The Fruit Juice Company sold 6,909,999,222 cans of juice last year. This year the company sold 4,999,002,135 cans. Which is the best estimate of how many more cans were sold last year than this year?

Answer: 45

Step-by-step explanation:

The total profit in all was \(1040-900=\$ 140\).

The total profit per pizza was \((0.50)(8)=\$4\).

This means they sold \(\frac{140}{4}=35\) pizzas.

Adding this to the 10 pizzas held back, there were \(35+10=45\) pizzas in the original order.

Answer:

Brand A  Costs 37.38 per ounce and Brand B cost 31.19 per ounce hope this helped ^-^

Answer:

c. Weights of babies are normally distributed

Step-by-step explanation:

The research has been conducted to identify the weight of new born babies in comparison to the weight of their mother. The samples are collected from young mothers who are at age of 16 to 18. The babies average weight turned out to be 7.3 pounds. It is assumed that the weight of babies is normally distributed.

Answer:

The answer is 46,440.

Step-by-step explanation:

108/100 * 43,000= 46,440

Answer

Mitchell now makes $46,440.

Step-by-step explanation:

108/100 * 43,000= 46,440

Hope this helped <3

Answer:

9/10 bc it would be .90 in decimals

Step-by-step explanation:

Answer:

9/10 is

Step-by-step explanation:

9/10 as a decimal is 0.9 and if you line them up, 0.9 is greater than 0.45

Answer:

1. Decimal: 0.1 Fraction: 1/10

2. Decimal: 0.8 Fraction: 8/10

3. Decimal: 0.4 Fraction: 4/10

4. Decimal: 0.6 Fraction: 6/10

5. Decimal: 0.7 Fraction: 7/10

Explaination:

brainliest me if it helps!

Answer:

Step-by-step explanation:

Answer:

Cluster sampling

Step-by-step explanation:

The kind of sampling described here is cluster sampling. In the cluster sampling method, a population is divided into clusters. Some of these clusters would then be randomly selected as samples. Each cluster is a mini representation of the entire population. The researcher in cluster sampling studies the whole clusters.

In this question we have a cluster of colleges that have been selected and a poll of all employees in these clusters.

This makes the answer cluster sampling

If only 2,836 students were admitted into the Ateneo among 27,813 students, who took the ACET this year, the Ateneo’s acceptance rate is b. 10.2%.

The rate is the ratio of one value, expression, measurement, or quantity compared to another.

The rate represents the quotient of the numerator and the denominator.

The rate is expressed as a percentage by multiplication with 100.

The number of students who took the ACET this year = 27,813

The number of students who were admitted into the Ateneo = 2,836

The percentage or rate admitted = 10.19667% (2,836 ÷ 27,813 × 100)

= 10.2%

Thus, we can conclude that the acceptance rate or percentage is Option B.

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Answer:

Step-by-step explanation:

2

Answer: letter B (answer is 2)

Step-by-step explanation:

Answer: $8

Step-by-step explanation:

one adult ticket costs twice as much as one student ticket so

cost of 1 student ticket=x

cost of one adult ticket=2x

total money made=1040

adults+students=1040 so

64(2x)+132(x)=1040

128x+132x=1040

260x=1040

divide both sides by 260

x=4

1 student ticket=$4

1 adult ticket=2x=2(4)=$8

Ike- I went geek sorry..

It should be noted that a dot plot, is also known as a strip plot or the dot chart. It is a form of data visualization which consists of the data points that are plotted as dots on a graph with an x- and y-axis.

Your information is incomplete. Therefore, an overview will be given.It should be noted that fit plots are tge types of charts that are used to graphically show certain data trends or groupings

A dot plot is the graphical display of data using dots. It should be noted that a good example is the choice of foods that one and their friends ate for snacks.

A dot plot is a graphical display that is used in statistics that uses dots to represent data. They can be used for univariate data; which is, data with only one variable which is being measured. They are useful when the variable is quantitative.

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Answer:

I got

2x^4u^4-6+9x^3u^2/ux^2

Step-by-step explanation:

Photo wrong only at the end u^2

\(h^{2}=6*6\\h^{2}=36\\h=6\\and\\ y=45\)

Answer:

If the base and the negative exponent is in the denominator already

Step-by-step explanation:

Normally, a base with a negative exponent moves to the denominator.

