Ensure that the graph has a title that accurately describes the presentation's subject. The measuring unit should be mentioned in the graph. The right scale must be chosen in order to accurately represent the facts.
What are the graphical representation of vector?Similar-direction vectors are referred to as like vectors. Contrarily, vectors that point in the opposite direction from one another are said to be unlike vectors.
Therefore, arrows can be used to graphically represent vectors.The arrow's length provides a measure of the vector's magnitude.The vector's direction is indicated by the direction of the arrow.
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Two cars collide and then stick together in an accident.
Car A has a mass of 1000. kg and is moving 5.00 m/s east, and
car B has a mass of 2000. kg and is moving 2.00 m/s west.
What is the speed of the cars after the collision?
b. 1.53m/s
c. 2.43m/s
a. 0.33m/s
d. 3.93m/s
What’s the answer
Answer:
Option A. 0.33 m/s
Explanation:
From the question given above, the following data were obtained:
Mass of A (mₐ) = 1000 kg
Velocity of A (uₐ) = 5 m/s
Mass of B (m₆) = 2000 kg
Velocity of B (u₆) = 2 m/s
Velocity (v) after collision =?
mₐuₐ – m₆u₆ = v (mₐ + m₆)
(1000 × 5) – (2000 × 2) = v (1000 + 2000)
5000 – 4000 = 3000v
1000 = 3000v
Divide both side by 3000
v = 1000 / 3000
v = 0.33 m/s
Thus, the speed of the cars after collision is 0.33 m/s
The speed of the cars after the collision is 0.33 m/s.
The right option is a. 0.33 m/s
To calculate the speed of the cars after the collision, we use the formula below.
Formula:
mu+m'u' = V(m+m')............... Equation 1Where:
m = mass of car Am' = mass of car Bu = initial velocity of car Au' = initial velocity of car BV = Speed of the cars after the collision.make V the subject of the equation
V = (mu+m'u')/(m+m').............. Equation 2From the question,
Given:
m = 1000 kgm' = 2000 kgu = 5 m/s eastu' = -2 m/s westSubstitute these values into equation 2
V = [(1000×5)+(2000×(-2))]/(1000+2000)V = (5000-4000)/(3000)V = 1000/3000V = 0.33 m/sHence, The speed of the cars after the collision is 0.33 m/s.
The right option is a. 0.33 m/s
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In the “Little Prince,” the Prince visits a small asteroid called B612. If the asteroid has a radius of 20.0 m and a mass of 1.00 x 10^4kg, what is the acceleration due to gravity on the asteroid (G=6.67x10-11N m2/kg2)?
The acceleration due to gravity on the asteroid, given that it has a mass of 1.00×10⁴ kg and a radius of 20.0 m is 1.67×10¯⁹ m/s²
How do I determine the acceleration due to gravity?Acceleration due to gravity of planets can be obtained by using the following formula:
g = GM / R²
Where
g is acceleration due to gravity on the planet M is the mass of the planetG is the gravitational constantR is the radius of the planetNow, we shall apply the above formula, to determine the acceleration due to gravity on the asteroid. Details below
Mass of asteroid (M) = 1.00×10⁴ KgRadius (R) = 20.0 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Acceleration due to gravity (g) =?g = GM / R²
g = (6.67×10¯¹¹ × 1.00×10⁴) / (20)²
g = 6.67×10¯⁷ / 400
g = 1.67×10¯⁹ m/s²
Thus, we can conclude that the acceleration due to gravity on the asteroid is 1.67×10¯⁹ m/s²
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The most common type of mirage is an illusion that light from faraway objects seem to be reflected by a pool of water that is not really there. Mirages are generally observed in deserts, when there is a hot layer of air near the ground. The index of refraction of air is lower at higher temperature. What physical phenomena explains how mirages are formed? Give a brief explanation of the phenomena as your LPE.
Answer:
Mirage is an optical illusion due to the refraction of light as it travels through different layers of air at different temperature.
