Answer:
13h
Step-by-step explanation:
Answer:
B. E = 7.5h
Step-by-step explanation:
Did the test and got it correct
Perform the operation and simplify
Answer:
\(\frac{(x-2)(x+4)}{x+2}\)
Step-by-step explanation:
\(\frac{(x+4)^2}{x+2} :\frac{(x+2)(x+4)}{(x+2)(x-2)} =\frac{(x+4)^2(x+2)(x-2)}{(x+2)(x+2)(x+4)}=\frac{(x-2)(x+4)}{x+2} .\)
A jar has marble ms in these three colors only: 7 green, 10 blue, 3 red.
What is the probability of randomly choosing a green marble, after choosing (and keeping) a red marble?
Answer with a percentage rounded to the nearest tenth.
The probability of randomly choosing a green marble after you have chosen red is 4.4%
What is probability?
Simply put, probability measures how probable something is to occur. We can discuss the probabilities of various outcomes, or how likely they are, whenever we are unsure of how an event will turn out. Statistics is the study of events subject to probability.
Given
A jar has 20 marbles: 3 green, 12 blue, 5 red.
Probability;
In probability theory, an event is a set of outcomes of an experiment or a subset of the sample space.
The total number of marbles = 20
The number of green marbles= 3
The number of blue marbles = 12
The number of red marbles = 5
The probability of choosing a red marble = Number of red marbles / Total number of marbles
= 5/20
The probability of choosing a green marble is = Number of green marbles / New total number of marbles
= 3/19
Therefore,
The probability of randomly choosing a green marble after you have chosen red is;
= 5/20 * 3/19
= 3/68
percentage = 3/68 * 100 = 4.4%
Hence, the probability of randomly choosing a green marble after you have chosen red is 4.4%
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30. When the polynomial f(x) = (p-1)x³ + px² + qx +r, where p, q and r are constants, is divided by (x + 2) and (x - 1), the remainders are - 5 and 4 respectively. If (x + 1) is a factor of f(x), find the values of p, q and r. Hence, factorize f(x) completely.
Answer:
Step-by-step explanation:
Using the remainder theorem we get:
\(f(-2)=-5\), \(f(1)=4\), and \(f(-1)=0\)
So we get
\(f(-2)=(-8)(p-1)+4p-2q+r=-5\)
\(-8p+8+4p-2q+r=-5\)
\(-4p-2q+r=-13\) \((a)\)
\(f(1)=(p-1)+p+q+r=4\)
\(2p+q+r=5\) \((b)\)
\(f(-1)=-(p-1)+p-q+r=0\)
\(-q+r=-1\) \((c)\)
We need to solve (a), (b) and (c) simultaneously to find p,q, and r.
from \((c)\) \(r=q-1\). Sub this into (a) and (b):
\(-4p-2q+(q-1)=-13 \rightarrow -4p-q=-12\) \((d)\)
\(2p+q+(q-1)=5 \rightarrow q=3-p\) \((e)\)
Sub (e) into (d) we get
\(-4p-(3-p)=-12 \rightarrow p=3\)
Sub \(p=3\) into \((e) \rightarrow q=0\)
Sub \(p=3,q=0\) into \((c) \rightarrow r=-1\)
SOLUTION: \(p=3,q=0,r=-1\)
So \(f(x)=2x^3+3x^2-1\)
by dividing (x+1) into f(x) we get (I am not showing working for this division)
\(f(x)=(x+1)(2x^2+x-1)\)
\(\rightarrow f(x)=(x+1)(2x-1)(x+1)\)
The sum of the square of a positive number and the square of 3 or more than the numbers is 17. What is the number
Answer:
1
Step-by-step explanation:
Let x represent the number. The given relation is ...
x² +(x+3)² = 17
2x² +6x +9 = 17 . . . . simplify
x² +3x -4 = 0 . . . . . . subtract 17 and divide by 2
(x +4)(x -1) = 0 . . . . . factor
The solutions make these factors zero: -4 and +1. The positive solution is 1.
The number is 1.
what is 2(9x + 4y^2)^5 pls helppp
Answer: Are you even still there?
Step-by-step explanation: You asked this question about an hour ago. You probably don't need help anymore. Thankyou!
Please help me with the question below
Answer:
She's 12 years old! i hope this helps you!
Step-by-step explanation:
ordered pairs satisfy the equation 3y−9x=9
Answer:
9
Step-by-step explanation:
3 (6)-9 (1)=9
18-9=9
i think that is the answer
what is .09 as a fraction?