Example: (2^-3 = 1 / (2)^3 = 1/8)

However, if the base and the negative exponent is already in the denominator, the base would move to the numerator and the exponent would become positive.

Example:  2 / (3)^-3 = 2 * 3^3 = 2 * 27 = 54

Answer:

D.

Step-by-step explanation:

6a² = surface area for cube

6(5)² = 150

2\(\pi\)(r)(h)+2\(\pi\)r²  = surface area cylinder

2\(\pi\)(2)(3)+2\(\pi\)(4) = 20pi

150 + 20pi = 212.8318531

Therefore, out of the 24 students that Blake interviewed, 9 of them participate in sports.

An equation is a mathematical statement that indicates that two expressions are equal. It typically consists of variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. The expressions on both sides of the equation are separated by an equal sign "=" which means that the two expressions have the same value.

Here,

According to the table, Blake interviewed a total of 24 students. To find out how many of these students participate in sports, we need to add up the number of students who collect sports cards and participate in sports, as well as the number of students who do not collect sports cards and participate in sports. So:

Total students who participate in sports = Number of students who collect sports cards and participate in sports + Number of students who do not collect sports cards and participate in sports

Total students who participate in sports = 6 + 3

Total students who participate in sports = 9

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The correct answer is B. Stratified sampling is​ used since the field is divided into subplots and a random sample is taken from each subplot.

Explanation:

Sampling refers to the process followed by researchers to select a group of individuals from a larger group; considering in most studies it is not possible to analyze all the population. In the case of stratified sampling, this involves dividing the general population into smaller groups, which are known as strata; after this, the researcher selects a specific number of individuals from each strata. This method guarantees the sample is selected randomly, and therefore the study is not biased. Stratified sampling was the method used in the example described because, in this, the general population (46-acre field) was divided into subplots that represent the strata. Also, after this, the researcher selected one random sample.

Answer:

\( \sf \huge \boxed{ \boxed{(b + \frac{2}{3} )(b - \frac{2}{3} )}}\)

Step-by-step explanation:

Answer:

Solution given:

\(b^{2} -\frac{4}{9}\)=\(b^{2} -\frac{2^2}{3^2}=b^2 -(\frac{2}{3})^2\)

it is in the form of x²-y²=(x+y)(x-y)

so

\(b^2 -(\frac{2}{3})^2=(b+\frac{2}{3})(b-\frac{2}{3})\) is A required polynomial.

Step-by-step explanation:

The spherical coordinates of the given rectangular coordinates are (10, 0, 60).

The cartesian coordinate or rectangular coordinates describes the location of a point in space using an ordered triple where each coordinate represents a distance. The spherical coordinate system describes the location of a point in space using an ordered triple where coordinate describes one distance and two angles. In the spherical coordinate system, a point is represented by the ordered triple (ρ, θ, φ).

The equations which are used to convert from rectangular coordinates to spherical coordinates are:

ρ^2=x^2+y^2+z^2

tan⁡〖θ= y/x〗

φ=arccos⁡〖z/√(x^2+y^2+z^2 )〗

The given rectangular coordinates are (5√3, 0, 5). Hence,

ρ^2=〖(5√3)〗^2+0^2+5^2 ≈ 100

ρ ≈ √100 ≈ 10

tan⁡〖θ= 0/(5√3)=0〗

θ=  tan^(-1)⁡0=0

φ=arccos⁡〖5/√(〖(5√3)〗^2+0^2+5^2 )〗= arccos 5/10=arccos⁡0.5 ≈ 60

Note:  The question is incomplete. The complete question probably is: Convert from rectangular to spherical coordinates. (Use symbolic notation and fractions where needed. Give your answer as a point's coordinates in the form (*,*,*). (5√3, 0, 5)

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The reason why the two percentages are different is that the sample does not reflect the characteristics of all the units of blood.

Sampling is a statistical technique in which a sample of a statistical population is selected for the study. The objective of sampling is to ensure that its properties can be extrapolated to the total population.

