the formation of which of the following rocks helps remove co2 from the atmosphere?

Answer:

Explanation:

The octet rule allows chemists to predict the placement of electrons around the nucleus (electron orbitals), the identification of electrons added or lost during chemical reactions and the chemical reactivity of atoms based upon their particular electron configuration.

Answer:

plastic

Explanation:

plastic doesn't conduct electricity

A 30 g metal is heated to 100.0°C and placed in 100 grams of 30°C water. If the final temperature of the system is 35°C, the specific heat of the metal is 0.82 J/g°C.

To solve for the specific heat of the metal, we can use the equation:
qmetal = -qwater
where qmetal is the heat gained by the metal and qwater is the heat lost by the water.
First, let's calculate the heat lost by the water:
qwater = mwater x Cwater x ΔTwater
qwater = 100 g x 4.18 J/g°C x (35°C - 30°C)
qwater = 2090 J
Next, let's calculate the heat gained by the metal:
qmetal = Cmetal x mm x ΔTmetal
qmetal = Cmetal x 30 g x (35°C - 100°C)
qmetal = -2550 Cmetal
Since qmetal = -qwater, we can set them equal to each other:
-Cmetal x 2550 J = 2090 J
Solving for Cmetal:
Cmetal = 2090 J / (2550 J/°C)
Cmetal = 0.82 J/g°C

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The equilibrium constant, K, for the reaction H2(g) + I2(g) ⇄ 2HI(g) can be calculated using the expression K= [HI]2/([H2][I2]). Since the concentrations of H2, I2, and HI are given in the question, we can calculate the equilibrium constant, K, for the reaction.

K = [HI]2/([H2][I2]) = (1.77 × 10-2)2/((1.83 × 10-3)(3.13 × 10-3)) = 4.43 × 104. Therefore, the equilibrium constant, K, for the reaction H2(g) + I2(g) ⇄ 2HI(g) at 425°C is 4.43 × 104.

Using the specified concentrations of H2, I2, and HI, it appears that you have correctly calculated the equilibrium constant, K, for the reaction H2(g) + I2(g) 2HI(g) at 425°C. The ratio of the concentrations of the reactants and products at equilibrium, K, is represented by each concentration being raised to the power of its stoichiometric coefficient.

The concentration of the product, HI, is preferred above the concentrations of the reactants, H2 and I2, at equilibrium, as shown by the value of K = 4.43 104 in this instance. This suggests that at equilibrium, the forward reaction—the creation of HI—is preferred.

It is significant to remember that the equilibrium constant, K, is temperature-dependent, and that temperature changes affect K's value.

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Noble gases have the maximum number of electrons in their outer shell. The statement made by the student about the stability of noble gases is generally true.

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Answer:

the mass of the new copper roof will increase over time as it turns green

Explanation:

this is because copper will react with atmospheric substances to form copper compound. this does not violate the law of conversation of mass because the mass increases as copper react with atmospheric substances in the presence of atmospheric air, oxidizes to copper compounds which are heavier in mass than copper atoms

According to the law of conservation of mass, the mass of the copper roof increases as oxygen is added to it to form copper oxide.

Oxidation is a reaction in which oxygen is added to an element.

Oxidation metals in the presence of air occurs frequently as metals are reactive.

Copper roof turns green with time as the metals react with oxygen in air to form copper oxide.

The mass of the new copper roof increases in accordance with the law of conservation of mass as oxygen is added to metallic copper to increase it's mass.

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Answer:

acidos

Explanation:

los conductores de energía eléctrica: es decir, este tipo de energía fluye con facilidad a través de sus iones. Al reaccionar con metales generan hidrógeno (H) y sal. Al reaccionar con bases o con óxidos metálicas generan agua

The percent oxygen in limestone is 48% and the percent carbon is 12%.

