The fraction 4/10 can be written as what

Answer:

C

Step-by-step explanation:

Angle 7 is congruent to angle 5 by the corresponding angles theorem, and angles 5 and 12 are supplementary because they are consecutive interior angles.

Thus, angles 7 and 12 are supplementary.

The axiom of regularity is a set theory principle which states that every non-empty set C contains an element that is disjoint from C.

The set theory concept rules that for every non-empty set C there is an element x of C such that x does not intersect C. The regularity axiom aims to establish that no non-empty set will have itself as an element.

The principle which is also called the axiom of foundation is a fundamental concept in set theory and credited to Zermelo–Fraenkel.

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Answer:

--------------------------

Find the difference of the initial and used amounts:

Answer:

N = 5

Step-by-step explanation:

6 (2n - 8) = 12

12n - 48 = 12

12n = 60

n = 5

HOPE THIS HELPS

PLZZ MARK BRAINLEIST

Answer:

5 = n (i think)

Step-by-step explanation:

6(2(5)- 8) = 12

6(10 - 8)= 12

6 (2) = 12

Based on the task content given; the solution to the equation for x 3 1/2(2 1/5x - 4 2/3) - 5 5/6 = 0 is 2 203/231

3 1/2(2 1/5x - 4 2/3) - 5 5/6 = 0

(3 1/2 × 2 1/5x) - (3 1/2 × 4 2/3) - 5 5/6 = 0

(7/2 × 11/5x) - (7/2 × 14/3) - 35/6 = 0

77/10x - 98/6 - 35/6 = 0

77/10x = 98/6 + 35/6

77/10x = 98+35 / 6

77/10x = 133/6

x = 133/6 ÷ 77/10

= 133/6 × 10/77

= 1330/462

x = 2 406/462

= 2 203/231

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Answer:

I think its +10 above surface

The correct equation of exponential function is  \(f(x) = 6 * (\frac{1}{3} )^x\)

What is an exponential function?

An exponential function is one that has the formula f (x) = \(a^{x}\), where x is a variable and a constant that serves as the function's base and must be greater than 0.

Given,

         starting value = 6

          constant ratio = 1/3

The general form of an exponential function

                \(f(x) = ab^{x}\)

      where a = starting value i.e when x = 0

                  b = rate of change in exponential equation

  So substituting our given values in the above equation, the exponential function is

           \(f(x) = 6 * (\frac{1}{3} )^x\)

Now the value 6 can be divided by 3 only if the value of x = 1

          \(f(1) =\frac{6}{3} = 2\)

If x = 5, then equation becomes,

          \(f(5) = 6 * (\frac{1}{3} )^5 = \frac{2}{81}\)

So we cannot simply divide 6 by 3 without considering the value of x.

Therefore the correct equation of exponential function is

           \(f(x) = 6 * (\frac{1}{3} )^x\)

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The system of equations as an augmented matrix is \(\left[\begin{array}{ccc|c}1&0&0&100\\0&-5&-7&350\\0&-5&-9&200\end{array}\right]\)

From the question, we have the following parameters that can be used in our computation:

x                  = 100

   -5m  - 7c  = 350

   -5m  - 9c  = 200

The above means that the variables in the system of equations are

x, m and c

So, we have the following representation

x    m     c        

1    0      0        100

0   -5    -7        350

0   -5    -9        200

When represented as an augmented matrix, we have

\(\left[\begin{array}{ccc|c}1&0&0&100\\0&-5&-7&350\\0&-5&-9&200\end{array}\right]\)

Hence, the augmented matrix is \(\left[\begin{array}{ccc|c}1&0&0&100\\0&-5&-7&350\\0&-5&-9&200\end{array}\right]\)

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Given the set of equations:

y - 3x = 5

2x - y = -2

Let's graph the set of equations.

Rewrite the equations in slope intercept form:

y = mx + b

Where m is the slope and b is the y-intercept

Let's rewrite both equations for y.

Equation 1:

y - 3x = 5

Add 3x to both sides of the equation:

y - 3x + 3x = 3x + 5

y = 3x + 5

Equation 2:

2x - y = -2

Subtract 2x from both sides:

2x - 2x - y = -2x - 2

-y = -2x - 2

Divide all terms by -1:

Thus, we have both equations in slope intercept form:

y = 3x + 5

y = 2x + 2

To graph, let's mark two points each from each equation.

y = 3x + 5

When x = 1

y = 3(1) + 5 = 3 + 5 = 8

When x = -1

y = 3(-1) + 5 = -3 + 5 = 2

Mark the points on the graph and connect using a straight line:

(x, y) ==> (1, 8) and (-1, 2)

• y = 2x + 2

When x = 1

y = 2(1) + 2 = 2 + 2 = 4

When x = -1

y = 2(-1) + 2 = -2 + 2 = 0

Mark the points on the graph and connect using a straight line:

(x, y) ==> (1, 4) and (-1, 0)

Thus, we have the graph below:

From the graph, we can see the point where both lines meet is at (-3, -4).

