The following plot shows two pH titration curves, each representing the titration of 50.0 mL of 0.100 M acid with 0.100 M NaOH. Part A which of the two curves represents the titration of a strong acid? Which represents a weak acid? Part B what is the approximate pH at the equivalence point for each of the acids?

Answer :Phosphorus P 32.6138

Oxygen O 67.3862

Explanation: Phosphorus P 32.6138

Oxygen O 67.3862

Answer: 110 g/mol

Explanation:

First we need to find the molar mass of CaCl2 using the periodic table:

Ca: 40

Cl: 35 (Since Cl has a 2 at the end, multiply 35 by 2)

70+40= 110

Then multiply by amount of moles

110g×1.000mol = 110 g/mol

Conversion of Ethyne into Ethanol:

The ethanal can be prepared by the ethyne by treating the ethyne with mercuric sulphate in presence of acid. First the mercury attacks on the reactant ethyne and forms a cyclic structure. Then water attacks on this cyclic structure forming a mercury cation. Then by the removal of hydride alcohol forms.

Hydration of Ethyne:

Alkynes readily combine with water in the presence of acid (usually sulfuric acid) and mercury(II) salts (usually the sulfate is used) to form carbonyl compounds, in a process known as Kucherov's reaction. In the case of acetylene (ethyne) the product is acetaldehyde (ethanal), while other alkynes form ketones.

NO3 is a form of nitrogen that can be utilized by plants.

What is an NO3?

The chemical formula for the polyatomic ion nitrate is NO3. The word "nitrates" refers to salts that include this ion. Many fertilizers and explosives have nitrates as a component. Water can dissolve almost all inorganic nitrates.

What is an nitrogen?

In Group 15 [Va] of the periodic table, nitrogen (N) is a nonmetallic element. The most prevalent element in the atmosphere of Earth is this colorless, flavorless, and odorless gas, which is also a component of all living things  nitrogen.

Therefore, NO3 is correct answer.

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a

Explanation:

because it just jsnbsbsjsjsnsnsn snjsjsnsnzjsj snsjsjs

Answer:

a

Explanation:

Answer:

1.Irreversible

2.Physical

3.

Answer:

Average ocean pH is now 8.1 and varies seasonally

Explanation:

The pressure after the expansion inside the balloon can be calculated using Boyle's law. When the volume changes from 3.2 L to 3.6 L, pressure changes from 12 Pa to 10.6 Pa.

Boyle's law states that at constant temperature, the volume of a gas is inversely proportional to the pressure of the gas.

hence, PV = a constant.

Let P1 and V1 be the initial pressure and volume and P2 and V2 be the final pressure and volume, then

P1 V1 = P2V2.

Given that,

P1 = 12Pa

V1 = 3.2 L

V2 = 3.6 L

P2 = P1 V1/V2

     = 3.2 l × 12 Pa /3.6 L

     = 10.6 Pa

Therefore, the final pressure  of the gas inside the balloon will be 10.6 Pa.

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Answer:

The answer is "670.176 km".

Explanation:

Volume of the occupies of one  M & M= 0.5 \ cm^3\\\\

M&M 1 mole\(= 6.02 \times 10^{23}\\\\\)

Calculating volume of M& M mole\(= 0.5 \ cm^3 \times 6.02 \times 10^{23}=3.01 \times 10^{23}\ cm^3\\\\\)

Calculating the cube mole\(L^3= 3.01 \times 10^{23}\ cm^3\\\\\)

\(L=6.70176 \times 10^{7}\ cm\\\\\)

   \(=6.70176 \times 10^{7}\ cm \times \frac{1\ m}{100\ cm}\\\\=670176\ m\\\\=670.176 \ km\)

Therefore 18 tractor trailers wouldn't be sufficient.

The energy in Ha for the second excited state of hydrogen (h[0,0,1]) is -1.51 Ha.

To calculate the energy of hydrogen in its second excited state, we need to use the formula for the energy of a hydrogen atom:

E = -13.6 ha / n^2

Where E is the energy in hartrees (ha), and n is the principal quantum number. In this case, n = 3, so we can plug that into the formula:

E = -13.6 ha / 3^2

E = -13.6 ha / 9

E = -1.51 ha

Therefore, the answer is E = -1.51 Ha.

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Answer:

Ca2+ I'm not sure hahahahhahah

Answer:

Ca

hope it is helpful..

Based on the information provided, it seems like Summit made a loss on their investment in Microsoft common shares. The difference between the purchase price of $485,000 and the fair value of $483,000 on December 31 indicates a loss of $2,000.