To find the percent oxygen and carbon in limestone, we need to use the formula:
% element = (mass of element / total mass of compound) x 100%
First, we need to calculate the mass of calcium in the sample:
Mass of calcium = total mass of compound - mass of oxygen - mass of carbon
Mass of calcium = 3.75 g - 1.80 g - 0.450 g
Mass of calcium = 2.52 g
Now we can calculate the percent oxygen:
% O = (1.80 g / 3.75 g) x 100%
% O = 48%
And the percent carbon:
% C = (0.450 g / 3.75 g) x 100%
% C = 12%
Therefore, the percent oxygen in limestone is 48% and the percent carbon is 12%.
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Answer :Yet Hooke was perhaps the single greatest experimental scientist of the  describing elasticity that is still used today ("Hooke's Law"); assisted Robert Boyle the history of biology largely rests on his book Micrographia, published in 1665.  than his compound microscope, but found simple microscopes difficult to use: he

Explanation: think you

Answer:

Please find the description below

Explanation:

According to this question, a scientist states the law of conservation of energy, which says that energy is neither created nor destroyed but can only be transformed from one form to another. However, there are three ways of heat transfer namely: conduction, convection, and radiation.

A pot of water being heated on a stove transfers thermal or heat energy from the fire in the stove to the pot via CONDUCTION because there is a physical contact between the solid pot and the fire. This transfer of thermal energy supports the scientist's statement in the sense that the thermal energy emitted by the fire is not lost but instead transferred to the pot and water in it.

If we know the orbital period of a planet around its star and the mass of the star, we can calculate the planet's average orbital distance.

Kepler's third law of planetary motion relates the orbital period of a planet around its star to the average orbital distance of the planet. The law states that the square of the orbital period is directly proportional to the cube of the average orbital distance.

By knowing the orbital period of the planet and the mass of the star, we can use Kepler's third law to calculate the average orbital distance of the planet. The mass of the star affects the gravitational force between the planet and the star, which in turn determines the size and shape of the planet's orbit. Therefore, by combining the orbital period and the mass of the star, we can derive the average orbital distance of the planet.

Other properties such as the eccentricity of the planet's orbit, the mass of the planet, and the radius of the planet cannot be directly determined solely from the orbital period and the star's mass. Additional information or measurements are required to calculate these parameters.

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The type of metabolism yeast use to generate carbon dioxide that makes bread rise is anaerobic fermentation.

Yeast is a microorganism that undergoes fermentation in the absence of oxygen. During the fermentation process, yeast breaks down sugars, such as glucose, through a series of metabolic reactions. One of the byproducts of this process is carbon dioxide (CO2). The carbon dioxide gas gets trapped within the dough, causing it to rise and give the bread a light and fluffy texture.

Anaerobic fermentation is the specific type of fermentation that occurs in the absence of oxygen. Yeast carries out anaerobic fermentation to produce energy when oxygen is not available. This process does not require oxygen and is therefore suitable for the conditions found in bread dough.

The type of metabolism yeast uses to generate the carbon dioxide that makes bread rise is anaerobic fermentation (option d).

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There are a lot of ionic compounds in fireworks, most of them are salts, like: Strontium Nitrate and Strontium Carbonate ( both in the color red); Calcium Carbonate and Calcium Chloride (orange); Sodium Nitrate, Sodium Oxalate (yellow); Barium Nitrate and Barium Carbonate (green) and so on. For the gunpowder itself we have the Potassium Nitrate as an ionic compound.

The chemical reaction for the combustion of black powder is:

6KNO3 + C7H4O + 2S -> K2CO3 + K2SO4 + K2S + 4CO2 + 2CO + 2 H2O + 3N2

It's not just a single reaction, but this is a general representation of it.

Answer:

Number 2 is Direction

Explanation:

The old answer for number four was incorrect

I apologize for the inconvenience but I do not have an answer that fits in the lines for number 4

When the nuclide aluminum-25 undergoes positron emission, the name of the product nuclide is magnesium-25, and the symbol for the product nuclide is 25Mg.

Positron emission is a type of radioactive decay in which a proton in the nucleus of an atom is converted into a positron, which is a positively charged particle.