This means the solution to the set of equations is: (-3, -4)

Answer:

39

Step-by-step explanation:

a=A=1521=39

Thomas' installment payment that he pays in one fortnight is approximately k523.08.

To calculate Thomas' installment payment, we need to consider the principal amount (k10,000) and the interest rate (36%).

First, let's calculate the total amount to be repaid at the end of the year, including the interest. The interest is calculated as a percentage of the principal amount:

Interest = Principal × Interest Rate

= k10,000 × 0.36

= k3,600

The total amount to be repaid is the sum of the principal and the interest:

Total Amount = Principal + Interest

= k10,000 + k3,600

= k13,600

Now, we need to calculate the number of fortnights in a year. There are 52 weeks in a year, and since each fortnight consists of two weeks, we have:

Number of Fortnights = 52 weeks / 2

= 26 fortnights

To find the installment payment for each fortnight, we divide the total amount by the number of fortnights:

Installment Payment = Total Amount / Number of Fortnights

= k13,600 / 26

≈ k523.08

Therefore, Thomas' installment payment that he pays in one fortnight is approximately k523.08.

It's important to note that this calculation assumes equal installment payments over the course of the year. Different repayment terms or additional fees may affect the actual installment amount. It's always advisable to consult with the bank or financial institution for accurate information regarding loan repayment.

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Answer:

Suppose that a white ball is selected, the probability that the coin landed tails = (12/37) = 0.3243

Step-by-step explanation:

Complete Question

Urn A has 5 white and 7 black balls. Urn B has 3 white and 12 black balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a white ball is selected. What is the probability that the coin landed tails?

Solution

Let the probability of that a head turns up and urn A is selcted be P(A) = (1/2)

Probability that a tail turns up and urn B is selected = P(B) = (1/2)

Probability that a white ball is picked = P(W)

The probability that a white ball is picked given that the coin toss gives a head and urn A is selected = P(W|A) = (5/12)

The probability that a white ball is picked given that the coin toss gives a tail and urn B is selected = P(W|B) = (3/15) = (1/5)

We now require the probability that the coin lands on a tail and urn B is selected given that a white ball is picked, P(B|W)

Note that the conditional probability P(X|Y) is expressed mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

And P(X n Y) = P(X|Y) × P(Y)

Hence, the required probability

P(B|W) = P(B n W) ÷ P(W)

Although, we do not have the probabilities P(B n W) and P(W), we can calculate them

P(B n W) = P(W n B) = P(W|B) × P(B) = (1/5) × (1/2) = (1/10)

P(W) = P(W n A) + P(W n B) (Since the events A and B are mutually exclusive)

P(W n A) = P(W|A) × P(A) = (5/12) × (1/2) = (5/24)

P(W n B) = (1/10)

P(W) = (5/24) + (1/10) = (37/120)

P(B|W) = P(B n W) ÷ P(W) = (1/10) ÷ (37/120) = (12/37) = 0.3243

Hope this Helps!!!

Answer:

Below

Step-by-step explanation:

The equation to use for CONTINUOUS compounding is :

FV = PV e^(it)

18532.08 = 8327 * e^( i*10)        where i is the interest in decimal form

18532.08/8327  = e^(10i)

2.225541 = e^(10i)             now take natural log  (ln) of both sides to get

.8000 = 10i

i = .08     or 8% interest

The solution to the system is x = -6 and y = 4.

To solve the system by the addition method, we want to add the equations together in a way that will eliminate one of the variables.

Let's start by multiplying the first equation by -3 to get -3x - 9y = -18, and then add the second equation to it:

-3x - 9y = -18

+ 3x + 4y = -2

-------------

    -5y = -20

Now we can solve for y by dividing both sides by -5:

y = 4

We can substitute y=4 into one of the original equations, say x+3y=6, to solve for x:

x + 3(4) = 6

x + 12 = 6

x = -6

So the solution to the system is x = -6 and y = 4.