Sampling is a way of saving resources, and at the same time obtaining results similar to those that would be achieved if a study of the entire population were carried out.

According to the above, the clinical researcher who selected a sample of the available blood units obtains different percentages because he selected randomly and this can modify the quantities of samples according to blood type.

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Answer: 1.45

Step-by-step explanation:

Answer

approximately 0.0067

Step-by-step explanation:

If you multiply 0.0067 with 16,500 you get about 110.55 and the more you keep going with the 6, the closer it gets to 110$.

Answer:

Step-by-step explanation

I:

Answers are in bold

S1 = 1

S2 = 0.5

S3 = 0.6667

S4 = 0.625

S5 = 0.6333

=========================================================

Explanation:

Let \(f(n) = \frac{(-1)^{n+1}}{n!}\)

The summation given to us represents the following

\(\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=\sum_{n=1}^{\infty} f(n)\\\\\\\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=f(1) + f(2)+f(3)+\ldots\\\\\)

There are infinitely many terms to be added.

-------------------

The partial sums only care about adding a finite amount of terms.

The partial sum \(S_1\) is the sum of the first term and nothing else. Technically it's not really a sum because it doesn't have any other thing to add to. So we simply say \(S_1 = f(1) = 1\)

I'm skipping the steps to compute f(1) since you already have done so.

-------------------

The second partial sum is when things get a bit more interesting.

We add the first two terms.

\(S_2 = f(1)+f(2)\\\\S_2 = 1+(-\frac{1}{2})\\\\S_2 = \frac{1}{2}\\\\S_2 = 0.5\\\\\\\)

The scratch work for computing f(2) is shown in the diagram below.

-------------------

We do the same type of steps for the third partial sum.

\(S_3 = f(1)+f(2)+f(3)\\\\S_3 = 1+(-\frac{1}{2})+\frac{1}{6}\\\\S_3 = \frac{2}{3}\\\\S_3 \approx 0.6667\\\\\\\)

The scratch work for computing f(3) is shown in the diagram below.

-------------------

Now add the first four terms to get the fourth partial sum.

\(S_4 = f(1)+f(2)+f(3)+f(4)\\\\S_4 = 1+(-\frac{1}{2})+\frac{1}{6}-\frac{1}{24}\\\\S_4 = \frac{5}{8}\\\\S_4 \approx 0.625\\\\\\\)

As before, the scratch work for f(4) is shown below.

I'm sure you can notice by now, but the partial sums are recursive. Each new partial sum builds upon what is already added up so far.

This means something like \(S_3 = S_2 + f(3)\) and \(S_4 = S_3 + f(4)\)

In general, \(S_{n+1} = S_{n} + f(n+1)\) so you don't have to add up all the first n terms. Simply add the last term to the previous partial sum.

-------------------

Let's use that recursive trick to find \(S_5\)

\(S_5 = [f(1)+f(2)+f(3)+f(4)]+f(5)\\\\S_5 = S_4 + f(5)\\\\S_5 = \frac{5}{8} + \frac{1}{120}\\\\S_5 = \frac{19}{30}\\\\S_5 \approx 0.6333\)

The scratch work for f(5) is shown below.

Answer:

See Below:

Step-by-step explanation:

Average is take by adding all the terms together and dividing by the number of terms. In this case it terms is people in the room.

22= (25+18+17+13+24+x)/6

Where 22 is the average age. The numerator is all the known ages added together, plus x which is the age of the person who just entered. Divided by 6 because you are finding the average age of 6 people.

22 = (25+18+17+13+24+x)/6     Multiply both sides by 6

132= 97+ x  Subtract 97 from both sides.

35 = x

The person who just entered the room is 35 years old.

