water and calorimeter, and T_i is the hidden ordinary temperature of the water and calorimeter.
Q_calorimeter = (200.0 g) * (0.385 J/g°C) * (18.0°C - T_i)
Subbing these circumstances into the norm of conservation of energy, we get:
m_ice * L_f = m_water * c * (T_f - T_i) + m_calorimeter * c_calorimeter * (T_f - T_i)
Tending to for T_i, we get:
T_i = T_f - [(m_ice * L_f)/(m_water * c + m_calorimeter * c_calorimeter)]
T_i = 18.0°C - [(10.0 g) * (333 J/g)/(300.0 g * 4.184 J/g°C + 200.0 g * 0.385 J/g°C)]
T_i = 2.68°C
As needs be, the basic ordinary temperature of the water and copper was 2.68°C (conveyed to three immense figures).
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A block m1 rests on a frictionless surface. A second block m2 sits on top of the first block. Here m1 = m2 = m. A horizontal force F is applied to the bottom block to pull it to the right as shown below. Assume that the blocks move together across the surface (block m2 does not slide off of block m1).
A block resting on a frictionless surface experiences a horizontal force that pulls another block atop it to the right, where the two blocks travel in tandem without slamming.
How much static friction is there between the upper and bottom blocks?Response and justification The higher block's acceleration is also equal to 3 m/s2 because there is no relative motion between the upper and lower blocks.
What is the static friction coefficient between block A and a flat floor?Block A and a level floor have a static friction coefficient of 0.45, while Block B has a static friction coefficient of 0.30. Each brick weighs 2.0 kg.
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a projectile is shot upward from the surface of the earth with an initial velocity of 384 ft/s. What is its velocity after 5 seconds
Answer:
335 ft/s
Explanation:
In this question, we have a very important factor missing. The equation of the projectile. So, in simplifying the question I'm going to assume an equation which you can correct thereafter
s(t) = -4.9t² + v(0)t + s0
From the question, we're told that v(0) = 384 ft/s, so if we apply that, we have
s(t) = -4.9t² + 384t + s0, where s0 = 0
On differentiating the equation, we have
s(t) = v(t) = -4.9(2t) + 384(1)
v(t) = -9.8t + 384
Now, at time t = 5 seconds, the velocity v =
v(t) = -9.8(5) + 384
v(t) = -49 + 384
v(t) = 335 ft/s
Therefore, the velocity of the projectile after 5 seconds is 335 ft/s. Please leave a like if it helped you.
An air-track glider attached to a spring oscillates between the 14.0 cm mark and the 71.0 cm mark on the track. The glider completes 12.0 oscillations in 34.0 s . You may want to review (Pages 391 - 393) . Part A What is the period of the oscillations
Answer:
A = 2,8333 s
Explanation:
El periodo es definido como el tiene que toma de dar una oscilación.
En este caso realiza varias osicilacion por lo cual debemos encontrar el promedio del perdono.
T = t/n
calculemos
A = 34,0/ 12,0
A = 2,8333 s
GUYS I NEED HELP RIGHT NOW
b you should know this no need to explain if you dont know well I'm sorry its b
In part C of the lab, when two wires are in series, so that current flows in opposite directions inside them, we see that the wires move ____.
a. towards each other (they attract)
b. away from each other (they repel)
c. both the wires move downwards towards the floor
d. both the wires move upwards towards the ceiling
Answer:
The correct option is B.
away from each other (they repel)
Explanation:
This because when current flows in opposite direction in wire, the electrons in them are at high density or electrons in the wires will be at high density which is as a result of contraction of the length due to relativistic of the length, this make the wires to move away from each other or repel.
Researchers studying the possible effects of “heading” a soccer ball--hitting it with the head--use a force plate to measure the interaction force between a ball and a hard surface. (Figure 1) shows smoothed data of the force when a 430 g
soccer ball is fired horizontally at the force plate with a speed of 15 m/s
With what speed does the ball rebound from the plate?
The speed of the ball rebounding from the plate is approximately 13.2 m/s.
According to the graph, the greatest force exerted by the football on the force plate during impact is around 1900 N. The ball comes to a halt on the force plate before rebounding.
