The graph of which function is the same as the graph of y=1/x shifted to the right 5 units and shifted up 2 units?

y = 1/x+5 + 2

y = 1/x-2 + 2

y = 1/x+5 - 2

y= 1/x-5 - 2
​

When the relationship between the unit of measurement of a scale (strength) and an outcome (pounds lifted) can be described by a linear equation y = a bx, the scale is said to have a property of equal intervals.

Therefore, when the relationship between the unit of measurement of a scale (strength) and an outcome (pounds lifted) can be described by a linear equation y = a bx, the scale is said to have a property of equal intervals.

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A- There is a variable X3 that is correlated with Y but not with X2.

If there is a variable X3 that is correlated with Y but not with X2, including X3 in the regression model can introduce bias to the coefficient for X2. This is because X3 is a confounding variable that affects both Y and X2. By omitting X3 from the regression model, the estimated coefficient for X2 will absorb the influence of X3, leading to a biased coefficient for X2.

In order to obtain an unbiased coefficient for X2, it is important to include all relevant variables that are correlated with both Y and X2 in the regression model.

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Step-by-step explanation:

\( \sf{ \longmapsto \: D.f(t)=20,000(1.08)t}\)

The equation

Is in point intercept form

The general equation of point intercept form is given as

Comparing the two equations

This implies

Hence, the slope in the equation is -2

Also, by comparing the equations

Thus the point in the equation is (2, 1)

Answer:

Step-by-step explanation:

left to right

63 33 28 88 55 120 24 24 2 90

48 28 40 50 72 30 60 99 12 20

18 16 81 9 42 32 62 40 22 66

18 8 60 6 49 108 110 27 121 80

36 35 20 24 44 36 54 96 132 12

56 144 77 30 72 36 70 16 15 14

45 21 25 84 10 100 40 12 120 54

64 30 27 60 24 36 121 10 18 18

Answer:

Step-by-step explanation: its either the data is the same as the middle or the data in the upper is bigger.

Solution:

Given:

Account 2 details:

Assume a year is 365 days;

Using the compound interest formula to get the amount;

Hence, substituting the values;

Therefore, the balance in account 2 will be $9633.55

Answer:

Step-by-step explanation:

By subtracting 2 from both sides, we get the equivalent inequality

x>−5 .

So, the solution set is

{x | x>−5} .

==========================================================

Explanation:

The tri-inequality A < B < C breaks up into A < B and B < C

Use this idea to break up 2 ≤ 2x < x+5 into these two pieces

We'll solve each inequality individually.

Let's start with the first one.

2 ≤ 2x

2/2 ≤ 2x/2

1 ≤ x

Now onto the second inequality

2x < x+5

2x-x < x+5-x

x < 5

-------------------------

From here recombine 1 ≤ x and x < 5  to get  1 ≤ x < 5

If x is an integer only, then the roster set of solutions that satisfy this inequality is {1, 2, 3, 4}. Notice 5 is not part of the solution set, but 1 is.

We can replace x with any of those items in bold to get a true statement.

For instance, let's replace x with 3.

1 ≤ x < 5 updates to 1 ≤ 3 < 5 which is true

Let's go back to the original tri-inequality and replace each x with 3. Then simplify each side.

2 ≤ 2x < x+5

2 ≤ 2*3 < 3+5

2 ≤ 6 < 8

We end up with a true statement, which verifies that x = 3 is one of the integer solutions. I'll let you verify the other values 1,2, and 4.

Answer:

Condition:

If a series converges, then the terms of the series approach 0.

Converse:

If the terms of a series approach 0, then the series converges.

Expect distributions of these variables are:

a) Ages of people at a Little League game are unimodal and skewed.

b) Number of siblings of people in your class is unimodal and skewed.

c) Pulse rates of college-age males unimodal and roughly symmetric.

d) Number of times each face of a die shows in 100 tosses is approximately uniform.

a) Age distribution during a Little League game is likely to be unimodal and skewed. The age range of attendees. This is because Little League has an upper age restriction and the majority of players will fall inside that range, with just a small number being outliers. As a result, the distribution is likely to be unimodal, with the majority of participants falling within a relatively small age range, and being skewed toward older ages.