In the case of aluminum-25, the nucleus undergoes positron emission, and a proton is converted into a positron. This results in the nucleus having one less proton and one more neutron, which changes the element to magnesium-25. It can be represented as:

\(\rm _{13}^{25}Al \rightarrow _{+1}^{0}e + _{12}^{25}Mg\)

Therefore, when aluminum-25 undergoes positron emission, the product nuclide is magnesium-25, with the symbol 25Mg.

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3 K + 1 D(NO3)3 ⇒ 3 KNO3 + 1 D is balanced equation.

Define chemical reactions .

Breaking chemical bonds between reactant molecules (particles) and creating new links between atoms in product particles are two aspects of chemical reactions (molecules). While there are the same number of atoms both before and after the chemical change, there will be a difference in the number of molecules.

A chemical equation that is balanced has equivalent amounts of each element's atoms on both sides of the equation and conserves mass. You can balance equations on your own by adhering to these basic guidelines: Verify that the equation's formulas are all accurate. Focus on just one aspect at a time. In balancing, huge amounts are added.

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The water particles in a beaker of water experience unequal attractive forces due to the difference in the nature of interactions between water molecules within the liquid and at the surface.

Inside the bulk of the liquid, water molecules are surrounded by neighbouring water molecules, resulting in strong cohesive forces between them. These cohesive forces arise from hydrogen bonding, where the partially positive hydrogen atom of one water molecule is attracted to the partially negative oxygen atom of another water molecule. These hydrogen bonds contribute to the overall stability and structure of the liquid.

At the surface of the water, however, water molecules experience an imbalance of attractive forces. Since there are no water molecules above the surface, the water molecules at the surface are not fully surrounded by other water molecules. As a result, the attractive forces between water molecules at the surface are stronger towards the inside of the liquid compared to the outside.

This imbalance leads to a net inward force on the surface water molecules, causing them to be pulled back into the liquid. This phenomenon is known as surface tension. Surface tension allows water to form droplets and exhibit behaviours such as capillary action.

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Answer:

the required temperature of uranium hexafluoride is 54156.25 K

Explanation:

Given the data in the question;

We know that average speed is;

u = \([ 3RT / MM ]^{1/2\) ----------- let this be equation 1

where MM is the molar mass

T is temperature

R is universal gas constant and u is the average speed.

First we get the average speed of H₂

\(U_{H}\)₂ =  \([ 3RT_H_2 / MM_H_2 ]^{1/2\) ------ let this be equation 2

Next is the average speed of UF₆

\(U_{UF\)₆ = \([ 3RT_{UF_6} / MM_{UF_6} ]^{1/2\) ------ let this be equation 3

given that; both have the same average speed, equation 2 = equation 3;

\([ 3RT_H_2 / MM_H_2 ]^{1/2\) = \([ 3RT_{UF_6} / MM_{UF_6} ]^{1/2\)

we multiply both sides by 1/3R and also square both sides.

\([ T_H_2 / MM_H_2 ]\) = \([ T_{UF_6} / MM_{UF_6} ]\)

given that; temperature of hydrogen T\(_{H\)₂ = 37°C = ( 37 + 273.15)K = 310.15 K

we know that Molar mass of H₂; MM\(_{H\)₂ = 2.016 g/mol  

and molar mass of  UF₆; MM\(_{UF\)₆ = 352.02 g/mol

so we substitute

[ 310.15 K / 2.016 g/mol  ] = [ T\(_{UF\)₆ / 352.02 g/mol ]

T\(_{UF\)₆ = [ 352.02 g/mol  × 310.15 K ] / 2.016 g/mol

T\(_{UF\)₆ = 109179.003 K/ 2.016

T\(_{UF\)₆ = 54156.25 K

Therefore, the required temperature of uranium hexafluoride is 54156.25 K

The solubility of oxygen at 10m depth below sea level, 25 degrees Celsius, and 30 g/L salinity is approximately 6.59 mg/L.

To calculate the solubility of oxygen at a specific depth below sea level, temperature, and salinity, we can refer to the oxygen solubility tables. The solubility of oxygen can vary depending on these factors.

