The force needed to overcome the attraction among molecules at the surface of a liquid is called?

By the definition of molarity, 1000ml of HCl solution contains 0.0858 moles of HCl.

The moles of HCl in 21ml of solutions can be obtained as follows-

Moles of HCl = 21ml *0.0858moles/1000ml

                     = 0.0081moles

Hence, moles of ethylamine =0.0081moles

Now,

the molarity of ethylamine solutions can be obtained as follows-

Since,

35ml of ethylamine solution contains 0.0018moles

the moles of ethylamine in 1000ml of the solution(molarity) can be obtained as-

Molarity = 1000ml/L * 0.0018mol/35ml

            = 0.0514 M

Hence,

the molarity of ethylamine solution is 0.0514 M

This is because, to find molarity of a solution considering a titration curve  which is a plot of pH v/s volume of titrant. The equivalence point in the titration curve is the point at which there is a significant change in pH with small addition of titrant. At the equivalence point, the moles of titrant equal the moles of analyte.

The volume of the HCl solution added to reach the equivalence point is 21ml.

At this point, the moles of HCl = moles of ethylamine

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The reaction quotient from the calculation is obtained as  12.3

The reaction quotient, Q, is a mathematical expression used in chemistry to predict the direction a chemical reaction will proceed under non-standard conditions.

It is calculated in the same way as the equilibrium constant, K, but uses the concentrations (or partial pressures) of the reactants and products at any given moment during a reaction, rather than at equilibrium.

We already know that the reaction quotient would refer to the non equilibrium conditions. Thus we have that;

Q = [N₂04]/[NO₂]^2

Q = 0.00553/(0.0212)^2

Q = 12.3

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Removing of products, increasing the temperature and decreasing the pressure all of these will alter the equilibrium concentration. The correct option to this question is D.

The Le Chatelier principle is as follows: A movement in the equilibrium's location counteracts the effect of a change in one of the variables that characterize a system at equilibrium.

Equilibrium-affecting variables and the Le Chatelier principle

Alterations in concentration

Alterations in pressure.

Temperatures fluctuate.

The system's balance is thrown off when one of these elements changes, and it then readjusts itself until it achieves equilibrium again. The sections that follow discuss some of the most significant factors that affect equilibria.

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Complete question:

Which of the following changes in reaction conditions will alter the composition of an equilibrium mixture of gases for a reaction having unequal moles of gaseous products and gaseous reactants?

A) removing of products

B) increasing the temperature

C) decreasing the pressure

D) All of these will alter the equilibrium concentrations.

Answer:

The volume of Component 1 is 36 cubic inches.

Explanation:

To calculate the volume of a composite solid, we need to determine the individual volumes of the different components and then add them together.

In this case, the composite solid consists of multiple components with the following dimensions:

Component 1:

Length: 4 inches

Width: 3 inches

Height: 3 inches

To find the volume of Component 1, we multiply the length, width, and height together:

Volume of Component 1 = Length x Width x Height = 4 in x 3 in x 3 in = 36 cubic inches

Therefore, the volume of Component 1 is 36 cubic inches.

Please provide the dimensions of the remaining components of the composite solid, and I will calculate the total volume by summing up the individual volumes.

Answer:

Specific heat of aluminum  = 0.27 j/g.°C

Explanation:

Given data:

Mass of Al = 100 g

Initial temperature = 108.4°C

Final temperature = 68.2°C

Heat released = -1080 j

Specific heat of aluminum = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  68.2°C -  108.4°C

ΔT = - 40.2°C

Q = m.c. ΔT

-1080 j = 100 g ×c ×- 40.2°C

-1080 j = -4020 g.°C ×c

c = -1080 j/-4020 g.°C

c = 0.27 j/g.°C

To calculate the molarity of a solution, we need to determine the number of moles of the solute (Bal2) and then divide it by the volume of the solution in liters.