b) How many siblings are in your class? The distribution of siblings in a class is probably unimodal and skewed. This is because the majority of people either have no siblings or have one or two siblings, with just a small minority having three or more. As a result, the distribution will be unimodal, with the majority of individuals falling within a very small range, and tilted in the direction of the lower numbers.

c) Males in college-age pulse rates: These men's pulse rate distributions are probably unimodal and roughly symmetric. It is doubtful that there would be different groups or outliers that would result in a bimodal distribution, even though there may be some natural variation in pulse rates. There is also no reason to assume that one tail of the distribution will be longer or more dispersed than the other, hence the distribution is probably symmetric.

d) Number of times each die face is revealed in 100 throws: The distribution of the number of times each die face is revealed in 100 throws is probably quite uniform. Each face has an equal chance of appearing on each toss, and throughout 100 tosses, each face is expected to do so roughly the same amount of times, assuming a fair die. As each face should appear nearly equally often, the distribution should be quite consistent.

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Answer:

A linear sequence

Step-by-step explanation:

In this sequence, the difference between the first two terms is  70−35=35 , we can check this is correct by finding the difference between the 2nd and 3rd terms, which is  105−70=35 . This means the first difference is 35.

The first difference gives us the number we multiply  n  by, or the quotient of n.

This means we get the nth term as  35n+c .

To get  c , we check the difference between the first term and the number we get when we multiply  n  by  35 , when  n=1 .

This gives us:

35n+c=35  

c=35−35n  

c=35−35(1)  

c=35−35  

c=0  

Once we have  c , we get the nth term of  35,70,105  to be  35n .

Yes, the sampling distribution is normally distributed because the population is normally distributed.

A sampling distribution is a chance distribution of a statistic obtained from a larger variety of samples drawn from a specific populace. The sampling distribution of a given population is the distribution of frequencies of a variety of various outcomes that would probable occur for a statistic of a populace.

A sampling distribution is a probability distribution of a statistic this is obtained via drawing a huge variety of samples from a particular populace. Researchers use sampling distributions so that you can simplify the technique of statistical inference.

Solution :

mean = μ40

standard deviation σ σ= 3

n = 10

μx =  40

σ x = σ√n =  3/√10  = 0.9487

μ x =  4σ\x = 0.9487

σx = 0.9487

Yes, the sampling distribution is normally distributed because the population is normally distributed.

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Students were surveyed about their favorite colors. 1/4 of the student preferred red, 1/8 of the students preferred blue, and 3/5 of the remaining students preferred greed, then 10 students surveyed did not choose a rainbow color as their favorite.

Let's use algebra to solve for the total number of students surveyed:

Let x be the total number of students surveyed.

Then, the number of students who preferred red is (1/4)x.

The number of students who preferred blue is (1/8)x.

The remaining students are (x - (1/4)x - (1/8)x) = (5/8)x.

Out of these remaining students, 3/5 preferred green, so we can set up the equation:

(3/5)(5/8)x = 15

Simplifying, we get:

(3/8)x = 15

Multiplying both sides by 8/3, we get:

x = 40

Therefore, there were 40 students surveyed in total. To find the number of students who did not choose a rainbow color as their favorite, we need to subtract the number of students who preferred red, blue, green, or purple from the total number of students:

Number of students who did not choose a rainbow color = x - (1/4)x - (1/8)x - 15 = 40 - 10 - 5 - 15 = 10

Therefore, 10 students surveyed did not choose a rainbow color as their favorite.

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The zeros of the function are -10 and +10

lesser x = -10

greater x = +10

The zeros of a quadratic equation are the points where the graph of the quadratic equation crosses the x-axis. . The zeros of quadratic equation will always have two values.

f(x) = 8x²- 800

f(x) = y

y = 8x²-800

when the graph crosses x axis the value of y = 0

therefore 0 = 8x²-800

divide both sides by 8

0 = x² - 00

x² = 100

x= √100

x= ±10

therefore lesser x = -10

greater 10 = +10

therefore the zeros of the quadratic equation f(x) = 8x²- 800 = +10 and -10

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A rough graph of T as a function of time t for hot water running from a tap would likely show an exponential decay curve.