1. Begin by identifying the given parameters:
  - Depth: 10m below sea level
  - Temperature: 25 degrees Celsius
  - Salinity: 30 g/L

2. Use the given parameters to locate the corresponding values in the oxygen solubility table.

3. The solubility of oxygen at a depth of 10m below sea level, 25 degrees Celsius, and 30 g/L salinity is typically around 6.59 mg/L.

Therefore, the solubility of oxygen at 10m depth below sea level, 25 degrees Celsius, and 30 g/L salinity is approximately 6.59 mg/L.

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The oxygen solubility at 10m depth below sea level, 25°C, and 30 g/L salinity is approximately 1538 mol/L.

To calculate the oxygen solubility at a specific depth below sea level, temperature, and salinity, we can use the solubility formula.

The solubility of a gas decreases with increasing temperature and salinity, and increases with increasing pressure.

Here's how you can calculate the oxygen solubility at 10m depth below sea level, 25°C, and 30 g/L salinity:

1. Determine the pressure at 10m depth below sea level: -

The pressure at sea level is approximately 1 atmosphere (atm).

The pressure increases by approximately 1 atm for every 10 meters of depth.

Therefore, at 10m depth, the pressure is approximately 2 atm.

2. Convert the temperature to Kelvin: -

To convert from Celsius to Kelvin, add 273 to the temperature.

25°C + 273 = 298 K.

3. Use the solubility formula:

The solubility of oxygen in water can be calculated using Henry's law:

S = k * P * C.

S is the solubility of oxygen in moles per liter (mol/L).

k is the Henry's law constant for oxygen in water at a specific temperature and salinity.  

P is the partial pressure of oxygen in atmospheres (atm).

C is the concentration of oxygen in moles per liter (mol/L).

4. Look up the Henry's law constant for oxygen at 25°C and 30 g/L salinity:

The Henry's law constant for oxygen at 25°C and 30 g/L salinity is approximately 769 L*atm/mol.

5. Calculate the solubility:  

S = (769 L*atm/mol) * (2 atm) * (1 mol/L). - S ≈ 1538 mol/L.

Therefore, the oxygen solubility at 10m depth below sea level, 25°C, and 30 g/L salinity is approximately 1538 mol/L.

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The curve in the given scenario is known as the meniscus. The correct option is B.

A graduated cylinder, also known as a measuring cylinder or mixing cylinder, is a piece of laboratory equipment that is commonly used to measure the volume of a liquid.

It is narrow and cylindrical in shape. The amount of liquid measured is represented by each marked line on the graduated cylinder.

A graduated cylinder is a piece of laboratory equipment used to measure the volume of liquids, chemicals, or solutions during the course of a day's work in the lab.

Graduated cylinders provide greater precision and accuracy than standard laboratory flasks and beakers.

The upward or downward curve seen at the top of a liquid in a container is known as the meniscus.

Thus, the correct option is B.

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The structure of Ester:

\(CH_3CH_2CH_2CH_2CH_2-C-O-CH_2CH_3\)

I

\(CH_3\)

An alcohol and a carboxylic acid react to form an ester, a type of chemical molecule. Esters are often used in a variety of common items including plastics, flavorings and fragrances. They often have a pleasant fruity or floral scent, which is what gives many fruits their distinctive aroma.

An alkyl group (R) is attached to one oxygen atom and a carbonyl group (C = O) is attached to another oxygen atom to form an ester structure. Alkyl or aryl groups can form alkyl groups.

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Answer: Each element on the periodic table is listed in a box with its atomic symbol and atomic number. The element's full name and atomic mass is also sometimes indicated. The image below shows a typical entry for the element calcium. The number above the atomic symbol represents the atomic number.

The empirical formula of a compound made up of 94.5 g of aluminum and 199.5 g of fluorine is AlF₃.

To determine the empirical formula of the compound, we need to first calculate the moles of each element present in the sample.

Moles of aluminum = 94.5 g / 26.98 g/mol = 3.50 mol

Moles of fluorine = 199.5 g / 18.99 g/mol = 10.51 mol

Next, we need to determine the smallest whole number ratio between these two values.