Answer:7 x 2 − 14 x + 5

Step-by-step explanation:

1 In general, given a{x}^{2}+bx+cax  

2

+bx+c, the factored form is:

a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a})

a(x−  

2a

−b+  

b  

2

−4ac

​

​

)(x−  

2a

−b−  

b  

2

−4ac

​

​

)

2 In this case, a=7a=7, b=-14b=−14 and c=5c=5.

7(x-\frac{14+\sqrt{{(-14)}^{2}-4\times 7\times 5}}{2\times 7})(x-\frac{14-\sqrt{{(-14)}^{2}-4\times 7\times 5}}{2\times 7})

7(x−  

2×7

14+  

(−14)  

2

−4×7×5

​

​

)(x−  

2×7

14−  

(−14)  

2

−4×7×5

​

​

)

3 Simplify.

7(x-\frac{14+2\sqrt{14}}{14})(x-\frac{14-2\sqrt{14}}{14})

7(x−  

14

14+2  

14

​

​

)(x−  

14

14−2  

14

​

​

)

4 Factor out the common term 22.

7(x-\frac{2(7+\sqrt{14})}{14})(x-\frac{14-2\sqrt{14}}{14})

7(x−  

14

2(7+  

14

​

)

​

)(x−  

14

14−2  

14

​

​

)

5 Simplify  \frac{2(7+\sqrt{14})}{14}  

14

2(7+  

14

​

)

​

  to  \frac{7+\sqrt{14}}{7}  

7

7+  

14

​

​

.

7(x-\frac{7+\sqrt{14}}{7})(x-\frac{14-2\sqrt{14}}{14})

7(x−  

7

7+  

14

​

​

)(x−  

14

14−2  

14

​

​

)

6 Simplify  \frac{7+\sqrt{14}}{7}  

7

7+  

14

​

​

  to  1+\frac{\sqrt{14}}{7}1+  

7

14

​

​

.

7(x-(1+\frac{\sqrt{14}}{7}))(x-\frac{14-2\sqrt{14}}{14})

7(x−(1+  

7

14

​

​

))(x−  

14

14−2  

14

​

​

)

7 Remove parentheses.

7(x-1-\frac{\sqrt{14}}{7})(x-\frac{14-2\sqrt{14}}{14})

7(x−1−  

7

14

​

​

)(x−  

14

14−2  

14

​

​

)

8 Factor out the common term 22.

7(x-1-\frac{\sqrt{14}}{7})(x-\frac{2(7-\sqrt{14})}{14})

7(x−1−  

7

14

​

​

)(x−  

14

2(7−  

14

​

)

​

)

9 Simplify  \frac{2(7-\sqrt{14})}{14}  

14

2(7−  

14

​

)

​

  to  \frac{7-\sqrt{14}}{7}  

7

7−  

14

​

​

.

7(x-1-\frac{\sqrt{14}}{7})(x-\frac{7-\sqrt{14}}{7})

7(x−1−  

7

14

​

​

)(x−  

7

7−  

14

​

​

)

10 Simplify  \frac{7-\sqrt{14}}{7}  

7 7−  14  to  1-\frac{\sqrt{14}}{7}1−  7 14

7(x-1-\frac{\sqrt{14}}{7})(x-(1-\frac{\sqrt{14}}{7}))

7(x−1−  7 /14 )(x−(1−  7 14 )) 11 Remove parentheses.

7(x-1-\frac{\sqrt{14}}{7})(x-1+\frac{\sqrt{14}}{7})

7(x−1−  7/ 14 .7(x−1+ 7 14 )

The selection can be made in 15 different ways, taking into account the distinct combinations of a boy and a girl from the given group of 5 boys and 3 girls.

To determine the number of ways a boy and a girl can be selected from a group of 5 boys and 3 girls to attend a conference, we can use the concept of combinations.

The number of ways to choose one boy from 5 boys is 5C1, which is equal to 5. Similarly, the number of ways to choose one girl from 3 girls is 3C1, which is equal to 3.

To select one boy and one girl, we need to multiply the number of ways to choose a boy and a girl together. Using the multiplication principle, we multiply the number of choices for each category: 5C1 * 3C1 = 5 * 3 = 15.

Therefore, there are 15 ways to select a boy and a girl from the given group to attend the conference.

Each combination represents a unique pair consisting of one boy and one girl. For example, if the boys are labeled as B1, B2, B3, B4, and B5, and the girls are labeled as G1, G2, and G3, the possible pairs could be (B1, G1), (B1, G2), (B1, G3), (B2, G1), (B2, G2), and so on, up to (B5, G3).

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