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Step-by-step explanation:

(x-2)^2 + (y-9)^2   = r^2

this is of the form fora circle with center  h,k and radius r

(x-h)^2 + (y-k)^2 = r^2

for the equation given   center =   2, 9    and radius = r

\(\begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{logarithm of factors} \\\\ \log_a(xy)\implies \log_a(x)+\log_a(y) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\(\log(x)=2\hspace{5em}\log(y)=3\hspace{4em}\log(2)\approx 0.3\hspace{4em}\log(3)\approx 0.48 \\\\[-0.35em] ~\dotfill\\\\ \log\left(\sqrt[3]{x^4\cdot y^2} \right)\implies \log\left(\left( x^4\cdot y^2 \right)^{\frac{1}{3}} \right)\implies \cfrac{1}{3}\log(x^4 y^2) \\\\\\ \cfrac{1}{3}[\log(x^4)~~ + ~~\log(y^2)]\implies \cfrac{1}{3}[4\log(x)~~ + ~~2\log(y)]\implies \cfrac{1}{3}[4(2)~~ + ~~2(3)] \\\\\\ \cfrac{1}{3}[8~~ + ~~6]\implies {\Large \begin{array}{llll} \cfrac{14}{3} \end{array}}\)

Answer:

\( - 104 = 8x \\ x = \frac{ - 104}{8} \\ x = - 13 \\ thank \: you\)

Answer:

\(\boxed {\boxed {\sf x= -13}}\)

Step-by-step explanation:

We are asked to solve the following one-step equation.

\(-104 = 8x\)

We solve the equation by solving for x. We must isolate the variable by performing the inverse operation.

x is being multiplied by 8 (8x = 8*x). The inverse operation of multiplication is division. Divide both sides of the equation by 8. This eliminates the 8 on the right side of the equation so only x remains.

\(\frac {-104}{8}= \frac{8x}{8}\)

\(\frac {-104}{8}= x\)

\(-13=x\)

We can check our answer by substituting it back into the original equation.

\(-104= 8x\)

\(-104= 8(-13)\)

\(-104= -104\)

This checks out, so we know our answer is correct and x is equal to -13.

Answer:

\(\text{27}\)

Step-by-step explanation:

Given that :

\(\text{Dimension of poster board} = 1 \ \text{yd} \ \text{by} \ 1 \ \text{yd}\)

\(\text{Dimension of each poster board} = \dfrac{1}{3} \ \text{yd} \ \text{by} \ \dfrac{1}{9} \ \text{yd}\)

Number of poster signs that can be cut :

\(\text{Area of poster sign} = \dfrac{1}{3} \times \dfrac{1}{9} = \dfrac{1}{27} \ \text{yard}^2\)

\(\text{Area of poster board} = 1 \ \text{yard}^2\)

Number of poster signs that can be cut :

\(\dfrac{\text{Area of poster board}}{\text{Area of poster sign}}\)

\(1 \ \text{yard}^2\div (\dfrac{1}{27} ) \ \text{yard}^2\)

\(1 \div \dfrac{1}{27}\)

\(1 \times \dfrac{27}{1}\)

\(\bold{= 27 \ poster \ signs}\)

Answer: option D

Step-by-step explanation:

Given equation:

P = 6 w + 8 [eq1]

l=2w+4 [where l is length]

using eq1 we have:

6w=P-8

w=(P-8)/6

hence  option D

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Step-by-step explanation:

kindly find attached detailed information of the remaining information as requested for your reference

1. The lower class limit is the left number in the age column

   i.e in the 25-34 the lower class limit is 25          

2. The upper class limit is the right number in the age column

   i.e in the 25-34 the lower class limit is 34

3. The class width is the difference  between the class boundaries of a single class

 class width = 34.5-24.5= 10

4. The number of individuals is= 29+34+16+3+5+1+2= 90    

Answer:

-11/12 − 1/6

-3/5 + 3/20

-2/3 + 1/12

Step-by-step explanation:

Answer: KL = KN LM=NO=9 Side-Side-Side

Step-by-step explanation:

The required answers to the question is given below.

Triangle congruence: If all three corresponding sides and all three corresponding angles are equal in size, two triangles are said to be congruent. Slide, twist, flip, and turn these triangles to create a similar appearance. They are in alignment with one another when moved. "≅" is the congruence symbol.

Use the following figure to understand the answer.