Answer:
9/100
Step-by-step explanation:
When we change .09 to a fraction, we can put the 9 over 100 because the 9 is in the hundredths place. We get 9/100. We can’t simplify it so it stays like that.
I hope this helped and please mark me as brainliest!
4. The radius of circle O is 22, and OC = 15. The diagram is not drawn to scale. What is the length of segment AB? Round the answer to the nearest tenth.
16.1
32.2
26.7
53.3
5. Circle O is shown below. The diagram is not to scale. What is the measure of angle BAC?
112 degrees
53.5 degrees
46.5 degrees
56 degrees
6. Ray AC is tangent to circle O at A. The diagram is not drawn to scale. If the measure of arc BY is 62, what is the measure of angle YAC?
31 degrees
38 degrees
59 degrees
62 degrees
If the radius of circle O is 22, and OC = 15 then length of AB is 36.86
Given that the radius of circle O is 22, and OC = 15.
We have to find the length of segment AB
OB=22, OC=12
Lets find length of CB using pythagoras theorem
CB²+CO²=OB²
CB² + 144 =484
CB² = 484-144
CB² =340
CB=18.43
AB=CB+AC
CB=AC as C is the midpoint
AB=18.43+18.43
=36.86
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6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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If f(x) = ⌊x⌋ + 1, what is f(2.6)?
Answer:
3.6
Step-by-step explanation:
To find f(2.6), you simply have to plug in 2.6 for every x in the equation. So, your new equation should be [2.6] + 1 = f(x). From there, you simply add the two together to come up with 3.6.
Answer:
3
Step-by-step explanation:
It is 3 cuz you sub in for x with 2.6 and then you add the 1 making it 3.6 and since it is floor function brackets you will round down to the nearest whole number thus making the answer 3
Simplify the expression. Write the answer in scientific notation.
(0.2 x 104) (4x10-8)
!pls pls pls!
Answer: 83.2
x
11
−
166.4
x
Step-by-step explanation: Multiply
104
by
0.2
.
20.8
x
(
4
x
10
−
8
)
Apply the distributive property.
20.8
x
(
4
x
10
)
+
20.8
x
⋅
−
8
Simplify the expression.
When Alana was born, her grandma put $1000 into a money market account that earns 9% interest each year. How much will be in the account when Alana is 21?
The amount that would be in the account when Alana is 21 is $2890
How to determine the valueWe have to know the formula for simple interest.
This is expressed as;
S.I = PRT/100
Given that the parameters of the formula are enumerated as;
SI is the simple interestP is the principal amountR is the interest rateT is the time takenFrom the information given, substitute the values, we have;
SI = 1000 × 9 × 21/100
Multiply the values,
Then, divide by the denominator, we have;
SI = $1890
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Convert 3.29 to a reduced fraction.
Answer: 329/100
Step-by-step explanation:
3 29/100 is the answer
WILL MARK BRAINLIEST!
Calculate mF in parallelogram FGDE.
Find all the values of x where the tangent line is horizontal.
f(x) = 2x^3 + 42x^2 + 270x + 11
Answer:
If I calculated correctly, the tangent line is horizontal where x ≈ -5.3 + 9.3i, and -5.3 - 9.3i
I'm somewhat concerned at having gotten complex numbers, and strongly recommend going through the steps to see if I missed anything. I checked it myself and don't see any errors.
Step-by-step explanation:
You can do this by taking the derivative of the function and solving for zero:
f(x) = 2x³ + 32x² + 220x + 11
f'(x) = 6x² + 64x + 220
f'(x) = 2(3x² + 32x + 110)
We can't factor that further, so let's do it the long way, starting by letting f'(x) equal zero:
0 = 2(3x² + 32x + 110)
0 = 3x² + 32x + 110
0 = 9x² + 96x + 990
0 = 9x² + 96x + 256 + 734
0 = (3x + 16)² + 734
(3x + 16)² = -734
3x + 16 = ± i√734
3x = -16 ± i√734
x = (-16 ± i√734) / 3
x ≈ (-16 + 27.9i) / 3, and (16 - 27.9i) / 3
x ≈ -5.3 + 9.3i, and -5.3 - 9.3i
I'm always wary when I end up with complex numbers. I'd suggest double checking everything here, but I'm fairly certain I did everything correctly.
i need help really bad
Answer:
see explanation
Step-by-step explanation:
If f(x) and \(f^{-1}\) are inverse functions, then
f(\(f^{-1}\))(x) = x
Thus substitute x = \(f^{-1}\) (x) into f(x)
f(\(\frac{x+6}{5}\) )
= 5 (\(\frac{x+6}{5}\) ) - 6
= x + 6 - 6
= x
Thus f(x) and \(f^{-1}\) (x) are inverse functions
Create a Venn diagram to illustrate each of the following: 26. (D ⋃ E) c ⋂ F
The Venn diagram for (D ⋃ E) ⋃ F will be the ovarlapped region of D,E and F.
