The following chemical reaction takes place in aqueous solution:
ZnBr2(aq)+2 NaOH(aq) --Zn(OH),(s)+2 NaBr(aq)
Write the net ionic equation for this reaction.

Answer:

c

Explanation:

c is correct i believe

In chromatography,when all the three samples have atleast one substance common it is indicated by Rf values which are same for the 3 samples as they have one substance common in them.

Chromatography is a separation technique which is generally used for separating substances  based on their solubilities. The technique makes use of two phases the mobile phase and the stationary phase.

The components are separated from each other based on their solubility in the mobile phase. Component which is least soluble does not travel along the mobile phase while component which is highly soluble travels with the mobile phase.

The difference in the solubility of the components is measured with the reference to the solvent front and is expressed in terms of Rf value.

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Answer:

Explanation:

A lever is a simple machine that can be used to increase the force or distance of an applied effort. The three main parts of a lever are the fulcrum, resistance arm, and effort arm.

The mechanical advantage of a lever depends on the ratio of the length of the effort arm to the length of the resistance arm. A longer effort arm will require less force to lift a load, but will require more distance to be moved. Conversely, a shorter effort arm will require more force to lift a load, but will require less distance to be moved.

Most americans overconsume calcium. fiber. added sugars. potassium because in calcium, fiber added sugars, potassium has an healthy and nutrition food and it does't cause diseases.

Adequate intake of calcium is necessary for bone health as well as for basic biological functions such as nerve transmission, vasoconstriction, vasodilation, and muscle contraction. adequate potassium intakes are associated with optimal blood pressure and may reduce the risk of developing kidney stones and bone loss. fiber may protect against cardiovascular disease, obesity, and type 2 diabetes, and it is essential for digestive health. that's why most american's overtake this calcium, fiber added sugars, potassium

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The syn addition of the H and OH to the double bond relates to the stereospecificity of the reaction.

Stereospecificity refers to the specific arrangement of atoms or groups in the products of a chemical reaction, which is determined by the spatial arrangement of reactants. In the case of syn addition, the hydrogen (H) and hydroxyl (OH) groups add to the same side of the double bond, resulting in a specific stereochemical outcome.

The addition of the H to the more substituted carbon and the OH to the less substituted carbon relates to the regioselectivity of the reaction.

Regioselectivity refers to the preference of a reaction to occur at a specific site or position within a molecule. In the given scenario, the regioselectivity dictates that the hydrogen (H) atom adds to the carbon atom that is more substituted (has more substituents attached), while the hydroxyl (OH) group adds to the carbon atom that is less substituted (has fewer substituents attached). This regioselective pattern is determined by the reaction conditions and the nature of the reactants involved.

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Decomposition processes should appear here on Chemistry previous modules DBA, When I'm done with the DBA, I'll respond to this query.

Opposition or antagonism to a force, effect, or movement is a reactionary act, process, or occurrence. especially: a reaction to a particular treatment, circumstance, or stimulus; leaning toward a past and typically antiquated political or social system or policy.

Combination, disintegration, single-replacement, twofold, and combustion are the five fundamental types of chemical reactions. You can classify a reaction into one of these groups by looking at the reactants and products.

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Answer: I was asked to classify equations, balance equations, and define + explain the law of conservation of mass

Answer:

Crystals form in nature when molecules gather to stabilize when liquid starts to cool and harden. This process is called crystallization and can happen when magma hardens or when water evaporates from a natural mixture too. Many crystals start small but as more atoms join and create a uniform and repetitive pattern, the crystal grows. This is how crystals are formed in nature.

Explanation:

Answer:

The chemicals differ depending on what the surrounding area is like.

Answer:

D

Explanation:

one of a series of test

Answer:

some of the questions are to be asked and answered scientifically because:

1.scientific method is less biased

Answer:

The first step of the scientific method is the "Question." This step may also be referred to as the "Problem." Your question should be worded so that it can be answered through experimentation. Keep your question concise and clear so that everyone knows what you are trying to solve.