The Proof is

1. KM=KO=5 (GIven)

2. MN=3 (Given)

3. KN=KM+MN=8 (because the lengths are equal to the sum of their parts.)

4. KL=8 (Given)

5. KL=KN (from 3,4 substitution)

6. NO=ML=9 (Given)

7. ΔKLM=ΔKNO the congruence criterion used is SSS congruence.

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The volume of the first and second solid shapes are 3014.4m³ and 360ft³ respectively.

The first shape comprises of a cone and a cylinder, and the volume is derived as follows:

volume of the cone = 1/3 × 3.14 × (8m)² × 5m

volume of the cone = 1004.8m³

volume of the cylinder = 3.14 × (8m)² × 0m

volume of the cylinder = 2009.6 m³

volume of the first solid shape = 1004.8m³ + 2009.6 m³

volume of the first solid shape = 3014.4m³

The second solid shape comprises of a trianglular prism and a cuboid

volume of the trianglular prism = base area × height

base area = 1/2 × 6ft × 4ft = 12ft²

volume of the trianglular prism = 12ft² × 6ft

volume of the trianglular prism = 72ft³

volume of the cuboid = 12ft × 6ft × 4ft

volume of the cuboid = 288ft³

volume of the second solid shape = 72ft³ + 288ft³

volume of the second solid shape = 360ft³

Therefore, the volume of the first and second solid shapes are 3014.4m³ and 360ft³ respectively.

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Answer:

 (a) isosceles

 (b), (c) scalene

Step-by-step explanation:

The lengths of the sides can be found from the distance formula:

 d = √((x2 -x1)^2 +(y2 -y1)^2)

Here, there are 9 lengths to be computed, so it is useful to let a spreadsheet or graphing calculator do it.

We find triangle (a) has two sides the same length, so it is isosceles.

The other two triangles have three different side lengths, so they are scalene.

_____

Additional comment

It is impossible to specify an equilateral triangle using rational coordinates.

There are total 15 students per teacher and 8 students per tutor. For 100 students, total 13 tutors are required.

The four fundamental operations of arithmetic are addition, subtract, multiply, and division of two or more numbers. Included in them is the study of integers, especially the order of operations, which is important for all other aspects of mathematics, notably algebra, information management, and geometry.

As per the given data provided in the question,

4 teachers  = 60 students

For 1 teacher = 60/4 = 15 students

Similarly,

6 tutors = 48 students

For 1 tutor = 48/6 = 8 students.

For total 100 students, total number of tutors = 100/8

= 12.5 or 13 tutors are required.

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Answer:

C.) The relationship is proportional

Step-by-step explanation:

If D is true, then it is not proportional, constants of proportionality must not include multuplting or subtracting from anything.

Also quick way to tell— the line doesn’t start from 0,0

if the equation has a slope of 0, then it's a horizontal line, and in this case, that line is 1 because 1 = 0+B and b=1

the answer is y=1

Answer:

First option, y=1

Step-by-step explanation:

linear eq: y=mx+b, slope m=0, then equation is like y=b (here we have y value as 1)

thus, y=1

By analyzing the graph and evaluating the objective function at each vertex of the feasible region, we can find the optimal solution, which is the vertex that maximizes the objective function z = 3x + y.

To find the optimal solution of the given problem using the graphical method, we need to plot the feasible region determined by the given constraints and then identify the point within that region that maximizes the objective function.

Let's start by graphing the constraints:

1. Plot the line 2x - y = 5. To do this, find two points on the line by setting x = 0 and solving for y, and setting y = 0 and solving for x. Connect the two points to draw the line.

2. Plot the line -x + 3y = 6 using a similar process.

3. The x-axis and y-axis represent the constraints x ≥ 0 and y ≥ 0, respectively.

Next, identify the feasible region, which is the region where all the constraints are satisfied. This region will be the intersection of the shaded regions determined by each constraint.

Finally, we need to identify the point within the feasible region that maximizes the objective function z = 3x + y. The optimal solution will be the vertex of the feasible region that gives the highest value for the objective function. This can be determined by evaluating the objective function at each vertex and comparing the values.

Note: Without a specific graph or additional information, it is not possible to provide the precise coordinates of the optimal solution in this case.

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The population after 68 years from now is 160, 000.

A relation of the form y = \(a^x\), with the independent variable x ranging over the entire real number line as the exponent of a positive number a.

Given:

10000 is the initial population

2 is the rate at which the population grows

68/17 is the number of periods that the population grows

Now, using Exponential function the population can be represented as

= 10000 x \(2^{(68/17)}\)

= 10000 x \(2^{(4)}\)

= 10000 x 16

= 160, 000

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