hello I need help with this question. I started it but am confused
Given:
The mass on the table is,
\(m=1.0\text{ kg}\)The hanging mass is,
\(M=1.5\text{ kg}\)THe coefficient of friction is,
\(\mu=0.20\)let the acceleration of the whole system is a (for the hanging mass it is downward and for the mass on the table it is rightward). the tension towards The fixed point of the pulley is T.
we can write,
\(Mg-T=Ma\ldots.\ldots..\ldots\ldots.(1)\)\(ma=T-\mu mg\ldots.\ldots.\ldots..\ldots..(2)\)Adding these equations we get,
\(\begin{gathered} (M+\mu m)g=(M+m)a \\ a=\frac{(M+\mu m)g}{M+m} \end{gathered}\)Substituting the values we get,
\(\begin{gathered} a=\frac{(1.5+0.20\times1.0)9.8}{1.5+1.0} \\ =6.67m/s^2 \end{gathered}\)Hence the acceleration is 6.66 m/s^2.
What is the law of conservation of energy?
Answer:
In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. ... For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.
Explanation:
How does mass affect acceleration
The acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass. That is, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
The acceleration of an object decreases as its mass increases since a larger force is required to produce a given acceleration of a more massive object. On the other hand, if a smaller force is used, the acceleration will be slower. This concept is mathematically represented by Newton's second law of motion: F = ma where F is the net force applied to an object, m is its mass, and a is the acceleration it experiences.
So, The acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass.
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What produces the primary force that causes the vocal folds to vibrate? (Hint: what supplies the energy?)
The primary force that causes the vocal folds to vibrate is the airflow from the lungs. The energy for this vibration is supplied by the air pressure created when we exhale. Here's a step-by-step explanation:
1. When we exhale, air pressure builds up below the closed vocal folds.
2. This air pressure pushes the vocal folds apart, allowing the air to pass through.
3. As the air passes, the vocal folds are drawn back together due to their elasticity and the Bernoulli effect (a principle in fluid dynamics).
4. This cycle of opening and closing repeats rapidly, causing the vocal folds to vibrate and produce sound.
So, the airflow from the lungs is the primary force causing the vocal folds to vibrate, and the energy is supplied by the air pressure created during exhalation.
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A mass M1=6kg rests on a frictionless table and connected by a massless string over a massless pulley to another mass M2=6.8kg which hangs freely from the string. When released, the hanging mass falls a distance d=.9m.1) How much work is done by the normal force on M1?2) What is the final speed of the two blocks?3) How much work is done by tension on M1?4) What is the tension in the string as the block falls?5) The work done by tension on only M2 is? a) positive b) zero, c) negative.6) What is the NET work done on M2?
Given data:
* The mass on the frictionless table is,
\(m_1=6\text{ kg}\)* The mass hangs freely from the string is,
\(m_2=6.8\text{ kg}\)* The hanging mass falls a distance is,
\(d=0.9\text{ m}\)Solution:
(1). The normal force of mass on the frictionless table is,
\(\begin{gathered} F_N=m_1g \\ F_N=6\times9.8 \\ F_N=58.8\text{ N} \end{gathered}\)As the displacement of the mass m_1 on the frictionless table is in the hroizontal direction.
Thus, the work done by teh normal force is,
\(W=F_Nd\cos (\theta)\)\(\text{where }\theta\text{ is the angle between the normal force and dispalcement}\)As both the normal force and displacement are perpendicuular to each other.
Thus, the work done by the nromal force on the mass m_1 is,
\(\begin{gathered} W=F_Nd\cos (90^{\circ}) \\ W=0 \end{gathered}\)Thus, the work done by the normal force on m_1 is zero.
question isolines of potential are drawn for the gravitational field of the sun-mercury system. the pattern of the isolines is identical to the pattern of equipotential lines for a system of two electrically charged objects with which of the following properties?
The pattern of isolines of potential for the gravitational field of the sun-mercury system is identical to the pattern of equipotential lines for a system of two electrically charged objects with opposite charges.
This is because both gravitational and electrical forces follow the inverse square law, where the force decreases as the distance between the objects increases.
In the case of opposite charges, the lines of equal potential connect the positive and negative charges, while in the case of the sun-mercury system, the lines connect the regions of space with equal gravitational potential energy.
Both systems display a similar pattern of concentric circles around the objects, with the lines becoming closer together as the objects become more massive or charged.