Given:

Mass of Bal2 = 413 g

Volume of solution = 750 ml = 0.75 L

1. Calculate the number of moles of Bal2:

First, we need to convert the mass of Bal2 to moles using its molar mass. The molar mass of Bal2 can be calculated by summing the atomic masses of boron (B) and iodine (I):

Molar mass of Bal2 = (atomic mass of B × 1) + (atomic mass of I × 2)

Molar mass of Bal2 = (10.81 g/mol × 1) + (126.90 g/mol × 2)

Molar mass of Bal2 = 10.81 g/mol + 253.80 g/mol

Molar mass of Bal2 = 264.61 g/mol

Now we can calculate the number of moles of Bal2:

Moles of Bal2 = Mass of Bal2 / Molar mass of Bal2

Moles of Bal2 = 413 g / 264.61 g/mol

Moles of Bal2 ≈ 1.561 mol

2. Calculate the molarity of the solution:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity (M) = 1.561 mol / 0.75 L

Molarity (M) ≈ 2.081 M

Therefore, the molarity of the solution is approximately 2.081 M.

The molarity of the solution is approximately 1.408 M as to calculate the molarity of a solution, one must need to know the number of moles of the solute and the volume of the solution in liters.

The molar mass of BaI₂ is:

Ba (barium) atomic mass = 137.33 g/mol

I (iodine) atomic mass = 126.90 g/mol

Molar mass of  BaI₂ = (Ba atomic mass) + 2 × (I atomic mass)

= 137.33 + 2 × 126.90

= 137.33 + 253.80

= 391.13 g/mol

Given that the mass of BaI₂ is 413 g,

Number of moles = Mass / Molar mass

= 413 g / 391.13 g/mol

= 1.056 moles

Volume of solution = 750 ml = 750/1000 = 0.75 L

Finally, one can calculate the molarity of the solution using the formula:

Molarity = Number of moles / Volume of solution

= 1.056 moles / 0.75 L

= 1.408 M

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Answer:

we should conserve energy the reason are in the points

To less power plants

To promote health

To reduce dependence

To finite resources

To make a positive impact

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

Answer:

0.043 M

Explanation:

The reaction that takes place is:

First we calculate how many HCl moles reacted, using the given concentration and volume required to reach the equivalence point:

As 1 mol of H⁺ reacts with 1 mol of OH⁻, in the 25.0 mL of the Ca(OH)₂ sample there are 1.0817 mmoles of OH⁻.

With that in mind we can calculate the hydroxide ion concentration in the original sample solution, using the calculated number of moles and given volume:

The titration is termed the neutralization reaction with the acid and base. The concentration of hydroxide in the titration is 0.0865 M.

The neutralization reaction is given as the reaction in which the acid and base react to form the salt and water, stabilizing the pH of the solution.

The neutralization of acid and base to identify the strength can be given as:

\(\rm M_V_1=M_2V_2\)

Substituting the strength and the volume of calcium hydroxide and the HCl with the volume:

\(\rm 0.029\;M\;\times\;37.3\;mL=M_2\;\times\;25\;mL\\M_2=\dfrac{ 0.029\;M\;\times\;37.3\;mL}{25\;mL} \\M_2=0.0432\;M\)

The strength of the calcium hydroxide in the reaction is 0.04326 M.

One molar unit of calcium hydroxide results in 2 molar units of hydroxide. The molar unit of hydroxide in 0.04326 M calcium hydroxide is:

\(\rm 1\;M\;Ca(OH)_2=2\;M\;OH^-\\\\0.04326\;M\;Ca(OH)_2=0.04326\;\times\;2\;M\;OH^-\\0.04326\;M\;Ca(OH)_2=0.0865\;M\;OH^-\)

The concentration of hydroxide ion in the titration is 0.0865 M.

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The covalent bond is present in the compound C₃H₈. The reactant C is 3, product C is 6, reactant H is 8, product H is 10, Reactant O is 2, product O is 9.

What is covalent bond ?

Atoms share electron pair between them in covalent bonds. H-H or C-H are examples of nonpolar covalent bonds between atoms with similar or identical electronegativity, whereas polar covalent bonds are formed when unequal electronegativity is shared between atoms (e.g., H–O).

What is reactant ?

Raw materials known as reactants combine to create products. When the right factors, such as temperature, time, or pressure, come into play, the chemical bonds between the reactants are broken, allowing the atoms to form new bonds that lead to various combinations.

Therefore, covalent bond is present in the compound C₃H₈. The reactant C is 3, product C is 6, reactant H is 8, product H is 10, Reactant O is 2, product O is 9.