Initially, the temperature of the water will be close to the temperature of the hot water supply in the house. However, as the water continues to flow, the temperature will gradually decrease due to heat loss through the pipes and the ambient temperature of the surrounding air. This decay will likely be exponential, with a relatively steep initial drop in temperature followed by a more gradual decrease over time. The graph would show an asymptotic approach towards room temperature as the water continues to flow. The exact shape of the curve will depend on a variety of factors, such as the length and material of the pipes, the ambient temperature, and the temperature of the hot water supply.

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Answer:

2

Step-by-step explanation:

28 + 2 = 30

Answer:

p = 2

Step-by-step explanation:

28 + p = 30

Subtract 28 from both sides

  p = 30 - 28

  p = 2

Answer:

Step-by-step explation:

4 + 3 + 2 + 3 + 4

16/5= 3.2

answer is B

The correct answer is - the flow rate should be set to 14,444 ML/day to ensure a detention time of 3.4 hours is maintained.

Solution- 14,444 ML/day

Firstly, convert the tank capacity to litres since the flow rate will be in ML/day.17,000 m³ = 17,000,000 litres

The formula for calculating the flow rate is: Flow rate = Tank volume / Detention time

Flow rate = 17,000,000 litres / (3.4 hours x 24 hours)

Flow rate = 17,000,000 litres / 81.6 hours

Flow rate = 208,333.33 litres/hour

Now that we have calculated the flow rate in litres per hour, we can convert it to mega litres per day (ML/day) by multiplying by 24 and dividing by 1,000,000.

Flow rate = 208,333.33 litres/hour x 24 / 1,000,000 = 5 ML/day

Therefore, the flow rate should be set to 14,444 ML/day to ensure a detention time of 3.4 hours is maintained.

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To express the ratio of the given questions in the fraction form are as follow:

1. (2 / 3)  hours

2. (2/3) year

3. 3/2  

4. (3/2) of 20years

5. 1/6

6. 2/4

7. 4/3

8. 1/7

9. 10/3

10. 2/1

As given in the question,

Ratio of the given expression in fraction form is given by:

1. 40 minutes = (120 minutes/3)

                      = (2 / 3)  hours

2. 8 months = (12months) ×( 2/3)

                    = (2/3) year

3. 45 members of sports to the 30 members of dance club

= 45/ 30

= 3/2

4. 3decades = (3 × 10)years

                    = (3/2) of 20years

5. Number of buses to the number of wheels

= 10 / ( 10×6)

= 1/6

6. Projects to quarters

= 2/4

7. Ratio of mango to the apple tree

= 4/3

8. Ratio of number of boxes to the t-shirts

= 1/7

9. ratio of banana to the apples

= 10/3

10. Ratio of girls to the boys

= 20/10

= 2/1

Therefore, the ratio of the given questions in the fraction form are as follow:

1. (2 / 3)  hours

2. (2/3) year

3. 3/2  

4. (3/2) of 20years

5. 1/6

6. 2/4

7. 4/3

8. 1/7

9. 10/3

10. 2/1

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The congruence theorem that can be used as the reasons why ΔABC ≅ ΔUVW, is the LA congruence theorem, which is the option, A

A. LA

The LA congruence theorem states that if the leg and one acute angle in a right triangle are congruent to the corresponding leg and acute angle of another right triangle, then the two triangles are congruent.

The details in the diagram are;

Triangle ΔABC and triangle ΔUVW are right triangles.

The angle ∠BAC and ∠VUW are right angles, and therefore; ∠BAC ≅ ∠VUW

The acute angle ∠ACB in the triangle ΔABC is congruent to the acute angle ∠UWV in the triangle ΔUVW

The segment AC in triangle ΔABC is congruent to the segment UW in triangle ΔUVW

The information obtained from the diagram are therefore one acute angle and one side in the right triangle ΔABC are congruent to one ane acute angle and a side in the triangle ΔUVW, which indicates that the triangles are congruent by the LA congruence theorem

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The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model. The optimal number of notebooks to make in each order is 590 units. The annual ordering cost (AOC) is approximately $892.20. The Annual Holding Cost (AHC) is $3540. The annual product cost (APC) is $233,460. The annual total cost of managing inventory (ATC) is approximately $237,892.20. The total number of orders in the year (N) is 33. The estimated time between each order (T) is approximately 7.58 days. The daily demand is approximately 77.82 units. The reorder point (ROP) is approximately 311 units.