Explanation:
On a clear hot afternoon, the sun heats up the ground, and the ground heats up the air immediately above it. The result is that the air directly above the ground is hotter than the air above it, leaving the air layers with different refractive indies. Since refractive index decreases with increase in temperature, the air immediately above the ground bends the light that travels through it from the sky, directly into our eyes. The image seen is perceived to be reflected from the ground, but in an actual sense is a direct image of the sky, giving one the impression of seeing a pool of water on the ground.
A book on a 2-meter high shelf has a mass of 0.4 kg. What is its potential energy?
Answer:
how can we get the best out with a little of my life and I think the most common reason I would n I have been having this problem for years is done in my life as the other people
The Earth wire only carries a current if there is a _____ in the
circuit. What one word completes the sentence?
Answer:
Fault
Explanation:
it only carries a current if there is a fault.
What is a Surveyor's Tape Measure used to Measure?
Given:
A surveyor's tape
To find:
The quantity a Surveyor's Tape used to Measure for
Explanation:
A surveyor's tape is used to measure distance or size. It is like a long flexible ruler.
Hence, the answer is length/distance/size.
7. A rock of mass 5 kg is pushed over the edge of a cliff which is 200 m high. a) Ignore air resistance and calculate the speed of the rock at the bottom of the cliff. In reality, air resistance cannot be ignored. The rock eventually reaches terminal velocity of 30 m.s-¹.
b) Calculate the kinetic energy of the rock at the bottom of the cliff.
c) Calculate the work done by air resistance.
d) Calculate the average force exerted by the air on the rock.
Speed of the rock at the bottom of the cliff is 44.3 m/s.
Kinetic energy of the rock at the bottom of the cliff is 4915 J.
Work done by air resistance is -2250 J
Average force exerted by the air on the rock is 11.25 N.
How to determine kinetic energy and speed?a) The speed of the rock at the bottom of the cliff can be calculated using the equation:
v = √(2gh)
where v = final velocity, g = acceleration due to gravity (9.81 m/s²), and h = height of the cliff (200 m).
Plugging in the values:
v = √(2 x 9.81 x 200) = 44.3 m/s
Therefore, the speed of the rock at the bottom of the cliff is 44.3 m/s.
b) The kinetic energy of the rock at the bottom of the cliff can be calculated using the equation:
KE = (1/2)mv²
where KE = kinetic energy, m = mass of the rock (5 kg), and v = velocity (44.3 m/s).
Plugging in the values:
KE = (1/2) x 5 x (44.3)² = 4915 J
Therefore, the kinetic energy of the rock at the bottom of the cliff is 4915 J.
c) The work done by air resistance can be calculated using the work-energy principle:
Work done by air resistance = KE_initial - KE_final
where KE_initial = initial kinetic energy of the rock, and KE_final = final kinetic energy of the rock (at terminal velocity).
Since the rock was initially at rest, its initial kinetic energy is zero. At terminal velocity, the kinetic energy of the rock is:
KE_final = (1/2)mv_terminal²
where m = mass of the rock (5 kg), and v_terminal = terminal velocity (30 m/s).
Plugging in the values:
KE_final = (1/2) x 5 x (30)² = 2250 J
Therefore, the work done by air resistance is:
Work done by air resistance = 0 - 2250 = -2250 J
The negative sign indicates that the work done by air resistance is in the opposite direction to the motion of the rock.
d) The average force exerted by the air on the rock can be calculated using the equation:
Work done by air resistance = Force x Distance
where Force = average force exerted by air on the rock, and Distance = distance travelled by the rock.
Rearrange the equation to solve for Force:
Force = Work done by air resistance / Distance
Plugging in the values:
Force = -2250 / 200 = -11.25 N
Therefore, the average force exerted by the air on the rock is 11.25 N. The negative sign indicates that the force is in the opposite direction to the motion of the rock.
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To understand the basic principles underlying interference.
One of the most important properties of waves is the principle of superposition. The principle of superposition for waves states that when two waves occupy the same point, their effect on the medium adds algebraically. So, if two waves would individually have the effect "+1" on a specific point in the medium, then when they are both at that point the effect on the medium is "+2." If a third wave with effect "-2" happens also to be at that point, then the total effect on the medium is zero. This idea of waves adding their effects, or canceling each other's effects, is the source of interference.
