the half-life of polonium-218 is 3 min. if you start with 16 mg, how long will it be before only 1 mg remains

Answers

Answer 1

The half-life of polonium-218 is 3 minutes, and we need to mass how long it will take for only 1 mg of the original 16 mg to remain. A substance's half-life is the time it takes for half of it to decay.

If we start with 16 mg and wait for one half-life, we will have 8 mg remaining. We will then have 4 mg remaining after two half-lives, 2 mg remaining after three half-lives, and so on. Let's suppose we need n half-lives to pass before the mass of polonium-218 is reduced to 1 mg.

We can use the following equation to calculate n:16 mg ÷ 2n = 1 mg

To solve for n, we can first isolate 2n on one side of the equation:2n = 16 mg ÷ 1 mg

2n = 16

n = log2 16

n = 4

Therefore, the mass of polonium-218 will be reduced to 1 mg after 4 half-lives. Since the half-life of polonium-218 is 3 minutes, the amount of time it takes for four half-lives to pass is: 4 × 3 min = 12 minutes .

Therefore, it will take 12 minutes for the mass of polonium-218 to be reduced to 1 mg.

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Related Questions

What is the energy if the frequency is 8.33 x 10^-4 Hz

Answers

오늘 저녁에 집에 와서 같이 저녁을 먹을까 아니면

this rock above contains many large (2-5cm across) phenocrysts that are salmon pink. which mineral is this?

Answers

Phenocrysts are the kind of feldspar minerals.

A mineral is an detail or chemical compound that is normally crystalline and that has been shaped because of geological techniques. Examples include quartz, feldspar minerals, calcite, sulfur and the clay minerals inclusive of kaolinite and smectite.

A clearly going on inorganic element or compound having an. orderly internal shape and feature chemical composition, crystal form, and physical. properties. Minerals range from rocks, which are certainly happening solids composed of 1 or more minerals.

Minerals are labeled based totally on their crystal shape and chemistry. Minerals are divided into two types particularly steel and non-metal.

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Carbon cycle – What are the main reservoirs
of the carbon cycle? Where do the inorganic and organic carbon
cycles interact? What are the major differences and similarities
between the inorganic and organic carbon?

Answers

The main reservoirs of the carbon cycle are the atmosphere, oceans, land (including vegetation and soils), and fossil fuels. In these reservoirs, carbon exists in both inorganic and organic forms.

The inorganic carbon cycle involves the exchange of carbon dioxide (CO2) between the atmosphere and oceans through processes like photosynthesis and respiration.

Organic carbon, on the other hand, is found in living organisms, dead organic matter, and soil organic matter. It is cycled through processes such as decomposition and consumption by organisms. The interactions between the inorganic and organic carbon cycles occur primarily in the biosphere, where photosynthesis converts inorganic carbon into organic carbon compounds. While inorganic carbon is primarily in the form of CO2, organic carbon is present in complex organic molecules. Both forms of carbon play crucial roles in energy transfer, nutrient cycling, and climate regulation.

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Write the product obtained by the electrolysis of CuCl2 at cathode and anode

respectively

Answers

During the electrolysis of CuCl₂ the products that are formed are

At the cathode: Copper metal (Cu)

At the anode: Chlorine gas (Cl₂)

Electrolysis is a chemical process that uses an electric current to drive a non-spontaneous chemical reaction. It involves the decomposition of an electrolyte (a substance that conducts electricity when dissolved in a solution or molten state) into its constituent ions through the application of an electric current.

At the cathode (negative electrode):

Cu²⁺ ions (from CuCl₂) are reduced to copper metal (Cu):

Cu²⁺ + 2e⁻ → Cu

Therefore, at the cathode, copper metal (Cu) is obtained.

At the anode (positive electrode):

2Cl⁻ ions (from CuCl₂) are oxidized to chlorine gas (Cl₂):

2Cl⁻ → Cl₂ + 2e⁻

Therefore, at the anode, chlorine gas (Cl₂) is obtained.

In summary:

At the cathode: Copper metal (Cu)

At the anode: Chlorine gas (Cl₂)

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Can someone help me please!

Can someone help me please!

Answers

I think it’s either d or b

what alkene is required to synthesize the following compound?

