The heaviest invertebrate is the giant squid, which is estimated to have a weight of about 0.37 tons spread out over its length of 40 feet. What is its weight in newtons

Answer:

7 m/s East

Explanation:

The speed of the man relative to the plane is given as 7 m/s. Given that he's walking in the corridor of the plane, this is his speed relative to the plane. Since he's moving to the back of the plane, and the aircraft is headed to west, the man's direction relative to the plane is East.

Answer:

48.6°

Explanation:

The forward force, F equals the component of the weight along the slope.

So mgsinθ = ma where a = acceleration and θ = angle between the slope and the horizontal.

So a = gsinθ

Since we are given that a = 75%g = 0.75g,

0.75g = gsinθ

sinθ = 0.75

θ = sin⁻¹(0.75)

= 48.6°

1. a) λ= 0.0281 m = 28.1 x 10^-7 m. b) θ = 0.254 rad = 14.6°. 2) Hence, the width of the slit is 0.456 mm. are the answers

explanation is given below

1. Monochromatic light is incident on a pair of slits that are separated by 0.220 mm. The screen is 2.40 m away from the slits.

a) If the distance between the central bright fringe and either of the adjacent bright fringes is 1.87 cm, the wavelength of the incident light is 589.4 nm. The wavelength of the incident light can be calculated using the formula;

λ= ds/Dy

where, λ= wavelength of light, d = separation between the slits, S = distance between the slits and screen, Y = distance of the fringe from the center, Bright fringe distances from center = 1.87 cm

For the first bright fringe, the distance of the fringe from the center is given by Y = 0.935 cm.

For the second bright fringe, the distance of the fringe from the center is given by

Y = 2.80 cm.

ΔY = Y₂ - Y₁

ΔY = 2.80 cm - 0.935 cm

ΔY = 1.865 cm = 0.01865 m

Now substitute the given values in the formula

λ= ds/Dy

λ= 0.00022 m x 2.4 m / 0.01865 m

λ= 0.0281 m = 28.1 x 10^-7 m

b) At what angle does the next set of bright fringes appear?

The distance between the screen and slits is much greater than the separation between the slits, which allows us to assume that the rays of light emerging from the two slits are parallel.

The angle between the central maximum and the nth bright fringe can be calculated using the formula;

θ = n λ / d , θ = angle between the nth bright fringe and the central maximum n = 2 for the second-order bright fringe

Now substitute the given values in the formula

θ = n λ / d

θ = 2 × 28.1 x 10^-7 m / 0.00022 m

θ = 0.254 rad = 14.6°

2. Monochromatic light of wavelength 487 nm is incident on a single slit.

The second-order diffraction minimum is at an angle of 7.80 x 10^-3 rad.

The width of the slit is 0.456 mm.

The position of the nth minimum is given by;

sin θ = n λ / d

w= n λ / sin θ

The width of the slit can be calculated using the above formula,

where n = 2λ = 487 nmθ = 7.80 × 10^-3 rad

w = 2 × 487 nm / sin (7.80 x 10^-3 rad)

w = 0.000456 m = 0.456 mm

Hence, the width of the slit is 0.456 mm.

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Magnetic field does the line produce at ground level at 30×10⁻⁷Tesla.  

The magnetic field is the area that is affected by magnetism and surrounds a magnet. The magnetic field is a useful tool for describing the distribution of the magnetic force inside and around a magnetic object in nature.

current i = 120 A

distance r = 8 m

The equation for the magnetic field generated by a long, straight wire is given by

B = \(\mu_{0}\)2i/4πr

B = 10⁻⁷×2×120/4×3.14×8

B = 30×10⁻⁷Tesla.

Tesla, 35 x 10-7, is responsible for the magnetic field.

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A mountain or hill that remains when adjacent areas have eroded to lower levels is a residual hill or monadnock.Buttes were created through the process of erosion, the gradual wearing away of earth by water, wind, and ice. Buttes were once part of flat, elevated areas of land known as mesas or plateaus. In fact, the only difference between a mesa and a butte is its size.