To represent the sets D, E, and F in the Venn diagram, we first construct three overlapping circles. Then, beginning with the innermost operation and moving outward, we shade the regions corresponding to the set operations in the expression.
We shade the area where the circles for D and E overlap because the equation (D ⋃ E) denotes the union of the sets D and E. All the elements in D, E, or both are represented by this area.
The union of (D ⋃ E) with F is the next step. This indicates that we darken the area where the circle for F crosses over into the area that we shaded earlier. All the components found in sets D, E, F, or any combination of these sets are represented in this region.
The final Venn diagram should include three overlapping circles, with (D ⋃ E) ⋃ F shaded in the area where all three circles overlap.
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8. [-/1 Points]
SPRECALC7 1.7.071.
A pilot flew a jet from City A to City B, a distance of 1600 ml. On the return trip, the average speed was 20% faster than the outbound speed. The round-trip took 8 h 20 min. What was the speed from
City A to City B?
mi/h
DETAILS
MY NOTES
ASK YOUR TEACHER
PRACTICE ANOTHER
The speed from City A to City B is 352 miles/hour.
What is the relationship between speed, distance, and time?By dividing the distance traveled by the time required to travel it, speed is calculated.Speed is inversely correlated with time and directly correlated with distance. Thus, distance equals speed times time.Distance divided by speed equals time; as speed rises, time goes down, and vice versa.Given:
Distance for trip = 1600 miles
Distance for return trip = 1600 miles
The round-trip took 8 h 20 min.
Total time taken for both trips = 8 hours 20 minutes = 8 + (1/3) hours = 25/3 hours
It is mentioned that on the return trip, the average speed was 20% faster than the outbound speed.
Let's assume x is the speed for an outbound trip.
So, x + 20% of x is the average speed of the return trip
x + 20% of x = x + 0.2x = 1.2x
Speed for the return trip = 1.2x
Total time = (distance/speed of outbound trip) + (distance/speed of return trip)
⇒ \(\frac{25}{3} =\frac{1600}{x} +\frac{1600}{1.2x}\)
⇒ \(\frac{25x}{3} =\frac{1600*1.2 +1600}{1.2}\)
⇒ \(10x = 3520\)
⇒ \(x = 352\)
Therefore, the speed from City A to City B is 352 miles/hour.
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Jessica's health insurance premium is $3964 annually. If her employer pays 85% and she is paid monthly, how much is deducted from each monthly check? O $22.88 O $49.55 O $330.33 O $594.60
Answer:
594.60
Step-by-step explanation:
basically you turn the percent into a decimal, so 0.85 times 3954. then you subtract 3964.00 and 3369.40 to get the answer <3
Simplify: 7/6 x −3/28 Also, find the reciprocal of the answer.
Answer:
Simplify = 7x/6 - 3/28
Reciprocal = 6x/7 - 28/3
Step-by-step explanation:
Add x to the top of the first fraction to combine them.
To find the reciprocal you flip the numbers. So the numerator is the bottom and the dominator is the top.
A geologist is making repeated measurements (in grams) on the mass of a rock. It is not known whether the measurements are a random sample from an approximately normal population. Below are three sets of replicate measurements, listed in the order they were made. For each set of readings, state whether the assumptions necessary for the validdity of the t-test appear to be met. If the assumptions are not met, explain why?
a. 213.03 212.95 213.04 213.00 212.99 213.01 221.03 213.05
b. 213.05 213.00 212.94 213.09 212.98 213.02 213.06 212.99
c. 212.92 212.95 212.97 213.00 213.01 213.04 213.05 213.06
Answer:
Step-by-step explanation:
The objective of this question is to known whether the assumptions of the known data set follows normal distribution or not and if it is appropriate to use t-test or not.
TO solve this question ; we construct a box plot for the known data set by using a MINITAB software
The process is as follows to guide you:
Enter your data in the worksheet
Then select Graph→ Boxplot→ EDA→ Boxplot
Under One Y , select simple, Then click OK
In Variables , enter measurements. Then click OK
So; for the first data set (a) 213.03 212.95 213.04 213.00 212.99 213.01 221.03 213.05 as shown in the attached file in word document for the boxplot below;
We will observe that there is a outliner present in the data set and the measurement do not meet the normal assumption ; as a result to that ; the t-distribution is not appropriate for this data.