Answers

The alkene required to synthesize the given compound is 1-butene. 3-methyl-2-hexanone is a cyclic compound with a methyl functional group and a carbonyl functional group that is composed of a six-carbon ring with one additional carbon atom linked to one of the ring's carbons.

The compound we need to synthesize has a methyl group (-CH3) attached to the terminal carbon of the alkene. This indicates that the alkene must have three carbon atoms with a double bond between the first and second carbons. The only alkene fitting this description is 1-butene, which has a molecular formula of C4H8 and a double bond between the first and second carbons.

By reacting 1-butene with an appropriate reagent, such as a methylating agent like dimethyl sulfate or methyl iodide, we can introduce a methyl group to the terminal carbon of the alkene, resulting in the desired compound. This reaction requires careful consideration of regio chemistry and selectivity to ensure that the methyl group is added specifically to the terminal carbon of 1-butene.

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From the following compounds, identify the ones that are nonpolar covalent.

H2O

NCl3

AuCl3

ClO2

SF4

SO3

Answers

Answer:

The nonpolar covalent compounds are:

H2O (polar covalent)

NCl3 (polar covalent)

AuCl3 (ionic)

ClO2 (polar covalent)

SF4 (polar covalent)

SO3 (nonpolar covalent)

What is the number of protons of oxygen

Answers

Answer:

8 protons

The number of protons tell us what type of element an atom is.

In Lab, We Used Oxone To Oxidize Borneol To Camphor. Write Chemical Equations Describing The Reaction Of NaCl And Oxone.

Answers

Answer:

NaO2SO3 -> Na2SO4 + O2

Explanation:

The reaction of NaCl (sodium chloride) and Oxone (potassium peroxymonosulfate) is described by the following chemical equations:

The first step in the reaction is to dissociate oxone into its component ions:

Oxone (potassium peroxymonosulfate) -> K+ (potassium ion) + O2SO3- (peroxymonosulfate ion)

The peroxymonosulfate ion (O2SO3-) then oxidizes the sodium chloride (NaCl) to produce sodium peroxymonosulfate (NaO2SO3) and chlorine gas (Cl2):

NaCl + O2SO3-  -> NaO2SO3 + Cl2

The sodium peroxymonosulfate (NaO2SO3) then decomposes into sodium sulfate (Na2SO4) and oxygen gas (O2):

NaO2SO3 ) -> Na2SO4  + O2.#SPJ4

.

sodium bicarbonate and acetic acid balanced equation

Answers

Answer:

C2H4O2 + NaHCO3 → NaC2H3O2 + H2O +CO2 4.

Explanation:

you have a lead ball with a mass of 420 g. the density of lead is 10.5 g/cm³. what is the volume of the ball

Answers

Answer:

The answer is

40.0 mL

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \)

From the question

mass = 420 g

density = 10.5 g/cm³

The volume is

\(volume = \frac{420}{10.5} \\ \)

We have the final answer as

40.0 mL

Hope this helps you

A sample of ground beef contains 21.3% protein and 16.9% fat, both by mass. What mass of this ground beef, in grams, contains 350 Calories? Assume all Calories come from protein and fat.

Answers

Answer:

147.5 grams

Explanation:

Let the required mass of ground beef be m .

protein in it = .213 m

fat in it = .169 m

1 gram of protein gives 4 cals .

1 gram of fat gives 9 cals .

cals given by .213 m protein = 4 x .213 m .

cals given by .169 m fat  = 9 x .169 m .

4 x .213 m  + 9 x .169 m = 350

.852 m + 1.521 m = 350

2.373 m = 350

m = 147.5 grams Ans

what is the average kinetic energy of 4.51 mol of a gas of molar mass 33.8 g/mol and rms speed 866 m/s

Answers

Answer:

A big load of icecream/ loaded cake.

Explanation:

each gram of carbohydrate supplies how many calories per gram

Answers

Each gram of carbohydrate supplies 4 calories per gram.Carbohydrates are macronutrients that provide energy to the body.

They are classified into three categories: sugars, starches, and fibers. Carbohydrates are the body's primary source of energy. They supply glucose, which is the body's main fuel source, to cells and organs.

The body breaks down carbohydrates into glucose during digestion, which is then transported to cells for use. The liver and muscles store excess glucose as glycogen, which is used as an energy source when glucose levels drop.Carbohydrates are typically divided into two categories based on their chemical structure: simple carbohydrates and complex carbohydrates.