Part C
In talking about interference, particularly with light, you will most likely speak in terms of phase differences, as well as wavelength differences. In the mathematical description of a sine wave, the phase corresponds to the argument of the sine function. For example, in the function y=Asin(kx), the value of kx at a particular point is the phase of the wave at that point. Recall that in radians a full cycle (or a full circle) corresponds to 2? radians. How many radians would the shift of half a wavelength from the previous part correspond to?
Express your answer in terms of ?.
Shift of half a wavelength from the previous part correspond to π radian.
What is the principle of interference?Interference is a phenomenon in which two waves combine by adding displacement together at every single point in the space and time, to form a resultant wave of greater, lower, or same amplitude.
The superposition principle explains that when two or more waves overlap in space, then the resultant disturbance is equal to the algebraic sum of individual disturbances
Given, Wavelength= λ
We have to find the phase difference when wavelength is half of the initial wavelength.
So, the path difference= Δx = λ/2
As, phase difference= 2π/λ * Δx
So, phase difference= 2π/λ * λ/2
Thus, phase difference= π radian
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does the mass of a parachute affect terminal velocity?
Answer:
The greater weight increases the terminal velocity by acting as an extra force against gravity and air resistance.
How does increasing the amount of charge on an object affect the electric force it exerts on another charged object?
Answer: The electric force increases because the amount of charge has a direct relationship to the force.
Explanation:
A 2.6 kg hollow sphere (radius = 10 cm) is realeased from rest at the top of a ramp and allowed to roll without slipping. The ramp is 1.2 m high and 5 m long. At the bottom of the ramp, find: Part A - The total kinetic energy of the sphere.
The total kinetic energy of the sphere when it is moving is equal to the potential energy when it is at rest at a height of 1.2 m. Then, the kinetic energy of the sphere is 30.57 J.
What is kinetic energy ?The kinetic energy of an object is the energy generated by virtue of its motion. The energy which is stored in an object when it is at rest is called its potential energy.
When the object starts to move, its potential energy starts to convert to kinetic energy.
Here, when the sphere, starts rolls down, its potential energy becomes kinetic energy.
thus, 1/2 mv² = mgh
given that mass of the sphere m = 2.6 kg
height of the ramp h = 1.2 m
g = 9.8 m/s²
Then, k = mgh before it reaches the ground.
mgh = 2.6 kg × 1.2 m × 9.8 m/s²
= 30.57 J.
Therefore, the kinetic energy of the sphere at the bottom of the ramp will be 30.57 J.
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A light ray strikes the surface of crown glass (n = 1.520), at a 25° angle with respect to the normal from air (n = 1.000293), and leaves the glass, returning to the air. Determine the angle at which the light refracts when it moves from air into the crown glass.
The angle at which the light refracts when it moves from air into the crown glass is 23.3°.
Refraction is the bending of light as it passes through a medium with a different density. It occurs due to a change in the speed of light as it enters a different medium.
We can use Snell's law to solve this problem, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the refractive indices of the two media:
n1 sin θ1 = n2 sin θ2
where n1 and n2 are the refractive indices of the initial and final media, and θ1 and θ2 are the angles of incidence and refraction, respectively.
From the problem, we have:
n1 = 1.000293 (air)
n2 = 1.520 (crown glass)
θ1 = 25°
We can rearrange Snell's law to solve for θ2:
sin θ2 = (n1/n2) sin θ1
sin θ2 = (1.000293/1.520) sin 25°
sin θ2 = 0.385
Taking the inverse sine of both sides, we get:
θ2 = 23.3°
Therefore, the angle at which the light refracts when it moves from air into the crown glass is 23.3°.
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Which statement best describes the circular flow model?
In 1926 Babe Ruth hit a home run that was estimated to have landed 180. meters from home plate and to have reached a height of 21.3 meters. What was the initial velocity of the ball?
Answer:
v = 47.85 m / s , θ = 64.7º
Explanation:
This is a missile throwing exercise.