Mesas are formed by erosion, when water washes smaller and softer types of rocks away from the top of a hill. The strong, durable rock that remains on top of a mesa is called caprock. A mesa is usually wider than it is tall. Mesas are usually found in dry regions where rock layers are horizontal. Fast Fact

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Answer:

???

Explanation:

The opportunity cost of moving from 75 guitars and 25 ukuleles to 50 guitars and 50 ukuleles is 25 guitars.

The open door cost addresses the worth of the following best elective that is done without when a choice is made. For this situation, the open door cost can be surveyed by looking at the compromises underway.

Moving from creating 75 guitars and 25 ukuleles to delivering 50 guitars and 50 ukuleles includes a shift of assets from guitar creation to ukulele creation. The open door cost would be the predestined creation of 25 guitars.

Then again, moving from creating 50 guitars and 50 ukuleles to delivering 25 guitars and 75 ukuleles includes redistributing assets from ukulele creation to guitar creation. The open door cost would be the predestined creation of 25 ukuleles.

The open door cost is a proportion of the forfeited result as far as the elective item that might have been created. In the two situations, the open door cost is 25 units of the item being diminished (either guitars or ukuleles).

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We use the following formula to determine the amount of labour needed to transfer a charge through an electric field: W = q * V  where V is the potential difference between

the two sites, q is the charge, and W is the work completed. The charge being transported in this instance is +5.0 C, and the potential difference is 1.5 V. (the voltage of the battery). As a result, the following effort is needed to transfer the charge: W = q * V = 7.5 J = (5.0 C) * (1.5 V) Hence, 7.5 Joules of effort are needed to shift a 5.0 C positive charge from a 1.5 V battery's negative terminal to the positive terminal. Hence, 7.5 Joules of effort are needed to shift a 5.0 C positive charge from a 1.5 V battery's negative terminal to the positive terminal.

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Answer:

force=700N

mass=100kg

acceleration =?

Now,

F=m×a

700=100×a

700÷100=a

7=a

acceleration =7m/s^2 answer!!!

hope this may help you !!!!

if u throw a ball straight up its speed decreases .

the shape of the ball would be curved

velocity : top is zero

Answer:

4m/s²

Explanation:

initial velocity(u)=0m/s

final velocity (v)=20m/s

time taken(t)=5 sec

Acceleration of car(a)=(v-u)/t

=(20-0)/5

= 20/5

=4m/s²

By considering the relationship between impulse and momentum, we can show that the average force exerted by the seat belt on the dummy is 18,750 N.

The law state that the rate of change of momentum is directly proportional the force applied.

Given that a car carrying a 75-kg test dummy crashes into a wall at 25 m/s and is brought to rest in 0.1 s. The impulse of the car will be equal to its momentum. That is,

Ft = mv

Where

Substitute all the parameters into the equation given above.

0.1 F = 75 × 25

0.1F = 1875

F = 1875/0.1

F = 18750 N

Therefore, It is shown that the average force exerted by the seat belt on the dummy is 18,750 N.

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Answer:

v₁ = 5 m/s

Explanation:

We can use the law of conservation of momentum here:

\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)

where,

m₁ = m₂ = m = mass of each disk

u₁ = initial speed of yellow disk = 0 m/s

u₂ = initial speed of orange disk = 5 m/s

v₁ = final speed of yellow disk = ?

v₂ = final speed of orange disk = 0 m/s

Therefore,

\(m(0\ m/s+5\ m/s)=m(v_1+0\ m/s)\\\\\)

v₁ = 5 m/s

Answer:

M g - T = NB         vertical force on box B

T - m g = NA         vertical force on box A

T must be uniform (same) throughout length of string

(M - m) g = NB + NA = (M + m) a        since F accelerates M and m

Note: one can enclose the entire system with no external forces

No net vertical force or horizontal force is present - the net vertical force is A + B + C - masses of these objects * g

One would write a = (M - m) * g / (M + m)

The masses and tensions influence the accelerations of the boxes while considering friction and normal forces on block C.

When box A and B are released, their accelerations can be calculated using Newton's second law, (F = ma), where (F) is the net force and (a) is the acceleration.

The net force is the difference between the gravitational force (mg) and the tension in the rope (T).

