The function f is defined as followed
f(x)=3x^2+1
More info linked please help with proper answer: find the expression for g(x)

(if you are good at this please help with the next two I will post soon after you answer)

Answer:

Infinite number of rational numbers exist between any two distinct rational numbers. We know that a rational number is a number which can be written in the form of qp where p and q are integers and q =0.

In this situation, interval measurement is being employed as the measurement level.

As the height of each student can be measured on a continuous scale with equal intervals between the values. It's important to note that the teacher may have rounded the measurements to the nearest unit, which would make it a discrete measurement.

Interval measurement is a level of measurement in which the values are measured on a continuous scale and have equal intervals between them, but there is no true zero point. This means that the difference between any two values on the scale is meaningful and consistent, but it is not possible to say that one value is "zero" or has no quantity of the measured attribute.

For example, measuring temperature in degrees Celsius or Fahrenheit is an example of interval measurement. In this case, the difference between 10 and 20 degrees is the same as the difference between 20 and 30 degrees, but there is no true zero temperature - a temperature of 0 degrees does not mean the absence of heat.

Another example of interval measurement is measuring time in minutes or hours. The difference between 10 minutes and 20 minutes is the same as the difference between 20 minutes and 30 minutes, but there is no "zero" point in time - even if nothing is happening, time continues to pass.

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Answer:

200 and 100

Step-by-step explanation:

Just did it:)

Answer:

The number of upper-level seats = 200

The number of lower-level seats = 100

Step-by-step explanation:

Given:

x = the number of upper-level seats.

y = the number of lower-level seats.

According to the question:

20x + 30y = 7000

15x + 35y = 6500

Multiply first equation by 3 and second by 4 then subtract them

\(3(20x + 30y) - 4(15x + 35y ) = 3(7000)-4(6500)\\60x+90y-60x-140y=-5000\\-50y=-5000\\y=100\)

Plug y=100 in 20x + 30y = 7000.

\(20x + 30y = 7000\\20x + 30(100) = 7000\\20x+3000=7000\\20x=4000\\x=200\)

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a. The probability that the network crashes on both Monday and Tuesday is 0.1024; b. The probability that the network crashes for the first time on Thursday is 0.1389 ; c. The probability that the network crashes every day is 0.0001; d. The probability that the network crashes on at least one day is 0.3222.

We can approach this problem using the binomial distribution. Let X be the number of days in a week that the network crashes. Then X follows a binomial distribution with parameters n = 5 (number of days in a workweek) and p = 0.16 (probability of a crash on any given day).

a. The probability that the network crashes on both Monday and Tuesday is:

P(X = 2) = (5 choose 2) * (0.16)² * (1-0.16)³

= 0.1024

b. The probability that the network crashes for the first time on Thursday is the probability that it does not crash on Monday, Tuesday, or Wednesday, but does crash on Thursday and/or Friday. So:

P(X = 1) * P(no crashes on Monday, Tuesday, Wednesday) = (5 choose 1) * (0.16) * (1-0.16)⁴ * (0.84)³

= 0.3808 * 0.3652

= 0.1389

c. The probability that the network crashes every day is:

P(X = 5) = (5 choose 5) * (0.16)⁵ * (1-0.16)⁰

= 0.0001

d. The probability that the network crashes on at least one day is the complement of the probability that it does not crash at all during the week:

P(X >= 1) = 1 - P(X = 0)

= 1 - (5 choose 0) * (0.16)⁰ * (1-0.16)⁵

= 1 - 0.6778

= 0.3222

Therefore, a. The probability that the network crashes on both Monday and Tuesday is 0.1024; b. The probability that the network crashes for the first time on Thursday is 0.1389 ; c. The probability that the network crashes every day is 0.0001; d. The probability that the network crashes on at least one day is 0.3222.

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Answer:155.56%.

Step-by-step explanation:To find the percentage increase, we need to calculate the difference between the two prices and divide it by the original price, then multiply by 100 to express the answer as a percentage.

Percentage increase = (New price - Original price) / Original price * 100

Percentage increase = (459 - 180) / 180 * 100

Percentage increase = 279 / 180 * 100

Percentage increase = 155.56%

So the price of the item increased by 155.56%.

