The function Y (x) = 1/3x represents the number of yards Y(x) in x feet. How many yards are there in 1 mile? (Hint: there are 5280 ft in 1 mile.)

Answer:

Step-by-step explanation:

$50050050re=$450(1+2re)=450+900re=900re=50900=0.05555¯=5.555¯%

The amount of interest will be $50 for the investment.

Simple interest is a way to figure out how much interest will be charged on a sum of money at a specific rate and for a specific amount of time.

Contrary to compound interest, where we add the interest of one year's principal to the next year's principal to calculate interest, the principal amount in simple interest remains constant.

Given that Krisi took out a $500 discounted loan calculated using a simple interest rate of 5% for a period of 2 years.

The interest will be calculated as:-

SI = ( 500 x 5 x 2 ) / 100

SI = $50

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The features of the quadratic function are given as follows:

The zero is the value of x for which the function touches or crosses the x-axis, hence it is of:

x = -2.

As the graph only touches the x-axis, the zero has an even multiplicity of 2.

The vertex is the turning point of the graph of the quadratic function, hence the coordinates are given as follows:

(-2,0).

Meaning that:

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Answer:

either 4032 or 56448

Step-by-step explanation:

you have to multiply length times height times width.

−7 < x – 3 ≤ 6 is just a regular inequality, neither conjunction nor disjunction are involved.

x + 5 < -1 or x + 2 > 5 is a disjunction.

3 > x – 4 and x + 8 ≥ 2 is a conjunction.

After answering the presented question, we can conclude that expressions Therefore, the population of the rural city in 2030 is approximately 11,014.18.

In mathematics, you can multiply, divide, add, or subtract. An expression is constructed as follows: Number, expression, and mathematical operator A mathematical expression is made up of numbers, variables, and functions (such as addition, subtraction, multiplication or division etc.) It is possible to contrast expressions and phrases. An expression or algebraic expression is any mathematical statement that has variables, integers, and an arithmetic operation between them. For example, the expression 4m + 5 has the terms 4m and 5, as well as the provided expression's variable m, all separated by the arithmetic sign +.

To approximate the population in 2030, we need to find the value of P(t) when t = 44, since 2030 is 44 years after 1986.

Using the given exponential growth model, we have:

\(P(t) = 3400^(0.0371t)\\P(44) = 3400^(0.0371*44)\\P(44) = 3400^1.6334\\P(44) = 11014.18\\\)

Therefore, the population of the rural city in 2030 is approximately 11,014.18.

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Matching of the functions domain and range are as follows:

f(x)   = 4-4x ;

Domain:{0,1,3,5,6}

Range;{-20,-16,-8,0,4}

f(x) = 5x - 3

Domain:{-2,-1,0,3,4}

Range:{-13,-8,-3,12,4}

f(x) = -10x

Domain:{-4,-2,0,2,4}

Range:{-40,-20,0,20,40}

f(x) = (3/x) + 1.5

Domain:{-3,-2,-1,2,6}

Range:{0.5,0,-1.5,3,2}.

1) The function f(x) = 4 - 4x

Take Domain:{0,1,3,5,6}

If, we take x=0 and put in the function then we get

f(x)=4-0

f(x)=4

put x=1

f(x) = 4 - 4 =0

put x=3 then we get

f(x)=4-12=--8

put x=5 them we get

f(x)=4-20=-16

put x=6 then we get

f(x)=4-24=-20

Therefore ,range:[-20,-16,-8,0,4}

2) The function f(x)=5x-3

Take domain{-2,-1,0,3,4}

Now, put x=-2 in the function then we get

f(x) = -13

now put x=-1 then we get

f(x)=-5-3=-8

Put x=0 then we get

f(x)=0-3=-3

Put x=3 then we get

f(x)=15-3=12

Put x=4 then we get

f(x)=20-3=17

Therefore , range:{-13,-8,-3,12,17}

3) The function f(x)=-10x

Take domain:{-4,-2,0,2,4}

Put x=-4 in the function then we get

f(x)=40

Put x= -2 then we get

f(x)=20

Put x=0 then we get

f(x)=0

Put x=2 then we get

f(x)=-20

Put x=4 then we get

f(x)=-40

Therefore , range :{-40,-20,0,20,40}

4) The function f(x)= (3/x) + 1.5

Take domain:{-3,-2,-1,2,6}

Put x= -3 in the taken function then we get

f(x)=-1+1.5=0.5

put x=-2 then  we get

f(x)= -1.5+1.5=0

Put x=-1 then we get

f(x)=-3+1.5=-1.5

Put x= 2 then we get

f(x)=1.5+1.5=3

Put x= 6 then we get

f(x)=0.5+1.5=2

Therefore, range : {0.5,0,-1.5,3,2}.