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10 POINTS QUESTION: Why both are models for monomers, polymers, and cross-linked polymers
Answer:
Because both monomers and polymers and cross linked polymers are mers with physically properties which is good for applycations
Explanation:
because they are good for using and not using
also, this is a 5 point question, you are not fooling anyone. thx for 5 points tho
Which body system is responsible for bringing the oxygen an organism will need to conduct cellular respiration?
Answer:
The respiratory system is responsible for bringing the oxygen an organism will need to conduct cellular respiration. The respiratory system includes the lungs and other organs involved in breathing, such as:
the trachea,bronchi,and alveoli.When we inhale, oxygen from the air enters the lungs and diffuses into the bloodstream, where it is transported to the body's cells. Inside the cells, oxygen is used in the process of cellular respiration to produce energy in the form of ATP.
Hope that helps! Good luck! :)
Three identical metallic spherical objects have individual charges of, q1 = -9.612 nC, q2 = +3.204 nC and q3 = +6.408 nC. If the three objects are brought into contact with each other at the same time and the separated, determine: a) the final net charge on q1 = __________ nC; b) the final net charge on q2 = __________ nC; c) the final net charge on q3 = __________ nC; d) the number of electrons that were removed from/added to q1 = __________ electrons were __________ q1.
Given three identical metallic spherical objects have individual charges of, q1 = -9.612 nC,
q2 = +3.204 nC,
and q3 = +6.408 nC.
If the three objects are brought into contact with each other at the same time and then separated, the final net charge on q1, q2, and q3 will be calculated as follows;
Initial total charge, Q = q1 + q2 + q3
Q= -9.612 nC + 3.204 nC + 6.408 nC
Q= -0.002 nC
The final net charge on q1, q2, and q3 is same as they are identical:
q1 + q2 + q3 = -0.002 nC
q1 = q2 = q3 = -0.002 nC/3
q1 = -0.0006667 nC
Therefore, the final net charge on q1, q2, and q3 is -0.0006667 nC.The charge on q1 before and after is -9.612 nC and -0.0006667 nC respectively. The difference is the number of electrons that were removed from/added to q1. The number of electrons can be calculated as follows;
Charge on an electron,
e = 1.6 ×\(10^{-19\) C
Total number of electrons removed from
q1 = [(final charge on q1) - (initial charge on q1)] / e
q1 = [-0.0006667 - (-9.612)] / 1.6 × \(10^{-19\)
q1 = 6.0075 × 1013
The number of electrons removed from q1 is 6.0075 × 1013, and electrons were removed from q1. Thus, option d is,
"The number of electrons that were removed from q1 = 6.0075 × 1013 electrons were removed from q1."
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Which property of a transverse wave stays the same even as the wave's
energy and other properties change?
Wavelength
Frequency
Rest position
Amplitude
ent
1 of 8 QUESTIONS
SUBMIT
The property of a transverse wave that stays the same even as the wave's energy and other properties change is the wavelength.
The correct option to the given question is option a.
The wavelength is the distance between two successive points of the wave that are in phase. As the wave's energy and amplitude change, the distance between two successive points of the wave that are in phase remains the same.
This is because wavelength is determined by the frequency of the wave and the speed of propagation. The frequency of the wave is the number of cycles of the wave that occur in one second, while the speed of propagation is the rate at which the wave travels through a medium.
If the frequency of the wave and the speed of propagation remain the same, then the wavelength will also remain the same even as the wave's energy and other properties change. This property is known as the characteristic of the wave.The amplitude is the maximum displacement of a point on the wave from its rest position. The frequency is the number of cycles of the wave that occur in one second. The rest position is the position of the medium when it is not disturbed.
Hence, wavelength of a transverse wave remains same even as the wave's energy and other properties change.
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(5) Use the result for the energy levels of the hydrogen atom to calculate the wavelengths of the first 5 lines of the Balmer series. In what part of the electromagnetic spectrum do these lines fall?
The Balmer series is a set of emission spectral lines of the hydrogen atom that results from electron transitions from the n = 3 state to the n = 2 state.
The wavelengths of the first five lines of the Balmer series can be calculated using the Rydberg formula.
The formula can be written as:
1/λ = R(1/4 − 1/n²)
where,
R is the Rydberg constant,
n is the principal quantum number of the higher energy level,
λ is the wavelength of the emitted photon.