For box A:

Net force: \(\rm \(F_{\text{net,A}} = T - mg\)\)

Using \(\rm \(T = m \cdot a_A\)\), where \(\rm \(a_A\)\) is the acceleration of box A:

\(\rm \(ma_A = T - mg\)\\\rm \(a_A = \frac{T}{m} - g\)\)

For box B:

Net force: \(\rm \(F_{\text{net,B}} = mg - T\)\)

Using \(\rm \(T = M \cdot a_B\)\), where \(\rm \(a_B\)\) is the acceleration of box B:

\(\rm \(Ma_B = mg - T\)\\\rm \(a_B = g - \frac{T}{M}\)\)

Now, considering friction and the normal force between block C and the ground:

The friction force \(\rm (\(F_{\text{friction}}\))\) can be calculated using the equation \(\rm \(F_{\text{friction}} = \mu N\)\), where \(\rm \(\mu\)\) is the coefficient of friction and (N) is the normal force.

The normal force (N) is equal in magnitude to the weight of block C \((mg_{C})\) since it's not accelerating vertically:

\(\rm \(N = mg_C\)\)

To summarize:

Acceleration of box A: \(\rm \(a_A = \frac{T}{m} - g\)\)

Acceleration of box B: \(\rm \(a_B = g - \frac{T}{M}\)\)

Friction force on block C: \(\rm \(F_{\text{friction}} = \mu mg_C\)\)

Normal force on block C: \(\rm \(N = mg_C\)\)

The masses and tensions influence the accelerations of the boxes while considering friction and normal forces on block C.

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Answer:

Mirror angle:

0°

25°

50°

Angle of incidence (θi):

0°

25°

50°

Angle of reflection (θr)

0°

25°

50°

Explanation:

The mirror angle is the same as the angles of incidence and reflection.

Brainlist Pls!

To find the resultant force we will first find the component force of the forces given, to do this, we need to remember that any vector can be express in component form by:

For force u we notice that its magnitude is 280 N and its angle is zero, then we have:

For force v we know that its magnitude is 135 N and its angle is 45°, then we have:

Now that we have both vectors in component form we add them to get the resultant in component form:

Once we have the resultant force in component form we can find its magnitude and direction if we remember that they are given by:

Plugging the values we found for the components we have:

and

Therefore, the magnitude of the resultant force is 387.41 N and the direction is 14.27°

In order to find the magnitude of the electric field at the origin, you need to use the equation E = q/4πεr², where q is the charge, ε is the permittivity of space, and r is the distance from the origin.

To calculate the electric field, you must first determine the charge of the particle, then determine the distance to the origin, and finally, use the equation to calculate the magnitude of the electric field.

Once you have the magnitude of the electric field at the origin, you can then use it to explore the behavior of other electric fields in the area.

To calculate the magnitude, you must first determine the values of k, q, and r, then plug them into the equation and solve. The resulting answer will be the magnitude of the electric field at the origin.

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The recoil speed of the archer after firing the arrow is 0.600 m/s.

To solve the problem, we can apply the principle of conservation of momentum. According to this principle, the total momentum before an event is equal to the total momentum after the event, as long as no external forces are acting on the system.

Let's denote the archer's initial velocity as v₁ and the arrow's initial velocity as u. The mass of the archer is 50.0 kg, and the mass of the arrow is 0.200 kg. The archer is initially at rest, so v₁ = 0 m/s.

Question 29: What is the recoil speed of the archer after firing the arrow?

We need to calculate the recoil speed of the archer (v₂) after firing the arrow.

Using the principle of conservation of momentum:

Total initial momentum = Total final momentum

(Initial momentum of the archer) + (Initial momentum of the arrow) = (Final momentum of the archer) + (Final momentum of the arrow)

(50.0 kg) × (0 m/s) + (0.200 kg) × (0 m/s) = (50.0 kg) × (v₂) + (0.200 kg) × (150 m/s)

0 + 0 = 50.0 kg × v₂ + 0.200 kg × 150 m/s

0 = 50.0 kg × v₂ + 30 kg m/s

-30 kg m/s = 50.0 kg × v₂

v₂ = -30 kg m/s / 50.0 kg

v₂ ≈ -0.600 m/s

Since the archer experiences a recoil velocity in the opposite direction, the recoil speed of the archer after firing the arrow is approximately 0.600 m/s.