Simple carbohydrates are made up of one or two sugar molecules and are found in foods such as fruits, milk, and candy. Complex carbohydrates, on the other hand, are made up of three or more sugar molecules and are found in foods such as whole grains, vegetables, and legumes.

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]
Consider the following intermediate chemical equations.
C(s) +
CO(g) +
O₂(g) → CO(g)
How will oxygen appear in the final chemical equation?
O O2(g) as a product
O O2(g) as a reactant
OO(g) as a product
O 20(g) as a reactant
O₂(g) → CO₂(g)

Answers

In the above intermediate chemical equation, oxygen will appear as follows: O₂(g) as a reactant (option B).

What is a chemical equation?

A chemical equation in chemistry is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

According to this question, an intermediate chemical equation is presented as follows:

CO(g) + O₂(g) → CO(g)C(s) + O₂(g) → CO₂(g)

As observed in the above chemical equation, oxygen will react in its gaseous form i.e. as a reactant.

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Question 5 of 5
A spiral staircase like the one shown can be a model of the
structure of a DNA molecule.
In this model, what do the steps on the staircase represent?

Question 5 of 5A spiral staircase like the one shown can be a model of thestructure of a DNA molecule.In

Answers

Answer:

A

Explanation:

l took the test

How do we solve this? I got B but answer key says A

How do we solve this? I got B but answer key says A

Answers

The concentration of NH3 at equillibirium is 0.00010M. Option A.

Ammonium nitrate is formed when nitric acid reacts with ammonia. It is a white crystalline solid consisting of ammonium ions and nitrate ions. Soluble in water, but does not form hydrates. Ammonia is directly neutralized with sulfuric acid to produce ammonium sulfate.

The neutralization evaporator and crystallizer are connected so that the heat released during neutralization is used to evaporate the water in the ammonium sulfate slurry. These units operate under partial vacuum. Nitric acid pH neutralization is common and any inorganic base such as sodium hydroxide or lime can be used. Ammonia gas reacts with hydrogen chloride gas to form ammonium chloride.

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Hi can someone please help me find the average for these temperatures? I need them asap

Hi can someone please help me find the average for these temperatures? I need them asap

Answers

Answer:

55 degrees F - cold water

120 degrees F

the last on I don't know

3. Consider an iron-carbon alloy containing 0.60 wt% carbon. What is the proeutectoid phase? Compute the mass fractions of the proeutectoid phase and the pearlite phase. (15) arven C-0.60 knite chuse

Answers

The mass fraction of the pro eutectoid phase is approximately 0, and of the pearlite phase is approximately 1.

In iron-carbon alloy with 0.60 wt% carbon, the pro eutectoid phase is cementite (Fe₃C). To calculate the mass fractions of the pro eutectoid phase and the pearlite phase,  consider the eutectoid reaction.

Eutectoid reactions in iron-carbon alloys are usually found at a composition of approximately 0.76 wt% carbon. As the alloy in question contains 0.60 wt% carbon it is hypo-eutectoid (i.e., below the eutectoid composition).

The lever rule will be used to calculate this equation  as follows:

f₁ = \(\frac{C_{0} - C_{e} }{C_{1} - C_{e} }\)

where the values represent here :

f₁ = mass fraction of the pro eutectoid phase (cementite),

Cₒ =carbon content in the alloy (0.60 wt%),

Cₑ =eutectoid composition (0.76 wt%),

C₁ = carbon content in the cementite phase (6.70 wt% carbon).

After substituting the given values into the equation:

f₁ = \(\frac{0.60 - 0.76}{6.70 - 0.76} \\\)

f₁ = \(\frac{0.16}{5.94}\)

f₁ ≈ -0.027

Here the negative value of f₁ shows that there is no pro eutectoid phase present in the alloy. Rather, the entire alloy consists of the pearlite phase.

Hence ,  the mass fraction of the pro-eutectoid phase is approximately 0, and the mass fraction of the pearlite phase is approximately 1.

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How do you test color?

Answers

Answer:

red

Explanation:

rojo yyyyy888888iiiiii

briefly explain why amorphous polymers are transparent, while predominantly crystalline polymers appear opaque or, at best, translucent.