The kinetic energy of the ball before impact equals the kinetic energy of the ball after the rebound, according to the law of conservation of energy.
The speed of the ball rebounding can be calculated using the formula:
(1/2)mv²= (1/2)mv_0²
where m is the mass of the ball (0.43 kg), v is the speed of the ball rebounding, and v_0 is the initial speed of the ball (15 m/s).
Solving for v, we get:
v = sqrt(v_0² - (2F/m))
where F is the maximum force exerted on the force plate (1900 N).
Plugging in the values, we get:
v = sqrt(15² - (2*1900/0.43)) ≈ 13.2 m/s
Therefore, the speed of the ball rebounding from the plate is approximately 13.2 m/s.
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A 6 kg blue ball rolls across the ground and collides with a stationary 1 kg red ball.
Before the collision the blue ball moved right with a speed of 4 m/s, and after the
collision it moved left with a speed of 1 m/s. If the red ball was not moving before the
collision, how fast is it moving after the collision?
The final velocity of the red ball is 18 m/s.
What is momentum?The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.
Then;
Mass of the blue ball = 6 kg
Mass of the red ball = 1 kg
Initial velocity of the blue ball = 4 m/s
Initial velocity of the red ball = 0 m/s
Final velocity of the red ball = ??
Final velocity of the blue ball = 1 m/s
We now have;
(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)
24 = v + 6
v = 24 - 6
v = 18 m/s
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answer and solution to this question
Frequency= 30 Hz, Period= 0.0333 s, Wave Number=15.708 rad/m, Wave Function= y(x, t) = 0.05 sin(15.708x - 94.248t), Transverse displacement= -0.013 m, Time= 0.297 s.
How to calculate the frequency?(a) To find the frequency (f), we can use the equation: wave speed = frequency x wavelength. Rearranging this equation, we get:
frequency = wave speed / wavelength
Substituting the given values, we get:
frequency = 12 m/s / 0.4 m = 30 Hz
Therefore, the frequency of the wave is 30 Hz.
To find the period (T), we can use the equation:
period = 1 / frequency
Substituting the frequency value we just calculated, we get:
period = 1 / 30 Hz = 0.0333... s (rounded to four decimal places)
Therefore, the period of the wave is approximately 0.0333 s.
To find the wave number (k), we can use the equation:
wave number = 2π / wavelength
Substituting the given values, we get:
wave number = 2π / 0.4 m = 15.708 rad/m (rounded to three decimal places)
Therefore, the wave number of the wave is approximately 15.708 rad/m.
(b) The wave function for a transverse wave on a string is given by:
y(x, t) = A sin(kx - ωt + φ)
where A is the amplitude, k is the wave number, x is the position of the point on the string, t is the time, ω is the angular frequency, and φ is the phase constant.
We already know the values of A, k, and ω from the previous calculations. To find φ, we can use the given initial condition: "at t = 0 end of the string has zero displacement and is moving upward". This means that y(0,0) = 0 and ∂y/∂t(0,0) > 0. Substituting these conditions into the wave function, we get:
0 = A sin(0 + φ)
∂y/∂t = -Aω cos(0 + φ)
Since sin(0 + φ) = sin(φ) = 0 (because sin(0) = 0), we get:
φ = nπ, where n is an integer
Since cos(0 + φ) = cos(φ) = 1 (because cos(0) = 1) and ∂y/∂t(0,0) > 0, we get:
n = 0 or 2
Therefore, the possible values of φ are 0 or 2π.
Substituting the values of A, k, ω, and φ, we get:
y(x, t) = 0.05 sin(15.708x - 94.248t)
Therefore, the wave function describing the wave is:
y(x, t) = 0.05 sin(15.708x - 94.248t)
(c) To find the transverse displacement of a wave at x = 0.25 m and t = 0.15 s, we can use the wave function we just found:
y(0.25, 0.15) = 0.05 sin(15.708(0.25) - 94.248(0.15))
y(0.25, 0.15) ≈ -0.013 m (rounded to three decimal places)
Therefore, the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m.
(d) To find how much time must elapse from the instant in part (c) until the point at x = 0.25 m has zero displacement,
From part (c), we know that the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m. We need to find the time it takes for this point to return to zero displacement.