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Answer:

Value of x = 11 ° , ∠B = 108° ,∠C = 36° ,∠D = 36°

Step-by-step explanation:

Given :

In ΔBCD , BC = BD And ∠B= (13x-35)° , ∠C= (5x-19)° ,∠D=(2x+14)°

To Find :

value of x and ∠D , ∠B and ∠C

Solution:

∵ BC=BD , So ∠C = ∠D

Therefore 5x-19 = 2x+14

3x = 33 , ∴ x=11°

So, ∠B = (13×11) - 35 = 108°

∠C = (5×11)-19 = 36°

∠D= (2×11) +14 =36°

As, a is block diagonal, with diagonal blocks of size \(m_1 \times m_1\), \(m_2 \times m_2\), \(\dots\), \(m_k \times m_k\), respectively. So,  if a commutes with d, then it must be block diagonal.

Let's suppose that d is a diagonal matrix with repeated diagonal entries grouped contiguously, i.e.,

d = \(\begin{pmatrix} D_1 & 0 & 0 & \cdots & 0 \ 0 & D_1 & 0 & \cdots & 0 \ 0 & 0 & D_2 & \cdots & 0 \ \vdots & \vdots & \vdots & \ddots & \vdots \ 0 & 0 & 0 & \cdots & D_k \end{pmatrix}\),

where \(D_1, D_2, \dots, D_k\) are scalars and appear with frequencies \(m_1, m_2, \dots, m_k\), respectively, so that \(m_1 + m_2 + \dots + m_k = n\), the size of the matrix.

Suppose that \(a\) is a matrix that commutes with d, i.e., ad = da.

Then, for any \(i \in {1, 2, \dots, k}\), we have

\(ad_{ii} = da_{ii}\)

Here, \(d_{ii}\) denotes the \(i$th\) diagonal entry of d, i.e., \(d_{ii} = D_i\) for \(i = 1, 2, \dots, k\). Since d is diagonal, \(d_{ij} = 0\) for \(i \neq j\), and

hence

\(ad_{ij} = da_{ij} = 0\)

for all \(i \neq j\).

Therefore, a is also diagonal, with diagonal entries \(a_{ii}\), and we have

\(a = \begin{pmatrix} a_{11} & 0 & 0 & \cdots & 0 \ 0 & a_{11} & 0 & \cdots & 0 \ 0 & 0 & a_{22} & \cdots & 0 \ \vdots & \vdots & \vdots & \ddots & \vdots \ 0 & 0 & 0 & \cdots & a_{kk} \end{pmatrix}\)

Thus, a is block diagonal, with diagonal blocks of size \(m_1 \times m_1\), \(m_2 \times m_2\), \(\dots\), \(m_k \times m_k\), respectively.

Therefore, if a commutes with d, then it must be block diagonal.

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ANSWER:

D. The set of all possible output values

STEP-BY-STEP EXPLANATION:

The range of a function is the interval of values that the response or dependent variable can take, that is, they would be the output values.

Therefore, the correct answer is D. The set of all possible output values

Answer:

Step-by-step explanation:

I'm going to guess that the question is "How do you represent the distance between the left and right sides?"

The red dots are closed which means that the end points are included.

5 ≤  x  ≤  8

The length is 8 - 5 = 3

Answer:

\(2000 {(1 + \frac{.07}{12}) }^{5 \times 12} = 2835.25\)

Since each term can be written as the previous term divided by three, this is a geometric sequence.

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

\(a_n = a_1q^{n-1}\)

In which \(a_1\) is the first term.

For this problem, we have that each term can be written as the previous term multiplied by one third or divided by three, hence the division of consecutive terms is always the same and this is a geometric sequence.

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Question 1:

(a) The equation representing Elaine's total parking cost is:

C = x * t

(b) So the cost of parking for a full 24 hours would be 24 times the cost per hour.

Question 2:

The given system of equations is inconsistent and has no solution.

(a) To represent Elaine's total parking cost, C, in dollars for t hours, we need to know the cost per hour. Let's assume the cost per hour is $x.

(b) If Elaine wants to park her car for a full 24 hours, we can substitute t = 24 into the equation from part (a):

C = x * 24

Question 2:

To solve the linear system:

-x - 6y = 5

x + y = 10

We can use the elimination method.