The first five lines of the Balmer series have n values of 3, 4, 5, 6, and 7.
Plugging these values into the Rydberg formula gives the following wavelengths:
Line 1 (n = 3 → 2): λ = 656.3 nm
Line 2 (n = 4 → 2): λ = 486.1 nm
Line 3 (n = 5 → 2): λ = 434.0 nm
Line 4 (n = 6 → 2): λ = 410.2 nm
Line 5 (n = 7 → 2): λ = 397.0 nm
The wavelengths of the first five lines of the Balmer series are in the visible part of the electromagnetic spectrum.
The wavelengths range from 656.3 nm (red) to 397.0 nm (violet).
Therefore, the first five lines of the Balmer series are part of the visible spectrum.
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Please select the word from the list that best fits the definition
A place where people interact with one another regularly on the Internet.
social structure
group
primary group
secondary group
formal organization
out-group
e-community
Answer:
E-Community
Explanation:
edge 2021
Answer:
The answer would be option E- community
Explanation:
Hope this helped :)
edg 2022
Distance is best described as
Please help!!!!
Answer:
How much an object has moved
A ball is thrown from a housetop with a horizontal velocity of 6.5 m/s. What is its horizontal velocity 0.5 s later?
Answer:
6.5 m/s
Explanation:
Horizontally the ball does not experience an acceleration
Therefore the velocity won't change
6.5 m/s
You lift a 44 N box from the floor and place it on a shelf that is 1.5 m above the ground . How much work did you use in lifting the box ?
Answer:
W = 66 J
Explanation:
Given that,
The weight of the box, W = 44 N
It is placed on a shelf that is 1.5 m above the ground.
We need to find the work done in lifting the box.
We know that,
Work done, W = Fd
So,
W = 44 N × 1.5 m
= 66 J
So, the required work done is equal to 66 J.
2. A girl pushes her little brother on his sled with a force of 300 N for 750 m.
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
If an area has limited types of wildlife, this means that it has __________. A. animals that are about to go extinct B. animals that have adapted well to their environments C. a wide variety of animals D. very few varieties of animals Please select the best answer from the choices provided A B C D
Answer:
It is d
Explanation:
Answer:
D !!!!!
Explanation:
saturn orbits the sun at more than 50% of the speed of Mars 
true or false????
Answer:
(TRUE) Mars seems to pass the fastest, Jupiter next, and Saturn the slowest. But all exhibit that puzzling quirk--near the point of their celestial course precisely opposite the Sun ("opposition"), their action amongst the stars briefly turns around.
Explanation:
Mars: 24.077 km/s (53,853 miles per
hour), or a period of about 686.93 days.
Answer:is true
Explanation:
12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.
Answer:
i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii) Find the value of k first: F = 400 + k(15^2) k = 28/9 F = 400 +(28/9)(30^2) = 320
Explanation:
+ 9. What force (in units of Newtons) is needed to give a 3.5 m/s" acceleration to a 1200 kg car?
Answer:
4200 Newtons
Explanation:
Force = mass x acceleration
1200 x 3.5 = 4200
Hi me and my friends are making a project about 'Pros and cons of different subjects' and i was wondering if yall could write cons about different subjects like physics,chemistry,history etc because we already wrote about pros and we really need help
Answer:
if A={5,10,15}and B={1,3,15} subsets of u ={1,3,5,10,15,20} find a (AUB)how should you hold a handgun for maximum accuracy? high on the grip with two hands high on the grip with one hand low on the grip with two hands low on the grip with one hand
Hold the pistol high mostly on grip to ensure that such recoil is sent straight back to the arm and hands. This enables more accurate shooting and better repeat shots. When two hands are available, use them.
What does a gun's recoil mean?Simply said, recoil is the gun's response to the expression of energy that is produced in the barrel and released from the muzzle. The hammer, which is located inside the gun's receiver, depresses your firing pin only when trigger is squeezed with enough force and pop the fuse on the round's end.
Recoil movement: what is it?The recoil is a backward motion that typically results from a force or contact. A gun will recoil when it moves rearward due to momentum. Mom might retreat from shock rather than momentum after hearing about your go to the shooting range.
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The weight of a dum bell is 500 n. It is lifted over a bodybuilder’s head at a distance of 0.7 meters. What is the work done by the bodybuilder on the dum bell?