Hope this helps :)

Pls brainliest...

Answer:

letter B

Explanation:

HOPES THIS HELPS

Answer:

3 domains are Bacteria, Archaea, and Eukarya.

Oxidation- Reduction reaction

Answer:

B: Helium is 0.316x faster

If equal amounts of helium and argon are placed in a porous container and allowed to escape, helium will diffuse 3.16x faster than argon.

According to Graham's law of diffusion of gases, the rate of diffusion of a gas is inversely related to the square root of its molecular weight.

Mathematically, when two gases are being compared;

            r1/r2 = √m2/√m1

Where r1 = diffusion rate of gas 1, r2 = difussion rate of gas 2, m1 = molar weight of gas 1, and m2 = molar weight of gas 2.

Molar weight of helium = 4

Molar weight of argon = 39.9

Hence,

              r helium/r argon = √39.9/√4

                                      = 6.317/2

                                        = 3.16

Therefore, 3.16 x r argon = r helium.

In other words, helium will diffuse 3.16x faster than argon.

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The balanced equation for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is:

2 SO2(g) + O2(g) → 2 SO3(g)

To determine the enthalpy change (ΔH) for this reaction, we can use Hess's law, which states that the overall enthalpy change for a reaction is equal to the sum of the enthalpy changes for a series of reactions that add up to the overall reaction. In other words, if we can find the enthalpy changes for a series of reactions that include the same reactants and products as the overall reaction, we can add them up to find the enthalpy change for the overall reaction.

To use Hess's law in this case, we can start with the given standard heats of formation and write the equation for the formation of sulfur trioxide from its constituent elements:

S(s) + 3/2 O2(g) → SO3(g) ΔHf° = R kJ/mol

Note that the enthalpy change for this reaction is equal to the standard heat of formation of sulfur trioxide (ΔHf°). Next, we can write the equation for the decomposition of sulfur dioxide into sulfur and oxygen:

2 SO2(g) → 2 S(s) + 2 O2(g) ΔH1

Note that this reaction is the reverse of the formation of sulfur dioxide from its constituent elements, so we need to reverse the sign of the enthalpy change (ΔH1) for that reaction. Finally, we can write the equation for the reaction we are interested in, which is the sum of the formation of sulfur trioxide and the decomposition of sulfur dioxide:

2 SO2(g) + O2(g) → 2 SO3(g) ΔH2

Using Hess's law, we can express the enthalpy change for the overall reaction (ΔH2) in terms of the enthalpy changes for the two component reactions:

ΔH2 = ΔHf° - ΔH1

Substituting the given values, we get:

ΔH2 = R kJ/mol - (-Q kJ/mol) = R + Q kJ/mol

Therefore, the enthalpy change for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is equal to the sum of the standard heats of formation of sulfur trioxide and sulfur dioxide, which is R + Q kJ/mol.

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The balanced equation for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is:

2 SO2(g) + O2(g) → 2 SO3(g)

To determine the enthalpy change (ΔH) for this reaction, we can use Hess's law, which states that the overall enthalpy change for a reaction is equal to the sum of the enthalpy changes for a series of reactions that add up to the overall reaction. In other words, if we can find the enthalpy changes for a series of reactions that include the same reactants and products as the overall reaction, we can add them up to find the enthalpy change for the overall reaction.