However, it's important to note that investments in stocks can be volatile and their values can fluctuate rapidly over time. It's also possible that the shares could increase in value in the future, which would offset any initial losses. Additionally, factors such as market trends, company performance, and economic conditions can all affect the value of stocks.

Therefore, it's essential to conduct thorough research and analysis before investing in any securities. It's also advisable to seek the advice of a financial advisor to help you make informed investment decisions and manage your portfolio effectively.

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Answer:

Volume of 10M HCl containing 4 moles HCl = 400 ml

Explanation:

Molarity x Volume (L) = moles

10M·V = 4 moles HCl

V = 4moles/10Molar = 4moles/10moles/Liter = 0.40L = 400ml

HCl (hydrochloric acid) and NaOH (sodium hydroxide) are both hazardous chemicals commonly used in laboratory and industrial settings.

The correct combination of health, flammability, and reactivity ratings for these chemicals according to their safety data are:

HCl:

Health: 3 (Serious hazard)

Flammability: 0 (Minimal hazard)

Reactivity: 1 (Slight hazard)

NaOH:

Health: 3 (Serious hazard)

Flammability: 0 (Minimal hazard)

Reactivity: 2 (Moderate hazard)

Both HCl and NaOH have serious health hazards, meaning that they can cause severe or life-threatening health effects if exposure occurs. However, they have minimal flammability hazards, indicating that they are unlikely to catch fire. In terms of reactivity, HCl is a slight hazard, while NaOH is a moderate hazard, meaning that they can react with certain substances under certain conditions, producing potentially hazardous products.

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Answer:

2.43 grams are needed

Explanation:

I did the test

Hope this helps :)

The anhydrous magnesium sulfate required to dry a di-ethyl ether solution after performing extractions involving water is enough such that some powder remains free flowing in solution with swirling without clumping.

Extraction is a process which involves transfer of a solute from one phase to another. A cup of tea or coffee prepared represents a process of extraction.The flavor and odor components are extracted from the dried material into the water.

Anhydrous magnesium sulphate works as a drying agent. Magnesium sulfate (MgSO₄) works by forming complex with H₂O in the solvent. It forms a hydrated MgSO₄ precipitate. This precipitate is then filtered out by gravity, which yields an anhydrous product. Due to the high affinity towards water molecules, MgSO₄ removes any amount of water from the extracts.

Due to the presence of an active hydrogen atom, ethyl alcohol reacts with magnesium metal. Diethyl ether, does not have any replaceable hydrogen atom. So, it does not react with magnesium sulfate, therefore, can be dried by anhydrous magnesium sulfate.

Complete question is -

How much anhydrous magnesium sulfate is required to dry a diethyl ether solution after preforming extractions involving water?

Select answer and submit.

a. Enough to cover the tip of your scoopula once

b. 1 g/mL of diethyl ether

c. Enough such that some powder remains free flowing in solution with        

   swirling without clumping

d. Anhydrous magnesium sulfate doesn't dry diethyl ether

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The latest estimate for the annual number of photos taken is 1.72 trillion.

People are taking more images all around the world, and Rise Above Research, a consulting organization that conducts market research for the digital imaging sector, predicts that the total number of photos taken worldwide will reach 1.5 trillion in 2022.

Around the world, 1.72 trillion images are taken annually, or 54,400 each second or 4.7 billion per day. Every year, around 2.3 trillion pictures will be taken by 2030. Photutorial research indicates that 1.2 trillion photos were shot globally in 2021. In 2022, the amount will rise to 1.72 trillion.

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Option B is the correct answer. If a bacterium adapted to a cold environment were moved to a much warmer environment, the increased temperature would increase the fluidity of the membrane.

The fluidity of the bacterial membrane is critical for its function, and it depends on the composition of the membrane lipids. At low temperatures, the membrane lipids of the bacterium from a cold environment have more unsaturated fatty acids, which increase the fluidity of the membrane to maintain its function. In contrast, at high temperatures, the membrane lipids of the bacterium from a warm environment have more saturated fatty acids, which decrease the fluidity of the membrane.

If a bacterium adapted to a cold environment were moved to a much warmer environment, the increased temperature would increase the fluidity of the membrane. To maintain the integrity and function of the membrane, the bacterium must decrease the fluidity of the membrane. The bacterium can do this by decreasing the length of the fatty acid tails on the membrane lipids. Shorter fatty acid tails result in fewer interactions between the lipid molecules, which decreases the fluidity of the membrane. Therefore, option B is the correct answer.