The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model.

To find the optimal number of notebooks to make in each order, we can use the EOQ formula:

EOQ = √[(2 * Demand * Ordering Cost) / Holding Cost]

EOQ = √[(2 * 19455 * 27) / 6]

EOQ ≈ 589.96

Since the number of notebooks must be a whole number, the optimal number to order would be 590 notebooks.

The annual ordering cost (AOC) can be calculated by dividing the annual demand by the EOQ and multiplying it by the ordering cost:

AOC = (Demand / EOQ) * Ordering Cost

AOC = (19455 / 590) * 27

AOC ≈ $892.20

The Annual Holding Cost (AHC) is calculated by multiplying the EOQ by the holding cost per unit:

AHC = EOQ * Holding Cost

AHC = 590 * 6

AHC = $3540

The annual product cost (APC) is calculated by multiplying the annual demand by the cost per unit:

APC = Demand * Cost per unit

APC = 19455 * 12

APC = $233,460

The annual total cost of managing inventory (ATC) is the sum of the annual ordering cost, annual holding cost, and annual product cost:

ATC = AOC + AHC + APC

ATC = 892.20 + 3540 + 233460

ATC ≈ $237,892.20

The total number of orders in the year (N) can be calculated by dividing the annual demand by the EOQ:

N = Demand / EOQ

N = 19455 / 590

N ≈ 33

The estimated time between each order (T) can be calculated by dividing the number of working days in a year by the total number of orders:

T = Number of working days / N

T = 250 / 33

T ≈ 7.58 days

The daily demand is calculated by dividing the annual demand by the number of working days in a year:

Daily Demand = Demand / Number of working days

Daily Demand = 19455 / 250

Daily Demand ≈ 77.82 units/day

The reorder point (ROP) is the number of units at which a new order should be placed. It can be calculated by multiplying the daily demand by the lead time (time taken for the supplier to deliver the order):

ROP = Daily Demand * Lead Time

ROP = 77.82 * 4

ROP ≈ 311.28 units

Therefore, the reorder point would be approximately 311 units.

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First we add 0.3 to 3.7, that way we will have an integer and it would be more easy to make the operations. Then we have 4.

Then we can substract the 4 to the 9.4, getting 5.4.

Finally we add once again 0.3 (because in the difference we have an extra .3) to the 5.4, getting 5.7.

Then Tamela swims 5.7 more than Blake every day.

The net loss is $1873.97.

What is the selling price?

The selling price formula is Selling Price = Cost Price + Profit Margin. Cost price is the price a retailer paid for the product. The profit margin is a percentage of the cost price.

Here, we have

Given: Suki purchased $9,600 worth of stock and paid her broker a 2.5% broker fee. She had an immediate need for cash and was forced to sell the stock when it was worth $8,000. She used a discount broker who charged $33.97 per trade transaction.

Purchase price: $9,600

Fee purchase:  2.5%

Selling price: $8,000

Fee scale: $33.97

The broker fee is the product of the broker fee rate of  2.5% and the purchase price:

Broker fee purchase = 2.5%× 9,600

= 240

The total purchase cost is the sum of the purchase price and the broker fee of the purchase:

Total purchase cost Purchase price =  Broker fee purchase

= 9600 + 240

= 9840

The total selling cost is the selling price decreased by the broker fee of the sale (flat rate):

Total selling cost = Selling price - Broker fee sale

= 8,000 - 33.97

= 7966.03

The net loss is then the difference between the total purchase cost and the total selling cost:

Net loss = Total purchase cost - Total selling cost

= 9840 - 7966.03

= 1873.97

Hence, the net loss is $1873.97.

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The converse of the conditional statement "If x < 20, then x < 30" is "If x < 30, then x < 20."

The converse statement is not true, because there are values of x that are less than 30 but are greater than or equal to 20.

Therefore, the counterexample is: x = 27.

If x = 27, the statement "If x < 30, then x < 20" is false because 27 is less than 30 but not less than 20.

Therefore, the answer is B) If x < 30, then x < 20 ; False -Counterexample: x=27 and x < 27.

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Dividing 3x^2 - 11x - 4 by x - 4 results in the quotient of 3x + 1 and a remainder of -23.