To use Hess's law in this case, we can start with the given standard heats of formation and write the equation for the formation of sulfur trioxide from its constituent elements:

S(s) + 3/2 O2(g) → SO3(g) ΔHf° = R kJ/mol

Note that the enthalpy change for this reaction is equal to the standard heat of formation of sulfur trioxide (ΔHf°). Next, we can write the equation for the decomposition of sulfur dioxide into sulfur and oxygen:

2 SO2(g) → 2 S(s) + 2 O2(g) ΔH1

Note that this reaction is the reverse of the formation of sulfur dioxide from its constituent elements, so we need to reverse the sign of the enthalpy change (ΔH1) for that reaction. Finally, we can write the equation for the reaction we are interested in, which is the sum of the formation of sulfur trioxide and the decomposition of sulfur dioxide:

2 SO2(g) + O2(g) → 2 SO3(g) ΔH2

Using Hess's law, we can express the enthalpy change for the overall reaction (ΔH2) in terms of the enthalpy changes for the two component reactions:

ΔH2 = ΔHf° - ΔH1

Substituting the given values, we get:

ΔH2 = R kJ/mol - (-Q kJ/mol) = R + Q kJ/mol

Therefore, the enthalpy change for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is equal to the sum of the standard heats of formation of sulfur trioxide and sulfur dioxide, which is R + Q kJ/mol.

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The symbol that represents a solution in a chemical reaction is "(aq)."

In chemistry, "(aq)" stands for "aqueous," which refers to a solution where the solute is dissolved in water. A solution is a homogeneous mixture composed of a solvent (in this case, water) and a solute (the substance being dissolved).

When a chemical species is in an aqueous solution, it means that it is dissolved and uniformly dispersed in water molecules. The "(aq)" symbol is typically used to indicate this state of the substance in a chemical equation or reaction.

For example, consider the equation:

NaCl(aq) + AgNO₃(aq) → AgCl(s) + NaNO₃(aq)

In this equation, NaCl(aq) and AgNO₃(aq) both represent substances that are dissolved in water. The "(aq)" notation indicates that these substances are in the form of an aqueous solution.

On the other hand, the symbols "(l)," "(s)," and "(g)" represent different states of matter. "(l)" represents a liquid, "(s)" represents a solid, and "(g)" represents a gas.

So, to summarize, the symbol "(aq)" is used to indicate that a substance is in the form of an aqueous solution, specifically dissolved in water, in a chemical reaction.

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It can be inferred that due to the relatively slight difference in electronegativity between carbon and hydrogen, and because of its symmetrical tetrahedral shape, methane CH4 is a nonpolar molecule.

Methane is a colorless, odorless gas that occurs naturally in large quantities and is also a byproduct of some human activities. Methane is the most basic hydrocarbon in the paraffin family and one of the most potent greenhouse gases. It has the molecular formula CH4.

Methane is the second most prevalent anthropogenic GHG after CO2, accounting for approximately 20% of world emissions. Compared to carbon dioxide, methane traps heat in the atmosphere 25 times more effectively.

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C. Reducing the temperature, is the two changes would make this reaction reactant-favored 2H₂+O₂ 2H₂O + energy

To make the given reaction reactant-favored, we need to shift the equilibrium towards the left side, favoring the formation of reactants (H₂ and O₂) rather than products (H₂O). This can be achieved by considering the impact of pressure and temperature on the reaction.

A. Reducing the pressure:

Reducing the pressure would not favor the reactants. According to Le Chatelier's principle, decreasing the pressure will shift the equilibrium towards the side with a higher number of moles of gas. In this case, both sides of the reaction have the same number of moles of gas (two moles), so reducing the pressure will not have a significant effect.

B. Increasing the pressure:

Increasing the pressure would not favor the reactants either. Again, according to Le Chatelier's principle, increasing the pressure will shift the equilibrium towards the side with fewer moles of gas. As both sides have the same number of moles of gas, changing the pressure will not impact the equilibrium.

C. Reducing the temperature:

Reducing the temperature would favor the reactants. The reaction is exothermic (releases energy), and according to Le Chatelier's principle, decreasing the temperature favors the reaction that produces heat. Therefore, reducing the temperature would shift the equilibrium towards the reactants (H₂ and O₂) side.

D. Increasing the temperature:

Increasing the temperature would not favor the reactants. In an exothermic reaction, increasing the temperature would shift the equilibrium towards the products (H₂O) side to absorb the additional heat.