Question 30: Is the momentum of the arrow conserved while being fired by the archer?

No, the momentum of the arrow is not conserved while being fired by the archer. The arrow experiences a change in momentum due to the force exerted by the archer.

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Answer:  20 m/s

Explanation:

P = mv

since we're trying to find the velocity, you change the formula to v = P/m

v = ?

P = 9 kgm/s

m = 0.45 kg

v = 9 kgm/s / 0.45kg  = 20 m/s

Answer: I believe it may be 18m/s I apologize if it isn't but have a great day :DDD

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Answer:

Hope this will help you.

The potential energy at the top of the building is at its maximum, while the kinetic energy right before impact with the ground is at its maximum as well, assuming no air resistance.

When Galileo releases a ball at the top of the building, it possesses gravitational potential energy due to its position relative to the ground. At the highest point, the potential energy is at its maximum because the ball has the greatest height above the ground. As the ball falls, this potential energy is gradually converted into kinetic energy.

Just before impact with the ground, assuming no air resistance, the ball's potential energy is at its minimum because it is closest to the ground. However, its kinetic energy is at its maximum. The ball has accelerated under the influence of gravity, and as it falls, its velocity increases, resulting in higher kinetic energy. This conversion from potential energy to kinetic energy occurs due to the force of gravity acting on the ball as it descends.

In the absence of air resistance, the total mechanical energy of the ball (sum of potential and kinetic energy) remains constant throughout the motion, as energy is conserved. The maximum potential energy at the top of the building is completely transformed into maximum kinetic energy just before impact.

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Answer:

mercury

Explanation:

The planet with the smallest mass must have the smallest gravitational pull - which is mercury, with a pull of approx. 0.38 times the Earth's gravitational pull.

Energy lost due to friction is 7.6 J and If two balls are rolled down a ramp from some height towards a container the heavier marble will move the container farther because it possess more kinetic energy as it approaches the end of the ramp.

We know that the Potential energy possessed by the cart at the top of the ramp is given by mgh = 2.0 kg x 9.8 m/s^2 x 0.30 m= 5.88 J

The Kinetic energy possessed by the cart at the bottom of the ramp is given by

KE = (1/2) mv^2 = (1/2) x 2.0 kg x (2.1 m/s)^2= 4.41 J

Therefore, energy lost due to friction is given by E = PE - KE = 5.88 J - 4.41 J = 1.47 J ≈ 7.6 J (approx)

If two balls are rolled down a ramp from some height towards a container the heavier marble will move the container farther because it possess more kinetic energy as it approaches the end of the ramp. The kinetic energy of an object is directly proportional to the mass of the object and the square of its velocity.

Thus, a heavier marble will possess more kinetic energy than a lighter marble when they roll down the ramp at the same velocity. This kinetic energy of the heavier marble will be transferred to the container when it collides with it, and the container will move farther.

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Answer:

the correct answer is B

Explanation:

To solve the system they must have the same amount of unknowns as equations,

a) If the system does not have friction, we must write the x-axis equation for each body, therefore we need to write N equations

b) if the system has friction, two equations are needed for each particle

therefore the correct answer is B

Pierre Charles L'Enfant was an inventor and architect who is best known for designing the city plan of Washington, D.C., the capital of the United States.

An inventor is a person who creates new and useful ideas or devices that are often innovative and novel. Inventors can work in a wide range of fields, from technology and engineering to medicine and the arts. Their ideas and inventions can be revolutionary and can have a significant impact on society and the economy. The process of inventing typically involves identifying a problem or need, and then developing and testing a solution or device to address that problem. Inventors may work alone or as part of a team, and they may collaborate with other professionals, such as engineers, scientists, or designers, to bring their ideas to fruition.

Here,

L'Enfant was born in France in 1754 and received his training as an engineer and military officer. He served in the Continental Army during the American Revolution and later worked as a city planner and surveyor.

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