Let's find the speed to reach the maximum height, at this point the vertical speed is zero
\(v_{y}^{2}\) = v_{oy}^{2} - 2 g y
0 = v_{oy}^{2} - 2gy
v_{oy} = √2gy
let's calculate
v_{oy} = √ (2 9.8 21.3)
v_{oy} = 20.43 m / s
now we can calculate the time it takes to get to this point
vy = v_{oy} - g t
t = v_{oy} / g
t = 20.43 / 9.8
t = 2.08 s
in projectile launching, the time it takes for the body to rise is the same as the time it takes to go down, so the total launch time is
\(t_{v}\) = 2 t
t_{v} = 2 2.08 = 4.16 s
let's use the horizontal throw ratio
x = v₀ₓ t_{v}
v₀ₓ = x / t_{v}
v₀ₓ = 180 / 4.16
v₀ₓ = 43.27 m / s
initial velocity is
v = √ (v₀ₓ² + v_{oy}^{2})
v = √ (20.43² + 43.27²)
v = 47.85 m / s
with an angle of
tan θ = I go / vox
θ = tan⁻¹ (43.27 / 20.43)
θ = 64.7º
Thallium-201 is a radioisotope used in brain scans. If the recommended dose is 3.0 mCi and a vial contains 60. mCi in 50. mL , how many milliliters should be injected?
2.5 mL of Thallium-201 should be injected to administer a recommended dose of 3.0 mCi.
Thallium-201 is a radioisotope that is used in brain scans to detect brain cancer. It is used in nuclear medicine as a radiopharmaceutical. The recommended dose for Thallium-201 is 3.0 mCi. If a vial of Thallium-201 contains 60. mCi in 50. mL, we can determine the number of milliliters that should be injected by using proportionality.A proportion can be used to compare two ratios and solve for an unknown value. For example, if x is the unknown value we are trying to solve for and a/b and c/d are two ratios that are equal, we can write a proportion:
a/b = c/d.
Cross-multiplying gives us the equation
ad = bc.
This formula can be used to solve for the unknown value x. For this problem, we can use a proportion to solve for the number of milliliters that should be injected. Let x be the number of milliliters that should be injected. Then we have the following ratio:
3.0 mCi / x mL = 60. mCi / 50. mL
To solve for x, we can cross-multiply:
3.0 mCi * 50. mL = 60. mCi * x mL150. mCi mL = 60. mCi x mCx = (150. mCi mL) / (60. mCi) x = 2.5 mL
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A person with a weight of 190 N sits on a box with a weight of 20 N, what is the normal force on the box?
The normal force on the box is 210 N.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Normal force on the box = total Weight of box and person = 210 N.
The normal force on the box is 210 N.
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Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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019 10.0 points
An engineer in a locomotive sees a car stuck
on the track at a railroad crossing in front of
the train. When the engineer first sees the
car, the locomotive is 100 m from the crossing
and its speed is 12 m/s.
If the engineer's reaction time is 0.55 s,
what should be the magnitude of the mini-
mum deceleration to avoid an accident?
Answer in units of m/s².
Answer:
Explanation:
Distance remaining after reaction time
s = s₀ - v₀t
s = 100 - 12(0.55) = 93.4 m
v² = u² + 2as
a = (v² - u²)/2s
a = (0² - 12²) / 2(93.4) = - 0.770877944...
|a| = 0.77 m/s²
Why is this event important to include in the biography?
It shows that Frida Kahlo got whatever she asked from her parents.
It shows that Frida Kahlo was vain and liked looking in the mirror.
It shows that Frida Kahlo liked to share things with her father.
It shows that Frida Kahlo used art to cope with her pain.
Answer:
D: It shows that Frida Kahlo used art to cope with her pain.
Explanation:
Within the text given it shows her emotions being lonely, immobile and in pain. But it all shows her asking her father for art which states that art is her sort of relief and happy place.
Answer:
It shows that Frida Kahlo used art to cope with her pain.