Multiply the second equation by -1 to create opposites of the x terms:

-x - 6y = 5

-x - y = -10

Add the two equations together to eliminate the x term:

(-x - 6y) + (-x - y) = 5 + (-10)

-2x - 7y = -5

Now we have a new equation:

-2x - 7y = -5

To check the answer, we can substitute the values of x and y back into the original equations:

From the second equation:

x + y = 10

Substituting y = 3 into the equation:

x + 3 = 10

x = 10 - 3

x = 7

Checking the first equation:

-x - 6y = 5

Substituting x = 7 and y = 3:

-(7) - 6(3) = 5

-7 - 18 = 5

-25 = 5

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Answer:

Step-by-step explanation:

3x and 3y are not "like terms," despite having the same coefficient.

Like terms have the same variable. For example, 3x and 2x are like terms, so

3x+2x = 5x

The value of x for each item is given as follows:

28. x = 5.

29. x = 3.44.

For item 28, we apply the crossing chord theorem, which states that the products of the parts of the chords are equal, hence the value of x is obtained as follows:

16x = 10 x 8

16x = 80

x = 5.

For item 29, we apply the two secant theorem, hence the value of x is obtained as follows:

10(x + 10) = 12(12 + 25)

10x + 100 = 444

10x = 344

x = 3.44.

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Answer: C

Step-by-step explanation:

Point D is at -14 on the number line.

In Mathematics, the midpoint of a line segment with two end points can be calculated by adding each end point on a line segment together and then divide by two (2).

Since E is the midpoint of line segment CD, we can logically deduce the following relationship:

Line segment CD = Line segment C + Line segment D

Midpoint E = (point C + point D)/2

By substituting the given points into the equation above, we have the following:

-3 = (8 + D)/2

-6 = 8 + D

D = -6 - 8

D = -14

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Answer:16x16

Step-by-step explanation:

Answer:

  C:  y = -(x +3)² -1

Step-by-step explanation:

You want the vertex-form equation of the parabola with vertex (-3, -1) and opening downward.

For vertex (h, k), the vertex form equation of a parabola is ...

  y = a(x -h)² +k

Given that (h, k) = (-3, -1), the equation will have the form ...

  y = a(x -(-3))² + (-1)

  y = a(x +3)² -1 . . . . . . . . . . matches choice C

The value of 'a' will be negative when the parabola opens downward. Here, its value is -1.

  y = -(x +3)² -1

__

Additional comment

Once you identify the left-shift of 3 units as resulting in an equation with (x +3)² as a component, you can make the appropriate answer choice without considering anything else. Of course, the fact that the curve opens downward immediately eliminates choices A and B.

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Answer:

275.15

Step-by-step explanation:

312.67 * 12% = 37.52

312.67 - 37.52 = $275.15

Answer:

the distance between Austin and Amarillo on Amy's map is 14 inches

Step-by-step explanation:

798 ÷ 28.5 = 28

28 ÷ 2 = 14

The pairs of coordinates arranged from least to greatest based on the differences between the points are:

(-1,-2) and (1,-4)

(4,1) and (2,2)

(-5,2) and (-3,-2)

(3,-4) and (-2,1)

(5,-2) and (-1,-1)

Let's calculate the differences and arrange the pairs accordingly:

(4,1) and (2,2):

Difference in x-coordinates: 4 - 2 = 2

Difference in y-coordinates: 1 - 2 = -1

(-5,2) and (-3,-2):

Difference in x-coordinates: -5 - (-3) = -2

Difference in y-coordinates: 2 - (-2) = 4

(3,-4) and (-2,1):

Difference in x-coordinates: 3 - (-2) = 5

Difference in y-coordinates: -4 - 1 = -5

(-1,-2) and (1,-4):

Difference in x-coordinates: -1 - 1 = -2

Difference in y-coordinates: -2 - (-4) = 2

(5,-2) and (-1,-1):

Difference in x-coordinates: 5 - (-1) = 6

Difference in y-coordinates: -2 - (-1) = -1

Now let's arrange them in order from least to greatest based on the differences in the points:

(3,-4) and (-2,1) (difference: 5)

(-1,-2) and (1,-4) (difference: 2)

(4,1) and (2,2) (difference: 2)

(-5,2) and (-3,-2) (difference: 4)

(5,-2) and (-1,-1) (difference: 6)

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The solution of the differentiated equation is dy/dx = -6x⁵