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Let's see

\(\\ \rm\Rrightarrow [M_3X_3]\leftrightharpoons {[M^{3+}]\atop 3x}+{[X^{3-}]\atop 3x}\)

So

As solubility and molar mass given

\(\\ \rm\Rrightarrow [M_3X_3]=\dfrac{Solubility}{Molar\:mass}\)

\(\\ \rm\Rrightarrow x=\dfrac{0.039}{108.64}\)

\(\\ \rm\Rrightarrow x=0.00034M=3.4\times 10^{-4}M\)

So

\(\\ \rm\Rrightarrow K_{sp}=(3x)(3x)=(3x)^2=9x²\)

So

\(\\ \rm\Rrightarrow K_{sp}=9(3.4\times 10^{-4})^2=0.0000010404=104\times 10^{-6}mol^2L^{-2}=104\mu mol^2L^{-2}\)

Answer:

Portraiture

Explanation:

It was traditionally used by rulers and wealthy photographers. It's a very old form of art and it was first shown in ancient Egypt. Drawn portraits were the only way of capturing someone's appearance and that is why they were so popular before the invention of photography and more.

Hope this helps :)

Social Documentation is a form of photography that documents social situations in an attempt to influence people's thoughts and actions. ... While this was traditionally used by rulers and the wealthy, photography made this type of photography less expensive.

Answer:

During rock cycle deposition follows erosion.

The reaction progresses 4 times quicker at 318 K than at 298 K and 128 times faster at 368 K than at 298 K when the reaction is carried out at 318 K than at 298 K.

Because the molecules of the reactants collide more frequently at higher temperatures, reaction rates rise. This occurs because as the temperature rises, the molecules' kinetic energy rises as well.

Rate1 and Rate2 are the rates of reaction at temperatures T1 and T2, respectively,

Rate2 / Rate1 = (k2 / k1)

As a result, the rate constant ratio between 318 K and 298 K is:

\(k2 / k1 = 2² = 4\)

Substituting this ratio into the equation for the ratio of rates, we get:

\(Rate2 / Rate1 = (k2 / k1) = 4\)

This means that the reaction proceeds 4 times faster at 318 K than at 298 K.

Using the same approach, the ratio of rate constants at 368 K and 298 K is:

\(k2 / k1 = 2⁷ = 128\)

Substituting this ratio into the equation for the ratio of rates, we get:

\(Rate2 / Rate1 = (k2 / k1) = 128\)

This means that the reaction proceeds 128 times faster at 368 K than at 298 K.

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Answer:

Concentration of H3O⁺  [H3O⁺] = 0.864 M

Explanation:

Given that:

The mass concentration of MO = 43 g/L

The volume of MO = 7.9 mL = 7.9 × 10⁻³ L

Recall that

The mass number of MO = Mass concentration of MO × Volume of MO

The mass number of MO = (43 g/L) * (7.9 × 10⁻³ L)

The mass number of MO =  0.3397 g

number of  moles of MO = (mass number of MO) / (molar mass of MO)

number of  moles of MO = (0.3397 g) / (327.33 g/mol)

moles of MO = 0.00104 mol

The total volume = 7.9 mL + 3.13 mL + 5.49 mL + 3.43 mL

The total volume = 19.95 mL = 19.95 × 10⁻³ L

Concentration of MO [MO} =(number of moles of MO) / (total volume)

[MO] = 0.00104 mol  /  19.95 × 10⁻³ L

[MO] = 5.2130 × 10⁻⁸ M

the number of moles of H3O⁺ = molarity of HCl in the solution × the volume of HCl in solution

the number of moles of H3O⁺ = [(2.0 M) * (3.13 mL)] + [(2.0 M) * (5.49 mL)]

the number of moles of H3O⁺ = 17.24 mmol

Concentration of H3O⁺  [H3O⁺] = (the number of moles of H3O⁺) / (total volume)

Concentration of H3O⁺  [H3O⁺] = (17.24 mmol) / (19.95 mL)

Concentration of H3O⁺  [H3O⁺] = 0.864 M

The Concentration of H3O⁺  [H3O⁺] is 0.864 M

But before that following calculations should be needed.