Explanation:
A 100-turn coil has a radius of 7.50 cm and a resistance of 50.0 W. At what rate must a perpendicular magnetic field change to produce a current of 5.00 A in the coil
Answer:
dB / dt = -141.47 T / s
Explanation:
For this exercise let's use Faraday's law to calculate the induced electromotive force
E = - N dФ / dt
the magnetic flux is
Ф = B. A
in this case the direction of the field and the normal to area are parallel so the scalar product is reduced to the algebraic product
Ф = B A
we substitute
E = - N A dB / dt
the area of the loop is
A = π r²
we substitute
E = - N π r² dB / dt
in the exercise indicate that the resistance of the coil is R = 50.0 Ω,
E = i R
we substitute
i R = -N π r² dB / dt
dB / dT = - i R / N π r²
let's calculate
dB / dt = - 5.00 50.0 / (100 π 0.075²)
dB / dt = -141.47 T / s
Particles q1 = -53.0 uc, q2 = +105 uc, and q3 = -88.0 uc are in a line. Particles qı and q2 are separated by 0.50 m and particles q2 and q3 are separated by 0.95 m. What is the net force on particle q3?
The net force on particle q3 is 112.11 N
What is electrostatic force?The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.
F = kq₁q₂/r²
where k = 9 x 10⁹ N.m²/C²
The Particles q1 = -53.0 uc, q2 = +105 uc, and q3 = -88.0 uc are in a line. Particles qı and q2 are separated by 0.50 m and particles q2 and q3 are separated by 0.95 m.
The net force F3 = F13 + F23
Substitute the values, we get the force F on q3 as
F3 = 9 x 10⁹x53.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.5+0.95)² + 9 x 10⁹x105.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.95)²
F3 = 112.11 N
Thus, the magnitude of the force on charge q3 is 112.11 N.
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If 1.34 ✕ 1020 electrons move through a pocket calculator during a full day's operation, how many coulombs of charge moved through it?
Given :
Number of operations move through a pocket calculator during a full day's operation , \(n=1.34 \times 10^{20}\) .
To Find :
How many coulombs of charge moved through it .
Solution :
We know , charge in one electron is :
\(e^-=-1.6\times 10^{-19}\ coulombs\)
So , charge on n electron is :
\(C=e^-\times n\\C=-1.6\times 10^{-19}\times 1.34\times 10^{20} \ C\\C=-21.44\ C\)
Therefore , -21.44 coulombs of charge is moved through it .
Hence , this is the required solution .
A 50gram bracelet is suspected of not being pure gold. It is dropped into a glass of water and 4 cm3of water overflows. Is the bracelet pure gold? How do you know?
Since, density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.
To know if the bracelet is pure gold, we calculate the density of the bracelet and compare it to the density of pure gold (19.3 g/cm³).
That is, for the bracelet to pure gold,
Density of bracelet ≈ 19.3 g/cm³
What is Density?Density can be defined as the ratio of the mass and the volume of a substance.
The formula of Density is give as
D = m/v................... Equation 1⇒ Where:
D = Density of the braceletm = mass of the braceletv = volume of the braceletFrom the question,
⇒ Given:
m = 50 gv = 4 cm³ (an object displace an amount of water equal to it's own volume)⇒ Substitute these values into equation 1
D = 50/4D = 12.5 g/cm³Hence, since the density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.
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9. When air or water is cools it...
A.) Sinks
B.) Becomes less dense
Answer:
when air or water cools it sinks
Question 9 (6 points)
A laser beam is aimed through a circular aperture of diameter 1 mm.
a. If the laser beam is red with a wavelength of 632.8 nm, what is the angle from the center of the Airy disk to the first dark ring? (2 points)
b. If the screen you are projecting the Airy disk onto is 2 m from the aperture, what is the distance between the center of the disk and the first dark ring? (2 points)
c. How does the distance between the center of the disk and the first dark ring change as you move the screen closer to the aperture? (1 point)
d. You change to a green laser with a wavelength of 532 nm. How does this affect the separation of the rings in the Airy disk? (1 point)
Answer: a. The angle from the center of the Airy disk to the first dark ring can be calculated using the formula:
θ = 1.22 λ/D
where θ is the angle in radians, λ is the wavelength of the laser beam, and D is the diameter of the circular aperture. Substituting the values given, we get:
θ = 1.22 (632.8 x 10^-9 m) / (1 x 10^-3 m) = 7.89 x 10^-4 radians
b. The distance between the center of the disk and the first dark ring can be calculated using the formula:
r = 1.22 λ L / D
where r is the distance in meters, λ is the wavelength of the laser beam, L is the distance between the aperture and the screen, and D is the diameter of the circular aperture. Substituting the values given, we get:
r = 1.22 (632.8 x 10^-9 m) (2 m) / (1 x 10^-3 m) = 1.59 x 10^-3 m
c. As the screen is moved closer to the aperture, the distance between the center of the disk and the first dark ring will decrease, since the formula for r includes the distance L as a factor.