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Answer:

If it's a buffer solution, the pH remains unchanged.

If it's a normal solution, and an acidic substance is added to it, the pH lowers.

If a basic substance is added to it, the pH increases.

Answer:

First, we need to determine the effect of changing the pH on the solubility of calcium fluoride. Since calcium fluoride is a salt of a weak acid (HF) and a strong base (CaOH), we can use the common ion effect to calculate the change in solubility.

At pH = 7.00, the concentration of HF is:

[H+] = 10^(-pH) = 10^(-7) = 1.0 x 10^-7 M

Ka = 10^(-pKa) = 10^(-3.17) = 7.9 x 10^-4

[H+] [F-]/[HF] = Ka

[F-]/[HF] = Ka/[H+] = (7.9 x 10^-4)/(1.0 x 10^-7) = 7.9 x 10^3

[S] = [CaF2] = 2.1 x 10^-4 M

Using the common ion effect, we can calculate the new concentration of fluoride ions (F-) at pH = 3.00.

[H+] = 10^-pH = 10^-3 = 1.0 x 10^-3 M

[F-]/[HF] = Ka/[H+] = (7.9 x 10^-4)/(1.0 x 10^-3) = 0.79

[F-] = [HF](0.79) = (2.1 x 10^-4)(0.79) = 1.66 x 10^-4 M

Therefore, the new molar solubility of calcium fluoride at pH = 3.00 is:

[S] = [CaF2] = [F-] = 1.66 x 10^-4 M

The factor by which the molar solubility increases is:

(1.66 x 10^-4 M)/(2.1 x 10^-4 M) = 0.79

Therefore, the molar solubility of calcium fluoride increases by a factor of 0.79 in a solution with pH = 3.00.

The molar solubility of caf2 increases by a factor of 1.39 in a solution with pH = 3.00 compared to a solution with pH = 7.00, due to the presence of F- ions from the dissociation of HF.

The solubility of calcium fluoride, caf2, is affected by the pH of the solution. At pH 7.00, the molar solubility of caf2 is 2.1 x 10-4 mol/L. To determine how the molar solubility changes at pH 3.00, we need to consider the acid-base equilibrium of the solution.

The pKa of HF is 3.17, which means that at pH 3.00, HF will be mostly in its protonated form, H2F+. The presence of H2F+ will decrease the solubility of caf2. We can use the common ion effect to calculate the new molar solubility of caf2 at pH 3.00.

First, we need to calculate the concentration of fluoride ions, F-, in the solution at pH 3.00. At this pH, most of the HF will be in its protonated form, H2F+, and only a small fraction will be in its deprotonated form, F-. The concentration of F- can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([F-]/[HF])

Rearranging the equation gives:

[F-]/[HF] = 10pH-pKa

Substituting the values of pH and pKa gives:

[F-]/[HF] = 10^(-0.17) = 0.426

The concentration of F- is therefore 0.426 times the concentration of HF.

Next, we can use the solubility product constant, Ksp, of caf2 to calculate its molar solubility in the presence of F-. The expression for Ksp is:

Ksp = [Ca2+][F-]2

At equilibrium, the concentration of Ca2+ is equal to the molar solubility of caf2, so we can substitute the value of Ksp and the concentration of F-:

Ksp = [caf2] [F-]2

2.87 x 10^-10 = [caf2] (0.426)^2

Solving for [caf2] gives:

[caf2] = 2.91 x 10^-4 mol/L

Therefore, the molar solubility of caf2 increases by a factor of:

(2.91 x 10^-4 mol/L) / (2.1 x 10^-4 mol/L) = 1.39

The molar solubility of caf2 increases by a factor of 1.39 in a solution with pH = 3.00 compared to a solution with pH = 7.00, due to the presence of F- ions from the dissociation of HF.

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In order to calculate the average bond energy of the O−H bond, we need to consider the energy changes involved in breaking the bonds in H2 and O2 and the energy change in forming the bonds in H2O.