From the question, we have the following equations that can be used in our computation:

x = ⁶√t

y = 8 - t

To start with:

We need to make the variable t the subject of the formula in the equation x = ⁶√t

Make t the subject

So, we have

t = x⁶

Substitute t = x⁶ in the equation y = 8 - t

y = 8 - x⁶

The rule of first principle of differentiation is represented as

If y = axⁿ, then dy/dx = naxⁿ⁻¹

Using the above as a guide, we have

y = 8 - x⁶

dy/dx = 0 * 8x⁰⁻¹ - 6 * x⁶⁻¹

Evaluate the difference

So, we have

dy/dx = 0 * 8x⁻¹ - 6 * x⁵

Evaluate the products

So, we have

dy/dx = 0 - 6x⁵

Evaluate the sum

So, we have

dy/dx = -6x⁵

Hence, the equation result is dy/dx = -6x⁵

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Answer:

6610

Step-by-step explanation:

We have tan(X) = opposite/ adjacent

tan(QBP) = PQ/BQ

tan(35) = PQ/BQ    ---eq(1)

tan(QAP) = PQ/AQ

tan(20) = \(\frac{PQ}{AB +BQ}\)

\(=\frac{1}{\frac{AB+BQ}{PQ} } \\\\=\frac{1}{\frac{AB}{PQ} +\frac{BQ}{PQ} } \\\\= \frac{1}{\frac{230}{PQ} + tan(35)} \;\;\;(from\;eq(1))\\\\= \frac{1}{\frac{230 + PQ tan(35)}{PQ} } \\\\= \frac{PQ}{230+PQ tan(35)}\)

230*tan(20) + PQ*tan(20)*tan(35) = PQ

⇒ 230 tan(20) = PQ - PQ*tan(20)*tan(35)

⇒ 230 tan(20) = PQ[1 - tan(20)*tan(35)]

\(PQ = \frac{230 tan(20)}{1 - tan(20)tan(35)}\)

\(= \frac{230*0.36}{1 - 0.36*0.7}\\\\= \frac{82.8}{1-0.25} \\\\=\frac{82.8}{0.75} \\\\= 110.4\)

PQ = 110.4

≈110

Height above sea level = 6500 + PQ

6500 + 110

= 6610

The mean number of goals for two seasons is 2.44 goals per match.

When the average is not of any individual rather it is an average of two or more groups or sets it is called a weighted average.

To obtain the weighted average we multiply no. of individuals by their averages and sum the next group in the previous procedure and divide them by the total no. of individuals.

Given, Last season Rio's football team scored 50 goals in 20 matches.

This season they scored 60 goals in 25 matches.

Therefore, The mean number of goals per match for each season is,

= (50 + 60)/(20 + 25).

= 110/45.

= 2.44 goals per match.

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The ogive curve for the data has to be obtained by first converting the data into a continuous class one and then plotting the less than cumulative frequency table obtained.

Here we have the data

0-3.9    4.0-7.9    8.0-11.9    12.0-15.9    16.0-19.9    20.0-23.9    24.0-27.9

  63          26          24              37                23               11                  16

Now first we need to convert this to a continuous distribution

We will get

Classes                  Frequency

-0.95-3.95                   63  

3.95-7.95                     26

7.95-11.95                     24

11.95-15.95                    37

15.95-19.95                   23

19.95-23.95                    11

24.0-27.95                     16

Now we need to construct a less than table

Less than                           Cumulative frequency

3.95                                                    63  

7.95                                                    89

11.95                                                   113

15.95                                                 150

19.95                                                 173

23.95                                                 184

27.95                                                200

Now to make an Ogive curve we need to plot the less than column at the x-axis and the frequency on the y-axis. Then draw a free hand line to connect all the points. This will give us our ogive curve

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Complete Question

A sample of 200 high school students was asked how many hours per week they spend watching television. The following frequency distribution presents the results.

0-3.9    4.0-7.9    8.0-11.9    12.0-15.9    16.0-19.9    20.0-23.9    24.0-27.9

  63          26          24              37                23               11                  16

Construct a relative frequency ogive for the frequency distribution.

Answer:

Solving gives us the result, x = 2, y = -1

Step-by-step explanation:

The system of equations is,

y = 2x-5

y=-2x+3

equating the two equations, we get,

(since y = y)

\(2x-5 = -2x + 3\\4x -5 = 3\\4x = 3+5\\4x=8\\x=8/4\\x=2\)

and then since y = 2x-5

\(y=2(2)-5\\y=-1\)

so, x =2, y = -1