The mass number of MO = Mass concentration of MO × Volume of MO

= (43 g/L) * (7.9 × 10⁻³ L)

=  0.3397 g

Now

number of  moles of MO = (mass number of MO) / (molar mass of MO)

= (0.3397 g) / (327.33 g/mol)

= 0.00104 mol

Now

The total volume = 7.9 mL + 3.13 mL + 5.49 mL + 3.43 mL

= 19.95 mL

= 19.95 × 10⁻³ L

Now

Concentration of MO [MO} =(number of moles of MO) / (total volume)

= 0.00104 mol  /  19.95 × 10⁻³ L

5.2130 × 10⁻⁸ M

Now

the number of moles of H3O⁺ = molarity of HCl in the solution × the volume of HCl in solution

= [(2.0 M) * (3.13 mL)] + [(2.0 M) * (5.49 mL)]

= 17.24 mmol

Now

Concentration of H3O⁺  [H3O⁺] = (the number of moles of H3O⁺) / (total volume)

= (17.24 mmol) / (19.95 mL)

= 0.864 M

Hence, The Concentration of H3O⁺  [H3O⁺] is 0.864 M

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Answer: Temperature = T, unknown

Saturated Solution, NH4Cl concentration = 60g/100g H2O = 0.6g NH4Cl/g H2O

Assume density of H2O = 1 g/ml

m = 0.6g NH4Cl/g H2O / 1 g/ml

m = 0.6g NH4Cl/ml

See the table of saturated solutions and identify the temperature at which the concentration of NH4Cl is 60g/100g H2O.

Explanation:  The line on the graph on reference table G indicates a saturated solution of NH4CL as a concentration of 60. g NH4 Cl/100. g H2O

Answer:

test her suspicion by checking to see whether other cats also make her sneeze

The order of the components of the electromagnetic spectrum from shortest wavelength to longest is as follows: 3-5-2-1-7-6-4.

Electromagnetic spectrum is the entire range of wavelengths of all known electromagnetic radiations extending from gamma rays, to X-rays through visible light, infrared, to radio waves.

The components of the electromagnetic spectrum from order of shortest to longest wavelength is as follows;

This suggests that gamma rays have the shortest wavelength while radio waves have the longest wavelength.

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Answer:

c

Explanation:

mass is like matter it cant be created or destroyed so mass stays the same.

Answer:

C) It is equal to the total mass of the products.

Explanation:

The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products.

- profparis

The focal length of the mirror is 15 cm

From the question given above, the following data were obtained:

Object distance (u) = 30 cm

Image distance (v) = 30 cm

The focal length of the mirror can be obtained as follow:

\(\frac{1}{f} = \frac{1}{v} + \frac{1}{u} \\\\\frac{1}{f} = \frac{1}{30} + \frac{1}{30}\\\\\frac{1}{f} = \frac{2}{30} \\\\\frac{1}{f} = \frac{1}{15} \\\\\)

Therefore, the focal length of the mirror is 15 cm

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The maximum mass of carbon dioxide that could be produced by the chemical reaction is 46.2 g

First, we shall determine the limiting reactant. This obtained as follow

2CH₃(CH₂)₂CH₃ + 13O₂ -> 8CO₂ + 10H₂O

From the balanced equation above,

116 g of CH₃(CH₂)₂CH₃ reacted with 416 g of O₂

Therefore,

48 g of CH₃(CH₂)₂CH₃ will react with = (48 × 416) / 116 = 172.14 g of O₂

From the above calculation, we can see that a higher amount (i.e 172.14 g) of O₂ than what was given (i.e 54.6 g) is needed to react with 48 g of CH₃(CH₂)₂CH₃

Thus, the limiting reactant is O₂

Finally, we shall determine maximum mass of carbon dioxide, CO₂ produced. Details below:

2CH₃(CH₂)₂CH₃ + 13O₂ -> 8CO₂ + 10H₂O

From the balanced equation above,

416 g of O₂ reacted to produce 352 g of CO₂

Therefore,

54.6 g of O₂ will react to produce = (54.6 × 352) / 416 = 46.2 g of CO₂

Thus, the maximum mass of carbon dioxide, CO₂ produced is 46.2 g

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Answer:

0.146 M

Explanation:

Use v1s1 = v2s2

here, v1 = 500 mL, v2 = 700 mL, s1 = 0.205 M & s2 = new concentration

(a) the molecular formula of the compound is C₆H₁₂.