In conclusion, reducing the temperature (option C) would make the reaction reactant-favored, favoring the formation of H₂ and O₂ rather than H₂O. Therefore, Option C is correct.

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The chemical reaction in which lithium hydroxide and hydrogen is an example of a single replacement reaction.

A single replacement reaction, also goes by the name "single displacement reaction" and it is a type of a reaction wherein one element in a compound is swapped with another element. For example:

AC + B → A + BC

Because of the production of a new bond in the products, single replacement reactions are often exothermic. This means that single-replacement reactions generate energy rather than consuming it (as in endothermic reactions).

   Only when the more reactive element replaces the less reactive element can single-replacement reactions occur.

The reactivity of the metals can be obtained from the table of activity series of metals.

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The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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Answer:  Mass is 2,37 kg

Explanation: Weight G = mg, and g = 9.81 m/s² on Earth.

m = W/g = 23.2 N /  9.81 m/s²

We can see here that when compared to sulfuric acid, carboxylic acids are weaker acids.

Sulfuric acid is a strong, highly corrosive acid with the chemical formula \(H_{2} SO_{4}\). It is one of the most important and widely used industrial chemicals. Sulfuric acid is known for its strong acidic properties and is often referred to as the "king of chemicals" due to its widespread applications in various industries.

Sulfuric acid is a dense, oily liquid that is colorless when pure. It is soluble in water, and when dissolved, it releases hydrogen ions (H+) to make the solution highly acidic.

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When equal masses of ch4(g) and o2(g) are placed in a container, exerting a total pressure of 600 torrs, then the partial pressure of ch4(g) will be 300torr

Let, x gm o2 and ch4 are present

Given,

Total Pressure = 600torr

Number of moles of o2 = x/16

Number of moles of Ch4 = x/16

According to the Daltons law of partial pressure,

Pa =Xa*Ptotal

Xa is the mole fraction of a

Xch4 =\(\frac{x/16}{x/16 +x/16}\)

         =1/2 = 0.5

Pch4 = 0.5×600 = 300torr

Therefore the partial pressure of ch4 will be 300 torr when a total pressure of 600 torr is applied to the mixture.

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Answer:

no.

Explanation:

Answer:

a

Explanation:

Answer:

D

Explanation:

answer: bits of rock rusting when exposed to oxygen and water

Explanation: i think because when it rains the water is left and freezes and night making the rock expand or start to Rust

The electrostatic potential energy and the kinetic energy of an electron in the ground state of hydrogen atom can be calculated from the total energy of the electron.

The total energy of the electron in the ground state of hydrogen atom is -13.6 eV.

The kinetic energy of the electron is related to the total energy of the electron by the formula:

Kinetic energy = - (Total energy)

Thus, kinetic energy = - (-13.6) = 13.6 eV.

The potential energy of the electron is related to the total energy of the electron by the formula:

Potential energy = 2 × Total energy

Thus, potential energy = 2 × (-13.6) = -27.2 eV.  

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The purpose of adding base in the aldol condensation reaction is c) Deprotonate α-carbon to generate electrophile.

What is aldol condensation?

Aldol condensation is a reaction in organic chemistry that involves the condensation of two carbonyl compounds, typically an aldehyde and a ketone, to form a β-hydroxy carbonyl compound.

In the aldol condensation reaction, a base is added to deprotonate the α-carbon of the carbonyl compound, typically an aldehyde or a ketone. The deprotonation of the α-carbon generates an enolate ion, which is an excellent nucleophile. This deprotonation step is crucial in generating the reactive electrophile necessary for the aldol condensation reaction.

By deprotonating the α-carbon, the base increases the electron density on the carbon atom, making it more nucleophilic and prone to react with another carbonyl compound. This enables the formation of a new carbon-carbon bond, resulting in the formation of an aldol product.

Therefore, the purpose of adding a base in the aldol condensation reaction is to deprotonate the α-carbon and generate an electrophilic enolate ion, which can then react with another carbonyl compound to form the desired product.

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