Answer:

Scale factor = \(\frac{1}{2}\)

Step-by-step explanation:

Perimeter of the actual flag = 22 in.

Perimeter of the scale drawing of the flag = 11 in.

Since, perimeter of a triangle = Sum of all three sides of the given triangle

Therefore, scale factor of the drawing

= \(\frac{\text{Measure of the side of drawing}}{\text{Measure of the side of actual}}\) = \(\frac{\text{Perimeter of drawing}}{\text{Perimeter of actual}}\)

= \(\frac{11}{22}\)

= \(\frac{1}{2}\)

Therefore, scale factor of the drawing will be \(\frac{1}{2}\).                                        

Each side of the scaled triangle will be half of the actual triangle.

assuming is simple interest

\(~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$960\\ P=\textit{original amount deposited}\dotfill & \$3840\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years \end{cases} \\\\\\ 960 = (3840)(0.05)(t)\implies \cfrac{960}{(3840)(0.05)}=t\implies 5=t\)

The required Matrices are AB is of order 4 × 4. , BA is of order  5 × 5.

Finding the product of a matrix is a difficult task. Only when the inner dimensions are equal—that is, when the sum of the columns of the first matrix and the rows of the second matrix—can the product of two matrices be calculated.

If A is an m × rm × r matrix and B is a r × nr × n matrix, then AB is a product matrix that is a m× nm × n matrix.

A is of size 4 × 5   and   B is of size 5 × 4.

if a matrix P has m rows and n columns, then its size is written as m × n.

Also, two matrices P and Q of sizes m × n and r × s respectively can be multiplies if the number of columns in P is equal to the number of rows in Q.

That is, if n = r. And the size of the matrix P × Q is m × s.

Now, from  the number of columns in A is equal to the number of rows in B, the product A × B is possible and is of order 5 × 5.

Consider , the number of columns in B is equal to the number of rows in A, the product B × A is possible and is of order 4 × 4.

Thus, the required answers are

AB is of order  4 × 4.

BA is of order  5 × 5.

For multiplication, number of column of first = number of row of second matrix.

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Answer:

Amount of water left = 25 / 8 cups

Step-by-step explanation:

Given:

Amount of water teacher Sara have = \(6\frac{7}{8}\) cups = 55 / 8 cups

Amount of water teacher used = 4/8 cups

Amount of water used by student = \(3\frac{2}{8}\) cups = 26 / 8 cups

Find:

Amount of water left

Computation:

Amount of water left = Amount of water teacher Sara have - [Amount of water teacher used + Amount of water used by student]

Amount of water left = [55/8] - [4/8 + 26/8]

Amount of water left = [55/8] - [30/8]

Amount of water left = [55-30] / 8

Amount of water left = 25 / 8 cups

Attached is a two-way frequency table, to help Hugo organize the results.

A two-way frequency table is a table used to organize and display the relationship between two categorical variables. It is constructed by counting the number of occurrences of each combination of categories and presenting the results in a table format.

1. Identify the categorical variables and list their possible categories.

cat, no cat, dog, no dog

2. Count the number of observations for each combination of categories.

cat = 17

no dog = 20

no cat no dog = 7

3. Organize the counts in a table with the categories of one variable as rows and the categories of the other variable as columns.

          | dog | no dog | total

cat      |        |              |   17  |

no cat |        |     7       |        |

total    |        |     20    |   41  |

4. Fill in the table with the counts of the observed combinations of categories.

cat but no dog = 20 - 7 = 13

both cat and dog = 17 -13 = 4

total no cat = 41 - 17 = 24

total dog = 41 - 20 = 21

dog but no cat = 24 - 7 = 17

          | dog | no dog | total

cat      |   4   |      13     |   17  |

no cat |   17  |     7       |   24  |

total    |   21  |     20    |   41  |

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Answer:

C

Step-by-step explanation:

The answer is C, 12 and 13, because the exact square root of 156 is about 12.5. On a number line, 12.5 is in between 12 and 13. Hope this helps, good luck, and God bless!

Answer: its A

sorry if im wrong

The equation 890 = 1/3 B(46)  can be used to find the area of the circular base .

Area is the space enclosed  within the perimeter of the given shape.