(b)  the molecular formula of the compound is NH₂Cl.

(a) Given the empirical formula CH₂ and a molar mass of 84 g/mol, we need to determine the molecular formula. To do so, we need to find the factor by which the empirical formula needs to be multiplied to achieve the given molar mass.

The empirical formula CH₂ has a molar mass of 14 g/mol (12 g/mol for carbon + 2 g/mol for hydrogen).

To find the factor, we divide the molar mass by the empirical formula mass:

Factor = (molar mass) / (empirical formula mass) = 84 g/mol / 14 g/mol = 6

Therefore, the molecular formula is obtained by multiplying the empirical formula by the factor:

CH₂ × 6 = C₆H₁₂

Thus, the molecular formula of the compound is C₆H₁₂.

(b) Given the empirical formula NH₂Cl and a molar mass of 51.5 g/mol, we follow a similar approach.

The empirical formula NH₂Cl has a molar mass of 51.5 g/mol (14 g/mol for nitrogen + 2 g/mol for each hydrogen + 35.5 g/mol for chlorine).

To find the factor, we divide the molar mass by the empirical formula mass:

Factor = (molar mass) / (empirical formula mass) = 51.5 g/mol / 51.5 g/mol = 1

Therefore, the molecular formula is the same as the empirical formula: NH₂Cl

Hence, the molecular formula of the compound is NH₂Cl.

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The relative atomic mass of Boron in trimethyl borate [(CH3O)3B] is; 10.8

According to the question;

The relative abundance of Boron in the spectrum is;

Relative atomic mass = (80% of 11) + (20% of 10)

Hence, the relative atomic mass of Boron in trimethyl borate [(CH3O)3B] is; 10.8

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The asbestos exposure during the years 1982 and 1983 was 2.5 fibers per cubic centimeter and 0.8 fibers per cubic centimeter respectively. So asbestos exposure decreased by 1.7 fibers per cubic centimeter during the year 1983.

Breathlessness Persistent, dry cough Chest pain or tightness Lack of a dry, crackling sound in the lungs when you breathe in Wider and rounder fingers and toes are some of the symptoms of asbestos exposure.

The largest group of people exposed to asbestos is those working in the construction industry. Historically, asbestos was also used by pipe fitters and shipyard workers. In addition, asbestos was used by military personnel, auto mechanics, and many other occupations.

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Answer:

1.379 M

Explanation:

The computation of the molarity of a solution is as follows;

As we know that

Molarity(M) = number of moles of solute ÷  volume of solution ( in L )

Given that

Mass = 10 grams

Molar mass of acetone(C3H6O) = 58 g/mol

moles = mass ÷ molar mass

= 10 g ÷ 58 g/mol

= 0.172414 mol

Now the molarity of the solution is  

Volume of solution = 125 mL = 0.125 L

As

1 L = 1000 mL

so,

125 mL = (125 mL  × ( 1 L ÷ 1000 mL) = 0.250 L)

Now the molarity is

= 0.172414 mol  ÷ 0.125 L

= 1.379 M

Answer:

????

Explanation:

where's the question

The true statement  for the quantum mechanical atomic model is that Electrons give off electromagnetic radiation when they jump from a high to a low energy level.

Option c is correct.

The quantum mechanical atomic model, also known as the wave mechanical model, describes the behavior of electrons in atoms as waves.

This model described that only electrons can exist only in certain discrete energy levels around the nucleus. When an electron absorbs energy, it moves to a higher energy level.

In other words, when it loses energy, it moves to a lower energy level.

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Answer:

the mas is .291 g

Explanation:

the mass of a object does not change. so when added the substance the beaker. you had the mass of both objects together. you know the mass of the beaker and you know the mass of both. since mass does not change. the beakers mass is still 74.605g. the mass of both objects is 74.896. all you have to do is subtract the mass of the beaker from the total mass. 74.896 - 74.605 equals .291g. so the mass of the unknown substance Is .291g