(b) From the document attached below; we will realize and observe that the boxplot doesn't contains an outliner. Also; it is clear and obvious that the shape of the distribution is right skewed. The measurement thus did not meet the assumptions and as a result t- distribution is not appropriate for this data.
(c)
From the document attached below; we will realize and observe that the boxplot doesn't contains an outliner. Also; it is clear and obvious that the shape of the distribution is left skewed. The measurement thus did not meet the assumptions and as a result t- distribution is not appropriate for this data.
(a): The \(t-\)distribution is not appropriate for this data.
(b): The \(t\)-distribution is not appropriate for this data.
(c): The \(t\)- distribution is not appropriate for this data.
\(t-\)test:
A t-test is a statistical test that is used to compare the means of two groups.
Part(a):
Check whether the unknown data set follows the normal distribution or not and is it appropriate to use the \(t\)-test or not.
Use the following MS excel instructions to draw a box plot.
Step-1: Enter the data into an excel sheet.
Step-2: Click add-ins-Mega stat-Descriptive statistics.
Step-3: Input the data into the input range box.
Step-4: Click Box-Plot -Click OK
It is observed that there is an outlier in the data set.
The obtained output is as follows:
So, the measurements do not satisfy the normality assumption.
Part(b):
Check whether the known data set follows normal distribution or not and is it appropriate to use the \(t\)-test or not.
Use the above MS excel instruction to draw a Box plot.
The obtained output is as follows.
It is observed that there is no outlier in the data set and the shape of the distribution is appears to be right-skewed.
So, the measurement do not satisfy the normality assumption.
Part(c):
Check whether the known data set follows normal distribution or not and is it appropriate to use the \(t\)- test or not.
Use the above MS Excel instruction to draw a Box-plot.
The obtained output is as follows.
It is observed that there is no outlier in the data set and the shape of the distribution is appears skewed to the left.
So, the measurement do not satisfy the normality assumption.
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Can someone help me Solve:
-2√3+√75=
Answer:
\(3\sqrt{3}\)------------------
Simplify in below steps:
\(-2\sqrt{3} +\sqrt{75} =\)\(-2\sqrt{3} +\sqrt{25*3} =\)\(-2\sqrt{3} +\sqrt{5^2*3} =\)\(-2\sqrt{3} +5\sqrt{3} =\)\(3\sqrt{3}\)Is 1 and 2/3 equal to 3divided by5
Answer:
sdfdfds
Step-by-step explanation:
Answer:
no
Step-by-step explanation:
3 divided by 5 is the same as 0.6
what is the probability that either event will occur?
The probability that either event will occur is P ( C ) = 0.89
Given data ,
Let the probability that either event will occur be P ( C )
P ( A ) = 20/36
P ( B ) = 12/36
where P ( A or B ) = P ( C )
P ( C ) = P ( A ) + P ( B )
P ( C ) = 32/36
P ( C ) = 0.88888
Hence , the probability is P ( C ) = 0.89
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Which function has an inverse that is a function?
b(x) = x2 + 3
d(x) = -9
m(x) = -7x
p(x) = |x|
Answer:
i aint never seen two pretty bestfriends
Step-by-step explanation:
Factorise 4x³+8x guys plz
Answer:
4x (x²+2)
Hope that helps
Answer:
4x(x+2x)
Step-by-step explanation:
There is no further explanations on it
105-30-45-3028+10000000000000038492=?
Answer:
105-30-45-3028+10000000000000038492= 1.000000000000003e19
Step-by-step explanation:
I did the math
have a good day!!
Help me pleasee! I dont understand this!
please help, I have been on this question for a while. Lotta yummy PTS
Answer:
\(y=\left|\dfrac{1}{2}x-\dfrac{5}{2}\right|+3\)
Step-by-step explanation:
Given equation:
\(y=\left|\dfrac{1}{2}x-2\right|+3\)
Translation
\(f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}\)
When translating a graph to the right, subtract the number of units from the x variable.
Translating the given graph one unit to the right:
\(f(x-1) \implies y=\left|\dfrac{1}{2}(x-1)-2\right|+3\)
Simplifying:
\(\implies y=\left|\dfrac{1}{2}(x-1)-2\right|+3\)
\(\implies y=\left|\dfrac{1}{2}x-\dfrac{1}{2}-2\right|+3\)
\(\implies y=\left|\dfrac{1}{2}x-\dfrac{5}{2}\right|+3\)
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