Dividing both values by 3.50, we get:

Moles of aluminum = 1

Moles of fluorine = 3

Therefore, the empirical formula of the compound is AlF₃.

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The partial pressure of gas c can be found by subtracting the sum of the partial pressures of gases a and b from the total pressure of the mixture. In this case, the partial pressure of gas c is:

Partial pressure of gas c = Total pressure - Partial pressure of gas a - Partial pressure of gas b

Partial pressure of gas c = 6.28 atm - 1.89 atm - 3.67 atm

Partial pressure of gas c = 0.72 atm

Therefore, the partial pressure of gas c is 0.72 atm. In a mixture of gases, the total pressure is the sum of the partial pressures contributed by each gas component. By subtracting the partial pressures of gases a and b from the total pressure, we can determine the remaining partial pressure, which corresponds to gas c. This calculation is based on Dalton's law of partial pressures, which states that the total pressure of a mixture of non-reacting gases is equal to the sum of their individual partial pressures.

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Answer:

salad

Explanation:

Answer:

  11. 1, 4.5

  12. right; 4.5 > 1

  13. 10, 3

  14. left; 10 > 3

Explanation:

All you're being asked to do is count the squares in the pictures.

11. The number of squares for the left wave from bottom to top is 2, so the amplitude is 1/2 that, 2/2 = 1. For the right wave it is 9 squares from bottom to top, so the amplitude is 9/2 = 4.5.

  left amplitude: 1, right amplitude: 4.5

__

12. The right wave has greater amplitude. Evidence: 4.5 > 1. It also takes up more vertical space in the picture.

__

13. It is difficult to determine the wavelength of the left wave, because two full peaks are not shown. If we try to match corresponding points, they appear to be about 10 squares apart.

The right wave has 2 peaks in 6 squares, so about 3 squares between peaks.

  left: wavelength 10, right: wavelength 3

__

14. The left wave has greater wavelength. Evidence: 10 > 3.

Answer:

11. 1, 4.5

12. right; 4.5 > 1

13. 10, 3

14. left; 10 > 3

Explanation:

The amount of aluminum needed to react completely with 4.5 mol of FeO would be 80.94 grams

From the equation of the reaction, the mole ratio of FeO and Al is 3:2.

Thus, with 4.5 mol of FeO, the equivalent mole of Al required for complete reaction would be:

2/3 x 4.5 = 3.0 mol

Since the molar mass of Al is given as 26.98, the mass of 3.0 mol Al can be deduced as:

Mass = mole x molar mass

        = 3 x 26.98

       = 80.94 grams

In other words, the mass of aluminum needed to react completely with 4.5 mol of FeO is 80.94 grams.

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Answer:

0.333J/g°C is the specific heat of the metal

Explanation:

The heat that the metaal gives is equal to the heat that water is absorbing. The equation is:

S(metal)*ΔT(metal)*Mass(metal) = S(H2O)*ΔT(H2O)*Mass(H2O)

Where S is specific heat, ΔT is change in temperature and mass the mass in grams of the metal and water.

Replacing:

S(metal)*(100.0°C-27.2°C)*125.0g = 4.184J/g°C*(27.2°C-24.3°C)*250.0g

S(metal) = 4.184J/g°C*(27.2°C-24.3°C)*250.0g / (100.0°C-27.2°C)*125.0g

S(metal) = 0.333J/g°C is the specific heat of the metal

Answer:

Mass of 1 mole potassium = 39.1

Therefore, a mole of potassium has more mass than a mole of sodium.

A claim about the arrangements of electrons and properties within a family of elements is described below:

Families of elements refer to elements that are found in the same group in the periodic table.

Elements that belong to the same family have the same arrangement of electrons.

The families of elements are found in the vertical columns knowns as groups. They have the same physical properties because they have the same number of e; electrons in their outermost shell.

For example, elements belonging to group 1 have one valence electron and show similarity in their chemical properties.

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