The reaction involves breaking two H−H bonds and one O=O bond in the reactants, and forming four O−H bonds in the product. The energy change (ΔH) for the reaction is -571 kJ. Given that the bond energy of H−H is 435 kJ and the bond energy of O=O is 498 kJ, we can calculate the total energy change in breaking the bonds in the reactants:

Energy change = 2 × (bond energy of H−H) + (bond energy of O=O)

                 = 2 × 435 kJ + 498 kJ

                 = 1368 kJ

Since the reaction is exothermic (ΔH < 0), the energy released in forming the bonds in the products will be equal to the magnitude of the energy change: Energy change in forming bonds = 571 kJ Now, we can calculate the average bond energy of the O−H bond:

Average bond energy of O−H = (Energy change in forming bonds) / (Number of O−H bonds formed)

                                         = 571 kJ / 4

                                          ≈ 142.75 kJ

Therefore, the average bond energy of the O−H bond is approximately 142.75 kJ.

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Answer:

B

Explanation:

Blue triangles are a cold front and red bowls are warm front

Stationary front is a combination

HOPE I helped :]

Answer:

stationary front

Explanation:

on a weather map, a stationary front is shown as alternating red semicircles and blue triangles like in the image at the left. notice how the blue triangles point in one direction, and the red semicircles point in the opposite direction.

An atom is a particle of matter that uniquely defines a chemical

element. An atom consists of a central nucleus that is usually surrounded by one or more electrons. Each electron is negatively charged. The nucleus is positively charged, and contains one or more relatively heavy particles known as protons and neutrons.

2.50 litres of a 10.0 M solution require the preparation of 25.0 moles of ethylene glycol.

Excellent antifreeze, anti-boil, and anti-corrosive qualities are produced when antifreeze and water are mixed in a 50/50 ratio. The proportion of conventional ethylene glycol to water in severely cold conditions can reach 70% antifreeze, 30% water. The maximum antifreeze to water ratio when using DEX-COOL® is 60/40.

moles = concentration (M) x volume (L)

Given that the desired concentration is 10.0 M and the volume needed is 2.50 L, the setup for calculating the total number of moles of ethylene glycol can be written as:

moles = 10.0 M x 2.50 L

moles = 25.0 mol

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Answer:

Cell wall

Explanation:

i just searched it up

The term used for the geometrical isomer shown below is the term "cis-isomer."

Cis-trans isomerism, also known as geometric isomerism or configurational isomerism, is a type of stereoisomerism that occurs in alkenes and cyclic compounds.

Cis-isomer and trans-isomer are two types of stereoisomers.

Cis-isomer refers to a molecule in which two functional groups or substituents are on the same side of the double bond or ring.

Cis-isomerism occurs when substituents on a double bond or ring have the same spatial orientation.

The molecule shown below is an example of a cis-isomer.

Cis-isomers and trans-isomers have the same molecular formula and sequence of bonded atoms but differ in their spatial arrangement.

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Evaporation. ( Evaporation is a type of evaporation that occurs at the surface of a liquid as it transitions to the gas phase. )

What are two types of evaporation?

There are two types of evaporation:

evaporation and boiling. Evaporation is a surface phenomenon and occurs only at the phase boundary between the liquid and gas phases. Atoms or molecules on the surface gain energy from the environment, overcome the attraction of other molecules, and evaporate.

How does the temperature affect evaporation?

Water evaporates at low temperatures, but it evaporates faster as the temperature rises. This makes sense. This is because more molecules move faster at higher temperatures. Therefore, the molecule is more likely to have enough energy to leave the liquid and become a gas.

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The new concentration of the KCl solution after mixing 1 L new volume is 0.28 M.

Concentration in terms of molarity will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ = molarity of old KCl solution = 1.6 M

V₁ = volume of old KCl solution = 175 mL = 0.175 L

M₂ = molarity of new KCl solution = ?

V₂ = volume of new KCl solution = 1 L

On putting all these values on the above equation, we get

M₂ = (1.6)(0.175) / (1) = 0.28 M

Hence resultant concentration is 0.28 M.

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The cell potential of the cell formed by these two reaction will be -1.91 v Hence, Option (C) is Correct.

The cell potential, (Ecell), is the measure of the potential difference between two half cells in an electrochemical cell.

Given ;

To Find :

Solution :

The reaction MG²⁺ + 2e- -------------> Mg is a reduction reaction while the reaction Ag ---> Ag + 1e⁻ is an oxidation reaction.

Second reaction is oxidation reaction so to convert it into reduction reaction we will change the sign of its electrode potential Hence, reduction potential of second half cell is 0.8 v

Now, to find the cell potential of the cell formed by these two reaction we will add the two half reactions and we get,

-2.71 + 0.8 = -1.91

Hence the cell potential of the cell formed by the given reaction is -1.91 v.Therefore, Option (C) is Correct.

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