To divide 3x^2 - 11x - 4 by x - 4, we can use long division.

First, we divide the highest degree term of the dividend by the divisor. In this case, (3x^2) / (x) gives us 3x as the first term of the quotient.

Next, we multiply the divisor (x - 4) by the first term of the quotient (3x) to obtain (3x)(x - 4) = 3x^2 - 12x.

We subtract this result from the dividend (3x^2 - 11x - 4) to get a new polynomial: (3x^2 - 11x - 4) - (3x^2 - 12x) = x + 8x - 4.

Now, we repeat the process with the new polynomial (x + 8x - 4). We divide the highest degree term (x) by the divisor (x - 4), which gives us the second term of the quotient, 8.

Multiplying the divisor (x - 4) by the second term of the quotient (8) gives us (8)(x - 4) = 8x - 32.

Subtracting this from the new polynomial (x + 8x - 4) - (8x - 32) = 40, we obtain the remainder.

Therefore, the division of 3x^2 - 11x - 4 by x - 4 gives the quotient 3x + 1 and the remainder -23.

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The difference in the amount paid by Cathy and Steven is $4000.

Simple interest is when the interest that is paid on the loan of a customer is a linear function of the loan amount, interest rate and the duration of the loan.

Simple interest = amount borrowed x interest rate x time

Simple interest of Cathy = $20,000 x 0.052 x 10 = $10,400

Simple interest of Steven = $20,000 x 0.048 x 15 = $14,400

Difference in interest = $14,400 - $10,400 = $4000

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Answer:

Step-by-step explanation:

You want to know how to determine the y-intercepts of a rational function, and their possible number.

A rational function f(x) is the ratio of two polynomial functions p(x) and q(x):

  f(x) = p(x)/q(x)

As such, both numerator and denominator have single function values for any value of the independent variable. The y-intercept of f(x) is ...

  f(0) = p(0)/q(0)

The values of p(0) and q(0) are simply the constant terms in those respective functions.

The simple way to find the y-intercept is to look at the ratio of the constant terms in the polynomial functions making up the rational function. If that is defined, there is one y-intercept. If it is undefined (q(0)=0), then there are no y-intercepts.

<95141404393>

Required solutions after simplification are 8bz, 1, 3x³/y², 144, x⁹, 1/y⁵ respectively.

7) To simplify the expression:

\(\frac{16db {z}^{5} }{ {(2z)}^{4} } \\ = \frac{16}{2} \times \frac{b}{z} \times \frac{ {z}^{5} }{ {z}^{4} } \\ = 8b \times {z}^{5 - 4} \\ = 8bz\)

Therefore, 16dbz⁵/(2z)⁴ simplifies to 8bz.

8)Any non-zero number raised to the power of zero is 1.

Therefore:(15n⁶m²x³/n⁻²m⁻³b⁻⁸)⁰ = 1

9)To simplify the expression:

\( \frac{30 {x}^{4} {y}^{ - 3} }{10 {x}^{ - 2} {y}^{5} }

= \frac{3 {x}^{4 - ( - 2)} }{ {y}^{3 - 5} }

= \frac{3 {x}^{6} }{ {y}^{ - 2} }

= \frac{3 {x}^{6} }{ {y}^{2} } \)

herefore, 30x⁴y⁻³/10x⁻²y⁵

\(\frac{30 {x}^{4} {y}^{ - 3} }{10 {x}^{ - 2} {y}^{5} } \) simplifies to \(\frac{3 {x}^{6} }{ {y}^{2} } \)

13) To solve this expression, we perform the exponentiation first and then perform the multiplication.

6² means 6 multiplied by itself, or 6×6 = 36.

So,4×6² = 4×36

So, 4×6²= 144

Therefore, 4×6² equals 144.

14) To simplify the expression: x³ × x⁻² × x⁷ × x

\( = {x}^{3 - 2 + 7 + 1} = {x}^{9} \)

Therefore, x³ * x⁻² * x⁷ * x simplifies to x⁹.

15)To simplify the expression:

\( {y}^{ - 11} \times {y}^{6} \times {y}^{0} \\ = {y}^{ - 11 + 6 + 0} \\ = {y}^{ - 5} \\ = \frac{1}{ {y}^{5} } \)

Therefore, Required value is 1/y⁵.

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