It is given in the question that Area of the base of a volcano has to be determined.

The structure of a volcano is that of a Cone

Area of a conical structure is given by

V = (1/3) * height * (radius)²

890 = 1/3 (radius)²(46)

V = 890 h = 46

area of a circle = π (radius)²,

890 = 1/3 B(46)

If B = (radius)²

Therefore Option D is the correct answer

890 = 1/3 B(46)  equation can be used to find the area of the circular base .

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Answer:

31 1/5 miles.

Answer:

D. 1

Step-by-step explanation:

Slope (m) formula:

m = y2 - y1 / x2 - x1

m = 2 - 9 / -4 - 3

m = -7/-7

Negative ÷ Negative = Positive

m = 1

Answer:

a=72° b = 6°

Step-by-step explanation:

answer is in pic

Answer:

20 problems.

Step-by-step explanation:

She has 100 - 65 = 35% of her problems left.

35% is equivalent to 7 problems,

so, 100% = 7 * 100/35

               = 100/5

              = 20 problems

Answer:

Step-by-step explanation:

Something

Step-by-step explanation:

Answer: 3/4 of a cup is 0.75

Step-by-step explanation:

Answer:

J

Step-by-step explanation:

Y, because triangle jhk is similar

The ideal amount of flour for 5 cakes is 40 cups of flour. The ratio of flour to cake for baking is 8 cups of flour for 2 cakes. This means for each cake, there should be 4 cups of flour. Therefore, for 5 cakes, it would be 5 multiplied by 4, which is equal to 40. This amount of flour should be enough to produce moist, light, and fluffy cakes.

If the baker uses more than 40 cups of flour, it could lead to overly dense and dry cakes, because the extra flour will absorb all the moisture and leave the cakes dry. On the other hand, using less than 40 cups of flour could lead to the cakes being too light and airy. Not having enough flour can lead to a dry and tough texture.

Therefore, the baker should use 40 cups of flour when making 5 cakes. Following the 8 cups of flour to 2 cakes ratio ensures that the cakes will have the perfect texture and consistency. This is why 40 cups of flour is the ideal amount for a baker to make 5 cakes.

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Answer:

80-62=18

Step-by-step explanation:

plug in the y, which is 80, then subtract 60 from 80, which is 18, not 28.

In match play, when the players agree to consider the hole tied after it has begun, the ruling is known as "halving the hole."

In match play, if the players agree to consider the hole tied after it has begun, the hole is deemed halved, and the players move on to the next hole without any penalty strokes. This is called "conceding the hole" and is a common practice in match play.

This means that both players receive half a point for the hole, and the match proceeds to the next hole.

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Fitness mania is cheaper as $200 < $240

A. The the restriction on the a-i's needed for W-a to be an unbiased estimator of μ is a-1 + a-2 + a-3 + a-4 = 1.

B. The variance simplifies to Var(W-a) = a-1² × Var(Y-1) + a-2² ×Var(Y-2) + a-3² × Var(Y-3) + a-4² × Var(Y-4).

C. The weights a-i must a-1 = 1/4, a-2 = 1/4, a-3 = 1/4, a-4 = 1/4.

D. The Var(W-a) is twice as large as Var(Y) in this case.

E. The Var(W-a) ≥ Var(Y) holds, demonstrating that Y is the best (least variance) linear unbiased estimator for μ.

To analyze the given problem, through each part step by step:

For the estimator W-a to be unbiased, its expected value E(W-a) must equal the population mean μ. In other words:

E(W-a) = a-1 × E(Y-1) + a_2 × E(Y-2) + a-3 × E(Y-3) + a-4 × E(Y-4) = μ.

Since the Y-i's are an i.i.d. random sample with a common mean μ, we have:

E(Y-i) = μ for i = 1, 2, 3, 4.