d. The separation of the rings in the Airy disk depends on the wavelength of the laser beam, according to the formula:
Δr = λL / D
where Δr is the separation between adjacent bright fringes, λ is the wavelength of the laser beam, L is the distance between the aperture and the screen, and D is the diameter of the circular aperture. Since the green laser has a shorter wavelength (532 nm) than the red laser (632.8 nm), the separation between the rings in the Airy disk will be smaller for the green laser. Specifically, we have:
Δr_green = (532 x 10^-9 m) (2 m) / (1 x 10^-3 m) = 1.06 x 10^-3 m
Δr_red = (632.8 x 10^-9 m) (2 m) / (1 x 10^-3 m) = 1.27 x 10^-3 m
So the separation between the rings in the Airy disk is smaller for the green laser.
Explanation: :)
what exercises most beneficial for your overall health
Answer:
Endurance, or aerobic
Strength, or resistance training
Balance
Flexibility
Explanation:
Answer:
Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).
Calculate the density of a marble at 16 g and has a volume of 8cm 3
Answer:
16g/8cm3 = 2g/cm3 or 2x106g/m3
Explanation:
Hope it helps
Please Give me Brainliest
Answer:
16g/8cm3 = 2g/cm3 or 2x106g/m3
6. A spring is originally 1.5 m long. It is stretched so that it is 1.8 m long. The spring constant is 50 N/m.
Find the potential energy stored in the spring.
Answer:
PE = 1/2 K X^2
K = 50 N/m
X = .3 m
PE = 1/2 * 50 * .3^2 = 2.25 Joules
B (B=26.5)
56.0%
A (A = 44.0)
28.0°
C(C=31.0)
< 1 of 1 >
Part A
Given the vectors A and B shown in the figure ((Figure 1)), determine the magnitude of B-A
Express your answer using three significant figures.
195] ΑΣΦ
|B-A =
Determine the magnitude of B-A is 53.68
1.4
Magnitude is a term used to describe size or distance. We can relate the magnitude of the movement to the size and movement speed of the object. The magnitude of a thing or an amount is its size. A car moves at a faster pace than a motorcycle, just in terms of speed.
Magnitude is the relative size of an object (mathematics). The mathematical term for a vector's length or size is the norm. By using the symbol |v|, the magnitude of a vector formula can be utilized to determine the length of a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point.
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A highly optimized power plant is designed for burning natural gas at 1100 degrees Celsius for its gas turbines which will be combined with a steam power plant for producing steam at 700 degrees Celsius using the combustion products exhausted from the gas turbine. The steam power plant will use cooling towers (i.e. the ambient air at 27 degrees Celsius) for its condensing units. The efficiency of the plant is claimed to be 78%. Evaluate this claim and comment.
The claimed efficiency of the power plant is 78%, which is significantly higher than the theoretical maximum efficiency of 29.2%. Further information is required to evaluate the claim.
The greatest conceivable proficiency of the consolidated cycle power plant can be determined involving the Carnot productivity recipe as follows:
η_Carnot = (1373 K - 973 K)/1373 K = 29.2%
This implies that the hypothetical greatest proficiency of the power plant is 29.2%.
The guaranteed proficiency of the power plant is 78%. This is fundamentally higher than the hypothetical most extreme proficiency of 29.2%, which recommends that the case isn't precise. There might be different elements that are adding to the guaranteed effectiveness, like the utilization of further developed innovation, yet minus any additional data, assessing the claim is troublesome.
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