350 J
714.2 J
500 J
1.4 x 10-3 J
Explanation:
W = F * d <==== ( Force * distance)
500 N * .7 m = 350 J
o
Question 4
1 pts
You jog around 180m track 4 times in 30 minutes. What is your average speed in
m/s? (Hint: Convert min to seconds first)
O 0.4 m/s
O 6 m/s
O 24 m/s
O O m/s
Answer:
0.4m/s
Explanation:
It is given speed so it is scalar.
distance covered in 1 round = 180m
therefore, distance covered in 4 rounds = 180*4 = 720m
time = 30 mins = 30*60 = 1800 seconds
average speed = total distance/total time taken
= 720/1800
= 0.4m/s
What are the eight planets of the solar system
Answer:
Mercury
Venus
Earth
Mars
Jupiter
Saturn
Uranus
Neptune
Answer:
Solar system planets: Order of the 8 planets:-
Mercury.Venus.Earth.Mars.Jupiter.Saturn.Uranus.Neptune.What is the current in a 160V circuit if the resistance is 2Ω?
Answer:
80 amperes
Explanation:
Current = Voltage/Resistance
160/2 = 80
a 45.0 mh inductor has a reactance of 1.30 k a0 what is its operating frequency? (b what is the capacitance of a capacitor with the same reactance at that frequency
The operating frequency is approximately 59.49 Hz, and the capacitance of a capacitor with the same reactance at that frequency is approximately 2.696 µF.
To find the operating frequency, we can use the formula for inductive reactance: XL = 2πfL, where XL is the reactance, f is the frequency, and L is the inductance.
Rearrange the formula to solve for frequency: f = XL / (2πL).
Using the given values, f = (1.30 * 10^3) / (2π * 45.0 * 10^-3) ≈ 59.49 Hz.
For part b, we use the formula for capacitive reactance: XC = 1 / (2πfC), where XC is the reactance, f is the frequency, and C is the capacitance.
Rearrange the formula to solve for capacitance: C = 1 / (2πfXC).
Using the calculated frequency and given reactance, C = 1 / (2π * 59.49 * 1.30 * 10^3) ≈ 2.696 * 10^-6 F, or approximately 2.696 µF.
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If air resistance is negligible, a falling object can be considered
Answer:
Explanation:
freely falling object
par 1/2
In a volcanic eruption, 3.8 km of mountain
with a density of 1739 kg/m” was lifted an
average height of 403 m.
The acceleration of gravity is 9.81 m/s2.
How much energy was released in this eruption?
Answer in units of J.
part 2/2
The energy released by thermonuclear bombs is measured in megatons of TNT, where 1 megaton of sqrt(T) is 4.2 * 10 ^ 15 * J Convert this energy release into megatons of TNT. Answer in units of Mton TNT.
part 1
mass = ρ x V
mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg
PE (potential energy)= mgh
PE = 6608.2 kg x 9.81 x 403
PE = 2.61 x 10⁷ J
part 2
megaton of TNT (Mt) =4.2 x 10¹⁵ J
convert PE to Mt:
2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt
If a ball is given a push so that it has an initial velocity of 6 m/s down a certain inclined plane, then the distance it has rolled after t seconds is given by the following equation s(t) = 6t + 5t2 (a) Find the velocity after 2 seconds. m/s (b) How long does it take for the velocity to reach 40 m/s? (Round your answer to two decimal places.)
The velocity after 2 seconds is 26 m/s. It takes 11.50 seconds to reach a velocity of 40m/s.
Given the equation s(t) = 6t + 5t²
Let's find the velocity after 2 seconds.
(a) Velocity = (ds)/(dt)
Differentiating s(t) with respect to t, we get; ds(t) / dt = 6 + 10t
At t = 2,ds(t) / dt = 6 + 10t = 6 + 10(2) = 26m/s
Therefore, the velocity after 2 seconds is 26 m/s.
(b) We are to find how long it takes for the velocity to reach 40m/s. We know that the initial velocity of the ball, u = 6m/s. Acceleration = gsinθ = 9.81 x sin (angle of inclination) = 9.81 x 0.3 = 2.943 m/s²From the first equation of motion, v = u + at
We know v = 40m/s, u = 6m/s, a = 2.943m/s² and t is what we are to find, hence the equation becomes;40 = 6 + 2.943(t)t = (40 - 6) / 2.943t = 11.50s
Therefore, it takes 11.50 seconds to reach a velocity of 40m/s.
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