To find the variance of W-a, Var(W-a), use the property that the variance of a linear combination of random variables is equal to the corresponding linear combination of their variances. Since the Y_i's are i.i.d. with a common variance σ², we have:

Var(W-a) = a-1² × Var(Y-1) + a-2² × Var(Y-2) + a-3² × Var(Y-3) + a-4² × Var(Y-4) + 2 × a-1 × a-2 × Cov(Y-1, Y-2) + 2 × a-1 × a-3 × Cov(Y-1, Y-3) + 2 ×a-1 × a-4 × Cov(Y-1, Y-4) + 2 × a-2 × a-3 ×Cov(Y-2, Y-3) + 2 × a-2 × a-4 ×Cov(Y-2, Y-4) + 2 × a-3 × a-4 × Cov(Y-3, Y-4).

However, since the Y-i's are assumed to be independent, the covariance terms vanish:

Cov(Y-i, Y-j) = 0 for i ≠ j.

Since the Y-i's have a common variance σ^2, we can further simplify:

Var(W-a) = σ² × (a-1² + a-2² + a-3² + a-4²).

When W-a = Y (the sample average), we have:

a-1 × Y-1 + a-2 × Y-2 + a-3 × Y-3 + a-4 × Y-4 = Y.

Since Y is the sample average,

Y = (Y-1 + Y-2 + Y-3 + Y-4)/4.

Equating the two expressions, we get:

a-1 × Y-1 + a-2 × Y-2 + a-3 × Y-3 + a-4 × Y-4 = (Y-1 + Y-2 + Y-3 + Y-4)/4.

To find a set of weights a-i where the restriction in part (a) is satisfied but W-a ≠ Y,  choose different values for the a-i's. For example:

a-1 = 1/2, a-2 = 1/2, a-3 = 0, a-4 = 0.

W-a will not be equal to Y. However, the restriction a-1 + a-2 + a-3 + a-4 = 1 is still satisfied. To find Var(W-a), we substitute these values into the formula from part (b):

Var(W-a) = σ² × (a-1²+ a-2² + a-3² + a-4²) = σ² × (1/2)² + (1/2)² + 0 + 0 = σ²/2.

Var(Y) = Var((Y-1 + Y-2 + Y-3 + Y-4)/4) = σ²/4.

Comparing Var(W-a) and Var(Y), we see that Var(W-a) = 2 × Var(Y).

The property mentioned, 4(a-1 + a-2 + a-3 + a-4)² ≤ a-1² + a-2²+ a-3² + a-4², ensures that Var(W-a) ≥ Var(Y) holds for any values of a-i that satisfy the restriction in part (a). By substituting the restriction into the left-hand side of the property and multiplying both sides by σ², we obtain:

Var(W-a) = σ² ×(a-1² + a-2² + a-3² + a-4²) ≥ σ² × 4(a-1 + a-2 + a-3 + a-4)² = 4σ².

Since Var(Y) = σ²/n, where n is the sample size, we have Var(Y) ≤ σ².

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Answer:

look at the screenshot

Step-by-step explanation:

Answer:

Step-by-step explanation:

Candice = 25mph for 4 hours.

Candice has driven= 25 * 4= 100miles.

Liz =50mph

Liz time to catch up to candice= 50 * 2= 100miles.

Therefore, It would have taken Liz two hours to catch up with Candice

Answer:

I hope this helps you:)

Step-by-step explanation:

The given function f(x) =3x² - 48/2x+8 has no Horizontal asymptote.

A horizontal asymptote may be defined as a horizontal line at which the graph of the function will appear to meet but will not actually meet. It is a tool to determine the end behavior of the function. We are given the function f(x) = 3x² - 48/2x+8. Now to find horizontal asymptote of this function we first find lim ₓ→∞ f(x) that is

lim ₓ→∞ (3x² - 48)/(2x + 8)

lim ₓ→∞ 3/2(x - 4) = ∞

Now, we calculate lim ₓ→-∞ f(x) that is

lim ₓ→-∞ (3x² - 48)/(2x + 8)

lim ₓ→-∞ 3/2(x - 4) = -∞

Since, both the limits are different therefore function does not have any horizontal asymptote.

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The probability for choosing a bead is given as follows:

0.16 = 16%.

The parameters that are needed to calculate a probability are listed as follows:

Then the probability is then calculated as the division of the number of desired outcomes by the number of total outcomes.

The total number of outcomes in this problem is given as follows:

24 + 42 + 84 = 150.

Out of those, 24 are beads, hence the probability is given as follows:

24/150 = 12/75 = 0.16 = 16%.

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