Answers

Amorphous and crystalline polymers are two types of polymers that exhibit different levels of transparency. Generally, amorphous polymers tend to be transparent while predominantly crystalline polymers appear opaque or, at best, translucent.

In this discussion, we will examine the reasons behind this observation and the factors that influence polymer transparency. Amorphous polymers are transparent due to their lack of ordered structure. In other words, amorphous polymers lack a crystalline structure, and their molecular chains are randomly oriented. When light passes through amorphous polymers, it is not refracted by the crystal structure, which causes the transparency. The random orientation of molecular chains causes the light to pass through uninterrupted. An example of an amorphous polymer that is transparent is polycarbonate.

Polycarbonate is widely used in consumer electronics and eyewear due to its transparency and high impact resistance. On the other hand, predominantly crystalline polymers are typically opaque or, at best, translucent. This is because the crystalline structure of the polymer leads to a high level of light scattering. Crystalline polymers have a regular arrangement of polymer chains and thus have a specific crystal lattice structure. The regular arrangement of molecules makes it challenging for light to pass through the polymer.

Instead, light interacts with the crystal lattice and gets scattered. This scattered light results in an opaque or translucent appearance. An example of a predominantly crystalline polymer is polyethylene. Polyethylene is typically opaque due to its crystalline structure.In summary, amorphous polymers tend to be transparent, while predominantly crystalline polymers appear opaque or, at best, translucent. The transparency of polymers is dependent on their molecular structure and the crystal lattice structure.

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What is the proper procedure for applying two-color monomer liquid and polymer powder nail enhancements using forms?

Answers

Preparing the natural nails and applying a drying agent to eliminate extra moisture are the first steps in the correct technique for applying two-color monomer liquid and polymer powder nail enhancements utilising forms.

The proper procedure for applying two-color monomer liquid and polymer powder nail enhancements using forms starts with preparing the natural nails and applying a dehydrating agent to remove excess moisture. Next, choose the desired two colors and mix the monomer liquid and polymer powder to create the acrylic mixture. Apply the forms to the nails and then apply the first color mixture to the free edge of the nail. Allow it to dry before applying the second color mixture to the remaining nail bed. After the acrylic has dried, remove the forms and file and shape the nails as desired. Finally, apply a top coat to seal the nail enhancements. It is important to follow proper procedures to ensure the best results and to avoid damaging the natural nails.

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There is a different Safety Data Sheet for every chemical.
Select one:
O True
o False

Answers

Answer:

True

Explanation:

This is true because every chemical reacts differently

what is the largest particle that can generally be transported by a stream moving at 200 centimeters per second1. boulder2. cobble

Answers

The largest particle that can generally be transported by a stream moving at 200 centimeters per second is a cobble.

So, the correct answer is option 2.

A cobble is a rounded rock fragment larger than a pebble but smaller than a boulder. It usually ranges in size from 64 to 256 millimeters in diameter. The velocity of a stream is a critical factor in determining the size of the particles that can be transported by the water. As the velocity of the stream increases, it can carry larger particles.

However, there is a limit to the size of the particles that can be transported, and a stream moving at 200 centimeters per second can carry a maximum particle size of a cobble. Anything larger, such as a boulder, would require a much stronger current to transport.

Hence, the answer of the question is option 2

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In a certain chemical reaction Compound combines with Compound to produce Compound (and no other products). Measurements were taken of the amounts of and present before and after a reaction that produced some : Compound initial amount final amount Calculate the theoretical yield of . Round your answer to the nearest . Suppose the percent yield of in this reaction was . Calculate the actual amount of that was isolated at the end of the reaction. Round your answer to the nearest .

Answers

Answer:

0.8g.

Explanation:

So, in this question we are to calculate for the actual yield of the product, Say C.

Thus, the equation for Determining the percentage yield is given as;

Percentage yield = actual yield/ theoretical yield × 100 ---------------------(1).

Therefore, from equation one above we can calculate the value for the percentage yield for product C.

A + B ==========================> C.

From the given value we have that, before the reaction there are 1.0 g of A and 7.0 g of B, after the reaction; we have 0 gram of A and 5.2 gram of B. That means that A is the limiting reactant. Thus, A Determines the reaction.