We can use the wave function we found in part (b) and set y(0.25, t) = 0:
0 = 0.05 sin(15.708(0.25) - 94.248t)
Since sin(θ) = 0 when θ = nπ (where n is an integer), we get:
15.708(0.25) - 94.248t = nπ
Solving for t, we get:
t = (15.708(0.25) - nπ) / 94.248
To find the smallest positive value of t that satisfies this equation, we need to use the smallest positive value of n that makes the right-hand side of the equation positive (because we want to find the time it takes for the point at x = 0.25 m to return to zero displacement, which happens after the point has completed a full cycle). We can see from the equation that n must be an even integer to make the right-hand side positive. The smallest even integer greater than zero is 2. Substituting n = 2, we get:
t = (15.708(0.25) - 2π) / 94.248
t ≈ 0.297 s (rounded to three decimal places)
Therefore, the time it takes for the point at x = 0.25 m to return to zero displacement is approximately 0.297 s.
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Pls help!!
Which situation describes a system with increasing gravitational potential energy?
a boy jumping down from a tree limb
a girl stretching a horizontal spring
a bicyclist riding up a steep hill
a train speeding up on a flat track
C) a bicyclist riding up a steep hill
The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:
A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.
Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.
A car is travelling at 16.7m/s. If the car can slow at a rate of 21.5m/s^2, how much time does the driver need in order to stop the red light?
Answer:
About 0.7767 seconds
Explanation:
\(\dfrac{16.7m/s}{21.5m/s^2}\approx 0.7767s\)
Hope this helps!
Five lamp, each labbled "6V,3W" are operated at normal brightness. What is the total energy supplied to the lamps in five seconds.
Answer:
E = 75 J
Explanation:
First, we will calculate the total power consumed by the five lamps:
\(Total\ Power = P = (5)(Power\ of\ one\ lamp)\\P = (5)(3\ W)\\P = 15\ W\)
Now, the energy supply can be calculated as follows:
\(E = Pt\)
where,
E = Energy = ?
t = time = 5 s
Therefore,
E = (15 W)(5 s)
E = 75 J
What is the wave where the oscillation is perpendicular to the direction
of motion.
What is the mass (in kg) of a Puffin flying 10 m/s with 1000 J of KE?
Answer:
20 kg
Explanation:
The kinetic energy (KE) of an object is given by:
KE = (1/2) * m * v^2
Where m is the mass of the object, and v is its velocity.
We can rearrange this formula to solve for the mass:
m = 2 * KE / v^2
Plugging in the values given:
m = 2 * 1000 J / (10 m/s)^2
m = 20 kg
Therefore, the mass of the Puffin flying at 10 m/s with 1000 J of KE is 20 kg.
What is a path through which electric current can flow through a wire
How much potential energy is stored in a spring that is stretched 15 cm by a force of 72 N?
Answer:
10,800
Explanation:
The formula is MGH I hop this helps
a.
70. All the following statements are true. Which one can be explained by Kepler's Second Law?
The Sun is not in the precise center of Saturn's orbit.
b. Earth is sightly closer to the Sun in January than in July
All the planets orbit the Sun in nearly the same plane.
d. Mars moves faster in its orbit when it is closer to the Sun than when it is farther from the Sun.
e. Venus orbits the Sun at a faster orbital speed than Earth.
The statement that can be explained using Kepler's Second Law is "Mars moves faster in its orbit when it is closer to the Sun than when it is farther from the Sun."
According to Encyclopedia Britannica, Kepler's second law states that; "a planet moves in its ellipse so that the line between it and the Sun placed at a focus sweeps out equal areas in equal times."
This law is sometimes referred to as the law of equal areas. It describes the fact that a planet moves faster when it is closer to the sun and slower when it farther from the sun.
An implication of this law is that mars moves faster in its orbit when it is closer to the Sun than when it is farther from the Sun.
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can a body have an east velocity while expressing westward acceleration
Yes it can, an object can be moving a certain direction while the ACCELERATION is in the opposite direction.
Lets say your riding a bike... if your squeezing your handle bar breaks, the acceleration of the bike would be pushing in the opposite direction of the direction the bike is moving.
Hope this helped!
A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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