Hence, the mass of product C = 1 g = 0.1 × 10^1 grams.

Therefore, using the reaction (1) above;

Percentage yield = actual yield/ theoretical yield × 100.

80 =( actual yield / 0.1 × 10^1 grams ) × 100.

80 × 0.1 × 10^1 grams = 100 × actual yield.

Actual yield = 0.8 g.

You have 0.00891 g of platinum. What is this in micrograms?
A. 8.91 ug
B. 8910 ug
C. 8.91 x 10-6 ug
D. 8.91 x 10-9 ug

Answers

Answer:

Hope it help you

Stayhomestaysafe

Plz mark my answer brainliest✍️✍️

Explanation:

It would be 8910 ug

REAL NAME - SHRESTH DUBEY

Rank the three types of bonds - ionic, polar covalent and nonpolar covalent - from
strongest to weakest. Justify your answer.

Answers

Answer : Ionic, polar covalent, and no polar covalent

Ionic has the strongest bond because there is a complete transfer of the valence electrons, this results in full charges. Polar covalent bonds have electrons shared unequally between the atoms, resulting in partial charges in the atoms. And nonpoplar covalent bonds have electrons shared equally between two atoms, resulting in i charges of the atoms.

The order of strongest to weakest bond type:

Ionic bond > Polar covalent bond > non polar covalent bond

Explanation:

Ionic bonds are chemicals bonds in which the complete transfer of electrons takes place between a highly electronegative atom and the least electronegative atom.In an ionic bond, there is a strong electrostatic force of attraction due to the formation of two oppositely charged ions.Covalent bonds are chemicals bonds in which the sharing of electrons takes place between atoms with a slight or nil difference in their electronegativities.There are two types of covalent bonds: polar covalent and nonpolar covalent.In polar covalent bonds, due to unequal sharing of electrons partial positive and negative charges are generated.These partial charges give rise to a temporary attractive force of attraction between atoms in polar covalent bonds.In non-polar covalent bonds,  equal sharing of electrons between atoms of the same or similar electronegativities.The order from strongest to weakest chemical bond:

Strong electrostatic force> temporary attractive force> no force of attraction

Ionic bond > Polar covalent bond > non polar covalent bond

So, from this, we can conclude that the order of ionic bond is the strongest followed by a polar covalent bond and then a nonpolar covalent bond.

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Gallium is a metallic element in Group III. It has similar properties to aluminium.
(a) (i) Describe the structure and bonding in a metallic element.

Answers

Metallic elements exist in a solid-state and they are opaque, have a shiny surface, good conductors of electricity and heat, malleable and ductile, and are dense. The structure of metals is formed by atoms that are held together by metallic bonds. These atoms have loosely bound valence electrons that can be shared between the neighboring atoms.

Therefore, the outermost shells of these atoms are incomplete due to the sharing of valence electrons, forming a lattice structure known as a metallic bond.Metallic elements have a unique crystal structure that occurs in two forms. The most common type of metal crystal structure is the body-centered cubic structure where the atoms are arranged in a cube with one atom located at the center of the cube. The other type of metal crystal structure is the face-centered cubic structure, where each corner of the cube is an atom and there is an additional atom at the center of each face of the cube .Metallic bonding occurs due to the delocalized electrons that exist in the metal structure. The valence electrons from each atom are free to move throughout the entire metal lattice. Therefore, these electrons form a "sea of electrons" that is shared by all the atoms in the lattice. This results in the metal structure having high thermal and electrical conductivity.Metals are known for their ductility and malleability properties. These properties are due to the metallic bonding that exists in the metal structure. Since the valence electrons are shared, they can easily move past one another, allowing the metal to be hammered into different shapes without breaking.The properties of metals vary depending on their structure and bonding. Gallium, being a metallic element in Group III, has similar properties to aluminum. Therefore, it has a similar metallic bond structure with delocalized electrons that provide the metal with its unique properties.

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ASAP HELP WILL MARK BRAINLIST 7,8,9, and 10

ASAP HELP WILL MARK BRAINLIST 7,8,9, and 10

Answers

7. a. I
8. c. 75 g/ml
9. b. .25g/cm3
10. b. the density decreases

Baking cookies are what type
of change?

Chemical physical or thermal?

Answers

Answer:

chemical

Explanation:

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